CN103838966B - A kind of modeling and simulating method based on half-bridge submodule voltage source converter - Google Patents

A kind of modeling and simulating method based on half-bridge submodule voltage source converter Download PDF

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CN103838966B
CN103838966B CN201410067803.9A CN201410067803A CN103838966B CN 103838966 B CN103838966 B CN 103838966B CN 201410067803 A CN201410067803 A CN 201410067803A CN 103838966 B CN103838966 B CN 103838966B
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mrow
msub
bridge
submodule
voltage
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CN103838966A (en
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郭高朋
温家良
尤夏
吴广禄
杨杰
药韬
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State Grid Corp of China SGCC
Smart Grid Research Institute of SGCC
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State Grid Corp of China SGCC
Smart Grid Research Institute of SGCC
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Abstract

The present invention relates to the emulation mode in direct current transportation field, and in particular to a kind of modeling and simulating method based on half-bridge submodule voltage source converter.This method comprises the steps:(1)Half-bridge submodule and the equivalent circuit and mathematical modeling of submodule group are set up, equivalent circuit is simulated three kinds of working conditions of half-bridge submodule and half-bridge submodule group;(2)Mathematical modeling to half-bridge submodule group simplifies, and determines the equivalent circuit of each bridge arm and the working condition of each bridge arm.The method that the present invention is provided can select different equivalent circuit and mathematical modeling for different research contents;The equivalent circuit and mathematical modeling are simple, easily realize, simulation accuracy is high.

Description

A kind of modeling and simulating method based on half-bridge submodule voltage source converter
Technical field
The present invention relates to the emulation mode in direct current transportation field, and in particular to one kind is based on half-bridge submodule voltage source unsteady flow The modeling and simulating method of device.
Background technology
With the development of Power Electronic Technique, direct current transportation(High Voltage Direct Current,HVDC)With it Inherent advantages, substantial amounts of application is obtained in power system.Changed relative to the well-known line voltage commutation based on IGCT Flow device(Line-Commutated Convertor), the voltage source converter based on IGBT(Voltage Source Convertor, VSC)It is more advantageous.Wherein, modular multi-level converter(Modular Multilevel Convertor,MMC)Extensive concern is obtained, its advantage includes:1. modularized design, voltage class and capacity are easier to expand Exhibition;, just can be with incoming transport system without installing wave filter additional 2. AC voltage distortion rate is smaller;3. power device and driving are very Maturation, reliability is of a relatively high.But, when studying the MMC of high-voltage large-capacity, because submodule number is especially huge, if adopting With the simulation model based on power electronic devices, then simulation velocity is especially slow, or even can not emulate, when research is based on the more of MMC When holding DC transmission system and direct current network, situation is just worse.
Nearly one or two years, someone is in research MMC simplification simulation model, and a document is by two IGBT in submodule (Containing FWD)Two variable resistors are equivalent to, for putting into and cutting off electric capacity.Further, it is bridge arm is equivalent by Dai Weinan, letter A voltage source and resistance are turned to, the interstitial content of artificial circuit is greatly reduced.But this simplification is to be directed to steady-state operation When MMC, and need to consider that trigger pulse distribution and capacitance voltage are balanced, simplify algorithm realize it is very complicated.Other texts The resolving ideas offered is similar with the document.One document proposes a kind of MMC simplified model, and bridge arm equivalent is controllable into one Voltage source, the electrical link of alternating current-direct current side realizes that this simplified model have ignored the fluctuation of capacitance voltage by controllable current source Circulation between process, therefore bridge arm is just not present;The emulation of DC Line Fault process is inaccurate, it is impossible to emulate charging process.
The content of the invention
In view of the shortcomings of the prior art, it is an object of the invention to provide a kind of based on half-bridge submodule voltage source converter Modeling and simulating method, this method establishes half-bridge submodule(Group)Equivalent circuit and mathematical modeling, half-bridge can be simulated Submodule(Group)Three kinds of working conditions;To half-bridge submodule(Group)Equivalent circuit and mathematical modeling carried out it is different degrees of Simplify, unconcerned control, such as voltage modulated, Pressure and Control algorithm, loop current suppression algorithm can be ignored, therefore can be directed to Different research contents selects different equivalent circuit and mathematical modeling;The equivalent circuit and mathematical modeling are simple, easily realize, Simulation accuracy is high.
The purpose of the present invention is realized using following technical proposals:
A kind of modeling and simulating method based on half-bridge submodule voltage source converter of the present invention, the voltage source converter by Three-phase is constituted, and is constituted per by two bridge arms up and down, each bridge arm is made up of half-bridge sub-module cascade, and each half-bridge submodule includes IGBT module branch road and capacitor branches in parallel, the IGBT module composition of the IGBT module branch route series connection, each IGBT Module is constituted by IGBT device and with its antiparallel diode;It thes improvement is that methods described comprises the steps:
(1)Half-bridge submodule and the equivalent circuit and mathematical modeling of submodule group are set up, equivalent circuit is simulated half-bridge Three kinds of working conditions of module and half-bridge submodule group;Each half-bridge submodule group at least includes 2 half-bridge submodules of series connection;
(2)Mathematical modeling to half-bridge submodule group simplifies, and determines the equivalent circuit and each bridge of each bridge arm The working condition of arm.
Further, the step(1)In, the equivalent circuit of the half-bridge submodule includes equivalent loss caused by electric current Conductance r, two diode Dp and Dn, switch SW and voltage source Vo;Branch road and voltage after diode Dp and the Dn series connection Source VoParallel connection, the switch SW is in parallel with diode Dp;Equivalent loss resistance r caused by the electric current be connected to diode Dp and Between Dn;
The mathematical modeling of the half-bridge submodule is as follows:
Vo=S × Vc<2>;
Wherein:C is the electric capacity in submodule;S is the switching signal of submodule;G is equivalent loss conductance caused by voltage; icIt is the charging and discharging currents of electric capacity;Vc(0_) is the initial value of submodule capacitor voltage;VcIt is the capacitance voltage in submodule;Vo It is the output voltage of submodule;
Further, the step(1)In, three kinds of working conditions of the half-bridge submodule include:
Blocking:Switch SW to open, S=1;During i > 0, electric current flows through Dp, submodule is electrically charged formula<1>, output voltage For VcFormula<2>;During i < 0, electric current flows through Dn, output voltage is 0;Wherein i flows through half-bridge submodule or half-bridge submodule group Electric current;
Unblock lock status:Switch SW closures;During S=1, submodule is put into, and electric capacity is charged or discharged formula<1>, output voltage For VcFormula<2>;During S=0, submodule is removed, and electric capacity will not be charged or discharged formula<1>, output voltage is 0, i.e. formula<2>;
Half blocking:Switch SW to open, i < 0, electric current flows through Dn, output voltage is 0;I > 0 and during S=0, output electricity Press as 0, i.e. formula<2>, electric capacity will not be electrically charged formula<1>;I > 0 and during S=1, output voltage is Vc, i.e. formula<2>, electric capacity filled Electric-type<1>.
Further, the step(1)In, the equivalent circuit I of half-bridge submodule group includes electric current in each submodule and caused Equivalent loss resistance sum R, two diodes Dp and Dn, switch SW and voltage source Vo1、Vo2……VoN;The diode Composition diode branch road after Dp and Dn series connection;Voltage source Vo1、Vo2……VoNVoltage source branch road is constituted after series connection;Described two grades Pipe branch road and voltage source branch circuit parallel connection;The switch SW is in parallel with diode Dp;It is equivalent caused by electric current in each submodule Loss resistance R is connected between diode Dp and Dn;
The mathematical modeling of the equivalent circuit I of the half-bridge submodule group is as follows:
Voj=Sj×Voj<4>;
Wherein:Vcj, Voj, Sj, gj, Vcj(0_) is respectively the capacitance voltage of j-th of half-bridge submodule, output voltage, switching Signal, equivalent loss conductance and capacitance voltage initial value caused by voltage;
Three kinds of working conditions of half-bridge submodule group are identical with three kinds of working conditions of half-bridge submodule.
Further, the step(1)In, the equivalent circuit II of half-bridge submodule group includes electric current in each submodule and caused Equivalent loss resistance sum R, two diodes Dp and Dn, switch SW and voltage source VGO;Diode Dp and the Dn series connection The branch road of composition afterwards and voltage source VGOIt is in parallel;The switch SW is in parallel with diode Dp;Electric current in each half-bridge submodule Caused equivalent loss resistance R is connected between diode Dp and Dn;
(One)The mathematical modeling I of the equivalent circuit II of half-bridge submodule group is as follows:
Wherein:VGoFor the total output voltage of each submodule;
(Two)The mathematical modeling II of the equivalent circuit II of half-bridge submodule group is as follows:
1. voltage of all half-bridge submodules including initial value is equal:
Wherein:N indicates N number of submodule;
2. because loss caused by voltage is identical, i.e.,:
Some time is carved with n half-bridge submodule and is in input state, to formula<7>In half-bridge submodule capacitor voltage asked With obtain:
Further, the step(2)In, the mathematical modeling II to half-bridge submodule group is simplified as:
Formula<6>It is rewritten as:
Wherein:Represent that half-bridge submodule includes the voltage of initial value;
Order:
Wherein:M represents modulation ratio;
Then formula<5>And formula<6>It is rewritten as:
VGo=m × VGc<13>;
Wherein:CGIt is the equivalent capacity of half-bridge submodule group, is numerically equal to the series connection of half-bridge submodule capacitor voltage Capacitance;VGcIt is the capacitance voltage sum in half-bridge submodule group;
Mathematical modeling II neglects bridge arm half-bridge submodule capacitor voltage and the loss as caused by voltage in the process of running Difference, simplify control process, it is not necessary to consider that capacitance voltage inside half-bridge submodule group is balanced and trigger pulse is distributed Control;Modulation ratio m is obtained by modulation algorithm, order:
Formula<14>Middle VacrefFor the reference value of half-bridge submodule group output voltage AC compounent;VdcrefFor half-bridge submodule The reference value of group output voltage DC component;VacrefAnd VdcrefValue ensure m value in [0,1].
Further, the step(2)In, the equivalent circuit of each bridge arm includes two diode D1And D2, switch SW and Controllable voltage source Vo;The diode D1And D2Branch road and controllable voltage source V after series connectionoIt is in parallel;The switch SW and diode D1It is in parallel;
The working condition of each bridge arm is as follows:
When flowing through the electric current i > 0 of bridge arm, bridge arm output voltage is submodule capacitor voltage sum, each submodule The electric current i chargings of bridge arm will be flowed through, order is adjusted to compare m=1;When flowing through the electric current i < 0 of bridge arm, all submodule electricity Appearance is all bypassed, and is added a diode, controllable voltage source is bypassed, the simple equivalent circuit of bridge arm can be closed to bridge arm Lock status is conciliate blocking and emulated, the expression formula such as formula of controllable voltage source and controllable current source<15>It is shown:
A, when switch SW be off when, bridge arm simple equivalent circuit can simulate the blocking of bridge arm, make m= 1, as electric current i > 0, electric current flows through diode D1, controllable voltage source charging is given, now i0=i;As electric current i < 0, electric current stream Cross diode D2, controllable voltage source is bypassed, now i0=0, controllable voltage source will not be electrically charged;
B, when switching SW and being in closure state, what bridge arm simplified that circuit can simulate bridge arm unblocks lock status, due to can Control the output voltage V of voltage sourceo> 0, therefore diode D2It is reversed by diode D1Be switched on and off SW bypass, no matter electric current i Direction how, have i0=i, unblocking and latching process for bridge arm is simulated with turning on and off for switch SW.
Compared with the prior art, the beneficial effects of the invention are as follows:
1st, modeling and simulating method proposed by the invention, establishes half-bridge submodule(Group)Equivalent circuit and mathematical modulo Type, can simulate half-bridge submodule(Group)Three kinds of working conditions;To half-bridge submodule(Group)Equivalent circuit and mathematics Model has carried out different degrees of simplification, can ignore unconcerned control, such as voltage modulated, Pressure and Control algorithm, circulation Restrainable algorithms, therefore different equivalent circuit and mathematical modeling can be selected for different research contents;The equivalent circuit and Mathematical modeling is simple, easily realizes, simulation accuracy is high.
2nd, modeling and simulating method proposed by the invention, submodule and submodule group are calculated using the mode of numerical integration Capacitance voltage, it is to avoid solving circuit matrix, greatly improved the simulation velocity of circuit.
3rd, modeling and simulating method proposed by the invention, is greatly reduced the use of nonlinear device, electricity is greatly reduced The interstitial content on road, reduces the solution difficulty of circuit matrix, so as to improve simulation velocity.
4th, modeling and simulating method proposed by the invention, can set up the simulation model of different simplified degree, for studying Different contents.
Brief description of the drawings
Fig. 1 is the equivalent circuit diagram for the half-bridge submodule that the present invention is provided;
Fig. 2 is the figure of equivalent circuit I for the half-bridge submodule group that the present invention is provided;
Fig. 3 is the figure of equivalent circuit II for the half-bridge submodule group that the present invention is provided;
Fig. 4 is the bridge arm simple equivalent circuit figure that the present invention is provided;
Fig. 5 is the flow chart for the modeling and simulating method based on half-bridge submodule voltage source converter that the present invention is provided;
Fig. 6 is the structure chart of half-bridge submodule;
Fig. 7 is the structure chart of half-bridge submodule group.
Embodiment
The embodiment to the present invention is described in further detail below in conjunction with the accompanying drawings.
The present invention provides a kind of modeling and simulating method based on half-bridge submodule voltage source converter, and this method establishes half The equivalent circuit and mathematical modeling of bridge submodule and half-bridge submodule group, can simulate half-bridge submodule and half-bridge submodule Three kinds of working conditions of group;The equivalent circuit and mathematical modeling of half-bridge submodule and half-bridge submodule group have been carried out in various degree Simplification, unconcerned control, such as voltage modulated can be ignored, Pressure and Control algorithm, loop current suppression algorithm, therefore can be with pin Different equivalent circuit and mathematical modeling are selected to different research contents;The equivalent circuit and mathematical modeling are simple, easily real Existing, simulation accuracy is high.The voltage source converter is made up of three-phase, is constituted per by two bridge arms up and down, each bridge arm is by half-bridge Sub-module cascade is constituted, and each half-bridge submodule includes IGBT module branch road and capacitor branches in parallel, the IGBT module The IGBT module composition of branch route series connection, each IGBT module is constituted by IGBT device and with its antiparallel diode;Device Structure chart is as shown in fig. 6, each half-bridge submodule group at least includes 2 half-bridge submodules of series connection;Its structure chart such as Fig. 7 institutes Show.
The flow chart of this method is as shown in figure 5, comprise the steps:
(1)Half-bridge submodule and the equivalent circuit and mathematical modeling of submodule group are set up, equivalent circuit is simulated half-bridge Three kinds of working conditions of module and half-bridge submodule group;
The equivalent circuit structure figure of the half-bridge submodule as shown in figure 1, including equivalent loss resistance r caused by electric current, Two diode Dp and Dn, switch SW and voltage source Vo;Branch road and voltage source V after diode Dp and the Dn series connectionoAnd Connection, the switch SW is in parallel with diode Dp;Equivalent loss resistance r caused by the electric current be connected to diode Dp and Dn it Between;
The mathematical modeling of the half-bridge submodule is as follows:
Vo=S × Vc<2>;
Wherein:C is the electric capacity in submodule;S is the switching signal of submodule;G is equivalent loss conductance caused by voltage; icIt is the charging and discharging currents of electric capacity;Vc(0_) is the initial value of submodule capacitor voltage;VcIt is the capacitance voltage in submodule;Vo It is the output voltage of submodule;
The step(1)In, three kinds of working conditions of the half-bridge submodule include:
Blocking:Switch SW to open, S=1;During i > 0, electric current flows through Dp, submodule is electrically charged formula<1>, output voltage For VcFormula<2>;During i < 0, electric current flows through Dn, output voltage is 0;Wherein i flows through half-bridge submodule or half-bridge submodule group Electric current;
Unblock lock status:Switch SW closures;During S=1, submodule is put into, and electric capacity is charged or discharged formula<1>, output voltage For VcFormula<2>;During S=0, submodule is removed, and electric capacity will not be charged or discharged formula<1>, output voltage is 0, i.e. formula<2>;
Half blocking:Switch SW to open, i < 0, electric current flows through Dn, output voltage is 0;I > 0 and during S=0, output electricity Press as 0, i.e. formula<2>, electric capacity will not be electrically charged formula<1>;I > 0 and during S=1, output voltage is Vc, i.e. formula<2>, electric capacity filled Electric-type<1>.
In the equivalent circuit of submodule, submodule by equivalent into controllable voltage source and some ancillary circuit elements, The discharge and recharge of the voltage and electric capacity of controllable voltage source is controlled by the switching signal S of submodule, and capacitance voltage is by electric current and switching Signal S integrations are obtained, and it is a numerical value, rather than an electrical node, therefore, it can greatly reduce non-linear device in circuit The quantity of part and the number of electrical node, so as to reduce the solution difficulty of circuit.
The step(1)In, the structure chart of the equivalent circuit I of half-bridge submodule group is as shown in Fig. 2 including in each submodule Equivalent loss resistance sum R, two diode Dp and Dn, switch SW and voltage source V caused by electric currento1、Vo2……VoN;Institute State the composition diode branch road after diode Dp and Dn series connection;Voltage source Vo1、Vo2……VoNVoltage source branch road is constituted after series connection; The diode branch road and voltage source branch circuit parallel connection;The switch SW is in parallel with diode Dp;Electric current draws in each submodule The equivalent loss resistance R risen is connected between diode Dp and Dn;
The mathematical modeling of the equivalent circuit I of the half-bridge submodule group is as follows:
Voj=Sj×Voj<4>;
Wherein:Vcj, Voj, Sj, gj, Vcj(0_) is respectively the capacitance voltage of j-th of half-bridge submodule, output voltage, switching Signal, equivalent loss conductance and capacitance voltage initial value caused by voltage;
Three kinds of working conditions of half-bridge submodule group are identical with three kinds of working conditions of half-bridge submodule.
The step(1)In, the structure chart of the equivalent circuit II of half-bridge submodule group is as shown in figure 3, including each submodule Equivalent loss resistance sum R, two diode Dp and Dn, switch SW and voltage source V caused by middle electric currentGO;The diode The branch road and voltage source V of composition after Dp and Dn series connectionGOIt is in parallel;The switch SW is in parallel with diode Dp;Each half-bridge Equivalent loss resistance R is connected between diode Dp and Dn caused by electric current in module;
(One)The mathematical modeling I of the equivalent circuit II of half-bridge submodule group is as follows:
Wherein:VGoFor the total output voltage of each submodule;
This mathematical modeling results in the capacitance voltage of each submodule, and capacitance voltage is balanced and trigger pulse distribution must It need consider.Relative to equivalent circuit I, the interstitial content of equivalent circuit II is greatly reduced.
(Two)The mathematical modeling II of the equivalent circuit II of half-bridge submodule group is as follows:
1. voltage of all half-bridge submodules including initial value is equal:
Wherein:N indicates N number of submodule;
2. because loss caused by voltage is identical, i.e.,:
Some time is carved with n half-bridge submodule and is in input state, to formula<7>In half-bridge submodule capacitor voltage asked With obtain:
(2)Mathematical modeling to half-bridge submodule group simplifies, and determines the equivalent circuit and each bridge of each bridge arm The working condition of arm.
Mathematical modeling II to half-bridge submodule group is simplified as:
Formula<6>It is rewritten as:
Wherein:Represent that half-bridge submodule includes the voltage of initial value;
Order:
Wherein:M represents modulation ratio;
Then formula<5>And formula<6>It is rewritten as:
VGo=m × VGc<13>;
Wherein:CGIt is the equivalent capacity of half-bridge submodule group, is numerically equal to the series connection of half-bridge submodule capacitor voltage Capacitance;VGcIt is the capacitance voltage sum in half-bridge submodule group;
Mathematical modeling II neglects bridge arm half-bridge submodule capacitor voltage and the loss as caused by voltage in the process of running Difference, simplify control process, it is not necessary to consider that capacitance voltage inside half-bridge submodule group is balanced and trigger pulse is distributed Control;Modulation ratio m is obtained by modulation algorithm, order:
So as to ignore voltage modulated process, make the control of bridge arm simpler.Formula<14>Middle VacrefFor half-bridge submodule group The reference value of output voltage AC compounent;VdcrefFor the reference value of half-bridge submodule group output voltage DC component;VacrefWith VdcrefValue ensure m value in [0,1].When the only steady state operation of research submodule group, submodule group etc. Effect circuit can be further simplified as a controllable voltage source, dispense diode and switch.Based on half-bridge submodule group etc. Circuit and mathematical modeling are imitated, modular multi-level converter can be studied, for different research contents, can be from difference Simplified model, be that the voltage source converter based on half-bridge submodule and its research of application are provided a great convenience.
The step(2)In, the equivalent circuit of each bridge arm includes two diode D1And D2, switch SW and controllable voltage Source Vo;The diode D1And D2Branch road and controllable voltage source V after series connectionoIt is in parallel;The switch SW and diode D1It is in parallel;
The working condition of each bridge arm is as follows:
When flowing through the electric current i > 0 of bridge arm, bridge arm output voltage is submodule capacitor voltage sum, each submodule The electric current i chargings of bridge arm will be flowed through, therefore can make and be adjusted to compare m=1;It is all when flowing through the electric current i < 0 of bridge arm Submodule electric capacity is all bypassed, therefore can add a diode, and controllable voltage source is bypassed, as shown in figure 4, being bridge arm Simple equivalent circuit, blocking can be conciliate to the blocking of bridge arm and emulated, controllable voltage source and controllable current The expression formula in source such as formula<15>It is shown:
A, when switch SW be off when, bridge arm simple equivalent circuit can simulate the blocking of bridge arm, make m= 1, as electric current i > 0, electric current flows through diode D1, controllable voltage source charging is given, now i0=i;As electric current i < 0, electric current stream Cross diode D2, controllable voltage source is bypassed, now i0=0, controllable voltage source will not be electrically charged;
B, when switching SW and being in closure state, what bridge arm simplified that circuit can simulate bridge arm unblocks lock status, due to can Control the output voltage V of voltage sourceo> 0, therefore diode D2It is reversed by diode D1Be switched on and off SW bypass, no matter electric current i Direction how, have i0=i, unblocking and latching process for bridge arm is simulated with turning on and off for switch SW.
Finally it should be noted that:The above embodiments are merely illustrative of the technical scheme of the present invention and are not intended to be limiting thereof, to the greatest extent The present invention is described in detail with reference to above-described embodiment for pipe, those of ordinary skills in the art should understand that:Still The embodiment of the present invention can be modified or equivalent substitution, and without departing from any of spirit and scope of the invention Modification or equivalent substitution, it all should cover among scope of the presently claimed invention.

Claims (4)

1. a kind of modeling and simulating method based on half-bridge submodule voltage source converter, the voltage source converter is by three-phase structure Into every to be made up of two bridge arms up and down, each bridge arm is made up of half-bridge sub-module cascade, and each half-bridge submodule includes in parallel IGBT module branch road and capacitor branches, the IGBT module composition of IGBT module branch route series connection, each IGBT module by IGBT device and constituted with its antiparallel diode;Characterized in that, methods described comprises the steps:
(1) half-bridge submodule and the equivalent circuit and mathematical modeling of submodule group are set up, equivalent circuit is simulated half-bridge submodule With three kinds of working conditions of half-bridge submodule group;Each half-bridge submodule group at least includes 2 half-bridge submodules of series connection;
(2) mathematical modeling to half-bridge submodule group simplifies, and determines the equivalent circuit and each bridge arm of each bridge arm Working condition;
In the step (1), the equivalent circuit of the half-bridge submodule include equivalent loss conductance r caused by electric current, two two Pole pipe Dp and Dn, switch SW and voltage source Vo;Branch road and voltage source V after diode Dp and the Dn series connectionoParallel connection, it is described Switch SW in parallel with diode Dp;Equivalent loss resistance r one end is connected to diode Dp and Dn company caused by the electric current Contact;
The mathematical modeling of the half-bridge submodule is as follows:
<mrow> <msub> <mi>V</mi> <mi>c</mi> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mi>C</mi> </mfrac> <msubsup> <mo>&amp;Integral;</mo> <mn>0</mn> <mi>t</mi> </msubsup> <mrow> <mi>S</mi> <mo>&amp;times;</mo> <msub> <mi>i</mi> <mi>c</mi> </msub> </mrow> <mo>-</mo> <msub> <mi>V</mi> <mi>c</mi> </msub> <mo>&amp;times;</mo> <mi>g</mi> <mi>d</mi> <mi>t</mi> <mo>+</mo> <msub> <mi>V</mi> <mi>c</mi> </msub> <mrow> <mo>(</mo> <msub> <mn>0</mn> <mo>-</mo> </msub> <mo>)</mo> </mrow> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>1</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Vo=S × Vc<2>;
Wherein:C is the electric capacity in submodule;S is the switching signal of submodule;G is equivalent loss conductance caused by voltage;icIt is The charging and discharging currents of electric capacity;Vc(0-) be submodule capacitor voltage initial value;VcIt is the capacitance voltage in submodule;VoIt is son The output voltage of module;
In the step (1), three kinds of working conditions of the half-bridge submodule include:
Blocking:Switch SW to open, S=1;During i > 0, electric current flows through Dp, submodule is electrically charged, and output voltage is Vc;I < 0 When, electric current flows through Dn, output voltage is 0;Wherein i is the electric current for flowing through half-bridge submodule or half-bridge submodule group;
Unblock lock status:Switch SW closures;During S=1, submodule is put into, and electric capacity is discharged, and output voltage is Vc;During S=0, Submodule is removed, and electric capacity will not be charged or discharged, and output voltage is 0, i.e. formula<2>;
Half blocking:Switch SW to open, i < 0, electric current flows through Dn, output voltage is 0;I > 0 and during S=0, output voltage is 0, i.e. formula<2>, electric capacity will not be electrically charged;I > 0 and during S=1, output voltage is Vc, i.e. formula<2>, electric capacity is electrically charged;
In the step (1), the equivalent circuit I of half-bridge submodule group includes equivalent loss resistance caused by electric current in each submodule Sum R, two diode Dp and Dn, switch SW and voltage source Vo1、Vo2……VoN;After diode Dp and the Dn series connection Constitute diode branch road;Voltage source Vo1、Vo2……VoNVoltage source branch road is constituted after series connection;The diode branch road and voltage source Branch circuit parallel connection;The switch SW is in parallel with diode Dp;Equivalent loss resistance sum R caused by electric current in each submodule One end is connected to diode Dp and Dn tie point;
The mathematical modeling of the equivalent circuit I of the half-bridge submodule group is as follows:
<mrow> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mi>C</mi> </mfrac> <msubsup> <mo>&amp;Integral;</mo> <mn>0</mn> <mi>t</mi> </msubsup> <mrow> <msub> <mi>S</mi> <mi>j</mi> </msub> <mo>&amp;times;</mo> <msub> <mi>i</mi> <mi>c</mi> </msub> </mrow> <mo>-</mo> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>&amp;times;</mo> <msub> <mi>g</mi> <mi>j</mi> </msub> <mi>d</mi> <mi>t</mi> <mo>+</mo> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mn>0</mn> <mo>-</mo> </msub> <mo>)</mo> </mrow> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>3</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Voj=Sj×Vcj<4>;
Wherein:Vcj, Voj, Sj, gj, Vcj(0-) be respectively j-th of half-bridge submodule capacitance voltage, output voltage, switching signal, Equivalent loss conductance and capacitance voltage initial value caused by voltage;
Three kinds of working conditions of half-bridge submodule group are identical with three kinds of working conditions of half-bridge submodule.
2. modeling and simulating method as claimed in claim 1, it is characterised in that in the step (1), half-bridge submodule group etc. Imitate circuit II include equivalent loss resistance sum R caused by electric current in each submodule, two diodes Dp and Dn, switch SW and Voltage source VGO;The branch road and voltage source V of composition after diode Dp and the Dn series connectionGOIt is in parallel;The switch SW and diode Dp is in parallel;Equivalent loss resistance sum R one end is connected to diode Dp and Dn company caused by electric current in each submodule Contact;
(1) mathematical modeling I of the equivalent circuit II of half-bridge submodule group is as follows:
<mrow> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mi>C</mi> </mfrac> <msubsup> <mo>&amp;Integral;</mo> <mn>0</mn> <mi>t</mi> </msubsup> <mrow> <msub> <mi>S</mi> <mi>j</mi> </msub> <mo>&amp;times;</mo> <msub> <mi>i</mi> <mi>c</mi> </msub> </mrow> <mo>-</mo> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>&amp;times;</mo> <msub> <mi>g</mi> <mi>j</mi> </msub> <mi>d</mi> <mi>t</mi> <mo>+</mo> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mn>0</mn> <mo>-</mo> </msub> <mo>)</mo> </mrow> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>5</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
<mrow> <msub> <mi>V</mi> <mrow> <mi>G</mi> <mi>o</mi> </mrow> </msub> <mo>=</mo> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msub> <mi>V</mi> <mrow> <mi>o</mi> <mi>j</mi> </mrow> </msub> <mo>=</mo> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <mrow> <mo>(</mo> <msub> <mi>S</mi> <mi>j</mi> </msub> <mo>&amp;times;</mo> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>)</mo> </mrow> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>6</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Wherein:VGoFor the total output voltage of each submodule;
(2) mathematical modeling II of the equivalent circuit II of half-bridge submodule group is as follows:
1. voltage of all half-bridge submodules including initial value is equal:
<mrow> <msub> <mover> <mi>V</mi> <mo>&amp;OverBar;</mo> </mover> <mi>c</mi> </msub> <mo>=</mo> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mi>N</mi> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>7</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Wherein:N indicates N number of submodule;
2. because loss caused by voltage is identical, i.e.,:
<mrow> <mi>G</mi> <mo>=</mo> <msub> <mi>g</mi> <mi>j</mi> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mi>N</mi> </mfrac> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msub> <mi>g</mi> <mi>j</mi> </msub> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>8</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Some time is carved with n half-bridge submodule and is in input state, to formula<7>In half-bridge submodule capacitor voltage carry out sum Arrive:
<mrow> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <mrow> <mi>C</mi> <mo>/</mo> <mi>N</mi> </mrow> </mfrac> <msubsup> <mo>&amp;Integral;</mo> <mn>0</mn> <mi>t</mi> </msubsup> <mrow> <mfrac> <mi>n</mi> <mi>N</mi> </mfrac> <mo>&amp;times;</mo> <msub> <mi>i</mi> <mi>c</mi> </msub> </mrow> <mo>-</mo> <mi>G</mi> <mo>&amp;times;</mo> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mi>d</mi> <mi>t</mi> <mo>+</mo> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mn>0</mn> <mo>-</mo> </msub> <mo>)</mo> </mrow> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>9</mn> <mo>&gt;</mo> <mo>.</mo> </mrow>
3. modeling and simulating method as claimed in claim 2, it is characterised in that in step (2), to the mathematics of half-bridge submodule group Model I is simplified as:
Formula<6>It is rewritten as:
<mrow> <msub> <mi>V</mi> <mrow> <mi>G</mi> <mi>o</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mi>n</mi> <mi>N</mi> </mfrac> <mo>&amp;times;</mo> <mi>N</mi> <mo>&amp;times;</mo> <msub> <mover> <mi>V</mi> <mo>&amp;OverBar;</mo> </mover> <mi>c</mi> </msub> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>10</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Wherein:Represent that half-bridge submodule includes the voltage of initial value;
Order:
<mrow> <mfenced open = "{" close = ""> <mtable> <mtr> <mtd> <mrow> <msub> <mi>V</mi> <mrow> <mi>G</mi> <mi>c</mi> </mrow> </msub> <mo>=</mo> <munderover> <mo>&amp;Sigma;</mo> <mrow> <mi>j</mi> <mo>=</mo> <mn>1</mn> </mrow> <mi>N</mi> </munderover> <mrow> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>j</mi> </mrow> </msub> <mo>=</mo> <mi>N</mi> <mo>&amp;times;</mo> <msub> <mover> <mi>V</mi> <mo>&amp;OverBar;</mo> </mover> <mi>c</mi> </msub> </mrow> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <mi>m</mi> <mo>=</mo> <mfrac> <mi>n</mi> <mi>N</mi> </mfrac> </mrow> </mtd> </mtr> <mtr> <mtd> <mrow> <msub> <mi>C</mi> <mi>G</mi> </msub> <mo>=</mo> <mfrac> <mi>C</mi> <mi>N</mi> </mfrac> </mrow> </mtd> </mtr> </mtable> </mfenced> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>11</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Wherein:M represents modulation ratio;
Then formula<5>And formula<6>It is rewritten as:
<mrow> <msub> <mi>V</mi> <mrow> <mi>G</mi> <mi>c</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mn>1</mn> <msub> <mi>C</mi> <mi>G</mi> </msub> </mfrac> <msubsup> <mo>&amp;Integral;</mo> <mn>0</mn> <mi>t</mi> </msubsup> <mrow> <mi>m</mi> <mo>&amp;times;</mo> <msub> <mi>i</mi> <mi>c</mi> </msub> </mrow> <mo>-</mo> <mi>G</mi> <mo>&amp;times;</mo> <msub> <mi>V</mi> <mrow> <mi>G</mi> <mi>c</mi> </mrow> </msub> <mi>d</mi> <mi>t</mi> <mo>+</mo> <msub> <mi>V</mi> <mrow> <mi>G</mi> <mi>c</mi> </mrow> </msub> <mrow> <mo>(</mo> <msub> <mn>0</mn> <mo>-</mo> </msub> <mo>)</mo> </mrow> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>12</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
VGo=m × VGc<13>;
Wherein:CGIt is the equivalent capacity of half-bridge submodule group, is numerically equal to the electric capacity of half-bridge submodule capacitor voltage series connection Value;VGcIt is the capacitance voltage sum in half-bridge submodule group;
Mathematical modeling II neglects bridge arm half-bridge submodule capacitor voltage and the difference being lost as caused by voltage in the process of running It is different, simplify control process, it is not necessary to consider balanced and trigger pulse distribution the control of capacitance voltage inside half-bridge submodule group; Modulation ratio m is obtained by modulation algorithm, order:
<mrow> <mi>m</mi> <mo>=</mo> <mfrac> <mrow> <msub> <mi>V</mi> <mrow> <mi>a</mi> <mi>c</mi> <mi>r</mi> <mi>e</mi> <mi>f</mi> </mrow> </msub> <mo>+</mo> <msub> <mi>V</mi> <mrow> <mi>d</mi> <mi>c</mi> <mi>r</mi> <mi>e</mi> <mi>f</mi> </mrow> </msub> </mrow> <msub> <mi>V</mi> <mrow> <mi>s</mi> <mi>m</mi> <mi>G</mi> <mi>c</mi> </mrow> </msub> </mfrac> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>14</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
Formula<14>Middle VacrefFor the reference value of half-bridge submodule group output voltage AC compounent;VdcrefExported for half-bridge submodule group The reference value of voltage DC component;VacrefAnd VdcrefValue ensure m value in [0,1].
4. modeling and simulating method as claimed in claim 1, it is characterised in that in the step (2), the equivalent electric of each bridge arm Road includes two diode D1And D2, switch SW and controllable voltage source Vo;The diode D1And D2Branch road after series connection with it is controllable Voltage source VoIt is in parallel;The switch SW and diode D1It is in parallel;
The working condition of each bridge arm is as follows:
When flowing through the electric current i > 0 of bridge arm, bridge arm output voltage is submodule capacitor voltage sum, and each submodule will The electric current i chargings of bridge arm are flowed through, order is adjusted to compare m=1;When flowing through the electric current i < 0 of bridge arm, all submodule electric capacity is complete All it is bypassed, adds a diode, controllable voltage source is bypassed, the simple equivalent circuit of bridge arm can be to the latch like of bridge arm State is conciliate blocking and emulated, the expression formula such as formula of controllable voltage source and controllable current source<15>It is shown:
<mrow> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <msub> <mi>V</mi> <mi>o</mi> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>i</mi> <mn>0</mn> </msub> </mtd> </mtr> </mtable> </mfenced> <mo>=</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <mi>m</mi> </mtd> <mtd> <mn>0</mn> </mtd> </mtr> <mtr> <mtd> <mn>0</mn> </mtd> <mtd> <mi>m</mi> </mtd> </mtr> </mtable> </mfenced> <mo>&amp;times;</mo> <mfenced open = "[" close = "]"> <mtable> <mtr> <mtd> <msub> <mi>V</mi> <mrow> <mi>c</mi> <mi>a</mi> <mi>r</mi> <mi>m</mi> </mrow> </msub> </mtd> </mtr> <mtr> <mtd> <msub> <mi>i</mi> <mi>c</mi> </msub> </mtd> </mtr> </mtable> </mfenced> <mo>-</mo> <mo>-</mo> <mo>-</mo> <mo>&lt;</mo> <mn>15</mn> <mo>&gt;</mo> <mo>;</mo> </mrow>
A, when switch SW be off when, bridge arm simple equivalent circuit can simulate the blocking of bridge arm, make m=1, when During electric current i > 0, electric current flows through diode D1, controllable voltage source charging is given, now i0=i;As electric current i < 0, electric current flows through two Pole pipe D2, controllable voltage source is bypassed, now i0=0, controllable voltage source will not be electrically charged;
B, when switching SW and being in closure state, what bridge arm simplified that circuit can simulate bridge arm unblocks lock status, due to controllable electric The output voltage V of potential sourceo> 0, therefore diode D2It is reversed by diode D1Be switched on and off SW bypass, no matter electric current i side To how, have i0=i, unblocking and latching process for bridge arm is simulated with turning on and off for switch SW.
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