CN102519715B - Simplified calculation method of bracket strength of nuclear power plant - Google Patents

Abstract

The invention relates to a simplified calculation method of the bracket strength of a nuclear power plant. The method comprises the following steps of: splitting a complicated bracket into a simple-structure standard bracket type; reasonably applying a traditional calculation formula to the simplified standard bracket type to respectively calculate the structural strength of connecting points of all split structures; and finally, calculating the root strength to obtain a result for judging whether the whole bracket strength meets the requirement. According to the simplified calculation method provided by the invention, the bracket strength can be manually calculated in a design process, so that other special ports are reduced, an unnecessary repeated modeling calculation process is avoided, and the work efficiency is improved.

Description

A kind of Simplified calculation method of bracket strength of nuclear power plant

Technical field

The present invention relates to a kind of method adjusting support intensity according to known conditions, be specifically related to a kind of Simplified calculation method of bracket strength of nuclear power plant.

Background technology

In nuclear power engineering, number of tubes is large, kind is many, and under the operating mode being operated in various complexity, need meet the designing requirement of strength and stiffness under different operating mode as the support of pipeline support equally.Conventional power plant support compared by nuclear power support has own characteristic again, selection standard support fewer, and majority is designed to special support, and structure type is complicated, in layout and design stent procedures, grasps pipe-hanger support Strength co-mputation knowledge and is very important.

At present, support intensity computing method can adopt microcomputer modelling to calculate, its detailed process:

(1) support Design person puies forward the Mechanics Calculation data of support to mechanics group, the information such as the stress condition of the construction profile comprising this support, the structured material selected, cradling function, support.

(2), after Mechanics Calculation group receives and puies forward money condition, start to set up stent model on computers according to known conditions, working procedure obtains result of calculation, finally extracts result.

(3) judge whether result of calculation meets the requirement of support intensity, just result of calculation directly can be returned to deviser if met, not meeting then needs to consult with support Design person.The underproof support of intensity need after deviser's amendment, then the repetitive process through step (1) and (2), until obtain the result of calculation be satisfied with.

By the intensity of this workflow management support, not only workload is large, takes time and effort, also will be subject to the restriction of work place, computer applied algorithm simultaneously, only just adopts this account form to supporting structure complicated especially in actual applications.

Summary of the invention

The object of the invention is to the defect calculating support intensity cycle length for existing computer, a kind of simplified calculation method of nuclear power station support intensity is provided, thus avoids unnecessary repetition Modeling Calculation process, improve counting yield.

For achieving the above object, the technical solution used in the present invention is as follows: a kind of Simplified calculation method of bracket strength of nuclear power plant, comprises the steps:

(1) load that support bears is determined;

(2) function performed by support is determined;

(3) supporting construction of support is split one or more being reduced to following simple structure type,

Class1: one end is fixed, the yi word pattern support of one end activity;

Type 2: one end is fixed, the L-type support of one end activity;

Type 3: the L-type support that two ends are all fixed;

Type 4: the door shaped stent that two ends are all fixed;

Type 5: the yi word pattern support that two ends are all fixed;

(4) respectively according to the computing formula of the simple structure type support in step (3), the force and moment of the supporting structure junction after simplification is calculated;

(5) the maximum cross-section stress at each primary attachment point place on the supporting structure after computational short cut;

(6) for the mode that support root adopts crab-bolt and substrate to fix, crab-bolt intensity is calculated; Adopt the mode be welded and fixed for support root, calculate weld stress intensity;

(7) rigidity of structure of support on each constraint direction under strong point place generation displacement condition is calculated.

Further, Simplified calculation method of bracket strength of nuclear power plant as above, in step (3), to the concrete grammar that supporting construction splits be, when single channel-section steel connects with two catching groove steel or H profile steel, take apart from phase contact, for single channel-section steel, joint is stiff end, and component takes root place for stiff end; For the component that intensity in structure is consistent, be considered as a single piece during fractionation, the element joints large with intensity is stiff end, and support takes root place for stiff end.

Beneficial effect of the present invention is as follows: by Simplified calculation method of bracket strength of nuclear power plant provided by the present invention, under limited conditions, the supporting construction of support is split in bounds and be reduced to simple structure type, just manually can calculate support intensity in the design process, decrease the interface with other specialties, avoid unnecessary repetition Modeling Calculation process, improve work efficiency.

Accompanying drawing explanation

Fig. 1-1 to Fig. 1-5 is the structural representation of five kinds of simple structure standard carriage types;

Fig. 2-1 to Fig. 2-8 is the exemplary plot that eight kinds of simple beams split;

Fig. 3-1 to Fig. 3-6 is the mechanical analysis schematic diagram of Class1 rack form;

Fig. 4-1 to Fig. 4-2 is the mechanical analysis schematic diagram of type 2 rack form;

Fig. 5 is the mechanical analysis schematic diagram of type 3 rack form;

Fig. 6 is the mechanical analysis schematic diagram of type 4 rack form;

Fig. 7 is the mechanical analysis schematic diagram of type 5 rack form;

Fig. 8 is the supporting structure schematic diagram of specific embodiment;

Fig. 9-1 to Fig. 9-2 is the force and moment schematic diagram calculation of C point in the support of specific embodiment;

Figure 10-1 to Figure 10-2 is the force and moment schematic diagram calculation of O point in the support of specific embodiment;

Figure 11 is the Stress Check calculating parameter schematic diagram of welded section in the support of specific embodiment;

Figure 12 is the supporting structure Stiffness evaluation calculating parameter schematic diagram of specific embodiment.

Embodiment

Below in conjunction with drawings and Examples, the present invention will be described in detail.

Simplified calculation method of bracket strength of nuclear power plant provided by the present invention, comprises the steps:

(1) load that support bears is determined;

(2) function performed by support is determined; Described function has the combination functions such as GL (guiding trestle), CB and PF function (fixed support), PL function (sliding support), BT function (limiting bracket), PL+BT; Cradling function does not affect the fractionation of support, but to determining whether support bears friction force and play an important role, thus to friction force be considered in subsequent calculations formula;

(3) supporting construction of support is split one or more being reduced to following simple structure type,

Class1: one end is fixed, the yi word pattern support of one end activity; As Figure 1-1;

Type 2: one end is fixed, the L-type support of one end activity; As shown in Figure 1-2;

Type 3: the L-type support that two ends are all fixed; As Figure 1-3;

Type 4: the door shaped stent that two ends are all fixed; As Figure 1-4;

Type 5: the yi word pattern support that two ends are all fixed; As Figure 1-5;

(4) respectively according to the computing formula of the simple structure type support in step (3), the force and moment of the supporting structure junction after simplification is calculated;

(5) the maximum cross-section stress at each primary attachment point place on the supporting structure after computational short cut;

(6) for the mode that support root adopts crab-bolt and substrate to fix, crab-bolt intensity is calculated; Adopt the mode be welded and fixed for support root, calculate weld stress intensity;

(7) rigidity of structure of support on each constraint direction under strong point place generation displacement condition is calculated.

For the support that need carry out strength accounting, before fractionation, first understand the overall structure form of support, and the Strength Changes between adjacent members, if the intensity of two catching groove steel or H profile steel is just much larger than single channel-section steel.Therefore in previous step (3) to the concrete grammar principle that supporting construction splits be:

A (), when single channel-section steel connects with two catching groove steel or H profile steel, take apart from phase contact, for single channel-section steel, joint is stiff end, component takes root place for stiff end, is exemplified below:

As shown in Fig. 2-1, the mode of fractionation is, AB: type 5; OA: Class1.

As shown in Fig. 2-2, the mode of fractionation is, AB: type 5; OA: Class1.

B (), for the consistent component of intensity in structure, be considered as a single piece during fractionation, the element joints large with intensity is stiff end, support takes root place for stiff end, is exemplified below:

As Figure 2-3, the mode of fractionation is, ABP: type 3; OA: Class1.

As in Figure 2-4, the mode of fractionation is, OABP: type 4.

As shown in Figure 2-5, the mode of fractionation is, ABCD: type 4; OP: type 5.

As shown in figures 2-6, the mode of fractionation is, ABC: type 2; OC: Class1; OD: Class1;

Wherein, maximum load is born at C point place.

As illustrated in figs. 2-7, the mode of fractionation is, ABC: type 3; ADO: type 2; CO: Class1.

As illustrated in figs. 2 through 8, the mode of fractionation is, AB: type 2; DBC: type 3;

Wherein, maximum load is born at B point place.

The strength calculation method of five kinds of cantilever type is introduced respectively below in conjunction with example and accompanying drawing.

Class1-one end is fixed, the yi word pattern support of one end activity:

As shown in Fig. 3-1,3-2, in figure, O point is for being welded in the centre of gravity place in shaped steel cross section on substrate, and A point is positioned at shaped steel surface and is the position of L apart from O point length.H is the discrepancy in elevation of A point apart from O point, and J is O point and A point distance in the u-direction.

The load at A point place adopts following mark to carry out defining (force and moments in three directions):

F _U ^AM _U ^A

F _V ^AM _V ^A

F _W ^AM _W ^A

Adopt following general formula to calculate the load at tie point 0 place:

F _U ^O＝F _U ^AM _U ^O＝M _U ^A+F _V ^A.H+F _W ^A.L

F _V ^O＝F _V ^AM _V ^O＝M _V ^A+F _U ^A.H（+F _W ^A.J)

F _W ^O＝F _W ^AM _W ^O＝M _W ^A+F _U ^A.L(+F _V ^A.J)

Class1 .1

As shown in Fig. 3-3, A point place load can obtain from mechanics of piping report calculated book:

F U A

F V A

F W A

M U A

M V A

M W A

PF

≠0

≠0

≠0

≠0

≠0

≠0

According to A point load, support Design person adopts the suffered load of following formulae discovery B point:

F _U ^B＝F _U ^AM _U ^B＝M _U ^A+F _V ^A.H

F _V ^B＝F _V ^AM _V ^B＝M _V ^A+F _U ^A.H

F _W ^B＝F _W ^AM _W ^B＝M _W ^A

The suffered load of existing known B point, if the elevation difference of O point and B point is very little, support Design person can ignore this elevation difference, adopts following formula to calculate the suffered load of O point, and B point is L, A point distance B point length apart from O point length is H:

F _U ^O＝F _U ^BM _U ^O＝M _U ^B+F _W ^B.L＝M _U ^A+F _V ^A.H+F _W ^A.L

F _V ^O＝F _V ^BM _V ^O＝M _V ^B＝M _V ^A+F _U ^A.H

F _W ^O＝F _W ^BM _W ^O＝M _W ^B+F _U ^B.L＝M _W ^A+F _U ^A.L

Class1 .2

As shown in Figure 3-4, A point place load can obtain from mechanics of piping report calculated book:

F U A

F V A

F W A

M U A

M V A

M W A

CB

≠0

≠0

≠0

＝0

＝0

＝0

GL

＝0

≠0

≠0

＝0

＝0

＝0

For guiding trestle (GL), need the suffered force of sliding friction of A point, computing formula is as follows:

${F_W}^A=0.3\sqrt{{\left({F_V}^A\right)}^2+{\left({F_W}^A\right)}^2}$

Support Design person can calculate the suffered load of O point according to the universal calculation equation of type 1; Usually need the elevation difference ignoring O point and A point, A point is L apart from O point length, and computing formula is as follows:

F _U ^O＝F _U ^AM _U ^O＝F _W ^A.L

F _V ^O＝F _V ^AM _V ^O＝0

F _W ^O＝F _W ^AM _W ^O＝F _U ^A.L

Class1 .3

As in Figure 3-5, A point place load can obtain from mechanics of piping report calculated book:

C point friction computing formula is as follows:

F _U ^C＝0.3F _V ^AF _V ^C＝F _V ^A

D point friction computing formula is as follows:

F _U ^D＝0.3F _W ^AF _W ^D＝F _W ^A

The computing formula of the suffered load of B point is as follows:

F _U ^B＝F _U ^CM _U ^B＝F _V ^C.BC

F _V ^B＝F _V ^CM _V ^B＝F _U ^C.BC

According to the load of B, D point, the general formula of type 1 is adopted to calculate the suffered load of O point, D point

The discrepancy in elevation being L, D point and O point apart from O point length is H:

F _U ^O＝F _U ^B+F _U ^D＝0.3F _V ^A+0.3F _W ^A

M _U ^O＝M _U ^B+F _V ^B.H+F _W ^D.L＝F _V ^A(BC+H)+F _W ^A.L

F _V ^O＝F _V ^B＝F _V ^A

M _V ^O＝M _V ^B+F _U ^B.H+F _U ^D.H＝0.3F _V ^A(BC+H)+0.3F _W ^A.H

F _W ^O＝F _W ^D＝F _W ^A

M _W ^O＝F _U ^D.L+F _U ^B.O B＝0.3F _W ^A.L+0.3F _V ^A.OB

Note 1: sliding function support (PL), the computing formula of A point is F _v=0

Note 2: horizontal functional support (BT), pipeline does not contact with D point, therefore A point F _vthe F of=0, C point and B point _w=0.3F _v.

Class1 .4

As seen in figures 3-6, A point place load can obtain from mechanics of piping report calculated book:

F U A

F V A

F W A

M U A

M V A

M W A

GL

＝0

≠0

≠0

＝0

＝0

＝0

If the suffered load of A point vertically downward, the conservative approach of Class1 .3 can be adopted to calculate.When the suffered load of A point straight up time, computing method are as follows:

For E point, E point friction need be considered:

F _W ^E＝F _W ^AF _U ^E＝0.3F _W ^A

B point and G point are divided equally by the additional twisting resistance of E point load generation one and an additional bending moment:

F _W ^B＝F _W ^G＝F _W ^E/2 M _V ^B＝M _W ^G＝F _U ^E.DE/2

Finally, determine that the suffered LOAD FOR formula of B point is as follows:

F _U ^B＝F _U ^C+F _U ^E/2 M _U ^B＝F _V ^C.BC

F _V ^B＝F _V ^CM _V ^B＝F _U ^C.BC+F _U ^E.DE/2

F _w ^b=F _w ^e/ 2 M _w ^bcan ignore

Type 2-one end is fixed, the L-type support of one end activity

As shown in Fig. 4-1, A point place load can obtain from mechanics of piping report calculated book:

F U A

F V A

F W A

M U A

M V A

M W A

PF

≠0

≠0

≠0

≠0

≠0

≠0

According in Class1 .1, B point and C point place load are determined to the describing method of BC beam.

Once the suffered load of B point is determined, support Design person can determine the suffered load of O point according to the universal calculation equation of OB beam in Class1.Computing formula is as follows:

According in Class1 .1, B point and C point place load are determined to the describing method of BC beam.

Once the suffered load of B point is determined, support Design person can determine the suffered load of O point according to the universal calculation equation of OB beam in Class1.B point is apart from the spacing of the discrepancy in elevation that O point length is L, B point and O point to be H, J be C point and B point.Computing formula is as follows:

F _U ^O＝F _U ^AM _U ^O＝M _U ^A+F _V ^A(BC+H)+F _W ^A(AC+J+L)

F _V ^O＝F _V ^AM _V ^O＝M _V ^A+F _U ^A.(BC+H)

F _W ^O＝F _W ^AM _W ^O＝M _W ^A+F _U ^A(AC+J+L)

Type 2.1

As shown in the Fig. 4-2, A point place load can obtain from mechanics of piping report calculated book:

F U A

F V A

F W A

M U A

M V A

M W A

CB

≠0

≠0

≠0

＝0

＝0

＝0

GL

＝0

≠0

≠0

＝0

＝0

＝0

For guiding trestle (GL function), should consider the friction force that A point bears, computing formula is as follows:

${F_U}^A=0.3\sqrt{{\left({F_U}^A\right)}^2+{\left({F_W}^A\right)}^2}$

B point bearing load, need determine according to the computing formula of AB beam in Class1 .2.

Once the suffered load of B point is determined, support Design person can determine the suffered load of O point according to the universal calculation equation of OB beam in type 1.1.B point is apart from the spacing of the discrepancy in elevation that O point length is L, B point and O point to be H, J be C point and B point.Computing formula is as follows:

F _U ^O＝F _U ^AM _U ^O＝F _V ^A(AB+H)+F _W ^A(J+L)

F _V ^O＝F _V ^AM _V ^O＝F _U ^A..AB+H)

F _W ^O＝F _W ^AM _W ^O＝F _U ^A(J+L)

The L-type support that type 3-two ends are fixing

As shown in Figure 5, B point is L apart from O point length,

1. calculate the moment of C point:

A) C point is as follows at the Calculating Torque during Rotary formula in U direction:

C point place is by the F of A point _vproduce

C point place is by the M of A point _uproduce

B) C point is as follows at the Calculating Torque during Rotary formula in V direction:

C point place is by the F of A point _uproduce

C point place is by the M of A point _vmoment=the M produced _v ^a.

C point place is by the M of A point _wthe moment that V direction produces can be ignored.

C) C point is as follows at the Calculating Torque during Rotary formula in W direction:

C point place is by the M of A point _wmoment=the M produced _w ^a.

Note 1: comparatively conservative formula is:

${M_W}^C={F_V}^A\·\frac{\mathrm{AC}.\mathrm{AB}}{{2\mathrm{BC}}^2}\·(\mathrm{AB}+\mathrm{BC}-\frac{\mathrm{AC})}{1+K}$ Wherein $K=\frac{\mathrm{BC}.I_{\mathrm{OB}}}{L.I_{\mathrm{BC}}}$

Note 2: $\mathrm{\α}=\frac{\mathrm{OB}.E.I_{\mathrm{BC}}}{\mathrm{BC}.G.J_{\mathrm{OB}}},\mathrm{\β}=\frac{{\mathrm{OB}}^3.I_{\mathrm{BC}}}{{\mathrm{BC}}^3.I_{\mathrm{OB}}}$

I _oBfor the moment of inertia of beam OB;

I _bCfor the moment of inertia of beam BC;

J _oBfor the torsional moment of inertia of beam OB;

E is Young modulus;

G is modulus of shearing=E/2.6;

2. calculate the moment of B point:

A) B point is as follows at the Calculating Torque during Rotary formula in U direction:

B point place is by the F of A point _vproduce

B point place is by the M of A point _uproduce

wherein $K=\frac{\mathrm{BC}.I_{\mathrm{OB}}}{L.I_{\mathrm{BC}}}$

B) B point is as follows at the Calculating Torque during Rotary formula in V direction:

B point place is by the F of A point _uproduce

B point place is by the M of A point _vproduce

Wherein: $\mathrm{\α}=\frac{\mathrm{OB}.E.I_{\mathrm{BC}}}{\mathrm{BC}.G.J_{\mathrm{OB}}},\mathrm{\β}=\frac{{\mathrm{OB}}^3.I_{\mathrm{BC}}}{{\mathrm{BC}}^3.I_{\mathrm{OB}}}$

C) B point is as follows at the Calculating Torque during Rotary formula in W direction:

B point place is by the M of A point _wproduce

3. calculate the moment of O point:

A) O point is as follows at the Calculating Torque during Rotary formula in U direction:

O point place is by the F of A point _vproduce

O point place is by the M of A point _uproduce

wherein $K=\frac{\mathrm{BC}.I_{\mathrm{OB}}}{L.I_{\mathrm{BC}}}$

B) O point is as follows at the Calculating Torque during Rotary formula in V direction:

O point place is by the F of A point _uproduce

O point place is by the M of A point _vproduce

Wherein: $\mathrm{\α}=\frac{\mathrm{OB}.E.I_{\mathrm{BC}}}{\mathrm{BC}.G.J_{\mathrm{OB}}},\mathrm{\β}=\frac{{\mathrm{OB}}^3.I_{\mathrm{BC}}}{{\mathrm{BC}}^3.I_{\mathrm{OB}}}$

C) O point is as follows at the Calculating Torque during Rotary formula in W direction:

O point place is by the M of A point _wproduce

O point place is by the M of A point _vproduce

O point place is by the F of A point _uproduce

4. calculate the power of B, C, O point:

A) B, C, O point is as follows in the power computing formula in U direction:

B, C, O point place is by the F of A point _upower≤the F produced _u ^a

O point (not comprising B, C point) place is by the M of A point _wproduce

B, C, O point place is by the M of A point _vproduce

B) B, C, O point is as follows in the power computing formula in V direction:

B, C, O point place is by the F of A point _vpower≤the F produced _v ^a

B, C, O point place is by the M of A point _uproduce

Wherein: $\mathrm{\α}=\frac{\mathrm{BC}.I_{\mathrm{OB}}}{L.I_{\mathrm{BC}}}$

C) B, C, O point is as follows in the power computing formula in W direction:

C point (not comprising B, O point) place is by the F of A point _wpower≤the F produced _w ^a

The door shaped stent that type 4-two ends are fixing

As shown in Figure 6, B point is L, C point distance P point length apart from O point length is L,

1. calculate the moment of B point:

A) B point is as follows at the Calculating Torque during Rotary formula in U direction:

B point place is by the F of A point _vmoment≤the 20%F produced _v ^a.AB

B point place is by the F of A point _wmoment≤the 25%F produced _w ^a.L

B point place is by the M of A point _uproduce wherein

B) B point is as follows at the Calculating Torque during Rotary formula in V direction:

B point place is by the F of A point _uproduce

(see note 2)

B point place is by the M of A point _vproduce

(see note 2)

C) B point is as follows at the Calculating Torque during Rotary formula in W direction:

B point place is by the M of A point _wproduce

Note 1: only AC in above-mentioned formula need be replaced with AB when calculating the moment at C point place, AB replaces with AC

Note 2: wherein: $\mathrm{\α}=\frac{\mathrm{OB}.E.I_{\mathrm{BC}}}{\mathrm{BC}.G.J_{\mathrm{OB}}},\mathrm{\β}=\frac{{\mathrm{OB}}^3.I_{\mathrm{BC}}}{{\mathrm{BC}}^3.I_{\mathrm{OB}}}$

I _obfor the moment of inertia of beam OB;

I _bCfor the moment of inertia of beam BC;

J _oBfor the torsional moment of inertia of beam OB;

E is Young modulus;

G is modulus of shearing=E/2.6;

2. calculate the moment of O point:

A) O point is as follows at the Calculating Torque during Rotary formula in U direction:

O point place is by the F of A point _vmoment≤the 10%F produced _v ^a.AB

O point place is by the F of A point _wmoment≤the 35%F produced _w ^a.L

O point place is by the M of A point _umoment≤the 35%M produced _u ^a

Note: actual value is: $\frac{{\mathrm{AB}}^2(6K+12)+2\mathrm{AB}.L(3K-5)-L^2(5K-1)}{{2L}^2(K+2)(6K+1)}$

Wherein: $K=\frac{\mathrm{BC}.I_{\mathrm{OB}}}{L.I_{\mathrm{BC}}}$

B) O point is as follows at the Calculating Torque during Rotary formula in V direction:

O point is by the M of A point _vthe moment produced is less than or equal to B point Moment.

O point is by the F of A point _uthe moment produced is less than or equal to B point Moment

C) O point is as follows at the Calculating Torque during Rotary formula in W direction:

O point place is by the M of A point _wproduce

O point place is by the M of A point _vproduce (see note 2)

O point place is by the F of A point _umoment≤the F produced _u ^a.L (see note 3)

Note 1: only AC in above-mentioned formula need be replaced with AB when calculating the moment at P point place, AB replaces with AC.

Note 2: Conservative estimation formula is: ${M_V}^A\·\frac{1}{\mathrm{BC}}(1+\frac{2(1+4\mathrm{\β}){\mathrm{BC}}^2-{3\mathrm{AB}}^2-{3\mathrm{AC}}^2}{\mathrm{BC}(1+6\mathrm{\α}+8\mathrm{\β})}$

Note 3: Conservative estimation formula is: ${F_U}^A\·\frac{L}{\mathrm{BC}}(\mathrm{AC}+\frac{(\mathrm{AC}-\mathrm{AB})(\mathrm{AC}.\mathrm{AB}+4\mathrm{\β}{\mathrm{BC}}^2)}{\mathrm{BC}(1+6\mathrm{\α}+8\mathrm{\β})}$

3. calculate the power of B, O point:

A) B, O point is as follows in the power computing formula in U direction:

B, O point place is by the F of A point _upower≤the F produced _u ^a

B, O point place is by the M of A point _wproduce

B, O point place is by the M of A point _vproduce (see bet 2)

B) B, O point is as follows in the power computing formula in V direction:

B, O point place is by the F of A point _vpower≤the F produced _v ^a

B, O point place is by the M of A point _uproduce

C) B, O point is as follows in the power computing formula in W direction:

B, O point place is by the F of A point _wpower≤the F produced _w ^a/ 2

O point (not comprising B point) place is by the F of A point _vpower≤the 40%F produced _v ^a

Note 1: only AC in above-mentioned formula need be replaced with AB when calculating the moment at P point and C point place, AB replaces with AC.

Note 2: by M _vthe power produced, its Conservative estimation formula is:

$\frac{{M_V}^A}{\mathrm{BC}}+\frac{{M_V}^A}{{\mathrm{BC}}^3}\left(\frac{{2\mathrm{BC}}^2-{3\mathrm{AB}}^2-{3\mathrm{AC}}^2}{1+6\mathrm{\α}}\right)$ Wherein $\mathrm{\α}=\frac{\mathrm{OB}.E.I}{\mathrm{BC}.G.J}$

Wherein: I is moment of inertia;

E is Young modulus;

G is modulus of shearing=E/2.6;

J is torsional moment of inertia.

The yi word pattern support that type 5-two ends are fixing

As shown in Figure 7,

1. calculate the moment of O point:

A) O point is as follows at the Calculating Torque during Rotary formula in U direction:

O point place is by the F of A point _wproduce

O point place is by the M of A point _uproduce

Minimum value is: 10%M _u ^a

B) O point is as follows at the Calculating Torque during Rotary formula in V direction:

O point place is by the M of A point _vproduce

C) O point is as follows at the Calculating Torque during Rotary formula in W direction:

O point place is by the M of A point _wproduce

Minimum value is: 10%M _w ^a

O point place is by the F of A point _uproduce

Note 1:F _vthe square produced can be ignored.

Note 2: only OA in above-mentioned formula need be replaced with AB when calculating the moment at B point place, AB replaces with OA.

2. calculate the power of O point:

A) O point is as follows in the computing formula of U direction force:

O point place is by the F of A point _uproduce

O point place is by the M of A point _uproduce

B) O point is as follows in the power computing formula in V direction:

O point place is by the F of A point _vproduce

C) O point is as follows in the power computing formula in W direction:

O point place is by the F of A point _wproduce

O point place is by the M of A point _wproduce

Note: calculate stressed of B point place and OA in above-mentioned formula need be replaced with AB, AB replaces with OA.

On the basis of the strength calculation method of above-mentioned five kinds of cantilever type, below in conjunction with specific embodiment, the present invention is further detailed explanation.

Embodiment

For being total to frame support shown in Fig. 8, performed function is GL function.The stressing conditions obtaining this support from mechanics of piping report calculated book is as follows: F1=11763N; F2=1704N; F3=4225N; F4=4980N.

This support is checked according to method for splitting presented hereinbefore and computing formula.

Friction force suffered by this support is:

Friction1＝0.3*F1+0.3*0.5*F2＝4163N

Friction2＝0.3*F2+0.3*0.5*F4＝1258N

The first step, check C Dian Chu cross section and whether meet the demands:

As shown in Fig. 9-1,9-2, first neglect AB part part, BC parts considered by type 1, calculate the force and moment at C point place:

X-direction: the shearing=Friction1+Friction2=4163+1258=5421N at C point place

Moment: Mx=F1*360+F2*590=5240040N.mm

Y-direction: the shearing=F1+F2=11763+1704=13467N at C point place

Moment: My=Friction1*360+Friction2*590=2240900N.mm

Y-direction: the pulling force=0.5*(F3+F4 at C point place)=0.5* (4225+4980)=4603N

Moment: Mz=0

Calculate the cross section property at C point place

Sectional area: S=2170+1400=3570mm ²

Section modulus: $\mathrm{Wy}=60580+\frac{{10*140}^3}{12*70}=93247{\mathrm{mm}}^3$

Section modulus: $\mathrm{Wx}=\frac{160*{70}^3-141*{59}^3}{12\×35}=61718{\mathrm{mm}}^3$

Section modulus: Wz=2*5.5*150.5*65.5=108435mm ³

Calculate the stress at C point place

Be aware of the counter load that is subject in C point place and section modulus, the section stress at C point place can be calculated.

C Dian Chu cross section meets stress requirement in sum.

Second step, check O point in structure and whether meet the demands:

As shown in Figure 10-1,10-2, calculate force and moment:

Pulling force: Fz=F3+F4=4225+4980=9205N

Shearing: Fc=F1+F2+0.3* (F1=F2+F3+F4)=20269N

Calculate X-direction moment:

Mox＝Mc+(F1+F2+0.5*F3+0.5*F4)*229＝4137801N.mm

Moy＝Friction1*500+Friction2*730＝2999840N.mm

Moz＝(Friction1+Friction2)*229＝1241409N.mm

Check the section stress of beam BO:

Section modulus: $\mathrm{Wx}=\frac{160*{140}^3-141*{129}^3}{12*70}={162330\mathrm{mm}}^3$

Section modulus: $\mathrm{Wz}=\frac{140*{160}^3-129*{141}^3}{12*80}={220650\mathrm{mm}}^3$

Section modulus: Wy=2*5.5*150.5*134.5=22665mm ³

Calculate the stress at O point place:

Drawing stress: $\frac{\mathrm{Mx}}{\mathrm{Wx}}=\frac{4137801}{162330}=26\mathrm{MPa}$

Shear stress: $\frac{\mathrm{My}}{\mathrm{Wy}}=\frac{2999840}{22665}=132\mathrm{MPa}$

Drawing stress: $\frac{\mathrm{Mz}}{\mathrm{Wz}}=\frac{1241409}{220650}=6\mathrm{MPa}$

O Dian Chu cross section meets stress requirement in sum.

3rd step: the Stress Check of welded section:

As shown in figure 11,

Section modulus: $\mathrm{Wx}=\frac{{2*7*530}^3}{12*265}=655433{\mathrm{mm}}^3$

Section modulus: $\mathrm{Wy}=\frac{530\×({174}^3-{160}^3)}{12*87}=594993{\mathrm{mm}}^3$

Section modulus: Wz=2*530*7 ²=51940mm ³

Stress:

Drawing stress: $\frac{\mathrm{Mx}}{\mathrm{Wx}}=\frac{4137801}{655433}=6\mathrm{MPa}$

Drawing stress: $\frac{\mathrm{My}}{\mathrm{Wy}}=\frac{2999840}{594993}=5\mathrm{MPa}$

Shear stress: $\frac{\mathrm{Mz}}{\mathrm{Wz}}=\frac{1241409}{51940}=24\mathrm{MPa}$

${\mathrm{\σ}}_R=\sqrt{{{\mathrm{\σ}}_T}^2+{{\mathrm{\σ}}_T}^2}\≤125\mathrm{MPa},$ Weld seam meets the demands.

4th step, check the load suffered by bolt:

Pulling force: $F_t=\frac{F_X}{4}+\left|\frac{M_x}{2B}\right|+\left|\frac{M_y}{2A}\right|=\frac{\mathrm{My}}{2*300}+\frac{\mathrm{Mx}}{2*300}+\frac{F3+F4}{4}=14200N$

Shearing: $F_c=\sqrt{{(\frac{|F_1+F_2|}{4}+\frac{\left|M_Z\right|B}{{2A}^2+{2B}^2})}^2+{(\frac{|\mathrm{Friction}1+\mathrm{Friction}2|}{4}+\frac{\left|M_z\right|A}{{2A}^2+{2B}^2})}^2}=5000N$

Design load=sqrt (Ft^2+Fc^2)=15055N α=2 °, this α is less than 60 °, and therefore design load must be less than or equal to the FT in handbook _max. the expansion bolt size selected by this support is P15, checks in P15 and can bear FT in suspension and support hand _maxfor 21000N, design load (15055N) <FT _max(21000N), therefore the selection of expansion bolt meets the demands.

5th step, check supporting structure rigidity:

Stiffness evaluation, as shown in figure 12,

$K=\frac{48\sqrt{5}{\mathrm{EI}}_{\mathrm{BC}}}{{\mathrm{BC}}^3}=\frac{48\sqrt{5}\&times;210000\&times;1420384}{{825}^3}\&ap;57000N/\mathrm{mm}$

6 " rigidity value of pipeline is 20000N/mm, and calculate gained K>20000N/mm, therefore rigidity value meets design requirement.

Check step by above five steps, finally can confirm that the design of this support is reasonable.

The Simplified calculation method of bracket strength that inventing provides has practical engineering background, whole computation process is caused by the complicated loaded down with trivial details computation process of the support intensity of the actual generation of engineering, and completing that a large amount of support intensity adjusts at short notice is accurately the most fundamental driving force that the present invention studies.The present invention is on the basis of labor Problems feature, complicated support is split, then traditional calculating formula is rationally applied in the standard carriage type of simplification, adjust the structural strength of each fractionation structural attachment point respectively, finally adjust root intensity, thus obtain the method whether whole support intensity meet the demands, successfully solve nuclear power engineering support intensity computational problem.

Obviously, those skilled in the art can carry out various change and modification to the present invention and not depart from the spirit and scope of the present invention.Like this, if belong within the scope of the claims in the present invention and equivalent technology thereof to these amendments of the present invention and modification, then the present invention is also intended to comprise these change and modification.

Claims (2)

1. a Simplified calculation method of bracket strength of nuclear power plant, comprises the steps:

(1) load that support bears is determined;

(2) function performed by support is determined;

(3) supporting construction of support is split one or more being reduced to simple structure type, the concrete grammar split is: when single channel-section steel connects with two catching groove steel or H profile steel, take apart, for single channel-section steel from phase contact, joint is stiff end, and component takes root place for stiff end; For the component that intensity in structure is consistent, be considered as a single piece during fractionation, the element joints large with intensity is stiff end, and support takes root place for stiff end;

(4) respectively according to the computing formula of the simple structure type support in step (3), the force and moment of the supporting structure junction after simplification is calculated;

(5) the maximum cross-section stress at each primary attachment point place on the supporting structure after computational short cut;

(6) for the mode that support root adopts crab-bolt and substrate to fix, crab-bolt intensity is calculated; Adopt the mode be welded and fixed for support root, calculate weld stress intensity;

(7) rigidity of structure of support on each constraint direction under strong point place generation displacement condition is calculated.

2. Simplified calculation method of bracket strength of nuclear power plant as claimed in claim 1, is characterized in that: the simple structure type described in step (3) comprises:

Class1: one end is fixed, the yi word pattern support of one end activity;

Type 2: one end is fixed, the L-type support of one end activity;

Type 3: the L-type support that two ends are all fixed;

Type 4: the door shaped stent that two ends are all fixed;

Type 5: the yi word pattern support that two ends are all fixed.