CN102103652A - Space vector equation solving-based three-dimensional line of position calculation method - Google Patents

Space vector equation solving-based three-dimensional line of position calculation method Download PDF

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CN102103652A
CN102103652A CN2010101576424A CN201010157642A CN102103652A CN 102103652 A CN102103652 A CN 102103652A CN 2010101576424 A CN2010101576424 A CN 2010101576424A CN 201010157642 A CN201010157642 A CN 201010157642A CN 102103652 A CN102103652 A CN 102103652A
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transect
localizer
point
cos
leftup
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梁威
梁续军
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CHANGSHA BOWEI SOFTWARE TECHNOLOGY Co Ltd
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CHANGSHA BOWEI SOFTWARE TECHNOLOGY Co Ltd
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Abstract

The invention relates to a space vector equation solving-based three-dimensional line of position calculation method, which is used for calculating lines of position of localizers and transects generated by tomography imaging equipment such as medical radiological imaging examination computed tomographic (CT) equipment, nuclear magnetic resonance examination equipment and the like. The method comprises the following steps of: reading corresponding TAG values by performing digital imaging and communication of medicine (DICOM) file resolution on x, y and z three-dimensional coordinates and three-dimensional angle direction values of planes of the localizer and the transect; judging whether the localizer and the transect can be calculated in a matching way or not according to an Image Type; calculating a plane normal vector equation parameter of a transect image to obtain a plane equation of the transect; calculating points of intersection between a plane Ax+By+Cz+D=0 of the transect image and side lines x-x1/l+y-y1/m+z-z1/n of the localizer respectively, wherein x1, y1 and z1 are the X, Y and Z coordinates of the upper left corner of the localizer respectively, and l, m and n are Cos direction values of direction values X, Y and Z of the first row of the localizer respectively; and if the plane of the transect image is judged to have two points of intersection with the four side lines of the localizer, calculating the points of intersection between a connecting line x-point[i].x]l=y-point[i].y/m=z-point[i].z/n=t of the points of intersection and the four side lines x-x2/A=y-y2/B=z-z2/C of the transect image as the coordinates of a starting point and an ending point of the line of position.

Description

A kind of three-dimensional localization line computation method based on the space vector equation solution
Technical field
The present invention relates to a kind of three-dimensional localization line computation method, relate in particular at medical radioactive image check CT, the locating surface that tomoscan image documentation equipments such as nuclear-magnetism inspection are produced and the position line computing method in cross section based on the space vector equation solution.
Background technology
In medical radioactive image tomoscan checking process, can produce the DICOM form medical image of locating surface (Localizer) and a series of tangent plane (Transect) image at the patient position.
In the DICOM image format, can identify the direction of one group of scan-image by a series of TAG, coordinate position, pixel and physical size mapping ratio, pixel is wide, height, image type (locating surface or cross section etc.), these coordinates, the direction value is at the image locating surface, and the example on the tangent plane is respectively as Fig. 1, and is shown in Figure 2.
The TAG label The Tag title The TAG implication TAG value example
(0020,0032) Image?Position?of Patient The upper left corner X of specify image, Y, Z coordinate -125.0\-132.0\3.5
(0020,0037) Image?Orientation Specify image first row, the direction Cosine value of the relative patient's direction of first row 1.0\0.0\0.0\0.0\1.0\0.0
(0028,0030) Pixel?Spacing The engineer's scale mapping relations of the pairing physical size of pixel and image (millimeter) 0.48828120.4882812
(0028,0010) Rows The number of lines of pixels of image 512
(0028,0011) Columns The pixel columns of image 512
(0008,0008) Image?Type The type of image Localizer,AXIAL
Face the sequence multiple image that the CT computed tomography obtains, the CT scan image is read in the process of sheet the doctor, the doctor need know the exact position of understanding the inspection area correspondence of current observation image slices on locating surface, need find the solution the tangent plane picture location, then need to find the solution its space vector equation, calculate locating surface image and the mutual corresponding position of tangent plane picture, the position line that draws is with auxiliary doctor's diagnostic imaging.
Summary of the invention
The objective of the invention is to set up a kind of three-dimensional localization line computation method, calculate the method for DICOM tomoscan image three-dimensional position line based on the space vector equation solution.
A kind of three-dimensional localization line computation method based on the space vector equation solution comprises following treatment step:
The first step: resolve the DICOM file of input, read the numerical value of following TAG:
The TAG label The Tag title
(0020,0032) Image?Position?of Patient
(0020,0037) Image?Orientation
(0028,0030) Pixel?Spacing
(0028,0010) Rows
(0028,0011) Columns
(0008,0008) Image?Type
And obtain the upper left corner X of current image, Y, Building Z mark by resolving Image Position Of Patient; Obtain current image first row, the direction Cosine value of the relative patient's direction of first row by resolving Image Orientation.
Second step: by judge Image Type judge current compute location face and cross section two DICOM images which be locating surface, which is the cross section, judges whether the mutual calculating of suitable locating surface.
The 3rd step: the plane equation that obtains tangent plane by the plane normal vector equation parameter of calculating the tangent plane image:
The 4th step: the plane Ax+By+Cz+D=0 that calculates tangent plane image place respectively and locating surface sideline x-x1/l=y-y1/m=z-z1/n (x1 wherein, y1, z1 are respectively the X in the locating surface upper left corner, Y, mark the Building Z; L, m, n are respectively the direction value X of locating surface first row, Y, the Cos direction value that Z is three) intersection point.
The 5th step:, then calculate intersection point line x-point[i if judge that the intersection point of the four edges of the plane at sectioning image place and spacer is 2] .x/l=y-point[i] .y/m=z-point[i] intersection point of four edges x-x2/A=y-y2/B=z-z2/C of .z/n=t and sectioning image determines the position line fragment position as the position line terminal.
Description of drawings
The present invention includes following accompanying drawing:
Fig. 1: locating surface x, y, z axle bed mark direction and locating surface upper left corner coordinate exemplary plot
Fig. 2: tangent plane x, y, z axle bed mark direction and locating surface upper left corner coordinate exemplary plot
Specific implementation method
Below in conjunction with accompanying drawing the present invention is described in further details.
The objective of the invention is to set up a kind of three-dimensional localization line computation method, calculate the method for DICOM tomoscan image three-dimensional position line based on the space vector equation solution.
A kind of three-dimensional localization line computation method based on the space vector equation solution comprises following treatment step:
The first step: resolve the DICOM file of input, read the numerical value of following TAG:
The TAG label The Tag title
(0020,0032) Image?Position?of Patient
(0020,0037) Image?Orientation
(0028,0030) Pixel?Spacing
(0028,0010) Rows
(0028,0011) Columns
(0008,0008) Image?Type
And obtain the upper left corner X of current image, Y, Building Z mark by resolving Image Position Of Patient; Obtain current image first row, the direction Cosine value of the relative patient's direction of first row by resolving ImageOrientation.
Second step: by judge Image Type judge current compute location face and cross section two DICOM images which be locating surface, which is the cross section, judges whether the mutual calculating of suitable locating surface.
The 3rd step: the plane normal vector equation parameter of calculating the tangent plane image by the following method:
A=Transect.RowDirection.Cos(Y)*Transect.ColumnDirection.Cos(Z)
-Transect.RowDirection.Cos(Z)*Transect.ColumnDirection.Cos(Y)
B=Transect.RowDirection.Cos(Z)*Transect.ColumnDirection.Cos(X)
-Transect.RowDirection.Cos(X)*Transect.ColumnDirection.Cos(Z)
B=Transect.RowDirection.Cos(X)*Transect.ColumnDirection.Cos(Y)
-Transect.RowDirection.Cos(Y)*Transect.ColumnDirection.Cos(Y)
D=-1*(A*Transect.Leftup.X+B*Transect.Leftup.Y+C*Transect.Leftup.Z)
The 4th step: the plane Ax+By+Cz+D=0 that calculates tangent plane image place respectively and locating surface sideline x-x1/l=y-y1/m=z-z1/n (x1 wherein, y1, z1 are respectively the X in the locating surface upper left corner, Y, mark the Building Z; L, m, n are respectively the direction value X of locating surface first row, Y, the Cos direction value that Z is three) intersection point.
Plane space intersection point progressively computing method is as follows:
Calculate the 1st limit:
a=(A*l+B*m+C*n)*Localizer.PixelSpace.Y
b=A*x1+B*y1+C*z1+D
If judge a=0, b!=0 illustrates straight line and plane parallel, does not have intersection point,
The calculating that enters next bar limit is judged;
If perhaps a=0, b=0 then illustrates straight line in the plane, does not also have intersection point,
The calculating that enters next bar limit is judged;
So only under the condition of a>0, carry out next step calculating again.
Calculate: t1=b/a
Judge the value of t1, should be greater than 0 pixel columns Localizer.Columns less than locating surface,
Otherwise restoring to normal position line computation failure;
The value of being calculated as follows (wherein i represents that current is the crossing calculating on which bar limit of tangent plane):
point[i][0]=x1+l*k*t1;
point[i][1]=y1+m*k*t1;
point[i][2]=z1+n*k*t1;
point[i][0]=0;
point[i][1]=t1;
Calculate the 2nd, 3 according to as above similarity method successively then, the intersecting of 4 tangent plane limits;
The 2nd, 3, in the crossing calculating on 4 tangent plane limits, computing method are removed a, the computing method of b value and as above article one limit slightly different following outside, all the other computing method are all identical:
Article 2, limit:
x1=Localizer.Leftup.X+
Localizer.Row*Localizer.PixelSpace.X*Localizer.RowDirection.Cos(X);
y1=Localizer.Leftup.Y+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Y);
z1=Localizer.Leftup.Z+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Z);
b=A*x1+B*y1+C*z1+D;
Article 3, limit:
x1=Localizer.Leftup.X;
y1=Localizer.Leftup.Y;
z1=Localizer.Leftup.Z;
k=Localizer.Leftup.PixelSpace.X;
l=Localizer.ColumnDirection.Cos(X);
m=Localizer.ColumnDirection.Cos(Y);
n=Localizer.ColumnDirection.Cos(Z);
a=(A*l+B*m+C*n)*k;
b=A*x1+B*y1+C*z1+D;
Article 4, limit:
x1=Localizer.Leftup.X+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(X)
y1=Localizer.Leftup.Y+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Y)
z1=Localizer.Leftup.Z+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Z)
b=A*x1+B*y1+C*z1+D
The 5th step:, then calculate intersection point line x-point[i if judge that the intersection point of the four edges of the plane at sectioning image place and spacer is 2] .x/l=y-point[i] .y/m=z-point[i] intersection point of four edges x-x2/A=y-y2/B=z-z2/C of .z/n=t and sectioning image determines the position line fragment position as the position line terminal.
Computing method are as follows:
l=point[1][0]-point[0][0];
m=point[1][1]-point[0][1];
n=point[1][2]-point[0][2];
a=l*Transect.RowDirection.Cos[X]
+m*Transect.RowDirection.Cos[Y]
+n*Transect.RowDirection.Cos[Z]
b=l*Transect.ColumnDirection.Cos[X]
+m*Transect.ColumnDirection.Cos[Y]
+n*Transect.ColumnDirection.Cos[Z]
Then by (a*a<b*b) relatively judges which two parallel edges and point[1 of tangent plane picture], point[2] intersect;
If (a*a<b*b) then explanation is tangent plane horizontal direction limit intersects then calculating with locating surface:
k=Transect.Rows*Transect.PixelSpace.Y
x2=Transect.Leftup.X+k*Transect.ColumnDirection[X]
y2=Transect.Leftup.Y+k*Transect.ColumnDirection[Y]
z2=Transect.Leftup.Z+k*Transect.ColumnDirection[Z]
If (a*a>b*b) then explanation is tangent plane horizontal direction limit intersects then calculating with locating surface:
x2=Transect.Leftup.X+k*Transect.RowDirection.Cos(X)
y2=Transect.Leftup.Y+k*Transect.RowDirection.Cos(Y)
z2=Transect.Leftup.Z+k*Transect.RowDirection.Cos(Z)
Calculate then:
t1=((x1-point[0][0])*B+(point[0][1]-y1)*A)/a;
t2=((x2-point[0][0])*B+(point[0][1]-y2)*A)/a;
Judge t1 then, the t2 two-value all between 0~1, is then calculated:
pointLine[0][0]=point[0][0]*(1-t1)+point[1][0]*t1
pointLine[0][1]=point[0][1]*(1-t1)+point[1][1]*t1
pointLine[1][0]=point[0][0]*(1-t2)+point[1][0]*t2
pointLine[1][1]=point[0][1]*(1-t2)+point[1][1]*t2
PointLine[0 wherein] [], pointLine[1] [] be respectively two end points of position line that locating surface and two faces of tangent plane intersect two coordinates on plane separately.

Claims (7)

1. three-dimensional localization line computation method based on the space vector equation solution by finding the solution its crossing position line of space vector Equation for Calculating, is characterized in that comprising following treatment step at locating surface (Localizer) and tangent plane (Transect):
(1) reads the x of locating surface and tangent plane, y, z axle three-dimensional coordinate and three-dimensional perspective direction value;
(2) judge locating surface (Localizer) and tangent plane (Transect);
(3) calculate tangent plane place plane equation parameter;
(4) intersection point in calculating tangent plane plane and locating surface sideline;
(5) intersection point in calculating intersection point line and tangent plane sideline calculates the position of three-dimensional localization line.
2. a kind of three-dimensional localization line computation method based on the space vector equation solution according to claim 1 is characterized in that the described plane normal vector equation parameter that tangent plane place plane equation parameter is calculated the tangent plane image by the following method that calculates:
A=Transect.RowDirection.Cos(Y)*Transect.ColumnDirection.Cos(Z)
-Transect.RowDirection.Cos(Z)*Transect.ColumnDirection.Cos(Y)
B=Transect.RowDirection.Cos(Z)*Transect.ColumnDirection.Cos(X)
-Transect.RowDirection.Cos(X)*Transect.ColumnDirection.Cos(Z)
B=Transect.RowDirection.Cos(X)*Transect.ColumnDirection.Cos(Y)
-Transect.RowDirection.Cos(Y)*Transect.ColumnDirection.Cos(Y)
D=-1*(A*Transect.Leftup.X+B*Transect.Leftup.Y+C*Transect.Leftup.Z)。
3. a kind of three-dimensional localization line computation method based on the space vector equation solution according to claim 1 is characterized in that the intersection point in described calculating tangent plane plane and locating surface sideline, and the computing method on every limit of four edges of tangent plane and locating surface are as follows:
Article 1, limit:
a=(A*l+B*m+C*n)*Localizer.PixelSpace.Y
b=A*x1+B*y1+C*z1+D
Article 2, limit:
x1=Localizer.Leftup.X+
Localizer.Row*Localizer.PixelSpace.X*Localizer.RowDirection.Cos(X);
y1=Localizer.Leftup.Y+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Y);
z1=Localizer.Leftup.Z+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Z);
b=A*x1+B*y1+C*z1+D;
Article 3, limit:
x1=Localizer.Leftup.X;
y1=Localizer.Leftup.Y;
z1=Localizer.Leftup.Z;
k=Localizer.Leftup.PixelSpace.X;
l=Localizer.ColumnDirection.Cos(X);
m=Localizer.ColumnDirection.Cos(Y);
n=Localizer.ColumnDirection.Cos(Z);
a=(A*l+B*m+C*n)*k;
b=A*x1+B*y1+C*z1+D;
Article 4, limit:
x1=Localizer.Leftup.X+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(X)
y1=Localizer.Leftup.Y+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Y)
z1=Localizer.Leftup.Z+
Localizer.Columns*Localizer.PixelSpace.Y*Localizer.RowDirection.Cos(Z)
b=A*x1+B*y1+C*z1+D。
4. a kind of three-dimensional localization line computation method based on the space vector equation solution according to claim 3 is characterized in that the intersection point in described calculating tangent plane plane and locating surface sideline, and is as follows at the public crossing computing method in every sideline of tangent plane and locating surface:
point[i][0]=x1+1*k*t1;
point[i][1]=y1+m*k*t1;
point[i][2]=z1+n*k*t1;
point[i][0]=0;
point[i][1]=t1。
5. it is as follows that a kind of three-dimensional localization line computation method based on the space vector equation solution according to claim 1, the intersection point that it is characterized in that described calculating intersection point line and tangent plane sideline calculate the location method of three-dimensional localization line:
l=point[1][0]-point[0][0];
m=point[1][1]-point[0][1];
n=point[1][2]-point[0][2];
a=l*Transect.RowDirection.Cos[X]
+m*Transect.RowDirection.Cos[Y]
+n*Transect.RowDirection.Cos[Z]
b=l*Transect.ColumnDirection.Cos[X]
+m*Transect.ColumnDirection.Cos[Y]
+n*Transect.ColumnDirection.Cos[Z]
Then by (a*a<b*b) relatively judges which two parallel edges and point[1 of tangent plane picture], point[2] intersect; If (if a*a<b*b) then explanation is tangent plane horizontal direction limit intersects with locating surface is (a*a>b*b) then explanation is that tangent plane horizontal direction limit and locating surface are crossing.
6. a kind of three-dimensional localization line computation method based on the space vector equation solution according to claim 5 is characterized in that the intersection point in described calculating intersection point line and tangent plane sideline calculates the location method of three-dimensional localization line:
If (a*a<b*b) then explanation is tangent plane horizontal direction limit intersects then calculating with locating surface:
k=Transect.Rows*Transect.PixelSpace.Y
x2=Transect.Leftup.X+k*Transect.ColumnDirection[X]
y2=Transect.Leftup.Y+k*Transect.ColumnDirection[Y]
z2=Transect.Leftup.Z+k*Transect.ColumnDirection[Z]
If (a*a>b*b) then explanation is tangent plane horizontal direction limit intersects then calculating with locating surface:
x2=Transect.Leftup.X+k*Transect.RowDirection.Cos(X)
y2=Transect.Leftup.Y+k*Transect.RowDirection.Cos(Y)
z2=Transect.Leftup.Z+k*Transect.RowDirection.Cos(Z)。
7. it is as follows that a kind of three-dimensional localization line computation method based on the space vector equation solution according to claim 5, the intersection point that it is characterized in that described calculating intersection point line and tangent plane sideline calculate the location method of three-dimensional localization line:
t1=((x1-point[0][0])*B+(point[0][1]-y1)*A)/a;
t2=((x2-point[0][0])*B+(point[0][1]-y2)*A)/a;
Judge t1 then, the t2 two-value all between 0~1, is then calculated:
pointLine[0][0]=point[0][0]*(1-t1)+point[1][0]*t1
pointLine[0][1]=point[0][1]*(1-t1)+point[1][1]*t1
pointLine[1][0]=point[0][0]*(1-t2)+point[1][0]*t2
pointLine[1][1]=point[0][1]*(1-t2)+point[1][1]*t2
PointLine[0 wherein] [], pointLine[1] [] be respectively two end points of position line that locating surface and two faces of tangent plane intersect two coordinates on plane separately.
CN2010101576424A 2010-04-28 2010-04-28 Space vector equation solving-based three-dimensional line of position calculation method Pending CN102103652A (en)

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Application publication date: 20110622