CN101122376B - High light LED projector production method - Google Patents

Abstract

The invention discloses a manufacture method for a high-brightness LED spot light. The invention is characterized in that a plurality of high-brightness light emitting diodes are arranged on a claw-shaped metal substrate, which is arranged in a light housing. The claw-shaped metal substrate consists of a metal substrate, which extends horizontally to a direction, and bends upwards into a plurality of sections, two sides of which extend outwards and bend upwards symmetrically. Multi-angle irradiation by light emitting diodes is used by the invention to make the LED spot lights meet the basic requirement of brightness and lighting scope as projector lights, and make the photometric curve conform to the standard of the projector light. Thus, the invention is provided with a favorable market prospect.

Description

A kind of manufacture method of high light LED projector

Technical field

The present invention relates to optics, mechanics, person in electronics, specifically a kind of manufacture method of high light LED projector.

Technical background

Energy-conservation, high briliancy that LED has, the characteristic that speed is fast, short distance is shone, the illumination of LED is at present used still in the majority with advertisement at night, traffic sign, automotive lighting etc.Early stage projecting lamp is a lot, though large-area building light projector has its advantage, some zone is not to be well suited for doing light projector, can cause light pollution to environment on every side like that, and what brought after the LED replacement projecting lamp is huge market.LED applies to the characteristics that have energy-conservation, high brightness and polytropy in the commercial advertisement, is fit to the requirement of commercial advertisement, attracts people's notice with its unique polytropy.The white light LEDs luminous efficiency rises year by year, and has the better colour renderings of LED such as more traditional ruddiness, gold-tinted, green glow, can be useful in the living environment that needs rich colors really, and therefore being expected will enter into indoor and outdoor lighting market future.But the employing high-brightness LED that each family releases on the market is the Projecting Lamp of light source, because the deficiency in the optical design of its led light source, make its illuminance value, reach the lighting effect that range of exposures all can not reach early stage projecting lamp, make people substitute early stage projecting lamp and hold the state of looking around the LED Projecting Lamp.

Summary of the invention

At the problem of above-mentioned appearance, the present invention proposes a kind of preparation method of high light LED projector, has fundamentally solved the LED Projecting Lamp as the illuminance of projecting lamp and the basic demand of illumination range, makes its distribution curve flux meet the standard of projecting lamp.

Technical scheme of the present invention

A kind of manufacture method of high light LED projector is installed in a plurality of high-brightness LEDs on the metal substrate of pawl type, and the metal substrate of pawl type is installed in the lamp housing.

The manufacture method of described a kind of high light LED projector, the metal substrate of described pawl type is extended to horizontal direction one side by a metal substrate, and upwards is converted into several sections, and upwards turn up the both sides of each that the folds section metal substrate outside extension of symmetry respectively.

The manufacture method of described a kind of high light LED projector, the metal substrate of described pawl type is extended to horizontal direction one side by longer sides by the metal substrate of a block length square, and upwards be converted into 4 sections, angle between each section is respectively 175 °, 163 °, 171 °, 160 ° from the near to the remote, the both sides of 3 sections metal substrates that fold from far-end respectively symmetry outwards extension upwards turn up, the symmetrical angle that folds is respectively 160 °, 160 °, 166 ° from top to bottom.

The manufacture method of described a kind of high light LED projector, 6 high-brightness LEDs that are with lens of one row evenly are installed on the metal substrate of rectangle, in the horizontal direction on 4 sections metal substrates extending of a side by near to 10,2,2,1 high-brightness LEDs that are with lens far evenly are installed respectively, on the metal substrate of turning up in the both sides of 3 sections metal substrates that fold from far- end 1,2,2 high-brightness LED that is with lens is installed respectively from top to bottom.

Principle of the present invention

Spot light: the size of every light source itself is compared and can be ignored by the distance between the object that shines with it.Spot light is a kind of ideal model. spot light is not mathematical point, but the point on the physical significance, promptly light source itself has certain dimension.

The principle of stacking of light wave: do the time spent simultaneously when the somewhere, space is subjected to two or more light waves, the net amplitude of this place's light vibration, the linear superposition of the complex amplitude vector when should be each light wave to this place independent action.

Two independently light source (two LEDs) be incoherent, just do not return and interference occurs, its mean intensity of closing vibration equals branch oscillation intensity sum.

$\stackrel{\‾}{I}=A_1^2+A_2^2+\mathrm{\Λ}$

Illumination is the physical quantity that characterizes the illuminated degree of area of illumination, concerning spot light:

$E=\frac{\mathrm{Id\&Omega;}}{\mathrm{d\&sigma;}}=\frac{\mathrm{<figure-callout\; id="2"\; label="Ids\; R"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">Ids</figure-callout>}}{R^{}}=\frac{I\cos \mathrm{\&alpha;}}{{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">R</figure-callout>}}^2}$

That is: E ∝ I

E∝A ²

α is the axis direction of light beam and the angle of area of illumination normal.

Luminous intensity is the physical quantity that characterizes the spatial distribution of the luminous flux that light source sends in the certain orientation scope, and the numerical value of the luminous flux that its available point light source sends in unit solid angle is measured.

$I=\frac{\mathrm{d\&Phi;}}{\mathrm{d\&Omega;}}$

As each LED of hypothesis when being a spot light, all characteristics of its corresponding points light source, and the light that LED sends do not produce interference, diffraction phenomena, and the luminous flux of each LEDs and the transmitance of lens all are identical simultaneously.Like this according to the principle of stacking of light and the illuminance formula of spot light, can obtain the n LEDs illuminated object a bit on the illuminance of stack $E_i=\underset{n=\mathrm{0,1,2,3}...}{\mathrm{\&Sigma;}}{E}_{\mathrm{in}};$ Get any 2 points, make its illuminance identical, reach the light effect of uniform; Calculate for convenient, adopt more satisfactory situation, get 2 special points, that is: the point of half of one group of spot center and two groups of angles, Ei=Ei+, $E_i=\underset{n=\mathrm{0,1,2,3}...}{\mathrm{\&Sigma;}}{E}_{\mathrm{in}}=\underset{n=\mathrm{1,2,3}\mathrm{\&Lambda;}}{\mathrm{\&Sigma;}}\frac{I_i\cos {\mathrm{\&alpha;}}_i}{R_i^2}$

$E_i+=\underset{n=\mathrm{0,1,2,3}...}{\mathrm{\&Sigma;}}{E_{\mathrm{in}}}^{\&prime;}=\underset{n=\mathrm{1,2},3\mathrm{\&Lambda;}}{\mathrm{\&Sigma;}}\frac{I_i^{\&Prime;}\mathrm{os}{{\mathrm{\&alpha;}}^{\&prime;}}_i}{R_i^{\&prime;2}}$

$\underset{n=\mathrm{1,2,3}\mathrm{\&Lambda;}}{\mathrm{\&Sigma;}}\frac{I_i\cos {\mathrm{\&alpha;}}_i}{R_i^2}=\underset{n=\mathrm{1,2,3}\mathrm{\&Lambda;}}{\mathrm{\&Sigma;}}\frac{I_i^{\&Prime;}\cos {{\mathrm{\&alpha;}}^{\&prime;}}_i}{R_i^{\&prime;2}}$

With the substitution evaluation method value of trying to achieve: have only three unknown numbers in the formula, wherein two unknown numbers are associated: I and γ, in the substitution formula, try to achieve the E value near the time angle.

When lamp being placed in the distance apart from irradiated body 1.5m, illuminated area is 5m*1.5m, and is even at this area glazing.

The angle that makes lens is θ, $\mathrm{Ri}=\frac{1.5}{\cos \mathrm{\&beta;}}$

$E0=\frac{I\cos \mathrm{\&beta;}}{{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">R</figure-callout>}}^2}+\frac{I\&prime;\&prime;\cos (\mathrm{\&beta;}+2\mathrm{\&epsiv;i})}{{\mathrm{<figure-callout\; id="2"\; label="R"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">R</figure-callout>}}^2}$

$=\frac{I{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3\mathrm{\&beta;}}{{1.5}^2}+\frac{I\&prime;\&prime;{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&beta;}\cos (\mathrm{\&beta;}+2\mathrm{\&epsiv;i})}{{1.5}^2}$

E0+=E01+E11

$=E01+\left(\frac{I\&prime;}{I}\right)E01$

$=(1+\frac{I\&prime;}{I})\frac{I\&prime;{\cos }^3(\mathrm{\&alpha;}+\mathrm{\&beta;}){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2\mathrm{\&gamma;}}{{1.5}^2}$

$\mathrm{\&Theta;E}0=E0+$

Try to achieve with the substitution evaluation method: γ ≈ 10 ⁰

d=R?tan2γ

$=\frac{1.5}{\mathrm{coas}(\mathrm{\&alpha;}+\mathrm{\&beta;})}\tan 2\mathrm{\&gamma;}\&le;0.75$

Solve alpha+beta 〉=41 ⁰

At this moment, there is more light to surpass the scope of 5m*1.5; When the illuminance at the edge of illuminated area was 0.75Ei, promptly angle was θ/4.

When alpha+beta=45 °, θ/4=7.5 °

$d\&prime;=R\tan (2\mathrm{\&gamma;}+\frac{\mathrm{\&theta;}}{4})=\frac{1.5}{\cos {45}^0}*\tan (2\mathrm{\&gamma;}+7.5)\&ap;0.8$

γ≈7 ⁰

If the number of the LED on each face is ni, if γ _i〉=7.5 ⁰ =0; If γ _i15 ⁰

$I_i^{\&prime;}=0;{\mathrm{\&beta;}}_0={16}^0$

$E_i=\frac{n_i{I}_i{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{\mathrm{\&beta;}}_i}{{1.5}^2}+\frac{n_{i+1}{I}_i^{\&prime;\&prime;}\cos ({\mathrm{\&beta;}}_i+2{\mathrm{\&gamma;}}_i){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{\mathrm{\&beta;}}_i}{{1.5}^2}$

$\mathrm{Ei}+=\frac{n_i{I}_i^{\&prime;}\cos {\mathrm{\&beta;}}_i{\cos }^2({\mathrm{\&beta;}}_i+{\mathrm{\&gamma;}}_i)}{{1.5}^2}+\frac{n_{i+1}{I\&prime;}_i\cos ({\mathrm{\&beta;}}_i+2{\mathrm{\&gamma;}}_i){\cos }^2({\mathrm{\&beta;}}_i+{\mathrm{\&gamma;}}_i)}{{1.5}^2}$

By Ei=Ei+

Can try to achieve γ _{I (i=1,2,3,4)}≈ 10 ⁰, 4.5 ⁰, 8.5 ⁰, 2.5 ⁰

β _i＝β _i-1+2γ _i-1

n＝1

Calculate below:

(1)i＝1?β ₁＝16 ⁰

$E_0=\frac{n_1{\mathrm{<figure-callout\; id="1"\; label="I"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">I</figure-callout>}}_1{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3\mathrm{\&beta;}}{{1.5}^2}+\frac{n_2{I\&prime;\&prime;}_1\cos ({\mathrm{\&beta;}}_1+2{\mathrm{\&gamma;}}_1){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{\mathrm{\&beta;}}_1}{{1.5}^2}$

$=\frac{I_1{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{\mathrm{\&beta;}}_1}{{1.5}^2}+\frac{2{I\&prime;\&prime;}_1\cos ({\mathrm{\&beta;}}_1+2{\mathrm{\&gamma;}}_1\mathrm{}){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{\mathrm{\&beta;}}_1}{{1.5}^2}$

$=\frac{I_1{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{16}^0}{{1.5}^2}+\frac{2{I\&prime;\&prime;}_1\cos ({16}^0+2{\mathrm{\&gamma;}}_1){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{16}^0}{{1.5}^2}$

$E0+=\frac{n_1{\mathrm{<figure-callout\; id="1"\; label="I"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">I</figure-callout>}}_1\&prime;\cos {\mathrm{\&beta;}}_1{\cos }^2({\mathrm{\&beta;}}_1+{\mathrm{\&gamma;}}_1)}{{1.5}^2}+\frac{n_2{I\&prime;}_1\cos ({\mathrm{\&beta;}}_1+2{\mathrm{\&gamma;}}_1){\cos }^2({\mathrm{\&beta;}}_1+{\mathrm{\&gamma;}}_1)}{{1.5}^2}$

$=\frac{{\mathrm{<figure-callout\; id="1"\; label="I"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">I</figure-callout>}}_1\&prime;\cos {16}^0{\cos }^2({16}^0+{\mathrm{\&gamma;}}_1)}{{1.5}^2}+\frac{2{I\&prime;}_1\cos ({16}^0+2{\mathrm{\&gamma;}}_1\mathrm{}){\cos }^2({16}^0+{\mathrm{\&gamma;}}_1)}{{1.5}^2}$

Get γ ≈ 12 by E0=E0+ ⁰2 γ=24 ⁰At this moment, blackening will occur, get maximum permissible value γ ≈ 10 in edge ⁰

(2)i＝2 β ₂＝36 ⁰

${\mathrm{<figure-callout\; id="1"\; label="E"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">E</figure-callout>}}_1=\frac{n_2{I}_2{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{\mathrm{\&beta;}}_2}{{1.5}^2}+\frac{n_3{I}_2^{\&prime;\&prime;}\cos {\mathrm{\&beta;}}_2\cos {14}^0{\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{\mathrm{\&beta;}}_2}{{1.5}^2}$

$=\frac{2I_2{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{36}^0}{{1.5}^2}+\frac{{2I}_2^{\&prime;\&prime;}\cos {14}^0{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{36}^0}{{1.5}^2}$

$\mathrm{<figure-callout\; id="1"\; label="E"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">E</figure-callout>}1+=\frac{n_2{I}_2^{\&prime;}\cos {\mathrm{\&beta;}}_2{\cos }^2({\mathrm{\&beta;}}_2+{\mathrm{\&gamma;}}_2)}{{1.5}^2}+\frac{n_3{I\&prime;}_2\cos ({\mathrm{\&beta;}}_2+2{\mathrm{\&gamma;}}_2\mathrm{}){\cos }^2({\mathrm{\&beta;}}_2+{\mathrm{\&gamma;}}_2)}{{1.5}^2}$

$=\frac{2I_2^{\&prime;}\cos {36}^0{\cos }^2({36}^0+{\mathrm{\&gamma;}}_2)}{{1.5}^2}+\frac{2{I\&prime;}_2\cos ({36}^0+2{\mathrm{\&gamma;}}_2){\cos }^2({36}^0+{\mathrm{\&gamma;}}_2)}{{1.5}^2}$

By E1=E1+

Substitution is tried to achieve

γ ₂≈4.5 ⁰

(3)i＝3?β ₃＝45 ⁰

${\mathrm{<figure-callout\; id="2"\; label="E"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">E</figure-callout>}}_2=\frac{n_3{I}_3{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{\mathrm{\&beta;}}_3}{{1.5}^2}+\frac{n_4{I}_3^{\&prime;\&prime;}\cos ({\mathrm{\&beta;}}_3+2{\mathrm{\&gamma;}}_3){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{\mathrm{\&beta;}}_3}{{1.5}^2}$

$=\frac{2I_3{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{45}^0}{{1.5}^2}+\frac{4I_3^{\&prime;\&prime;}\cos ({45}^0+2{\mathrm{\&gamma;}}_3){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{45}^0}{{1.5}^2}$

$\mathrm{<figure-callout\; id="2"\; label="E"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">E</figure-callout>}2+=\frac{n_3{I}_3^{\&prime;}\cos {\mathrm{\&beta;}}_3{\cos }^2({\mathrm{\&beta;}}_3+{\mathrm{\&gamma;}}_3)}{{1.5}^2}+\frac{n_4{I\&prime;}_3\cos ({\mathrm{\&beta;}}_3+2{\mathrm{\&gamma;}}_3){\cos }^2({\mathrm{\&beta;}}_3+{\mathrm{\&gamma;}}_3)}{{1.5}^2}$

$=\frac{2I_3^{\&prime;}{\cos 45}^0{\cos }^2({45}^0+{\mathrm{\&gamma;}}_3)}{{1.5}^2}+\frac{4{I\&prime;}_3\cos ({45}^0+2{\mathrm{\&gamma;}}_3){\cos }^2({45}^0+{\mathrm{\&gamma;}}_3)}{{1.5}^2}$

Try to achieve γ by the E2=E2+ substitution ₃≈ 8.5 ⁰

(4)i＝4 β ₄＝62 ⁰

${\mathrm{<figure-callout\; id="3"\; label="E"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">E</figure-callout>}}_3=\frac{n_4{I}_4{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{\mathrm{\&beta;}}_4}{{1.5}^2}+\frac{n_5{I}_4^{\&prime;\&prime;}\cos ({\mathrm{\&beta;}}_4+2{\mathrm{\&gamma;}}_4){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{\mathrm{\&beta;}}_4}{{1.5}^2}$

$=\frac{10I_4{\mathrm{<figure-callout\; id="3"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^3{62}^0}{{1.5}^2}+\frac{6I_4^{\&prime;\&prime;}\cos ({62}^0+2{\mathrm{\&gamma;}}_4){\mathrm{<figure-callout\; id="2"\; label="cos"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">cos</figure-callout>}}^2{62}^0}{{1.5}^2}$

$\mathrm{<figure-callout\; id="3"\; label="E"\; filenames="S06141171420060825E000011.png"\; state="\{\{state\}\}">E</figure-callout>}3+=\frac{n_4{I}_4^{\&prime;}\cos {\mathrm{\&beta;}}_4{\cos }^2({\mathrm{\&beta;}}_4+{\mathrm{\&gamma;}}_4)}{{1.5}^2}+\frac{n_5{I\&prime;}_4\cos ({\mathrm{\&beta;}}_4+2{\mathrm{\&gamma;}}_4){\cos }^2({\mathrm{\&beta;}}_4+{\mathrm{\&gamma;}}_4)}{{1.5}^2}$

$=\frac{10I_4^{\&prime;}\cos {62}^0{\cos }^2({62}^0+{\mathrm{\&gamma;}}_4)}{{1.5}^2}+\frac{n_5{I\&prime;\&prime;\&prime;}_4\cos ({62}^0+2{\mathrm{\&gamma;}}_4){\cos }^2({62}^0+{\mathrm{\&gamma;}}_4)}{{1.5}^2}$

Try to achieve γ by the E3=E3+ substitution ₄≈ 2.5 ⁰

Effect of the present invention

The present invention adopts multi-angle LED irradiation to make the LED Projecting Lamp as the illuminance of projecting lamp and the basic demand of illumination range, makes its distribution curve flux meet the standard of projecting lamp, has market prospects preferably.

Description of drawings

Fig. 1 internal structure schematic diagram of the present invention.

Fig. 2 metal substrate structural representation of the present invention.

Fig. 3 light structures schematic diagram of the present invention.

Fig. 4 principle schematic of the present invention.

Fig. 5 principle schematic of the present invention.

The specific embodiment:

Referring to Fig. 1～5.A kind of manufacture method of high light LED projector, the aluminium sheet 4 of one block length square is extended to horizontal direction one side by longer sides, and upwards be converted into 4 sections aluminium sheets 5, aluminium sheet 6, aluminium sheet 7, aluminium sheet 8, making the angle between aluminium sheet 4 and the aluminium sheet 5 is 175 °, angle between aluminium sheet 5 and the aluminium sheet 6 is 163 °, angle between aluminium sheet 6 and the aluminium sheet 7 is 171 °, angle between aluminium sheet 7 and the aluminium sheet 8 is 160 °, with aluminium sheet 6, aluminium sheet 7, upwards turn up the both sides of the aluminium sheet 8 outside extension of symmetry respectively, fold the aluminium sheet 9 of symmetry, aluminium sheet 10, aluminium sheet 11, making the angle between aluminium sheet 9 and the aluminium sheet 8 is 160 °, making the angle between aluminium sheet 10 and the aluminium sheet 7 is 160 °, and making the angle between aluminium sheet 11 and the aluminium sheet 6 is 166 °.The high-brightness LED 2 that is with lens 3 is installed on the aluminium sheet 1,6 high-brightness LEDs 2 of one row are installed on the aluminium sheet 4,5 high-brightness LEDs 2 of two rows are installed on the aluminium sheet 5,2 high-brightness LEDs 2 of one row are installed in respectively on aluminium sheet 6, aluminium sheet 7, aluminium sheet 10, the aluminium sheet 11,1 high-brightness LED 2 of one row is installed in respectively on aluminium sheet 8, the aluminium sheet 9, all is with lens 3 on all high-brightness LEDs 2.There is the aluminium sheet 1 of high-brightness LED 2 to be installed in the lamp housing whole erection, and is connected with drive circuit.

Claims (1)

1. the manufacture method of a high light LED projector, it is characterized in that: a plurality of high-brightness LEDs are installed on the metal substrate of pawl type, and the metal substrate of pawl type is installed in the lamp housing, the metal substrate of described pawl type is extended to horizontal direction one side by a metal substrate, and upwards be converted into several sections, upwards turn up the both sides of each that the folds section metal substrate outside extension of symmetry respectively, the technology substrate of described pawl type is extended to horizontal direction one side by longer sides by the square metal substrate of a block length, and upwards be converted into 4 sections, angle between each section is respectively 175 ° from the near to the remote, 163 °, 171 °, 160 °, the both sides of 3 sections metal substrates that fold from far-end respectively symmetry outwards extension upwards turn up, the symmetrical angle that folds is respectively 160 ° from top to bottom, 160 °, 166 °, 6 high-brightness LEDs that are with lens of one row evenly are installed on rectangular metal substrate, evenly install 10 by near respectively to far away on 4 sections metal substrates that a side is extended in the horizontal direction, 2,2,1 high-brightness LED that is with lens installs 1 respectively from top to bottom on the metal substrate of turning up in the both sides of 3 sections metal substrates that fold from far-end, 2,2 high-brightness LEDs that are with lens.

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