CN102788598A - Error suppressing method of fiber strap-down inertial navigation system based on three-axis rotation - Google Patents

Error suppressing method of fiber strap-down inertial navigation system based on three-axis rotation Download PDF

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CN102788598A
CN102788598A CN201210305216XA CN201210305216A CN102788598A CN 102788598 A CN102788598 A CN 102788598A CN 201210305216X A CN201210305216X A CN 201210305216XA CN 201210305216 A CN201210305216 A CN 201210305216A CN 102788598 A CN102788598 A CN 102788598A
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CN102788598B (en
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孙伟
徐爱功
徐宗秋
车莉娜
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Liaoning Technical University
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Abstract

本发明提供的是一种基于三轴旋转的光纤捷联惯导系统误差抑制方法。利用全球定位系统(GPS)确定载体的初始位置参数;采集光纤陀螺仪和石英加速度计输出的数据;对加速度计的输出与重力加速度的关系以及陀螺仪输出与地球自转角速率的关系确定载体的姿态信息并完成系统的初始对准;IMU采用十二个转停次序为一个旋转周期的转位方案;将IMU旋转后光纤陀螺仪和石英加速度计生成的数据转换到导航坐标系下,得到惯性器件常值偏差的调制形式;利用光纤陀螺的输出值对捷联矩阵进行更新;计算IMU旋转调制后载体的位置信息;本发明将三轴方向上的惯性器件常值偏差进行调制,提高导航定位精度。

Figure 201210305216

The invention provides an error suppression method for an optical fiber strapdown inertial navigation system based on three-axis rotation. Use the global positioning system (GPS) to determine the initial position parameters of the carrier; collect the data output by the fiber optic gyroscope and the quartz accelerometer; determine the relationship between the output of the accelerometer and the acceleration of gravity and the relationship between the output of the gyroscope and the angular rate of the earth's rotation attitude information and complete the initial alignment of the system; the IMU uses twelve rotation-stop sequences as a rotation cycle indexing scheme; after the IMU rotates, the data generated by the fiber optic gyroscope and the quartz accelerometer are converted into the navigation coordinate system to obtain the inertia Modulation form of device constant value deviation; use the output value of fiber optic gyroscope strapdown matrix Update; calculate the position information of the carrier after the IMU rotation modulation; the invention modulates the constant value deviation of the inertial device in the three-axis direction to improve the navigation and positioning accuracy.

Figure 201210305216

Description

Fiber strapdown inertial navigation system error inhibition method based on three rotations
(1) technical field
What the present invention relates to is a kind of measuring method, in particular a kind of fiber strapdown inertial navigation system error inhibition method based on three rotations.
(2) background technology
Inertial navigation is to utilize inertia sensitive element (gyroscope and accelerometer) to measure the line motion and the angular motion in carrier relative inertness space, and under known starting condition, goes out the navigational parameters such as speed, position and attitude of carrier with COMPUTER CALCULATION.It relies on the Sensitive Apparatus of self to accomplish navigation task fully, need not to rely on any external information, also not to any energy of external radiation, is a kind of autonomous navigational system fully, therefore has good concealment, anti-interference, the advantage that do not receive any meteorological condition restriction.In addition, inertial navigation system also has the characteristics of data updating rate height, short-term accuracy height and good stability.Just because of above advantage, it has obtained widespread use at Aeronautics and Astronautics, navigation and a lot of civil area.In strapdown inertial navigation system; All inertance elements are directly installed on the carrier; What inertance element was exported is exactly angular velocity and the acceleration of carrier with respect to inertial space; By computing machine the acceleration information that records under the carrier coordinate system is transformed into navigation coordinate system and carries out navigation calculation again, be equivalent to utilize the gyroscope output data in computing machine, to make up of the reference of a mathematical platform as navigation calculating.
Optical fibre gyro is as a kind of novel angular rate sensor; Compare with traditional gyroscope (liquid floated gyroscope, dynamically tuned gyro, DTG, electrostatic gyro); Has significant advantage: 1) owing to have no rotary part; Thereby firm in structure, anti-vibration, shock resistance, anti-big overload, reliability is high.Simultaneity factor is low in energy consumption, does not need preheating, and start-up time is short, and need not keep in repair, and the life-span is long; 2) because optical fiber is nonmetallic materials, so radiation resistance, strong interference immunity, stable performance can work in the comparatively abominable electromagnetic environment; 3) owing to the area of sensitivity with fiber optic loop is directly proportional, can increase the area of fiber optic loop through the way that increases the fiber optic loop number of turns, the sensitivity that improves gyro, so volume is little, simple in structure, processing technology is simple and cost is low; 4) dynamic range is big, the latch-up phenomenon in the time of can not low rate occurring, and can directly export digital signal, be convenient to utilize computing machine to carry out system in combination.
In the strapdown inertial navigation system, people have promoted the fast development of inertia device for the lasting research of inertia devices such as gyroscope that constitutes Inertial Measurement Unit and accelerometer.But the device precision is high more, and further the cost of boost device precision is just big more.After the inertia device precision reached certain requirement, the performance that adopts the next further improvement of the method system of compensation inertia device deviation was to realize a more realization approach of high precision navigation.The compensation method of inertance element has two kinds: the one, and utilize external information to compensate correction; Another kind method is the self compensation of inertia device deviation; The rotation modulation technique is a kind of method of self compensation; Through around an axle or a plurality of rotator inertia measuring units (IMU), navigation error is modulated, reach the purpose that navigation accuracy is dispersed, improved to the control navigation error.
The single shaft rotation only can compensate the normal value deviation of inertia device on two sensitive axes directions; Though the twin shaft rotation can compensate the normal value deviation of inertia device on three sensitive axes directions, can't avoid the negative effect of carrier angular motion to the rotation modulation technique.Therefore, how reasonable in design three rotation compensation modes have important meaning for the navigation accuracy of further raising fiber strapdown inertial navigation system.
(3) summary of the invention
Technology of the present invention is dealt with problems and is: overcome the deficiency of prior art, a kind of fiber strapdown inertial navigation system error inhibition method based on three sensitive axes rotations of Inertial Measurement Unit is provided.
Technical solution of the present invention is: a kind of fiber strapdown inertial navigation system error inhibition method based on three rotations; It is characterized in that adopting three transposition schemes of Inertial Measurement Unit to come to isolate fully the carrier angular motion; Make the relative geographic coordinate system of Inertial Measurement Unit static; Avoid the carrier angular motion for the negative influence of adopting Inertial Measurement Unit rotation modulation technique, can confirm that inertia device often is worth the inhibition form of deviation, to realize more precise navigation.Its concrete steps are following:
(1) confirms the initial position parameters of carrier through GPS, they are bound to navigational computer;
(2) SINS carries out preheating and prepares, and gathers data that fibre optic gyroscope and quartz accelerometer export and data are handled;
(3) IMU adopts 12 commentaries on classics to stop the transposition scheme that order is a swing circle (like accompanying drawing 2);
Order 1, IMU rotates counterclockwise 180 ° of in-position B, stand-by time T from the A point sOrder 2, IMU rotates counterclockwise 180 ° of in-position C, stand-by time T from the B point sOrder 3, IMU rotates counterclockwise 180 ° of in-position A, stand-by time T from the C point sOrder 4, IMU rotates counterclockwise 180 ° of in-position C, stand-by time T from the A point sOrder 5, IMU rotates counterclockwise 180 ° of in-position B, stand-by time T from the C point sOrder 6, IMU rotates counterclockwise 180 ° of in-position A, stand-by time T from the B point sOrder 7, IMU clockwise rotates 180 ° of in-position B, stand-by time T from the A point sOrder 8, IMU clockwise rotates 180 ° of in-position C, stand-by time T from the B point sOrder 9, IMU clockwise rotates 180 ° of in-position A, stand-by time T from the C point sOrder 10, IMU clockwise rotates 180 ° of in-position C, stand-by time T from the A point sOrder 11, IMU clockwise rotates 180 ° of in-position B, stand-by time T from the C point sOrder 12, IMU clockwise rotates 180 ° of in-position A, stand-by time T from the B point sIMU rotates sequential loop according to this to carry out.
(4) data-switching that Inertial Measurement Unit rotation back gyroscope is generated obtains the modulation format that inertia device often is worth deviation under carrier coordinate system;
Suppose that the gyroscope constant value drift on the IMU horizontal direction is respectively ε xAnd ε yUnder the carrier quiescent conditions; Because three positions of A, B, C that IMU pauses are with respect to navigation coordinate system symmetry; Therefore on three fixed positions in one three transposition cycles, three gyroscope constant value drifts are fastened the attitude error that projection causes at navigation coordinate and must be satisfied:
3 ( ∫ 0 T s ϵ x n dt ) A + 3 ( ∫ 0 T s ϵ x n dt ) B + 3 ( ∫ 0 T s ϵ x n dt ) C = 0
3 ( ∫ 0 T s ϵ y n dt ) A + 3 ( ∫ 0 T s ϵ y n dt ) B + 3 ( ∫ 0 T s ϵ y n dt ) C = 0
3 ( ∫ 0 T s ϵ z n dt ) A + 3 ( ∫ 0 T s ϵ z n dt ) B + 3 ( ∫ 0 T s ϵ z n dt ) C = 0
Exist the symmetry problem of rotation according to the rotation in three scheme of rotation of IMU, ignore the influence of carrier movement and with local geographic coordinate system as a reference, 12 order transposition schemes can be expressed as:
Process 1: order 1,6,7,12, in the rotation period of formation, the gyroscopic drift of x, y axle is ox at navigation coordinate ny nDemonstrate the Changing Pattern in positive and negative each week in the plane, the normal value deviation that therefore in the integral process of complete cycle, produces is zero, that is:
( ∫ 0 T z ϵ x n dt ) A → + B + ( ∫ 0 T z ϵ x n dt ) B → + A + ( ∫ 0 T z ϵ x n dt ) A → - B + ( ∫ 0 T z ϵ x n dt ) B → - A = 0
( ∫ 0 T z ϵ y n dt ) A → + B + ( ∫ 0 T z ϵ y n dt ) B → + A + ( ∫ 0 T z ϵ y n dt ) A → - B + ( ∫ 0 T z ϵ y n dt ) B → - A = 0
Wherein, the time of each rotation process is counted T z, around the responsive coordinate axis of Inertial Measurement Unit rotate counterclockwise into+, clockwise rotate into-.
Process 2: order 2,5,8,11, in the rotation period of formation, the gyroscopic drift of y, z axle is oy at navigation coordinate nz nDemonstrate the Changing Pattern in positive and negative each week in the plane, the normal value deviation that therefore in the integral process of complete cycle, produces is zero, that is:
( ∫ 0 T z ϵ y n dt ) B → + C + ( ∫ 0 T z ϵ y n dt ) C → + B + ( ∫ 0 T z ϵ y n dt ) B → - C + ( ∫ 0 T z ϵ y n dt ) C → - B = 0
( ∫ 0 T z ϵ z n dt ) B → + C + ( ∫ 0 T z ϵ z n dt ) C → + B + ( ∫ 0 T z ϵ z n dt ) B → - C + ( ∫ 0 T z ϵ z n dt ) C → - B = 0
Process 3: order 3,4,9,10, in the rotation period of formation, the gyroscopic drift of x, z axle is ox at navigation coordinate nz nDemonstrate the Changing Pattern in positive and negative each week in the plane, the normal value deviation that therefore in the integral process of complete cycle, produces is zero, that is:
( ∫ 0 T z ϵ x n dt ) C → + A + ( ∫ 0 T z ϵ x n dt ) A → + C + ( ∫ 0 T z ϵ x n dt ) C → - A + ( ∫ 0 T z ϵ x n dt ) A → - C = 0
( ∫ 0 T z ϵ z n dt ) C → + A + ( ∫ 0 T z ϵ z n dt ) A → + C + ( ∫ 0 T z ϵ z n dt ) C → - A + ( ∫ 0 T z ϵ z n dt ) A → - C = 0
It is exactly the value that periodically changes the strapdown matrix that 12 order change the process of stopping, make three gyrostatic sensitive axes in a rotation period along center of rotation be symmetrically distributed (like accompanying drawing 3).Having proved intuitively that one 12 order changes stops in the process, and gyroscope often is worth the relative navigation coordinate of deviation system by modulation fully, and the navigation accuracy of system is not exerted an influence.In like manner stop in the cycle a complete commentaries on classics because the symmetrical distribution of three fixed positions and rotation process, can obtain that Inertial Measurement Unit stops and the transposition process in the accelerometer zero drift in the similar effect effect of navigation coordinate system.
(5) output valve of gyroscope under the IMU coordinate system brought in the strapdown inertial navigation system, adopts the equivalent rotating vector method that strapdown matrix
Figure BSA00000768634100041
is upgraded:
ω ns s = ω is s - ( C s n ) T ( ω ie n + ω en n )
Wherein:
Figure BSA00000768634100043
is the component of rotational-angular velocity of the earth under navigation system;
Figure BSA00000768634100044
is the component of motion angular velocity under navigation system of spherical coordinate system relatively for navigation coordinate;
Figure BSA00000768634100045
is the component of motion angular velocity on the IMU coordinate system of the relative navigation coordinate of IMU system.
If the equivalent rotating vector differential equation of the relative navigation coordinate of IMU coordinate system system is:
Φ · = ω ns s + 1 2 Φ × ω ns s + 1 12 Φ × ( Φ × ω ns s )
Solve the rotating vector of equivalence and replace hypercomplex number to separate according to angular velocity
Figure BSA00000768634100047
q = cos Φ 2 + Φ | Φ | sin Φ 2
Because q=q 0+ q 1I+q 2J+q 3K, i, j, k are direction vector.Therefore the renewal process of attitude matrix
Figure BSA00000768634100049
is:
C s n = q 0 2 + q 1 2 - q 2 2 - q 3 2 2 ( q 1 q 2 - q 0 q 3 ) 2 ( q 1 q 3 + q 0 q 2 ) 2 ( q 1 q 2 + q 0 q 3 ) q 0 2 - q 1 2 + q 2 2 - q 3 2 2 ( q 2 q 3 - q 0 q 1 ) 2 ( q 1 q 3 - q 0 q 2 ) 2 ( q 2 q 3 + q 0 q 1 ) q 0 2 - q 1 2 - q 2 2 + q 3 2
(6) the use of quartz accelerometer output value
Figure BSA000007686341000411
and Step (5) the calculated attitude matrix
Figure BSA000007686341000412
calculated after IMU rotation modulated carrier position.
1) calculates the acceleration f down of navigation system n:
f n = C s n f is s
2) position of calculating carrier:
According to t 1Carrier east orientation horizontal velocity V constantly x(t 1) and north orientation horizontal velocity V y(t 1), ask for t 2Carrier positions is constantly:
Figure BSA000007686341000414
3) calculate the carrier positions error:
Figure BSA000007686341000415
Wherein:
Figure BSA00000768634100051
λ 0Longitude and the latitude of representing initial time carrier present position respectively; Δ λ representes the latitude of carrier, the variable quantity of longitude respectively; R N, R MThe radius-of-curvature of representing earth meridian circle, prime vertical respectively; t 1, t 2Two the adjacent time points in the process that resolve for inertial navigation system.
The present invention's advantage compared with prior art is: the present invention has broken in traditional SINS IMU and carrier and has been connected and causes system's navigation accuracy to receive the constraint of inertia device effects; Propose a kind of IMU often to be worth the deviation modulation scheme around the inertia device that three fixing position rotatings of the sensitive axes of three directions of carrier stop; This method can often be worth deviation with all inertia devices modulates, and improves navigation and positioning accuracy effectively.
Effect to the present invention is useful is explained as follows:
Under the VC++ simulated conditions, this method is carried out emulation experiment:
Carrier remains static, the error model parameters of IMU three positions 12 order rotation-stop schemes:
The dead time of three positions: T s=5 minutes;
The time that consumes when rotating 180 °: T z=12 seconds;
Rotate in 180 ° the process, the acceleration and deceleration time in each transposition respectively is 4 seconds;
Carrier initial position: 45.7796 ° of north latitude, 126.6705 ° of east longitudes;
The initial attitude error angle: three initial attitude error angles are zero;
Equatorial radius: R e=6378393.0 meters;
Ellipsoid degree: e=3.367e-3;
The earth surface acceleration of gravity that can get by universal gravitation: g 0=9.78049;
Rotational-angular velocity of the earth (radian per second): 7.2921158e-5;
The gyroscope constant value drift: 0.01 degree/hour;
Accelerometer bias: 10 -4g 0
Constant: π=3.1415926;
It is as shown in Figure 4 to utilize the said method of invention to obtain the carrier positions graph of errors.The result shows that the 12 order commentaries on classics of IMU three positions stops under the condition, adopts the inventive method can obtain high orientation precision.
(4) description of drawings
Fig. 1 is a kind of fiber strapdown inertial navigation system error inhibition method process flow diagram based on three rotations of the present invention;
Fig. 2 is the fiber strapdown inertial navigation system IMU rotation-stop scheme detailed step figure based on three rotations of the present invention;
Fig. 3 is that the fiber strapdown inertial navigation system IMU based on three rotations of the present invention changes stopping time constant value drift orientation distribution;
Contrast experiment's curve of carrier positioning error when Fig. 4 is carrier positions error and the IMU stationary state of the fiber strapdown inertial navigation system based on three rotations of the present invention.
(5) embodiment
Describe in detail below in conjunction with the accompanying drawing specific embodiments of the invention:
(1) confirms the initial position parameters of carrier through GPS, they are bound to navigational computer;
(2) SINS carries out preheating and prepares, and gathers data that fibre optic gyroscope and quartz accelerometer export and data are handled;
(3) IMU adopts 12 commentaries on classics to stop the transposition scheme that order is a swing circle (like accompanying drawing 2);
Order 1, IMU rotates counterclockwise 180 ° of in-position B, stand-by time T from the A point sOrder 2, IMU rotates counterclockwise 180 ° of in-position C, stand-by time T from the B point sOrder 3, IMU rotates counterclockwise 180 ° of in-position A, stand-by time T from the C point sOrder 4, IMU rotates counterclockwise 180 ° of in-position C, stand-by time T from the A point sOrder 5, IMU rotates counterclockwise 180 ° of in-position B, stand-by time T from the C point sOrder 6, IMU rotates counterclockwise 180 ° of in-position A, stand-by time T from the B point sOrder 7, IMU clockwise rotates 180 ° of in-position B, stand-by time T from the A point sOrder 8, IMU clockwise rotates 180 ° of in-position C, stand-by time T from the B point sOrder 9, IMU clockwise rotates 180 ° of in-position A, stand-by time T from the C point sOrder 10, IMU clockwise rotates 180 ° of in-position C, stand-by time T from the A point sOrder 11, IMU clockwise rotates 180 ° of in-position B, stand-by time T from the C point sOrder 12, IMU clockwise rotates 180 ° of in-position A, stand-by time T from the B point sIMU rotates sequential loop according to this to carry out.
(4) data-switching that Inertial Measurement Unit rotation back gyroscope is generated obtains the modulation format that inertia device often is worth deviation under carrier coordinate system;
Suppose that the gyroscope constant value drift on the IMU horizontal direction is respectively ε xAnd ε yUnder the carrier quiescent conditions; Because three positions of A, B, C that IMU pauses are with respect to navigation coordinate system symmetry; Therefore on three fixed positions in one three transposition cycles, three gyroscope constant value drifts are fastened the attitude error that projection
Figure BSA00000768634100061
causes at navigation coordinate and must be satisfied:
3 ( ∫ 0 T s ϵ x n dt ) A + 3 ( ∫ 0 T s ϵ x n dt ) B + 3 ( ∫ 0 T s ϵ x n dt ) C = 0
3 ( ∫ 0 T s ϵ y n dt ) A + 3 ( ∫ 0 T s ϵ y n dt ) B + 3 ( ∫ 0 T s ϵ y n dt ) C = 0 - - - ( 1 )
3 ( ∫ 0 T s ϵ z n dt ) A + 3 ( ∫ 0 T s ϵ z n dt ) B + 3 ( ∫ 0 T s ϵ z n dt ) C = 0
Exist the symmetry problem of rotation according to the rotation in three scheme of rotation of IMU, ignore the influence of carrier movement and with local geographic coordinate system as a reference, 12 order transposition schemes can be expressed as:
Process 1: order 1,6,7,12, in the rotation period of formation, the gyroscopic drift of x, y axle is ox at navigation coordinate ny nDemonstrate the Changing Pattern in positive and negative each week in the plane, the normal value deviation that therefore in the integral process of complete cycle, produces is zero, that is:
( ∫ 0 T z ϵ x n dt ) A → + B + ( ∫ 0 T z ϵ x n dt ) B → + A + ( ∫ 0 T z ϵ x n dt ) A → - B + ( ∫ 0 T z ϵ x n dt ) B → - A = 0
( 2 )
( ∫ 0 T z ϵ y n dt ) A → + B + ( ∫ 0 T z ϵ y n dt ) B → + A + ( ∫ 0 T z ϵ y n dt ) A → - B + ( ∫ 0 T z ϵ y n dt ) B → - A = 0
Wherein, the time of each rotation process is counted T z, around the responsive coordinate axis of Inertial Measurement Unit rotate counterclockwise into+, clockwise rotate into-.
Process 2: order 2,5,8,11, in the rotation period of formation, the gyroscopic drift of y, z axle is oy at navigation coordinate nz nDemonstrate the Changing Pattern in positive and negative each week in the plane, the normal value deviation that therefore in the integral process of complete cycle, produces is zero, that is:
( ∫ 0 T z ϵ y n dt ) B → + C + ( ∫ 0 T z ϵ y n dt ) C → + B + ( ∫ 0 T z ϵ y n dt ) B → - C + ( ∫ 0 T z ϵ y n dt ) C → - B = 0
( 3 )
( ∫ 0 T z ϵ z n dt ) B → + C + ( ∫ 0 T z ϵ z n dt ) C → + B + ( ∫ 0 T z ϵ z n dt ) B → - C + ( ∫ 0 T z ϵ z n dt ) C → - B = 0
Process 3: order 3,4,9,10, in the rotation period of formation, the gyroscopic drift of x, z axle is ox at navigation coordinate nz nDemonstrate the Changing Pattern in positive and negative each week in the plane, the normal value deviation that therefore in the integral process of complete cycle, produces is zero, that is:
( ∫ 0 T z ϵ x n dt ) C → + A + ( ∫ 0 T z ϵ x n dt ) A → + C + ( ∫ 0 T z ϵ x n dt ) C → - A + ( ∫ 0 T z ϵ x n dt ) A → - C = 0
( 4 )
( ∫ 0 T z ϵ z n dt ) C → + A + ( ∫ 0 T z ϵ z n dt ) A → + C + ( ∫ 0 T z ϵ z n dt ) C → - A + ( ∫ 0 T z ϵ z n dt ) A → - C = 0
It is exactly the value that periodically changes the strapdown matrix that 12 order change the process of stopping, make three gyrostatic sensitive axes in a rotation period along center of rotation be symmetrically distributed (like accompanying drawing 3).Having proved intuitively that one 12 order changes stops in the process, and gyroscope often is worth the relative navigation coordinate of deviation system by modulation fully, and the navigation accuracy of system is not exerted an influence.In like manner stop in the cycle a complete commentaries on classics because the symmetrical distribution of three fixed positions and rotation process, can obtain that Inertial Measurement Unit stops and the transposition process in the accelerometer zero drift in the similar effect effect of navigation coordinate system.
(5) output valve of gyroscope under the IMU coordinate system brought in the strapdown inertial navigation system, adopts the equivalent rotating vector method that strapdown matrix
Figure BSA000007686341000711
is upgraded:
ω ns s = ω is s - ( C s n ) T ( ω ie n + ω en n ) - - - ( 5 )
Wherein:
Figure BSA000007686341000713
is the component of rotational-angular velocity of the earth under navigation system;
Figure BSA000007686341000714
is the component of motion angular velocity under navigation system of spherical coordinate system relatively for navigation coordinate;
Figure BSA000007686341000715
is the component of motion angular velocity on the IMU coordinate system of the relative navigation coordinate of IMU system.
If the equivalent rotating vector differential equation of the relative navigation coordinate of IMU coordinate system system is:
Φ · = ω ns s + 1 2 Φ × ω ns s + 1 12 Φ × ( Φ × ω ns s ) - - - ( 6 )
Solve the rotating vector of equivalence and replace hypercomplex number to separate according to angular velocity
Figure BSA00000768634100082
q = cos Φ 2 + Φ | Φ | sin Φ 2 - - - ( 7 )
Because q=q 0+ q 1I+q 2J+q 3K, i, j, k are direction vector.Therefore the renewal process of attitude matrix is:
C s n = q 0 2 + q 1 2 - q 2 2 - q 3 2 2 ( q 1 q 2 - q 0 q 3 ) 2 ( q 1 q 3 + q 0 q 2 ) 2 ( q 1 q 2 + q 0 q 3 ) q 0 2 - q 1 2 + q 2 2 - q 3 2 2 ( q 2 q 3 - q 0 q 1 ) 2 ( q 1 q 3 - q 0 q 2 ) 2 ( q 2 q 3 + q 0 q 1 ) q 0 2 - q 1 2 - q 2 2 + q 3 2 - - - ( 8 )
(6) the use of quartz accelerometer output value
Figure BSA00000768634100086
and Step (5) the calculated attitude matrix
Figure BSA00000768634100087
calculated after IMU rotation modulated carrier position.
1) calculates the acceleration f down of navigation system n:
f n = C s n f is s - - - ( 9 )
2) position of calculating carrier:
According to t 1Carrier east orientation horizontal velocity V constantly x(t 1) and north orientation horizontal velocity V y(t 1), ask for t 2Carrier positions is constantly:
Figure BSA00000768634100089
3) calculate the carrier positions error:
Figure BSA000007686341000810
Wherein: λ 0Longitude and the latitude of representing initial time carrier present position respectively;
Figure BSA000007686341000812
Δ λ representes the latitude of carrier, the variable quantity of longitude respectively; R N, R MThe radius-of-curvature of representing earth meridian circle, prime vertical respectively; t 1, t 2Two the adjacent time points in the process that resolve for inertial navigation system.

Claims (5)

1.一种基于三轴旋转的光纤捷联惯导系统误差抑制方法,其特征在于包括以下步骤:1. a kind of optical fiber strapdown inertial navigation system error suppression method based on triaxial rotation, it is characterized in that comprising the following steps: (1)通过GPS确定载体的初始位置参数,将它们装订至导航计算机中;(1) Determine the initial position parameters of the carrier by GPS, and bind them into the navigation computer; (2)捷联惯导系统进行预热准备,采集光纤陀螺仪和石英加速度计输出的数据并对数据进行处理;(2) The strapdown inertial navigation system is preheated, and the data output by the fiber optic gyroscope and the quartz accelerometer are collected and processed; (3)IMU采用十二个转停次序为一个旋转周期的转位方案(如附图2);(3) The IMU adopts an indexing scheme in which twelve rotation-stop sequences are one rotation cycle (as shown in Figure 2); 次序1,IMU从A点出发逆时针转动180°到达位置B,停止时间Ts;次序2,IMU从B点出发逆时针转动180°到达位置C,停止时间Ts;次序3,IMU从C点出发逆时针转动180°到达位置A,停止时间Ts;次序4,IMU从A点出发逆时针转动180°到达位置C,停止时间Ts;次序5,IMU从C点出发逆时针转动180°到达位置B,停止时间Ts;次序6,IMU从B点出发逆时针转动180°到达位置A,停止时间Ts;次序7,IMU从A点出发顺时针转动180°到达位置B,停止时间Ts;次序8,IMU从B点出发顺时针转动180°到达位置C,停止时间Ts;次序9,IMU从C点出发顺时针转动180°到达位置A,停止时间Ts;次序10,IMU从A点出发顺时针转动180°到达位置C,停止时间Ts;次序11,IMU从C点出发顺时针转动180°到达位置B,停止时间Ts;次序12,IMU从B点出发顺时针转动180°到达位置A,停止时间Ts;IMU按照此转动顺序循环进行。Sequence 1, IMU starts from point A and rotates 180° counterclockwise to position B, stop time T s ; sequence 2, IMU starts from point B to rotate 180° counterclockwise to position C, stop time T s ; Sequence 3, IMU starts from C Start from point A and turn 180° counterclockwise to reach position A, stop time T s ; Sequence 4, IMU turn 180° counterclockwise from point A to reach position C, stop time T s ; Sequence 5, IMU turn counterclockwise 180° from point C ° Arrive at position B, stop time T s ; Sequence 6, IMU starts from point B and rotates 180° counterclockwise to reach position A, stops at time T s ; Sequence 7, IMU starts from point A and rotates 180° clockwise to position B, stops Time T s ; Sequence 8, IMU starts from point B and turns 180° clockwise to reach position C, stop time T s ; Sequence 9, IMU starts from point C to turn 180° clockwise to reach position A, stop time T s ; Sequence 10 , the IMU starts from point A and rotates 180° clockwise to reach position C, stop time T s ; sequence 11, IMU starts from point C to rotate 180° clockwise to reach position B, stop time T s ; sequence 12, IMU starts from point B Rotate 180° clockwise to reach position A, stop time T s ; IMU cycles through this rotation sequence. (4)将惯性测量单元旋转后陀螺仪生成的数据转换到载体坐标系下,得到惯性器件常值偏差的调制形式;(4) Convert the data generated by the gyroscope after the inertial measurement unit rotates to the carrier coordinate system to obtain the modulation form of the constant value deviation of the inertial device; 假定IMU水平方向上的陀螺常值漂移分别为εx和εy。载体静止条件下,由于IMU停顿的A、B、C三个位置相对于导航坐标系对称,因此在一个三轴转位周期内的三个固定位置上,三个陀螺仪常值漂移在导航坐标系上投影引起的姿态角误差必然满足:Assume that the gyro constant drifts in the horizontal direction of the IMU are ε x and ε y , respectively. Under the static condition of the carrier, since the three positions A, B, and C where the IMU stops are symmetrical with respect to the navigation coordinate system, at three fixed positions within a three-axis indexing cycle, the three gyroscope constants drift in the navigation coordinate system Attach the projection The resulting attitude angle error must satisfy: 33 (( ∫∫ 00 TT sthe s ϵϵ xx nno dtdt )) AA ++ 33 (( ∫∫ 00 TT sthe s ϵϵ xx nno dtdt )) BB ++ 33 (( ∫∫ 00 TT sthe s ϵϵ xx nno dtdt )) CC == 00 33 (( ∫∫ 00 TT sthe s ϵϵ ythe y nno dtdt )) AA ++ 33 (( ∫∫ 00 TT sthe s ϵϵ ythe y nno dtdt )) BB ++ 33 (( ∫∫ 00 TT sthe s ϵϵ ythe y nno dtdt )) CC == 00 33 (( ∫∫ 00 TT sthe s ϵϵ zz nno dtdt )) AA ++ 33 (( ∫∫ 00 TT sthe s ϵϵ zz nno dtdt )) BB ++ 33 (( ∫∫ 00 TT sthe s ϵϵ zz nno dtdt )) CC == 00 根据IMU三轴转动方案中的转动存在着转动的对称性问题,忽略载体运动的影响并以当地地理坐标系作为参考,12次序转位方案可以表述为:According to the rotation symmetry problem in the IMU three-axis rotation scheme, ignoring the influence of the carrier motion and taking the local geographic coordinate system as a reference, the 12-order transposition scheme can be expressed as: 过程1:次序1、6、7、12,构成的转动周期内,x、y轴的陀螺仪漂移在导航坐标系oxnyn平面内呈现出正反各一周的变化规律,因此在整周期的积分过程中产生的常值偏差为零,即:Process 1: Sequence 1, 6, 7, 12, within the rotation period formed, the gyroscope drift of the x and y axes presents a positive and negative cycle of change in the navigation coordinate system ox n y n plane, so in the entire cycle The constant deviation produced during the integration of is zero, that is: (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) BB →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; -- BB ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) BB →&Right Arrow; -- AA == 00 (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) AA →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) AA →&Right Arrow; -- BB ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; -- AA == 00 其中,每个转动过程的时间计为Tz,围绕惯性测量单元敏感坐标轴逆时针转动为+,顺时针转动为-。Wherein, the time of each rotation process is counted as T z , counterclockwise rotation around the sensitive coordinate axis of the inertial measurement unit is +, and clockwise rotation is -. 过程2:次序2、5、8、11,构成的转动周期内,y、z轴的陀螺仪漂移在导航坐标系oynzn平面内呈现出正反各一周的变化规律,因此在整周期的积分过程中产生的常值偏差为零,即:Process 2: Sequence 2, 5, 8, 11, within the rotation cycle formed, the gyroscope drift of the y and z axes presents a positive and negative cycle change law in the navigation coordinate system oy n z n plane, so in the whole cycle The constant deviation produced during the integration of is zero, that is: (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) CC →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; -- CC ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) CC →&Right Arrow; -- BB == 00 (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) BB →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) BB →&Right Arrow; -- CC ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; -- BB == 00 过程3:次序3、4、9、10,构成的转动周期内,x、z轴的陀螺仪漂移在导航坐标系oxnzn平面内呈现出正反各一周的变化规律,因此在整周期的积分过程中产生的常值偏差为零,即:Process 3: Sequences 3, 4, 9, 10, within the rotation cycle formed, the gyroscope drift of the x and z axes presents a positive and negative cycle of change in the navigation coordinate system ox n z n plane, so in the entire cycle The constant deviation produced during the integration of is zero, that is: (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) CC →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) CC →&Right Arrow; -- AA ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; -- CC == 00 (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) AA →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; -- AA ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) AA →&Right Arrow; -- CC == 00 十二次序转停过程就是周期性的改变捷联矩阵的值,使三个陀螺仪的敏感轴在一个转动周期内沿转动中心对称分布(如附图3)。直观地证明了一个十二次序转停过程中,陀螺仪常值偏差相对导航坐标系被完全调制,对系统的导航精度不产生影响。同理在一个完整的转停周期内,由于三个固定位置及转动过程的对称分布,可以得到惯性测量单元停止及转位过程中加速度计零位偏差在导航坐标系的类似作用效果。The twelve-sequence rotation-stop process is to periodically change the value of the strapdown matrix, so that the sensitive axes of the three gyroscopes are symmetrically distributed along the rotation center within one rotation cycle (as shown in Figure 3). It is proved intuitively that during a twelve-sequence turn-to-stop process, the gyroscope constant value deviation is completely modulated relative to the navigation coordinate system, and has no effect on the navigation accuracy of the system. Similarly, in a complete rotation-stop cycle, due to the symmetrical distribution of the three fixed positions and the rotation process, the similar effect of the zero position deviation of the accelerometer in the navigation coordinate system can be obtained during the stop and indexing process of the inertial measurement unit. (5)将陀螺仪在IMU坐标系下的输出值
Figure FSA00000768634000027
带入捷联惯性导航系统中,采用等效旋转矢量法对捷联矩阵
Figure FSA00000768634000028
进行更新:
(5) The output value of the gyroscope in the IMU coordinate system
Figure FSA00000768634000027
Into the strapdown inertial navigation system, using the equivalent rotation vector method to the strapdown matrix
Figure FSA00000768634000028
Make an update:
ωω nsns sthe s == ωω isis sthe s -- (( CC sthe s nno )) TT (( ωω ieie nno ++ ωω enen nno )) 其中:
Figure FSA000007686340000210
为地球自转角速度在导航系下的分量;
Figure FSA000007686340000211
为导航坐标系相对地球坐标系的运动角速度在导航系下的分量;为IMU相对导航坐标系的运动角速度在IMU坐标系上的分量。
in:
Figure FSA000007686340000210
is the component of the earth's rotation angular velocity in the navigation system;
Figure FSA000007686340000211
is the component of the motion angular velocity of the navigation coordinate system relative to the earth coordinate system under the navigation system; is the component of the angular velocity of the motion of the IMU relative to the navigation coordinate system on the IMU coordinate system.
设IMU坐标系相对导航坐标系的等效旋转矢量微分方程为:Let the equivalent rotation vector differential equation of the IMU coordinate system relative to the navigation coordinate system be: ΦΦ ·&Center Dot; == ωω nsns sthe s ++ 11 22 ΦΦ ×× ωω nsns sthe s ++ 11 1212 ΦΦ ×× (( ΦΦ ×× ωω nsns sthe s )) 根据角速度
Figure FSA00000768634000031
求解出等效的旋转矢量并代替四元数解,
According to angular velocity
Figure FSA00000768634000031
Solve for the equivalent rotation vector and replace the quaternion solution,
qq == coscos ΦΦ 22 ++ ΦΦ || ΦΦ || sinsin ΦΦ 22 由于q=q0+q1i+q2j+q3k,i、j、k为方向向量。因此姿态矩阵
Figure FSA00000768634000033
的更新过程为:
Since q=q 0 +q 1 i+q 2 j+q 3 k, i, j, k are direction vectors. Therefore the attitude matrix
Figure FSA00000768634000033
The update process is:
CC sthe s nno == qq 00 22 ++ qq 11 22 -- qq 22 22 -- qq 33 22 22 (( qq 11 qq 22 -- qq 00 qq 33 )) 22 (( qq 11 qq 33 ++ qq 00 qq 22 )) 22 (( qq 11 qq 22 ++ qq 00 qq 33 )) qq 00 22 -- qq 11 22 ++ qq 22 22 -- qq 33 22 22 (( qq 22 qq 33 -- qq 00 qq 11 )) 22 (( qq 11 qq 33 -- qq 00 qq 22 )) 22 (( qq 22 qq 33 ++ qq 00 qq 11 )) qq 00 22 -- qq 11 22 -- qq 22 22 ++ qq 33 22 (6)利用石英加速度计的输出值
Figure FSA00000768634000035
和步骤(5)计算的姿态矩阵
Figure FSA00000768634000036
计算出经过IMU旋转调制后载体的位置。
(6) Utilize the output value of the quartz accelerometer
Figure FSA00000768634000035
and the attitude matrix calculated in step (5)
Figure FSA00000768634000036
Calculate the position of the carrier after the IMU rotation modulation.
1)计算导航系下加速度fn1) Calculate the acceleration f n under the navigation system: ff nno == CC sthe s nno ff isis sthe s 2)计算载体的位置:2) Calculate the position of the carrier: 根据t1时刻的载体东向水平速度Vx(t1)和北向水平速度Vy(t1),求取t2时刻载体位置为:According to the carrier's eastward horizontal velocity V x (t 1 ) and northward horizontal velocity V y (t 1 ) at time t 1, the position of the carrier at time t 2 is calculated as:
Figure FSA00000768634000038
Figure FSA00000768634000038
3)计算载体位置误差:3) Calculate the carrier position error:
Figure FSA00000768634000039
Figure FSA00000768634000039
其中:
Figure FSA000007686340000310
λ0分别表示初始时刻载体所处位置的经度和纬度;
Figure FSA000007686340000311
Δλ分别表示载体的纬度、经度的变化量;RN、RM分别表示地球子午圈、卯酉圈的曲率半径;t1、t2为惯导系统的解算过程中两个相邻的时间点。
in:
Figure FSA000007686340000310
λ 0 represents the longitude and latitude of the carrier's position at the initial moment, respectively;
Figure FSA000007686340000311
Δλ respectively represent the variation of the latitude and longitude of the carrier; R N and R M represent the curvature radii of the meridian circle and Maoyou circle of the earth respectively; t 1 and t 2 are two adjacent times in the process of inertial navigation system solution point.
2.根据权利要求1所述的基于三轴旋转的光纤捷联惯导系统误差抑制方法,其特征在于将IMU采用十二个转停次序为一个旋转周期的转位方案,具体包括如下步骤:2. the optical fiber strapdown inertial navigation system error suppression method based on three-axis rotation according to claim 1, is characterized in that the translocation scheme that the IMU adopts twelve rotation-stop sequences as a rotation cycle specifically includes the following steps: 次序1,IMU从A点出发逆时针转动180°到达位置B,停止时间Ts;次序2,IMU从B点出发逆时针转动180°到达位置C,停止时间Ts;次序3,IMU从C点出发逆时针转动180°到达位置A,停止时间Ts;次序4,IMU从A点出发逆时针转动180°到达位置C,停止时间Ts;次序5,IMU从C点出发逆时针转动180°到达位置B,停止时间Ts;次序6,IMU从B点出发逆时针转动180°到达位置A,停止时间Ts;次序7,IMU从A点出发顺时针转动180°到达位置B,停止时间Ts;次序8,IMU从B点出发顺时针转动180°到达位置C,停止时间Ts;次序9,IMU从C点出发顺时针转动180°到达位置A,停止时间Ts;次序10,IMU从A点出发顺时针转动180°到达位置C,停止时间Ts;次序11,IMU从C点出发顺时针转动180°到达位置B,停止时间Ts;次序12,IMU从B点出发顺时针转动180°到达位置A,停止时间Ts;IMU按照此转动顺序循环进行。Sequence 1, IMU starts from point A and rotates 180° counterclockwise to position B, stop time T s ; sequence 2, IMU starts from point B to rotate 180° counterclockwise to position C, stop time T s ; Sequence 3, IMU starts from C Start from point A and turn 180° counterclockwise to reach position A, stop time T s ; Sequence 4, IMU turn 180° counterclockwise from point A to reach position C, stop time T s ; Sequence 5, IMU turn counterclockwise 180° from point C ° Arrive at position B, stop time T s ; Sequence 6, IMU starts from point B and rotates 180° counterclockwise to reach position A, stops at time T s ; Sequence 7, IMU starts from point A and rotates 180° clockwise to position B, stops Time T s ; Sequence 8, IMU starts from point B and turns 180° clockwise to reach position C, stop time T s ; Sequence 9, IMU starts from point C to turn 180° clockwise to reach position A, stop time T s ; Sequence 10 , the IMU starts from point A and rotates 180° clockwise to reach position C, stop time T s ; sequence 11, IMU starts from point C to rotate 180° clockwise to reach position B, stop time T s ; sequence 12, IMU starts from point B Rotate 180° clockwise to reach position A, stop time T s ; IMU cycles through this rotation sequence. 3.根据权利要求1所述的基于三轴旋转的光纤捷联惯导系统误差抑制方法,其特征在于将惯性测量单元旋转后陀螺仪生成的数据转换到载体坐标系下,得到惯性器件常值偏差的调制形式,具体包括如下步骤:3. The method for suppressing the error of the optical fiber strapdown inertial navigation system based on three-axis rotation according to claim 1, wherein the data generated by the gyroscope after the inertial measurement unit is rotated is converted to the carrier coordinate system to obtain the constant value of the inertial device The modulation form of the deviation specifically includes the following steps: 假定IMU水平方向上的陀螺常值漂移分别为εx和εy。载体静止条件下,由于IMU停顿的A、B、C三个位置相对于导航坐标系对称,因此在一个三轴转位周期内的三个固定位置上,三个陀螺仪常值漂移在导航坐标系上投影引起的姿态角误差必然满足:Assume that the gyro constant drifts in the horizontal direction of the IMU are ε x and ε y , respectively. Under the static condition of the carrier, since the three positions A, B, and C where the IMU stops are symmetrical with respect to the navigation coordinate system, at three fixed positions within a three-axis indexing cycle, the three gyroscope constants drift in the navigation coordinate system Attach the projection The resulting attitude angle error must satisfy: 33 (( ∫∫ 00 TT sthe s ϵϵ xx nno dtdt )) AA ++ 33 (( ∫∫ 00 TT sthe s ϵϵ xx nno dtdt )) BB ++ 33 (( ∫∫ 00 TT sthe s ϵϵ xx nno dtdt )) CC == 00 33 (( ∫∫ 00 TT sthe s ϵϵ ythe y nno dtdt )) AA ++ 33 (( ∫∫ 00 TT sthe s ϵϵ ythe y nno dtdt )) BB ++ 33 (( ∫∫ 00 TT sthe s ϵϵ ythe y nno dtdt )) CC == 00 33 (( ∫∫ 00 TT sthe s ϵϵ zz nno dtdt )) AA ++ 33 (( ∫∫ 00 TT sthe s ϵϵ zz nno dtdt )) BB ++ 33 (( ∫∫ 00 TT sthe s ϵϵ zz nno dtdt )) CC == 00 根据IMU三轴转动方案中的转动存在着转动的对称性问题,忽略载体运动的影响并以当地地理坐标系作为参考,12次序转位方案可以表述为:According to the rotation symmetry problem in the IMU three-axis rotation scheme, ignoring the influence of the carrier motion and taking the local geographic coordinate system as a reference, the 12-order transposition scheme can be expressed as: 过程1:次序1、6、7、12,构成的转动周期内,x、y轴的陀螺仪漂移在导航坐标系oxnyn平面内呈现出正反各一周的变化规律,因此在整周期的积分过程中产生的常值偏差为零,即:Process 1: Sequence 1, 6, 7, 12, within the rotation period formed, the gyroscope drift of the x and y axes presents a positive and negative cycle of change in the navigation coordinate system ox n y n plane, so in the entire cycle The constant deviation produced during the integration of is zero, that is: (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) BB →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; -- BB ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) BB →&Right Arrow; -- AA == 00 (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) AA →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) AA →&Right Arrow; -- BB ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; -- AA == 00 其中,每个转动过程的时间计为Tz,围绕惯性测量单元敏感坐标轴逆时针转动为+,顺时针转动为-。Wherein, the time of each rotation process is counted as T z , counterclockwise rotation around the sensitive coordinate axis of the inertial measurement unit is +, and clockwise rotation is -. 过程2:次序2、5、8、11,构成的转动周期内,y、z轴的陀螺仪漂移在导航坐标系oynzn平面内呈现出正反各一周的变化规律,因此在整周期的积分过程中产生的常值偏差为零,即:Process 2: Sequence 2, 5, 8, 11, within the rotation cycle formed, the gyroscope drift of the y and z axes presents a positive and negative cycle change law in the navigation coordinate system oy n z n plane, so in the whole cycle The constant deviation produced during the integration of is zero, that is: (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) CC →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) BB →&Right Arrow; -- CC ++ (( ∫∫ 00 TT zz ϵϵ ythe y nno dtdt )) CC →&Right Arrow; -- BB == 00 (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) BB →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; ++ BB ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) BB →&Right Arrow; -- CC ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; -- BB == 00 过程3:次序3、4、9、10,构成的转动周期内,x、z轴的陀螺仪漂移在导航坐标系oxnzn平面内呈现出正反各一周的变化规律,因此在整周期的积分过程中产生的常值偏差为零,即:Process 3: Sequences 3, 4, 9, 10, within the rotation cycle formed, the gyroscope drift of the x and z axes presents a positive and negative cycle of change in the navigation coordinate system ox n z n plane, so in the entire cycle The constant deviation produced during the integration of is zero, that is: (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) CC →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) CC →&Right Arrow; -- AA ++ (( ∫∫ 00 TT zz ϵϵ xx nno dtdt )) AA →&Right Arrow; -- CC == 00 (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; ++ AA ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) AA →&Right Arrow; ++ CC ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) CC →&Right Arrow; -- AA ++ (( ∫∫ 00 TT zz ϵϵ zz nno dtdt )) AA →&Right Arrow; -- CC == 00 十二次序转停过程就是周期性的改变捷联矩阵的值,使三个陀螺仪的敏感轴在一个转动周期内沿转动中心对称分布(如附图3)。直观地证明了一个十二次序转停过程中,陀螺仪常值偏差相对导航坐标系被完全调制,对系统的导航精度不产生影响。同理在一个完整的转停周期内,由于三个固定位置及转动过程的对称分布,可以得到惯性测量单元停止及转位过程中加速度计零位偏差在导航坐标系的类似作用效果。The twelve-sequence rotation-stop process is to periodically change the value of the strapdown matrix, so that the sensitive axes of the three gyroscopes are symmetrically distributed along the rotation center within one rotation cycle (as shown in Figure 3). It is proved intuitively that during a twelve-sequence turn-to-stop process, the gyroscope constant value deviation is completely modulated relative to the navigation coordinate system, and has no effect on the navigation accuracy of the system. Similarly, in a complete rotation-stop cycle, due to the symmetrical distribution of the three fixed positions and the rotation process, the similar effect of the zero position deviation of the accelerometer in the navigation coordinate system can be obtained during the stop and indexing process of the inertial measurement unit. 4.根据权利要求1所述的基于三轴旋转的光纤捷联惯导系统误差抑制方法,其特征在于将陀螺仪在IMU坐标系下的输出值
Figure FSA00000768634000055
带入捷联惯性导航系统中,采用等效旋转矢量法对捷联矩阵
Figure FSA00000768634000056
进行更新:
4. the optical fiber strapdown inertial navigation system error suppression method based on three-axis rotation according to claim 1, is characterized in that the output value of the gyroscope under the IMU coordinate system
Figure FSA00000768634000055
Into the strapdown inertial navigation system, using the equivalent rotation vector method to the strapdown matrix
Figure FSA00000768634000056
Make an update:
ωω nsns sthe s == ωω isis sthe s -- (( CC sthe s nno )) TT (( ωω ieie nno ++ ωω enen nno )) 其中:
Figure FSA00000768634000058
为地球自转角速度在导航系下的分量;
Figure FSA00000768634000059
为导航坐标系相对地球坐标系的运动角速度在导航系下的分量;
Figure FSA000007686340000510
为IMU相对导航坐标系的运动角速度在IMU坐标系上的分量。
in:
Figure FSA00000768634000058
is the component of the earth's rotation angular velocity in the navigation system;
Figure FSA00000768634000059
is the component of the motion angular velocity of the navigation coordinate system relative to the earth coordinate system under the navigation system;
Figure FSA000007686340000510
is the component of the angular velocity of the motion of the IMU relative to the navigation coordinate system on the IMU coordinate system.
设IMU坐标系相对导航坐标系的等效旋转矢量微分方程为:Let the equivalent rotation vector differential equation of the IMU coordinate system relative to the navigation coordinate system be: ΦΦ ·&Center Dot; == ωω nsns sthe s ++ 11 22 ΦΦ ×× ωω nsns sthe s ++ 11 1212 ΦΦ ×× (( ΦΦ ×× ωω nsns sthe s )) 根据角速度
Figure FSA000007686340000512
求解出等效的旋转矢量并代替四元数解,
According to angular velocity
Figure FSA000007686340000512
Solve for the equivalent rotation vector and replace the quaternion solution,
qq == coscos ΦΦ 22 ++ ΦΦ || ΦΦ || sinsin ΦΦ 22 由于q=q0+q1i+q2j+q3k,i、j、k为方向向量。因此姿态矩阵
Figure FSA000007686340000514
的更新过程为:
Since q=q 0 +q 1 i+q 2 j+q 3 k, i, j, k are direction vectors. Therefore the attitude matrix
Figure FSA000007686340000514
The update process is:
CC sthe s nno == qq 00 22 ++ qq 11 22 -- qq 22 22 -- qq 33 22 22 (( qq 11 qq 22 -- qq 00 qq 33 )) 22 (( qq 11 qq 33 ++ qq 00 qq 22 )) 22 (( qq 11 qq 22 ++ qq 00 qq 33 )) qq 00 22 -- qq 11 22 ++ qq 22 22 -- qq 33 22 22 (( qq 22 qq 33 -- qq 00 qq 11 )) 22 (( qq 11 qq 33 -- qq 00 qq 22 )) 22 (( qq 22 qq 33 ++ qq 00 qq 11 )) qq 00 22 -- qq 11 22 -- qq 22 22 ++ qq 33 22
5.根据权利要求1所述的基于三轴旋转的光纤捷联惯导系统误差抑制方法,其特征在于利用石英加速度计的输出值
Figure FSA00000768634000061
和步骤(5)计算的姿态矩阵
Figure FSA00000768634000062
计算出经过IMU旋转调制后载体的位置。
5. the optical fiber strapdown inertial navigation system error suppression method based on three-axis rotation according to claim 1 is characterized in that the output value of the quartz accelerometer is utilized
Figure FSA00000768634000061
and the attitude matrix calculated in step (5)
Figure FSA00000768634000062
Calculate the position of the carrier after the IMU rotation modulation.
1)计算导航系下加速度fn1) Calculate the acceleration f n under the navigation system: ff nno == CC sthe s nno ff isis sthe s 2)计算载体的位置:2) Calculate the position of the carrier: 根据t1时刻的载体东向水平速度Vx(t1)和北向水平速度Vy(t1),求取t2时刻载体位置为:According to the carrier's eastward horizontal velocity V x (t 1 ) and northward horizontal velocity V y (t 1 ) at time t 1, the position of the carrier at time t 2 is calculated as: 3)计算载体位置误差:
Figure FSA00000768634000065
3) Calculate the carrier position error:
Figure FSA00000768634000065
其中:
Figure FSA00000768634000066
λ0分别表示初始时刻载体所处位置的经度和纬度;
Figure FSA00000768634000067
Δλ分别表示载体的纬度、经度的变化量;RN、RM分别表示地球子午圈、卯酉圈的曲率半径;t1、t2为惯导系统的解算过程中两个相邻的时间点。
in:
Figure FSA00000768634000066
λ 0 represents the longitude and latitude of the carrier's position at the initial moment, respectively;
Figure FSA00000768634000067
Δλ respectively represent the variation of the latitude and longitude of the carrier; R N and R M represent the curvature radii of the meridian circle and Maoyou circle of the earth respectively; t 1 and t 2 are two adjacent times in the process of inertial navigation system solution point.
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