CN104282311B - The quantization method and device of sub-band division in a kind of audio coding bandwidth expansion - Google Patents

The quantization method and device of sub-band division in a kind of audio coding bandwidth expansion Download PDF

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CN104282311B
CN104282311B CN201410524838.0A CN201410524838A CN104282311B CN 104282311 B CN104282311 B CN 104282311B CN 201410524838 A CN201410524838 A CN 201410524838A CN 104282311 B CN104282311 B CN 104282311B
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msub
subband
sub
sampling point
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CN104282311A (en
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胡瑞敏
张茂胜
姚雪春
王晓晨
姜林
涂卫平
王松
杨乘
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Shenzhen Research Institute of Wuhan University
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Abstract

The present invention relates to the quantization method and device of sub-band division in a kind of audio coding bandwidth expansion, the present invention carries out four segmentations to training sample high-frequency signal successively, every time sampling point cut-point is obtained during segmentation according to the sampling point standard deviation product minimum value of two new subbands, finally obtain 16 sampling point cut-points, the audio coding bandwidth of input is extended with this 16 sampling point cut-points, more preferable high frequency spectrum structure can be obtained, closer to high frequency spectrum shape, so as to improve high frequency spectrum reconstruction quality;The sub-band division method that the present invention uses takes into full account the statistical property in quantized subband, compared to Bark band or is evenly dividing mode, and subjective hearing MOS of the invention points are slightly lifted, and signal to noise ratio is obviously improved.

Description

The quantization method and device of sub-band division in a kind of audio coding bandwidth expansion
Technical field
The present invention relates to a kind of quantization side of sub-band division in audio coding field, more particularly to audio coding bandwidth expansion Method and device.
Background technology
Psychologic acoustics research shows that people have difference for the sensitiveness under audio different frequency, more sensitive to low frequency, And it is insensitive to high frequency, therefore use less information to be encoded to save code check for HFS in audio coding.And The complete missing of HFS can bring the discomfort in sense of hearing again, therefore often recover high frequency by the way of bandwidth expansion, and It can all be used in bandwidth expansion and arrive sub-band division, conventional subband is divided often using Bark band or the mode being evenly dividing, this Mode have ignored the statistical property in quantized subband.Therefore by carrying out statistical analysis to quantitative information, and subband is carried out accordingly Division, quantizing distortion is favorably reduced, improve bandwidth extension encoding quality.
The content of the invention
The defects of it is an object of the invention to overcome prior art, and subband in a kind of audio coding bandwidth expansion is provided The quantization method and device of division.
To achieve the above object, the present invention uses following technical scheme:Sub-band division in a kind of audio coding bandwidth expansion Quantization method, comprise the following steps:
S1, it is N number of sampling point per frame for the high-frequency signal of training sample, it is any to being taken one by one between sampling point N in sampling point 1 Sampling point position m, high-frequency signal is divided into two subbands, calculates two subband sampling point standard deviation product Km[i], obtain one group of sampling point Standard difference-product vector { Sj[i],
{Sj[i]}={ K2,K3,K4,K5,....KN-1}
Wherein i=1, m=2,3,4,5 ... N-1, xjRepresent sampling point signal,WithRepresent that the arithmetic of two subband sampling points is put down Average,
If Km[i]For { Sj[i]In least member, then take m values to make sampling point point for the cut-point position of two subbands of division Cutpoint P [i]11=m11
S2, two subbands of formation are newly divided to step S1, take any sampling point position in the range of each sub-band division one by one M is put, each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and obtain two Group sampling point standard difference-product vector { Sj[i],
Wherein i=1,2, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband,
If Km[i]For { Sj[i]In least member, then take m21、m22It is worth to divide the cut-point position of two subbands, makes sample Point cut-point P [i]21=m21、P[i]22=m22
S3, to be formed four subbands are divided to new step S2, take any sampling point position in the range of each sub-band division one by one M is put, each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and obtain four Group sampling point standard difference-product vector { Sj[i],
Wherein i=1,2,3,4, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband, if Km[i] For { Sj[i]In least member, then take m31、m32、m33、m34It is worth to divide the cut-point position of four subbands, makes sampling point split Point P [i]31=m31、P[i]32=m32、P[i]33=m33、P[i]34=m34
S4, eight subbands of formation are newly divided to step S3, take any sampling point position in the range of each sub-band division one by one M is put, each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and obtain eight Group sampling point standard difference-product vector { Sj[i],
Wherein i=1,2,3,4,5,6,7,8, mSFor the starting position of i-th of subband, meFor the stop bits of i-th of subband Put, if Km[i]For { Sj[i]In least member, then take m41、m42、m43、m44、m45、m46、m47、m48It is worth for two subbands of division Cut-point position, make sampling point cut-point P [i]41=m41、P[i]42=m42、P[i]43=m43、P[i]44=m44、P[i]45=m45、P [i]46=m46、P[i]47=m47、P[i]48=m48, finally give 16 subbands newly divided.
Divided in described step S1, S2, S3 in the new subband formed, such as wherein any one subband only includes 1 sample Point, in the respective subsequent step of step S1, S2, S3, only the subband including 2 or more than 2 sampling points is divided, The new division number of sub-bands then exported in step s 4 is less than 16, and the quantity of sampling point cut-point is less than eight.
Every frame sampling point N of the step S1 is 256,512 or 1024.
The high-frequency signal of the training sample is 400,000 frames.
The device of sub-band division in a kind of audio coding bandwidth expansion, including the first sub-band division module, the second subband are drawn Sub-module, the 3rd sub-band division module, the 4th sub-band division module, wherein,
The first sub-band division module, for the high-frequency signal of input to be divided into 2 subbands, in the sampling point of two subbands Split under conditions of standard deviation product minimum, obtained two subband signals be output to the second sub-band division module, And obtain first time sampling point cut-point;
The second sub-band division module, for being divided into 2 sons according to by the input of the first sub-band division module The high-frequency signal of band, by each subband signal, row is divided into two subband signals, two new sons that each subband newly marks off again The sampling point standard deviation product of band is minimum, and is output to the 3rd sub-band division module, while obtains second of sampling point cut-point;
The 3rd sub-band division module, for being divided into 4 sons according to by the input of the second sub-band division module The high-frequency signal of band, each subband signal is further divided into two subband signals, two new subbands that each subband newly marks off Sampling point standard deviation product is minimum, and is output to the 4th sub-band division module, while obtains third time sampling point cut-point;
The 4th sub-band division module, for being divided into 8 sons according to by the input of the 3rd sub-band division module The high-frequency signal of band, each subband signal is further divided into two subband signals, two new subbands that each subband newly marks off Sampling point standard deviation product is minimum, obtains 16 subbands finally divided, while obtain the 4th sampling point cut-point.
The second sub-band division module, the 3rd sub-band division module, the 4th sub-band division module are received Subband sampling point be 1 when, then only to sampling point be more than 2 subband further split.
Compared with the prior art, the invention has the advantages that:The sub-band division method that the present invention uses takes into full account subband Statistical property in quantization, compared to Bark band or mode is evenly dividing, subjective hearing MOS of the invention points are slightly lifted, noise Than being obviously improved.
The invention will be further described with specific embodiment below in conjunction with the accompanying drawings.
Brief description of the drawings
The quantization method FB(flow block) that it is sub-band division in audio coding bandwidth expansion of the present invention that Fig. 1, which is,;
The quantization device schematic diagram that it is sub-band division in audio coding bandwidth expansion of the present invention that Fig. 2, which is,.
Embodiment
In order to more fully understand the technology contents of the present invention, technical scheme is entered with reference to specific embodiment One step introduction and explanation.
As shown in figure 1, in a kind of audio coding bandwidth expansion sub-band division quantization method, comprise the following steps:
Step S1, it is N number of sampling point per frame, in sampling point 1 between sampling point N for the high-frequency signal of the frame of training sample 400,000 Any sampling point position m is taken one by one, and high-frequency signal is divided into two subbands, calculates two subband sampling point standard deviation product Km[i], obtain To one group of sampling point standard difference-product vector { Sj[i],
{Sj[i]}={ K2,K3,K4,K5,....KN-1}
Wherein i=1, m=2,3,4,5 ... N-1, xjRepresent sampling point signal,WithRepresent the arithmetic average of two subbands Value,
If Km[i]For { Sj[i]In least member, then take m values to make sampling point point for the cut-point position of two subbands of division Cutpoint P [i]11=m11, then two new subbands, (see Figure 100) are obtained.
Step S2, two subbands of formation are newly divided to step S1, take any sample in the range of each sub-band division one by one Point position m, each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and To two groups of sampling point standard difference-product vector { Sj[i],
Wherein i=1,2, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband,
If Km[i]For { Sj[i]In least member, then take m21、m22It is worth to divide the cut-point position of two subbands, makes sample Point cut-point P [i]21=m21、P[i]22=m22Then obtain four new subbands (see Figure 200).
Step S3, to be formed four subbands are divided to new step S2, take any sample in the range of each sub-band division one by one Point position m, each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and To four groups of sampling point standard difference-product vector { Sj[i],
Wherein i=1,2,3,4, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband, if Km[i] For { Sj[i]In least member, then take m31、m32、m33、m34It is worth to divide the cut-point position of four subbands, makes sampling point split Point P [i]31=m31、P[i]32=m32、P[i]33=m33、P[i]34=m34, then obtain eight new subbands (see Figure 30 0).
Step S4, eight subbands of formation are newly divided to step S3, take any sample in the range of each sub-band division one by one Point position m, each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and To eight groups of sampling point standard difference-product vector { Sj[i],
Wherein i=1,2,3,4,5,6,7,8, mSFor the starting position of i-th of subband, meFor the stop bits of i-th of subband Put, if Km[i]For { Sj[i]In least member, then take m41、m42、m43、m44、m45、m46、m47、m48It is worth for two subbands of division Cut-point position, make sampling point cut-point P [i]41=m41、P[i]42=m42、P[i]43=m43、P[i]44=m44、P[i]45=m45、P [i]46=m46、P[i]47=m47、P[i]48=m48, finally give 16 subbands newly divided (see Figure 40 0).
In above-mentioned cutting procedure, there is a kind of special case, i.e. the new son formed is divided in step S1, S2, S3 It is possible to only contain a sampling point in band, the probability of even now is extremely low, and such as running into wherein any one subband only includes 1 sample Point, then the subband can not continue to split, continue behind in step, son that can only to including 2 or more than 2 sampling points Band is divided, then the new division subband final amt exported in step s 4 is less than 16, and the quantity of sampling point cut-point is few In eight.
High-frequency signal obtains signal sampling point cut-point P [i] through this method11=m11、P[i]21=m21、P[i]22=m22、P [i]31=m31、P[i]32=m32、P[i]33=m33、P[i]34=m34、P[i]41=m41、P[i]42=m42、P[i]43=m43、P [i]44=m44、P[i]45=m45、P[i]46=m46、P[i]47=m47、P[i]48=m48, in the audio coding bandwidth expansion to input Zhan Zhong, the cut-point using above-mentioned determination are split, and can obtain more preferable high frequency spectrum structure, closer to high frequency spectrum shape Shape, so as to improve high frequency spectrum reconstruction quality.
Specifically, step S1 every frame sampling point N is 256,512 or 1024.
Further, the high-frequency signal of the training sample is 400,000 frames.
As shown in Fig. 2 in a kind of audio coding bandwidth expansion sub-band division device, including the first sub-band division module 10th, the second sub-band division module 20, the 3rd sub-band division module 30, the 4th sub-band division module 40, wherein,
First sub-band division module 10, for the high-frequency signal of input to be divided into 2 subbands, in the sampling point mark of two subbands Split under conditions of accurate poor product minimum, obtained two subband signals are output to the second sub-band division module, and Obtain first time sampling point cut-point.
Second sub-band division module 20, for being divided into 2 subbands according to by the input of the first sub-band division module High-frequency signal, by each subband signal again row be divided into two subband signals, two new subbands that each subband newly marks off Sampling point standard deviation product it is minimum, and be output to the 3rd sub-band division module, while obtain second of sampling point cut-point.
The 3rd sub-band division module 30, for being divided into 4 according to by the input of the second sub-band division module The high-frequency signal of subband, each subband signal is further divided into two subband signals, two new subbands that each subband newly marks off Sampling point standard deviation product it is minimum, and be output to the 4th sub-band division module, while obtain third time sampling point cut-point.
The 4th sub-band division module 40, for being divided into 8 according to by the input of the 3rd sub-band division module The high-frequency signal of subband, each subband signal is further divided into two subband signals, two new subbands that each subband newly marks off Sampling point standard deviation product it is minimum, obtain 16 subbands finally divide, while the 4th sampling point cut-point of acquisition.
Above-mentioned sub-band division device obtains first time sampling point cut-point, second of sampling point cut-point, the segmentation of third time sampling point The 4th sampling point cut-point of point, in the audio coding bandwidth expansion to input, the cut-point using above-mentioned determination is split, More preferable high frequency spectrum reconstruction signal can be obtained, is reduced because frequency spectrum replicates the probability of medium-high frequency distortion spectrum.
Second sub-band division module 20, the 3rd sub-band division module 30, the 4th sub-band division module 40 are in institute In the case of when the subband sampling point of reception is 1, then only the subband that sampling point is more than 2 is further split, obtain sampling point point Cutpoint.
The technology contents described above that the present invention is only further illustrated with embodiment, in order to which reader is easier to understand, But embodiments of the present invention are not represented and are only limitted to this, any technology done according to the present invention extends or recreation, is sent out by this Bright protection.

Claims (6)

1. the quantization method of sub-band division in a kind of audio coding bandwidth expansion, it is characterised in that comprise the following steps:
S1, it is N number of sampling point per frame for the high-frequency signal of training sample, in sampling point 1 to taking any sampling point between sampling point N one by one Position m, high-frequency signal is divided into two subbands, calculates two subband sampling point standard deviation product Km[i], obtain one group of sampling point standard Difference-product vector { Sj[i],
<mrow> <msub> <mi>K</mi> <mrow> <mi>m</mi> <mrow> <mo>&amp;lsqb;</mo> <mi>i</mi> <mo>&amp;rsqb;</mo> </mrow> </mrow> </msub> <mo>=</mo> <mrow> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mi>m</mi> </mfrac> <munderover> <mi>&amp;Sigma;</mi> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>m</mi> </munderover> <msup> <mrow> <mo>(</mo> <mrow> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <mi>x</mi> <mo>&amp;OverBar;</mo> </mover> </mrow> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> </mrow> <mo>*</mo> <mrow> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <mo>(</mo> <mrow> <mi>N</mi> <mo>-</mo> <mi>m</mi> </mrow> <mo>)</mo> </mrow> </mfrac> <munderover> <mi>&amp;Sigma;</mi> <mrow> <mi>j</mi> <mo>=</mo> <mi>m</mi> <mo>+</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msup> <mrow> <mo>(</mo> <mrow> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <msup> <mi>x</mi> <mo>&amp;prime;</mo> </msup> <mo>&amp;OverBar;</mo> </mover> </mrow> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> </mrow> </mrow>
{Sj[i]}={ K2,K3,K4,K5,....KN-1}
Wherein i=1, m=2,3,4,5 ... N-1, xjRepresent sampling point signal,WithRepresent the arithmetic average of two subband sampling points Value,
If Km[i]For { Sj[i]In least member, then take m values for division two subbands cut-point position, make sampling point cut-point P [i]11=m11
S2, two subbands of formation are newly divided to step S1, take any sampling point position m in the range of each sub-band division one by one, Each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and obtain two groups of samples Point standard difference-product vector { Sj[i],
<mrow> <msub> <mi>K</mi> <mrow> <mi>m</mi> <mo>&amp;lsqb;</mo> <mi>i</mi> <mo>&amp;rsqb;</mo> </mrow> </msub> <mo>=</mo> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <mi>m</mi> <mo>-</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>1</mn> </mrow> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> </mrow> <mi>m</mi> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <mi>x</mi> <mo>&amp;OverBar;</mo> </mover> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> <mo>*</mo> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> <mo>-</mo> <mi>m</mi> </mrow> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mi>m</mi> <mo>+</mo> <mn>1</mn> </mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <msup> <mi>x</mi> <mo>&amp;prime;</mo> </msup> <mo>&amp;OverBar;</mo> </mover> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> </mrow>
{Sj[i]}={ Kms+1,Kms+2,....Kme-1}
Wherein i=1,2, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband,
If Km[i]For { Sj[i]In least member, then take m21、m22It is worth to divide the cut-point position of two subbands, makes sampling point point Cutpoint P [i]21=m21、P[i]22=m22
S3, to be formed four subbands are divided to new step S2, take any sampling point position m in the range of each sub-band division one by one, Each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and obtain four groups of samples Point standard difference-product vector { Sj[i],
<mrow> <msub> <mi>K</mi> <mrow> <mi>m</mi> <mo>&amp;lsqb;</mo> <mi>i</mi> <mo>&amp;rsqb;</mo> </mrow> </msub> <mo>=</mo> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <mi>m</mi> <mo>-</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>1</mn> </mrow> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> </mrow> <mi>m</mi> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <mi>x</mi> <mo>&amp;OverBar;</mo> </mover> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> <mo>*</mo> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> <mo>-</mo> <mi>m</mi> </mrow> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mi>m</mi> <mo>+</mo> <mn>1</mn> </mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <msup> <mi>x</mi> <mo>&amp;prime;</mo> </msup> <mo>&amp;OverBar;</mo> </mover> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> </mrow>
<mrow> <mo>{</mo> <msub> <mi>S</mi> <mrow> <mi>j</mi> <mrow> <mo>&amp;lsqb;</mo> <mi>i</mi> <mo>&amp;rsqb;</mo> </mrow> </mrow> </msub> <mo>}</mo> <mo>=</mo> <mo>{</mo> <msub> <mi>K</mi> <mrow> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>1</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>K</mi> <mrow> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>2</mn> </mrow> </msub> <mo>,</mo> <mn>....</mn> <msub> <mi>K</mi> <mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> <mo>-</mo> <mn>1</mn> </mrow> </msub> <mo>}</mo> </mrow>
Wherein i=1,2,3,4, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband, if Km[i]For {Sj[i]In least member, then take m31、m32、m33、m34It is worth to divide the cut-point position of four subbands, makes sampling point cut-point P [i]31=m31、P[i]32=m32、P[i]33=m33、P[i]34=m34
S4, eight subbands of formation are newly divided to step S3, take any sampling point position m in the range of each sub-band division one by one, Each subband is further subdivided into two new subbands, calculates the standard deviation product K of two new subband sampling pointsm[i], and obtain eight groups of samples Point standard difference-product vector { Sj[i],
<mrow> <msub> <mi>K</mi> <mrow> <mi>m</mi> <mo>&amp;lsqb;</mo> <mi>i</mi> <mo>&amp;rsqb;</mo> </mrow> </msub> <mo>=</mo> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <mi>m</mi> <mo>-</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>1</mn> </mrow> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> </mrow> <mi>m</mi> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <mi>x</mi> <mo>&amp;OverBar;</mo> </mover> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> <mo>*</mo> <mo>&amp;lsqb;</mo> <msqrt> <mrow> <mfrac> <mn>1</mn> <mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> <mo>-</mo> <mi>m</mi> </mrow> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>1</mn> </mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> </munderover> <msup> <mrow> <mo>(</mo> <msub> <mi>x</mi> <mi>j</mi> </msub> <mo>-</mo> <mover> <msup> <mi>x</mi> <mo>&amp;prime;</mo> </msup> <mo>&amp;OverBar;</mo> </mover> <mo>)</mo> </mrow> <mn>2</mn> </msup> </mrow> </msqrt> <mo>&amp;rsqb;</mo> </mrow>
<mrow> <mo>{</mo> <msub> <mi>S</mi> <mrow> <mi>j</mi> <mrow> <mo>&amp;lsqb;</mo> <mi>i</mi> <mo>&amp;rsqb;</mo> </mrow> </mrow> </msub> <mo>}</mo> <mo>=</mo> <mo>{</mo> <msub> <mi>K</mi> <mrow> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>1</mn> </mrow> </msub> <mo>,</mo> <msub> <mi>K</mi> <mrow> <msub> <mi>m</mi> <mi>s</mi> </msub> <mo>+</mo> <mn>2</mn> </mrow> </msub> <mo>,</mo> <mn>....</mn> <msub> <mi>K</mi> <mrow> <msub> <mi>m</mi> <mi>e</mi> </msub> <mo>-</mo> <mn>1</mn> </mrow> </msub> <mo>}</mo> </mrow>
Wherein i=1,2,3,4,5,6,7,8, mSFor the starting position of i-th of subband, meFor the end position of i-th of subband, if Km[i]For { Sj[i]In least member, then take m41、m42、m43、m44、m45、m46、m47、m48It is worth to divide the segmentation of two subbands Point position, makes sampling point cut-point P [i]41=m41、P[i]42=m42、P[i]43=m43、P[i]44=m44、P[i]45=m45、P [i]46=m46、P[i]47=m47、P[i]48=m48, finally give 16 subbands newly divided.
2. according to claim 1 in audio coding bandwidth expansion sub-band division quantization method, it is characterised in that the step Divided in rapid S1, S2, S3 in the new subband formed, such as wherein any one subband only includes 1 sampling point, in the step In the respective subsequent step of S1, S2, S3, only the subband including 2 or more than 2 sampling points is divided, then in step s 4 The new division number of sub-bands of output is less than 16, and the quantity of sampling point cut-point is less than eight.
3. according to claim 1 in audio coding bandwidth expansion sub-band division quantization method, it is characterised in that the step Rapid S1 every frame sampling point N is 256,512 or 1024.
4. according to claim 1 in audio coding bandwidth expansion sub-band division quantization method, it is characterised in that the instruction The high-frequency signal for practicing sample is 400,000 frames.
5. the device of sub-band division in a kind of audio coding bandwidth expansion, it is characterised in that including the first sub-band division module, Two sub-band division modules, the 3rd sub-band division module, the 4th sub-band division module, wherein,
The first sub-band division module, for the high-frequency signal of input to be divided into 2 subbands, in the sampling point standard of two subbands Split under conditions of poor product minimum, obtained two subband signals are output to the second sub-band division module, and obtain Obtain first time sampling point cut-point;
The second sub-band division module, for according to 2 subbands of being divided into by the first sub-band division module input High-frequency signal, by each subband signal, row is divided into two subband signals again, two new subbands that each subband newly marks off Sampling point standard deviation product is minimum, and is output to the 3rd sub-band division module, while obtains second of sampling point cut-point;
The 3rd sub-band division module, for according to 4 subbands of being divided into by the second sub-band division module input High-frequency signal, each subband signal is further divided into two subband signals, the sampling point for two new subbands that each subband newly marks off Standard deviation product is minimum, and is output to the 4th sub-band division module, while obtains third time sampling point cut-point;
The 4th sub-band division module, for according to 8 subbands of being divided into by the 3rd sub-band division module input High-frequency signal, each subband signal is further divided into two subband signals, the sampling point for two new subbands that each subband newly marks off Standard deviation product is minimum, obtains 16 subbands finally divided, while obtain the 4th sampling point cut-point.
6. according to claim 5 in audio coding bandwidth expansion sub-band division device, it is characterised in that it is described second son When the subband sampling point received with division module, the 3rd sub-band division module, the 4th sub-band division module is 1, then Only the subband that sampling point is more than 2 is further split.
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Publication number Priority date Publication date Assignee Title
EP0663740A2 (en) * 1994-01-18 1995-07-19 Daewoo Electronics Co., Ltd Apparatus for adaptively encoding input digital audio signals from a plurality of channels
CN101223570A (en) * 2005-07-15 2008-07-16 微软公司 Frequency segmentation to obtain bands for efficient coding of digital media
CN101292286A (en) * 2005-10-21 2008-10-22 诺基亚公司 Audio coding

Patent Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
EP0663740A2 (en) * 1994-01-18 1995-07-19 Daewoo Electronics Co., Ltd Apparatus for adaptively encoding input digital audio signals from a plurality of channels
CN101223570A (en) * 2005-07-15 2008-07-16 微软公司 Frequency segmentation to obtain bands for efficient coding of digital media
CN101292286A (en) * 2005-10-21 2008-10-22 诺基亚公司 Audio coding

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