CN104200043B - The design method of suspension stabiliser bar rubber bushing length - Google Patents
The design method of suspension stabiliser bar rubber bushing length Download PDFInfo
- Publication number
- CN104200043B CN104200043B CN201410476381.0A CN201410476381A CN104200043B CN 104200043 B CN104200043 B CN 104200043B CN 201410476381 A CN201410476381 A CN 201410476381A CN 104200043 B CN104200043 B CN 104200043B
- Authority
- CN
- China
- Prior art keywords
- mrow
- msub
- msubsup
- mfrac
- alpha
- Prior art date
- Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
- Expired - Fee Related
Links
Landscapes
- Other Investigation Or Analysis Of Materials By Electrical Means (AREA)
- Springs (AREA)
- Vehicle Body Suspensions (AREA)
Abstract
The present invention relates to the design method of suspension stabiliser bar rubber bushing length, belong to vehicle suspension technical field.Previous home and abroad fails to provide reliable resolution design method always to rubber bushing length.Present invention be characterized in that:According to the wheelspan of vehicle, the roll angular rigidity design requirement value of stabilizer bar system, end part of stabilizer rod deformation coefficient Gw, the radial rigidity expression formula K of rubber bushingx, the mathematical model of optimizing design of suspension stabiliser bar rubber bushing length is established, the optimization design value of rubber bushing length can be obtained using Matlab programs.Accurate, reliable rubber bushing length optimization design load is can obtain using this method, i.e., on the premise of design and production cost is not increased, only by the optimization design to rubber bushing length, stabilizer bar system can be made to reach the design requirement of roll angular rigidity;Meanwhile design and testing expenses can be reduced using this method, vehicle suspension design level is improved, improves vehicle ride performance and handling safety.
Description
Technical field
The present invention relates to the design method of vehicle suspension stabiliser bar, particularly suspension stabiliser bar rubber bushing length.
Background technology
QS is one of important composition part of vehicle suspension system, when Vehicular turn travels to prevent vehicle body
Excessive inclination occurs and rolls angular oscillation.QS is added in vehicle suspension system can reduce this cross side
Incline, if the forward and backward suspension roll angular rigidity distribution design of vehicle is improper, it will influence the steering characteristic of vehicle, general front suspension system
The roll angular rigidity of system is more than the roll angular rigidity of rear-suspension system.The roll angular rigidity of suspension system is not only tied by stabiliser bar
The influence of structure, diameter, while also by the length of rubber bushing, inner circle radius, exradius, material property and installation displacement
Etc. the influence of factor.It is however, theoretical due to being deformed analytical Calculation by rubber bushing radial deformation and end part of stabilizer rod vertical deviation
And the restriction to intercouple key issues of influence, the design for stablizing shank diameter and rubber bushing length, home and abroad at present
Fail to provide reliable resolution design method always.Home and abroad scholar is mostly to utilize simulation analysis software at present, to laterally steady
Fixed pole system variant and rigidity carry out Numerical Simulation Analysis, still, can only be to given structure and load using simulation analysis software
In the case of stabilizer bar system deformation and rigidity carry out simulating, verifying, no analytical formula, it is impossible to meet stabilizer bar system parse
Design and the requirement of modernization CAD design.
With the fast development of Vehicle Industry and the raising of travel speed, the design to suspension stabilizer bar system proposes more
High design requirement.How structure, diameter and the material property of stabiliser bar, and the material property of rubber bushing, inner circle given
Radius, exradius and two rubber bushing installation sites it is constant in the case of, i.e., do not increasing design and production cost premise
Under, only by the optimization design to rubber bushing length, stabilizer bar system can be made to reach the design requirement of roll angular rigidity, be
Enterprise's technical problem in the urgent need to address at present.Therefore, it is necessary to establish a kind of accurate, reliable suspension stabiliser bar rubber bushing
The design method of length, vehicle suspension design level is improved, on the premise of production cost is not increased, is served as a contrast by stabiliser bar rubber
Cover the optimization design of length so that stabilizer bar system reaches the design requirement of roll angular rigidity, improve vehicle ride performance and
Security.
The content of the invention
For defect present in above-mentioned prior art, the technical problems to be solved by the invention be to provide it is a kind of easy,
The design method of reliable suspension stabiliser bar rubber bushing length, its design flow diagram is as shown in figure 1, suspension stabilizer bar system
Structural representation, as shown in Figure 2.
In order to solve the above technical problems, the design method of suspension stabiliser bar rubber bushing length provided by the present invention, its
It is characterised by using following steps.
(1) the vertical deviation deformation coefficient G of end part of stabilizer rod is calculatedw:
According to the total length l of QSc, brachium l1, transition arc radius R, the central angle θ of transition arc, material bullet
Mounting distance l between property modulus E and Poisson's ratio μ, and two rubber bushings0, to the vertical deviation deformation coefficient G of end part of stabilizer rodw
Calculated, i.e.,:
In formula,
G6=-32 (μ+1) [R (cos θ -1)-l1sinθ]2[2l1cosθ-lc+2Rsinθ];
(2) rubber bushing RADIAL stiffness K is establishedxExpression formula:
Using rubber bushing length L as parameter to be designed, according to the diameter d of stabiliser bar, the inner circle radius of rubber bushing
ra, exradius rb, elastic modulus Ex, Poisson's ratio μx, establish rubber bushing RADIAL stiffness KxCalculation expression, i.e.,
Wherein, Kx(L) it is expression formula on rubber bushing length L;
Bessel correction functions:I(0,αb), K (0, αb);I(1,αb), K (1, αb);
I(1,αa), K (1, αa);I(0,αa), K (0, αa);
(3) foundation and design calculating of rubber bushing length L design mathematic models:
According to vehicle propons or the wheelspan B of back axle, the diameter d of stabiliser bar, total length lc, the installation between two rubber bushings
Distance l0, the design requirement value of stabilizer bar system roll angular rigidityResulting end part of stabilizer rod is calculated in step (1)
Vertical deviation deformation coefficient Gw, and the expression formula K for the rubber bushing radial direction Line stiffness established in step (2)x(L) rubber, is established
Liner sleeve length L mathematical model of optimizing design, i.e.,:
Using Matlab calculation procedures, above-mentioned mathematical modeling is solved, can be obtained in the structure of stabiliser bar, rubber bushing
Inner circle radius ra, exradius rbAnd in the case that installation site is all constant, meet stabilizer bar system roll angular rigidity design requirement
Rubber bushing length L optimization design value.
The present invention has the advantage that than prior art:
Due to being deformed analytical Calculation theory by rubber bushing radial deformation and end part of stabilizer rod vertical deviation and intercoupled
The restriction of key issues of influence, design of the home and abroad for stabiliser bar rubber bushing length at present, fail to provide reliably always
Resolution design method.Home and abroad scholar is mostly to utilize simulation analysis software at present, to QS system variant and just
Degree carries out Numerical Simulation Analysis, still, can only be to giving the stable leverage under structure and load condition using simulation analysis software
System deformation and rigidity carry out simulating, verifying, no analytical formula, it is impossible to meet that stabilizer bar system analytical design method and modernization CAD are set
The requirement of meter.The present invention is according to the wheelspan of vehicle, the roll angular rigidity design requirement value of stabilizer bar system, the change of end part of stabilizer rod
Shape coefficient, using rubber bushing length as parameter to be designed, the optimization for establishing suspension stabiliser bar rubber bushing length is set
Mathematical modeling is counted, the optimization design value of rubber bushing length can be obtained using Matlab programs.This method can exist to stabiliser bar
Given structure, diameter and material property, and the material property of rubber bushing, inner circle radius, exradius and two rubber bushings peace
In the case that holding position is constant, i.e., on the premise of design and production cost is not increased, only by the excellent of rubber bushing length
Change design, stabilizer bar system can be made to reach the design requirement of roll angular rigidity.Therefore, it is available accurately and reliably using this method
Rubber bushing length optimization design value, it is horizontal to improve vehicle suspension design, only logical on the premise of production cost is not increased
The optimization design of stabiliser bar rubber bushing length is crossed, stabilizer bar system can be made to reach the design requirement of roll angular rigidity;Meanwhile
Vehicle ride performance and handling safety can be improved.Therefore, the present invention designs for the Optimized Matching of suspension stabilizer bar system, carries
Reliable design method and technology are supplied.
Brief description of the drawings
In order to more fully understand that invention is described further below in conjunction with the accompanying drawings.
Fig. 1 is the design flow diagram of suspension stabiliser bar rubber bushing length;
Fig. 2 is the structural representation of lateral stability lever system;
Fig. 3 is the structural representation of rubber bushing;
Fig. 4 is the stabilizer bar system roll angular rigidity of embodiment one with the change curve of rubber bushing length;
Fig. 5 is the stabilizer bar system roll angular rigidity of embodiment three with the change curve of rubber bushing length.
Embodiment
The present invention is described in further detail below by embodiment.
Embodiment one:The wheelspan B=1600mm of certain vehicle propons, the structure of stabiliser bar is used, as shown in Fig. 2 wherein,
lcFor the total length of stabiliser bar, lc=800mm;l1For brachium, l1=150mm;l0Mounting distance between rubber bushing, l0=
400mm;R is transition arc radius, R=50mm;θ is transition arc central angle, θ=60 °;The elastic modulus E of stable bar material
=210GPa, Poisson's ratio μ=0.3.The structure of rubber bushing is as shown in figure 3, wherein, stabiliser bar 1, interior round buss cylinder 2, rubber lining
Set 3, outer round buss 4, the diameter d=20mm of stabiliser bar 1, the inner circle radius r of rubber bushing 3a=13mm, exradius rb=
30mm, elastic modulus Ex=7.84MPa, Poisson's ratio μx=0.47, the length L of rubber bushing is parameter to be designed.Before the vehicle
The design requirement value of the roll angular rigidity of suspension stabilizer bar systemStructure, rubber lining in stabiliser bar
The inner circle radius r of seta, exradius rbAnd in the case that installation site is constant, design is optimized to the length L of rubber bushing.
The design method for the suspension stabiliser bar rubber bushing length that present example is provided, its design cycle such as Fig. 1 institutes
Show, comprise the following steps that:
(1) the vertical deviation deformation coefficient G of end part of stabilizer rod is calculatedw:
According to the total length l of QSc=800mm, brachium l1=150mm, transition arc radius R=50mm, transition
Central angle θ=60 ° of circular arc;Elastic modulus E=210GPa, Poisson's ratio μ=0.3;And the locating distance between two rubber bushings
From l0=400mm, to the vertical deviation deformation coefficient G of end part of stabilizer rodwCalculated, i.e.,:
In formula,
G6=-32 (μ+1) [R (cos θ -1)-l1sinθ]2[2l1cosθ-lc+ 2Rsin θ]=- 0.5624m3;
(2) rubber bushing RADIAL stiffness K is establishedxExpression formula:
Using rubber bushing length L as parameter to be designed, according to the diameter d=20mm of stabiliser bar, rubber bushing it is interior
Radius of circle ra=13mm, exradius rb=30mm, elastic modulus Ex=7.84MPa, Poisson's ratio μx=0.47, establish rubber lining
Cover RADIAL stiffness KxCalculation expression, i.e.,:
Wherein, Kx(L) it is expression formula on rubber bushing length L;
Bessel correction functions:I(0,αb), K (0, αb);I(1,αb), K (1, αb);
I(1,αa), K (1, αa);I(0,αa), K (0, αa);
(3) foundation and design calculating of rubber bushing Design of length mathematical modeling:
According to the wheelspan B=1600mm of the vehicle propons, the diameter d=20mm of stabiliser bar, total length lc=800mm, two
Mounting distance l between rubber bushing0=400mm, the design requirement value of stabilizer bar system roll angular rigidityThe vertical deviation deformation coefficient G of end part of stabilizer rod obtained by being calculated in step (1)w=1.5935 ×
10-12m5The expression formula K for the rubber bushing radial direction Line stiffness established in/N, and step (2)x(L) rubber bushing length L, is established
Mathematical model of optimizing design, i.e.,:
Using Matlab calculation procedures, above-mentioned mathematical modeling is solved, can be obtained in the structure of stabiliser bar, rubber bushing
Inner circle radius ra, exradius rbAnd in the case that installation site is constant, meet stabilizer bar system roll angular rigidity design requirement
The optimization design value L=27mm of rubber bushing length.
Wherein, the structure in stabiliser bar, the inner circle radius r of rubber bushinga, exradius rbAnd the bar that installation site is constant
Under part, the roll angular rigidity design requirement value of the vehicle front suspension stabilizer bar system, with rubber bushing length L change curve,
As shown in Figure 4.
Embodiment two:It is the structural parameters of certain vehicle front suspension, the structural parameters of stabiliser bar, rubber bushing inner circle radius, outer
Radius of circle and material characteristic parameter, all identical with embodiment one, the simply inclination of the vehicle front suspension stabilizer bar system
Angular rigidityDesign requirement value, the difference with embodiment one, wherein,In other structures parameter not
In the case of change, design is optimized to rubber bushing length L, to meet the design requirement of stabilizer bar system roll angular rigidity.
Using the design procedure of embodiment one, the length L of the vehicle front suspension stabiliser bar rubber bushing is designed.By
The structural parameters of structural parameters, stabiliser bar in the vehicle front suspension and inner circle radius, exradius and the material of rubber bushing
Characterisitic parameter, all identical with embodiment one, the simply roll angular rigidity design requirement value and embodiment of stabilizer bar system
One differs.Therefore, in roll angular rigidity design requirement valueIn the case of, design the resulting car
The length L=42mm of front suspension rubber bushing.
Understood compared with embodiment one, due to roll angular rigidity design requirement value10kN.m/rad is added, then only
The length of rubber bushing is increased into 42mm by previous 27mm, you can in the case where not changing other structures parameter, obtain
To the stabilizer bar system for meeting the roll angular rigidity design requirement.
Embodiment three:The wheelspan B=1600mm of certain vehicle propons, stabiliser bar is used in addition to diameter d=21mm, its
Its structural parameters and mounting structure parameter and material characteristic parameter, it is all identical with embodiment one;The inner circle of rubber bushing
Radius ra=13.5mm, exradius rb=30mm;The elastic modulus E of rubber bushingx=7.84MPa, Poisson's ratio μx=0.47;
Length L is amount to be designed.The design requirement value of the roll angular rigidity of the vehicle front suspension stabilizer bar system
Under conditions of the given structure of stabiliser bar, the inner circle radius of rubber bushing, exradius and installation site, to rubber bushing
Length L is designed.
Using the design procedure of embodiment one, the length L of the vehicle front suspension stabiliser bar rubber bushing is designed.
(1) the vertical deviation deformation coefficient G of end part of stabilizer rod is calculatedw:
Due to the mounting distance l between horizontal stabilizer bar structure parameter, material characteristic parameter and two rubber bushings0, all
With applying the identical of example one, therefore, the vertical deviation deformation coefficient G of end part of stabilizer rodwIt is also identical with embodiment one,
I.e.:
(2) rubber bushing RADIAL stiffness K is establishedxExpression formula:
Using rubber bushing length L as parameter to be designed, according to the diameter d=21mm of stabiliser bar, rubber bushing it is interior
Radius of circle ra=13.5mm, exradius rb=30mm, elastic modulus Ex=7.84MPa, Poisson's ratio μx=0.47, establish rubber
Bushing RADIAL stiffness KxCalculation expression, i.e.,:
Wherein, Kx(L) it is expression formula on rubber bushing length L;
Bessel correction functions:I(0,αb), K (0, αb);I(1,αb), K (1, αb);
I(1,αa), K (1, αa);I(0,αa), K (0, αa);
(3) foundation and design calculating of rubber bushing Design of length mathematical modeling:
According to the wheelspan B=1600mm of propons, the diameter d=21mm of stabiliser bar, total length lc=800mm, two rubber lining
Mounting distance l between set0=400mm, the design requirement value of stabilizer bar system roll angular rigidityStep
Suddenly the vertical deviation deformation coefficient G of the end part of stabilizer rod obtained by being calculated in (1)w=1.5935 × 10-12m5/ N, and step (2)
Middle established rubber bushing radial direction Line stiffness expression formula Kx(L) rubber bushing length L design mathematic model, is established, i.e.,:
Using Matlab calculation procedures, above-mentioned mathematical modeling is solved, can be obtained in the structure of stabiliser bar, rubber bushing
Inner circle radius ra, exradius rbAnd in the case that installation site is all constant, meet stabilizer bar system roll angular rigidity design requirement
Rubber bushing length optimization design value L=25mm.
Wherein, the structure in stabiliser bar, the inner circle radius r of rubber bushinga, exradius rbAnd the bar that installation site is constant
Under part, the roll angular rigidity design requirement value of the vehicle front suspension stabilizer bar system, with rubber bushing length L change curve,
As shown in Figure 5.
Claims (1)
1. the design method of suspension stabiliser bar rubber bushing length, it is comprised the following steps that:
(1) the vertical deviation deformation coefficient G of end part of stabilizer rod is calculatedw:
According to the total length l of QSc, brachium l1, transition arc radius R, the central angle θ of transition arc, elastic properties of materials mould
Measure the mounting distance l between E and Poisson's ratio μ, and two rubber bushings0, to the vertical deviation deformation coefficient G of end part of stabilizer rodwCarry out
Calculate, i.e.,:
<mrow>
<msub>
<mi>G</mi>
<mi>w</mi>
</msub>
<mo>=</mo>
<mfrac>
<mrow>
<msub>
<mi>G</mi>
<mn>1</mn>
</msub>
<mo>+</mo>
<msub>
<mi>G</mi>
<mn>2</mn>
</msub>
<mo>+</mo>
<msub>
<mi>G</mi>
<mn>3</mn>
</msub>
<mo>+</mo>
<msub>
<mi>G</mi>
<mn>4</mn>
</msub>
<mo>+</mo>
<msub>
<mi>G</mi>
<mn>5</mn>
</msub>
<mo>+</mo>
<msub>
<mi>G</mi>
<mn>6</mn>
</msub>
</mrow>
<mi>&pi;E</mi>
</mfrac>
<mo>;</mo>
</mrow>
In formula,
<mrow>
<msub>
<mi>G</mi>
<mn>1</mn>
</msub>
<mo>=</mo>
<mfrac>
<msubsup>
<mrow>
<mn>64</mn>
<mi>l</mi>
</mrow>
<mn>1</mn>
<mn>3</mn>
</msubsup>
<mn>3</mn>
</mfrac>
<mo>,</mo>
<msub>
<mi>G</mi>
<mn>2</mn>
</msub>
<mo>=</mo>
<mo>-</mo>
<mfrac>
<mrow>
<mn>64</mn>
<mo>[</mo>
<msup>
<mrow>
<mo>(</mo>
<msub>
<mi>l</mi>
<mn>1</mn>
</msub>
<mi>cos</mi>
<mi>&theta;</mi>
<mo>+</mo>
<mi>R</mi>
<mi>sin</mi>
<mi>&theta;</mi>
<mo>)</mo>
</mrow>
<mn>3</mn>
</msup>
<mo>+</mo>
<mfrac>
<mn>1</mn>
<mn>8</mn>
</mfrac>
<msup>
<mrow>
<mo>(</mo>
<msub>
<mi>l</mi>
<mn>0</mn>
</msub>
<mo>-</mo>
<msub>
<mi>l</mi>
<mi>c</mi>
</msub>
<mo>)</mo>
</mrow>
<mn>3</mn>
</msup>
<mo>]</mo>
</mrow>
<mn>3</mn>
</mfrac>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>G</mi>
<mn>3</mn>
</msub>
<mo>=</mo>
<mn>64</mn>
<mi>R</mi>
<mo>[</mo>
<mfrac>
<mn>1</mn>
<mn>2</mn>
</mfrac>
<msubsup>
<mi>l</mi>
<mn>1</mn>
<mn>2</mn>
</msubsup>
<mrow>
<mo>(</mo>
<mi>&theta;</mi>
<mo>+</mo>
<mfrac>
<mrow>
<mi>sin</mi>
<mn>2</mn>
<mi>&theta;</mi>
</mrow>
<mn>2</mn>
</mfrac>
<mo>)</mo>
</mrow>
<mo>+</mo>
<mfrac>
<mn>1</mn>
<mn>2</mn>
</mfrac>
<msup>
<mi>R</mi>
<mn>2</mn>
</msup>
<mrow>
<mo>(</mo>
<mi>&theta;</mi>
<mo>-</mo>
<mfrac>
<mrow>
<mi>sin</mi>
<mn>2</mn>
<mi>&theta;</mi>
</mrow>
<mn>2</mn>
</mfrac>
<mo>)</mo>
</mrow>
<mo>+</mo>
<msub>
<mi>l</mi>
<mn>1</mn>
</msub>
<mi>R</mi>
<msup>
<mi>sin</mi>
<mn>2</mn>
</msup>
<mi>&theta;</mi>
<mo>]</mo>
<mo>,</mo>
<msub>
<mi>G</mi>
<mn>4</mn>
</msub>
<mo>=</mo>
<mfrac>
<mrow>
<msub>
<mrow>
<mn>8</mn>
<mi>l</mi>
</mrow>
<mn>0</mn>
</msub>
<msup>
<mrow>
<mo>(</mo>
<msub>
<mi>l</mi>
<mn>0</mn>
</msub>
<mo>-</mo>
<msub>
<mi>l</mi>
<mi>c</mi>
</msub>
<mo>)</mo>
</mrow>
<mn>2</mn>
</msup>
</mrow>
<mn>3</mn>
</mfrac>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>G</mi>
<mn>5</mn>
</msub>
<mo>=</mo>
<mn>64</mn>
<mi>R</mi>
<mrow>
<mo>(</mo>
<mi>&mu;</mi>
<mo>+</mo>
<mn>1</mn>
<mo>)</mo>
</mrow>
<mo>[</mo>
<msup>
<mi>R</mi>
<mn>2</mn>
</msup>
<mrow>
<mo>(</mo>
<mfrac>
<mrow>
<mn>3</mn>
<mi>&theta;</mi>
</mrow>
<mn>2</mn>
</mfrac>
<mo>+</mo>
<mfrac>
<mrow>
<mi>sin</mi>
<mn>2</mn>
<mi>&theta;</mi>
</mrow>
<mn>4</mn>
</mfrac>
<mo>-</mo>
<mn>2</mn>
<mi>sin</mi>
<mi>&theta;</mi>
<mo>)</mo>
</mrow>
<mo>+</mo>
<mfrac>
<mn>1</mn>
<mn>2</mn>
</mfrac>
<msubsup>
<mi>l</mi>
<mn>1</mn>
<mn>2</mn>
</msubsup>
<mrow>
<mo>(</mo>
<mi>&theta;</mi>
<mo>-</mo>
<mfrac>
<mrow>
<mi>sin</mi>
<mn>2</mn>
<mi>&theta;</mi>
</mrow>
<mn>2</mn>
</mfrac>
<mo>)</mo>
</mrow>
<mo>+</mo>
<msub>
<mrow>
<mn>4</mn>
<mi>l</mi>
</mrow>
<mn>1</mn>
</msub>
<mi>R</mi>
<msup>
<mi>sin</mi>
<mn>4</mn>
</msup>
<mfrac>
<mi>&theta;</mi>
<mn>2</mn>
</mfrac>
<mo>]</mo>
<mo>,</mo>
</mrow>
G6=-32 (μ+1) [R (cos θ -1)-l1sinθ]2[2l1cosθ-lc+2Rsinθ];
(2) rubber bushing RADIAL stiffness K is establishedxExpression formula:
Using rubber bushing length L as parameter to be designed, according to the diameter d of stabiliser bar, the inner circle radius r of rubber bushinga, outside
Radius of circle rb, elastic modulus Ex, Poisson's ratio μx, establish rubber bushing RADIAL stiffness KxCalculation expression, i.e.,
<mrow>
<msub>
<mi>K</mi>
<mi>x</mi>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<mfrac>
<mn>1</mn>
<mrow>
<mi>u</mi>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>+</mo>
<mi>y</mi>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
</mrow>
</mfrac>
<mo>;</mo>
</mrow>
Wherein, Kx(L) it is expression formula on rubber bushing length L;
<mrow>
<mi>u</mi>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<mfrac>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>+</mo>
<msub>
<mi>&mu;</mi>
<mi>x</mi>
</msub>
<mo>)</mo>
</mrow>
<mrow>
<mn>2</mn>
<mi>&pi;</mi>
<msub>
<mi>E</mi>
<mi>x</mi>
</msub>
<mi>L</mi>
</mrow>
</mfrac>
<mo>[</mo>
<mi>ln</mi>
<mfrac>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
</mfrac>
<mo>-</mo>
<mfrac>
<mrow>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mo>-</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
</mrow>
<mrow>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
</mrow>
</mfrac>
<mo>]</mo>
<mo>,</mo>
</mrow>
<mrow>
<mi>y</mi>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<msub>
<mi>a</mi>
<mn>1</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>0</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>+</mo>
<msub>
<mi>a</mi>
<mn>2</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>0</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>+</mo>
<msub>
<mi>a</mi>
<mn>3</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>+</mo>
<mfrac>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>+</mo>
<msub>
<mi>&mu;</mi>
<mi>x</mi>
</msub>
<mo>)</mo>
</mrow>
<mrow>
<mn>5</mn>
<mi>&pi;L</mi>
<msub>
<mi>E</mi>
<mi>x</mi>
</msub>
</mrow>
</mfrac>
<mo>[</mo>
<mi>ln</mi>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mo>+</mo>
<mfrac>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mrow>
<msubsup>
<mi>r</mi>
<mi>b</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
</mrow>
</mfrac>
<mo>]</mo>
<mo>,</mo>
</mrow>
αb=α rb,αa=α ra,
<mrow>
<mi>&alpha;</mi>
<mo>=</mo>
<mn>2</mn>
<msqrt>
<mn>15</mn>
</msqrt>
<mo>/</mo>
<mi>L</mi>
<mo>;</mo>
</mrow>
<mrow>
<msub>
<mi>a</mi>
<mn>1</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<mfrac>
<mrow>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>+</mo>
<msub>
<mi>&mu;</mi>
<mi>x</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>[</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<mrow>
<mo>(</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<mn>3</mn>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mo>)</mo>
</mrow>
<mo>-</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mrow>
<mo>(</mo>
<mn>3</mn>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mo>)</mo>
</mrow>
<mo>]</mo>
</mrow>
<mrow>
<mn>5</mn>
<mi>&pi;L</mi>
<msub>
<mi>E</mi>
<mi>x</mi>
</msub>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<mo>[</mo>
<msubsup>
<mi>r</mi>
<mi>b</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>]</mo>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>-</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>]</mo>
</mrow>
</mfrac>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>a</mi>
<mn>2</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<mfrac>
<mrow>
<mrow>
<mo>(</mo>
<msub>
<mi>&mu;</mi>
<mi>x</mi>
</msub>
<mo>+</mo>
<mn>1</mn>
<mo>)</mo>
</mrow>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<mrow>
<mo>(</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<mn>3</mn>
<msubsup>
<mi>r</mi>
<mi>b</mi>
<mn>2</mn>
</msubsup>
<mo>)</mo>
</mrow>
<mo>-</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mrow>
<mo>(</mo>
<mn>3</mn>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mo>)</mo>
</mrow>
<mo>]</mo>
</mrow>
<mrow>
<mn>5</mn>
<mi>&pi;</mi>
<msub>
<mi>E</mi>
<mi>x</mi>
</msub>
<mi>L</mi>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mrow>
<mo>(</mo>
<msubsup>
<mi>r</mi>
<mi>b</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>)</mo>
</mrow>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>-</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>]</mo>
</mrow>
</mfrac>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>a</mi>
<mn>3</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<mo>-</mo>
<mfrac>
<mrow>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>+</mo>
<msub>
<mi>&mu;</mi>
<mi>x</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>[</mo>
<msub>
<mi>b</mi>
<mn>1</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>+</mo>
<msub>
<mi>b</mi>
<mn>2</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>+</mo>
<msub>
<mi>b</mi>
<mn>3</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>]</mo>
</mrow>
<mrow>
<mn>5</mn>
<mi>&pi;L</mi>
<msub>
<mi>E</mi>
<mi>x</mi>
</msub>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mrow>
<mo>(</mo>
<msubsup>
<mi>r</mi>
<mi>b</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>)</mo>
</mrow>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>-</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>]</mo>
</mrow>
</mfrac>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>b</mi>
<mn>1</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<mrow>
<mo>(</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<mn>3</mn>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mo>)</mo>
</mrow>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>0</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>+</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>0</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>]</mo>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>b</mi>
<mn>2</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<mo>-</mo>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mrow>
<mo>(</mo>
<msup>
<msub>
<mi>r</mi>
<mi>b</mi>
</msub>
<mn>2</mn>
</msup>
<mo>+</mo>
<mn>3</mn>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>)</mo>
</mrow>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>0</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>+</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>0</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>]</mo>
<mo>,</mo>
</mrow>
<mrow>
<msub>
<mi>b</mi>
<mn>3</mn>
</msub>
<mrow>
<mo>(</mo>
<mi>L</mi>
<mo>)</mo>
</mrow>
<mo>=</mo>
<msub>
<mi>&alpha;r</mi>
<mi>b</mi>
</msub>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<mo>[</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<mrow>
<mo>(</mo>
<msubsup>
<mi>r</mi>
<mi>b</mi>
<mn>2</mn>
</msubsup>
<mo>+</mo>
<msubsup>
<mi>r</mi>
<mi>a</mi>
<mn>2</mn>
</msubsup>
<mo>)</mo>
</mrow>
<mi>ln</mi>
<msub>
<mi>r</mi>
<mi>a</mi>
</msub>
<mo>]</mo>
<mo>[</mo>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>-</mo>
<mi>K</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>a</mi>
</msub>
<mo>)</mo>
</mrow>
<mi>I</mi>
<mrow>
<mo>(</mo>
<mn>1</mn>
<mo>,</mo>
<msub>
<mi>&alpha;</mi>
<mi>b</mi>
</msub>
<mo>)</mo>
</mrow>
<mo>]</mo>
<mo>;</mo>
</mrow>
Bessel correction functions:I(0,αb), K (0, αb);I(1,αb), K (1, αb);
I(1,αa), K (1, αa);I(0,αa), K (0, αa);
(3) foundation and design calculating of rubber bushing length L design mathematic models:
According to vehicle propons or the wheelspan B of back axle, the diameter d of stabiliser bar, total length lc, the mounting distance between two rubber bushings
l0, the design requirement value of stabilizer bar system roll angular rigidityThe vertical of resulting end part of stabilizer rod is calculated in step (1)
Displacement deformation coefficient Gw, and the expression formula K for the rubber bushing radial direction Line stiffness established in step (2)x(L) rubber bushing, is established
Length L mathematical model of optimizing design, i.e.,:
Using Matlab calculation procedures, above-mentioned mathematical modeling is solved, structure, the inner circle of rubber bushing in stabiliser bar can be obtained
Radius ra, exradius rbAnd in the case that installation site is all constant, meet the rubber of stabilizer bar system roll angular rigidity design requirement
Glue liner sleeve length L optimization design value.
Priority Applications (1)
Application Number | Priority Date | Filing Date | Title |
---|---|---|---|
CN201410476381.0A CN104200043B (en) | 2014-09-18 | 2014-09-18 | The design method of suspension stabiliser bar rubber bushing length |
Applications Claiming Priority (1)
Application Number | Priority Date | Filing Date | Title |
---|---|---|---|
CN201410476381.0A CN104200043B (en) | 2014-09-18 | 2014-09-18 | The design method of suspension stabiliser bar rubber bushing length |
Publications (2)
Publication Number | Publication Date |
---|---|
CN104200043A CN104200043A (en) | 2014-12-10 |
CN104200043B true CN104200043B (en) | 2018-04-10 |
Family
ID=52085336
Family Applications (1)
Application Number | Title | Priority Date | Filing Date |
---|---|---|---|
CN201410476381.0A Expired - Fee Related CN104200043B (en) | 2014-09-18 | 2014-09-18 | The design method of suspension stabiliser bar rubber bushing length |
Country Status (1)
Country | Link |
---|---|
CN (1) | CN104200043B (en) |
Citations (4)
Publication number | Priority date | Publication date | Assignee | Title |
---|---|---|---|---|
JP2002019437A (en) * | 2000-07-04 | 2002-01-23 | Daihatsu Motor Co Ltd | Rear suspension |
CN200958539Y (en) * | 2006-07-07 | 2007-10-10 | 中国第一汽车集团公司 | Composite rubber lining |
CN101462476A (en) * | 2009-01-12 | 2009-06-24 | 奇瑞汽车股份有限公司 | Torsion beam type suspension fork |
CN102758871A (en) * | 2012-07-17 | 2012-10-31 | 山东理工大学 | Radial deformation superposition analysis calculation method for car stabilizer bar rubber bushing |
-
2014
- 2014-09-18 CN CN201410476381.0A patent/CN104200043B/en not_active Expired - Fee Related
Patent Citations (4)
Publication number | Priority date | Publication date | Assignee | Title |
---|---|---|---|---|
JP2002019437A (en) * | 2000-07-04 | 2002-01-23 | Daihatsu Motor Co Ltd | Rear suspension |
CN200958539Y (en) * | 2006-07-07 | 2007-10-10 | 中国第一汽车集团公司 | Composite rubber lining |
CN101462476A (en) * | 2009-01-12 | 2009-06-24 | 奇瑞汽车股份有限公司 | Torsion beam type suspension fork |
CN102758871A (en) * | 2012-07-17 | 2012-10-31 | 山东理工大学 | Radial deformation superposition analysis calculation method for car stabilizer bar rubber bushing |
Also Published As
Publication number | Publication date |
---|---|
CN104200043A (en) | 2014-12-10 |
Similar Documents
Publication | Publication Date | Title |
---|---|---|
CN104200040A (en) | Design method for stiffness matching and diameter of vehicle suspension stabilizer bars | |
CN101826125B (en) | Method for designing McPherson suspension | |
CN104182597A (en) | Vehicle suspension roll angle rigidity checking method | |
CN102758871A (en) | Radial deformation superposition analysis calculation method for car stabilizer bar rubber bushing | |
CN104200043B (en) | The design method of suspension stabiliser bar rubber bushing length | |
CN104200050B (en) | The design method of suspension stabiliser bar rubber bushing thickness | |
CN104175831B (en) | The design method of the inner circle sleeve thickness of suspension stabiliser bar rubber bushing | |
CN104268357A (en) | Design method for diameter of coaxial cab stabilizer bar | |
CN104281759B (en) | The design method of interior biasing non-coaxial driver's cabin stabiliser bar rubber sleeve length | |
CN104281758B (en) | The design method of the torsion tube length of interior biasing non-coaxial driver's cabin stabilizer bar system | |
CN104239638B (en) | Suspension stabiliser bar rubber bushing clipping room away from design method | |
CN104331576B (en) | The design method of the torsion tube length of outer biasing non-coaxial driver's cabin stabiliser bar | |
CN104239657B (en) | Coaxial-type driver's cabin stabiliser bar suspension clipping room away from design method | |
CN104331575A (en) | Method for designing external offset of torsion pipe of external biasing non-coaxial cab stabilizer bar | |
CN104268362B (en) | The design method of coaxial-type driver's cabin stabiliser bar pendulum arm length | |
CN104268360B (en) | The design method of coaxial-type driver's cabin stabiliser bar rubber sleeve exradius | |
CN104281760B (en) | The design method of the torsion tube interior biasing amount of interior biasing non-coaxial driver's cabin stabiliser bar | |
CN104361175B (en) | The design method of the torsion tube internal diameter of outer biasing non-coaxial driver's cabin stabiliser bar | |
CN104361164A (en) | Design method for torque tube outer diameter of internal bias non-coaxial cab stabilizer bar system | |
CN104346497B (en) | The design method of interior biasing non-coaxial driver's cabin stabilizer bar system torsion tube internal diameter | |
CN104268359B (en) | The design method of coaxial-type driver's cabin stabiliser bar rubber sleeve length | |
CN104200123A (en) | Method for calculating rigidity of transverse stabilizer bar system on basis of radial deformation of rubber bushing | |
CN104331578B (en) | The design method of outer biasing non-coaxial driver's cabin stabiliser bar rubber sleeve length | |
CN104252568B (en) | The design method of coaxial-type driver's cabin stabilizer bar system torsion tube wall thickness | |
CN104268361B (en) | The design method of coaxial-type driver's cabin stabiliser bar rubber sleeve inner circle radius |
Legal Events
Date | Code | Title | Description |
---|---|---|---|
C06 | Publication | ||
PB01 | Publication | ||
C10 | Entry into substantive examination | ||
SE01 | Entry into force of request for substantive examination | ||
GR01 | Patent grant | ||
GR01 | Patent grant | ||
CF01 | Termination of patent right due to non-payment of annual fee | ||
CF01 | Termination of patent right due to non-payment of annual fee |
Granted publication date: 20180410 Termination date: 20200918 |