CN103109561A - WCDMA system residual capacity evaluation method, device and equipment - Google Patents

Abstract

The invention provides a WCDMA system residual capacity evaluation method, a device and equipment. The method comprises acquiring the equivalent bandwidth of each business according to the total bandwidth of the WCDMA system, the predetermined error rate, the information rate, and the activity factor of each business in the WCDMA system; acquiring the residual capacity of the WCDMA system according to the equivalent bandwidth of at least one business and the total bandwidth of the WCDMA. Therefore the evaluation of the residual capacity can be realized, when various types of the businesses in the WCDMA system exist.

Description

Method, device and equipment for estimating remaining capacity of WCDMA system

technical field

The present invention relates to communication technology, in particular to a method, device and equipment for estimating the remaining capacity of a Wideband Code Division Multiple Access (WCDMA) system.

Background technique

Due to the mobility of the mobile terminal, it is necessary to switch between different cells. When switching, it is necessary to compare the remaining capacity of the target cell with the remaining capacity of the current serving cell. If the remaining capacity of the target cell is large, the handover is accepted, otherwise it is rejected.

In the Time Division Multiple Access (hereinafter referred to as: TDMA) system, the remaining capacity of the system can be estimated by calculating the remaining time slots; in the frequency division multiple access (Frequency Division Multiple Access, hereinafter referred to as: FDMA) system, the The remaining bandwidth is used to estimate the remaining capacity; while the Wideband Code Division Multiple Access (hereinafter referred to as: WCDMA) system is a Quality of Service (hereinafter referred to as: QoS) limited system, that is, the system capacity depends on the user QoS Requirements, such as bit error rate and information rate, are usually used to represent user QoS requirements, and users occupy the spectrum bandwidth of the entire system through spread spectrum. Due to the above-mentioned characteristics of the WCDMA system, when calculating the capacity of the WCDMA system, the prior art calculates by separately analyzing the capacity of a certain service type, that is, assuming that the system only supports one kind of service, the rate requirement and error rate of the service can be used to calculate the capacity of the WCDMA system. The code rate is required to calculate the maximum number of users that the system can support for the service, and subtract the existing users from the maximum number of users to obtain the number of users that can be accessed by the remaining capacity.

However, in practical applications, there are often multiple services with different rates and bit error rate requirements in the WCDMA system at the same time. When there are multiple service types in the WCDMA system, the remaining capacity of the WCDMA system cannot be calculated by the existing technology .

Contents of the invention

Embodiments of the present invention provide a method, device and equipment for estimating the remaining capacity of a WCDMA system to solve the problem in the prior art that the remaining capacity of the WCDMA system cannot be calculated when there are multiple service types in the WCDMA system.

In the first aspect, an embodiment of the present invention provides a method for estimating the remaining capacity of a wideband code division multiple access WCDMA system, including: according to the total bandwidth of the WCDMA system and the preset bit error rate of each service in the WCDMA system, information rate and activation factor to obtain the equivalent bandwidth of each of the services;

Acquiring the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system.

In the first possible implementation manner, the equivalent bandwidth of each service is obtained according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system include:

Acquiring the processing gain of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services;

Obtaining the equivalent bandwidth of each of the services according to the total bandwidth of the WCDMA system and the processing gain, the bit error rate and the activation factor of each of the services.

计算每个所述业务的处理增益，其中，G_m为所述业务的处理增益，W为所述WCDMA系统的总带宽，R_b为所述业务预设的信息速率；With reference to the first possible implementation of the first aspect, in a second possible implementation, according to the total bandwidth of the WCDMA system and the information rate preset for each of the services, acquire each Business processing gains include: According to

Calculating the processing gain of each of the services, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service;

计算每个所述业务的等效带宽，其中，

为所述业务的等效带宽，γ_m为所述业务的激活因子，

为所述业务的误码率，G_m为所述业务的处理增益，Q为运算函数，

According to the total bandwidth of the WCDMA system and the processing gain of each of the services, the bit error rate and the activation factor, obtaining the equivalent bandwidth of each of the services includes: according to

Calculate the equivalent bandwidth of each of said services, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

Be the bit error rate of described business, G _m is the processing gain of described business, Q is operation function,

In the second aspect, an embodiment of the present invention provides a device for estimating the remaining capacity of a wideband code division multiple access WCDMA system, including:

The first calculation unit is configured to obtain the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system;

The second calculation unit is configured to obtain the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system.

In a first possible implementation manner, the first calculation unit includes:

The first calculation subunit is used to obtain the processing gain of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services;

The second calculation subunit is configured to obtain the equivalent bandwidth of each of the services according to the total bandwidth of the WCDMA system, the processing gain, the bit error rate and the activation factor of each of the services.

计算每个所述业务的处理增益，其中，G_m为所述业务的处理增益，W为所述WCDMA系统的总带宽，R_b为所述业务预设的信息速率；With reference to the first possible implementation manner of the first aspect, in a second possible implementation manner, the first computing subunit is specifically configured to

Calculating the processing gain of each of the services, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service;

为所述业务的等效带宽，γ_m为所述业务的激活因子，

为所述业务的误码率，G_m为所述业务的处理增益，Q为运算函数， $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\π}}}\underset{x}{\overset{\∞}{\∫}}\exp (-y^2/2)\mathrm{dy}.$ The second calculation subunit is specifically used for Calculate the equivalent bandwidth of each of said services, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

Be the bit error rate of described business, G _m is the processing gain of described business, Q is operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; <figure-callout\; id="2"\; label="y"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">y</figure-callout>}}^2/2)\mathrm{dy}.$

In a third aspect, an embodiment of the present invention provides a device for estimating the remaining capacity of a wideband code division multiple access WCDMA system, including:

A memory for storing preset bit error rates, information rates and activation factors for each service in the WCDMA system;

A processor, configured to obtain the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system, and according to at least one The equivalent bandwidth of the service and the total bandwidth of the WCDMA system are obtained to obtain the remaining capacity of the WCDMA system.

In a first possible implementation manner, the processor is specifically configured to obtain the processing gain of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services, and according to the The total bandwidth of the WCDMA system and the processing gain, the bit error rate and the activation factor of each of the services are used to obtain the equivalent bandwidth of each of the services.

为所述业务的等效带宽，γ_m为所述业务的激活因子，

为所述业务的误码率，G_m为所述业务的处理增益，Q为运算函数， $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-y^2/2)\mathrm{dy}.$ With reference to the third aspect or the first possible implementation manner of the third aspect, in a second possible implementation manner, the processor is specifically configured to Calculate the processing gain of each of the services, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service, and according to Calculate the equivalent bandwidth of each of said services, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

Be the bit error rate of described business, G _m is the processing gain of described business, Q is operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; <figure-callout\; id="2"\; label="y"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">y</figure-callout>}}^2/2)\mathrm{dy}.$

The method, device and equipment for estimating the remaining capacity of a WCDMA system provided by the embodiments of the present invention. When there are one or more services with different preset bit error rates, information rates and activation factors in the WCDMA system, the total bandwidth of the WCDMA system and the preset bit error rates, information rates and activation factors of each service in the WCDMA system factor to obtain the equivalent bandwidth of each service; then, obtain the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system. The method realizes the estimation of the remaining capacity of the system when multiple different services exist in the WCDMA system, and solves the problem in the prior art that it is impossible to estimate the remaining capacity of the system when multiple different services exist in the WCDMA system at the same time.

Description of drawings

In order to more clearly illustrate the technical solutions in the embodiments of the present invention or the prior art, the following will briefly introduce the drawings that need to be used in the description of the embodiments or the prior art. Obviously, the accompanying drawings in the following description are only These are some embodiments of the present invention. For those skilled in the art, other drawings can also be obtained according to these drawings without any creative effort.

FIG. 1 is a schematic flow chart of Embodiment 1 of a method for estimating the remaining capacity of a WCDMA system according to the present invention;

FIG. 2 is a schematic flow chart of Embodiment 2 of a method for estimating the remaining capacity of a WCDMA system according to the present invention;

3 is a schematic diagram of a system model of Embodiment 2 of the method for estimating the remaining capacity of a WCDMA system according to the present invention;

FIG. 4 is a constellation diagram of QPSK modulation in Embodiment 2 of the method for estimating the residual capacity of a WCDMA system according to the present invention;

5 is a schematic flow chart of Embodiment 3 of the method for estimating the remaining capacity of the WCDMA system according to the present invention;

FIG. 6 is a schematic structural diagram of Embodiment 1 of the device for estimating the remaining capacity of the WCDMA system according to the present invention;

FIG. 7 is a schematic structural diagram of Embodiment 2 of the device for estimating the remaining capacity of the WCDMA system according to the present invention;

FIG. 8 is a schematic structural diagram of Embodiment 1 of a device for estimating the remaining capacity of a WCDMA system according to the present invention.

Detailed ways

The following will clearly and completely describe the technical solutions in the embodiments of the present invention with reference to the accompanying drawings in the embodiments of the present invention. Obviously, the described embodiments are only some, not all, embodiments of the present invention. Based on the embodiments of the present invention, all other embodiments obtained by persons of ordinary skill in the art without making creative efforts belong to the protection scope of the present invention.

In the following embodiments of methods, devices and devices for estimating the remaining capacity of a WCDMA system, the WCDMA system may specifically be a variable gain WCDMA system.

Fig. 1 is a schematic flow chart of Embodiment 1 of a method for estimating the remaining capacity of a WCDMA system according to the present invention. As shown in Fig. 1, the method includes the following steps:

Step 101: Obtain the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system.

Specifically, in the WCDMA system, user services occupy the spectrum bandwidth of the entire system through spread spectrum. The total bandwidth of the system is 3.84M. Under the conditions of satisfying the preset bit error rate, information rate and activation factor of each service, it can Obtain the equivalent bandwidth of each service through the relationship between the equivalent bandwidth and the total bandwidth, the preset bit error rate, the information rate, and the activation factor.

Step 102: Obtain the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system.

Specifically, there is at least one service in the WCDMA system, the equivalent bandwidth of a single service is calculated through step 101, and the total bandwidth of the WCDMA system is used to subtract the equivalent bandwidth of each service existing in the system to obtain the remaining bandwidth of the WCDMA system capacity.

In this embodiment, when there are one or more services with different preset bit error rates, information rates, and activation factors in the WCDMA system, the total bandwidth of the WCDMA system and the preset bit error rates of each service in the WCDMA system, The information rate and the activation factor are used to obtain the equivalent bandwidth of each service; then, according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system, the remaining capacity of the WCDMA system is obtained. The method realizes the estimation of the remaining capacity of the system when there are multiple different types of services in the WCDMA system, and solves the problem in the prior art that the estimation of the remaining capacity of the system cannot be calculated when multiple different services of the WCDMA system exist at the same time.

Fig. 2 is a schematic flow chart of Embodiment 2 of the method for estimating the residual capacity of the WCDMA system of the present invention. Fig. 2 is based on step 101 of the method embodiment shown in Fig. 1 , and explains in more detail the method for estimating the equivalent bandwidth of the WCDMA system, as As shown in Figure 2, the method includes:

Step 201: Obtain the processing gain of each service according to the total bandwidth of the WCDMA system and the preset information rate of each service.

计算每个业务的处理增益，其中，G_m为业务的处理增益，W为WCDMA系统的总带宽，r_b为业务预设的信息速率。Specifically, according to

Calculate the processing gain of each service, where G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and r _b is the preset information rate of the service.

可以按照如下过程推导获得：In more detail, the formula

It can be derived as follows:

Taking the single code channel transmission scheme of the WCDMA system as an example, Fig. 3 is a schematic diagram of the system model of Embodiment 2 of the method for estimating the residual capacity of the WCDMA system of the present invention; The transmitter includes: channel coding (interleaving/channel adaptive filling), carrier modulation and spread spectrum modules, wherein the carrier modulation can be Quadrature Phase Shift Keying (QuadraturePhase Shift Keying, hereinafter referred to as: QPSK) modulation, after processing All business rates reach a unified 3.84Mbps, occupying the entire spectrum bandwidth of the system.

Correspondingly, in the downlink, the service data is received by the downlink receiver through the wireless channel with interference and noise characteristics. The receiver includes: despreading module, carrier demodulation and channel decoding. After processing, the service rate reaches the baseband rate.

The input signal-to-noise ratio of the receiver is S _i /N _i , where S _i is the input signal power, and N _i is the input noise power. The output signal-to-noise ratio of the receiver is S _o /N _o , where S _o is the output signal power and N _o is the output noise power.

The processing gain of the receiver is defined as the ratio of the output SNR to the input SNR, then the processing gain of the receiver can be expressed as:

$G=\frac{S_o/N_o}{S_i/N_i}$ --Formula 1

In the case that there are K services of the same type in the system, let P be the received signal power of each user service, W be the spread spectrum bandwidth of the system, n ₀ be the power spectral density of the noise, (K-1)P is the received interference power of other users, then the input signal-to-noise ratio of the user service in the receiver can be expressed as:

$\frac{S_i}{N_i}=\frac{P}{(K-1)P+{\mathrm{no}}_{0}W}$ ——Formula 2

其他用户或干扰噪声信号与用户信号的地址码不相关，不能得到解调，因此其他用户或干扰噪声信号的功率保持不变。则该用户业务在接收机的输出信噪比为：After the receiver despreads and demodulates, all the user's service signals are received, and the bandwidth has been converted to the baseband at the same time. Let the information rate of the baseband signal be r _b , and the useful service signal power at this time is

Other users or interfering noise signals are not correlated with the address codes of user signals and cannot be demodulated, so the power of other users or interfering noise signals remains unchanged. Then the output signal-to-noise ratio of the user service at the receiver is:

$\frac{S_o}{N_o}=\frac{\frac{P}{W}\&times;r_b}{(K-1)P+{\mathrm{no}}_{0}W}=\frac{P}{(K-1)P+{\mathrm{no}}_{0}W}\&times;\frac{W}{r_b}$ ——Formula 3

Putting Equation 2 and Equation 3 into Equation 1, the expression of processing gain can be obtained as follows:

$G=\frac{S_o/N_o}{S_i/N_i}=\frac{W}{r_b}$ ——Formula 4

Putting Equation 4 into Equation 3, we can get:

$\frac{S_o}{N_o}=\frac{P}{(K-1)P+{\mathrm{no}}_{0}W}\&times;G$ ——Formula 5

In the case of multiple types of services in the system, assuming that there are M types of services in the system, N _m is the number of m-th type of business in the system, G _m is the processing gain of the m-th type of business in the system, γ _m is the activation factor of the m-th type of business in the system, and P _m is the received power of the m-th type of business in the system, wherein the value ranges of the above m are 1, 2, ..., M , in the additive Gaussian white noise channel model, the thermal noise power is N ₀ .

According to Equation 4, the processing gain of the m-th type of business is:

$G_m=\frac{W}{r_b}$ ——Formula 6

According to Equation 6, the relationship between the information rate and the processing gain can be known. When the information rate is known, the processing gain corresponding to this type of service can be known.

Step 202: Obtain the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the processing gain, bit error rate and activation factor of each service.

计算每个业务的等效带宽，其中，为业务的等效带宽，γ_m为业务的激活因子，为业务的误码率，G_m为业务的处理增益，Q为运算函数，

Specifically, according to

Calculate the equivalent bandwidth of each service, where, is the equivalent bandwidth of the service, γ _m is the activation factor of the service, is the bit error rate of the business, G _m is the processing gain of the business, Q is the operation function,

可以按照如下过程推导获得：In more detail, the formula

It can be derived as follows:

On the basis of obtaining the relationship between the information rate and the processing gain in step 201, in step 202, first, obtain the relationship between the processing gain, signal-to-noise ratio, activation factor, and equivalent bandwidth; then, obtain the relationship between the signal-to-noise ratio and the bit error rate; Finally, the relationship between processing gain, bit error rate, activation factor, and equivalent bandwidth is obtained.

More specifically, firstly, the relationship among processing gain, signal-to-noise ratio, activation factor and equivalent bandwidth is obtained;

In step 201, when there are multiple types of services in the system, according to formula 5, the signal-to-noise ratio of the mth type of service output by the receiver is:

$\frac{{\mathrm{<span\; class="notranslate">\; S</span>}}_{\mathrm{<span\; class="notranslate">\; om</span>}}}{{\mathrm{<span\; class="notranslate">\; N</span>}}_{\mathrm{<span\; class="notranslate">\; om</span>}}}<span\; class="notranslate">\; =</span>\frac{{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}}{{\mathrm{<span\; class="notranslate">\; \&Sigma;</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 1</span>}}^{\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; N</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}}{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}}{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}}<span\; class="notranslate">\; -</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}<span\; class="notranslate">\; +</span>{\mathrm{<span\; class="notranslate">\; N</span>}}_{\mathrm{<span\; class="notranslate">\; 0</span>}}}$

$=\frac{P_m{G}_m}{{\mathrm{\&Sigma;}}_{\underset{j\&NotEqual;m}{j=1}}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j+N_m{P}_m{\mathrm{\&gamma;}}_m-P_m{\mathrm{\&gamma;}}_m+N_0}$ ——Formula 7

When ensuring the normal operation of this type of service, the output signal-to-noise ratio must meet the requirement of a minimum signal-to-noise ratio R _m , namely:

$\frac{P_m{G}_m}{{\mathrm{\&Sigma;}}_{\underset{j\&NotEqual;m}{j=1}}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j+N_m{P}_m{\mathrm{\&gamma;}}_m-P_m{\mathrm{\&gamma;}}_m+N_0}\&Greater\; Equal;R_m$ ——Formula 8

Arranging formula 8 to get:

$\frac{\frac{{\mathrm{\&gamma;}}_m{R}_m}{{\mathrm{\&gamma;}}_m{R}_m+G_m}}{{\mathrm{\&gamma;}}_m-\frac{{\mathrm{\&gamma;}}_m{R}_m}{{\mathrm{\&gamma;}}_m{R}_m+G_m}{\mathrm{\&gamma;}}_m{N}_m}({\mathrm{\&Sigma;}}_{\underset{j\&NotEqual;m}{j=1}}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j+N_0)\&le;P_m$ ——Formula 9

将β_m带入式9中，整理得：make

Bringing β _m into Equation 9, we get:

$\frac{{\mathrm{<span\; class="notranslate">\; \&beta;</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}}{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}<span\; class="notranslate">\; -</span>{\mathrm{<span\; class="notranslate">\; \&beta;</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; N</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; \&Sigma;</span>}}_{\underset{\mathrm{<span\; class="notranslate">\; j</span>}<span\; class="notranslate">\; \&NotEqual;</span>\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; j</span>}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 1</span>}}}^{\mathrm{<span\; class="notranslate">\; m</span>}}{\mathrm{<span\; class="notranslate">\; N</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}}{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}}{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; j</span>}}<span\; class="notranslate">\; +</span>{\mathrm{<span\; class="notranslate">\; N</span>}}_{\mathrm{<span\; class="notranslate">\; 0</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; \&le;</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; m</span>}}$

Therefore, when ensuring the normal operation of this type of service, the minimum received power is:

$P_m=\frac{{\mathrm{\&beta;}}_m}{{\mathrm{\&gamma;}}_m-{\mathrm{\&beta;}}_m{\mathrm{\&gamma;}}_m{N}_m}({\mathrm{\&Sigma;}}_{\underset{j\&NotEqual;m}{j=1}}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j+N_0)$ ——Formula 10

Multiply both sides of formula 10 by (γ _m -β _m γ _m N _m )N _m at the same time, and get:

$N_m{P}_m{\mathrm{\&gamma;}}_m=N_m{\mathrm{\&beta;}}_m\underset{j=1}{\overset{m}{\mathrm{\&Sigma;}}}{N}_j{P}_j{\mathrm{\&gamma;}}_j+N_m{\mathrm{\&beta;}}_m{N}_0$ - Formula 11

According to Formula 11, N ₁ P ₁ γ ₁ , N ₂ P ₂ γ ₂ , N ₃ P ₃ γ ₃ , ... N _m P _m γ _m are accumulated and summed to get:

${\mathrm{\&Sigma;}}_{j=1}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j={\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j+N_0{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j$ - Formula 12

Arrange formula 12 into:

${\mathrm{\&Sigma;}}_{j=1}^m{N}_j{P}_j{\mathrm{\&gamma;}}_j=\frac{N_0{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j}{1-{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j}$ - Formula 13

Putting Equation 13 into Equation 10, we get:

$P_m=\frac{N_0{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j}{1-{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j}$ - Formula 14

Equation 14 is the solution of the minimum received power when the service is guaranteed to work normally. From Equation 14, it can be concluded that the necessary and sufficient conditions for the received power P _m to have a solution are:

$1-{\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j>0$ - Formula 15

Right now:

${\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_j<1$ - Formula 16

Multiplying both sides of Equation 16 by the total bandwidth W at the same time, we can get:

${\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\mathrm{\&beta;}}_{j}W<W$ - Formula 17

将上式带入式17中整理得：make

Bring the above formula into formula 17 to get:

${\mathrm{\&Sigma;}}_{j=1}^m{N}_j{\&PartialD;}_j<W$ - Formula 18

的积求和小于总带宽，因此，可以将

定义为第j类业务对应的等效带宽。Since W represents the total bandwidth of the system, and N _j represents the number of services of the jth type that exist simultaneously in the system, the meaning expressed in the above formula can be understood as: the condition that the system can guarantee the service QoS requirements is that the number of various services in the system is multiplied by corresponding

The sum of the products is less than the total bandwidth, therefore, the

Defined as the equivalent bandwidth corresponding to the jth type of business.

Thus available:

${\&PartialD;}_m={\mathrm{\&beta;}}_{m}W=\frac{{\mathrm{\&gamma;}}_m{R}_{m}W}{{\mathrm{\&gamma;}}_m{R}_m+G_m}$ - Formula 19

From Equation 19, the relationship among processing gain, SNR, activation factor, and equivalent bandwidth can be obtained; thus, when the processing gain, SNR, and activation factor of a given service are given, according to Equation 19, in a WCDMA system, The equivalent bandwidth corresponding to the service.

However, in a real system, the user's QoS requirement is usually expressed by the bit error rate, so, then, the relationship between the signal-to-noise ratio and the bit error rate is obtained;

In the WCDMA system, the modulation method used is QPSK, regardless of using a matched filter or a correlation receiver, the same bit error rate can be achieved. The I and Q channels of QPSK are both binary phase shift keying (Binary Phase Shift Keying, hereinafter referred to as: BPSK) modulation, and the two BPSKs are orthogonal to each other during ideal coherent demodulation.

Fig. 4 is the constellation diagram of QPSK modulation of the second embodiment of the method for estimating the remaining capacity of the WCDMA system of the present invention. As shown in Fig. 4, the constellation diagram of QPSK has four constellation points, and the coordinates are respectively S ₁ =(A, 0), S ₂ = (0, A), S ₃ = (-A, 0), S ₄ = (0, -A). It can be seen from Figure 4 that the distance between S ₁ and S ₃ is 2A, and the distance between S ₁ and S ₂ is

r _b is the bit signal-to-noise ratio, which is defined as the ratio of information energy E _b per bit to noise power 2N ₀ , and the expression of information energy per bit is:

${\mathrm{E.}}_b={\&Integral;}_0^{T_b}{\mathrm{the\; s}}_1^2\left(t\right)\mathrm{dt}=A^2$ - Formula 20

so: $r_b=\frac{{\mathrm{<figure-callout\; id="2"\; label="A"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">A</figure-callout>}}^2}{2N_0}$ - Formula 21

Similarly, _rs is the SNR of QPSK symbols, because each symbol contains 2 bits, so the energy of each symbol is twice the information energy per bit, ie E _s =2E _b =2A ² . The noise power is 2N ₀ , so the expression of the symbol signal-to-noise ratio r _s can be obtained as:

$r_{\mathrm{the\; s}}=\frac{A^2}{N_0}$ - Formula 22

Approximately, the symbol error rate of QPSK is approximated by multiplying the bit error rate corresponding to the minimum distance d _min on the constellation diagram by the number M _dmin of adjacent constellation points with a distance d _min , namely:

$P_{\mathrm{the\; s}}\&ap;m_{d_{\min }}Q\left(\frac{d_{\min }}{\sqrt{2N_0}}\right)$ ——Formula 23

Among them, Q is the operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; <figure-callout\; id="2"\; label="y"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">y</figure-callout>}}^2/2)\mathrm{dy}.$

It can be seen from Figure 4 that the minimum distance between QPSK constellation points is:

${\mathrm{<span\; class="notranslate">\; d</span>}}_{\mathrm{<span\; class="notranslate">\; min</span>}}<span\; class="notranslate">\; =</span>\sqrt{\mathrm{<span\; class="notranslate">\; 2</span>}\mathrm{<span\; class="notranslate">\; A</span>}}$

可以得到QPSK误符号率的近似公式：The number of adjacent constellation points with a distance of d _min

An approximate formula for the QPSK symbol error rate can be obtained:

$P_{\mathrm{the\; s}}\&ap;2Q\left(\sqrt{\frac{A^2}{N_0}}\right)=2Q\left(\sqrt{r_{\mathrm{the\; s}}}\right)$ - formula 24

Each symbol or information contains log ₂ M bits, and in QPSK, M=4. In the system, Gray code is used for encoding, that is, there is only one symbol difference between two adjacent symbols. For example, in Figure 4, S ₁ is encoded with "00", S ₂ is encoded with "01", and S ₃ is encoded with "11""Encoding, _S4 is encoded with "10".

The way of coding with Gray code ensures that when there is a judgment error between two adjacent symbols, there is only one bit error, and the error in the adjacent judgment domain is most likely to occur, so it can be approximately considered that between the adjacent judgment and When an error occurs, only one bit error occurs, and the approximate expression of the bit error rate can be expressed as:

$P_b\&ap;\frac{P_{\mathrm{the\; s}}}{{\log }_{2}m}=\frac{P_{\mathrm{the\; s}}}{2}$ - Formula 25

From Equation 21 and Equation 22, it can be seen that the relationship between symbol SNR and bit SNR is _rs = 2r _b , and the bit error rate in QPSK modulation can be obtained:

$P_b=\frac{1}{2}{P}_{\mathrm{the\; s}}=Q\left(\sqrt{r_{\mathrm{the\; s}}}\right)=Q\left(\sqrt{2r_b}\right)$ - Formula 26

The relationship between bit error rate and bit signal-to-noise ratio for the mth type of business can be expressed as:

$P_b^m=Q\left(\sqrt{2r_b^m}\right)$ - Formula 27

so, $r_b^m={\left[Q^{-1}\left(P_b^m\right)\right]}^2/2$ - Formula 28

为第m类型业务的误比特率，

为第m类型业务的比特信噪比。in,

is the bit error rate of the mth type of business,

is the bit signal-to-noise ratio of the mth type of service.

In the embodiment of the present invention, the bit error rate is the bit error rate. Therefore, Equation 28 expresses the relationship between the bit error rate and the bit signal-to-noise ratio of the mth type of service.

Finally, put Equation 28 into Equation 19 to obtain the relationship between processing gain, bit error rate, activation factor and equivalent bandwidth, namely:

${\&PartialD;}_m=\frac{{\mathrm{\&gamma;}}_m{\left[Q^{-1}\left(P_b^m\right)\right]}^2/2}{{\mathrm{\&gamma;}}_m{\left[Q^{-1}\left(P_b^m\right)\right]}^2/2+G_m}W$ - Formula 29

In this embodiment, according to the total bandwidth of the WCDMA system and the preset information rate of each service, the processing gain of each service is obtained; according to the total bandwidth of the WCDMA system and the processing gain, bit error rate and activation factor of each service, the The equivalent bandwidth of each service, through the equivalent bandwidth formula, the WCDMA method is equivalent to the FDMA method, which is convenient for estimating the remaining capacity of the system when there are many different types of services in the WCDMA system, so as to facilitate network switching When , the remaining capacity of the target cell is compared with the remaining capacity of the current serving cell to improve the reliability of handover. And because the remaining capacity is uniformly represented by the equivalent bandwidth, it is convenient to balance loads through resource management among different systems, which is conducive to the reasonable allocation of resources, as well as the comparison and scheduling of system resources between systems.

FIG. 5 is a schematic flowchart of Embodiment 3 of the method for estimating the remaining capacity of a WCDMA system according to the present invention; this embodiment further describes the embodiment shown in FIG. 2 by taking a specific application as an example, as shown in FIG. 5 .

It is assumed that there are four types of services in the WCDMA system, which are voice services, interactive services, streaming services, and background services.

Step 501: Calculate the equivalent bandwidth of various types of services in the WCDMA system.

编码速率r_b＝12.2k，激活因子γ₁＝0.6，W＝3.84M，采用单码道传输，根据获得话音业务的处理增益为：Voice service: bit error rate

Coding rate r _b =12.2k, activation factor γ ₁ =0.6, W=3.84M, using single code channel transmission, according to The processing gain for obtaining the voice service is:

${\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; W</span>}}{{\mathrm{<span\; class="notranslate">\; r</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}}{\mathrm{<span\; class="notranslate">\; 12.2</span>}\mathrm{<span\; class="notranslate">\; k</span>}}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 315</span>}$

计算出一路话音业务的等效带宽为：If QPSK modulation and demodulation is used, then according to

Calculate the equivalent bandwidth of one voice service as:

${<span\; class="notranslate">\; \&PartialD;</span>}_{\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; =</span>\frac{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 1</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}}{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 1</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}<span\; class="notranslate">\; +</span>{\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 1</span>}}}\mathrm{<span\; class="notranslate">\; W</span>}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 0.6</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}}{\mathrm{<span\; class="notranslate">\; 0.6</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}<span\; class="notranslate">\; +</span>\mathrm{<span\; class="notranslate">\; 315</span>}}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 35</span>}\mathrm{<span\; class="notranslate">\; k</span>}$

数据速率r_b＝64k，激活因子γ₂＝0.3，W＝3840k，采用单码道传输，根据获得话音业务的处理增益为：Interactive business: bit error rate

Data rate r _b =64k, activation factor γ ₂ =0.3, W=3840k, using single code channel transmission, according to The processing gain for obtaining the voice service is:

${\mathrm{<span\; class="notranslate">\; <figure-callout\; id="2"\; label="G"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">G</figure-callout></span>}}_{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; W</span>}}{{\mathrm{<span\; class="notranslate">\; r</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}}{\mathrm{<span\; class="notranslate">\; 64</span>}\mathrm{<span\; class="notranslate">\; k</span>}}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 60</span>}$

计算出一路话音业务的等效带宽为：If QPSK modulation and demodulation is used, then according to

Calculate the equivalent bandwidth of one voice service as:

${<span\; class="notranslate">\; \&PartialD;</span>}_{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; =</span>\frac{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 2</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}}{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 2</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}<span\; class="notranslate">\; +</span>{\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 2</span>}}}\mathrm{<span\; class="notranslate">\; W</span>}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 0.3</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}}{\mathrm{<span\; class="notranslate">\; 0.3</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}<span\; class="notranslate">\; +</span>\mathrm{<span\; class="notranslate">\; 60</span>}}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 89.5</span>}\mathrm{<span\; class="notranslate">\; k</span>}$

数据速率r_b＝64k，激活因子γ₃＝1，W＝3.84M，采用单码道传输，根据

获得话音业务的处理增益为：Streaming services: bit error rate

Data rate r _b =64k, activation factor γ ₃ =1, W=3.84M, using single code channel transmission, according to

The processing gain for obtaining the voice service is:

${\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 3</span>}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; W</span>}}{{\mathrm{<span\; class="notranslate">\; r</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}}{\mathrm{<span\; class="notranslate">\; 64</span>}\mathrm{<span\; class="notranslate">\; k</span>}}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 60</span>}$

计算出一路话音业务的等效带宽为：If QPSK modulation and demodulation is used, then according to

Calculate the equivalent bandwidth of one voice service as:

${<span\; class="notranslate">\; \&PartialD;</span>}_{\mathrm{<span\; class="notranslate">\; 3</span>}}<span\; class="notranslate">\; =</span>\frac{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 3</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 3</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}}{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 3</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 3</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}<span\; class="notranslate">\; +</span>{\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 3</span>}}}\mathrm{<span\; class="notranslate">\; W</span>}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 1</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}}{\mathrm{<span\; class="notranslate">\; 1</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}<span\; class="notranslate">\; +</span>\mathrm{<span\; class="notranslate">\; 60</span>}}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 283</span>}\mathrm{<span\; class="notranslate">\; k</span>}$

数据速率r_b＝64k，激活因子γ₄＝0.2，W＝3.84M，采用单码道传输，根据

获得话音业务的处理增益为：Background business: bit error rate

Data rate r _b =64k, activation factor γ ₄ =0.2, W=3.84M, using single code channel transmission, according to

The processing gain for obtaining the voice service is:

${\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 4</span>}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; W</span>}}{{\mathrm{<span\; class="notranslate">\; r</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}}{\mathrm{<span\; class="notranslate">\; 64</span>}\mathrm{<span\; class="notranslate">\; k</span>}}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 60</span>}$

计算出一路话音业务的等效带宽为：If QPSK modulation and demodulation is used, then according to

Calculate the equivalent bandwidth of one voice service as:

${<span\; class="notranslate">\; \&PartialD;</span>}_{\mathrm{<span\; class="notranslate">\; 4</span>}}<span\; class="notranslate">\; =</span>\frac{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 4</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 4</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}}{{\mathrm{<span\; class="notranslate">\; \&gamma;</span>}}_{\mathrm{<span\; class="notranslate">\; 4</span>}}{<span\; class="notranslate">\; [</span>{\mathrm{<span\; class="notranslate">\; Q</span>}}^{<span\; class="notranslate">\; -</span>\mathrm{<span\; class="notranslate">\; 1</span>}}<span\; class="notranslate">\; (</span>{\mathrm{<span\; class="notranslate">\; P</span>}}_{\mathrm{<span\; class="notranslate">\; b</span>}}^{\mathrm{<span\; class="notranslate">\; 4</span>}}<span\; class="notranslate">\; )</span><span\; class="notranslate">\; ]</span>}^{\mathrm{<span\; class="notranslate">\; 2</span>}}<span\; class="notranslate">\; /</span>\mathrm{<span\; class="notranslate">\; 2</span>}<span\; class="notranslate">\; +</span>{\mathrm{<span\; class="notranslate">\; G</span>}}_{\mathrm{<span\; class="notranslate">\; 3</span>}}}\mathrm{<span\; class="notranslate">\; W</span>}<span\; class="notranslate">\; =</span>\frac{\mathrm{<span\; class="notranslate">\; 0</span>}<span\; class="notranslate">\; .</span>\mathrm{<span\; class="notranslate">\; 2</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}}{\mathrm{<span\; class="notranslate">\; 0.2</span>}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 4.774</span>}<span\; class="notranslate">\; +</span>\mathrm{<span\; class="notranslate">\; 60</span>}}<span\; class="notranslate">\; \&times;</span>\mathrm{<span\; class="notranslate">\; 3840</span>}\mathrm{<span\; class="notranslate">\; k</span>}<span\; class="notranslate">\; =</span>\mathrm{<span\; class="notranslate">\; 60.2</span>}\mathrm{<span\; class="notranslate">\; k</span>}$

Step 502: Calculate the remaining capacity of the WCDMA system.

Assuming that there are 30 voice services, 3 streaming services, 10 interactive services and 2 background services in the system, the remaining capacity of the system is the total system bandwidth minus the equivalent bandwidth occupied by various services, namely:

3840k-35k×30-283k×3-89.5k×10-60.2k×2=925.6k

The remaining capacity of the system can carry any service. Divide the remaining capacity by the equivalent bandwidth corresponding to the service to know the number of services that the system can carry. For example, the above system can also carry 11 voice services and 1 streaming service , 2 interactive services and 1 background service, the remaining capacity of the system is 18.4k, which is not enough to carry any business, and the system reaches the maximum capacity. Alternatively, the above system can carry 4 voice services, 2 streaming services, and 2 interactive services, and the remaining capacity of the system is 40.6k, which is not enough to carry any kind of service, and the system capacity reaches the maximum. As long as the sum of the equivalent bandwidths of all services in the system is less than the total bandwidth of the system, the system can provide reliable transmission for any combination of services.

FIG. 6 is a schematic structural diagram of Embodiment 1 of a device for estimating the remaining capacity of a WCDMA system according to the present invention. As shown in FIG. 6, the device includes a first calculation unit 61 and a second calculation unit 62, wherein the first calculation unit 61 is configured to preset bit error rates, The information rate and activation factor are used to obtain the equivalent bandwidth of each service; the second calculation unit 62 is used to obtain the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system.

The device of this embodiment can be used to execute the technical solution of the method embodiment shown in FIG. 1 . For its implementation principle and execution method, refer to the method embodiment shown in FIG. 1 , which will not be repeated here. In this embodiment, when there are one or more services with different preset bit error rates, information rates and activation factors in the WCDMA system, the first calculation unit calculates the total bandwidth of the WCDMA system and each service preset in the WCDMA system Set the bit error rate, information rate and activation factor to obtain the equivalent bandwidth of each service; then, the second calculation unit obtains the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system. It realizes the estimation of the remaining capacity of the system when multiple different services exist simultaneously in the WCDMA system, and solves the problem in the prior art that it is impossible to estimate the remaining capacity of the system when multiple different services exist simultaneously in the WCDMA system.

FIG. 7 is a schematic structural diagram of Embodiment 2 of a device for estimating the remaining capacity of a WCDMA system according to the present invention. The apparatus of this embodiment is based on the apparatus embodiment shown in FIG. 6 , further, the first calculation unit 61 may include: a first calculation subunit 611 and a second calculation subunit 612, wherein the first calculation subunit 611 , used to obtain the processing gain of each service according to the total bandwidth of the WCDMA system and the preset information rate of each service; the second calculation subunit 612 is used to obtain the processing gain of each service according to the total bandwidth of the WCDMA system and the processing gain of each service, Bit error rate and activation factor to obtain the equivalent bandwidth of each service.

计算每个业务的处理增益，其中，G_m为业务的处理增益，W为WCDMA系统的总带宽，R_b为业务预设的信息速率；第二计算子单元612具体用于根据

计算每个业务的等效带宽，其中，

为业务的等效带宽，γ_m为业务的激活因子，

为业务的误码率，G_m为业务的处理增益，Q为运算函数， $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-y^2/2)\mathrm{dy}.$ Furthermore, the first computing subunit 611 is specifically configured to

Calculate the processing gain of each service, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service; the second calculation subunit 612 is specifically used to

Calculate the equivalent bandwidth of each service, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

is the bit error rate of the business, G _m is the processing gain of the business, Q is the operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; <figure-callout\; id="2"\; label="y"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">y</figure-callout>}}^2/2)\mathrm{dy}.$

The device of this embodiment can be used to implement the technical solution of the method embodiment shown in FIG. 2 . For its implementation principle and execution method, refer to the method embodiment shown in FIG. 2 , and details are not repeated here. In this embodiment, the first calculation subunit obtains the processing gain of each service according to the total bandwidth of the WCDMA system and the preset information rate of each service; the second calculation subunit obtains the processing gain of each service according to the total bandwidth of the WCDMA system and the information rate of each service Process the gain, bit error rate and activation factor to obtain the equivalent bandwidth of each service. Through the formula of equivalent bandwidth, the WCDMA method is equivalent to the FDMA method, so that when there are many different services in the WCDMA system, the system remaining Capacity estimation, so that it is convenient to compare the remaining capacity of the target cell with the remaining capacity of the current serving cell during network switching, so as to improve the reliability of switching. And because the remaining capacity is uniformly represented by the equivalent bandwidth, it is convenient to balance loads through resource management among different systems, which is conducive to the reasonable allocation of resources, as well as the comparison and scheduling of system resources between systems.

FIG. 8 is a schematic structural diagram of Embodiment 1 of a device for estimating the remaining capacity of a WCDMA system according to the present invention. As shown in Figure 8, the device includes a memory 81 and a processor 82, wherein the memory 81 is used to store the preset bit error rate, information rate and activation factor of each service in the WCDMA system; The total bandwidth of each service and the preset bit error rate, information rate and activation factor of each service in the WCDMA system can be used to obtain the equivalent bandwidth of each service. According to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system, the WCDMA system can be obtained remaining capacity.

The device in this embodiment can be used to execute the technical solution of the method embodiment shown in FIG. 1 . For its implementation principle and execution method, refer to the method embodiment shown in FIG. 1 , which will not be repeated here. In this embodiment, when there are one or more services with different preset bit error rates, information rates and activation factors in the WCDMA system, the preset bit error rates and information rates of each service in the WCDMA system are stored in the memory. and activation factor; the processor obtains the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system; then, according to the equivalent bandwidth of at least one service Bandwidth and the total bandwidth of the WCDMA system to obtain the remaining capacity of the WCDMA system. The method realizes the estimation of the remaining capacity of the system when multiple different services exist in the WCDMA system, and solves the problem in the prior art that it is impossible to estimate the remaining capacity of the system when multiple different services exist in the WCDMA system at the same time.

In the above embodiment, the processor 82 is specifically configured to obtain the processing gain of each service according to the total bandwidth of the WCDMA system and the preset information rate of each service, and obtain the processing gain of each service according to the total bandwidth of the WCDMA system and the processing gain of each service, Bit error rate and activation factor to obtain the equivalent bandwidth of each service.

计算每个业务的处理增益，其中，G_m为业务的处理增益，W为WCDMA系统的总带宽，R_b为业务预设的信息速率，并根据

计算每个业务的等效带宽，其中，

为业务的等效带宽，γ_m为业务的激活因子，

为业务的误码率，G_m为业务的处理增益，Q为运算函数， $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-y^2/2)\mathrm{dy}.$ Further, the processor 82 is specifically used to

Calculate the processing gain of each business, where G _m is the processing gain of the business, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the business, and according to

Calculate the equivalent bandwidth of each service, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

is the bit error rate of the business, G _m is the processing gain of the business, Q is the operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; <figure-callout\; id="2"\; label="y"\; filenames="HDA00002653806900021.png"\; state="\{\{state\}\}">y</figure-callout>}}^2/2)\mathrm{dy}.$

The device in this embodiment can be used to implement the technical solution of the method embodiment shown in FIG. 2 . For its implementation principle and execution method, refer to the method embodiment shown in FIG. 2 , and details are not repeated here. In this embodiment, the processor obtains the processing gain of each service according to the total bandwidth of the WCDMA system and the preset information rate of each service; then, according to the total bandwidth of the WCDMA system and the processing gain, bit error rate and Activation factor, to obtain the equivalent bandwidth of each service, through the equivalent bandwidth formula, the WCDMA method is equivalent to the FDMA method, which is convenient for estimating the remaining capacity of the system when there are many different services in the WCDMA system, so as to facilitate the During network switching, compare the remaining capacity of the target cell with the remaining capacity of the current serving cell to improve the reliability of switching. And because the remaining capacity is uniformly represented by the equivalent bandwidth, it is convenient to balance loads through resource management among different systems, which is conducive to the reasonable allocation of resources, as well as the comparison and scheduling of system resources between systems.

Those of ordinary skill in the art can understand that all or part of the steps for implementing the above method embodiments can be completed by program instructions and related hardware. The aforementioned program can be stored in a computer-readable storage medium. When the program is executed, it executes the steps including the above-mentioned method embodiments; and the aforementioned storage medium includes: ROM, RAM, magnetic disk or optical disk and other various media that can store program codes.

Finally, it should be noted that: the above embodiments are only used to illustrate the technical solutions of the present invention, rather than limiting them; although the present invention has been described in detail with reference to the foregoing embodiments, those of ordinary skill in the art should understand that: It is still possible to modify the technical solutions described in the foregoing embodiments, or perform equivalent replacements for some or all of the technical features; and these modifications or replacements do not make the essence of the corresponding technical solutions deviate from the technical solutions of the various embodiments of the present invention. scope.

Claims (9)

1. an estimation method of wideband code division multiple access WCDMA system remaining capacity, is characterized in that, comprises: Acquiring the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system; Acquiring the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system. 2. The method according to claim 1, wherein, according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system, obtaining each of the The equivalent bandwidth of the business includes: Acquiring the processing gain of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services; Obtaining the equivalent bandwidth of each of the services according to the total bandwidth of the WCDMA system and the processing gain, the bit error rate and the activation factor of each of the services. 3. The method of claim 2, wherein, The obtaining the processing gain of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services includes: according to

Calculating the processing gain of each of the services, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service; According to the total bandwidth of the WCDMA system and the processing gain of each of the services, the bit error rate and the activation factor, obtaining the equivalent bandwidth of each of the services includes: according to

Calculate the equivalent bandwidth of each of said services, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

Be the bit error rate of described business, G _m is the processing gain of described business, Q is operation function, 4. an estimation device of wideband code division multiple access WCDMA system remaining capacity, it is characterized in that, comprises: The first calculation unit is configured to obtain the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system; The second calculation unit is configured to obtain the remaining capacity of the WCDMA system according to the equivalent bandwidth of at least one service and the total bandwidth of the WCDMA system. 5. The device according to claim 4, wherein the first computing unit comprises: The first calculation subunit is used to obtain the processing gain of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services; The second calculation subunit is configured to obtain the equivalent bandwidth of each of the services according to the total bandwidth of the WCDMA system, the processing gain, the bit error rate and the activation factor of each of the services. 6. The device of claim 5, wherein: The first calculation subunit is specifically used for

Calculating the processing gain of each of the services, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service; The second calculating subunit is specifically used for

Calculate the equivalent bandwidth of each of said services, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service,

Be the bit error rate of described business, G _m is the processing gain of described business, Q is operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; y}}^2/2)\mathrm{dy}.$ 7. An estimation device for wideband code division multiple access WCDMA system remaining capacity, is characterized in that, comprises: A memory for storing preset bit error rates, information rates and activation factors for each service in the WCDMA system; A processor, configured to obtain the equivalent bandwidth of each service according to the total bandwidth of the WCDMA system and the preset bit error rate, information rate and activation factor of each service in the WCDMA system, and according to at least one The equivalent bandwidth of the service and the total bandwidth of the WCDMA system are obtained to obtain the remaining capacity of the WCDMA system. 8. The device according to claim 7, wherein the processor is specifically configured to acquire the processing information of each of the services according to the total bandwidth of the WCDMA system and the preset information rate of each of the services The gain is to obtain the equivalent bandwidth of each of the services according to the total bandwidth of the WCDMA system and the processing gain, the bit error rate and the activation factor of each of the services. 9. Apparatus according to claim 7 or 8, characterized in that The processor is specifically configured to

Calculate the processing gain of each of the services, wherein G _m is the processing gain of the service, W is the total bandwidth of the WCDMA system, and R _b is the preset information rate of the service, and according to

Calculate the equivalent bandwidth of each of said services, where,

is the equivalent bandwidth of the service, γ _m is the activation factor of the service, Be the bit error rate of described business, G _m is the processing gain of described business, Q is operation function, $Q\left(x\right)=\frac{1}{\sqrt{2\mathrm{\&pi;}}}\underset{x}{\overset{\&infin;}{\&Integral;}}\exp (-{\mathrm{the\; y}}^2/2)\mathrm{dy}.$

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