CN102914726A - Fault positioning method for common-tower double-circuit line - Google Patents

Fault positioning method for common-tower double-circuit line Download PDF

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CN102914726A
CN102914726A CN2012104407215A CN201210440721A CN102914726A CN 102914726 A CN102914726 A CN 102914726A CN 2012104407215 A CN2012104407215 A CN 2012104407215A CN 201210440721 A CN201210440721 A CN 201210440721A CN 102914726 A CN102914726 A CN 102914726A
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王艳
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North China Electric Power University
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Abstract

A fault positioning method for a common-tower double-circuit line comprises the following steps: firstly, carrying out six-sequence decomposition for electrical quantity at two ends of the double-circuit line; next, calculating the fault distance by a long line equation of a transmission line of a same positive-sequence fault component of the six-sequence components, and obtaining six-sequence current of a fault point according to the electrical quantity at two ends of the double-circuit line, the fault distance and the long line equation; then converting the six-sequence current into six-phase current; and finally, judging a fault phase according to the amplitude value characteristic of the phase current of the fault point. According to the method provided by the invention, when fault phase-selection of the double-circuit line is carried out, the fault distance detection can be performed at the same time, and the advantages of clear principle, high distance detection accuracy, simple and reliable phase-selection logic and the like are provided. The method provided by the invention is free of the influence of fault point transitional resistance, circuit distributed capacitor current and load current, can automatically adapt to and regulate a definite value of the phase-selection criterion with the change of a system operation manner, and can provide effective phase-selection logic for distance protection of the common-tower double-circuit line.

Description

A kind of Fault Locating Method for the double-circuit line on same pole road
Technical field
The present invention relates to a kind of range finding and phase-selecting method of transmission line malfunction, belong to the power transmission and distribution technical field.
Background technology
Along with the development of modern electric technology and the continuous increase of net capacity, power transmission line corridor is more and more nervous, and particularly this problem is particularly outstanding in big and medium-sized cities.Double-circuit lines on the same pole is because two loop line roads share a shaft tower, has a required transmission line corridor narrow, takies the characteristics such as the good farmland is few, construction speed fast, remarkable in economical benefits, widely applies in actual motion and planning construction.
The double-circuit line method of operation is complicated, have mutual inductance and cross line fault between line, brings mutually certain difficulty for the fault localization of six line transmission systems and choosing.And be to guarantee uninterrupted power supply and few power failure the as far as possible, require double-circuit line when breaking down, only to excise fault phase and keep healthy phases and continue operation, therefore double-circuit line has proposed the strict demand of selecting properly fault phase and fault wire to relay protection.
Phase-selecting method commonly used mainly contains two classes, i.e. Sudden Changing Rate choosing reaches mutually stable state fault amount and selects phase.Phase differential current Sudden Changing Rate class selects the phase method to be widely used in the modern protection; it comes the failure judgement type by the sudden change value that compares three phase differential current faults front and back; these class methods are not subjected to the impact of load current; sensitivity is swift in motion; the general phase of selecting that is used for the fault initial stage, shortcoming are that sensitivity is not enough when detecting terminal long transmission line singlephase earth fault with transition resistance.In addition, need to consider the variation of double-circuit line on same pole healthy phases electric current when this class phase-selecting method is used for double-circuit line on same pole, therefore be still waiting further research.Stable state fault amount class phase-selecting method comprises that mainly impedance selects the phase method, and voltage selects the phase method, and the order electric current selects Xiang Fa etc.Impedance selects the measurement result of phase method Main Basis impedance measurement element to confirm fault phase, energy selecting properly fault phase under most of simple faults, but it is subjected to the impact of system operation mode, trouble spot transition resistance larger, selects the phase result often undesirable.Voltage selects the phase method need to solve long transmission line at a distance fault and the sensitivity problem during at a distance with transition resistance earth fault, and it can't distinguish interior phase-to phase fault or cross line fault when being used for the double-circuit line on same pole system.The phase method of selecting the zero sequence negative-sequence current adopts the facies principle that selects of fault current sequence component relative phase relation; described method is less and be not subjected to that load current affects etc. advantage is used widely because having the impact that is subjected to fault resistance, and the consequent malfunction that is usually used in protecting is selected phase.Along with the new mathematical tool such as wavelet theory and the birth of signal analysis theory, many scholars are to selecting the phase new principle to carry out large quantity research, and these select the phase new principle a bit to be in theoretical research stage, and some is being tested, and also has with a certain distance from practicality.In a word, existing phase-selecting method respectively has advantage, but selects in the application of phase at double-circuit line on same pole, all has some problems.
Summary of the invention
The object of the invention is to the drawback for prior art, a kind of Fault Locating Method for the double-circuit line on same pole road is provided, effectively select phase logic for the distance protection of double-circuit line on same pole provides.
Problem of the present invention realizes with following technical proposals:
A kind of Fault Locating Method for the double-circuit line on same pole road, described method is at first carried out double-circuit line two ends electric parameters (voltage, the magnitude of current) six orders and is decomposed, then utilize that the transmission line long-line equation with positive sequence fault component calculates fault distance in the six order components, recycling double loop two ends electric parameters, fault distance and long-line equation are tried to achieve six order electric currents of trouble spot, six order electric currents are converted into six phase currents, last amplitude Characteristics failure judgement phase according to the trouble spot phase current.
Above-mentioned Fault Locating Method for the double-circuit line on same pole road, described method is processed according to the following steps:
A. utilize Metzler matrix that following formula provides that double loop both end voltage amount, the magnitude of current are carried out respectively six orders and decompose, two three-phase inversion of double loop are become six independent order components: same positive sequence
Figure 899816DEST_PATH_IMAGE001
, same negative phase-sequence
Figure 723415DEST_PATH_IMAGE002
, same zero sequence Anyway order , anti-negative phase-sequence
Figure 457519DEST_PATH_IMAGE005
, anti-zero sequence
Figure 33994DEST_PATH_IMAGE006
,
；
Wherein,
Figure 509155DEST_PATH_IMAGE008
B. adopt with positive sequence fault component transmission line long-line equation and carry out fault localization, the range finding equation is:
，
In the formula,
Figure 395388DEST_PATH_IMAGE010
With
Figure 328709DEST_PATH_IMAGE011
Be respectively the same positive sequence fault component voltage and current of double loop two ends (M end and N end); Same positive sequence wave impedance for circuit;
Figure 787689DEST_PATH_IMAGE013
For circuit with the positive sequence propagation constant;
Figure 807598DEST_PATH_IMAGE014
Be the same positive sequence impedance of circuit unit length;
Figure 810189DEST_PATH_IMAGE015
For the circuit unit length with the positive sequence admittance;
Figure 864733DEST_PATH_IMAGE016
Be double loop length,
Figure 560156DEST_PATH_IMAGE017
For holding distance to M in the trouble spot;
C. will
Figure 801782DEST_PATH_IMAGE018
The substitution following formula calculates respectively trouble spot six order electric currents:
Figure 873643DEST_PATH_IMAGE019
，
In the formula,
Figure 251535DEST_PATH_IMAGE020
With
Figure 395157DEST_PATH_IMAGE021
Be respectively i sequence voltage component and the i order current component of double loop two ends (M end and N end);
Figure 858500DEST_PATH_IMAGE022
I order wave impedance for circuit; Be circuit i order propagation constant;
Figure 232029DEST_PATH_IMAGE024
Be the impedance of circuit unit length i order;
Figure 269256DEST_PATH_IMAGE025
Be the admittance of circuit unit length i order;
D. utilize following formula trouble spot six order electric currents to be converted into six phase currents of double line down point:
Figure 485473DEST_PATH_IMAGE026
，
In the formula:
Figure 899137DEST_PATH_IMAGE027
,
Figure 251621DEST_PATH_IMAGE028
,
Figure 459748DEST_PATH_IMAGE029
Be six order electric currents of trouble spot,
Figure 897683DEST_PATH_IMAGE030
Six phase currents for the trouble spot;
E. utilize the size of each phase current of trouble spot to distinguish fault separate:
Set a relay protection action current threshold value
Figure 115038DEST_PATH_IMAGE031
If the phase current of trouble spot is worth greater than this, then this is judged to fault phase mutually, otherwise then is judged to healthy phases.
Above-mentioned Fault Locating Method for the double-circuit line on same pole road, the relay protection action current threshold value of differentiation fault phase
Figure 322028DEST_PATH_IMAGE031
Determined by following formula:
，
Figure 891867DEST_PATH_IMAGE033
，
Wherein
Figure 647333DEST_PATH_IMAGE034
Get the higher value of M, protection installation place, N both sides i phase current, k is safety factor, and k equals 0.5.
The present invention can carry out fault localization in the double-circuit line Fault Phase Selection; have that principle is clear, distance accuracy is high, select the advantages such as phase logic is simple and reliable; described method is not subjected to the trouble spot transition resistance; the impact of line distribution capacitance electric current and load current; and can select along with the variation self-adaptation adjustment of system operation mode the definite value of phase criterion, can provide for the distance protection of double-circuit line on same pole and effectively select phase logic.
Description of drawings
The invention will be further described below in conjunction with accompanying drawing.
Fig. 1 is the schematic diagram of a uniform transmission line;
Fig. 2 is the double-circuit line on same pole system that simulation calculation adopts;
Fig. 3 holds the 100km IBCIIC of place through 300 apart from M among Fig. 2
Figure 974409DEST_PATH_IMAGE035
Simulation result during earth fault;
Fig. 4 is Hebei province city part electric network wiring scheme;
Fig. 5 is transformer station 2 among Fig. 4,3, in when, apart from transformer station's 2 end 69.6kM places double-circuit lines the IAIIAG fault occuring, the fault waveform figure that the RCS-931BM protective device obtains;
Fig. 6 selects the phase result;
Fig. 7 selects the phase process flow diagram.
Each symbol inventory is in the literary composition:
Figure 789919DEST_PATH_IMAGE036
Be same positive-sequence component;
Figure 936866DEST_PATH_IMAGE037
Be same negative sequence component;
Figure 496023DEST_PATH_IMAGE038
Be same zero-sequence component;
Figure 677606DEST_PATH_IMAGE039
Be order component anyway;
Figure 664017DEST_PATH_IMAGE040
Be anti-negative sequence component;
Figure 94998DEST_PATH_IMAGE041
Be anti-zero-sequence component;
Figure 661108DEST_PATH_IMAGE010
With Be respectively the same positive sequence fault component voltage and current of double loop two ends (M end and N end);
Figure 854509DEST_PATH_IMAGE042
Same positive sequence wave impedance for circuit;
Figure 507208DEST_PATH_IMAGE043
For circuit with the positive sequence propagation constant;
Figure 877009DEST_PATH_IMAGE014
Be the same positive sequence impedance of circuit unit length;
Figure 564342DEST_PATH_IMAGE015
For the circuit unit length with the positive sequence admittance; Be double loop length;
Figure 501391DEST_PATH_IMAGE017
For holding distance to M in the trouble spot;
Figure 409305DEST_PATH_IMAGE020
With
Figure 951144DEST_PATH_IMAGE021
Be respectively i sequence voltage component and the i order current component of double loop two ends (being M end and N end);
Figure 919100DEST_PATH_IMAGE044
I order wave impedance for circuit;
Figure 546391DEST_PATH_IMAGE045
Be circuit i order propagation constant;
Figure 257995DEST_PATH_IMAGE024
Be the impedance of circuit unit length i order; Be the admittance of circuit unit length i order;
Figure 58778DEST_PATH_IMAGE029
Be trouble spot six order electric currents;
Figure 907785DEST_PATH_IMAGE030
Be trouble spot six phase currents; Be relay protection action current threshold value;
Figure 470670DEST_PATH_IMAGE034
Higher value for M, protection installation place, N both sides i phase current; K is safety factor.
Embodiment
Calculate and derive:
1. utilize six order component methods and transmission line long-line equation to ask for fault distance and current in the fault point
As shown in Figure 1, on the circuit apart from the M side
Figure 780429DEST_PATH_IMAGE018
The place, apart from the N side
Figure 116732DEST_PATH_IMAGE046
The voltage, electric current at place can be respectively be expressed as (1) formula and (2) formula with the voltage and current of M, N both sides with long-line equation.
Figure 170139DEST_PATH_IMAGE047
（1）
（2）
In the following formula,
Figure 21737DEST_PATH_IMAGE049
With ,
Figure 702435DEST_PATH_IMAGE051
With
Figure 193459DEST_PATH_IMAGE052
Be respectively the voltage and current of M side and N side protection installation place;
Figure 845020DEST_PATH_IMAGE053
,
Figure 155916DEST_PATH_IMAGE054
Be fault point voltage, electric current;
Figure 551125DEST_PATH_IMAGE055
,
Figure 896655DEST_PATH_IMAGE056
The electric current that comes from M side and N effluent respectively for the trouble spot;
Figure 719118DEST_PATH_IMAGE016
Be the transmission line of electricity total length;
Figure 517310DEST_PATH_IMAGE057
Be propagation constant,
Figure 716210DEST_PATH_IMAGE058
Be characteristic impedance, R, L, G and C are respectively resistance, inductance, the electricity of circuit unit length and lead and electric capacity.
The total current of trouble spot is:
Figure 916247DEST_PATH_IMAGE059
With in formula (1) and the formula (2)
Figure 909611DEST_PATH_IMAGE053
Simultaneous can get:
Figure 195099DEST_PATH_IMAGE060
Will With
Figure 252233DEST_PATH_IMAGE062
Bring following formula into:
Figure 416499DEST_PATH_IMAGE063
（3）
Formula (3) shows, utilizes transmission line two ends electric parameters to find the solution fault distance
Figure 189282DEST_PATH_IMAGE018
Precondition be: must know fault phase.Therefore, in the situation that the separate the unknown of fault find the solution Infeasible.And have mutual inductance between the analyses for double circuits on same tower, thereby also be unsuitable for directly using above-mentioned algorithm.
For this reason, utilizing six order component methods will have each other the double loop two ends electric parameters of coupled relation to carry out six orders decomposes.Described method becomes six independent order components by Metzler matrix with two three-phase inversion of double loop: same positive sequence
Figure 639035DEST_PATH_IMAGE036
, same negative phase-sequence
Figure 239781DEST_PATH_IMAGE037
, same zero sequence
Figure 234282DEST_PATH_IMAGE038
Anyway order
Figure 109834DEST_PATH_IMAGE039
, anti-negative phase-sequence
Figure 342232DEST_PATH_IMAGE040
, anti-zero sequence
Figure 645038DEST_PATH_IMAGE041
Each order in the six order components satisfies the long-line equation of transmission line equally.
Consider when various types of fault occurs double loop and all contain with the positive sequence amount
Figure 595676DEST_PATH_IMAGE036
Therefore, can utilize
Figure 9340DEST_PATH_IMAGE036
The long-line equation of component is tried to achieve
Figure 361824DEST_PATH_IMAGE018
Value.But, only there is same positive-sequence component in the double loop during owing to normal operation, therefore utilization is tried to achieve with positive sequence
Figure 835530DEST_PATH_IMAGE018
Value will be subjected to the impact of load current.For eliminating its impact, adopt the fault component with positive sequence to carry out fault localization.At this moment, the range finding equation is:
Figure 804623DEST_PATH_IMAGE009
（4）
In the formula, With
Figure 228969DEST_PATH_IMAGE011
Be respectively the same positive sequence fault component voltage and current of M end and N end;
Figure 873577DEST_PATH_IMAGE012
Same positive sequence wave impedance for circuit; For circuit with the positive sequence propagation constant;
Figure 554274DEST_PATH_IMAGE065
Be the same positive sequence impedance of circuit unit length;
Figure 412508DEST_PATH_IMAGE066
For the circuit unit length with the positive sequence admittance.
Try to achieve fault distance
Figure 431280DEST_PATH_IMAGE018
After, it is worth generation to formula (5), obtain respectively trouble spot six order electric currents:
（5）
In the formula,
Figure 402964DEST_PATH_IMAGE020
With
Figure 115705DEST_PATH_IMAGE021
Be respectively i sequence voltage component and the i order current component of double loop two ends (M end and N end);
Figure 102116DEST_PATH_IMAGE022
I order wave impedance for circuit;
Figure 267518DEST_PATH_IMAGE023
Be circuit i order propagation constant;
Figure 833628DEST_PATH_IMAGE024
Be the impedance of circuit unit length i order;
Figure 197613DEST_PATH_IMAGE025
Be the admittance of circuit unit length i order.
By formula (6) double line down is put six phase currents that six order electric currents are converted into the trouble spot again.
Figure 354925DEST_PATH_IMAGE068
（6）
In the formula:
Figure 476465DEST_PATH_IMAGE027
,
Figure 377425DEST_PATH_IMAGE028
, Be six order electric currents of trouble spot,
Figure 392971DEST_PATH_IMAGE030
Six phase currents for the trouble spot.
2. utilize the phase current feature of trouble spot to realize selecting phase
After trying to achieve each phase current of trouble spot, utilize the amplitude size of each phase current of trouble spot to distinguish fault separate.The current in the fault point of healthy phases is zero, and the current in the fault point of fault phase is larger, for the phasor of M, N both sides short-circuit current and.Set an action current threshold value
Figure 532966DEST_PATH_IMAGE031
If the phase current of trouble spot is worth greater than this, then this is judged to fault phase mutually, otherwise then is judged to healthy phases.Criterion is as follows:
Figure 972037DEST_PATH_IMAGE069
（7）
Simulation example:
Double-circuit line on same pole shown in Figure 2 system is carried out emulation.System voltage 500KV, M side system capacity 2000MVA, N side system capacity 1000MVA, the both sides power supply is arranged the angle and is
Figure 982719DEST_PATH_IMAGE070
The every cycle of system 24 points of sampling, simulation run break down during to 0.1s.
Suppose that double loop breaks down apart from the K point at M end 100Km place, the double loop two ends that then emulation obtained (M end, N end) voltage, the magnitude of current carry out respectively six orders and decompose, and obtain the same positive sequence fault component of both end voltage, electric current
Figure 481833DEST_PATH_IMAGE010
With
Figure 109124DEST_PATH_IMAGE011
Its value substitution following formula just can be obtained fault distance.
Figure 351886DEST_PATH_IMAGE009
Table 1 has provided the range finding result under M end 100km place, the different faults type cases.
Range finding result under the table 1 different faults type cases
Figure 217074DEST_PATH_IMAGE071
As shown in Table 1, the double-circuit line on same pole utilization has very high distance accuracy with the long-line equation telemetry of positive sequence fault component.
Suppose IBCIIC to occur through 300 apart from M end 100km place
Figure 418248DEST_PATH_IMAGE035
Transition resistance earth fault, as shown in Table 1, the result that finds range this moment is
Figure 1676DEST_PATH_IMAGE072
, in its value substitution formula (5) corresponding trouble spot six order current equations, try to achieve trouble spot six order electric currents, after trouble spot six order electric currents are converted into six phase currents of trouble spot.Respectively with six phase currents and action current threshold value
Figure 48130DEST_PATH_IMAGE073
Make comparisons, obtain fault separate.Fig. 3 has provided apart from the M end 100km IBCIIC of place through 300
Figure 298982DEST_PATH_IMAGE035
Select the phase result during earth fault.Dotted line is the electric current threshold value among the figure, and solid line is each phase current magnitude of trouble spot.As shown in Figure 3, fault phase is IB, IC, IIC, and namely the C of the B phase of I loop line, C phase and II loop line mutually.Other kinds type Fault Phase Selection result is all correct.
Fig. 4 is Hebei province city part electric network wiring scheme.Transformer station 1 is connected by double loop for the 220kV station in turn for 500kV station, transformer station 2 and transformer station 3.Transformer station 2,3 equal total length 84.069kM of two loop lines, the leader cable model is LGJQ-2
Figure 139899DEST_PATH_IMAGE074
240.Fig. 5 is transformer station 2,3, in when, apart from transformer station's 2 end 69.6kM places double-circuit lines the IAIIAG fault occuring, the fault waveform figure that the RCS-931BM protective device obtains.
With above-mentioned physical fault recorder data criterion that substitution is carried, recording the trouble spot is 69.3kM to the fault distance of transformer station 2, and distance accuracy is 99.57%.Fig. 6 is for selecting the phase result, and dotted line is the electric current threshold value among the figure, and solid line is each phase current magnitude of trouble spot.Known by Fig. 6, the phase result that selects of this criterion is that IA, IIA are fault phase, and IB, IC, IIB and IIC are healthy phases.

Claims (3)

1. a Fault Locating Method that is used for the double-circuit line on same pole road is characterized in that, described method is at first carried out double-circuit line two ends electric parameters the decomposition of six orders, and described electric parameters is voltage and the magnitude of current; Then utilize that the transmission line long-line equation with positive sequence fault component calculates fault distance in the six order components, recycling double loop two ends electric parameters, fault distance and long-line equation are tried to achieve six order electric currents of trouble spot, six order electric currents are converted into six phase currents, last amplitude Characteristics failure judgement phase according to the trouble spot phase current.
2. a kind of Fault Locating Method for the double-circuit line on same pole road according to claim 1 is characterized in that, described method is processed according to the following steps:
A. utilize Metzler matrix that following formula provides that double loop both end voltage amount, the magnitude of current are carried out respectively six orders and decompose, two three-phase inversion of double loop are become six independent order components: same positive sequence
Figure 369772DEST_PATH_IMAGE001
, same negative phase-sequence , same zero sequence
Figure 623216DEST_PATH_IMAGE003
Anyway order
Figure 404090DEST_PATH_IMAGE004
, anti-negative phase-sequence
Figure 389364DEST_PATH_IMAGE005
, anti-zero sequence
Figure 230281DEST_PATH_IMAGE006
,
Figure 301005DEST_PATH_IMAGE007
；
Wherein,
Figure 885570DEST_PATH_IMAGE008
B. adopt with positive sequence fault component transmission line long-line equation and carry out fault localization, the range finding equation is:
Figure 725350DEST_PATH_IMAGE009
，
In the formula, With
Figure 560768DEST_PATH_IMAGE011
Be respectively the same positive sequence fault component voltage and current of double loop two ends M end and N end;
Figure 417866DEST_PATH_IMAGE012
Same positive sequence wave impedance for circuit;
Figure 643311DEST_PATH_IMAGE013
For circuit with the positive sequence propagation constant;
Figure 826030DEST_PATH_IMAGE014
Be the same positive sequence impedance of circuit unit length;
Figure 871347DEST_PATH_IMAGE015
For the circuit unit length with the positive sequence admittance;
Figure 797714DEST_PATH_IMAGE016
Be double loop length,
Figure 346507DEST_PATH_IMAGE017
For holding distance to M in the trouble spot;
C. will
Figure 977426DEST_PATH_IMAGE018
The substitution following formula calculates respectively trouble spot six order electric currents:
，
In the formula,
Figure 974518DEST_PATH_IMAGE020
With
Figure 908976DEST_PATH_IMAGE021
Being respectively the double loop two ends is i sequence voltage component and each order current component of M end and N end;
Figure 167919DEST_PATH_IMAGE022
I order wave impedance for circuit;
Figure 453407DEST_PATH_IMAGE023
Be circuit i order propagation constant;
Figure 190419DEST_PATH_IMAGE024
Be the impedance of circuit unit length i order; Be the admittance of circuit unit length i order;
D. utilize following formula trouble spot six order electric currents to be converted into six phase currents of double line down point:
Figure 674807DEST_PATH_IMAGE026
，
In the formula: ,
Figure 722714DEST_PATH_IMAGE028
, For the trouble spot gets six order electric currents,
Figure 232510DEST_PATH_IMAGE030
Six phase currents for the trouble spot;
E. utilize the size of each phase current of trouble spot to distinguish fault separate:
Set a relay protection action current threshold value
Figure 492590DEST_PATH_IMAGE031
If the phase current of trouble spot is worth greater than this, then this is judged to fault phase mutually, otherwise then is judged to healthy phases.
3. a kind of Fault Locating Method for the double-circuit line on same pole road according to claim 2 is characterized in that, distinguishes the threshold value of the relay protection action current of fault phase Determined by following formula:
Figure 600541DEST_PATH_IMAGE032
，
Figure 106608DEST_PATH_IMAGE033
，
Wherein
Figure 853984DEST_PATH_IMAGE034
Get the higher value of M, protection installation place, N both sides i phase current, k is safety factor, and k equals 0.5.
CN2012104407215A 2012-11-07 2012-11-07 Fault positioning method for common-tower double-circuit line Pending CN102914726A (en)

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CN112684374A (en) * 2020-11-11 2021-04-20 大唐水电科学技术研究院有限公司 Fault analysis method for same-phase overline disconnection of four circuit lines on same tower
CN114019294A (en) * 2021-09-13 2022-02-08 大唐水电科学技术研究院有限公司 Method and device for analyzing three-phase disconnection fault of four-circuit line and four-circuit line on same pole

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CN106814282A (en) * 2015-11-27 2017-06-09 中国电力科学研究院 A kind of double-circuit line on same pole phase-selecting method
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CN107026430A (en) * 2016-01-29 2017-08-08 中国电力科学研究院 A kind of double-circuit line on same pole phase-selecting method based on single-ended Sudden Changing Rate
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CN106124927A (en) * 2016-06-20 2016-11-16 山东大学 The asynchronous fault distance-finding method of double-circuit lines on the same pole containing series compensation
CN107015115A (en) * 2017-04-13 2017-08-04 南京电力工程设计有限公司 A kind of fault distance-finding method of same tower double back transmission line
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CN107271842A (en) * 2017-06-05 2017-10-20 天津大学 A kind of parallel erected on same tower double-circuit line Fault Locating Method based on positive-sequence component in the same direction
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CN108828407A (en) * 2018-06-29 2018-11-16 国网江苏省电力有限公司无锡供电分公司 Double circuits on same tower mixed power transmission line fault locating method
CN108828407B (en) * 2018-06-29 2020-10-23 国网江苏省电力有限公司无锡供电分公司 Fault positioning method for double-circuit mixed transmission line on same pole
CN109655710A (en) * 2018-12-03 2019-04-19 国网江苏省电力有限公司检修分公司 Double circuits on same tower transmission line of electricity both ends measure the bearing calibration of phasor, apparatus and system
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