CN103066589A - Equivalent modeling method of power system double output phase regulator - Google Patents

Abstract

The invention relates to an equivalent modeling method of a power system double-output phase regulator. The main technical characteristic of the equivalent modeling method of the power system double-output phase regulator is that the method includes the following steps: (1), establishing a double output phase adjuster mathematical model, (2), establishing a positive sequence equivalent simulation circuit model to confirm self-impedance of a positive sequence equivalent current branch of a double-output type voltage regulator and mutual impedance between two current branches, (3), establishing a negative sequence equivalent simulation circuit model to confirm self-impedance of a negative sequence equivalent current branch and mutual impedance between two current branches, (4), establishing a zero sequence equivalent simulation circuit model. According to a topological structure of the double-output phase regulator and a constrained relationship among input voltage and output voltage and current, the positive sequence equivalent simulation circuit model, the negative sequence equivalent simulation circuit model, and the zero sequence equivalent simulation circuit model are established, and strict mathematical analytic solution of the self-impedance and the mutual impedance of two current branches is established, analysis calculation precision of a double-output type phase shifter is significantly improved.

Description

The equivalent modeling method of electric power system dual output phase regulator

Technical field

The invention belongs to the phase regulator technical field, especially a kind of equivalent modeling method of electric power system dual output phase regulator.

Background technology

Power system safety and stability operation and flexibly regulation and control all have great importance with stable to socio-economic development.Electric power system is complicated dynamical system, the trend of electrical network distributes and retrained by generator injecting power level and position, grid structure, load electricity consumption situation, along with generator access in the electrical network and load electricity capacity increase, marked change will occur in the electric network swim distribution character, the reasonability that trend distributes is affected by this also can, and presents gradually the transmission of electricity bottleneck.Passway for transmitting electricity trend skewness weighing apparatus is with the ability to transmit electricity of restriction local link and the efficient utilization of transmission facility.For this reason, improve the electric network swim distribution and strengthen damp series compensation, controllable series compensation TCSC and Static Series Synchronous Compensator SSSC and phase regulator (Phase-Shifting Transformer, the PST) application demand of controlled ability of transferring of electrical network increasing with less economic cost.

Phase regulator is as important electric power system adjusting device equipment, its basic principle is to inject a component of voltage with the input voltage quadrature in electrical network, the output voltage phase angle is offset, by changing the phase angle between two systems, transmitting active power between can control system is realized the purpose of meritorious tide optimization and lower loss.

Lose-lose removing from mould phase regulator is to be developed by single output phase shifter, by regulating the connection type of main circuit, realizes two phase-shifting voltages of output.The accuracy of lose-lose removing from mould phase regulator computation model will be directly connected to the electric power system correlative study that contains PST.At present, the processing scheme of lose-lose removing from mould phase regulator Static Equivalent circuit is to be two branch roads that are comprised of no-load voltage ratio link, phase shift link and equivalent impedance 3 parts with its equivalence.Yet, owing to have mutual impedance between two equivalent branch roads of lose-lose removing from mould phase regulator, ignore this impedance in the conventional treatment, this will cause between design object and actual motion characteristic and there are differences.

Summary of the invention

The object of the invention is to overcome the deficiencies in the prior art, a kind of equivalent modeling method of electric power system dual output phase regulator is provided, it takes into account the model of mutual impedance between equivalent branch road by foundation, overcome and ignore the computational analysis error that mutual impedance brings between two equivalent branch roads of lose-lose removing from mould phase shifter, improve lose-lose removing from mould phase shifter analytical calculation precision.

The present invention solves its technical problem and takes following technical scheme to realize:

A kind of equivalent modeling method of electric power system dual output phase regulator may further comprise the steps:

Step 1, according to lose-lose removing from mould phase regulator topological structure, quantitative based on kirchhoff voltage, electric current, set up the lose-lose removing from mould phase regulator Mathematical Modeling between adjuster input, output voltage and electric current;

Step 2, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up the positive sequence equivalent simulation circuit model, this positive sequence simulation circuit model is connected and composed by ideal transformer, positive sequence voltage source and series impedance, then according to the input and output external characteristic doctrine of equivalents of phase regulator topological structure and positive sequence equivalent simulation circuit model, determine by the mutual impedance between the self-impedance of lose-lose removing from mould voltage regulator positive sequence equivalent current branch and two current branch;

Step 3, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up negative phase-sequence equivalent simulation circuit model, this positive sequence simulation circuit model is connected and composed by ideal transformer, negative sequence voltage source and series impedance, then according to the input and output external characteristic doctrine of equivalents of phase regulator topological structure and negative phase-sequence equivalent simulation circuit model, determine by the mutual impedance between the self-impedance of lose-lose removing from mould voltage regulator negative phase-sequence equivalent current branch road and two current branch;

Step 4, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up zero sequence equivalent simulation circuit model, the mutual impedance between two current branch self-impedances of this zero sequence simulation circuit model and two current branch.

And described lose-lose removing from mould phase regulator Mathematical Modeling is:

$\left\{\begin{array}{c}{\stackrel{\·}{I}}_{\mathrm{Aex}}=j\sqrt{3}{n}_{\mathrm{ex}}{i}_{\mathrm{Ase}}\\ {\stackrel{\·}{I}}_{\mathrm{As}}={\stackrel{\·}{I}}_{\mathrm{ase}1}(1-j\sqrt{3}{n}_{\mathrm{ex}}{n}_{\mathrm{se}1})+{\stackrel{\·}{I}}_{\mathrm{ase}2}(1+j\sqrt{3}{n}_{\mathrm{ex}}{n}_{\mathrm{se}2})\end{array}\right.$

In the following formula:

: the A phase winding electric current of the former limit of shunt transformer winding;

: the A phase winding electric current of the former limit of series transformer winding;

: the input current of phase regulator A phase;

: the A phase winding electric current of series transformer secondary the first winding;

: the A phase winding electric current of series transformer secondary the second winding;

n _Ex: the no-load voltage ratio of shunt transformer;

n _Se1: the no-load voltage ratio of first pair of winding of series transformer;

n _Se2: the no-load voltage ratio of second pair of winding of series transformer.

And the self-impedance of described positive sequence simulation circuit model and mutual impedance are:

$\left\{\begin{array}{c}{\mathrm{<figure-callout\; id="1"\; label="Z\; eq"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{eq}}={\mathrm{<figure-callout\; id="1"\; label="Z\; ase"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}\\ {\mathrm{<figure-callout\; id="2"\; label="Z\; eq"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{eq}}={\mathrm{<figure-callout\; id="2"\; label="Z\; ase"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}2}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}\\ Z_M=-3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Aex}}-n_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Ase}}\end{array}\right.$

In the following formula:

Z _Eq1: the positive sequence equivalent impedance of dual output phase regulator branch road 1;

Z _Eq2: the positive sequence equivalent impedance of dual output phase regulator branch road 2;

Z _M: the positive sequence mutual impedance between the dual output phase regulator branch road 1 and 2;

Z _Ase1: the impedance of series transformer secondary the first winding;

Z _Ase1: the impedance of series transformer secondary the second winding;

Z _Ase: the impedance of the former limit of series transformer winding;

Z _Aex: the impedance of shunt transformer winding.

And the self-impedance of described negative phase-sequence simulation circuit model and mutual impedance are:

$Z_{\mathrm{eq}1\left(2\right)}={\mathrm{<figure-callout\; id="1"\; label="Z\; ase"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}$

$Z_{\mathrm{eq}2\left(2\right)}={\mathrm{<figure-callout\; id="2"\; label="Z\; ase"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}2}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}$

$Z_{M\left(2\right)}=-3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Aex}}-n_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Ase}}$

In the following formula:

Z _{Eq1 (2)}: the negative phase-sequence equivalent impedance of dual output phase regulator branch road 1;

Z _{Eq2 (2)}: the negative phase-sequence equivalent impedance of dual output phase regulator branch road 2;

Z _{M (2)}: the negative phase-sequence mutual impedance between the dual output phase regulator branch road 1 and 2.

And the self-impedance of described zero sequence simulation circuit model and mutual impedance are:

$Z_{\mathrm{eq}1\left(0\right)}={\mathrm{<figure-callout\; id="1"\; label="Z\; ase"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}$

$Z_{\mathrm{eq}2\left(0\right)}={\mathrm{<figure-callout\; id="2"\; label="Z\; ase"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}$

Z _M(0)＝-n _se1n _se2Z _Ase

In the following formula:

Z _{Eq1 (0)}: the zero sequence equivalent impedance of dual output phase regulator branch road 1;

Z _{Eq2 (0)}: the zero sequence equivalent impedance of dual output phase regulator branch road 2;

Z _{M (0)}: the zero sequence mutual impedance between the dual output phase regulator branch road 1 and 2.

Advantage of the present invention and good effect are:

The present invention is by the topological structure of lose-lose removing from mould phase regulator and the restriction relation between input, output voltage and electric current, self-impedance and the strict mathematical analysis of mutual impedance set up in positive sequence equivalent circuit model, negative phase-sequence equivalent electric circuit module and zero sequence equivalent model and two current branch are found the solution formula, significantly improve lose-lose removing from mould phase shifter analytical calculation precision.

Description of drawings

Fig. 1 is the physical topological structure of lose-lose removing from mould phase regulator;

Fig. 2 is lose-lose removing from mould phase regulator positive sequence equivalent circuit diagram;

Fig. 3 is lose-lose removing from mould phase regulator negative phase-sequence schematic equivalent circuit;

Fig. 4 is lose-lose removing from mould phase regulator zero sequence schematic equivalent circuit;

Fig. 5 is the test macro of checking lose-lose removing from mould phase regulator positive sequence equivalent current simulations precision.

Embodiment

Below in conjunction with accompanying drawing the present invention is further described.

A kind of equivalent modeling method of electric power system dual output phase regulator as shown in Figure 1, may further comprise the steps:

Step 1, according to as shown in Figure 1 lose-lose removing from mould phase regulator topological structure, quantitative based on kirchhoff voltage, electric current, set up the lose-lose removing from mould phase regulator Mathematical Modeling between adjuster input, output voltage and electric current, as shown in Equation (1).

$\left\{\begin{array}{c}{\stackrel{\&CenterDot;}{I}}_{\mathrm{Aex}}=j\sqrt{3}{n}_{\mathrm{ex}}{i}_{\mathrm{Ase}}\\ {\stackrel{\&CenterDot;}{I}}_{\mathrm{As}}={\stackrel{\&CenterDot;}{I}}_{\mathrm{ase}1}(1-j\sqrt{3}{n}_{\mathrm{ex}}{n}_{\mathrm{se}1})+{\stackrel{\&CenterDot;}{I}}_{\mathrm{ase}2}(1+j\sqrt{3}{n}_{\mathrm{ex}}{n}_{\mathrm{se}2})\end{array}\right.---\left(1\right)$

In the following formula:

: the A phase winding electric current of the former limit of shunt transformer winding;

: the A phase winding electric current of the former limit of series transformer winding;

: the input current of phase regulator A phase;

: the A phase winding electric current of series transformer secondary the first winding;

: the A phase winding electric current of series transformer secondary the second winding;

n _Ex: the no-load voltage ratio of shunt transformer;

n _Se1: the no-load voltage ratio of first pair of winding of series transformer;

n _Se2: the no-load voltage ratio of second pair of winding of series transformer.

Step 2, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up positive sequence equivalent simulation circuit model as shown in Figure 2, this positive sequence simulation circuit model comprises two current branch, and every current branch is connected and composed by ideal transformer, series electrical potential source and self-impedance; Then according to the input and output external characteristic doctrine of equivalents of phase regulator topological structure and positive sequence equivalent simulation circuit model, determine the positive sequence equivalent current branch described by lose-lose removing from mould voltage regulator electric parameter, the self-impedance Z in two current branch _Eq1, Z _Eq2And the mutual impedance Z between two circuit _MAs shown in Equation (2).

$\left\{\begin{array}{c}{\mathrm{<figure-callout\; id="1"\; label="Z\; eq"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{eq}}={\mathrm{<figure-callout\; id="1"\; label="Z\; ase"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{<figure-callout\; id="2"\; label="Ase\; Z\; eq"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Ase</figure-callout>}}& \\ Z_{\mathrm{eq}}{2}_{}={\mathrm{<figure-callout\; id="2"\; label="Z\; ase"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}2}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}\\ Z_M=-3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Aex}}-n_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Ase}}\end{array}\right.---\left(2\right)$

Step 4, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up negative phase-sequence equivalent simulation circuit model as shown in Figure 3, this negative phase-sequence simulation circuit model comprises two current branch, and every current branch is connected and composed by ideal transformer, series electrical potential source and self-impedance; Then according to the input and output external characteristic doctrine of equivalents of phase regulator topological structure and negative phase-sequence equivalent simulation circuit model, determine the positive sequence equivalent current branch described by lose-lose removing from mould voltage regulator electric parameter, the mutual impedance result between the self-impedance in two current branch and two circuit as shown in Equation (3):

$Z_{\mathrm{eq}1\left(2\right)}={\mathrm{<figure-callout\; id="1"\; label="Z\; ase"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}$

$Z_{\mathrm{eq}2\left(2\right)}=Z_{\mathrm{ase}2\left(2\right)}+3n_{\mathrm{ex}}^2{n}_{\mathrm{se}2}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}---\left(3\right)$

$Z_{M\left(2\right)}=-3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Aex}}-n_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Ase}}$

Step 5, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up zero sequence equivalent simulation circuit model as shown in Figure 5, this zero sequence simulation circuit model comprises the mutual impedance between every current branch self-impedance and two current branch, the mutual impedance result between the self-impedance in two current branch and two circuit as shown in Equation (4):

$Z_{\mathrm{eq}1\left(0\right)}={\mathrm{<figure-callout\; id="1"\; label="Z\; ase"\; filenames="HDA00002561063300011.png,HDA00002561063300012.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}$

$Z_{\mathrm{eq}2\left(0\right)}={\mathrm{<figure-callout\; id="2"\; label="Z\; ase"\; filenames="HDA00002561063300012.png,HDA00002561063300021.png"\; state="\{\{state\}\}">Z</figure-callout>}}_{\mathrm{ase}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}---\left(4\right)$

Z _M(0)＝-n _se1n _se2Z _Ase

Can find out do not have the no-load voltage ratio link in the zero sequence equivalent circuit of dual output phase regulator, this is another important discovery that the present invention obtains.

Realized the equivalent modeling method of electric power system dual output phase regulator by above-mentioned steps.

The below is take the positive sequence equivalent simulation circuit model as example, checking lose-lose removing from mould phase regulator equivalent current simulation accuracy, as shown in Figure 5, set up the test macro of checking lose-lose removing from mould phase regulator positive sequence equivalent current simulations precision, this system is connected capacitor and reactor and is placed between the two infinitely great power supplys by the dual output phase regulator and consists of.Capacitor and reactor are got two groups of data, first group: X _L=125.66371 Ω, X _C=-81.68141 Ω; Second group: X _L=81.68141 Ω, X _C=-81.68141 Ω.Adopt main circuit electric parameter as shown in table 1, the calculating accuracy of checking equivalent simulation model.Result of calculation is as shown in table 2, result verification take into account in the equivalent model necessity that mutual impedance between two branch roads promotes simulation accuracy.

Table 1 phase shifter apparatus parameter

Table 2 result of calculation

Use said method can verify equally the going property of standard of negative phase-sequence equivalent simulation circuit model and zero sequence equivalent simulation circuit model.Difference only is that the power supply in negative phase-sequence equivalent circuit and the zero sequence equivalent circuit adopts negative phase-sequence power supply and zero sequence power supply to get final product accordingly.

It is emphasized that; embodiment of the present invention is illustrative; rather than determinate; therefore the present invention includes and be not limited to the embodiment described in the embodiment; every other execution modes that drawn by those skilled in the art's technical scheme according to the present invention belong to the scope of protection of the invention equally.

Claims (5)

1. the equivalent modeling method of an electric power system dual output phase regulator is characterized in that: may further comprise the steps:

Step 1, according to lose-lose removing from mould phase regulator topological structure, quantitative based on kirchhoff voltage, electric current, set up the lose-lose removing from mould phase regulator Mathematical Modeling between adjuster input, output voltage and electric current;

Step 2, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up the positive sequence equivalent simulation circuit model, this positive sequence simulation circuit model is connected and composed by ideal transformer, positive sequence voltage source and series impedance, then according to the input and output external characteristic doctrine of equivalents of phase regulator topological structure and positive sequence equivalent simulation circuit model, determine by the mutual impedance between the self-impedance of lose-lose removing from mould voltage regulator positive sequence equivalent current branch and two current branch;

Step 3, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up negative phase-sequence equivalent simulation circuit model, this positive sequence simulation circuit model is connected and composed by ideal transformer, negative sequence voltage source and series impedance, then according to the input and output external characteristic doctrine of equivalents of phase regulator topological structure and negative phase-sequence equivalent simulation circuit model, determine by the mutual impedance between the self-impedance of lose-lose removing from mould voltage regulator negative phase-sequence equivalent current branch road and two current branch;

Step 4, according to lose-lose removing from mould phase regulator Mathematical Modeling, set up zero sequence equivalent simulation circuit model, the mutual impedance between two current branch self-impedances of this zero sequence simulation circuit model and two current branch.

2. the equivalent modeling method of electric power system dual output phase regulator according to claim 1, it is characterized in that: described lose-lose removing from mould phase regulator Mathematical Modeling is:

$\left\{\begin{array}{c}{\stackrel{\&CenterDot;}{I}}_{\mathrm{Aex}}=j\sqrt{3}{n}_{\mathrm{ex}}{\stackrel{\&CenterDot;}{I}}_{\mathrm{Ase}}\\ {\stackrel{\&CenterDot;}{I}}_{\mathrm{As}}={\stackrel{\&CenterDot;}{I}}_{\mathrm{ase}1}(1-j\sqrt{3}{n}_{\mathrm{ex}}{n}_{\mathrm{se}1})+{\stackrel{\&CenterDot;}{I}}_{\mathrm{ase}2}(1+j\sqrt{3}{n}_{\mathrm{ex}}{n}_{\mathrm{se}2})\end{array}\right.$

In the following formula:

The A phase winding electric current of the former limit of shunt transformer winding;

The A phase winding electric current of the former limit of series transformer winding;

The input current of phase regulator A phase;

The A phase winding electric current of series transformer secondary the first winding;

The A phase winding electric current of series transformer secondary the second winding;

n _Ex: the no-load voltage ratio of shunt transformer;

n _Se1: the no-load voltage ratio of first pair of winding of series transformer;

n _Se2: the no-load voltage ratio of second pair of winding of series transformer.

3. the equivalent modeling method of electric power system dual output phase regulator according to claim 1, it is characterized in that: the self-impedance of described positive sequence simulation circuit model and mutual impedance are:

$\left\{\begin{array}{c}{Z}_{\mathrm{eq}1}=Z_{\mathrm{ase}1}+{3n}_{\mathrm{ex}}^2{n}_{\mathrm{se}1}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}\\ Z_{\mathrm{eq}2}=Z_{\mathrm{ase}2}+{3n}_{\mathrm{ex}}^2{n}_{\mathrm{se}2}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}\\ Z_M=-{3n}_{\mathrm{ex}}^2{n}_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Aex}}-n_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Ase}}\end{array}\right.$

In the following formula:

Z _Eq1: the positive sequence equivalent impedance of dual output phase regulator branch road 1;

Z _Eq2: the positive sequence equivalent impedance of dual output phase regulator branch road 2;

Z _M: the positive sequence mutual impedance between the dual output phase regulator branch road 1 and 2;

Z _Ase1: the impedance of series transformer secondary the first winding;

Z _Ase1: the impedance of series transformer secondary the second winding;

Z _Ase: the impedance of the former limit of series transformer winding;

Z _Aex: the impedance of shunt transformer winding.

4. the equivalent modeling method of electric power system dual output phase regulator according to claim 1, it is characterized in that: the self-impedance of described negative phase-sequence simulation circuit model and mutual impedance are:

$Z_{\mathrm{eq}1\left(2\right)}=Z_{\mathrm{ase}1}+{3n}_{\mathrm{ex}}^2{n}_{\mathrm{se}1}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}$

$Z_{\mathrm{eq}2\left(2\right)}=Z_{\mathrm{ase}2}+{3n}_{\mathrm{ex}}^2{n}_{\mathrm{se}2}^2{Z}_{\mathrm{Aex}}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}$

$Z_{M\left(2\right)}=-3n_{\mathrm{ex}}^2{n}_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Aex}}-n_{\mathrm{se}1}{n}_{\mathrm{se}2}{Z}_{\mathrm{Ase}}$

In the following formula:

Z _{Eq1 (2)}: the negative phase-sequence equivalent impedance of dual output phase regulator branch road 1;

Z _{Eq2 (2)}: the negative phase-sequence equivalent impedance of dual output phase regulator branch road 2;

Z _{M (2)}: the negative phase-sequence mutual impedance between the dual output phase regulator branch road 1 and 2.

5. the equivalent modeling method of electric power system dual output phase regulator according to claim 1, it is characterized in that: the self-impedance of described zero sequence simulation circuit model and mutual impedance are:

$Z_{\mathrm{eq}1\left(0\right)}=Z_{\mathrm{ase}1}+n_{\mathrm{se}1}^2{Z}_{\mathrm{Ase}}$

$Z_{\mathrm{eq}2\left(0\right)}=Z_{\mathrm{ase}2}+n_{\mathrm{se}2}^2{Z}_{\mathrm{Ase}}$

Z _M(0)＝-n _se1n _se2Z _Ase

In the following formula:

Z _{Eq1 (0)}: the zero sequence equivalent impedance of dual output phase regulator branch road 1;

Z _{Eq2 (0)}: the zero sequence equivalent impedance of dual output phase regulator branch road 2;

Z _{M (0)}: the zero sequence mutual impedance between the dual output phase regulator branch road 1 and 2.

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