CN101304304A - Dynamic cooperation transmission method for OFDM mobile relay network - Google Patents

Dynamic cooperation transmission method for OFDM mobile relay network Download PDF

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CN101304304A
CN101304304A CNA2008101140579A CN200810114057A CN101304304A CN 101304304 A CN101304304 A CN 101304304A CN A2008101140579 A CNA2008101140579 A CN A2008101140579A CN 200810114057 A CN200810114057 A CN 200810114057A CN 101304304 A CN101304304 A CN 101304304A
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陈朝阳
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Beijing Northern Fiberhome Technologies Co Ltd
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Beijing Northern Fiberhome Technologies Co Ltd
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Abstract

The invention relates to a dynamic cooperative transmission method in OFDM mobile relay network and a reuse greedy resource allocation algorithm adopted in the method. The cooperative transmission can realize the parallel transmission of a plurality of BS/RS in an OFDM signal synchronous and realize the resource reuse between BS and RS. By adopting the reuse greedy resource allocation algorithm, the resource is reused in the maximum degree on one hand, and the problem of pilot frequency collision is solved on the other hand, thus avoiding unusable and vacant resource caused by the pilot frequency collision and realizing high efficient utilization of the resource.

Description

A kind of OFDM moves dynamic cooperation transmission method in the junction network
Technical field
The present invention relates to mobile communication technology, be specifically related to a kind of OFDM and move the greedy resource allocation algorithm of reusing that adopts in the dynamic cooperation transmission method and this method in the junction network.
Background technology
Will adopt the frequency band of 3.4GHZ~3.6GHz in the IMT-Advance mobile communication system, compare with 1.8GHz~2.3GHz frequency band that the 3G mobile communication system adopts, frequency has improved a lot, and path loss will increase greatly.The sub-district of bringing in order to overcome the path loss increase covers the problem of dwindling.Mobile relaying has obtained increasing research as a kind of covering expansion technique.Mobile relaying is a kind ofly can effectively enlarge the wireless network coverage, improves the method for throughput of system.Usually the complexity of RS (relay station) is more much smaller than BS (base station), therefore when satisfied fixed system covering and throughput index request, can reduce the whole lower deployment cost of network by the deployment relay station.In mobile junction network, it is two major issues that utilization of resources and interference are avoided.
At standard IEEE Standard for Local and Metropolitan area networks, Part 16:Air Interferencefor Fixed Broadband Wireless Access System, oct.2004 and IEEE Standard for Local andMetropolitan area networks, Part 16:Air Interface for Fixed and Mobile Broadband WirelessAccess Systems Amendment 2:Physical and Medium Access Control Layers for CombinedFixed and Mobile Operation in Licensed Bands and Corrigendum 1, in the down link OFDMA subcarrier allocation algorithm among the Feb.2006, pilot signal at first is assigned on a plurality of subcarriers, and then carries out the distribution of subchannel data.Owing to do not have the mechanism that pilot tone and subchannel data are connected, so all subchannel datas can utilize all pilot tones to carry out channel estimating.This subcarrier allocation algorithm forbids carrying out simultaneously a plurality of BS/RS transmission in an OFDM (OFDM) symbol, because this mistake that can cause terminal channel to estimate.BS and RS transmission simultaneously in a frequency pilot sign causes the pilot tone case of collision as shown in Figure 1.
In mobile junction network shown in Figure 1, the SS1 terminal belong to the RS relay station and be in the BS base station and RS relay station overlapping covered in; The SS2 terminal belongs to BS and only is in the coverage of BS.Channel response from BS to SS1 is H1 (k), and the channel response from RS to SS1 is H2 (k), and the channel response from BS to SS2 is H3 (k), and wherein k is a user index.RS sends data to SS1 by subchannel data 2, and BS sends data to SS1 by subchannel data 1 simultaneously.BS and RS are inserted into pilot signal in the OFDM symbol.If RS and BS transmit data simultaneously in same OFDM symbol, i.e. parallel transmission, SS1 will be received the pilot signal (from RS, another is from BS) of stack.Therefore SS1 will estimate the pilot channel response of wrong stack, i.e. H1 (k)+H2 (k), and this channel response is used for the SS1 Data Receiving estimates, rather than and the H2 (k) of the correct coupling of data channel response.To reduce the performance of SS1 greatly like this, this problem is called the pilot tone collision.Similarly, the pilot tone collision when sending in an OFDM symbol simultaneously, a plurality of RS relay stations also can take place.The pilot tone collision not only can reduce the performance that terminal correctly receives data, and can reduce the resources effective utilization.Even there is idle resource the BS base station at the OFDM symbol, the RS relay station also can't use this idling-resource.Similarly, even the data of 1 relay station do not take the whole subcarriers in 1 OFDM symbol, the BS base station relay station adjacent with other also can't use residual resource.Therefore need under the prerequisite that does not change terminal operating mode, solve the problem of pilot tone collision, make the shared utilization that realizes resource between the BS/RS effectively.
Summary of the invention
The object of the present invention is to provide a kind of OFDM to move the method for dynamic cooperation transmission in the junction network, the present invention adopts the dynamic cooperation transmission to solve the problem of pilot tone collision on BS base station and RS relay station, if first group of terminal is in the overlapping area of coverage of base station BS and relay station RS, second group of terminal only is in the area of coverage of BS, then in BS in same OFDM symbol and the RS parallel transmission process, BS transmits pilot tone, the data of described first group of terminal and the data of described second group of terminal, the data of RS transmission pilot tone and described first group of terminal; The data of the data of described first group of terminal and described second group of terminal are transmitted in different subchannel datas, are determined by the scheduler program on the BS.
The 3rd group of terminal only is in the area of coverage of RS, and RS also transmits the data of the 3rd group of terminal, and the data of described first group of terminal are transmitted in different subchannel datas with the data of described the 3rd group of terminal, determined by the scheduler program on the BS.
The object of the present invention is to provide a kind of OFDM to move the method for dynamic cooperation transmission in the junction network, the present invention adopts the dynamic cooperation transmission to solve the problem of pilot tone collision on BS base station and RS relay station, if first group of terminal is in the overlapping area of coverage of base station BS and relay station RS, second group of terminal only is in the area of coverage of RS, then in BS in same OFDM symbol and the RS parallel transmission process, the data of BS transmission pilot tone and described first group of terminal, RS transmits pilot tone, the data of described first group of terminal and the data of described second group of terminal; The data of the data of described first group of terminal and described second group of terminal are transmitted in different subchannel datas, are determined by the scheduler program on the BS.
Alternatively, first group of terminal only comprises 1 terminal, and/or second group of terminal only comprises 1 terminal.
Alternatively, the scheduling near BS belong to the terminal of RS the time, as long as satisfy the performance requirement of this terminal, then can reduce the overall transmission power of BS and RS.
In order to make full use of the dynamic cooperation transmission, realize resource reuse and obtain space diversity needing dispatching method flexibly.The present invention discloses a kind of greedy resource allocation algorithm of reusing, and farthest reuses resource on the one hand, avoids as much as possible on the other hand because the resource that the pilot tone collision causes is unavailable and idle, and described resource allocation algorithm of reusing greediness comprises 4 steps:
Step 1: terminal is classified, promptly to the snr value of BS and RS terminal is divided into different classifications according to terminal;
Step 2: determine initial reuse group according to frequency re-use factor FRF;
Step 3: at first according to terminal data what, adjust the terminal in the different initial reuse group, realize channeling as far as possible; Then, different initial reuse group is carried out multiplexing, to utilize all subcarriers of whole OFDM fully.
Step 4: collaborative transmission, promptly determine to be subjected to the terminal that the pilot tone collision influences, calculate pilot tone and data transmission utilization measure that BS and RS go up different terminals, and be accomplished to the collaborative transmission of each terminal.
Preferably, described step 1 comprises: if from the terminal to BS/RS and other the snr value difference of BS/RS greater than a certain threshold value, then this terminal is classified into the terminal in the area of coverage that only is in the top-quality BS/RS of signal to noise ratio, otherwise this terminal is included into the different overlapping areas of coverage according to the snr value difference.
Preferably, described a certain threshold value is 20dB.
Preferably, described step 2 comprises: according to the classification of the terminal from high FRF to low FRF situation, obtain initial reuse group, if a certain terminal belongs to the reuse group of some high FRF, then this terminal should be shifted out from the reuse group of all low FRF.
Preferably, in the described step 3 according to terminal data what, the terminal of adjusting in the different initial reuse group comprises: the terminal in the reuse group of high FRF is moved on in the reuse group of low FRF, vacate corresponding subcarrier, again the terminal in the reuse group of lower FRF is moved on in the reuse group of high FRF, carry out parallel transmission.
One aspect of the present invention has solved the problem of pilot tone collision, avoided since pilot tone to collide the resource that causes unavailable and idle, farthest reuse resource on the other hand, thereby realized the efficient utilization of resource.
Description of drawings
Fig. 1 BS and RS transmission simultaneously in a frequency pilot sign causes the pilot tone collision;
Fig. 2 solves the collaborative transmission of pilot tone collision;
The collaborative transmission of Fig. 3 realizes resource reuse;
Fig. 4 reuses the model that greedy scheduling of resource is used.
Embodiment
Below in conjunction with accompanying drawing and example, the invention will be further described.
As shown in Figure 2, the BS base station at the data D1 of subchannel data φ 1 transmission SS1, sends the data D2 of SS2 at pilot frequency locations pilot signal transmitted P at subchannel data φ 2.The RS relay station is at pilot frequency locations pilot signal transmitted P, and the data D1 in that subchannel data φ 1 sends SS1 does not send data at subchannel data φ 2.Because BS base station and RS relay station are in subchannel data φ 1 collaborative transmission, SS1 just can not run into the pilot tone collision problem again, because SS1 not only receives the pilot tone of collision, but also receives the data of collision.BS can carry out in an OFDM symbol to the transmission of SS1 simultaneously to SS2 and RS, also can avoid because the situation that the idling-resource that the pilot tone collision causes can not be used effectively.When the SS2 of the close BS of scheduling,, can reduce the overall transmission power of BS and RS as long as satisfy the performance requirement of SS2.This method also can reduce the interference to other adjacent cells terminal.
Fig. 3 has provided by collaborative transmission and has realized resource reuse.The BS base station at the data D3 of subchannel data φ 1 transmission SS3, sends the data D1 of SS1 at pilot frequency locations pilot signal transmitted P at subchannel data φ 2.The RS relay station at the data D3 of subchannel data φ 1 transmission SS3, sends the data D2 of SS2 at pilot frequency locations pilot signal transmitted P at subchannel data φ 2.At RS in the transmission course of SS2 and SS3, if SS1 not in the coverage of RS relay station, then can dispatch the BS base station simultaneously to the transmission of SS1.By BS and the RS collaborative transmission to SS3, SS3 just can not run into the pilot tone collision.In addition,,, can also adjust the transmitted power of BS and RS in the collaborative transmission, reduce network interferences by dispatching suitable terminal as while parallel transmission situation.
Usually, a RS relay station can be served a plurality of terminals, wherein some terminal also can receive strong signal from the RS relay station near the RS relay station, and some terminal is positioned at RS and BS covering overlapping area, and these terminals can receive the similar signal of a plurality of intensity from RS, BS and adjacent R S.For these terminals, can obtain space diversity.For the terminal that can only receive 1 strong signal, just there is not space diversity, do not need collaborative transmission yet, distribute to the resource of these terminals and can be reused by BS and contiguous RS.
Need a kind of dynamic cooperation transmission mechanism, adopt collaborative transmission to realize that still resource reuse is by dynamically decision of dispatching algorithm, to obtain the space diversity or the resource reuse of maximum possible terminal.In collaborative transmission course, the power of its pilot tone and transfer of data needs is optimized on BS base station and RS relay station dynamic real-time ground according to signal to noise ratio (snr).By optimizing, also can reduce interference to other cellular cell.
Have under the dynamic cooperation transmission situation in a plurality of transmissions source, for example 1 BS base station and 2 RS relay stations (being respectively RS1 and RS2).Definition: SS InnerTo be better than the terminal that receives signal from BS and RS2 far away for the signal that receives from RS1; SS Middle RS1 ∩ BS ∩ RS2For receive the terminal of the similar signal of intensity from RS1, RS2 and BS; SS Middle RS1 ∩ BSFor the signal strength signal intensity that receives from RS1 and BS is identical, and the more weak terminal of RS2 signal that receives; SS Middle RS1 ∩ RS2For the signal strength signal intensity that receives from RS1 and RS2 similar, and the more weak terminal of signal strength signal intensity that receives from BS.Then at SS Middle RS1 ∩ BS ∩ RS2, SS Middle RS1 ∩ BS, SS Middle RS1 ∩ RS2Termination set closes and obtains space diversity and optimize transmitted power; BS and RS1 are collaborative to SS Middle RS1 ∩ BSIn terminal transmit, RS2 is simultaneously to own terminal transmission; RS1 and RS2 are collaborative to SS Middle RS1 ∩ RS2In terminal transmit, BS is simultaneously to own terminal transmission; RS1 is to SS InnerTransmit, BS and RS2 transmit to the terminal of oneself respectively separately.Owing to adopted collaborative transmission means, the pilot tone collision can not cause performance loss.
Reuse the high efficiency utilization that greedy resource scheduling algorithm is realized resource with model explanation as shown in Figure 4.Concrete steps are as follows:
Step 1: terminal is classified.
Purpose: for the scheduling and resource reuse prepare.
According to different BS/RS transmission situations all terminals are divided into different types.In Fig. 4, have 5 transmission sources, so 31 kinds of different BS/RS transmission situations are arranged.We represent the base station with RS0, and each relay station RS represents (i=1,2,3,4) with RSi, and base station and relay station is unified with RSi (i=0,1,2,3,4) expression.31 kinds of situations are as follows:
5 RSi (i=0,1,2,3,4) transmit simultaneously, a kind of situation;
4 transmission simultaneously among 5 RSi, 5 kinds of situations;
3 transmission simultaneously among 5 RSi, 10 kinds of situations;
2 transmission simultaneously among 5 RSi, 10 kinds of situations;
Any transmission among 5 RSi, 5 kinds of situations.
Can determine under every kind of BS/RS transmission situation the SS of different RSi respectively Inner(the terminal set of each RSi inside) and SS Middle(set of the different RSi of this RSi overlapping region terminal) with other.For terminal is classified, BS need understand the channel situation of terminal to base station BS and relay station RS.Usually,, there is terminal to arrive the SNR information of BS and RS among the BS, can directly be used to carry out the terminal classification for the needs that switch, power is controlled AMC (adaptive modulation and coding).SNR information can also be revised (ranging) process from initial or periodic range finding and obtain.BS and RS detect all distance measuring signals in the range channel, to obtain the signal to noise ratio (snr) of terminal; Simultaneously, relay station RS reports to BS with the result that it records, and then, base station BS can be according to the classification that decides terminal by the signal to noise ratio snr of measuring and report obtains.If from the terminal to BS/RS and other the SNR difference of BS/RS greater than a certain threshold value (as: 20dB), then this user can be classified into the SS of the top-quality BS/RS of SNR InnerOtherwise terminal can be included into different SS according to the SNR difference Middle
Step 2: determine initial reuse group.
Purpose: find out the parallel transmission that all can resource reuse.
According to the classification of the terminal from high FRF (frequency re-use factor) to low FRF situation, obtain initial reuse group.If a certain terminal belongs to the reuse group of some high FRF, then this terminal should be shifted out from the reuse group of all low FRF.
In model shown in Figure 4, have 31 initial reuse group with FRF factor (1~5).Wherein:
The FRF factor equals 51 group; (terminal is in 5 overlay regions that send the source)
The FRF factor equals 45 groups; (terminal is in wherein any 4 overlay regions that send the source)
The FRF factor equals 3 10 groups; (terminal is in wherein any 3 overlay regions that send the source)
The FRF factor equals 2 10 groups; (terminal is in wherein any 2 overlay regions that send the source)
The FRF factor equals 15 groups; (terminal only is in wherein any 1 area of coverage that sends the source)
Initial reuse group is as follows: (FRF=M/N represents the N group of FRF=M, and for example FRF=4/2 represents that the FRF factor equals 4 the 2nd group)
FRF=5/1 SS FRF = 5 / 1 RS 0 = ∩ k = 1,2,3,4 SS inner RS 0 - RSk SS FRF = 5 / 1 RS 1 = ∩ k = 0,2 , 3,4 SS inner RS 1 - RSk SS FRF = 5 / 1 RS 2 = ∩ k = 0,1,3,4 SS inner RS 2 - RSk SS FRF = 5 / 1 RS 3 = ∩ k = 0,1,2,4 SS inner RS 3 - RSk SS FRF = 5 / 1 RS 4 = ∩ k = 0,1,2,3 SS inner RS 4 - RSk
Definition: SS FRF = 5 RS 0 = SS FRF = 5 / 1 RS 0 , SS FRF = 5 RS 1 = SS FRF = 5 / 1 RS 1 , SS FRF = 5 RS 2 = SS FRF = 5 / 1 RS 2 , SS FRF = 5 RS 3 = SS FRF = 5 / 1 RS 3 , SS FRF = 5 RS 4 = SS FRF = 5 / 1 RS 4 .
FRF=4/1 SS FRF = 4 / 1 RS 1 = ∩ k = 2,3,4 SS inner RS 1 - RSk - SS FRF = 5 RS 1 SS FRF = 4 / 1 RS 2 = ∩ k = 1,3,4 SS inner RS 2 - RSk - SS FRF = 5 RS 2 SS FRF = 4 / 1 RS 3 = ∩ k = 1,2,4 SS inner RS 3 - RSk - SS FRF = 5 RS 3 SS FRF = 4 / 1 RS 4 = ∩ k = 1,2,3 SS inner RS 4 - RSk - SS FRF = 5 RS 4
FRF=4/2 SS FRF = 4 / 2 RS 0 = ∩ k = 2,3,4 SS inner RS 0 - RSk - SS FRF = 5 RS 0 SS FRF = 4 / 2 RS 2 = ∩ k = 0 , 3,4 SS inner RS 2 - RSk - SS FRF = 5 RS 2 SS FRF = 4 / 2 RS 3 = ∩ k = 0 , 2,4 SS inner RS 3 - RSk - SS FRF = 5 RS 3 SS FRF = 4 / 2 RS 4 = ∩ k = 0 , 2,3 SS inner RS 4 - RSk - SS FRF = 5 RS 4
FRF=4/3 SS FRF = 4 / 3 RS 0 = ∩ k = 1,3,4 SS inner RS 0 - RSk - SS FRF = 5 RS 0 SS FRF = 4 / 3 RS 1 = ∩ k = 0 , 3,4 SS inner RS 1 - RSk - SS FRF = 5 RS 1 SS FRF = 4 / 3 RS 3 = ∩ k = 0 , 1 , 4 SS inner RS 3 - RSk - SS FRF = 5 RS 3 SS FRF = 4 / 3 RS 4 = ∩ k = 0,1 , 3 SS inner RS 4 - RSk - SS FRF = 5 RS 4
FRF=4/4 SS FRF = 4 / 4 RS 0 = ∩ k = 1 , 2 , 4 SS inner RS 0 - RSk - SS FRF = 5 RS 0 SS FRF = 4 / 4 RS 1 = ∩ k = 0 , 2,4 SS inner RS 1 - RSk - SS FRF = 5 RS 1 SS FRF = 4 / 4 RS 2 = ∩ k = 0 , 1 , 4 SS inner RS 2 - RSk - SS FRF = 5 RS 2 SS FRF = 4 / 4 RS 4 = ∩ k = 0,1 , 2 SS inner RS 4 - RSk - SS FRF = 5 RS 4
FRF=4/5 SS FRF = 4 / 5 RS 0 = ∩ k = 1 , 2 , 3 SS inner RS 0 - RSk - SS FRF = 5 RS 0 SS FRF = 4 / 5 RS 1 = ∩ k = 0 , 2,3 SS inner RS 1 - RSk - SS FRF = 5 RS 1 SS FRF = 4 / 5 RS 2 = ∩ k = 0 , 1 , 3 SS inner RS 2 - RSk - SS FRF = 5 RS 2 SS FRF = 4 / 5 RS 3 = ∩ k = 0,1 , 2 SS inner RS 3 - RSk - SS FRF = 5 RS 3
Definition: SS FRF = 4 RS 0 = SS FRF = 4 / 2 RS 0 + SS FRF = 4 / 3 RS 0 + SS FRF = 4 / 4 RS 0 + SS FRF = 4 / 5 RS 0
SS FRF = 4 RS 1 = SS FRF = 4 / 1 RS 1 + SS FRF = 4 / 3 RS 1 + SS FRF = 4 / 4 RS 1 + SS FRF = 4 / 5 RS 1
SS FRF = 4 RS 2 = SS FRF = 4 / 1 RS 2 + SS FRF = 4 / 2 RS 2 + SS FRF = 4 / 4 RS 2 + SS FRF = 4 / 5 RS 2
SS FRF = 4 RS 3 = SS FRF = 4 / 1 RS 3 + SS FRF = 4 / 2 RS 3 + SS FRF = 4 / 3 RS 3 + SS FRF = 4 / 5 RS 3
SS FRF = 4 RS 4 = SS FRF = 4 / 1 RS 4 + SS FRF = 4 / 2 RS 4 + SS FRF = 4 / 3 RS 4 + SS FRF = 4 / 4 RS 4
FRF=3/1 SS FRF = 3 / 1 RS 0 = ∩ k = 1,2 SS inner RS 0 - RSk - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 SS FRF = 3 / 1 RS 1 = ∩ k = 0,2 SS inner RS 1 - RSk - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 SS FRF = 3 / 1 RS 2 = ∩ k = 0,1 SS inner RS 2 - RSk - SS FRF = 5 RS 2 - SS FRF = 4 RS 2
FRF=3/2 SS FRF = 3 / 2 RS 0 = ∩ k = 1 , 3 SS inner RS 0 - RSk - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 SS FRF = 3 / 2 RS 1 = ∩ k = 0 , 3 SS inner RS 1 - RSk - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 SS FRF = 3 / 2 RS 3 = ∩ k = 0,1 SS inner RS 3 - RSk - SS FRF = 5 RS 3 - SS FRF = 4 RS 3
FRF=3/3 SS FRF = 3 / 3 RS 0 = ∩ k = 1 , 4 SS inner RS 0 - RSk - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 SS FRF = 3 / 3 RS 1 = ∩ k = 0 , 4 SS inner RS 1 - RSk - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 SS FRF = 3 / 3 RS 4 = ∩ k = 0,1 SS inner RS 4 - RSk - SS FRF = 5 RS 4 - SS FRF = 4 RS 4
FRF=3/4 SS FRF = 3 / 4 RS 0 = ∩ k = 2 , 3 SS inner RS 0 - RSk - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 SS FRF = 3 / 4 RS 2 = ∩ k = 0 , 3 SS inner RS 2 - RSk - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 SS FRF = 3 / 4 RS 3 = ∩ k = 0 , 2 SS inner RS 3 - RSk - SS FRF = 5 RS 3 - SS FRF = 4 RS 3
FRF=3/5 SS FRF = 3 / 5 RS 0 = ∩ k = 2 , 4 SS inner RS 0 - RSk - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 SS FRF = 3 / 5 RS 2 = ∩ k = 0 , 4 SS inner RS 2 - RSk - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 SS FRF = 3 / 5 RS 4 = ∩ k = 0 , 2 SS inner RS 4 - RSk - SS FRF = 5 RS 4 - SS FRF = 4 RS 4
FRF=3/6 SS FRF = 3 / 6 RS 0 = ∩ k = 3 , 4 SS inner RS 0 - RSk - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 SS FRF = 3 / 6 RS 3 = ∩ k = 0 , 4 SS inner RS 3 - RSk - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 SS FRF = 3 / 6 RS 4 = ∩ k = 0 , 3 SS inner RS 4 - RSk - SS FRF = 5 RS 4 - SS FRF = 4 RS 4
FRF=3/7 SS FRF = 3 / 7 RS 1 = ∩ k = 2 , 3 SS inner RS 1 - RSk - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 SS FRF = 3 / 7 RS 2 = ∩ k = 1 , 3 SS inner RS 2 - RSk - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 SS FRF = 3 / 7 RS 3 = ∩ k = 1 , 2 SS inner RS 3 - RSk - SS FRF = 5 RS 3 - SS FRF = 4 RS 3
FRF=3/8 SS FRF = 3 / 8 RS 1 = ∩ k = 2 , 4 SS inner RS 1 - RSk - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 SS FRF = 3 / 8 RS 2 = ∩ k = 1 , 4 SS inner RS 2 - RSk - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 SS FRF = 3 / 8 RS 4 = ∩ k = 1 , 2 SS inner RS 4 - RSk - SS FRF = 5 RS 4 - SS FRF = 4 RS 4
FRF=3/9 SS FRF = 3 / 9 RS 1 = ∩ k = 3 , 4 SS inner RS 1 - RSk - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 SS FRF = 3 / 9 RS 3 = ∩ k = 1 , 4 SS inner RS 3 - RSk - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 SS FRF = 3 / 9 RS 4 = ∩ k = 1 , 3 SS inner RS 4 - RSk - SS FRF = 5 RS 4 - SS FRF = 4 RS 4
FRF=3/10 SS FRF = 3 / 10 RS 2 = ∩ k = 3 , 4 SS inner RS 2 - RSk - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 SS FRF = 3 / 10 RS 3 = ∩ k = 2 , 4 SS inner RS 3 - RSk - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 SS FRF = 3 / 10 RS 4 = ∩ k = 2 , 3 SS inner RS 4 - RSk - SS FRF = 5 RS 4 - SS FRF = 4 RS 4
Definition: SS FRF = 3 RS 0 = SS FRF = 3 / 1 RS 0 + SS FRF = 3 / 2 RS 0 + SS FRF = 3 / 3 RS 0 + SS FRF = 3 / 4 RS 0 + SS FRF = 3 / 5 RS 0 + SS FRF = 3 / 6 RS 0
SS FRF = 3 RS 1 = SS FRF = 3 / 1 RS 1 + SS FRF = 3 / 2 RS 1 + SS FRF = 3 / 3 RS 1 + SS FRF = 3 / 7 RS 1 + SS FRF = 3 / 8 RS 1 + SS FRF = 3 / 9 RS 1
SS FRF = 3 RS 2 = SS FRF = 3 / 1 RS 2 + SS FRF = 3 / 4 RS 2 + SS FRF = 3 / 5 RS 2 + SS FRF = 3 / 7 RS 2 + SS FRF = 3 / 8 RS 2 + SS FRF = 3 / 10 RS 2
SS FRF = 3 RS 3 = SS FRF = 3 / 2 RS 3 + SS FRF = 3 / 4 RS 3 + SS FRF = 3 / 6 RS 3 + SS FRF = 3 / 7 RS 3 + SS FRF = 3 / 9 RS 3 + SS FRF = 3 / 10 RS 3
SS FRF = 3 RS 4 = SS FRF = 3 / 3 RS 4 + SS FRF = 3 / 5 RS 4 + SS FRF = 3 / 6 RS 4 + SS FRF = 3 / 8 RS 4 + SS FRF = 3 / 9 RS 4 + SS FRF = 3 / 10 RS 4
FRF=2/1 SS FRF = 2 / 1 RS 0 = SS inner RS 0 - RS 1 - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 - SS FRF = 3 RS 0 SS FRF = 2 / 1 RS 1 = S S inner RS 1 - RS 0 - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 - SS FRF = 3 RS 1
FRF=2/2 SS FRF = 2 / 2 RS 0 = SS inner RS 0 - RS 2 - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 - SS FRF = 3 RS 0 SS FRF = 2 / 2 RS 2 = S S inner RS 2 - RS 0 - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 - SS FRF = 3 RS 2
FRF=2/3 SS FRF = 2 / 3 RS 0 = SS inner RS 0 - RS 3 - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 - SS FRF = 3 RS 0 SS FRF = 2 / 3 RS 3 = S S inner RS 3 - RS 0 - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 - SS FRF = 3 RS 3
FRF=2/4 SS FRF = 2 / 4 RS 0 = SS inner RS 0 - RS 4 - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 - SS FRF = 3 RS 0 SS FRF = 2 / 4 RS 4 = S S inner RS 4 - RS 0 - SS FRF = 5 RS 4 - SS FRF = 4 RS 4 - SS FRF = 3 RS 4
FRF=2/5 SS FRF = 2 / 5 RS 1 = SS inner RS 1 - RS 2 - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 - SS FRF = 3 RS 1 SS FRF = 2 / 5 RS 2 = S S inner RS 2 - RS 1 - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 - SS FRF = 3 RS 2
FRF=2/6 SS FRF = 2 / 6 RS 1 = SS inner RS 1 - RS 3 - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 - SS FRF = 3 RS 1 SS FRF = 2 / 6 RS 3 = S S inner RS 3 - RS 1 - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 - SS FRF = 3 RS 3
FRF=2/7 SS FRF = 2 / 7 RS 1 = SS inner RS 1 - RS 4 - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 - SS FRF = 3 RS 1 SS FRF = 2 / 7 RS 4 = S S inner RS 4 - RS 1 - SS FRF = 5 RS 4 - SS FRF = 4 RS 4 - SS FRF = 3 RS 4
FRF=2/8 SS FRF = 2 / 8 RS 2 = SS inner RS 2 - RS 3 - SS FRF = 5 RS 2 - SS RFR = 4 RS 2 - SS FRF = 3 RS 2 SS FRF = 2 / 8 RS 3 = S S inner RS 3 - RS 2 - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 - SS FRF = 3 RS 3
FRF=2/9 SS FRF = 2 / 9 RS 2 = SS inner RS 2 - RS 4 - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 - SS FRF = 3 RS 2 SS FRF = 2 / 9 RS 4 = S S inner RS 4 - RS 2 - SS FRF = 5 RS 4 - SS FRF = 4 RS 4 - SS FRF = 3 RS 4
FRF=2/10 SS FRF = 2 / 10 RS 3 = SS inner RS 3 - RS 4 - SS FRF = 5 RS 3 - SS RFR = 4 RS 3 - SS FRF = 3 RS 3 SS FRF = 2 / 10 RS 4 = S S inner RS 4 - RS 3 - SS FRF = 5 RS 4 - SS FRF = 4 RS 4 - SS FRF = 3 RS 4
Definition: SS FRF = 2 RS 0 = SS FRF = 2 / 1 RS 0 + SS FRF = 2 / 2 RS 0 + SS FRF = 2 / 3 RS 0 + SS FRF = 2 / 4 RS 0
SS FRF = 2 RS 1 = SS FRF = 2 / 1 RS 1 + SS FRF = 2 / 5 RS 1 + SS FRF = 2 / 6 RS 1 + SS FRF = 2 / 7 RS 1
SS FRF = 2 RS 2 = SS FRF = 2 / 2 RS 2 + SS FRF = 2 / 5 RS 2 + SS FRF = 2 / 8 RS 2 + SS FRF = 2 / 9 RS 2
SS FRF = 2 RS 3 = SS FRF = 2 / 3 RS 3 + SS FRF = 2 / 6 RS 3 + SS FRF = 2 / 8 RS 3 + SS FRF = 2 / 10 RS 3
SS FRF = 2 RS 4 = SS FRF = 2 / 4 RS 4 + SS FRF = 2 / 7 RS 4 + SS FRF = 2 / 9 RS 4 + SS FRF = 2 / 10 RS 4
FRF=1/1 SS FRF = 1 / 1 RS 0 = SS inner RS 0 - SS FRF = 5 RS 0 - SS FRF = 4 RS 0 - SS FRF = 3 RS 0 - SS FRF = 2 RS 0
FRF=1/2 SS FRF = 1 / 2 RS 1 = SS inner RS 1 - SS FRF = 5 RS 1 - SS FRF = 4 RS 1 - SS FRF = 3 RS 1 - SS FRF = 2 RS 1
FRF=1/3 SS FRF = 1 / 3 RS 2 = SS inner RS 2 - SS FRF = 5 RS 2 - SS FRF = 4 RS 2 - SS FRF = 3 RS 2 - SS FRF = 2 RS 2
FRF=1/4 SS FRF = 1 / 4 RS 3 = SS inner RS 3 - SS FRF = 5 RS 3 - SS FRF = 4 RS 3 - SS FRF = 3 RS 3 - SS FRF = 2 RS 3
FRF=1/5 SS FRF = 1 / 5 RS 4 = SS inner RS 4 - SS FRF = 5 RS 4 - SS FRF = 4 RS 4 - SS FRF = 3 RS 4 - SS FRF = 2 RS 4
Wherein, SS Inner RSi-RSkThe expression terminal belong to RSi and be positioned at RSi and the common overlay area of RSk among.
Step 3: mapping.
Purpose: by reasonably dispatching the transmission of BS and each RS flexibly, to obtain the channeling and the effective utilization of resources of maximum possible.
At first,, adjust each terminal in the initial reuse group, realize channeling as far as possible according to sending to what of each terminal data; By the terminal in the high FRF factor set being moved on in the low FRF factor set, vacate corresponding subcarrier, again the terminal in the lower FRF factor set is moved on in the high FRF factor set, carry out parallel transmission.
Secondly, multiplexing different reuse group is with all subcarriers (promptly occupying whole OFDM symbol) that utilize whole OFDM fully.
Step 4: collaborative transmission.
Purpose: solve owing to reuse and the multiplexing pilot tone collision problem that causes.
According to resource reuse and the multiplexed situation on each OFDM symbol, BS knows which terminal need work in coordination with transmission.BS calculates pilot tone and the data transmission utilization measure on the BS and RS in the collaborative transmission, and this weighted value is notified to relay station RS.Then, base station BS and relay station RS are accomplished to the collaborative transmission of each terminal.
More than under be preferred embodiment of the present invention only, be not limited to the present invention, all any modifications of within the present invention spirit and principle, being made, be equal to replacement and improvement etc., all be contained within protection scope of the present invention.

Claims (10)

1, a kind of OFDM moves the method for dynamic cooperation transmission in the junction network, it is characterized in that: if first group of terminal is in the overlapping area of coverage of base station BS and relay station RS, second group of terminal only is in the area of coverage of BS, then in BS in same OFDM symbol and the RS parallel transmission process, BS transmits pilot tone, the data of described first group of terminal and the data of described second group of terminal, the data of RS transmission pilot tone and described first group of terminal; The data of the data of described first group of terminal and described second group of terminal are transmitted in different subchannel datas, are determined by the scheduler program on the BS.
2, the method for claim 1, it is characterized in that, the 3rd group of terminal only is in the area of coverage of RS, RS also transmits the data of the 3rd group of terminal, the data of described first group of terminal are transmitted in different subchannel datas with the data of described the 3rd group of terminal, are determined by the scheduler program on the BS.
3, a kind of OFDM moves the method for dynamic cooperation transmission in the junction network, it is characterized in that: if first group of terminal is in the overlapping area of coverage of base station BS and relay station RS, second group of terminal only is in the area of coverage of RS, then in BS in same OFDM symbol and the RS parallel transmission process, the data of BS transmission pilot tone and described first group of terminal, RS transmits pilot tone, the data of described first group of terminal and the data of described second group of terminal; The data of the data of described first group of terminal and described second group of terminal are transmitted in different subchannel datas, are determined by the scheduler program on the BS.
As claim 1 or 3 described methods, it is characterized in that 4, first group of terminal only comprises 1 terminal, and/or second group of terminal only comprises 1 terminal.
5, as each described method among the claim 1-4, it is characterized in that: the scheduling near BS belong to the terminal of RS the time, as long as satisfy the performance requirement of this terminal, then can reduce the overall transmission power of BS and RS.
As each described method among the claim 1-5, it is characterized in that 6, described scheduler program adopts reuses greedy resource allocation algorithm, this algorithm comprises 4 steps:
Step 1: terminal is classified, promptly to the snr value of BS and RS terminal is divided into different classifications according to terminal;
Step 2: determine initial reuse group according to frequency re-use factor FRF;
Step 3: at first according to terminal data what, adjust the terminal in the different initial reuse group, realize channeling as far as possible; Then, different initial reuse group is carried out multiplexing, to utilize all subcarriers of whole OFDM fully.
Step 4: collaborative transmission, promptly determine to be subjected to the terminal that the pilot tone collision influences, calculate pilot tone and data transmission utilization measure that BS and RS go up different terminals, and be accomplished to the collaborative transmission of each terminal.
7, method as claimed in claim 6, it is characterized in that, described step 1 comprises: if from the terminal to BS/RS and other the snr value difference of BS/RS greater than a certain threshold value, then this terminal is classified into the terminal in the area of coverage that only is in the top-quality BS/RS of signal to noise ratio, otherwise this terminal is included into the different overlapping areas of coverage according to the snr value difference.
8, method as claimed in claim 7 is characterized in that, described a certain threshold value is 20dB.
9, method as claimed in claim 6, it is characterized in that described step 2 comprises:, obtain initial reuse group according to the classification of the terminal from high FRF to low FRF situation, if a certain terminal belongs to the reuse group of some high FRF, then this terminal should be shifted out from the reuse group of all low FRF.
10, method as claimed in claim 6, it is characterized in that, in the described step 3 according to terminal data what, the terminal of adjusting in the different initial reuse group comprises: the terminal in the reuse group of high FRF is moved on in the reuse group of low FRF, vacate corresponding subcarrier, again the terminal in the reuse group of lower FRF is moved on in the reuse group of high FRF, carry out parallel transmission.
CNA2008101140579A 2008-05-30 2008-05-30 Dynamic cooperation transmission method for OFDM mobile relay network Pending CN101304304A (en)

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Cited By (4)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
WO2010081388A1 (en) * 2009-01-14 2010-07-22 大唐移动通信设备有限公司 Method and system for coordinated transmission and a mobile terminal and network side device
WO2010118558A1 (en) * 2009-04-17 2010-10-21 上海贝尔股份有限公司 Method, apparatus and device for selecting relay user and allocating downlink resource
CN101951307A (en) * 2010-09-24 2011-01-19 西安电子科技大学 Method for selecting cell cooperation set under CoMP
CN103167516A (en) * 2011-12-12 2013-06-19 中国移动通信集团设计院有限公司 Method and device for confirming frequency reuse degree in global system for mobile communication (GSM) system

Cited By (7)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
WO2010081388A1 (en) * 2009-01-14 2010-07-22 大唐移动通信设备有限公司 Method and system for coordinated transmission and a mobile terminal and network side device
US8855068B2 (en) 2009-01-14 2014-10-07 China Academy Of Telecommunications Technology Method and system for coordinated transmission and a mobile terminal and network side device
WO2010118558A1 (en) * 2009-04-17 2010-10-21 上海贝尔股份有限公司 Method, apparatus and device for selecting relay user and allocating downlink resource
US9094093B2 (en) 2009-04-17 2015-07-28 Alcatel Lucent Method, apparatus and device for relay user selection and downlink resource allocation
CN101951307A (en) * 2010-09-24 2011-01-19 西安电子科技大学 Method for selecting cell cooperation set under CoMP
CN101951307B (en) * 2010-09-24 2013-01-23 西安电子科技大学 Method for selecting cell cooperation set under CoMP
CN103167516A (en) * 2011-12-12 2013-06-19 中国移动通信集团设计院有限公司 Method and device for confirming frequency reuse degree in global system for mobile communication (GSM) system

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