CN101789584A - Method for differential protection of sampling value of abrupt change and differential relays - Google Patents

Method for differential protection of sampling value of abrupt change and differential relays Download PDF

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CN101789584A
CN101789584A CN 201010034082 CN201010034082A CN101789584A CN 101789584 A CN101789584 A CN 101789584A CN 201010034082 CN201010034082 CN 201010034082 CN 201010034082 A CN201010034082 A CN 201010034082A CN 101789584 A CN101789584 A CN 101789584A
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transformer
value
current
sudden change
differential
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CN101789584B (en
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柳焕章
屠黎明
张德泉
肖远清
杨军
聂娟红
李会新
黄少锋
陈祥文
尹梁方
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Beijing Sifang Automation Co Ltd
Central China Grid Co Ltd
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Central China Grid Co Ltd
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Abstract

本发明公开了用于变压器内部故障的突变量采样值差动保护方法和差动继电器。由于常规的稳态量差动保护继电器在变压器发生变压器严重故障时动作速度慢的问题,本发明提出了突变量采样值差动保护方法和差动继电器。该差动保护方法和差动继电器采用突变量采样值的差流平方积分和突变量采样值等效两侧电流的乘积构成一个高定值的继电器和一个低定值的继电器。试验结果表明本发明具有很好的安全性、快速性。

The invention discloses a differential protection method and a differential relay for the sudden change sampling value used for transformer internal faults. Due to the problem that the conventional steady-state quantity differential protection relay has a slow action speed when the transformer is severely faulted, the present invention proposes a differential protection method and a differential relay for sudden change quantity sampling values. The differential protection method and the differential relay adopt the product of the differential current square integral of the sampled value of the sudden change and the equivalent current on both sides of the sampled value of the sudden change to form a relay with a high fixed value and a relay with a low fixed value. The test result shows that the present invention has good safety and rapidity.

Description

突变量采样值差动保护方法和差动继电器 Differential Protection Method and Differential Relay of Sampling Value of Sudden Change

技术领域technical field

本发明涉及继电保护技术变压器保护领域,特别涉及一种变压器差动保护技术。The invention relates to the field of relay protection technology and transformer protection, in particular to a transformer differential protection technology.

背景技术Background technique

随着变压器的容量越来越大,变压器的造价非常昂贵,而且系统的短路容量越来越大,在变压器引线上发生严重的故障,短路电流很大,并且穿过变压器本体,对变压器本体的绝缘产生破坏,同时在绕组产生的机械应力对变压器的绕组和铁心产生很大的扭曲作用。因此研究变压器的快速保护成为变压器主保护研究的重要而迫切的课题。As the capacity of the transformer is getting bigger and bigger, the cost of the transformer is very expensive, and the short-circuit capacity of the system is getting bigger and bigger. Serious faults occur on the transformer leads, and the short-circuit current is very large, and it passes through the transformer body. The insulation is damaged, and the mechanical stress generated in the winding produces a great distortion on the winding and core of the transformer. Therefore, it is an important and urgent subject to study the fast protection of transformers.

目前变压器的快速保护主要是电流差速断保护,不经任何闭锁,为保证其可靠性,定值一般为5~12倍的变压器额定电流,并且需要采用滤波算法,因此该保护有一定长度的数据窗才能开始计算判别,所以其通常的动作时间在20ms以上,并且由于采用固定定值的方式,不管多大的故障电流动作时间是相同的,这些都不利于降低大电流故障时对变压器的冲击。At present, the fast protection of the transformer is mainly the current differential break protection without any blocking. In order to ensure its reliability, the fixed value is generally 5 to 12 times the rated current of the transformer, and a filtering algorithm is required, so the protection has a certain length of data Therefore, its usual operating time is more than 20ms, and due to the fixed value method, no matter how large the fault current is, the operating time is the same, which is not conducive to reducing the impact on the transformer when a large current fault occurs.

如果能够采用新的算法在不降低安全性的前提下根据故障电流的大小动态的调整动作时间,依据故障的严重程度快速切除故障,减轻对变压器本体的冲击。If the new algorithm can be used to dynamically adjust the action time according to the size of the fault current without reducing the safety, the fault can be quickly removed according to the severity of the fault, and the impact on the transformer body can be reduced.

发明内容Contents of the invention

为解决变压器的快速动作同时兼顾继电器的安全性,本发明提出了突变量采样值变压器差动保护方法和基于该差动保护方法的突变量采样值差动继电器。In order to solve the fast action of the transformer and take into account the safety of the relay, the present invention proposes a differential protection method for a transformer with a sudden change sampling value and a differential relay with a sudden change sampling value based on the differential protection method.

本发明具体采用以下技术方案:The present invention specifically adopts the following technical solutions:

一种突变量采样值变压器差动保护方法,其特征在于,所述方法包括以下步骤:A method for differential protection of a sudden change sampling value transformer, characterized in that the method comprises the following steps:

(1)通过变压器各侧电流互感器采集变压器各侧的电流以及各侧的突变量电流值;(1) Collect the current on each side of the transformer and the sudden change current value on each side through the current transformers on each side of the transformer;

(2)将变压器的多侧差动转换为变压器突变量采样值两侧差动:将所采集的变压器多侧中的突变量电流采样值绝对值最大侧定为变压器差动保护的一端,将其余侧的突变量电流采样值和等效定为变压器差动保护的另一端,其中,(2) Convert the multi-side differential of the transformer into the difference between the two sides of the sampling value of the sudden change of the transformer: the side with the maximum absolute value of the sampling value of the sudden change current collected in the multi-side of the transformer is set as one end of the transformer differential protection, and the The sudden change current sampling value and equivalent of the other sides are defined as the other end of the transformer differential protection, where,

Δi(t)——变压器突变量采样值差动电流;Δi (t)——The differential current of the sampling value of the sudden change of the transformer;

ΔiM(t)——变压器各侧突变量电流采样值中的最大值;Δi M (t)——The maximum value of the sudden change current sampling value on each side of the transformer;

Δi∑-M(t)=Δi(t)-ΔiM(t)——变压器其它侧突变量电流采样值之和;Δi ∑ - M (t) = Δi (t) - Δi M (t) - the sum of the sampling values of sudden changes in other sides of the transformer;

(3)当满足以下动作方程时,变压器突变量采样值差动保护动作:(3) When the following action equation is satisfied, the differential protection of the sampling value of the sudden change of the transformer operates:

动作方程如下:The action equation is as follows:

ΣΣ ΔiΔi ΣΣ 22 (( tt )) >> -- CC 11 ΣΣ ΔiΔi Mm (( tt )) ΔiΔi ΣΣ -- Mm (( tt )) ++ (( ρρ ·· II ee )) 22 NN ++ CC 22 ΔiΔi ΣΣ 22 (( tt )) MAXMAX -- -- -- (( 11 ))

∑ΔiM(t)Δi∑-M(t)>C3Ie 2N+C4|[ΔiM(t)Δi∑-M(t)]|MAX    (2)∑Δi M (t)Δi ∑-M (t)>C 3 I e 2 N+C 4 |[Δi M (t)Δi ∑-M (t)]| MAX (2)

式中:N为一周波采样点数;In the formula: N is the number of cycle sampling points;

C1,C2,C3,C4为常数,依据区分内部故障和区外故障来确定取值范围,其取值范围为1~10之间。C 1 , C 2 , C 3 , and C 4 are constants, and the value range is determined based on the distinction between internal faults and external faults, and the value range is between 1 and 10.

Ie为变压器额定电流;I e is the rated current of the transformer;

Figure G2010100340823D00022
η依据《大型发电机变压器继电保护整定计算导则》进行取值。
Figure G2010100340823D00022
The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer".

Δi 2(t)MAX为变压器突变量采样值差动电流平方的最大值;Δi 2 (t) MAX is the maximum value of the square of the differential current of the transformer sudden change sampling value;

[ΔiM(t)Δi∑-M(t)]|MAX为“变压器各侧突变量电流采样值中的最大值”和“变压器其它侧突变量电流采样值之和”的乘积的最大值;[Δi M (t)Δi ∑-M (t)] | MAX is the maximum value of the product of "the maximum value of the current sampling value of the sudden change on each side of the transformer" and "the sum of the sampling values of the sudden change current at other sides of the transformer";

Δi 2(t)MAX反映了故障的严重程度,[ΔiM(t)Δi∑-M(t)]|MAX反映了故障的性质。在变压器发生严重故障时,所述差动保护方法的动作时间特性会随着故障电流的大小变化,当动作电流越大,动作速度越快,具有反时限的特性。Δi 2 (t) MAX reflects the severity of the fault, and [Δi M (t)Δi ∑-M (t)]| MAX reflects the nature of the fault. When a serious fault occurs in the transformer, the operating time characteristic of the differential protection method will change with the magnitude of the fault current. When the operating current is larger, the operating speed will be faster, which has an inverse time-limit characteristic.

本发明还公开了一种基于上述差动保护方法的突变量采样值变压器差动继电器,其特征在于:The present invention also discloses a transformer differential relay based on the above-mentioned differential protection method, which is characterized in that:

所述继电器采用突变量电流采样值的差流平方积分和突变量电流采样值等效两侧电流的乘积构成一个高定值的继电器和一个低定值的继电器,其中,The relay adopts the product of the difference current square integral of the sudden change current sampling value and the equivalent current on both sides of the sudden change current sampling value to form a relay with a high fixed value and a relay with a low fixed value, wherein,

所述高定值继电器的动作方程如下:The action equation of the high-set value relay is as follows:

ΣΣ ΔiΔi ΣΣ 22 (( tt )) >> -- CC 11 ΣΣ ΔiΔi Mm (( tt )) ΔiΔi ΣΣ -- Mm (( tt )) ++ (( ρρ ·&Center Dot; II ee )) 22 NN ++ CC 22 ΔiΔi ΣΣ 22 (( tt )) MAXMAX -- -- -- (( 11 ))

所述低定值继电器的动作方程如下:The action equation of the low fixed value relay is as follows:

∑ΔiM(t)Δi∑-M(t)>C3Ie 2N+C4|[ΔiM(t)Δi∑-M(t)]|MAX    (2)∑Δi M (t)Δi ∑-M (t)>C 3 I e 2 N+C 4 |[Δi M (t)Δi ∑-M (t)]| MAX (2)

式中:N为一周波采样点数;In the formula: N is the number of cycle sampling points;

C1,C2,C3,C4为常数,依据区分内部故障和区外故障来确定取值范围,其取值范围为1~10之间。C 1 , C 2 , C 3 , and C 4 are constants, and the value range is determined based on the distinction between internal faults and external faults, and the value range is between 1 and 10.

Ie为变压器额定电流;I e is the rated current of the transformer;

η依据《大型发电机变压器继电保护整定计算导则》进行取值。 The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer".

Δi 2(t)MAX为变压器突变量采样值差动电流平方的最大值;Δi 2 (t) MAX is the maximum value of the square of the differential current of the transformer sudden change sampling value;

[ΔiM(t)Δi∑-M(t)]|MAX为“变压器各侧突变量电流采样值中的最大值”和“变压器其它侧突变量电流采样值之和”的乘积的最大值;[Δi M (t)Δi ∑-M (t)] | MAX is the maximum value of the product of "the maximum value of the current sampling value of the sudden change on each side of the transformer" and "the sum of the sampling values of the sudden change current at other sides of the transformer";

Δi 2(t)MAX反映了故障的严重程度,[ΔiM(t)Δi∑-M(t)]|MAX反映了故障的性质。Δi 2 (t) MAX reflects the severity of the fault, and [Δi M (t)Δi ∑-M (t)]| MAX reflects the nature of the fault.

Figure G2010100340823D00031
η依据《大型发电机变压器继电保护整定计算导则》进行取值;
Figure G2010100340823D00031
The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer";

当所述高定值继电器动作方程满足时,或者所述高定值继电器动作方程不满足而所述低定值继电器动作方程满足时,所述突变量采样值变压器差动继电器动作。When the high fixed value relay action equation is satisfied, or when the high fixed value relay action equation is not satisfied but the low fixed value relay action equation is satisfied, the sudden change sampling value transformer differential relay operates.

η的取值依据《大型发电机变压器继电保护整定计算导则》,如表1所示:表1The value of η is based on the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer", as shown in Table 1: Table 1

  变压器容量Transformer capacity   差速断整定定值Differential speed break setting value   η的取值The value of η   6300kVA及以下6300kVA and below   7.0~12.0倍Ie7.0~12.0 times Ie   1212

  变压器容量Transformer capacity   差速断整定定值Differential speed break setting value   η的取值The value of η   6300kVA~31500kVA6300kVA~31500kVA   4.5~7.0倍Ie4.5~7.0 times Ie   1010   40000kVA~120000kVA40000kVA~120000kVA   3.0~6.0倍Ie3.0~6.0 times Ie   8 8   120000kVA以上Above 120000kVA   2.0~5.02.0~5.0   66

与现有技术相比,本发明具有以下优点:Compared with the prior art, the present invention has the following advantages:

目前变压器的快速保护主要是电流差速断保护,不经任何闭锁,为保证其可靠性,定值一般为5~12倍的变压器额定电流,并且需要采用滤波算法,因此该保护有一定长度的数据窗才能开始计算判别,所以其通常的动作时间在20ms以上,并且由于采用固定定值的方式,不管多大的故障电流动作时间是相同的。At present, the fast protection of the transformer is mainly the current differential break protection without any blocking. In order to ensure its reliability, the fixed value is generally 5 to 12 times the rated current of the transformer, and a filtering algorithm is required, so the protection has a certain length of data The calculation and discrimination can only be started after the window, so its usual action time is above 20ms, and due to the fixed value method, no matter how big the fault current is, the action time is the same.

本发明提出的继电器在变压器发生严重故障时,其动作时间特性会随着故障电流的大小变化,当动作电流越大,动作速度越快,具有反时限的特性,与现有技术相比更符合变压器保护的基本原则。同时本继电器具有明显的方向特征(ΔiM(t)Δi∑-M(t)),具有很好抗CT饱和、CT传变误差、励磁涌流的能力。因此,突变量采样值差动继电器大大提高了严重故障的切除速度同时具有很高的安全性。When the relay proposed by the present invention has a serious fault in the transformer, its operating time characteristic will change with the size of the fault current. When the operating current is larger, the operating speed will be faster, and it has the characteristic of inverse time limit, which is more in line with the existing technology. Basic principles of transformer protection. At the same time, the relay has obvious directional characteristics (Δi M (t) Δi Σ-M (t)), and has a good ability to resist CT saturation, CT transmission error, and excitation inrush current. Therefore, the sudden change sampled value differential relay greatly improves the removal speed of serious faults and has high safety at the same time.

附图说明Description of drawings

图1为典型的变电站变压器的系统图及差动保护范围说明;Figure 1 is a system diagram of a typical substation transformer and a description of the range of differential protection;

图2为常规变压器典型的电流速断动作曲线;Figure 2 is a typical current quick-break action curve of a conventional transformer;

图3为本发明功能实现的流程图。Fig. 3 is a flowchart of the function realization of the present invention.

具体实施方式Detailed ways

为使本发明的上述目的、特征和优点能够更加明显易懂,下面结合附图对本发明的具体实施方式做详细的说明。In order to make the above objects, features and advantages of the present invention more comprehensible, specific implementations of the present invention will be described in detail below in conjunction with the accompanying drawings.

参见图1,典型的变电站变压器的系统图及差动保护范围说明。See Figure 1, the system diagram of a typical substation transformer and the description of the differential protection range.

图1中曲线所包括的范围为差动保护继电器保护的范围,称为区内故障,采用变压器各侧电流构成。曲线外的故障称为区外故障。The range covered by the curve in Figure 1 is the range protected by the differential protection relay, which is called the fault in the area, and is formed by the current on each side of the transformer. Faults outside the curve are called out-of-area faults.

参见图2,该图为常规变压器典型的差动继电器动作曲线。其动作方程为:See Figure 2, which is a typical differential relay action curve of a conventional transformer. Its action equation is:

|| II ·· ΣΣ || ≥&Greater Equal; II sdsd -- -- -- (( 33 ))

式中:为变压器差动电流,由各侧电流的向量和计算而来;In the formula: is the transformer differential current, calculated from the vector sum of the currents on each side;

Isd为变压器差速断电流定值,通常按5~12倍Ie整定;I sd is the fixed value of transformer differential cut-off current, which is usually set at 5 to 12 times Ie;

本发明所公开的突变量电流采样值变压器差动保护方法在本实施例中具体包括以下步骤,如图3所示:The method for differential protection of a transformer with sudden change current sampling value disclosed in the present invention specifically includes the following steps in this embodiment, as shown in FIG. 3 :

(1)通过变压器各侧电流互感器采集变压器各侧的电流以及各侧的突变量电流值;(1) Collect the current on each side of the transformer and the sudden change current value on each side through the current transformers on each side of the transformer;

(2)在本发明中优选将变压器其它侧电流归算到高压侧:(2) In the present invention, the other side currents of the transformer are preferably attributed to the high voltage side:

以高压侧的电流为基准,其他各侧向高压侧归算。计算各侧的平衡系数为:Based on the current of the high-voltage side, other sides are reduced to the high-voltage side. Calculate the balance factor for each side as:

计算变压器各侧一次额定电流:Calculate the primary rated current of each side of the transformer:

II lelet's go == SS ee 33 Uu 11 ee -- -- -- (( 44 ))

式中:Se为变压器最大额定容量;U1e为变压器各侧额定电压(应以运行的实际电压为准)。In the formula: S e is the maximum rated capacity of the transformer; U 1e is the rated voltage of each side of the transformer (the actual operating voltage should prevail).

计算变压器各侧二次额定电流:Calculate the secondary rated current of each side of the transformer:

II 22 ee == II 11 ee nno LHLH -- -- -- (( 55 ))

式中:I1e为变压器各侧一次额定电流;nLH为变压器各侧CT变比。In the formula: I 1e is the primary rated current of each side of the transformer; n LH is the CT transformation ratio of each side of the transformer.

以高压侧为基准,计算变压器中、低压侧平衡系数:Based on the high-voltage side, calculate the balance coefficient of the medium and low-voltage sides of the transformer:

KK phpH .. Mm == II 22 ee .. Hh II 22 ee .. Mm == II 11 ee .. Hh // nno LHLH .. Hh II 11 ee .. Mm // nno LHLH .. Mm == SS ee // 33 Uu 11 ee .. Hh SS ee // 33 Uu 11 ee .. Mm ·&Center Dot; nno LHLH .. Mm nno LHLH .. Hh == Uu 11 ee .. Mm Uu 11 ee .. Hh ·&Center Dot; nno LHLH .. Mm nno LHLH .. Hh -- -- -- (( 66 ))

KK phpH ,, LL == Uu 11 ee .. LL Uu 11 ee .. Hh ·&Center Dot; nno LHLH .. LL nno LHLH .. Hh -- -- -- (( 77 ))

将其他侧各相电流与相应的平衡系数相乘,即得幅值补偿后的各相电流。Multiply the current of each phase on the other side with the corresponding balance coefficient to obtain the current of each phase after amplitude compensation.

(3)进一步优选对变压器各侧电流进行相位补偿:(3) It is further preferred to perform phase compensation on the currents on each side of the transformer:

变压器各侧CT二次电流相位由软件自校正,以在Δ->Y侧进行校正相位,Y0/Δ-11变压器为例。其校正方法如下:The CT secondary current phase on each side of the transformer is self-corrected by software, taking the phase correction on the Δ->Y side, Y0/Δ-11 transformer as an example. Its correction method is as follows:

Δ侧:Delta side:

ΔΔ II ·&Center Dot; NANA ′′ == (( ΔΔ II ·&Center Dot; NANA -- ΔΔ II ·&Center Dot; NCNC )) ΔΔ II ·&Center Dot; NBNB ′′ == (( ΔΔ II ·· NBNB -- ΔΔ II ·&Center Dot; NANA )) ΔΔ II ·· NCNC ′′ == (( ΔΔ II ·· NCNC -- ΔΔ II ·· NBNB )) -- -- -- (( 88 ))

Y侧:Y side:

ΔΔ II ·· MAMA ′′ == ΔΔ II ·&Center Dot; MAMA -- ΔΔ II ·· 00 ΔΔ II ·· MBMB ′′ == ΔΔ II ·&Center Dot; MBMB -- ΔΔ II ·· 00 ΔΔ II ·· MCMC ′′ == ΔΔ II ·&Center Dot; MCMC -- ΔΔ II ·· 00 ΔΔ II ·· 00 == (( ΔΔ II ·&Center Dot; MAMA ++ ΔΔ II ·· MBMB ΔΔ II ·&Center Dot; MCMC )) // 33 -- -- -- (( 99 ))

式中:

Figure G2010100340823D00053
为Y侧CT二次电流;
Figure G2010100340823D00054
为Y侧校正后的各相电流。为Δ侧CT二次电流;
Figure G2010100340823D00056
为Δ侧校正后的各相电流;其它接线方式可以类推。In the formula:
Figure G2010100340823D00053
is the Y-side CT secondary current;
Figure G2010100340823D00054
is the corrected current of each phase on the Y side. is the CT secondary current on the Δ side;
Figure G2010100340823D00056
It is the corrected current of each phase on the Δ side; other wiring methods can be analogized.

继电器的相关计算,都是在电流相位校正和平衡补偿后的基础上进行。The relevant calculations of the relay are all carried out on the basis of current phase correction and balance compensation.

(4)将所采集的变压器多侧中的突变量电流绝对值最大侧定为变压器差动保护的一端,将其余侧的突变量电流和等效定为变压器差动保护的另一端,其中,(4) The side with the maximum absolute value of the sudden change current in the multi-sides of the collected transformer is defined as one end of the transformer differential protection, and the sudden change current and equivalent of the other sides are set as the other end of the transformer differential protection, among which,

Δi(t)——变压器突变量采样值差动电流;Δi (t)——The differential current of the sampling value of the sudden change of the transformer;

ΔiM(t)——变压器各侧突变量电流采样值中的最大值;Δi M (t)——The maximum value of the sudden change current sampling value on each side of the transformer;

Δi∑-M(t)=Δi(t)-ΔiM(t)——变压器其它侧突变量电流采样值之和;Δi ∑ - M (t) = Δi (t) - Δi M (t) - the sum of the sampling values of sudden changes in other sides of the transformer;

突变量采样值差动电流的计算方法如下:The calculation method of the differential current of the sampling value of sudden change is as follows:

ΔΔ II ·· ΣΣ == ΣΣ ii == 11 nno ΔΔ II ·&Center Dot; ii -- -- -- (( 1010 ))

式中:

Figure G2010100340823D00058
为突变量采样值差动电流;
Figure G2010100340823D00059
为所有侧相电流的突变量采样值之和。In the formula:
Figure G2010100340823D00058
The differential current is the sampling value of the sudden change;
Figure G2010100340823D00059
It is the sum of the sudden change sampling values of all side phase currents.

突变量采样值差动电流的平方积分计算公式如下:The calculation formula of the square integral of the differential current of the sampling value of the sudden change is as follows:

∑Δi 2(t)(11)∑Δi 2 (t)(11)

突变量采样值乘积的积分计算公式如下:The integral calculation formula of the product of the sudden change sampling value is as follows:

∑ΔiM(t)Δi∑-M(t)(12)ΣΔi M (t)Δi Σ-M (t)(12)

求取突变量采样值差动电流的平方最大值Δi 2(t)MAX,突变量采样值乘积的最大值|[ΔiM(t)Δi∑-M(t)]|MAXCalculate the maximum value of the square of the differential current Δi 2 (t) MAX of the sampled value of the sudden change, and |[Δi M (t) Δi ∑-M (t)]| MAX of the product of the sampled value of the sudden change.

(5)当满足以下任一动作方程时,变压器突变量采样值差动保护动作:(5) When any of the following action equations is satisfied, the differential protection action of the sampling value of the sudden change of the transformer:

动作方程如下:The action equation is as follows:

ΣΣ ΔiΔi ΣΣ 22 (( tt )) >> -- CC 11 ΣΣ ΔiΔi Mm (( tt )) ΔiΔi ΣΣ -- Mm (( tt )) ++ (( ρρ ·&Center Dot; II ee )) 22 NN ++ CC 22 ΔiΔi ΣΣ 22 (( tt )) MAXMAX -- -- -- (( 1313 ))

∑ΔiM(t)Δi∑-M(t)>C3Ie 2N+C4|[ΔiM(t)Δi∑-M(t)]|MAX    (14)∑Δi M (t)Δi ∑-M (t)>C 3 I e 2 N+C 4 |[Δi M (t)Δi ∑-M (t)]| MAX (14)

式中:N为一周波采样点数;In the formula: N is the number of cycle sampling points;

C1,C2,C3,C4为常数,依据区分内部故障和区外故障来确定取值范围,其取值范围为1~10之间。C 1 , C 2 , C 3 , and C 4 are constants, and the value range is determined based on the distinction between internal faults and external faults, and the value range is between 1 and 10.

Ie为变压器额定电流;I e is the rated current of the transformer;

Figure G2010100340823D00062
η依据《大型发电机变压器继电保护整定计算导则》进行取值。
Figure G2010100340823D00062
The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer".

Δi 2(t)MAX为变压器突变量采样值差动电流平方的最大值;Δi 2 (t) MAX is the maximum value of the square of the differential current of the transformer sudden change sampling value;

[ΔiM(t)Δi∑-M(t)]|MAX为“变压器各侧突变量电流采样值中的最大值”和“变压器其它侧突变量电流采样值之和”的乘积的最大值;[Δi M (t)Δi ∑-M (t)] | MAX is the maximum value of the product of "the maximum value of the current sampling value of the sudden change on each side of the transformer" and "the sum of the sampling values of the sudden change current at other sides of the transformer";

Δi 2(t)MAX反映了故障的严重程度,[ΔiM(t)Δi∑-M(t)]|MAX反映了故障的性质。

Figure G2010100340823D00063
Δi 2 (t) MAX reflects the severity of the fault, and [Δi M (t)Δi ∑-M (t)]| MAX reflects the nature of the fault.
Figure G2010100340823D00063

η的取值依据如下原则:The value of η is based on the following principles:

依据《大型发电机变压器继电保护整定计算导则》:According to the "Large Generator Transformer Relay Protection Setting Calculation Guidelines":

  变压器容量Transformer capacity   差速断整定定值Differential speed break setting value   η的取值The value of η   6300kVA及以下6300kVA and below   7.0~12.0倍Ie7.0~12.0 times Ie   1212   6300kVA~31500kVA6300kVA~31500kVA   4.5~7.0倍Ie4.5~7.0 times Ie   1010   40000kVA~120000kVA40000kVA~120000kVA   3.0~6.0倍Ie3.0~6.0 times Ie   8 8   120000kVA以上Above 120000kVA   2.0~5.02.0~5.0   66

满足式(13)或式(14),则保护动作。Satisfies formula (13) or formula (14), then protection action.

根据上述保护方法的变压器差动继电器的动作方程如下式:The action equation of the transformer differential relay according to the above protection method is as follows:

ΣΣ ΔiΔi ΣΣ 22 (( tt )) >> -- CC 11 ΣΣ ΔiΔi Mm (( tt )) ΔiΔi ΣΣ -- Mm (( tt )) ++ (( ρρ ·&Center Dot; II ee )) 22 NN ++ CC 22 ΔiΔi ΣΣ 22 (( tt )) MAXMAX -- -- -- (( 1515 ))

∑ΔiM(t)Δi∑-M(t)>C3Ie 2N+C4|[ΔiM(t)Δi∑-M(t)]|MAX    (16)∑Δi M (t)Δi ∑-M (t)>C 3 I e 2 N+C 4 |[Δi M (t)Δi ∑-M (t)]| MAX (16)

式中:N为一周波采样点数;In the formula: N is the number of cycle sampling points;

C1,C2,C3,C4为常数,依据区分内部故障和区外故障来确定取值范围,其取值范围为1~10之间。C 1 , C 2 , C 3 , and C 4 are constants, and the value range is determined based on the distinction between internal faults and external faults, and the value range is between 1 and 10.

Ie为变压器额定电流;I e is the rated current of the transformer;

Figure G2010100340823D00072
η依据《大型发电机变压器继电保护整定计算导则》进行取值。
Figure G2010100340823D00072
The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer".

Δi 2(t)MAX为变压器突变量采样值差动电流平方的最大值;Δi 2 (t) MAX is the maximum value of the square of the differential current of the transformer sudden change sampling value;

[ΔiM(t)Δi∑-M(t)]|MAX为“变压器各侧突变量电流采样值中的最大值”和“变压器其它侧突变量电流采样值之和”的乘积的最大值;[Δi M (t)Δi ∑-M (t)] | MAX is the maximum value of the product of "the maximum value of the current sampling value of the sudden change on each side of the transformer" and "the sum of the sampling values of the sudden change current at other sides of the transformer";

Δi 2(t)MAX反映了故障的严重程度,[ΔiM(t)Δi∑-M(t)]|MAX反映了故障的性质。η的取值依据如下原则:Δi 2 (t) MAX reflects the severity of the fault, and [Δi M (t)Δi ∑-M (t)]| MAX reflects the nature of the fault. The value of η is based on the following principles:

依据《大型发电机变压器继电保护整定计算导则》:According to the "Large Generator Transformer Relay Protection Setting Calculation Guidelines":

  变压器容量Transformer capacity   差速断整定定值Differential speed break setting value   η的取值The value of η   6300kVA及以下6300kVA and below   7.0~12.0倍Ie7.0~12.0 times Ie   1212   6300kVA~31500kVA6300kVA~31500kVA   4.5~7.0倍Ie4.5~7.0 times Ie   1010   40000kVA~120000kVA40000kVA~120000kVA   3.0~6.0倍Ie3.0~6.0 times Ie   8 8   120000kVA以上Above 120000kVA   2.0~5.02.0~5.0   66

满足式(15)或式(16),则保护动作。If formula (15) or formula (16) is met, the protection will operate.

目前变压器的快速保护主要是电流差速断保护,不经任何闭锁,为保证其可靠性,定值一般为5~12倍的变压器额定电流,并且需要采用滤波算法,因此该保护有一定长度的数据窗才能开始计算判别,所以其通常的动作时间在20ms以上,并且由于采用固定定值的方式,不管多大的故障电流动作时间是相同的。At present, the fast protection of the transformer is mainly the current differential break protection without any blocking. In order to ensure its reliability, the fixed value is generally 5 to 12 times the rated current of the transformer, and a filtering algorithm is required, so the protection has a certain length of data The calculation and discrimination can only be started after the window, so its usual action time is above 20ms, and due to the fixed value method, no matter how big the fault current is, the action time is the same.

本发明提出的继电器在变压器发生严重故障时,其动作时间特性会随着故障电流的大小变化,当动作电流越大,动作速度越快,具有反时限的特性,与现有技术相比更符合变压器保护的基本原则。同时本继电器具有明显的方向特征(ΔiM(t)Δi∑-M(t)),具有很好抗CT饱和、CT传变误差、励磁涌流的能力。因此,突变量采样值差动继电器大大提高了严重故障的切除速度同时具有很高的安全性。When the relay proposed by the present invention has a serious fault in the transformer, its operating time characteristic will change with the size of the fault current. When the operating current is larger, the operating speed will be faster, and it has the characteristic of inverse time limit, which is more in line with the existing technology. Basic principles of transformer protection. At the same time, the relay has obvious directional characteristics (Δi M (t) Δi Σ-M (t)), and has a good ability to resist CT saturation, CT transmission error, and excitation inrush current. Therefore, the sudden change sampled value differential relay greatly improves the removal speed of serious faults and has high safety at the same time.

Claims (3)

1.一种突变量采样值变压器差动保护方法,其特征在于,所述方法包括以下步骤:1. a sudden change amount sampling value transformer differential protection method, is characterized in that, described method comprises the following steps: (1)通过变压器各侧电流互感器采集变压器各侧的电流以及计算各侧的突变量电流值;(1) Collect the current on each side of the transformer through the current transformers on each side of the transformer and calculate the sudden change current value on each side; (2)将变压器的多侧差动转换为变压器突变量采样值两侧差动:将所采集的变压器多侧中的突变量电流采样值绝对值最大侧定为变压器差动保护的一端,将其余侧的突变量电流采样值和等效定为变压器差动保护的另一端,其中,(2) Convert the multi-side differential of the transformer into the difference between the two sides of the sampling value of the sudden change of the transformer: the side with the maximum absolute value of the sampling value of the sudden change current collected in the multi-side of the transformer is set as one end of the transformer differential protection, and the The sudden change current sampling value and equivalent of the other sides are defined as the other end of the transformer differential protection, where, Δi(t)——变压器突变量采样值差动电流;Δi (t)——The differential current of the sampling value of the sudden change of the transformer; ΔiM(t)——变压器各侧突变量电流采样值中的最大值;Δi M (t)——The maximum value of the sudden change current sampling value on each side of the transformer; Δi∑-M(t)=Δi(t)-ΔiM(t)——变压器其它侧突变量电流采样值之和;Δi ∑ - M (t) = Δi (t) - Δi M (t) - the sum of the sampling values of sudden changes in other sides of the transformer; (3)当满足以下任一动作方程时,变压器突变量采样值差动保护动作:(3) When any of the following action equations is met, the differential protection of the sampling value of the sudden change of the transformer operates: 动作方程如下:The action equation is as follows: ΣΔΣΔ ii ΣΣ 22 (( tt )) >> -- CC 11 ΣΔΣΔ ii Mm (( tt )) ΔΔ ii ΣΣ -- Mm (( tt )) ++ (( ρρ ·· II ee )) 22 NN ++ CC 22 ΔΔ ii ΣΣ 22 (( tt )) MAXMAX -- -- -- (( 11 )) ∑ΔiM(t)Δi∑-M(t)>C3Ie 2N+C4 |[ΔiM(t)Δi∑-M(t)]|MAX(2)∑Δi M (t)Δi ∑-M (t)>C 3 I e 2 N+C 4 |[Δi M (t)Δi ∑-M (t)]| MAX (2) 式中:N为一周波采样点数;In the formula: N is the number of cycle sampling points; C1,C2,C3,C4为常数,依据区分内部故障和区外故障来确定取值范围,其取值范围为1~10之间;C 1 , C 2 , C 3 , and C 4 are constants, and the value range is determined based on the distinction between internal faults and external faults, and the value range is between 1 and 10; Ie为变压器额定电流;I e is the rated current of the transformer; ρ = η - 3 cos π 20 ms t , η依据《大型发电机变压器继电保护整定计算导则》进行取值; ρ = η - 3 cos π 20 ms t , The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer"; Δi 2(t)MAX为变压器突变量采样值差动电流平方的最大值;Δi 2 (t) MAX is the maximum value of the square of the differential current of the transformer sudden change sampling value; [ΔiM(t)Δi∑-M(t)]|MAX为“变压器各侧突变量电流采样值中的最大值”和“变压器其余侧突变量电流采样值之和”的乘积的最大值;[Δi M (t)Δi ∑-M (t)] | MAX is the maximum value of the product of "the maximum value of the sudden change current sampling value on each side of the transformer" and "the sum of the sudden change current sampling values of the other sides of the transformer"; Δi 2(t)MAX反映了故障的严重程度,[ΔiM(t)Δi∑-M(t)]|MAX反映了故障的性质。Δi 2 (t) MAX reflects the severity of the fault, and [Δi M (t)Δi ∑-M (t)]| MAX reflects the nature of the fault. 2.根据权利要求1所述的突变量采样值变压器差动保护方法,其特征在于:在变压器发生严重故障时,所述差动保护方法的动作时间特性会随着故障电流的大小变化,当动作电流越大,动作速度越快,具有反时限的特性。2. The transformer differential protection method with sudden change sampling value according to claim 1, characterized in that: when a serious fault occurs in the transformer, the operating time characteristic of the differential protection method will change with the magnitude of the fault current, when The larger the action current, the faster the action speed, which has the characteristics of inverse time limit. 3.一种基于权利要求1或2的突变量采样值变压器差动继电器,其特征在于:所述继电器采用突变量电流采样值的差流平方积分和突变量电流采样值等效两侧电流的乘积构成一个高定值的继电器和一个低定值的继电器,其中,3. A transformer differential relay based on claim 1 or 2, characterized in that: said relay adopts the differential current square integral of the sudden change current sampling value and the equivalent two-side current of the sudden change current sampling value The product constitutes a high-set relay and a low-set relay, where, 所述高定值继电器的动作方程如下:The action equation of the high-set value relay is as follows: ΣΔΣΔ ii ΣΣ 22 (( tt )) >> -- CC 11 ΣΔΣΔ ii Mm (( tt )) ΔΔ ii ΣΣ -- Mm (( tt )) ++ (( ρρ ·· II ee )) 22 NN ++ CC 22 ΔΔ ii ΣΣ 22 (( tt )) MAXMAX -- -- -- (( 11 )) 所述低定值继电器的动作方程如下:The action equation of the low fixed value relay is as follows: ∑ΔiM(t)Δi∑-M(t)>C3Ie 2N+C4|[ΔiM(t)Δi∑-M(t)]|MAX(2)∑Δi M (t)Δi ∑-M (t)>C 3 I e 2 N+C 4 |[Δi M (t)Δi ∑-M (t)]| MAX (2) 式中:N为一周波采样点数;In the formula: N is the number of cycle sampling points; C1,C2,C3,C4为常数,依据区分内部故障和区外故障来确定取值范围,其取值范围为1~10之间。C 1 , C 2 , C 3 , and C 4 are constants, and the value range is determined based on the distinction between internal faults and external faults, and the value range is between 1 and 10. Ie为变压器额定电流;I e is the rated current of the transformer; ρ = η - 3 cos π 20 ms t , η依据《大型发电机变压器继电保护整定计算导则》进行取值; ρ = η - 3 cos π 20 ms t , The value of η is determined according to the "Guidelines for Calculation of Relay Protection Setting of Large Generator and Transformer"; Δi 2(t)MAX为变压器突变量采样值差动电流平方的最大值;Δi 2 (t) MAX is the maximum value of the square of the differential current of the transformer sudden change sampling value; [ΔiM(t)Δi∑-M(t)]|MAX为“变压器各侧突变量电流采样值中的最大值”和“变压器其它侧突变量电流采样值之和”的乘积的最大值;[Δi M (t)Δi ∑-M (t)] | MAX is the maximum value of the product of "the maximum value of the current sampling value of the sudden change on each side of the transformer" and "the sum of the sampling values of the sudden change current at other sides of the transformer"; Δi 2(t)MAX反映了故障的严重程度,[ΔiM(t)Δi∑-M(t)]|MAX反映了故障的性质。当所述高定值继电器动作方程满足时,或者所述高定值继电器动作方程不满足而所述低定值继电器动作方程满足时,所述突变量采样值变压器差动继电器动作。Δi 2 (t) MAX reflects the severity of the fault, and [Δi M (t)Δi ∑-M (t)]| MAX reflects the nature of the fault. When the high fixed value relay action equation is satisfied, or when the high fixed value relay action equation is not satisfied but the low fixed value relay action equation is satisfied, the sudden change sampling value transformer differential relay operates.
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CN109390912A (en) * 2018-11-12 2019-02-26 积成电子股份有限公司 Transformer differential protection method based on the long integral of suddenly-change sampling value variable window
CN111244894A (en) * 2020-01-19 2020-06-05 南方电网科学研究院有限责任公司 Protection method and device for transformer winding turn-to-turn short circuit and storage medium
CN111244894B (en) * 2020-01-19 2021-05-14 南方电网科学研究院有限责任公司 Protection method and device for transformer winding turn-to-turn short circuit and storage medium

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