CN103389681B - A kind of modeling method of full-automatic plate bending machine digital control system - Google Patents

Abstract

The invention discloses a kind of modeling method of plate bending rolls digital control system, by step one, first calculate pressure in volume bowlder steel plate inside radius situation and displacement, to the description of the quantitative relationship for the round inside radius of processing work, pressure and displacement; Step 2, corresponding plate bending rolls roll bending radius number of times are quantitatively described; Step 3, upper roll displacement when calculating pre-bending and horizontal displacement; According to three above-mentioned step Modeling Calculation methods, horizontal displacement, upper roll displacement and pressure of top roll value when just can calculate pre-bending.By the modeling method of plate bending rolls digital control system of the present invention, do not need to rely on the experience of operating personnel, only need simple data being filled in get final product high precision, high efficiencyly complete roll bending.

Description

A kind of modeling method of full-automatic plate bending machine digital control system

Technical field

The present invention relates to a kind of digital control system modeling method, particularly relate to a kind of modeling method of plate bending rolls full-automatic numerical control system.

Background technology

The kind of plate bending rolls is a lot, mechanical-hydraulic is also very ripe, but because the electric control system of each manufacturer can only meet action request, produce the precision of roll bending and speed completely by the skill level of operative employee, be difficult to reach ovality requirement within 1.5mm, and artificial roll bending is by rule of thumb and the theoretical roll bending data of neither one and processing step purely, different people rolls out different effects, the relatively good workpiece that skilled operative employee just can roll out, unskilled operative employee cannot roll out workpiece, this kind relies on manually-operated roll bending mode cannot reach quick and high-precision requirement, therefore, plate bending rolls needs to form a set of technique that can instruct roll bending, again can by the digital control system of the automatic roll bending of technique, so just man's activity can be overcome, reach high precision, high-level efficiency, but have no this type of report in prior art.

Summary of the invention

In order to solve the deficiencies in the prior art, the object of the present invention is to provide a kind of modeling method of plate bending rolls digital control system, can high precision, high efficiencyly complete roll bending, do not need the experience relying on operating personnel.

For achieving the above object, the technological means of employing of the present invention is: a kind of modeling method of plate bending rolls digital control system, and its step is as follows:

One, first calculate the pressure under volume circle internal diameter is r situation and displacement, to the description of the quantitative relationship for inside radius before the resilience of processing work, pressure and displacement, be described by formula below:

$r^{\′}=\frac{1-Ko\mathrm{\ξ}s/10E}{1+\frac{K1\mathrm{\ξ}s\×2\×r}{10Ed}}r---\left(1\right),$

Calculate inside radius before resilience,

$M=\frac{1}{6}\×b\×d^2\×(K1+\frac{Ko\×d}{2r^{\′}})\×\mathrm{\ξ}s---\left(2\right),$

$sin\mathrm{\α}=\frac{\frac{L}{2}}{r^{\′}+\frac{d}{2}+\frac{D2}{2}}---\left(3\right),$

After inside radius input before resilience, calculate the moment of flexure of steel plate,

$tg\mathrm{\α}=\frac{sin\mathrm{\α}}{\sqrt{1-\left(sin\mathrm{\α}\right)\×\left(sin\mathrm{\α}\right)}}---\left(4\right),$

$Pa=\frac{2M}{(r^{\′}+S/2)tg\mathrm{\α}}---\left(5\right),$

Just pressure of top roll Pa can be calculated after substituting into,

${(r+d+\frac{D2}{2})}^2={\left(\frac{L}{2}\right)}^2+{(H+r+\sqrt{(D1/2+D2/2)\×(D1/2+D2/2)-(L/2)\×(L/2)}-D1/2)}^2---\left(6\right),$

Other are known, can obtain top roll displacement H;

In formula: K1=1.5, r ＇ is inside radius before steel plate resilience, and unit mm, ξ s is yield limit N/mm ², Ko is coefficient of intensification, and E gets 19800-20600kg/mm ², M is material deformation moment of flexure, and unit is N.mm, b is that plate is wide, and unit mm, α are steel plate and centerlines, d is steel plate thickness, and unit mm, r are volume circle internal diameter, unit mm, H are for being rolled into the displacement of r bowlder top roll, unit mm, L is two lower roller center distances, and unit mm, D1 are upper roller diameter, unit mm, D2 are lower roller diameter, unit mm;

Two, corresponding plate bending rolls roll bending radius number of times is quantitatively described, and passes through following formula:

r _k＝r×(n-k)×1.1(7)，

Three roller roll bending radius number of times definition,

In formula: r be last shaping time inside radius, n is roll bending total degree, and k is every number of times k≤n, k >=1;

Upper roll displacement H when three, calculating pre-bending and horizontal displacement X:

$X_T=\frac{L}{2}\×(1-\frac{\frac{D1}{2}+d+\frac{D2}{2}}{r^{\′}+\frac{d}{2}+\frac{D2}{2}})---\left(8\right),$

B＝(1.5-2.5)d(9)，

$X=X_T-(1-\frac{D1}{2\×r^{\′}-d})\×B---\left(10\right),$

Calculated level displacement X,

$AG=\sqrt{{(r^{\′}+d/2+D2/2)}^2-{\left(\frac{L}{2}\right)}^2}---\left(11\right),$

AD＝XT/(tg(β+α)/2)(12)，

α＝acsin(B/r＇)(13)，

$\mathrm{\β}=\mathrm{\α}+2\×acsin\left(\frac{X}{r^{\′}-\frac{d}{2}-\frac{D1}{2}}\right)---\left(14\right),$

$CG1=\sqrt{{(\frac{D1}{2}+\frac{D2}{2})}^2-{\left(\frac{L}{2}\right)}^2}---\left(15\right),$

H＝AG-AD-CG1(16)，

Upper roll displacement H after calculating pre-bending puts in place, now volume circle displacement h=H+5mm

$Pa=\frac{M}{r^{\′}+\frac{d}{2}}\×(\frac{1}{tg\mathrm{\α}}+\frac{1}{tg\mathrm{\β}})---\left(17\right),$

Pressure of top roll Pa when calculating pre-bending,

In formula: B is pre-bending straight flange coefficient, and d is steel plate thickness, r ＇ is inside radius before steel plate resilience, and L is two lower roller center distances, and D1 is upper roller diameter, and D2 is lower roller diameter, and X is horizontal shift, and H is the displacement of pre-bending top roll;

According to above-mentioned Modeling Calculation method, horizontal displacement, upper roll displacement and pressure of top roll value when just can calculate pre-bending.

Beneficial effect of the present invention is: by the modeling method of plate bending rolls digital control system of the present invention, does not need to rely on the experience of operating personnel, only needs simple data being filled in get final product high precision, high efficiencyly complete roll bending.

Accompanying drawing explanation

Below in conjunction with drawings and Examples, the present invention is further described.

Fig. 1 is each roller schematic diagram of plate bending rolls in modeling process of the present invention.

Embodiment

The modeling method of a kind of plate bending rolls digital control system as shown in Figure 1, its step is as follows:

As a WS11K-50X3000 three rolls plate bending machine, upper roller diameter D1 is 600mm, lower roller diameter D2 is 380mm, centre distance L is 600mm, cylinder diameter is 230mm (twin-tub), coiled steel plate is wanted to be: the general plate of 30mm (thick) × 1000 (wide) × 7944.2 (length), internal diameter is 2500mm

One, first calculate the pressure in volume radius of circle r=1250mm situation and displacement, to the description of the quantitative relationship for inside radius before the resilience of processing work, pressure and displacement, be described by formula below:

$r^{\′}=\frac{1-Ko\mathrm{\ξ}s/10E}{1+\frac{K1\mathrm{\ξ}s\×2\×r}{10Ed}}r---\left(1\right),$

R=1250mm is brought in (1) formula and calculates inside radius before resilience,

$M=\frac{1}{6}\×b\×d^2\×(K1+\frac{Ko\×d}{2r^{\′}})\×\mathrm{\ξ}s---\left(2\right),$

$sin\mathrm{\α}=\frac{\frac{L}{2}}{r^{\′}+\frac{d}{2}+\frac{D2}{2}}---\left(3\right),$

After inside radius r ＇ before resilience is inputted (2) formula and (3) formula, calculate the material deformation moment M of this steel plate,

$tg\mathrm{\α}=\frac{sin\mathrm{\α}}{\sqrt{1-\left(sin\mathrm{\α}\right)\×\left(sin\mathrm{\α}\right)}}---\left(4\right),$

$Pa=\frac{2M}{(r^{\′}+S/2)tg\mathrm{\α}}---\left(5\right),$

Just pressure of top roll Pa can be calculated after substituting into,

${(r+d+\frac{D2}{2})}^2={\left(\frac{L}{2}\right)}^2+{(H+r+\sqrt{(D1/2+D2/2)\×(D1/2+D2/2)-(L/2)\×(L/2)}-D1/2)}^2---\left(6\right),$

Other are known, can obtain top roll displacement H,

In formula: K1=1.5, r ＇ is inside radius before steel plate resilience, and unit mm, ξ s is yield limit N/mm ², Ko is coefficient of intensification, and E gets 19800-20600kg/mm ², M is material deformation moment of flexure, and unit is N.mm, b is that plate is wide, and unit mm, α are steel plate and centerlines, d is steel plate thickness, and unit mm, r are volume circle internal diameter, unit mm, H are for being rolled into the displacement of r bowlder top roll, unit mm, L is two lower roller center distances, and unit mm, D1 are upper roller diameter, unit mm, D2 are lower roller diameter, unit mm;

Two, corresponding plate bending rolls roll bending radius number of times is quantitatively described, and passes through following formula:

r _k＝r×(n-k)×1.1(7)，

Three roller roll bending radius number of times definition, top roll divides and presses down n=3 three times, k value 1,2,3, brings in (7) formula, calculates r1=2750mm, r2=1375mm,

In formula: r be last shaping time inside radius, n is roll bending total degree, and k is every number of times k≤n, k >=1;

Upper roll displacement H when three, calculating pre-bending and horizontal displacement X:

$X_T=\frac{L}{2}\×(1-\frac{\frac{D1}{2}+d+\frac{D2}{2}}{r^{\′}+\frac{d}{2}+\frac{D2}{2}})---\left(8\right),$

B＝(1.5-2.5)d(9)，

$X=X_T-(1-\frac{D1}{2\×r^{\′}-d})\×B---\left(10\right),$

Calculated level displacement X=123mm,

$AG=\sqrt{{(r^{\′}+d/2+D2/2)}^2-{\left(\frac{L}{2}\right)}^2}---\left(11\right),$

AD＝XT/(tg(β+α)/2)(12)，

α＝acsin(B/r＇)(13)，

$\mathrm{\β}=\mathrm{\α}+2\×acsin\left(\frac{X}{r^{\′}-\frac{d}{2}-\frac{D1}{2}}\right)---\left(14\right),$

$CG1=\sqrt{{(\frac{D1}{2}+\frac{D2}{2})}^2-{\left(\frac{L}{2}\right)}^2}---\left(15\right),$

H＝AG-AD-CG1(16)，

Upper roll displacement H after calculating pre-bending puts in place, now volume circle displacement h=H+5=115mm,

$Pa=\frac{M}{r^{\′}+\frac{d}{2}}\×(\frac{1}{tg\mathrm{\α}}+\frac{1}{tg\mathrm{\β}})---\left(17\right),$

Pressure of top roll Pa=2804200.4 (N) when calculating pre-bending

In formula: B is pre-bending straight flange coefficient, and d is steel plate thickness, r ＇ is inside radius before steel plate resilience, and T is two lower roller center distances, and D1 is upper roller diameter, and D2 is lower roller diameter, and X is horizontal shift, and H is the displacement of pre-bending top roll;

According to above-mentioned Modeling Calculation method, horizontal displacement, upper roll displacement and pressure of top roll value when just can calculate pre-bending.

Above-mentioned steps is summarised as: put by steel plate, and with alignment means to good, after clicking " beginning ", whole roll bending action just completes automatically according to processing step above, it is as follows that its pressure roller does step: material loading aligns, and top roll presses to the shift value place of contact steel plate, declines to material; Top roll declines and reversion operates simultaneously, and top roll drops to the shift value h place calculating volume circle, is inverted to the leading section of plate; Calculate h=H+5=115mm, top roll presses to the shift value place of the pre-bending of calculating; The shift value h place in the volume garden that top roll rising calculates, is just forwarding plate stationary position to; Top roll rises, and departs from plate, the horizontal shift place-X of level mobile computing backward, (negative sense);-x=-123mm, top roll drops to the shift value h place in the volume garden of calculating, is just forwarding the rearward end (optimal site of pre-bending) of plate to; Top roll is depressed into the shift value H place of the pre-bending of calculating; Top roll is raised to h place; Main transmission is inverted to steady place, and top roll climbs away steel plate; During level is returned; Top roll divides the full circle value place full circle joint close being depressed into calculating for three times, terminates; Calculate r1=2750, H1=112mm, r2=1375, H2=99mm, r=1250, H=97mm top roll rises to peak, and overturning feeding is complete.

The above, be only the specific embodiment of the present invention, is not limited thereto, and is anyly familiar with those skilled in the art in the technical scope that the present invention discloses, and can expect change easily or replace, all should be encompassed within protection scope of the present invention.

Claims (1)

1. a modeling method for plate bending rolls digital control system, is characterized in that step is as follows:

One, first calculate the pressure under volume circle internal diameter is r situation and displacement, to the description of the quantitative relationship for inside radius before the resilience of processing work, pressure and displacement, be described by formula below:

$r^{\′}=\frac{1-Ko\mathrm{\ξ}s/10E}{1+\frac{K1\mathrm{\ξ}s\×2\×r}{10Ed}}r---\left(1\right),$

Calculate inside radius before resilience,

$M=\frac{1}{6}\×b\×d^2\×(K1+\frac{Ko\×d}{2r^{\′}})\×\mathrm{\ξ}s---\left(2\right),$

$sin\mathrm{\α}=\frac{\frac{L}{2}}{r^{\′}+\frac{d}{2}+\frac{D2}{2}}---\left(3\right),$

After inside radius input before resilience, calculate the moment of flexure of steel plate,

$tg\mathrm{\α}=\frac{sin\mathrm{\α}}{\sqrt{1-\left(sin\mathrm{\α}\right)\×\left(sin\mathrm{\α}\right)}}---\left(4\right),$

$Pa=\frac{2M}{(r^{\′}+d/2)tg\mathrm{\α}}---\left(5\right),$

Just pressure of top roll Pa can be calculated after substituting into,

${(r+d+\frac{D2}{2})}^2=\left(\frac{L}{2}\right)2+{(H+r+\sqrt{(D1/2+D2/2)\×(D1/2+D2/2)-(L/2)\×(L/2)}-D1/2)}^2---\left(6\right),$

Other are known, can obtain top roll displacement H;

In formula: K1=1.5, r ＇ is inside radius before steel plate resilience, and unit mm, ξ s is yield limit N/mm ², Ko is coefficient of intensification, and E gets 19800-20600kg/mm ², M is material deformation moment of flexure, and unit is N.mm, b is that plate is wide, and unit mm, α are steel plate and centerlines, d is steel plate thickness, and unit mm, r are volume circle internal diameter, unit mm, H are for being rolled into the displacement of r bowlder top roll, unit mm, L is two lower roller center distances, and unit mm, D1 are upper roller diameter, unit mm, D2 are lower roller diameter, unit mm;

Two, corresponding plate bending rolls roll bending radius number of times is quantitatively described, and passes through following formula:

r _k＝r×(n-k)×1.1(7)，

Three roller roll bending radius number of times definition,

In formula: r be last shaping time inside radius, n is roll bending total degree, and k is every number of times k≤n, k >=1;

Upper roll displacement H when three, calculating pre-bending and horizontal displacement X:

$X_T=\frac{L}{2}\×(1-\frac{\frac{D1}{2}+d+\frac{D2}{2}}{r^{\′}+\frac{d}{2}+\frac{D2}{2}})---\left(8\right),$

B＝(1.5-2.5)d(9)，

$X=X_T-(1-\frac{D1}{2\×r^{\′}-d})\×B---\left(10\right),$

Calculated level displacement X,

$AG=\sqrt{{(r^{\′}+d/2+D2/2)}^2-{\left(\frac{L}{2}\right)}^2}---\left(11\right),$

AD＝XT/(tg(β+α)/2)(12)，

α＝acsin(B/r＇)(13)，

$\mathrm{\β}=\mathrm{\α}+2\×acsin\left(\frac{X}{r^{\′}-\frac{d}{2}-\frac{D1}{2}}\right)---\left(14\right),$

$CG1=\sqrt{{(\frac{D1}{2}+\frac{D2}{2})}^2-{\left(\frac{L}{2}\right)}^2}---\left(15\right),$

H＝AG-AD-CG1(16)，

Upper roll displacement H after calculating pre-bending puts in place, now volume circle displacement h=H+5mm

$Pa=\frac{M}{r^{\′}+\frac{d}{2}}\×(\frac{1}{tg\mathrm{\α}}+\frac{1}{tg\mathrm{\β}})---\left(17\right),$

Pressure of top roll Pa when calculating pre-bending,

In formula: B is pre-bending straight flange coefficient, and d is steel plate thickness, r ＇ is inside radius before steel plate resilience, and L is two lower roller center distances, and D1 is upper roller diameter, and D2 is lower roller diameter, and X is horizontal shift, and H is the displacement of pre-bending top roll;

According to above-mentioned Modeling Calculation method, horizontal displacement, upper roll displacement and pressure of top roll value when just can calculate pre-bending.