CN102186213B - Uplink wireless resource management method based on isomeric relay wireless network framework - Google Patents

Uplink wireless resource management method based on isomeric relay wireless network framework Download PDF

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CN102186213B
CN102186213B CN2011101154709A CN201110115470A CN102186213B CN 102186213 B CN102186213 B CN 102186213B CN 2011101154709 A CN2011101154709 A CN 2011101154709A CN 201110115470 A CN201110115470 A CN 201110115470A CN 102186213 B CN102186213 B CN 102186213B
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portable terminal
subcarrier
expression
speed
via node
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CN102186213A (en
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韩霄
陈惠芳
谢磊
王匡
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Zhejiang University ZJU
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Zhejiang University ZJU
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    • Y—GENERAL TAGGING OF NEW TECHNOLOGICAL DEVELOPMENTS; GENERAL TAGGING OF CROSS-SECTIONAL TECHNOLOGIES SPANNING OVER SEVERAL SECTIONS OF THE IPC; TECHNICAL SUBJECTS COVERED BY FORMER USPC CROSS-REFERENCE ART COLLECTIONS [XRACs] AND DIGESTS
    • Y02—TECHNOLOGIES OR APPLICATIONS FOR MITIGATION OR ADAPTATION AGAINST CLIMATE CHANGE
    • Y02D—CLIMATE CHANGE MITIGATION TECHNOLOGIES IN INFORMATION AND COMMUNICATION TECHNOLOGIES [ICT], I.E. INFORMATION AND COMMUNICATION TECHNOLOGIES AIMING AT THE REDUCTION OF THEIR OWN ENERGY USE
    • Y02D30/00—Reducing energy consumption in communication networks
    • Y02D30/70—Reducing energy consumption in communication networks in wireless communication networks

Abstract

The invention relates to an uplink wireless resource management method based on an isomeric relay wireless network framework. The method comprises the following steps of: firstly, selecting an idled mobile terminal e as a relay node; secondly, determining the speed rate and the power of a first hop of a relay link; thirdly, allocating subcarriers to all mobile stations (MS) by a base station (BS); and finally, allocating power to all subcarriers based on a water injection principle. By the method, system resources can be fairly and efficiently utilized, the performance such as throughput, interrupt probability and the like of a system are improved.

Description

Ascending wireless resource management method based on isomery trunked radio network system architecture
Technical field
The invention belongs to the mobile wireless network technical field, be specifically related to a kind of ascending wireless resource management method based on isomery trunked radio network system architecture.
Background technology
Along with the development of wireless multimedia communication, the particularly at a high speed professional development such as real-time video communication proposes more and more higher requirement to speed and the reliability of system.This supports so high speed and the requirement of reliability with regard to meaning the technology that renewal need to be arranged.Yet traditional cellular network possibly can't satisfy above demand.Therefore, OFDM access (Orthogonal Frequency Division Multiple Access, OFDMA) technology and relaying technique are introduced into radio communication.
Frequency selective fading is a subject matter in the radio communication.In the multicarrier multi-access systems, (Mobile Station, MS) is the subcarrier of deep fade for certain portable terminal, may decline very little for another one MS.OFDMA is exactly a kind of of multicarrier multi-access technology.In the OFDMA technology, each MS can the selective channel condition preferably subchannel carry out transfer of data, because the independence of channel fading between MS, thereby guaranteed that each subcarrier is all used by the more excellent MS of respective channels condition, obtained the multi-user diversity gain on the frequency, so just can satisfy better the service quality (Quality of Service, QoS) of MS.
Relaying has its special advantage as a core technology of the 4th third-generation mobile communication (Fourth Generation, 4G).In cellular system, introduce relaying, can improve transmission rate and reliability, increase the area coverage of residential quarter, and can improve the service quality of edge customer.Relaying technique can be divided into relaying and the outer relaying of band in the band.The former can be described as again cooperating relay, its can be under the prerequisite that does not increase antenna the implementation space diversity, but because its half-duplex characteristic can be lost spectrum efficiency.Being with outer relaying can be called the isomery relaying again, is to utilize the out-of-band frequency resource of cellular network to carry out relaying.Therefore, the performance such as system throughput and outage probability can be greatly improved.
The isomery relaying technique is integrated in the cellular OFDM A network, will be a technology that has prospect.Yet, also do not have up to now the work of this respect.In addition, because after introducing the isomery relaying, traditional radio resource management method will be no longer applicable, therefore how under the prerequisite that guarantees certain fairness, by system resource is distributed, be a technical problem that further needs solution thereby improve throughput of system.
Summary of the invention
The present invention is directed to the deficiency on the prior art, proposed a kind of ascending wireless resource management method based on isomery trunked radio network system architecture.The applied system architecture of this ascending wireless resource management method is based on the OFDMA network and the Ad Hoc network of OFDMA network bands outer (it is outer to be called for short band).
Isomery trunked radio network system architecture among the present invention is based on OFDMA network and the outer Ad Hoc network of band, and in this network system architecture, MS is bimodulus, and they have the wave point of OFDMA and Ad Hoc network.Need the MS of transport service can select idle MS to assist it to communicate as its via node.Like this, needing has just had 2 up links between the MS of transport service and base station (Base Station, the BS): need the MS of transport service and BS by the direct communication of OFDMA network, this is direct connected link; Need the MS of transport service to continue therein and communicate by letter with BS under the assistance of node, this is repeated link, and first between MS and its via node jumped and communicate by letter is by with outer Ad Hoc network, and it is by the OFDMA network that via node is communicated by letter with the second jumping between the BS.
In the isomery trunked radio network system architecture in the present invention, have a BS and MIndividual MS, the set expression of MS is , wherein need the MS of transport service to have FIndividual, be expressed as
Figure 604659DEST_PATH_IMAGE002
, idle MS has EIndividual, be expressed as
Figure 2011101154709100002DEST_PATH_IMAGE003
The total bandwidth of OFDMA network is B, the subcarrier number in the network is K, be expressed as
Figure 502821DEST_PATH_IMAGE004
The total bandwidth of Ad Hoc network is B '
For above-mentioned isomery trunked radio network system architecture, the present invention proposes a kind of ascending wireless resource management method of low complex degree, may further comprise the steps:
Step (1) is worked as portable terminal fWhen needing transport service, at first need to select idle portable terminal eAs via node, concrete grammar is as follows:
(a) portable terminal fSend " relay request " message, " relay request " message described here comprises it to the distance of BS, uses
Figure 2011101154709100002DEST_PATH_IMAGE005
Expression.
(b) after idle portable terminal is received " relay request " message, according to oneself distance to the base station
Figure 707537DEST_PATH_IMAGE006
, delay a period of time sends relaying again and replys message; Distance
Figure 827809DEST_PATH_IMAGE006
Be divided into L interval, section time of delay that each interval is corresponding above-mentioned.To the nearer portable terminal of base station distance, time of delay is shorter, so just can choose the idle portable terminal nearest from the base station as via node.
(c) portable terminal of transmission " relay request " message fReceive idle portable terminal eFirst " relaying answer " after, just broadcast " relaying selected " information, notify idle portable terminal e, portable terminal fSelected it as via node, and notify other idle portable terminal need not wait for again portable terminal fFinished relay selection.With
Figure 2011101154709100002DEST_PATH_IMAGE007
The indication of expression relay selection, when
Figure 965529DEST_PATH_IMAGE007
=1 o'clock, the expression portable terminal fSelected idle portable terminal eAs its via node; When
Figure 381729DEST_PATH_IMAGE007
=0 o'clock, the expression portable terminal fDo not select idle portable terminal eAs its via node.
Step (2) is determined speed and the power that repeated link first is jumped, and concrete grammar is as follows:
(d) for portable terminal of one group of MS( fAnd corresponding via node e) first jump (first jumping and refer to here: from needing the portable terminal of transport service fBy Ad Hoc network, to its corresponding via node eLink), use
Figure 401638DEST_PATH_IMAGE008
Represent the interference of other MS group.Wherein, F 'Expression is except portable terminal fIn addition, other needs the portable terminal of transport service, E 'Expression F 'Corresponding via node,
Figure 2011101154709100002DEST_PATH_IMAGE009
Expression is except portable terminal fIn addition, other needs the portable terminal of transport service F 'Arrive fVia node eChannel power gain, The expression portable terminal F 'At Ad Hoc network to its via node E 'Transmitting power.
Suppose not have the interference of other MS group, namely
Figure 2011101154709100002DEST_PATH_IMAGE011
, and the hypothesis portable terminal fRepeated link first speed of jumping Equal the targeted rate upper limit
Figure 2011101154709100002DEST_PATH_IMAGE013
, by the Shannon rate equation
Figure 308524DEST_PATH_IMAGE014
, obtain portable terminal fTo its via node eTransmission power level
Figure 2011101154709100002DEST_PATH_IMAGE015
, wherein
Figure 487832DEST_PATH_IMAGE016
Be fArrive eChannel power gain,
Figure 2011101154709100002DEST_PATH_IMAGE017
It is the power spectral density of white Gaussian noise.
If
Figure 215486DEST_PATH_IMAGE015
Be less than or equal to portable terminal fMaximum in Ad Hoc network available horsepower
Figure 124536DEST_PATH_IMAGE018
, then
Figure 131806DEST_PATH_IMAGE015
Constant, and
Figure 595148DEST_PATH_IMAGE012
Just equal
Figure 470701DEST_PATH_IMAGE013
If
Figure 968678DEST_PATH_IMAGE015
Greater than portable terminal fMaximum in Ad Hoc network available horsepower
Figure 632003DEST_PATH_IMAGE018
, then order Equal
Figure 261884DEST_PATH_IMAGE018
, and bring the Shannon rate equation into
Figure 2011101154709100002DEST_PATH_IMAGE019
, obtain
Figure 20893DEST_PATH_IMAGE012
(e) successively other MS group is also carried out the operation same with step (d), need the portable terminal of transport service thereby drawn all fTo its via node eTransmission power level
Figure 229020DEST_PATH_IMAGE020
(f) to all MS groups, remove in the step (d)
Figure 666955DEST_PATH_IMAGE011
Hypothesis, with what draw previously
Figure 8943DEST_PATH_IMAGE020
, the substitution formula
Figure 215934DEST_PATH_IMAGE008
, just tried to achieve interference value
Figure 2011101154709100002DEST_PATH_IMAGE021
Still think its speed
Figure 860542DEST_PATH_IMAGE012
Equal
Figure 785772DEST_PATH_IMAGE013
, then by the Shannon rate equation
Figure 416605DEST_PATH_IMAGE022
, obtain power
Figure 274840DEST_PATH_IMAGE015
If Be less than or equal to portable terminal fMaximum in Ad Hoc network available horsepower
Figure 706138DEST_PATH_IMAGE018
, then
Figure 900183DEST_PATH_IMAGE015
Constant, and
Figure 81766DEST_PATH_IMAGE012
Just equal
Figure 68176DEST_PATH_IMAGE013
If
Figure 967999DEST_PATH_IMAGE015
Greater than portable terminal fMaximum in Ad Hoc network available horsepower
Figure 940634DEST_PATH_IMAGE018
, then order
Figure 976723DEST_PATH_IMAGE015
Equal
Figure 134035DEST_PATH_IMAGE018
, and bring the Shannon rate equation into
Figure 2011101154709100002DEST_PATH_IMAGE023
, obtain
Figure 911367DEST_PATH_IMAGE012
(g) repeating step (f) is until all performance numbers of trying to achieve
Figure 281169DEST_PATH_IMAGE020
All no longer changed, perhaps variable quantity less than
Figure 968502DEST_PATH_IMAGE024
Wherein,
Figure 172081DEST_PATH_IMAGE024
A very little value, expression
Figure 780917DEST_PATH_IMAGE015
Variable quantity in twice iteration in front and back.Determine by these , bring the Shannon rate equation into , finally determine the speed that all MS group repeated links first are jumped
Figure 387927DEST_PATH_IMAGE026
Step (3) BS gives each MS allocation of subcarriers, and concrete grammar is as follows:
(h) for KSome subcarriers in the individual subcarrier k, suppose that it has distributed to the portable terminal that needs transport service fDirect connected link, pass through formula
Figure 2011101154709100002DEST_PATH_IMAGE027
, obtain the increment of speed
Figure 887042DEST_PATH_IMAGE028
Wherein,
Figure 2011101154709100002DEST_PATH_IMAGE029
It is portable terminal fThe present rate of direct connected link,
Figure 389698DEST_PATH_IMAGE030
It is portable terminal fObtain current subcarrier kRear direct connected link speed.
Figure 2011101154709100002DEST_PATH_IMAGE031
That subcarrier distributes indication, when
Figure 632461DEST_PATH_IMAGE031
=1 o'clock, the expression subcarrier kDistributed to portable terminal fWhen
Figure 419020DEST_PATH_IMAGE031
=0 o'clock, the expression subcarrier kDo not distribute to portable terminal f
Figure 557877DEST_PATH_IMAGE032
It is portable terminal fAt subcarrier kOn transmitting power.
Figure 2011101154709100002DEST_PATH_IMAGE033
It is portable terminal fArrive BS at subcarrier kOn channel power gain. For capacity difference distance (Capacity gap), can be expressed as
Figure 2011101154709100002DEST_PATH_IMAGE035
, wherein BER is bit error rate.
(i) simultaneously, suppose subcarrier kDistributed to portable terminal eThe portable terminal here eIt is the portable terminal that needs transport service fCorresponding via node.Pass through formula
Figure 859863DEST_PATH_IMAGE036
, obtain the increment of speed
Figure 2011101154709100002DEST_PATH_IMAGE037
Wherein,
Figure 999464DEST_PATH_IMAGE038
It is portable terminal eTo the present rate of BS, the speed of namely repeated link the second jumping.
Figure 2011101154709100002DEST_PATH_IMAGE039
It is portable terminal eObtain current subcarrier kAfter speed.
Figure 840381DEST_PATH_IMAGE040
It is portable terminal eAt subcarrier kOn transmitting power.
Figure 2011101154709100002DEST_PATH_IMAGE041
It is portable terminal eArrive BS at subcarrier kOn channel power gain.
(j) similar above-mentioned two steps, traveling through all needs transport service and does not reach rate-limit
Figure 52050DEST_PATH_IMAGE013
Portable terminal fAnd corresponding via node, find so that the portable terminal of rate increment maximum, namely Or
Figure 2011101154709100002DEST_PATH_IMAGE043
, current subcarrier is distributed to this portable terminal, namely have
Figure 132188DEST_PATH_IMAGE031
=1 or
Figure 144006DEST_PATH_IMAGE044
=1.
Finish current subcarrier kDistribution after, again calculate portable terminal fTotal speed
Figure 2011101154709100002DEST_PATH_IMAGE045
If
Figure 108551DEST_PATH_IMAGE046
, this portable terminal then fCan participate in the distribution of follow-up subcarrier; If
Figure 2011101154709100002DEST_PATH_IMAGE047
, this portable terminal then fNo longer participate in the distribution of follow-up subcarrier.Wherein,
Figure 231228DEST_PATH_IMAGE048
, the expression portable terminal fTotal speed equal direct connected link speed
Figure 348351DEST_PATH_IMAGE029
With repeated link speed sum.And repeated link speed equals repeated link the first hop rate rate
Figure 2011101154709100002DEST_PATH_IMAGE049
With repeated link the second hop rate rate
Figure 531070DEST_PATH_IMAGE038
In, that minimum value
Figure 310808DEST_PATH_IMAGE050
(k) circulate execution in step (h), step (i) and step (j) until all MS reach the targeted rate upper limit always
Figure 112541DEST_PATH_IMAGE013
, perhaps the subcarrier distribution is over, and finishes subcarrier and distributes.
Step (4) distributes power for each subcarrier based on water-filling.Concrete grammar is as follows:
The definition portable terminal mAt subcarrier kOn the channel gain noise ratio be
Figure 2011101154709100002DEST_PATH_IMAGE051
Thereby portable terminal mOptimal power allocation can be expressed as , wherein,
Figure DEST_PATH_IMAGE053
, and horizontal plane
Figure 936327DEST_PATH_IMAGE054
Selection to guarantee
Figure DEST_PATH_IMAGE055
Wherein, The expression portable terminal mThe maximum of available horsepower in the OFDMA network.
The invention has the advantages that: the present invention is directed to isomery trunked radio network system architecture, the corresponding ascending wireless resource management method that has proposed a kind of low complex degree.The method can be utilized the performances such as system resource, the throughput of raising system and outage probability fair, efficiently.
Description of drawings
Fig. 1 is isomery trunked radio network system architecture;
Fig. 2 is the inventive method flow chart.
Embodiment
The invention will be further described below in conjunction with accompanying drawing.Present embodiment is implemented under take technical solution of the present invention as prerequisite, provided detailed execution mode and concrete operating process, but protection scope of the present invention is not limited to following embodiment.
Isomery trunked radio network system architecture as shown in Figure 1, this system architecture in this network system architecture, has a BS and 50 MS based on OFDMA network and the outer Ad Hoc network of band, the set expression of MS is
Figure DEST_PATH_IMAGE057
, wherein need the MS of transport service to have 5, be expressed as , idle MS has 45, is expressed as MS is bimodulus, and they have the wave point of OFDMA and Ad Hoc network.Need the MS of transport service can select idle MS to assist it to communicate as its via node.Like this, needing has just had 2 up links between the MS of transport service and base station (Base Station, the BS): need the MS of transport service and BS by the direct communication of OFDMA network, this is direct connected link; Need the MS of transport service to continue therein and communicate by letter with BS under the assistance of node, this is repeated link, and first between MS and its via node jumped and communicate by letter is by with outer Ad Hoc network, and it is by the OFDMA network that via node is communicated by letter with the second jumping between the BS.The total bandwidth of OFDMA network is 25MHz, and the subcarrier number in the network is 512, is expressed as The total bandwidth of Ad Hoc network is 40MHz.
For above-mentioned isomery trunked radio network system architecture, the present invention proposes a kind of ascending wireless resource management method of low complex degree, as shown in Figure 2, may further comprise the steps:
Step (1) is worked as portable terminal fWhen needing transport service, at first need to select idle portable terminal eAs via node, concrete grammar is as follows:
(a) portable terminal fSend " relay request " message, " relay request " message described here comprises it to the distance of BS, uses
Figure 687672DEST_PATH_IMAGE005
Expression.
(b) after idle portable terminal is received " relay request " message, according to oneself distance to the base station
Figure 973160DEST_PATH_IMAGE006
, delay a period of time sends " relaying answer " message again.Distance is divided into 1000 intervals, each interval corresponding time of delay.To the nearer portable terminal of base station distance, time of delay is shorter, so just can choose the idle portable terminal nearest from the base station as via node.
(c) portable terminal of transmission " relay request " message fReceive idle portable terminal eFirst " relaying answer " after, just broadcast " relaying selected " information, notify idle portable terminal e, portable terminal fSelected it as via node, and notify other idle portable terminal need not wait for again portable terminal fFinished relay selection. The relay selection indication, when
Figure 499136DEST_PATH_IMAGE007
=1 o'clock, the expression portable terminal fSelected idle portable terminal eAs its via node; When
Figure 69926DEST_PATH_IMAGE007
=0 o'clock, the expression portable terminal fDo not select idle portable terminal eAs its via node.
Step (2) is determined speed and the power that repeated link first is jumped, and concrete grammar is as follows:
(d) for portable terminal of one group of MS( fAnd corresponding via node e) first jump (first jumping and refer to here: from needing the portable terminal of transport service fBy Ad Hoc network, to its corresponding via node eLink), use Represent the interference of other MS group.Wherein, F 'Expression is except portable terminal fIn addition, other needs the portable terminal of transport service, E 'Expression F 'Corresponding via node,
Figure DEST_PATH_IMAGE061
Expression is except portable terminal fIn addition, other needs the portable terminal of transport service F 'Arrive fVia node eChannel power gain,
Figure 383412DEST_PATH_IMAGE062
The expression portable terminal F 'At Ad Hoc network to its via node E 'Transmitting power.
Suppose not have the interference of other MS group, namely
Figure 417096DEST_PATH_IMAGE011
, and the hypothesis portable terminal fRepeated link first speed of jumping
Figure 17842DEST_PATH_IMAGE012
Equal the targeted rate upper limit
Figure 12343DEST_PATH_IMAGE013
, by the Shannon rate equation
Figure 356736DEST_PATH_IMAGE014
, obtain portable terminal fTo its via node eTransmission power level
Figure 589135DEST_PATH_IMAGE015
, wherein
Figure 767306DEST_PATH_IMAGE016
Be fArrive eChannel power gain,
Figure 717945DEST_PATH_IMAGE017
It is the power spectral density of white Gaussian noise.In the present embodiment
Figure 131608DEST_PATH_IMAGE013
Be made as 10Mbps, Be made as-174dBm/Hz.
If
Figure 426641DEST_PATH_IMAGE015
Be less than or equal to portable terminal fMaximum in Ad Hoc network available horsepower
Figure 21832DEST_PATH_IMAGE018
, then Constant, and
Figure 446177DEST_PATH_IMAGE012
Just equal
Figure 559627DEST_PATH_IMAGE013
If
Figure 484858DEST_PATH_IMAGE015
Greater than portable terminal fMaximum in Ad Hoc network available horsepower
Figure 115690DEST_PATH_IMAGE018
, then order
Figure 442766DEST_PATH_IMAGE015
Equal
Figure 992696DEST_PATH_IMAGE018
, and bring the Shannon rate equation into
Figure 405223DEST_PATH_IMAGE019
, obtain , in the present embodiment
Figure 270597DEST_PATH_IMAGE018
Be made as 10mW.
(e) successively other MS group is also carried out the operation same with step (d), need the portable terminal of transport service thereby drawn all fTo its via node eTransmission power level
Figure 725849DEST_PATH_IMAGE020
(f) to all MS groups, remove in the step (d)
Figure 891251DEST_PATH_IMAGE011
Hypothesis, with what draw previously
Figure 457362DEST_PATH_IMAGE020
, the substitution formula
Figure 759030DEST_PATH_IMAGE008
, just tried to achieve interference value
Figure 791708DEST_PATH_IMAGE021
Still think its speed
Figure 913248DEST_PATH_IMAGE012
Equal
Figure 814208DEST_PATH_IMAGE013
, then by the Shannon rate equation
Figure 970383DEST_PATH_IMAGE022
, obtain power
Figure 767437DEST_PATH_IMAGE015
If
Figure 530601DEST_PATH_IMAGE015
Be less than or equal to portable terminal fMaximum in Ad Hoc network available horsepower
Figure 438514DEST_PATH_IMAGE018
, then
Figure 980354DEST_PATH_IMAGE015
Constant, and Just equal
Figure 44442DEST_PATH_IMAGE013
If Greater than portable terminal fMaximum in Ad Hoc network available horsepower
Figure 27758DEST_PATH_IMAGE018
, then order
Figure 697774DEST_PATH_IMAGE015
Equal
Figure 281202DEST_PATH_IMAGE018
, and bring the Shannon rate equation into , obtain
Figure 171983DEST_PATH_IMAGE012
(g) repeating step (f) is until all performance numbers of trying to achieve
Figure 481742DEST_PATH_IMAGE020
All no longer changed, perhaps variable quantity less than Wherein,
Figure 137031DEST_PATH_IMAGE024
A very little value, expression Variable quantity in twice iteration in front and back, in the present embodiment Be made as 0.000001mW.Determine by these , bring the Shannon rate equation into , finally determine the speed that all MS group repeated links first are jumped
Step (3) BS gives each MS allocation of subcarriers, and concrete grammar is as follows:
(h) for KSome subcarriers in the individual subcarrier k, suppose that it has distributed to the portable terminal that needs transport service fDirect connected link, pass through formula
Figure 313377DEST_PATH_IMAGE027
, obtain the increment of speed
Figure 383794DEST_PATH_IMAGE028
Wherein,
Figure 779003DEST_PATH_IMAGE029
It is portable terminal fThe present rate of direct connected link,
Figure 999900DEST_PATH_IMAGE030
It is portable terminal fObtain current subcarrier kRear direct connected link speed.
Figure 822363DEST_PATH_IMAGE031
That subcarrier distributes indication, when
Figure 276347DEST_PATH_IMAGE031
=1 o'clock, the expression subcarrier kDistributed to portable terminal fWhen =0 o'clock, the expression subcarrier kDo not distribute to portable terminal f It is portable terminal fAt subcarrier kOn transmitting power.
Figure 668648DEST_PATH_IMAGE033
It is portable terminal fArrive BS at subcarrier kOn channel power gain.
Figure 422977DEST_PATH_IMAGE034
For capacity difference distance (Capacity gap), can be expressed as
Figure 566514DEST_PATH_IMAGE035
, wherein BER is bit error rate, is made as in the present embodiment
Figure DEST_PATH_IMAGE063
10 -3So,
Figure 621057DEST_PATH_IMAGE064
(i) simultaneously, suppose subcarrier kDistributed to portable terminal eThe portable terminal here eIt is the portable terminal that needs transport service fCorresponding via node.Pass through formula , obtain the increment of speed
Figure 449784DEST_PATH_IMAGE037
Wherein,
Figure 724908DEST_PATH_IMAGE038
It is portable terminal eTo the present rate of base station, the speed of namely repeated link the second jumping.
Figure 899537DEST_PATH_IMAGE039
It is portable terminal eObtain current subcarrier kAfter speed.
Figure 234704DEST_PATH_IMAGE040
It is portable terminal eAt subcarrier kOn transmitting power.
Figure 963625DEST_PATH_IMAGE041
It is portable terminal eArrive BS at subcarrier kOn channel power gain.
(j) similar above-mentioned two steps, traveling through all needs transport service and does not reach rate-limit
Figure 448964DEST_PATH_IMAGE013
Portable terminal fAnd corresponding via node, find so that the portable terminal of rate increment maximum, namely
Figure 946942DEST_PATH_IMAGE042
Or
Figure 249747DEST_PATH_IMAGE043
, current subcarrier is distributed to this portable terminal, namely have =1 or
Figure 82891DEST_PATH_IMAGE044
=1.
Finish current subcarrier kDistribution after, again calculate portable terminal fTotal speed
Figure 91167DEST_PATH_IMAGE045
If
Figure 33715DEST_PATH_IMAGE046
, this portable terminal then fCan participate in the distribution of follow-up subcarrier; If
Figure 2808DEST_PATH_IMAGE047
, this portable terminal then fNo longer participate in the distribution of follow-up subcarrier.Wherein,
Figure 423425DEST_PATH_IMAGE048
, the expression portable terminal fTotal speed equal direct connected link speed
Figure 302520DEST_PATH_IMAGE029
With repeated link speed sum.And repeated link speed equals repeated link the first hop rate rate
Figure 415969DEST_PATH_IMAGE049
With repeated link the second hop rate rate
Figure 341200DEST_PATH_IMAGE038
In, that minimum value
Figure 96666DEST_PATH_IMAGE050
(k) circulate execution in step (h), step (i) and step (j) until all MS reach the targeted rate upper limit always
Figure 158163DEST_PATH_IMAGE013
, perhaps the subcarrier distribution is over, and finishes subcarrier and distributes.
Step (4) distributes power for each subcarrier based on water-filling.Concrete grammar is as follows:
The definition portable terminal mAt subcarrier kOn the channel gain noise ratio be Thereby portable terminal mOptimal power allocation can be expressed as
Figure 9368DEST_PATH_IMAGE052
, wherein,
Figure 37367DEST_PATH_IMAGE053
, and horizontal plane
Figure 750108DEST_PATH_IMAGE054
Selection to guarantee
Figure 939781DEST_PATH_IMAGE055
Wherein,
Figure 246129DEST_PATH_IMAGE056
The expression portable terminal mThe maximum of available horsepower in the OFDMA network, in the present embodiment
Figure 812239DEST_PATH_IMAGE056
Be made as 100mW.

Claims (1)

1. based on the ascending wireless resource management method of isomery trunked radio network system architecture, in this isomery trunked radio network system architecture, a base station and M portable terminal are arranged, the set expression of portable terminal is M={m|1,2 ..., M} wherein needs the portable terminal of transport service to have F, is expressed as F={f|1,2 ..., F}, idle portable terminal has E, is expressed as E={e|F+1, F+2, ..., M}; The total bandwidth of OFDMA network is B, and the subcarrier number in the network is K, is expressed as K={k|1,2 ..., K}; The total bandwidth of Ad Hoc network is B ', it is characterized in that the method comprises the steps:
Step (1) at first needs to select idle portable terminal e as via node when portable terminal f needs transport service, and concrete grammar is as follows:
(a) portable terminal f sends relay request message, and described relay request message contains portable terminal f to the distance of base station, uses d F, BSExpression;
(b) after idle portable terminal is received relay request message, according to own arrive the base station apart from d E, BS, delay a period of time sends relaying again and replys message; Apart from d E, BSBe divided into L interval, section time of delay that each interval is corresponding above-mentioned;
(c) after the portable terminal f of transmission relay request message receives that first relaying of idle portable terminal e is replied message, just broadcast a relaying selected message, notify idle portable terminal e, portable terminal f selected it as via node, and notify other idle portable terminal need not wait for again that portable terminal f has finished relay selection; Use s F, eS is worked as in the indication of expression relay selection F, e=1 o'clock, expression portable terminal f selected idle portable terminal e as its via node; Work as s F, e=0 o'clock, expression portable terminal f did not select idle portable terminal e as its via node;
Step (2) is determined speed and the power that repeated link first is jumped, and concrete grammar is as follows:
(d) jump for first of one group of portable terminal, use
Figure FDA00003049302300011
Represent the interference of other portable terminal group; Wherein, f ' represents that other needs the portable terminal of transport service except portable terminal f, via node corresponding to e ' expression f ', | H E, f'| 2Expression is except portable terminal f, and other needs the portable terminal f ' of transport service to the channel power gain of the via node e of f, P F', e'Expression portable terminal f ' is in the transmitting power of Ad Hoc network to its via node e ';
Suppose not have the interference of other portable terminal group, i.e. I f=0, and the speed of repeated link the first jumping of hypothesis portable terminal f
Figure FDA00003049302300021
Equal the targeted rate upper limit By the Shannon rate equation Obtain portable terminal f to the transmission power level of its via node e
Figure FDA00003049302300024
Wherein | H F, e| 2That f is to the channel power gain of e, N 0It is the power spectral density of white Gaussian noise;
If Be less than or equal to portable terminal f in the maximum of Ad Hoc network available horsepower
Figure FDA00003049302300026
Then
Figure FDA00003049302300027
Constant, and Just equal
Figure FDA00003049302300029
If
Figure FDA000030493023000210
Greater than the maximum of portable terminal f in Ad Hoc network available horsepower
Figure FDA000030493023000211
Then order
Figure FDA000030493023000212
Equal
Figure FDA000030493023000213
And bring the Shannon rate equation into R ^ f hop 1 = B ′ log 2 ( 1 + Σ e = F + 1 M s f , e P f AdHoc | H f , e | 2 B ′ N 0 + 0 ) , Obtain
(e) successively other portable terminal group is also carried out the operation same with step (d), need the portable terminal f of transport service to the transmission power level of its via node e thereby drawn all
Figure FDA000030493023000216
(f) to all portable terminal groups, remove I in the step (d) f=0 hypothesis is with what draw previously The substitution formula Just tried to achieve interference value I fStill think its speed
Figure FDA000030493023000219
Equal Then by the Shannon rate equation
Figure FDA000030493023000221
Obtain power
Figure FDA000030493023000222
If
Figure FDA000030493023000223
Be less than or equal to portable terminal f in the maximum of Ad Hoc network available horsepower Then
Figure FDA000030493023000225
Constant, and
Figure FDA000030493023000226
Just equal
Figure FDA000030493023000227
If
Figure FDA000030493023000228
Greater than the maximum of portable terminal f in Ad Hoc network available horsepower Then order
Figure FDA000030493023000230
Equal
Figure FDA000030493023000231
And bring the Shannon rate equation into R ^ f hop 1 = B ′ log 2 ( 1 + Σ e = F + 1 M s f , e P f AdHoc | H f , e | 2 B ′ N 0 + I f ) , Obtain
Figure FDA000030493023000233
(g) repeating step (f) is until all performance numbers of trying to achieve
Figure FDA000030493023000234
All no longer change, perhaps variable quantity is less than Δ; Wherein Δ is a very little value, expression
Figure FDA000030493023000235
Variable quantity in twice iteration in front and back; Determine by these
Figure FDA00003049302300031
Bring the Shannon rate equation into
Figure FDA00003049302300032
The final speed of determining that all portable terminal group repeated links first are jumped
Figure FDA00003049302300033
Each portable terminal allocation of subcarriers is given in step (3) base station, and concrete grammar is as follows:
(h) for the some subcarrier k in K the subcarrier, suppose the direct connected link that subcarrier k has distributed to needs the portable terminal of transport service f, pass through formula ΔR f = R f ′ direct - R f direct = Σ k = 1 K a f , k × B K log 2 ( 1 + P f , k | H f , BS k | 2 Γ N 0 B K ( Σ k = 1 K a f , k + 1 ) ) - Σ k = 1 K a f , k × B K log 2 ( 1 + P f , k | H f , BS k | 2 Γ N 0 B K Σ k = 1 K a f , k ) , Obtain the increment Delta R of speed fWherein,
Figure FDA000030493023000311
The present rate of the direct connected link of portable terminal f,
Figure FDA00003049302300035
That portable terminal f obtains direct connected link speed behind the current subcarrier k, a F, kBe that subcarrier distributes indication, work as a F, k=1 o'clock, expression subcarrier k distributed to portable terminal f; Work as a F, k=0 o'clock, expression subcarrier k did not distribute to portable terminal f, P F, kThe transmitting power of portable terminal f on subcarrier k,
Figure FDA000030493023000312
That portable terminal f is to the channel power gain of BS on subcarrier k; Γ is the capacity difference distance, can be expressed as Γ=-ln (5*BER)/1.6, wherein BER is bit error rate;
(i) simultaneously, suppose that subcarrier k has distributed to portable terminal e; The portable terminal e here is the corresponding via node that needs the portable terminal f of transport service; Pass through formula ΔR e = R e ′ hop 2 - R e hop 2 = Σ k = 1 K a e , k × B K log 2 ( 1 + P e , k | H e , BS k | 2 Γ N 0 B K ( Σ k = 1 K a e , k + 1 ) ) - Σ k = 1 K a e , k × B K log 2 ( 1 + P e , k | H e , BS k | 2 Γ N 0 B K Σ k = 1 K a e , k ) , Obtain the increment Delta R of speed eWherein
Figure FDA00003049302300037
Be portable terminal e to the present rate of BS, repeated link second speed of jumping namely, The speed after portable terminal e obtains current subcarrier k, P E, kThe transmitting power of portable terminal e on subcarrier k,
Figure FDA00003049302300039
That portable terminal e is to the channel power gain of BS on subcarrier k;
(j) traveling through all needs transport service and does not reach rate-limit
Figure FDA000030493023000310
Portable terminal f and corresponding via node, find so that the portable terminal of rate increment maximum, i.e. f=argmax (Δ R f) or e=argmax (Δ R e), current subcarrier is distributed to this portable terminal, a is namely arranged F, k=1 or a E, k=1;
After finishing the distribution of current subcarrier k, again calculate total speed R of portable terminal f fIf
Figure FDA00003049302300041
Then this portable terminal f can participate in the distribution of follow-up subcarrier; If
Figure FDA00003049302300042
Then this portable terminal f no longer participates in the distribution of follow-up subcarrier; Wherein,
Figure FDA00003049302300043
Total speed of expression portable terminal f equals direct connected link speed With repeated link speed sum, and repeated link speed equals repeated link the first hop rate rate
Figure FDA00003049302300045
With repeated link the second hop rate rate In, that minimum value
(k) circulate execution in step (h), step (i) and step (j) until all portable terminals all reach the targeted rate upper limit always Perhaps the subcarrier distribution is over, and finishes subcarrier and distributes;
Step (4) distributes power for each subcarrier based on water-filling, and concrete grammar is as follows:
The channel gain noise ratio of definition portable terminal m on subcarrier k is
Figure FDA00003049302300049
Thereby the optimal power allocation of portable terminal m can be expressed as
Figure FDA000030493023000410
Wherein,
Figure FDA000030493023000411
And the selection of horizontal plane λ will guarantee
Figure FDA000030493023000412
Wherein
Figure FDA000030493023000413
The maximum of expression portable terminal m available horsepower in the OFDMA network.
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