CN104317856A - Method for testing and evaluating vocabulary amount - Google Patents

Abstract

The invention relates to a method for testing and evaluating the vocabulary amount, and belongs to the field of language learning. The method comprises the following steps: determining the attribute values of all vocabularies and dividing difficulty levels; randomly selecting an attribute value from the vocabularies of a first difficulty level for serving as an initial feature value, and determining a vocabulary difficulty coefficient; calculating a corresponding feature value of a first testing vocabulary, and judging a corresponding option; calculating a difficulty coefficient value which corresponds to the feature value, and meanwhile determining a next feature value according to a state value; judging whether a subject comprehends a test result or not according to testing evaluation object matrix processing, and obtaining a vocabulary evaluation domain estimated value of the subject. By adopting the method, the defects of non-correlation among test vocabularies and incapability of adjusting the difficulty coefficient are overcome, and an accurate result is obtained by using a small number of testing vocabularies.

Description

A kind of test and evaluation method of vocabulary

Technical field

The present invention relates to a kind of test and evaluation method of vocabulary, belong to language learning field.

Background technology

Along with the development of society, a lot of test evaluations is all intelligent, especially in the test of language vocabulary amount.The language vocabulary water gaging taking which type of method could test out experimenter is more accurately put down, and how to design more rational computing method and has just become crucial factor, the real level reflecting an experimenter that a rational measuring and calculation method can prepare.Especially in the test of English glossary, the vocabulary size level of experimenter how is doped by a certain amount of test result.In a kind of test at random, how experimenter the sample vocabulary result of having tested and the vocabulary association that will test.How on the basis of the sample vocabulary result of having tested, random and suitable adjustment to be carried out to the difficulty will testing vocabulary.This is general standardization examination or is difficult to accomplish in testing.

In order to overcome the relevance of evaluation relevance in the test of above-mentioned middle Intellectualized standard and degree-of-difficulty factor thereof, the present invention proposes a kind of language vocabulary and measures examination and appraisal procedure.The next vocabulary of random test can husband's character with the horse having surveyed vocabulary, and the difficulty of test vocabulary also there is horse can husband's character.

Summary of the invention

The invention provides a kind of test and evaluation method of vocabulary, for the defect not having relevance between the test vocabulary overcome in intelligent vocabulary standard testing, and the nonadjustable defect of degree-of-difficulty factor of test vocabulary.Except overcoming its defect, test vocabulary, under the prerequisite with certain randomness, makes the advantage that the relevance of testing vocabulary is strengthened.

Technical scheme of the present invention is: a kind of test and evaluation method of vocabulary, and the concrete steps of described method are as follows:

Step1, determine that the property value of all vocabulary is 1......i (i ∈ N ^*), and be divided into 1 difficulty level with every 1500 vocabulary; Wherein, the vocabulary being finally less than 1500 is attributed to last 1 difficulty level;

Step2, from the vocabulary of the 1st difficulty level, choose a property value as initial characteristic values id at random ₀, and determine that vocabulary degree-of-difficulty factor is x ₀; Wherein, x ₀=1 represents initial degree-of-difficulty factor value;

Step3, calculating first test vocabulary characteristic of correspondence value: wherein, f (x ₀) be initial characteristic values generating function;

Step4, eigenwert id to measurand ₁the option of corresponding vocabulary judges:

If the eigenwert id of measurand ₁the option of corresponding vocabulary is correct, then defined label F ₁=1;

If the eigenwert id of measurand ₁the option mistake of corresponding vocabulary, then defined label F ₁=0;

Step5, calculating id _n-1corresponding vocabulary degree-of-difficulty factor x _n-1value:

If F _n-1=1, then x _n-1=x _n-2+ 1;

If F _n-1=0, then x _n-1=x _n-2-0.5;

Wherein, n >=2;

Step6, according to F _n-1value, determine the eigenwert id of next measurand _n:

If F _n-1=1, then id _n=id _n-1+ t _n-1;

If F _n-1=0, then id _n=id _n-1-t _n-1;

Wherein, x _n-1for getting id according to lexical feature value _n-1time corresponding degree-of-difficulty factor value; x _n-2for getting id according to lexical feature value _n-2time corresponding degree-of-difficulty factor value; F (x _n-1) represent when degree-of-difficulty factor value is x _n-1time eigenwert generating function; F (x _n-2) represent when degree-of-difficulty factor value is x _n-2time eigenwert generating function; N>=2;

Step7, according to experimenter, 2 × L test result matrix R is shown to the eigenwert of the object tested and state value thereof:

$R=\left[\begin{array}{ccccccc}{\mathrm{id}}_1& {\mathrm{id}}_2& {\mathrm{id}}_3& {\mathrm{id}}_4& ......& {\mathrm{id}}_{L-1}& {\mathrm{id}}_L\\ F_1& F_2& F_3& F_4& ......& F_{L-1}& F_L\end{array}\right]$

Wherein, L represents total number of test and L >=1;

Step8, test result matrix R carried out process show whether experimenter grasps test result:

If eigenwert id _lcorresponding F _lwhen being 1, then think at id _nvocabulary experimenter in the neighborhood of left and right can grasp;

If eigenwert id _lcorresponding F _lwhen being 0, then think at id _nvocabulary experimenter in the neighborhood of left and right does not grasp;

Step9, according to test result, show that the vocabulary test and appraisal territory estimated value of experimenter is:

Wherein, N represents that test judges right total number, and M represents total number of testing and misdeeming; ψ _k(id _k) represent measurand eigenwert id _kthe value of the left and right neighborhood when option of corresponding vocabulary is correct, represent measurand eigenwert id _jthe value of the left and right neighborhood during option mistake of corresponding vocabulary.

Described eigenwert generating function $f\left(x_{n-2}\right)=\frac{15000}{1+{\mathrm{id}}_0{e}^{-x_{n-2}}},n\≥2.$

Principle of work of the present invention is:

The first step, founding mathematical models.

Second step, the mathematical model according to setting up: first determine the property value of all vocabulary and carry out difficulty level division; Then at random from the vocabulary of the 1st difficulty level, to choose a property value as initial characteristic values and determine vocabulary degree-of-difficulty factor; Then calculate the characteristic of correspondence value of first test vocabulary and the option corresponding to it is judged; Then calculate the degree-of-difficulty factor value of being somebody's turn to do corresponding to eigenwert again, determine next eigenwert according to state value simultaneously; Finally show whether experimenter grasps test result and draw the vocabulary test and appraisal territory estimated value of experimenter according to test evaluation object matrix disposal.

The invention has the beneficial effects as follows:

1, test between vocabulary and there is relevance, next test vocabulary is associated with the eigenwert of a upper test words, also relevant to mistake with a upper judgement testing vocabulary, the variable quantity of eigenwert is counted by the function that an eigenwert is relevant, make there is a relevance, i.e. a kind of simple Markov character between test vocabulary like this.Instead of test in a kind of random mode, such test more close to the true horizon of measured, can overcome the defect of testing at present and not having relevance in vocabulary between test words.

2, the degree-of-difficulty factor of vocabulary can adjust mistake according to the judgement of test, and to test right degree-of-difficulty factor can increase, and test errors degree-of-difficulty factor can reduce.Make it possible to real-time adjustment difficulty coefficient, just can better embody the level that measured grasps so in testing.

3, test the relevance having single order between vocabulary, for good for the stochastic comparison of multistage multidimensional test, less test vocabulary can be used just can to estimate the level of an experimenter.Less vocabulary test is used to go out result more accurately comparatively speaking.Overcome between test vocabulary and there is no relevance, and nonadjustable defect of degree-of-difficulty factor; Turn to improve, use less test vocabulary to draw result more accurately.

Accompanying drawing explanation

Fig. 1 is test evaluation matrix computational approach process flow diagram of the present invention;

Fig. 2 is the signal mode process figure of test evaluation matrix of the present invention;

Fig. 3 is that the present invention tests and assesses the result calculation flow chart of computing method.

Embodiment

Embodiment 1: as Figure 1-3, a kind of test and evaluation method of vocabulary, the concrete steps of described method are as follows:

Step1, determine that the property value of all vocabulary is 1......i (i ∈ N ^*), and be divided into 1 difficulty level with every 1500 vocabulary; Wherein, the vocabulary being finally less than 1500 is attributed to last 1 difficulty level;

Step2, from the vocabulary of the 1st difficulty level, choose a property value as initial characteristic values id at random ₀, and determine that vocabulary degree-of-difficulty factor is x ₀; Wherein, x ₀=1 represents initial degree-of-difficulty factor value;

Step3, calculating first test vocabulary characteristic of correspondence value: wherein, f (x ₀) be initial characteristic values generating function;

Step4, eigenwert id to measurand ₁the option of corresponding vocabulary judges:

If the eigenwert id of measurand ₁the option of corresponding vocabulary is correct, then defined label F ₁=1;

If the eigenwert id of measurand ₁the option mistake of corresponding vocabulary, then defined label F ₁=0;

Step5, calculating id _n-1corresponding vocabulary degree-of-difficulty factor x _n-1value:

If F _n-1=1, then x _n-1=x _n-2+ 1;

If F _n-1=0, then x _n-1=x _n-2-0.5;

Wherein, n >=2;

Step6, according to F _n-1value, determine the eigenwert id of next measurand _n:

If F _n-1=1, then id _n=id _n-1+ t _n-1;

If F _n-1=0, then id _n=id _n-1-t _n-1;

Wherein, x _n-1for getting id according to lexical feature value _n-1time corresponding degree-of-difficulty factor value; x _n-2for getting id according to lexical feature value _n-2time corresponding degree-of-difficulty factor value; F (x _n-1) represent when degree-of-difficulty factor value is x _n-1time eigenwert generating function; F (x _n-2) represent when degree-of-difficulty factor value is x _n-2time eigenwert generating function; N>=2;

Step7, according to experimenter, 2 × L test result matrix R is shown to the eigenwert of the object tested and state value thereof:

$R=\left[\begin{array}{ccccccc}{\mathrm{id}}_1& {\mathrm{id}}_2& {\mathrm{id}}_3& {\mathrm{id}}_4& ......& {\mathrm{id}}_{L-1}& {\mathrm{id}}_L\\ F_1& F_2& F_3& F_4& ......& F_{L-1}& F_L\end{array}\right]$

Wherein, L represents total number of test and L >=1;

Step8, test result matrix R carried out process show whether experimenter grasps test result:

If eigenwert id _lcorresponding F _lwhen being 1, then think at id _nvocabulary experimenter in the neighborhood of left and right can grasp;

If eigenwert id _lcorresponding F _lwhen being 0, then think at id _nvocabulary experimenter in the neighborhood of left and right does not grasp;

Step9, according to test result, show that the vocabulary test and appraisal territory estimated value of experimenter is:

Wherein, N represents that test judges right total number, and M represents total number of testing and misdeeming; ψ _k(id _k) represent measurand eigenwert id _kthe value of the left and right neighborhood when option of corresponding vocabulary is correct, represent measurand eigenwert id _jthe value of the left and right neighborhood during option mistake of corresponding vocabulary.

Embodiment 2: as Figure 1-3, a kind of test and evaluation method of vocabulary, the concrete steps of described method are as follows:

First founding mathematical models:

Known: the state value F that characteristics of objects value is corresponding _n=1 represents that test vocabulary is answered questions, F _n=0 represents that mistake answered in test vocabulary; Feature difference computing function is chosen for the function of form, the foundation of this function of example is: if with vocabulary size, according to Chinese scholars to vocabulary quantifier elimination, then in conjunction with the English teaching in China and area, extrapolate vocabulary that China Advanced English learner grasps probably about 10000-13000 vocabulary.Selected sample vocabulary source according to being get rid of all people's name, place name, the cognate of and some function-function words and content-sincere.Such as certain vocabulary has odd number and plural number, then only get odd number as test vocabulary; Certain vocabulary has verb and occlusion, then select verb form to make test vocabulary; When adjective and adverbial word, get adjective and make test vocabulary; And get rid of some non-vocabulary symbols, after screening, general primary lexical just only has 15000 vocabulary like this.So using the test upper limit of these data as vocabulary.The maximal value of characteristics of objects function also can not surpass this upper limit, so the B=15000 in function, and initial value A=id ₀, a+bx=-x.Then the f (x) of final instantiation is: if be that simpler function is also passable f (x) example, illustrate with above-mentioned function in this example.Characteristics of objects value change function f (x _n-2); Characteristics of objects value variable quantity t _n-1; Test evaluation matrix R: the matrix of consequence representing experimenter's test; Variable neighborhood function ψ _k(id _k),

Then carry out the algorithm of testing and assessing, comprise the steps:

Step1, determine that the property value of all vocabulary is 1......i (i ∈ N ^*), and be divided into 1 difficulty level with every 1500 vocabulary; Wherein, the vocabulary being finally less than 1500 is attributed to last 1 difficulty level;

Step2, from the vocabulary of the 1st difficulty level, choose a property value as initial characteristic values id at random ₀, and determine that vocabulary degree-of-difficulty factor is x ₀; Wherein, x ₀=1 represents initial degree-of-difficulty factor value;

Step3, calculating first test vocabulary characteristic of correspondence value: wherein, f (x ₀) be initial characteristic values generating function;

Step4, eigenwert id to measurand ₁the option of corresponding vocabulary judges:

If the eigenwert id of measurand ₁the option of corresponding vocabulary is correct, then defined label F ₁=1;

If the eigenwert id of measurand ₁the option mistake of corresponding vocabulary, then defined label F ₁=0;

Step5, calculating id _n-1corresponding vocabulary degree-of-difficulty factor x _n-1value:

If F _n-1=1, then x _n-1=x _n-2+ 1;

If F _n-1=0, then x _n-1=x _n-2-0.5;

Wherein, n >=2;

Step6, according to F _n-1value, determine the eigenwert id of next measurand _n:

If F _n-1=1, then id _n=id _n-1+ t _n-1;

If F _n-1=0, then id _n=id _n-1-t _n-1;

Wherein, x _n-1for getting id according to lexical feature value _n-1time corresponding degree-of-difficulty factor value; x _n-2for getting id according to lexical feature value _n-2time corresponding degree-of-difficulty factor value; F (x _n-1) represent when degree-of-difficulty factor value is x _n-1time eigenwert generating function; F (x _n-2) represent when degree-of-difficulty factor value is x _n-2time eigenwert generating function; N>=2;

Step7, according to experimenter, 2 × L test result matrix R is shown to the eigenwert of the object tested and state value thereof:

$R=\left[\begin{array}{ccccccc}{\mathrm{id}}_1& {\mathrm{id}}_2& {\mathrm{id}}_3& {\mathrm{id}}_4& ......& {\mathrm{id}}_{L-1}& {\mathrm{id}}_L\\ F_1& F_2& F_3& F_4& ......& F_{L-1}& F_L\end{array}\right]$

Wherein, L represents total number of test and L >=1;

Step8, test result matrix R carried out process show whether experimenter grasps test result:

If eigenwert id _lcorresponding F _lwhen being 1, then think at id _nvocabulary experimenter in the neighborhood of left and right can grasp;

If eigenwert id _lcorresponding F _lwhen being 0, then think at id _nvocabulary experimenter in the neighborhood of left and right does not grasp;

Step9, according to test result, show that the vocabulary test and appraisal territory estimated value of experimenter is:

Wherein, N represents that test judges right total number, and M represents total number of testing and misdeeming; ψ _k(id _k) represent measurand eigenwert id _kthe value of the left and right neighborhood when option of corresponding vocabulary is correct, represent measurand eigenwert id _jthe value of the left and right neighborhood during option mistake of corresponding vocabulary.

Wherein, described eigenwert generating function $f\left(x_{n-2}\right)=\frac{15000}{1+{\mathrm{id}}_0{e}^{-x_{n-2}}},n\≥2.$

Make a concrete analysis of as follows:

Suppose: the eigenwert of tested object is exactly the frequency of utilization ranking value of word; Experimenter's follow-on test 7 vocabulary, the 4th vocabulary test mistake, initial value id ₀=1200;

As shown in Figure 3: the initial value of test sample book degree-of-difficulty factor value is x ₀=1, according to id ₁=id ₀+ f (x ₀) show that the feature of first test corresponding to vocabulary is: id ₁=1200+33=1233, and judge F ₁=1, then x ₁=x ₀+ 1=2;

Id is calculated according to step Step6 ₂=id ₁+ t ₁;

Calculate id again ₃, id ₃=id ₂+ t ₂;

After the degree-of-difficulty factor of 7 vocabulary tested in this example gathers be: x _l=[1 234 3.5 4.5 5.5], l=0 ... 6;

The word of the F==1 that the eigenwert of certain measurand is corresponding as shown in Figure 2 then in the dotted line of left and right is passable, think grasp, be divided into 10 grades according to conventional 15000 words, suppose neighborhood function value at different levels=[500 400 300 200 100 80 60 40 20 10];

Characteristics of objects value generating function $f\left(x_{n-2}\right)=\frac{15000}{1+{\mathrm{id}}_0{e}^{-x_{n-2}}},n\≥2,$ Then draw according to Fig. 1:

t _m＝[58?155?406?250?644?2191]，m＝1,…6；

Draw id _l=[1,233 1,291 1,446 1,852 1,602 2,246 4437], L=1 ... 7;

Finally draw R matrix:

$R=\left[\begin{array}{ccccccc}1233& 1291& 1446& 1852& 1602& 2246& 4437\\ 1& 1& 1& 1& 1& 1& 1\end{array}\right];$

Judge again and again according to the flow process in Fig. 3, draw arithmetic result:

Wherein, N=6, M=1; Measurand eigenwert id _kthe value ψ of the left and right neighborhood when option of corresponding vocabulary is correct _k(id _k)=[500,500,500,400,400,300] (as: id ₁the vocabulary of=1233 correspondences belongs to the 1st grade, and the 1st grade of corresponding neighborhood function value is 500; The value reason of other left and right neighborhood is identical with it); Survey characteristics of objects value id _jthe value of the left and right neighborhood during option mistake of corresponding vocabulary

To sum up, the arithmetic result drawn is exactly the final evaluation of this experimenter, and using the estimated value of this result as the vocabulary level of this tester, namely estimating the general vocabulary of this experimenter is 4400.

By reference to the accompanying drawings the specific embodiment of the present invention is explained in detail above, but the present invention is not limited to above-mentioned embodiment, in the ken that those of ordinary skill in the art possess, various change can also be made under the prerequisite not departing from present inventive concept.

Claims (2)

1. a test and evaluation method for vocabulary, is characterized in that: the concrete steps of described method are as follows:

Step1, determine that the property value of all vocabulary is 1......i (i ∈ N ^*), and be divided into 1 difficulty level with every 1500 vocabulary; Wherein, the vocabulary being finally less than 1500 is attributed to last 1 difficulty level;

Step2, from the vocabulary of the 1st difficulty level, choose a property value as initial characteristic values id at random ₀, and determine that vocabulary degree-of-difficulty factor is x ₀; Wherein, x ₀=1 represents initial degree-of-difficulty factor value;

Step3, calculating first test vocabulary characteristic of correspondence value: wherein, f (x ₀) be initial characteristic values generating function;

Step4, eigenwert id to measurand ₁the option of corresponding vocabulary judges:

If the eigenwert id of measurand ₁the option of corresponding vocabulary is correct, then defined label F ₁=1;

If the eigenwert id of measurand ₁the option mistake of corresponding vocabulary, then defined label F ₁=0;

Step5, calculating id _n-1corresponding vocabulary degree-of-difficulty factor x _n-1value:

If F _n-1=1, then x _n-1=x _n-2+ 1;

If F _n-1=0, then x _n-1=x _n-2-0.5;

Wherein, n >=2;

Step6, according to F _n-1value, determine the eigenwert id of next measurand _n:

If F _n-1=1, then id _n=id _n-1+ t _n-1;

If F _n-1=0, then id _n=id _n-1-t _n-1;

Wherein, x _n-1for getting id according to lexical feature value _n-1time corresponding degree-of-difficulty factor value; x _n-2for getting id according to lexical feature value _n-2time corresponding degree-of-difficulty factor value; F (x _n-1) represent when degree-of-difficulty factor value is x _n-1time eigenwert generating function; F (x _n-2) represent when degree-of-difficulty factor value is x _n-2time eigenwert generating function; N>=2;

Step7, according to experimenter, 2 × L test result matrix R is shown to the eigenwert of the object tested and state value thereof:

$R=\left[\begin{array}{ccccccc}{\mathrm{id}}_1& {\mathrm{id}}_2& {\mathrm{id}}_3& {\mathrm{id}}_4& ......& {\mathrm{id}}_{L-1}& {\mathrm{id}}_L\\ F_1& F_2& F_3& F_4& ......& F_{L-1}& F_L\end{array}\right]$

Wherein, L represents total number of test and L >=1;

Step8, test result matrix R carried out process show whether experimenter grasps test result:

If eigenwert id _lcorresponding F _lwhen being 1, then think at id _nvocabulary experimenter in the neighborhood of left and right can grasp;

If eigenwert id _lcorresponding F _lwhen being 0, then think at id _nvocabulary experimenter in the neighborhood of left and right does not grasp;

Step9, according to test result, show that the vocabulary test and appraisal territory estimated value of experimenter is:

Wherein, N represents that test judges right total number, and M represents total number of testing and misdeeming; ψ _k(id _k) represent measurand eigenwert id _kthe value of the left and right neighborhood when option of corresponding vocabulary is correct, represent measurand eigenwert id _jthe value of the left and right neighborhood during option mistake of corresponding vocabulary.

2. the test and evaluation method of vocabulary according to claim 1, is characterized in that: described eigenwert generating function $f\left(x_{n-2}\right)=\frac{15000}{1+{\mathrm{id}}_0{e}^{-x_{n-2}}},n\≥2.$