CN103372582A - Ultrathin strip steel coiling equipment and method - Google Patents

Abstract

The invention discloses ultrathin strip steel coiling equipment which comprises a coiling machine, a compression roller device and a driving device, wherein an L-shaped mechanical arm is used as the compression roller device, and one end of the compression roller device is fixed above the rear side of the coiling machine and serves as the rotating center of the compression roller device; the driving device is arranged on the rear side of the coiling machine, is connected with the rotating center of the compression roller device and drives the compression roller device to rotate around the rotating center. The invention also provides an ultrathin strip steel coiling method which comprises the following steps of: collecting equipment parameters of a winding drum and a compression roller; collecting characteristic parameters of strip steel; giving various working condition coefficients; calculating the lifting position of the compression roller; defining parameters in a coiling process, and giving the maximum coiling radius; calculating the coiling radius; judging the position of the compression roller; judging whether the coiling radius is less than or equal to the difference obtained by subtracting the thickness of the strip steel from the maximum coiling radius. The invention provides a coiling method and equipment suitable for ultrathin strip steel, and the coiling quality of the strip steel can be effectively improved.

Description

The taking-up equipment of paper-thin strip and method

Technical field

The present invention relates to the cold rolling technology field, more particularly, relate to a kind of taking-up equipment and method of paper-thin strip.

Background technology

The product specification that the secondary cold-rolling unit is produced is thinner, and the thin product thickness of smooth Model Products can reach 0.15mm, and the secondary cold-rolling Model Products is the thinnest can to reach 0.05mm.For paper-thin strip, in actual production process, except rolling the defectives such as thin difficulty, plate shape is bad, performance is not up to standard, surface quality is defective, batch defective and also be the another one difficult problem in the paper-thin strip production process, belong to the emphasis of on-the-spot tackling key problem.In the production process of paper-thin strip, typically batch defective and just comprise band steel fold cramp etc.Batch the cramp defective as example take what generally occur in the coil of strip inner core, in coiling process, if there is batching the cramp problem, the excision of must cancelling of band steel causes the reduction of band steel lumber recovery, thereby has caused larger economic loss to the scene.

In the past, on-the-spot in order to overcome the strip coiling defective, the assurance reeling quality prevents that coil of strip from producing the phenomenons such as band steel fold cramp, coiling tension will increase by 10%～30% batching at first, make the coil of strip inner core form similar " sleeve " hard sandwich layer, along with the carrying out of batching, coiling tension drops to given working tension gradually, like this, tension force has formed certain tapering, is called " tapering coiling tension ", and the relation of tapering coiling tension and coil of strip diameter as shown in Figure 1.Wherein, taper tension recovery point computational methods be generally calculate entrance coil of strip weight 10% the time the strip coiling diameter, coiling tension returns to the coiling tension value of normal setting at this point.

Aforesaid way has certain effect greater than 0.18mm with steel for thickness, but when belt steel thickness is lower than 0.18m m, strip coiling and starting are very difficult, still adopt this moment the method for optimizing coiling tension can't solve the problems such as band steel fold cramp, often need repeatedly excision to batch bad band steel, had a strong impact on production efficiency.

Summary of the invention

Purpose of the present invention aims to provide a kind of taking-up equipment and method of paper-thin strip, solves the various deficiencies that exist in the prior art.

According to the present invention, a kind of taking-up equipment of paper-thin strip is provided, comprise coiling machine, press-roller device and drive unit.Press-roller device is L shaped mechanical arm, and the one end is fixed in the back side top of coiling machine, as the pivot of press-roller device.Drive unit is arranged at the rear side of coiling machine, and links to each other with the pivot of press-roller device, drives press-roller device and rotates around pivot.

According to one embodiment of the invention, the overbending direction of L shaped mechanical arm is towards the reel center of coiling machine.

According to one embodiment of the invention, the taking-up equipment of paper-thin strip also comprises S roller and lower S roller.Upper S roller is arranged at directly over the lower S roller, and the line at the center of the center of upper S roller and lower S roller is perpendicular to horizontal plane.The bottom of lower S roller is higher than the reel center of coiling machine.

According to one embodiment of the invention, drive unit is hydraulic cylinder.

According to a further aspect in the invention, provide a kind of method for coiling of paper-thin strip, may further comprise the steps: the device parameter of collecting reel and pressure roller; The characteristic parameter of collecting belt steel; Given all kinds of application factor; Calculate the position of lifting of pressure roller; Definition coiling process parameter, and given maximum reeling radius; Calculate reeling radius; Judge the pressure roller position; Judge whether reeling radius deducts the poor of belt steel thickness less than or equal to maximum reeling radius.

According to one embodiment of the invention, the reel parameter comprises coiler mandrel external diameter R ₀, the pressure roller diameter is d _y, the radius of turn of pressure roller is R _Zy, the pivot of pressure roller and the vertical range at coiler mandrel center be l _Oa, horizontal range is

The diameter d of upper S roller _Ss, lower S roller diameter d _Sx, upper S roller top and coiling machine the vertical range l at reel center _Fd, lower S roller bottom is l with the vertical range at the reel center of coiling machine _Cd, the horizontal range at S roller and coiler mandrel center up and down Characteristic parameter with steel comprises the thickness h with steel, width b, the band steel yield limit σ with steel _s, with the elastic modulus E of steel.Application factor comprises that pressure roller power application factor ξ, pressure roller lift the application factor ψ of position ₁, ψ ₂

According to one embodiment of the invention, the computing formula that pressure roller lifts the position is

According to one embodiment of the invention, the computing formula of reeling radius is R=R ₀+ kh, wherein k represents to be with steel to wrap coiling machine k circle.

According to one embodiment of the invention, the computing formula of pressure roller Position Control angle β is $\mathrm{\&beta;}={\mathrm{\&beta;}}_1+{\mathrm{\&beta;}}_2=\arcsin \left(\frac{l_{o_{1}a}}{\sqrt{{{\mathrm{<figure-callout\; id="2"\; label="l\; oa"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">l</figure-callout>}}_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2}}\right)+\arccos \left(\frac{{{\mathrm{<figure-callout\; id="2"\; label="l\; oa"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">l</figure-callout>}}_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2+R_{\mathrm{zy}}^2-{(R+\frac{d_y}{2})}^2}{2R_{\mathrm{zy}}\sqrt{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2}}\right),$ Wherein, β ₁Be the line of the pivot of the reel center of described coiling machine and pressure roller and angle, the β of plumb line direction ₂Be the angle between the line of the pivot of the reel center of the line of minimum steel band situation lower compression roller center and described pressure roller pivot and described coiling machine and described pressure roller.

According to one embodiment of the invention, judge that whether reeling radius is R≤R less than or equal to the formula that maximum reeling radius deducts the difference of belt steel thickness _Max-h, wherein R _MaxBe maximum reeling radius.

Adopted technical scheme of the present invention, from equipment and technology two aspects, proposed one and overlapped method for coiling and the equipment that is suitable for paper-thin strip, the new press-roller device of position adjustable, cornerite is disposed in employing above coiling machine, and by rational control pressure roller position angle, batch the methods such as cornerite and pressure roller pressure, can effectively improve the reeling quality with steel.

Description of drawings

In the present invention, identical Reference numeral represents identical feature all the time, wherein:

Fig. 1 is the relation of tapering coiling tension and coil of strip diameter in the prior art;

Fig. 2 is the structural representation of the taking-up equipment of paper-thin strip of the present invention;

Fig. 3 is the flow chart of the method for coiling of paper-thin strip of the present invention;

Fig. 4 is the schematic diagram of press-roller device when extreme position of Fig. 2;

Fig. 5 is the schematic diagram of press-roller device when general position of Fig. 2;

Partial enlarged drawing when Fig. 6 is contacting of the reel center of coiling machine of Fig. 2 and press-roller device.

The specific embodiment

Further specify technical scheme of the present invention below in conjunction with drawings and Examples.

As shown in Figure 2, in order to realize purpose of the present invention, improve reeling quality, the invention provides a kind of taking-up equipment of paper-thin strip, comprise coiling machine 1, press-roller device 2, upper S roller 3, lower S roller 4 and drive unit 5.

Configuration press-roller device 2 above coiling machine 1, press-roller device 2 is L shaped mechanical arm, and the one end is fixed in the back side top of coiling machine 1, and as the pivot O of press-roller device 2, and the overbending direction of L shaped mechanical arm is towards the reel center O of coiling machine ₁, the center of the other end of press-roller device 2 is O ₂

The diameter of press-roller device 2 is d _y, the radius of turn of pressure roller is R _Zy, the vertical range at the reel center of the pivot of press-roller device 2 and coiling machine 1 is l _Oa, horizontal range is

Simultaneously, in Fig. 2, upper S roller 3 be arranged at lower S roller 4 directly over, and the line at the center of the center of upper S roller 3 and lower S roller 4 is perpendicular to horizontal plane.The bottom of lower S roller 4 is higher than the reel center O of coiling machine 1 ₁

Simultaneously with reference to figure 4 and Fig. 5, the diameter d of upper S roller 3 _SsRepresent, the diameter d of lower S roller 4 _SxRepresent that α represents to batch the angle, β represents that the vertical range at the reel center of pressure roller Position Control angle, upper S roller 3 tops and coiling machine 1 is l _Fd, lower S roller 4 bottoms and coiling machine 1 the vertical range at reel center be l _Cd, upper S roller 3, lower S roller 4 with the horizontal range at the reel center of coiling machine 1 be

The air line distance at the reel center of lower S roller 4 bottoms and coiling machine 1 is

Simultaneously with reference to figure 4 and Fig. 5, C is the bottom position of lower S roller 4, D be lower S roller 4 under, with the reel center O of coiling machine 1 ₁Be in the position of same level line; A be press-roller device 2 pivot O under, with the reel center O of coiling machine 1 ₁Be in the position of same level line; E is O ₁On the D line segment any is in order to represent apart from l _FdIn Fig. 4, φ _MinAnd φ _MaxRespectively minimum, maximum coil of strip diameter.

Drive unit 5 is arranged at the rear side of coiling machine 1, and links to each other with the pivot of press-roller device 2, drives press-roller device 2 and rotates around pivot O, and coil of strip is compressed.As a kind of preferred embodiment of the present invention, drive unit 5 is preferably hydraulic cylinder, does not adopt other alternative structures such as lever but do not get rid of drive unit 5.

With reference to Fig. 3, used the taking-up equipment of the paper-thin strip of the present invention of Fig. 2, the method for coiling of paper-thin strip is as shown in Figure 3 accordingly:

Step 301: beginning.

Step 302: collect the device parameter of coiler mandrel and pressure roller, mainly comprise outside barrel diameter R ₀=508mm, pressure roller diameter are d _y=160mm, the radius of turn of pressure roller is R _ZyThe vertical range at the reel center of the pivot of=1420mm, pressure roller and coiling machine is l _Oa=1545mm, horizontal range are The diameter d of upper S roller _Ss=610mm, lower S roller diameter d _SxThe vertical range l at=610mm, upper S roller top and coiler mandrel center _Fd=1270mm, lower S roller bottom are l with the vertical range at the reel center of coiling machine _Cd=50mm, the horizontal range at S roller and coiler mandrel center up and down

Step 303: the characteristic parameter of collecting belt steel mainly comprises thickness h=0.15mm, the width b=900mm with steel, band steel yield limit σ with steel _s=400Mpa, with the elastic modulus E=2.1*10 of steel ⁵Mpa.

Step 304: given all kinds of application factors comprise that mainly pressure roller power application factor ξ=1.0, pressure roller lift the application factor ψ of position ₁=1.6, ψ ₂=0.6.

Step 305: utilize formula

Calculate pressure roller and lift position R _t=1207.1mm.

Step 306: pressure roller is depressed when batching beginning, and the band steel batches at coiling machine, definition coiling process parameter k (k namely represents to be with steel to wrap coiling machine k circle), given maximum reeling radius R _Max=1750mm, and make k=1.

Step 307: calculating reeling radius R is R=R ₀+ kh=508.15mm.

Step 308: judge inequality R≤R _tSet up? if inequality is set up, then be with pressure roller to batch, pressure roller Position Control angle $\mathrm{\&beta;}={\mathrm{\&beta;}}_1+{\mathrm{\&beta;}}_2=\arcsin \left(\frac{l_{o_{1}a}}{\sqrt{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2}}\right)+\arccos \left(\frac{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2+R_{\mathrm{zy}}^2-{(R+\frac{d_y}{2})}^2}{2R_{\mathrm{zy}}\sqrt{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2}}\right),$ Batch angle

, pressure roller pressure

Change step 309 over to.If inequality is false, then pressure roller lifts, and changes step 309 over to.Wherein, M _{Bullet is moulded}Be under the effect of pressure roller thrust, band bullet that steel produces is moulded the bending moment value, and h ₁Be elastic region Partial Height on the band steel cross section, ${\mathrm{<figure-callout\; id="1"\; label="h"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">h</figure-callout>}}_1=\frac{{\mathrm{\&sigma;}}_s\&times;2R}{E}.$

Step 309: judge inequality R≤R _MaxDoes-h set up? if set up, then make k=k+1, change step 307 over to.Otherwise, change step 310 over to;

Step 310: finish to batch.

With reference to figure 4 and Fig. 5, in conjunction with each above-mentioned parameter, provide the collocation method of press-roller device 2 of the present invention:

Determining of pressure roller Position Control angle

In order to find the solution pressure roller Position Control angle β, at first must find the solution β ₁, β ₁Be AO and OO ₁The angle of line.

As shown in Figure 5, according to geometric knowledge, at △ AOO ₁In, have:

$\sin \left({\mathrm{\&beta;}}_1\right)=\frac{A{O}_1}{\mathrm{<figure-callout\; id="1"\; label="O\; O"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">O</figure-callout>}{O}_{}{}_1}=\frac{600}{\sqrt{{1545}^2+{600}^2}}=0.362---\left(1\right)$

By formula (1) as can be known:

β ₁＝31.19°(2)

Then, find the solution β ₂, β ₂OO ₁With O O ₂The angle of line.

At △ BOO ₁In, according to the cosine law, have:

${\mathrm{\&beta;}}_2=\arccos \left(\frac{{\mathrm{OO}}_1^2+{\mathrm{OO}}_2^2-O_1{\mathrm{<figure-callout\; id="2"\; label="O"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">O</figure-callout>}}_2^2}{2O{O}_1\&CenterDot;O{O}_2}\right)---\left(3\right)$

Wherein:

$\mathrm{<figure-callout\; id="1"\; label="O\; O"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">O</figure-callout>}{O}_{}{}_1=\sqrt{{1545}^2+{600}^2}=1657.42---\left(4\right)$

OO ₂＝1420 (5)

O ₁O ₂＝R+80 (6)

Formula (4) to (6) substitution formulas (3) are got:

${\mathrm{\&beta;}}_2=\arccos \left(\frac{{\mathrm{OO}}_1^2+{\mathrm{OO}}_2^2-O_1{\mathrm{<figure-callout\; id="2"\; label="O"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">O</figure-callout>}}_2^2}{2O{O}_1\&CenterDot;O{O}_2}\right)$

$=\arccos \left(\frac{{1657.42}^2+{1420}^2-{(R+80)}^2}{2\&CenterDot;1657.42\&CenterDot;1420}\right)$

$=\arccos \left(\frac{4757041-{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">R</figure-callout>}}^{2}160R}{4707073}\right)---\left(7\right)$

Finally, obtain pressure roller Position Control angle:

Batch the angle control method

As shown in Figure 5 and Figure 6, to batch angle α in order finding the solution, at first must to find the solution α ₁In Fig. 5, the B point is the reel center O of coiling machine ₁Movable end center O with press-roller device ₂Contact point.Batching angle α is O ₁O ₂The tangent line of ordering at B and the angle of BC line, α ₁O ₁O and O ₁The angle of A.

According to geometric knowledge, at △ AOO ₁In, have:

$\cos \left({\mathrm{\&alpha;}}_1\right)=\frac{{\mathrm{<figure-callout\; id="1"\; label="AO"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">AO</figure-callout>}}_1}{{\mathrm{<figure-callout\; id="1"\; label="OO"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">OO</figure-callout>}}_1}=\frac{600}{\sqrt{{1545}^2+{600}^2}}=0.362---\left(9\right)$

By formula (9) as can be known:

α ₁＝68.81° (10)

Then, find the solution α ₂, α ₂O ₁O and O ₁O ₂Angle.

At △ BOO ₁In, according to the cosine law, have:

${\mathrm{\&alpha;}}_2=\arccos \left(\frac{{\mathrm{<figure-callout\; id="1"\; label="OO"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">OO</figure-callout>}}_1^2+O_1{\mathrm{<figure-callout\; id="2"\; label="O"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">O</figure-callout>}}_2^2-{\mathrm{<figure-callout\; id="2"\; label="OO"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">OO</figure-callout>}}_2^2}{2{\mathrm{<figure-callout\; id="1"\; label="OO"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">OO</figure-callout>}}_1\&CenterDot;O_1{O}_2}\right)$

$=\arccos \left(\frac{{1657.42}^2+{(R+80)}^2-{1420}^2}{2\&CenterDot;1657.42\&CenterDot;(R+80)}\right)$

$=\arccos \left(\frac{{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">R</figure-callout>}}^2+160R+737041.1}{3314.84R+265187.2}\right)---\left(11\right)$

Subsequently, find the solution α ₄, α ₄CO ₁And O ₁The angle of D.

At △ CO ₁Among the D, according to the cosine law, have:

${\mathrm{\&alpha;}}_4=\arcsin \left(\frac{\mathrm{CD}}{O_{1}C}\right)---\left(12\right)$

CD=1270-610*2=50 (13) wherein

$O_{1}C=\sqrt{O_1{\mathrm{<figure-callout\; id="2"\; label="D"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">D</figure-callout>}}^2+{\mathrm{<figure-callout\; id="2"\; label="CD"\; filenames="HDA0000156174020000021.png"\; state="\{\{state\}\}">CD</figure-callout>}}^2}=\sqrt{{2200}^2+{50}^2}=2200.568---\left(14\right)$

Formula (13), (14) substitution formula (12) are got:

Find the solution again α ₃, α ₃O ₁O ₂And O ₁The angle of C.Like this, α ₃Can represent with following formula:

At △ O ₁Among the BC, can be known by the cosine law

Like this, at △ O ₁Have among the BC

Put in order:

The pressure roller pressure setting method

According to research, pressure roller power P can adopt model as shown in Figure 6:

$P=\frac{\mathrm{\&xi;}}{12R\sin \mathrm{\&alpha;}}({3h}^2-{\mathrm{<figure-callout\; id="1"\; label="h"\; filenames="HDA0000156174020000021.png,HDA0000156174020000031.png"\; state="\{\{state\}\}">h</figure-callout>}}_1^2)h{\mathrm{\&sigma;}}_s---\left(20\right)$

In the formula: ξ-application factor, in the present embodiment, get ξ=1.0;

σ _s-band steel yield limit in the present embodiment, is selected σ _s=400Mpa;

h ₁Elastic region Partial Height on the-band steel cross section, namely

H-belt steel thickness, in the present embodiment h=0.15mm;

B-strip width, in the present embodiment b=900mm;

E-band steel bomb modulus, in the present embodiment E=2.1*10 ⁵Mpa.

Pressure roller lifts location determining method

For Thin Strip Steel, in order to guarantee reeling quality, pressure roller is not that entire volume is all being pressed in coiling process, but unclamps after being wound to certain diameter.Lift the position for control reeling quality and important: if lift too early then can not guarantee reeling quality, can increase first coiling power evening and lift, second can be because of occurring cut because pressure roller pressure is less, pressure roller is unstable at belt steel surface.Lift the position for pressure roller, then main relevant with belt steel thickness and coiler mandrel radius: belt steel thickness is less, and it is more late to lift the position; The reel radius is larger, lifts the position more early.Follow the tracks of and theory analysis through a large amount of scenes, provide following computational methods:

$R_t=\frac{{\mathrm{\&psi;}}_1{R}_0}{e^{{\mathrm{\&psi;}}_{2}h}}=\frac{2.6*508}{e^{0.6*0.15}}=1207.1---\left(21\right)$

In the formula: R _t-pressure roller lifts the position;

R ₀-coiler mandrel external diameter, in the present embodiment R ₀=508mm;

H-belt steel thickness, in the present embodiment h=0.15mm;

ψ ₁, ψ ₂-pressure roller lifts the application factor of position, in the present embodiment ψ ₁=2.6, ψ ₂=0.6

Compare with the conventional spool press-roller device, press-roller device of the present invention both can be adjusted pressure roller pressure, can adjust pressure roller position and cornerite again, batch, realize not occur in the strip coiling process skidding thereby not only can guarantee to stablize, and can effectively administer reeling quality problems such as being with the cramp of steel fold.Especially, the relevant device and method that batches of the present invention not only is fit to the following paper-thin strip of 0.18m m, and the above band steel of suitable 0.18mm, strong adaptability.

Those of ordinary skill in the art will be appreciated that above specification only is one or more embodiments among the numerous embodiment of the present invention, and is not as limitation of the invention.Any for the above embodiment equalization variation, modification and be equal to the technical schemes such as alternative, as long as connotation scope according to the invention, all will drop in the scope that claims of the present invention protect.

Claims (10)

1. the taking-up equipment of a paper-thin strip is characterized in that, comprising:

Coiling machine, press-roller device and drive unit;

Described press-roller device is L shaped mechanical arm, and the one end is fixed in the back side top of described coiling machine, as the pivot of described press-roller device;

Described drive unit is arranged at the rear side of described coiling machine, and links to each other with the described pivot of described press-roller device, drives described press-roller device and rotates around described pivot.

2. the taking-up equipment of paper-thin strip as claimed in claim 1 is characterized in that:

The overbending direction of described L shaped mechanical arm is towards the reel center of described coiling machine.

3. the taking-up equipment of paper-thin strip as claimed in claim 2 is characterized in that, also comprises:

Upper S roller and lower S roller;

Described upper S roller is arranged at directly over the described lower S roller, and the line at the center of the center of described upper S roller and described lower S roller is perpendicular to horizontal plane;

The bottom of described lower S roller is higher than the described reel center of described coiling machine.

4. the taking-up equipment of paper-thin strip as claimed in claim 1 is characterized in that:

Described drive unit is hydraulic cylinder.

5. the method for coiling of a paper-thin strip is characterized in that, may further comprise the steps:

Collect the device parameter of reel and pressure roller;

The characteristic parameter of collecting belt steel;

Given all kinds of application factor;

Calculate the position of lifting of pressure roller;

Definition coiling process parameter, and given maximum reeling radius;

Calculate reeling radius;

Judge the pressure roller position;

Judge whether reeling radius deducts the poor of belt steel thickness less than or equal to maximum reeling radius.

6. the method for coiling of paper-thin strip as claimed in claim 5 is characterized in that:

Described reel parameter comprises:

Coiler mandrel external diameter R ₀, the pressure roller diameter is d _y, the radius of turn of pressure roller is R _Zy, the pivot of pressure roller and the vertical range at coiler mandrel center be l _Oa, horizontal range is

The diameter d of upper S roller _Ss, lower S roller diameter d _Sx, upper S roller top and coiling machine the vertical range l at reel center _Fd, lower S roller bottom is l with the vertical range at the reel center of coiling machine _Cd, the horizontal range at S roller and coiler mandrel center up and down

Described characteristic parameter with steel comprises thickness h, the width b with steel, the band steel yield limit σ with steel _s, with the elastic modulus E of steel;

Described application factor comprises that pressure roller power application factor ξ, pressure roller lift the application factor ψ of position ₁, ψ ₂

7. the method for coiling of paper-thin strip as claimed in claim 6 is characterized in that:

The computing formula that described pressure roller lifts the position is

8. the method for coiling of paper-thin strip as claimed in claim 6 is characterized in that:

The computing formula of described reeling radius is R=R ₀+ kh, wherein k represents to be with steel to wrap coiling machine k circle.

9. the method for coiling of paper-thin strip as claimed in claim 6 is characterized in that:

The computing formula of described pressure roller Position Control angle β is $\mathrm{\&beta;}={\mathrm{\&beta;}}_1+{\mathrm{\&beta;}}_2=\arcsin \left(\frac{l_{o_{1}a}}{\sqrt{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2}}\right)+\arccos \left(\frac{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2+R_{\mathrm{zy}}^2-{(R+\frac{d_y}{2})}^2}{2R_{\mathrm{zy}}\sqrt{{l_{\mathrm{oa}}}^2+{l_{o_{1}a}}^2}}\right),$

Wherein, β ₁Be the line of the pivot of the reel center of described coiling machine and pressure roller and angle, the β of plumb line direction ₂Be the angle between the line of the pivot of the reel center of the line of minimum steel band situation lower compression roller center and described pressure roller pivot and described coiling machine and described pressure roller.

10. the method for coiling of paper-thin strip as claimed in claim 6 is characterized in that:

Describedly judge that whether reeling radius is R≤R less than or equal to the formula that maximum reeling radius deducts the difference of belt steel thickness _Max-h, wherein R _MaxBe maximum reeling radius.

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