CN105960005A - Power control method for ensuring user fairness in ultra-dense network - Google Patents
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Abstract
Description
技术领域technical field
本发明属于移动通信领域,涉及移动通信网络中的终端功率控制,具体涉及一种可以保障移动终端上行链路的能量效率公平的小基站功率控制方法。The invention belongs to the field of mobile communication, relates to terminal power control in a mobile communication network, in particular to a small base station power control method capable of ensuring fair energy efficiency of uplinks of mobile terminals.
背景技术Background technique
随着移动通信技术的爆发式发展,以智能手机为代表的移动终端不断普及,各种移动应用层出不穷,无论是网络整体的移动数据流量还是单个用户的移动数据流量都呈现出快速增长的态势。为了应对海量流量的挑战,运营商都开始密集部署小基站组成异构双层网络来增强网络的容量。同时,过去用户更多的是从网络获取数据,上传数据量相对较少,因此从基站到终端的下行链路的数据流量往往高于从终端到基站的上行链路。然而,近年来随着移动社交网络、网络游戏、云计算等应用的流行,移动用户上传的数据量越来越大,并且越来频繁。With the explosive development of mobile communication technology, mobile terminals represented by smart phones are becoming more and more popular, and various mobile applications emerge in an endless stream. Both the overall mobile data traffic of the network and the mobile data traffic of a single user are showing a trend of rapid growth. To cope with the challenge of massive traffic, operators have begun to densely deploy small base stations to form a heterogeneous two-tier network to enhance network capacity. At the same time, in the past, users mostly obtained data from the network, and the amount of uploaded data was relatively small. Therefore, the data traffic of the downlink from the base station to the terminal was often higher than the uplink from the terminal to the base station. However, in recent years, with the popularity of applications such as mobile social networks, online games, and cloud computing, the amount of data uploaded by mobile users has become larger and more frequent.
另一方面,对于终端来说,移动数据的传输和处理都会带来严重的能量消耗。由于电池技术的限制,近年来移动终端的电池的容量增长相对缓慢,移动终端续航时间短已成为消费者的一大痛点。由于跟数据收发相关的射频端能量消耗占移动终端整体能量消耗的比重很高,通过优化上行链路的功率控制的方式来实现移动终端的节能潜力巨大。On the other hand, for the terminal, the transmission and processing of mobile data will bring serious energy consumption. Due to the limitations of battery technology, the battery capacity of mobile terminals has grown relatively slowly in recent years, and the short battery life of mobile terminals has become a major pain point for consumers. Since the energy consumption of the radio frequency terminal related to data transmission and reception accounts for a high proportion of the overall energy consumption of the mobile terminal, the energy saving potential of the mobile terminal is huge by optimizing the power control of the uplink.
同时,对于移动网络上行传输来说,用户所处环境、业务需求等各方面的差异会对移动终端的上行传输效率造成巨大影响。传输相同的数据流量,对于链路条件差的用户来说,其能量消耗相对较大,能量效率相对较低,而链路条件好、干扰较小的用户,其能量消耗相对较小,能量效率较高。然而,对于移动网络来说,让用户以相对公平的方式享受移动服务是必要的。考虑到当下能量效率指标对于移动终端的巨大意义,保障移动终端以相对公平的能量效率来传输数据也是合理且必要的。At the same time, for the uplink transmission of the mobile network, the differences in various aspects such as the user's environment and service requirements will have a huge impact on the uplink transmission efficiency of the mobile terminal. To transmit the same data flow, for users with poor link conditions, the energy consumption is relatively large and the energy efficiency is relatively low, while for users with good link conditions and less interference, the energy consumption is relatively small and the energy efficiency is relatively low. higher. However, it is necessary for mobile networks to allow users to enjoy mobile services in a relatively fair manner. Considering the great significance of the current energy efficiency index for mobile terminals, it is also reasonable and necessary to ensure that mobile terminals transmit data with relatively fair energy efficiency.
现行的移动通信标准中上行链路的功率控制以保障接收信干噪比为目的,并未考虑对于能量效率的优化。同时,现有的一些新方法大多以保障移动用户的数据速率的公平性为目标,以优化能量效率的公平性的方案较少。特别的,移动网络终端上行链路的能量效率公平性保障方法还存在空白。The power control of the uplink in the current mobile communication standard is aimed at ensuring the received signal-to-interference-noise ratio, without considering the optimization of energy efficiency. At the same time, most of the existing new methods aim to ensure the fairness of the data rate of mobile users, and there are few schemes to optimize the fairness of energy efficiency. In particular, there is still a gap in the energy efficiency fairness guarantee method for the uplink of the mobile network terminal.
发明内容Contents of the invention
本发明的目的是为了解决上述问题,提出一种超密集网络中保障用户公平性的功率控制方法,本发明采用了上行功率控制的方式,通过综合考虑超密集网络中小基站用户的等级、用户的信道增益等因素,实时调节终端的上行传输功率,达到了最大化终端的上行链路能量效率加权之和的目标,具有既保障终端上行链路的高能量效率,又保障不同终端之间能量效率相对公平的优势。The purpose of the present invention is to solve the above problems and propose a power control method to ensure user fairness in an ultra-dense network. Factors such as channel gain, adjust the uplink transmission power of the terminal in real time, and achieve the goal of maximizing the weighted sum of the uplink energy efficiency of the terminal, which not only ensures the high energy efficiency of the uplink of the terminal, but also ensures the energy efficiency between different terminals relatively fair advantage.
本发明超密集网络中保障用户公平性的功率控制方法,分以下步骤:The power control method for ensuring user fairness in the ultra-dense network of the present invention is divided into the following steps:
步骤1:小基站对每个用户被分配的上行信道进行信道估计,获取信道增益;Step 1: The small base station performs channel estimation on the uplink channel allocated to each user to obtain channel gain;
设小基站的子信道集合为N表示子信道数目;用户集合为K表示用户的数目;用户k被分配的信道集合为Nk表示分配给用户k的子信道的数目;用户k在上行链路子信道n上的信道增益为 Let the subchannel set of the small base station be N represents the number of sub-channels; the user set is K represents the number of users; the channel set assigned to user k is N k represents the number of subchannels allocated to user k; the channel gain of user k on uplink subchannel n is
步骤2:小基站设置两个K×1维向量λ(t)=[λ1(t),…,λk(t),…,λK(t)]T、γ(t)=[γ1(t),…,γk(t),…,γK(t)]T作为计算最佳发射功率的辅助变量,其中t是迭代次数记数变量,用来标识向量λ(t)和γ(t)的迭代次数,λ1(t)、λk(t)、λK(t)分别表示向量λ(t)的第1、第k和第K个元素,γ1(t)、γk(t)、γK(t)分别表示向量γ(t)的第1、第k和第K个元素;引入两个K=1维向量β(s)=[β1(s),…,βk(s),…,βK(s)]T和μ(s)=[μ1(s),…,μk(s),…,μK(s)]T作为计算最佳发射功率的辅助变量,其中,s是迭代次数记数变量,用来标识β(s)和μ(s)的迭代次数,β1(s)、βk(s)、βK(s)分别表示向量β(s)的第1、第k和第K个元素,μ1(s)、μk(s)、μK(s)分别表示向量μ(s)的第1、第k和第K个元素;将迭代次数记数变量t的值初始化为1,将向量λ(t)与γ(t)的每个元素在t=1时的值设为0,即λ(1)=γ(1)=[0,…,0,…,0]T;Step 2: The small base station sets two K×1-dimensional vectors λ(t)=[λ 1 (t),…,λ k (t),…,λ K (t)] T , γ(t)=[γ 1 (t),…,γ k (t),…,γ K (t)] T is used as an auxiliary variable to calculate the optimal transmit power, where t is the number of iteration count variables, used to identify the vector λ(t) and The number of iterations of γ(t), λ 1 (t), λ k (t), and λ K (t) represent the 1st, kth and Kth elements of the vector λ(t), respectively, γ 1 (t), γ k (t), γ K (t) represent the 1st, kth and Kth elements of vector γ(t) respectively; introduce two K=1-dimensional vectors β(s)=[β 1 (s), …,β k (s),…,β K (s)] T and μ(s)=[μ 1 (s),…,μ k (s),…,μ K (s)] T as the most Auxiliary variable of optimal transmit power, where s is the number of iteration count variable, used to identify the number of iterations of β(s) and μ(s), β 1 (s), β k (s), β K (s) represent the 1st, kth and Kth elements of the vector β(s), respectively, and μ 1 (s), μ k (s), μ K (s) represent the 1st, kth and Kth elements of the vector μ(s) respectively The Kth element; the value of the iteration count variable t is initialized to 1, and the value of each element of the vector λ(t) and γ(t) is set to 0 when t=1, that is, λ(1)= γ(1)=[0,...,0,...,0] T ;
将迭代次数记数变量s的值初始化为1,将β(s)与μ(s)的每个元素在s=1时的值设为1,即β(1)=μ(1)=[1,…,1…,1]T;Initialize the value of the number of iteration count variable s to 1, and set the value of each element of β(s) and μ(s) to 1 when s=1, that is, β(1)=μ(1)=[ 1,...,1...,1] T ;
步骤3:小基站依次计算每个终端在被分配的每个子信道上的最佳上行发射功率值;Step 3: The small base station sequentially calculates the optimal uplink transmission power value of each terminal on each allocated subchannel;
如果计算所得的发射功率小于零,则终端在该子信道上的最佳发射功率设为0;否则,终端在该子信道上的最佳发射功率即为计算所得的发射功率;If the calculated transmission power is less than zero, the optimal transmission power of the terminal on the subchannel is set to 0; otherwise, the optimal transmission power of the terminal on the subchannel is the calculated transmission power;
步骤4:小基站将迭代次数计数变量t的值加1,更新参数向量λ(t)、γ(t)的每个元素,并判断参数向量λ(t)、γ(t)是否已经收敛,如果参数向量λ(t)、γ(t)没有收敛,则跳转到步骤3,如果参数向量λ(t)、γ(t)已经收敛,则跳转到步骤5;Step 4: The small base station adds 1 to the value of the iteration count variable t, updates each element of the parameter vectors λ(t), γ(t), and judges whether the parameter vectors λ(t), γ(t) have converged, If the parameter vectors λ(t), γ(t) have not converged, then go to step 3, if the parameter vectors λ(t), γ(t) have converged, then go to step 5;
步骤5:小基站将迭代次数计数变量s的值加1,小基站更新参数向量β(s)、μ(s)的每个元素,并判断参数向量β(s)、μ(s)是否已经收敛,如果参数向量β(s)、μ(s)已经收敛,则跳转到步骤6,否则,跳转到步骤3;Step 5: The small base station adds 1 to the value of the iteration count variable s, the small base station updates each element of the parameter vectors β(s), μ(s), and judges whether the parameter vectors β(s), μ(s) have Convergence, if the parameter vectors β(s), μ(s) have converged, then go to step 6, otherwise, go to step 3;
步骤6:小基站将每个终端的上行最佳发射功率值下发给各个用户终端,然后等待下一次功率控制。Step 6: The small base station sends the optimal uplink transmission power value of each terminal to each user terminal, and then waits for the next power control.
所属步骤3中,小基站在每个子信道上的发射功率值为:In step 3, the transmit power value of the small base station on each sub-channel is:
其中,表示小基站中占用子信道n的用户k在子信道n上的最佳发射功率,B表示单个子信道的带宽,σ2表示小基站在每个子信道上的噪声功率;表示用户k到小基站在子信道n上的信道增益,wk表示用户k上行链路的能量效率相对其他用户的权重,μk(s)为K×1维向量μ(s)的第k个元素,βk(s)为K×1维向量β(s)的第k个元素,λk(t)为K×1维向量λ(T)的第k个元素,γk(t)为K×1维向量γ(T)的第k个元素。wk表示用户k上行链路的能量效率相对其他用户的权重,wk可以由运营商根据自己的需要来确定,只要确保即可。例如,运营商可以根据为用户提供的服务等级来确定,假如运营商可以为用户提供C种服务等级,则不同的服务等级可以依据经验确定一个不同的wc,wc越大,表示该类等级的用户的能量效率权重越高,则对该类等级的用户的能量效率进行优化的优先级越高,否则,则权重低,该类等级的用户的能量效率优化的优先级就低。具体地说,每个用户k根据服务等级确定一个后,同一个基站下的用户再进行一次归一化处理,即可获得 in, Indicates the optimal transmission power of user k occupying sub-channel n in the small base station on sub-channel n, B represents the bandwidth of a single sub-channel, and σ2 represents the noise power of the small base station on each sub-channel; Indicates the channel gain from user k to the small base station on subchannel n, w k indicates the weight of user k’s uplink energy efficiency relative to other users, μ k (s) is the kth of the K×1-dimensional vector μ(s) elements, β k (s) is the kth element of the K×1-dimensional vector β(s), λ k (t) is the kth element of the K×1-dimensional vector λ(T), γ k (t) is the kth element of the K×1-dimensional vector γ(T). w k represents the weight of user k’s uplink energy efficiency relative to other users, w k can be determined by operators according to their own needs, as long as it is ensured that That's it. For example, the operator can determine according to the service level provided to users. If the operator can provide users with C service levels, different service levels can be determined based on experience . The higher the energy efficiency weight of users of a class, the higher the priority of optimizing the energy efficiency of users of this class, otherwise, the lower the weight, the lower the priority of optimizing the energy efficiency of users of this class. Specifically, each user k determines a After that, the users under the same base station can be normalized again to obtain
所属步骤4中,小基站基于以下公式更新自己的参数向量λ中的每个元素In step 4, the small base station updates each element in its own parameter vector λ based on the following formula
其中,Γk(t)表示向量λ(t)的每个元素在第t次迭代的步长,并且满足 表示用户k请求的最低数据速率。Among them, Γ k (t) represents the step size of each element of the vector λ(t) in the t-th iteration, and satisfies Indicates the lowest data rate requested by user k.
小基站基于以下公式更新自己的参数向量γ(t)中的每个元素The small base station updates each element in its own parameter vector γ(t) based on the following formula
其中,ζk(t)表示向量ζ(t)的每个元素在第t次迭代的步长,并满足 表示终端k在各个子信道上的发射功率之和的上限。Among them, ζ k (t) represents the step size of each element of the vector ζ (t) in the t iteration, and satisfies Indicates the upper limit of the sum of transmit power of terminal k on each subchannel.
各个小基站判断参数向量λ、γ是否已经收敛基于以下依据,即是否满足λk(t)=λk(t-1)和γk(t)=γk(t-1),如果λ(t)、γ(t)的每个元素都满足以上条件,则表示λ(t)、γ(t)已经收敛,否则,则表示λ(t)、γ(t)没有收敛。Each small base station judges whether the parameter vectors λ and γ have converged based on the following basis, that is, whether λ k (t)=λ k (t-1) and γ k (t)=γ k (t-1) are satisfied, if λ( If each element of t) and γ(t) satisfies the above conditions, it means that λ(t) and γ(t) have converged, otherwise, it means that λ(t) and γ(t) have not converged.
所属步骤5中,小基站更新自己的参数向量β(s)和μ(s)基于以下规则In step 5, the small base station updates its own parameter vectors β(s) and μ(s) based on the following rules
其中,是由β(s)和μ(s)组合成的2K×1维向量,in, is a 2K×1-dimensional vector composed of β(s) and μ(s),
是由β(s-1)和μ(s-1)组合成的2K×1维向量,是K×1维辅助向量,是2K×1维辅助向量,分别表示2K×1维向量的第1、第K和第2K维元素; is a 2K×1-dimensional vector composed of β(s-1) and μ(s-1), is the K×1 dimensional auxiliary vector, is a 2K×1-dimensional auxiliary vector, represent 2K×1-dimensional vectors respectively The 1st, Kth and 2Kth dimension elements of ;
当k∈[1,K]时, When k∈[1,K],
当k∈[K+1,2K]时, 表示2K×1维向量关于2K×1向量的雅克比矩阵,为终端k的固定电路功率消耗。When k∈[K+1,2K], Represents a 2K×1-dimensional vector About 2K×1 vectors The Jacobian matrix of is the fixed circuit power consumption of terminal k.
判断β(s)、μ(s)是否已经收敛基于以下条件,即β(s)、μ(s)的每个元素是否都满足βk(s)=βk(s-1)和μk(s)=μk(s-1)。。如果满足,则表示β、μ已经收敛,否则,则表示β(s)、μ(s)没有收敛。Judging whether β(s) and μ(s) have converged is based on the following conditions, that is, whether each element of β(s) and μ(s) satisfies β k (s)=β k (s-1) and μ k (s) = μk(s-1). . If it is satisfied, it means that β and μ have converged, otherwise, it means that β(s) and μ(s) have not converged.
本发明的优点在于:The advantages of the present invention are:
(1)本发明为不同终端的上行传输的能量效率赋予了不同的权重值,并对所有用户的上行传输的能量效率进行了优化,从而可以保障用户的上行链路传输的能量效率的高效和公平,使不同用户以相对公平而且较高的能量效率实现数据的上行传输;(2);(3);(1) The present invention assigns different weight values to the energy efficiencies of uplink transmissions of different terminals, and optimizes the energy efficiencies of uplink transmissions of all users, thereby ensuring high efficiency and high energy efficiency of uplink transmissions of users. Fairness, enabling different users to achieve data uplink transmission with relatively fair and high energy efficiency; (2); (3);
附图说明Description of drawings
图1为本发明超密集网络中保障用户公平性的功率控制方法的整理步骤流程图;Fig. 1 is a flow chart of the arrangement steps of the power control method for ensuring user fairness in the ultra-dense network of the present invention;
具体实施方式detailed description
下面将结合附图和实施例对本发明作进一步的详细说明。The present invention will be further described in detail with reference to the accompanying drawings and embodiments.
本发明提供一种可以保障移动终端上行链路的能量效率公平的小基站功率控制方法,采用了上行功率控制的方式,通过综合考虑超密集网络中小基站用户的等级、用户的信道增益等因素,实时调节终端的上行传输功率,达到最大化终端的上行链路能量效率加权之和的效果,具有既保障终端上行链路高的能量效率,又保障不同终端之间能量效率相对公平的优势。The present invention provides a small base station power control method that can ensure the fair energy efficiency of the uplink of the mobile terminal. The uplink power control method is adopted, and by comprehensively considering factors such as the user level of the small base station in the ultra-dense network, the user's channel gain, etc., The uplink transmission power of the terminal is adjusted in real time to achieve the effect of maximizing the weighted sum of the uplink energy efficiency of the terminal, which has the advantages of not only ensuring high energy efficiency of the terminal uplink, but also ensuring relatively fair energy efficiency among different terminals.
本发明的一种超密集网络中保障用户公平性的功率控制方法,流程如图1所示,包括以下几个步骤:A power control method for ensuring user fairness in an ultra-dense network of the present invention, as shown in Figure 1, includes the following steps:
步骤1:小基站对每个用户被分配的上行信道进行信道估计,获取信道增益。Step 1: The small base station performs channel estimation on the uplink channel allocated to each user to obtain channel gain.
如果小基站可使用的子信道集合表示为用户集合表示为用户k被分配的信道集合表示为则用户k在上行链路子信道n上的信道增益表示为 If the set of subchannels available to the small base station is expressed as A collection of users is represented as The channel set allocated to user k is expressed as Then the channel gain of user k on the uplink sub-channel n is expressed as
步骤2:小基站设置两个K×1维向量λ(t)=[λ1(t),…,λk(t),…,λK(t)]T、γ(t)=[γ1(t),…,γk(t),…,γK(t)]T作为计算最佳发射功率的辅助变量,其中t是迭代次数记数变量,用来标识向量λ(t)和γ(t)的迭代次数,λ1(t)、λk(t)、λK(t)分别表示向量λ(t)的第1、第k和第K个元素,γ1(t)、γk(t)、γK(t)分别表示向量γ(t)的第1、第k和第K个元素;引入两个K×1维向量β(s)=[β1(s),…,βk(s),…,βK(s)]T和μ(s)=[μ1(s),…,μk(s),…,μK(s)]T作为计算最佳发射功率的辅助变量,其中,s是迭代次数记数变量,用来标识β(s)和μ(s)的迭代次数,β1(s)、βk(s)、βK(s)分别表示向量β(s)的第1、第k和第K个元素,μ1(s)、μk(s)、μK(s)分别表示向量μ(s)的第1、第k和第K个元素;将迭代次数记数变量t的值初始化为1,将向量λ(t)与γ(t)的每个元素在t=1时的值设为0,即λ(1)=γ(1)=[0,…,0,…,0]T;Step 2: The small base station sets two K×1-dimensional vectors λ(t)=[λ 1 (t),…,λ k (t),…,λ K (t)] T , γ(t)=[γ 1 (t),…,γ k (t),…,γ K (t)] T is used as an auxiliary variable to calculate the optimal transmit power, where t is the number of iteration count variables, used to identify the vector λ(t) and The number of iterations of γ(t), λ 1 (t), λ k (t), and λ K (t) represent the 1st, kth and Kth elements of the vector λ(t), respectively, γ 1 (t), γ k (t), γ K (t) represent the 1st, kth and Kth elements of vector γ(t) respectively; introduce two K×1-dimensional vectors β(s)=[β 1 (s), …,β k (s),…,β K (s)] T and μ(s)=[μ 1 (s),…,μ k (s),…,μ K (s)] T as the most Auxiliary variable of optimal transmit power, where s is the number of iteration count variable, used to identify the number of iterations of β(s) and μ(s), β 1 (s), β k (s), β K (s) represent the 1st, kth and Kth elements of the vector β(s), respectively, and μ 1 (s), μ k (s), μ K (s) represent the 1st, kth and Kth elements of the vector μ(s) respectively The Kth element; the value of the iteration count variable t is initialized to 1, and the value of each element of the vector λ(t) and γ(t) is set to 0 when t=1, that is, λ(1)= γ(1)=[0,...,0,...,0] T ;
将迭代次数记数变量s的值初始化为1,将β(s)与μ(s)的每个元素在s=1时的值设为1,即β(1)=μ(1)=[1,…,1…,1]T。Initialize the value of the number of iteration count variable s to 1, and set the value of each element of β(s) and μ(s) to 1 when s=1, that is, β(1)=μ(1)=[ 1,...,1...,1] T .
步骤3:小基站依次计算在每个终端在它被分配的每个子信道上的最佳上行发射功率值。Step 3: The small base station sequentially calculates the optimal uplink transmission power value of each terminal on each sub-channel allocated to it.
如果计算所得的发射功率小于零,则终端在该子信道上的最佳发射功率为0;否则,终端在该子信道上的发射功率即为计算所得的发射功率。If the calculated transmit power is less than zero, the optimal transmit power of the terminal on the sub-channel is 0; otherwise, the transmit power of the terminal on the sub-channel is the calculated transmit power.
本发明适用于宏基站和小基站使用不同的频段,同时,小基站之间也有有效的干扰避免机制的环境。因此,相邻小基站之间的干扰也处在可以忽略的水平。用表示小基站中占用子信道n的用户k在子信道n上的上行发射功率,B表示单个子信道的带宽,σ2表示小基站在每个子信道上的噪声功率,表示分配给用户k的子信道集合,表示终端k的固定电路消耗,表示终端k的最低数据速率限制,表示终端k在所有子信道上发射功率总和的上限,则上行最佳发射功率的获得基于求解以下问题P1:The present invention is applicable to the environment where the macro base station and the small base station use different frequency bands, and at the same time, there is an effective interference avoidance mechanism between the small base stations. Therefore, the interference between adjacent small base stations is also at a negligible level. use Indicates the uplink transmission power of user k occupying subchannel n in the small base station on subchannel n, B indicates the bandwidth of a single subchannel, σ2 indicates the noise power of the small base station on each subchannel, Indicates the set of subchannels allocated to user k, denotes the fixed circuit consumption at terminal k, Indicates the minimum data rate limit for terminal k, Represents the upper limit of the sum of the transmission power of terminal k on all sub-channels, then the optimal transmission power of uplink is obtained based on solving the following problem P1:
问题P1是一个有最低数据速率QoS保障的用户上行传输能量效率加权和最大化问题,其中,wk表示用户k上行传输的能量效率的权重,wk可以由运营商根据自己的需要来确定,只要保证即可。例如,运营商可以根据为用户提供的服务等级来确定,假如运营商可以为用户提供C种服务等级,则不同的服务等级可以依据经验确定一个不同的wc,wc越大,表示该等级的用户的能量效率权重高,则对该等级的用户的能量效率进行优化的优先级就高,否则,则权重低,该类等级的用户的能量效率优化的优先级就低。每个用户k根据服务等级被赋予一个后,同一个基站下的用户再进行一次归一化处理,即可得到 Problem P1 is a weighted and maximized problem of user uplink transmission energy efficiency with the lowest data rate QoS guarantee, where w k represents the weight of energy efficiency of user k uplink transmission, w k can be determined by the operator according to its own needs, just make sure That's it. For example, the operator can determine according to the service level provided to users. If the operator can provide users with C service levels, then different service levels can be determined based on experience. A different wc , the larger wc, indicates the level If the user's energy efficiency weight is high, the priority of optimizing the energy efficiency of users of this level is high; otherwise, the weight is low, and the priority of energy efficiency optimization of users of this level is low. Each user k is assigned a After that, the users under the same base station can be normalized again to get
问题P1是一个非凸优化问题,为了相对高效的求解以上非凸优化问题,引入两组辅助变量向量β(s)=[β1(s),…,βk(s),…,βK(s)]T和μ(s)=[μ1(s),…,μk(s),…,μK(s)]T,二者都是K×1维的向量。可以证明,有且仅存在一组和使得问题P1的最优解与下面的问题P2的最优解相等Problem P1 is a non-convex optimization problem. In order to solve the above non-convex optimization problems relatively efficiently, two sets of auxiliary variable vectors β(s)=[β 1 (s),…,β k (s),…,β K (s)] T and μ(s)=[μ 1 (s),…,μ k (s),…,μ K (s)] T , both are K×1-dimensional vectors. It can be shown that there is one and only one set of and such that the optimal solution to problem P1 is Equivalent to the optimal solution of the following problem P2
并且满足以下公式and satisfy the following formula
因此,小基站求解每个终端在它被分配的每个子信道上的最佳上行发射功率值可以通过两层循环迭代来解决。内层循环时,β(s)=[β1(s),…,βk(s),…,βK(s)]T和μ(s)=[μ1(s),…,μk(s),…,μK(s)]T已经给定,将β(s),μ(s)取代问题P2中的β*(s),μ*(s),则问题P2变成一个典型的凸优化问题,引入两组朗格朗日乘子λ(t)=[λ1(t),…,λk(t),…,λK(t)]T、γ(t)=[γ1(t),…,γk(t),…,γK(t)]T,可以通过凸优化中经典的拉格朗日对偶松弛的思路,通过次梯度法不断更新λ(t)γ(t)直到二者收敛,从而简单快速的得到最优解Therefore, the small base station can solve the optimal uplink transmission power value of each terminal on each subchannel allocated to it through two layers of cyclic iterations. In inner loop, β(s)=[β 1 (s),…,β k (s),…,β K (s)] T and μ(s)=[μ 1 (s),…,μ k (s),…, μ K (s)] T has been given, replace β * (s), μ * (s) in problem P2 with β (s), μ (s), then problem P2 becomes A typical convex optimization problem, introducing two sets of Langrange multipliers λ(t)=[λ 1 (t),…,λ k (t),…,λ K (t)] T , γ(t) =[γ 1 (t),…,γ k (t),…,γ K (t)] T , through the idea of classical Lagrange dual relaxation in convex optimization, λ( t)γ(t) until the two converge, so that the optimal solution can be obtained simply and quickly
得到内层循环的最优解后,外层循环可以对β=[β1,β2,…,βK],μ=[μ1,μ2,…,μK]两组向量进行迭代更新收敛。具体的说,基于等式和可以构造下式:get the inner loop After the optimal solution of , the outer loop can iteratively update and converge the two sets of vectors β=[β 1 ,β 2 ,…,β K ], μ=[μ 1 ,μ 2 ,…,μ K ]. Specifically, based on the equation and The following formula can be constructed:
当k∈[1,K]时, When k∈[1,K],
当k∈[K+1,2K]时, When k∈[K+1,2K],
可以证明,当且仅当β(s)=β*(s),u(s)=u*(s)时,因此,可以通过拟牛顿法来迭代获得β*(s),u*(s)。It can be proved that if and only if β(s)=β * (s), u(s)=u * (s), Therefore, β * (s), u * (s) can be obtained iteratively by the quasi-Newton method.
步骤4:小基站将迭代次数计数器t的值加1。基于次梯度法,小基站用以下公式更新的朗格朗日乘子λ(t)中的每个元素其中,Γk(t)表示向量λ(t)的每个元素在第t次迭代的步长,并且满足 表示用户k请求的最低数据速率;Step 4: The small base station adds 1 to the value of the iteration count counter t. Based on the subgradient method, the small base station uses the following formula to update each element in the Langrange multiplier λ(t) Among them, Γ k (t) represents the step size of each element of the vector λ(t) in the t-th iteration, and satisfies Indicates the minimum data rate requested by user k;
小基站基于以下公式更新参数向量γ(t)中的每个元素The small base station updates each element in the parameter vector γ(t) based on the following formula
其中,ζk(t)表示向量ζ(t)的每个元素在第t次迭代的步长,并满足 表示终端k在各个子信道上的发射功率之和的上限。Among them, ζ k (t) represents the step size of each element of the vector ζ (t) in the t iteration, and satisfies Indicates the upper limit of the sum of transmit power of terminal k on each subchannel.
各个小基站基于以下依据判拉格朗日乘子λ(t)、γ(t)是否已经收敛。如果λ(t)、γ(t)的每个元素都满足λk(t)=λk(t-1)和γk(t)=γk(t-1),则表示λ(t)、γ(t)已经收敛,否则,则表示λ(t)、γ(t)没有收敛。Each small base station judges whether the Lagrangian multipliers λ(t) and γ(t) have converged based on the following basis. If each element of λ( t ) and γ(t) satisfies λk(t)=λk(t-1) and γk (t)= γk ( t -1), then λ(t) , γ(t) have converged, otherwise, it means λ(t), γ(t) have not converged.
如果拉格朗日乘子λ(t)、γ(t)没有收敛,则跳转到步骤3;否则,则跳转到步骤5。If the Lagrangian multipliers λ(t), γ(t) do not converge, go to step 3; otherwise, go to step 5.
步骤5:小基站将迭代次数计数器s的值加1。基于拟牛顿法,小基站用以下公式更新β(s)和μ(s),Step 5: The small base station adds 1 to the value of the iteration count counter s. Based on the quasi-Newton method, the small base station uses the following formula to update β(s) and μ(s),
其中,是K×1维辅助向量,表示2K×1维向量关于2K×1向量的雅克比矩阵。。in, is the K×1 dimensional auxiliary vector, Represents a 2K×1-dimensional vector About 2K×1 vectors The Jacobian matrix of . .
当β(s)、μ(s)的每个元素都满足以下两个式子,When each element of β(s) and μ(s) satisfies the following two formulas,
βk(s)=βk(s-1)β k (s) = β k (s-1)
μk(s)=μk(s-1)。μ k (s) = μ k (s-1).
则β(s)、μ(s)收敛,否则,则β(s)、μ(s)没有收敛。Then β(s) and μ(s) converge, otherwise, β(s) and μ(s) do not converge.
如果β(s)、μ(s)已经收敛,则跳转到步骤6,否则,跳转到步骤3。If β(s) and μ(s) have converged, go to step 6, otherwise, go to step 3.
步骤6:小基站将得到每个终端的上行最佳发射功率值下发给各个用户终端,然后等待下一次功率控制。Step 6: The small base station sends the best uplink transmit power value obtained for each terminal to each user terminal, and then waits for the next power control.
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