CN100461825C - Page returning method for electronic program list navigation - Google Patents

Page returning method for electronic program list navigation Download PDF

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Publication number
CN100461825C
CN100461825C CN 200710000732 CN200710000732A CN100461825C CN 100461825 C CN100461825 C CN 100461825C CN 200710000732 CN200710000732 CN 200710000732 CN 200710000732 A CN200710000732 A CN 200710000732A CN 100461825 C CN100461825 C CN 100461825C
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page
stack
return
home
returned
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CN101005566A (en
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王国俊
龚文强
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中兴通讯股份有限公司
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Abstract

本发明公开了一种用于电子节目单导航的页面返回方法。 The present invention discloses an electronic program guide pages for return navigation method. 步骤S102,设置用于存储页面参数的堆栈;步骤S104,访问电子节目单导航的首页时,首页的参数被压入堆栈;步骤S106,当访问当前页面上的链接时,进入链接对应的页面后,所进入的页面的参数被压入堆栈;步骤S108,当在当前页面选择了返回操作时,首先将当前堆栈的栈顶元素弹出,然后返回最新的栈顶元素,根据所返回的栈顶元素生成返回页面的链接,进入所返回的页面,返回至步骤S106。 Step S102, the page is provided for storing the parameter stack; step S104, when access to the electronic program navigation single home, home parameters are pushed onto the stack; step S106, when the access link on the current page, enter the page corresponding to the link , parameters of the incoming page is pushed onto the stack; step S108, if the page selects the return operation, the first current stack pop the top element in the current, and then returns the latest top element, the top element is returned by the generate a return linked pages, enter the page returned, returns to step S106. 通过在EPG后台上实现一种通用的页面返回方法,从而让用户通过遥控器按键就能够有效地遍历所有的EPG页面链接。 After the EPG table implemented by a general method that returns the page, allowing the user through the remote control keys can be effectively traverse all EPG page links.

Description

用于电子节目单导航的页面返回方法 Page for electronic program navigation of return method

技术领域 FIELD

本发明涉及网络电视技术,尤其涉及一种用于电子节目单导航的页面返回方法。 The present invention relates to a network television technology, and particularly relates to an electronic program guide pages for return navigation method.

背景技术 Background technique

EPG ( Electronic Program Guide,电子节目单导4元)是IPTV (网络电视)系统的门户,是系统与用户的接口。 EPG (Electronic Program Guide, electronic program guide 4 million) portal IPTV (network TV) system, the system interface with the user. 它的主要任务是为用户提供业务的入口服务,是直接呈现给用户的界面,是供用户选择的系统月艮务索引。 Its main task is to provide users with the business portal service, is directly presented to the user interface is for users to choose a system that works to monthly index. 目前EPG主要是运行在神几顶盒的硬件环境下,釆用Web技术来实现,这种环境下实现的EPG的主要特点是:所实现的EPG是一种无状态的系统交互,用户主要通过页面上的链接来进行页面的迁移;另外,基于机顶盒技术的一个显著的特点是,用户操作界面的手段主要是采用遥控器来进行。 Currently EPG is mainly running in a few top box hardware environment of God, preclude the use of Web technology to achieve the main features of the EPG is implemented in this environment: EPG is achieved by a stateless system interaction, primarily through user links on the page to the page migration; Furthermore, significant characteristics are based on a set-top box technology, the user interface means is mainly used for remote control.

用户在进行页面的迁移时,就涉及到一个页面回退的问题。 When the user during the migration page, it involves the issue of a page rollback. 在基于PC的WEB浏览器上,用户对页面的回退#:作可以通过浏览器提供的输入框来重新定位于所需的位置上或者通过浏览器提供的回退按4丑来选择回退点。 On the PC WEB browser, the user pages based fallback #: as an input box provided by the browser to re-locate back-off to the desired location on or provided through the browser Press 4 to select a fallback ugly point. 但在基于^/L顶盒和遥控器^t安键操作的用户环境下,上述两者方案都不成立:机顶盒内嵌的浏览器没有^是供菜单或者输入框来让用户进行重新定位输入,它实际上就是一个全屏的浏览模式,这是因为首先遥控器进行输入操作不方便,并且用户也无法知道也不必知道具体的位置链接;另外EPG系统提供的是 However, in the user environment based on ^ / L-top box and a remote control key ^ t safe operation, both of the above-described embodiment does not hold: a set top box embedded browser menu is available or not ^ input box to allow the user to reposition the input, it is actually a full-screen browsing mode, because the first remote control for convenient input operation, the user can not know and do not know the specific location of the link; another EPG system is provided

一纟且预定义好迁移关系的页面,每个页面的返回点不一定,尤是上次浏览的那个页面。 Si and a good migration predefined page relationships, not necessarily point to return every page, especially that last visited that page.

这样,在WEB服务器的后台来实现一种针对于EPG应用特点的回退返回才几制就成为必要。 Thus, in the background WEB server to achieve a return to the EPG application for refund return only a few of the characteristics of the system becomes necessary.

发明内容 SUMMARY

本发明的主要目的在于提供一种用于电子节目单导航的页面返回方法,用于通过在EPG后台上实现一种通用的页面返回方法, 从而让用户通过遥控器按键就能够有效地遍历所有的EPG页面链接。 The main object of the present invention is to provide an electronic program guide pages for return navigation method implemented for the stage after the EPG by a general method that returns the page, allowing the user through the remote control keys can be effectively traverse all EPG page link.

为了实现上述目的,本发明提供了一种用于电子节目单导航的页面返回方法。 To achieve the above object, the present invention provides an electronic program guide pages for return navigation method. i亥页面返回方'法包4舌以下步骤: Back side Hai Page i 'French bread tongue 4 steps:

步骤S102,设置用于存储页面参数的堆栈; Step S102, the page is provided for storing the parameter stack;

步骤S104,访问电子节目单导航的首页时,首页的参数被压入 Step S104, when access to the electronic program navigation single home, home parameters are pressed

堆栈; Stack;

步骤S106,当访问当前页面上的链接时,进入链接对应的页面后,所进入的页面的参数;故压入堆栈; After step S106, when the access link on the current page, enter the page corresponding to the link, parameters entered page; it onto the stack;

步骤S108,当在当前页面选择了返回操作时,首先将当前堆栈的栈顶元素弹出,然后返回弹出栈顶元素以后剩下的栈顶元素,才艮才居所返回的才戈顶元素生成返回页面的链4妻,进入所返回的页面,返回至步骤S106。 Step S108, when the current page is selected in the returning operation, the first current stack pop the top element, the top element and then returns the remaining elements pop stack only after returning home Burgundy was only generate a return page Ge top element wife chain 4, enter the page returned, the process returns to step S106.

进一步地,通过外几顶盒来访问电子节目单导航的首页、当前页面上的链接、以及通过机顶盒在当前页面选择返回操作。 Further, access to a single electronic navigation programs outside the home by a few top box, the links on the current page, and set-top box by selecting the page in the current return operation.

进一步地,首页的参数是栈底元素,当堆栈中只存在首页的参数时,出栈操作只包括返回首页的参数。 Further, the bottom of the stack parameters are home element when the parameter is present only in the home stack, the stack operation comprises only the Home parameters.

优选地,在步骤S106中,当所进入的页面的参凄t将^皮压入堆 Preferably, in step S106, when the parameter t sad enters a page stack is pressed into the skin ^

则将存在位置之上的所有元素弹出,再将所进入的页面的参lt压入堆栈。 All elements will be present on the pop-up position, and then enters the reference lt pages onto the stack.

进一步地,电子节目单导航的页面之间的链接是树形结构。 Further, the link between the electronic single page navigation program is a tree structure.

进一步地,在页面上设置返回标签,用于进行返回操作的选择。 Further, return tab provided on the page, the return operation for selection.

优选地,在步骤S108中,进入所返回的页面后,所进入的页面的参数不被压入堆栈。 Preferably, in step S108, after entering the page returned, enter the parameters of the page is not pushed onto the stack. 通过设置返回标识,来区分进入链接的页面还是进入返回的页面,如果是进入链接的页面,则执行入栈操作, 如果是进入返回的页面,则不4丸行入栈4乘作。 By setting the return identifier to distinguish the page to enter the link into the page or return, if it is to enter the linked pages, the execution stack operation, if it is returned into the page, not the stack 4 by 4 pill line for.

页面参凄t可以包4舌页面访问路径。 Page 4 may be coated parameter t sad tongue page access path.

可以通过页面Tag元素来触发入栈4喿作和出栈才喿作。 It can be triggered as a stack 4 Qiao Tag and popped through page elements just as Qiao.

通过上述冲支术方案,本发明的EPG页面之间的返回方法祐:才由象和封装成了一个普通的链接形式,这样页面上完全不用考虑返回的实现细节,而只需通过在页面上放置一个返回的标签就可实现到上一级页面的返回。 By supporting the punching operation program, the EPG pages between the return process of the invention Woo: was made and packaged in a form like a normal link, so that the page no need to consider the return of the implementation details, but only by the page placing a tag can be implemented to return a page return.

附图说明 BRIEF DESCRIPTION

此处所说明的附图用来提供对本发明的进一步理解,构成本申,清的一部分,本发明的示意性实施例及其"i兌明用于解释本发明,并不构成对本发明的不当限定。在附图中:图1是根据本发明的用于电子节目单导航的页面返回方法的流 The drawings described herein are provided for further understanding of the invention, the present application, form part of the clear, exemplary embodiments of the present invention and the "i against the next, serve to explain the present invention without unduly limiting the present invention. in the drawings: FIG. 1 is a method according to the page to return to navigation of the electronic program stream according to the invention

程图; Chart;

图2是根据本发明实施例的EPG页面链接迁移抽象模型图; FIG 2 is a view of a link migration EPG page abstract model of an embodiment of the present invention;

以及 as well as

图3是根据本发明实施例的EPG页面返回机制运行顺序图。 FIG 3 is a sequence diagram showing operation of the mechanism based on the EPG page return an embodiment of the present invention. 具体实施方式 Detailed ways

下面将参考附图详细说明本发明。 The present invention will be described in detail below with reference to the accompanying drawings.

参照图1,根据本发明的用于电子节目单导航的页面返回方法包4舌以下步骤: Referring to FIG 1, the package according to the steps of the tongue 4 to the page of the electronic program navigation method according to the invention Returns:

步骤S102,设置用于存储页面参数的堆栈。 Step S102, the stack is provided for storing the page parameter.

步骤S104,访问电子节目单导航的首页时,首页的参数被压入堆栈。 Step S104, when accessing a single electronic navigation program Home Home parameters are pushed onto the stack.

步骤S106,当访问当前页面上的链4妄时,进入链4妾对应的页面后,所进入的页面的参翁j皮压入堆栈。 After step S106, when the chain 4 on the current page Access jump into the chain 4 concubine corresponding page, the page reference Weng enters the skin j pushed onto the stack.

优选地,当所进入的页面的参数将^皮压入堆栈时,判断所进入的页面的参数是否已经在堆栈中存在,如果存在,则将存在位置之上的所有元素弹出,再将所进入的页面的参数压入堆栈。 Preferably, when the parameters of the page enters the skin ^ onto the stack, the parameter determination enters the page already exists in the stack, if present, will be all the elements present above the eject position, and then enters page parameters onto the stack.

步骤S108,当在当前页面选择了返回操作时,首先将当前堆栈的栈顶元素弹出,然后返回最新的栈顶元素,4艮据所返回的栈顶元素生成返回页面的链4妄,进入所返回的页面,返回至步-骤S106。 Step S108, when the current page is selected in the returning operation, the first current stack pop the top element, and then returns the latest top element 4 according Gen returned top element 4 generates a return jump to the page chain into the return to a page, go back to step - step S106.

优选地,进入所返回的页面后,所进入的页面的参数不被压入堆栈。 Preferably, after entering the page returned, enter the parameters of the page is not pushed onto the stack. 通过i殳置返回标识,来区分进入链4矣的页面还是进入返回的页面,如杲是进入链接的页面,则执行入栈操作,如果是进入返回的页面,则不执行入栈操作。 Shu set identifier returned by i, to distinguish the page into the carry chain of 4 or returned into the page, such as page links entering Gao, push operation is performed, if it is returned into the page, the stack operation is performed.

进一步地,通过才几顶盒来访问电子节目单导4元的首页、当前页面上的链4矣、以及在当前页面选择返回才乘作。 Further, to access the electronic program guide by only a few top box 4 yuan Home, 4 chains carry on the current page, and return it take for the current page selection.

进一步地,首页的参数是栈底元素,当堆栈中只存在首页的参数时,出栈操作只包括返回首页的参数。 Further, the bottom of the stack parameters are home element when the parameter is present only in the home stack, the stack operation comprises only the Home parameters.

进一步地,电子节目单导航的页面之间的链接是树形结构。 Further, the link between the electronic single page navigation program is a tree structure.

进一步地,在页面上设置返回标签,用于进行返回操作的选择。 Further, return tab provided on the page, the return operation for selection.

页面参凄t可以包4舌页面访问路径。 Page 4 may be coated parameter t sad tongue page access path.

可以通过页面Tag元素来触发入栈操作和出栈操作。 Push operation and can be triggered by the pop operations page Tag elements. 本发明涉及IPTV技术,特别涉及EPG页面回退技术。 The present invention relates to IPTV technology, in particular, to roll back technology EPG page.

页面返回需要在EPG后台上来实现的原因是机顶盒内嵌的浏览器没有像IE —样的菜单或者工具栏之类的方法提供给用户来进4亍页面的回退,这才羊用户在页面迁移时,只能朝着一个方向前进, 而页面的回退需要由EPG后台来进4亍4空制。 EPG reason to return to the page in the background up to achieve the set-top box embedded browser did not like IE - like menus or toolbars such method available to the user to roll back into the right foot of the page 4, this sheep user page migration when only one direction forward, and page rollback required by the EPG come back into right foot 4 4 empty system.

针对于EPG页面的特点,用户访问页面之间的链接关系可以抽象成树形结构。 According to the characteristics in the EPG pages, links between the user access the page can be abstracted into a tree structure. 如图2所示,用户首先访问的是EPG首页,它是树形结构的根节点,然后通过首页提供的链接一层一层的往下访问,如果需要从某个节点访问树中的任何一个其它节点,要么该节点提供了到该节点的直接链接,要么从该节点回退到更高的层次, 2, the user first accesses the EPG home page, which is the root of the tree structure, then access down layer by layer by providing a home link, if any need to access a particular node of the tree other nodes, or the node provides a direct link to the node, or fall back to a higher level from the node,

然后从那个地方进入到目标节点。 Then enter from that place to the destination node. 如果EPG页面上存在列表展示, 可能会涉及到翻页的情况,但无i仑用户翻了多少页,它始终是停留在当前页面对应的节点上,这种情况对应的是图2中最左边倒数第2个节点的循环线,这个时候如果用户进行回退,从逻辑上来说应该是回到进入该节点的上一个节点,而不是回到用户刚才翻页的那个节点上,所以对于页面存在翻页的这种链接,在图2上就抽象成指向自己的一个链接。 If there is a list showing the EPG page, may be related to the case flip, but no i turned Lun user how many pages it is always stays on the page corresponding to the current node, corresponds to this case is the left in Figure 2 Circular penultimate two nodes, this time if the user rollback, logically it should be entered on a return to that node, rather than back to the node just flip the user, so the page exists this page link, in FIG. 2 are abstracted into a link pointing to own. 另外对于一些页面可能会存在多个地方进入,那么从这个页面返回时,应该是回到进入它的那个页面。 In addition to some pages may be multiple places to enter, so when returning from this page, it should be returned to enter that page.

根据上述分析,在基于机顶盒访问网页的应用环境中,本发明提供了一种页面返回的实现方法,该方法的核心是在EPG的服务器上实现一种类似于堆栈的数据结构,它是一种特殊的堆栈,它的操作步骤如下: According to the above analysis, the set-top box-based application environment to access the page, the present invention provides a method for implementing a return page, the core of the method is to achieve a similar stack on the EPG server data structure, which is a special stack, which steps are as follows:

1、 神几顶盒访问EPG的首页,首页的参凌t入栈,首页是栈底元素,当栈中只存在该元素时,出栈操作只是返回该元素,不再做其它操作; 1, several God-top box to access EPG home, home t Ling reference stack, a home bottom of the stack element, when there is only the element stack, pop operation just returns the element, no longer do other operations;

2、 机顶盒访问首页上的链接,进入该链4妻对应的页面后,该页面的参^t入栈; 2, the set-top box to access the home link, the chain 4 entering the wife corresponding page that ^ t parameter stack;

3、 按照步骤2,访问的页面净皮不断的压入堆对戋中,在压冲戋的时候,需要做如下的判断:首先判断当前要压栈的页面是否已经在堆栈中存在,如果存在那么堆栈将该位置及其之上的所有记录都从堆栈中弹出,然后将当前的页面压栈; 3. Follow steps 2, page trim leather visited constantly pushed on the stack constricted, the time pressure washed constricted, we need to make the following judgment: first determine whether the current push to the page already exists in the stack, if there is then all the records and their location on the stack are popped from the stack, then push the current page;

4、 如果在当前页面用户选择了返回操作,那么EPG首先将当前堆栈的栈顶元素弹出,然后返回最新栈顶的元素;EPG根据返回的元素来生成返回页面的链接。 4. If you chose to return to operation in the current page user, the EPG first current pop the top element of the stack, and then return to the elements of the latest top of the stack; EPG to generate a return link to the page based on the elements returned.

采用上述逻辑来实现EPG页面访问路径的上下文^f呆存,具有如下特点:EPG页面之间的链接是一种树形结构,但用户的访问路径可以看作是线性结构,这种结构是一种特殊的堆栈结构,之所以采用这个特殊的堆栈结构, 一方面是堆栈的栈顶元素是在用户进行页面迁移时才能产生,但是产生的元素却不属于用户访问路径中的元素,它只有在用户进一步操作时才是有效的数据元素。 Logic to implement the above-described EPG page access path context memory stay ^ f, with the following characteristics: the link between EPG page is a tree structure, but the user's access path can be regarded as a linear structure which is a a special kind of stack structure, the reason for using this particular stack structure, on the one hand is the top element of the stack can be generated when a user page migration, but does not belong to the elements generated elements of the user access path, it is only in data element is valid when the user further operates. 对于在压 For the press

堆栈长度的不断增加,同时也^f呆i正返回逻辑的正确性。 Increasing the length of the stack, while also being returned i ^ f stay correctness of the logic.

本发明首先需要实现的是上述的堆栈结构,根据图2所描述的页面链接迁移模型,我们可以认为它是简单的树形结构,对于树形结构的访问,我们是按照深度优先的原则来遍历整个树上的节点的,那么支持这种访问所需要的辅助数据结构就是需要一个堆栈来i己录用户的i方问路径。 First, the present invention is required to achieve the above-described stacked structure, according to the page link migration model described in FIG 2, we can assume that it is a simple tree, access to a tree structure, according to the principle we are depth-first traversal to the entire tree node, then the auxiliary data structure to support such access is needed is a need to stack i i already record the user's side asked path.

这个堆栈需要提供的操作主要有两个:入栈和出栈,图3描述了操作堆栈的顺序图,但这两个操作和标准堆栈相应的操作逻辑有区别: The operation of this need to provide a stack of two main reasons: pushing and popping, FIG. 3 depicts a sequence diagram of the operand stack, but two respective logical operations and operation standards stacks are different:

对于出栈操作,我们知道在进入某个页面时,首先我们必须将这个页面的请求参凄t压入堆栈,^f旦是当从这个页面返回的时候,需要执行一个出栈操作,这个操作应该是首先弹出栈顶元素丢弃,然后在获取当前栈顶元素,作为出栈操作的返回值。 For pop operations, we know that when entering a page, we must first request the page parameter sad t pushed onto the stack, ^ f is when Dan returned from this page, you need to perform a pop operation, this operation first pop the top element should be discarded, then get the current top of the stack, the stack as a return value of the operation.

对于入栈操作,首先我们需要判断栈中是否存在和当前要入栈元素相同标识的元素,如果存在,表示当前入栈操作是从一个很深 For incoming operation, the first thing we need to determine whether there is a current stack element to identify the same elements of the stack, if present, indicates that the current operation is from a deep stack

抛弃,然后再将该元素入栈。 Abandoned, then the element stack. 这样就避免栈中元素无限制的增长。 This prevents the stack of elements unlimited growth.

在实现了上述堆栈结构之后,接下来需要考虑的就是如何和 In the realization of the above stack structure, you need to consider is how and

Web这种技术特点相结合的问题,首先我们需要考虑这样一个问题,当我们要返回到上一个页面的时候,需要执行一个出栈操作, 同时在进入返回的那个页面的时候又需要执行一个入栈操作,但这个操作需要的数据其实就是当前栈顶的元素,所以在页面返回的时 This Web technology features a combination of problems, first of all we need to consider the question, when we want to return to the previous page when you need to perform a pop operation, but also need to be performed when entering the pages of a return of the data stack operation, but the operation requires a current element is actually the top of the stack, so when the page is returned

候,入栈操作是不必要的,但EPG在冲丸行入栈操作的时候并不能区 Waiting, incoming operation is not necessary, but can not EPG area when the red pill row stack operation

作,所以EPG在实现返回的时候,需要设置一个标志来区分这种情况,为了不影响原来堆栈内的内容,该标志可以通过Web服务器所支持的Session机制来传递。 For, so EPG in the realization of return, you need to set a flag to distinguish this case, in order not to affect the contents of the original stack, this flag Session mechanism supported by the Web server to deliver.

在EPG页面上,需要触发堆栈的两个操作, 一个是页面参数压栈操作,另外一个就是页面参数出栈操作,这些操作可以封装成标准的页面Tag元素。 On the EPG page, two triggers requires the operand stack, page one is a push operation parameter, a further parameter page is the stack of operations that can be encapsulated into a standard Tag page elements.

图3描述了页面压栈和页面出栈的流程: 3 depicts a page and page push the stack of flow:

201客户端向EPG服务器发起页面请求; 201 client initiates the page request to the EPG server;

202 EPG服务器获取请求参数,生成一个堆栈中的对象来保存这些参数; 202 EPG server acquires the request parameters, generate a stack of objects to save these parameters;

203 EPG服务器将该对象压入堆栈中; 203 EPG server in the object onto the stack;

204堆栈#4居上述描述的入栈失见则将该对象压入堆栈; Stack 204 # 4 ranks as described above and the object is to see out of the stack onto the stack;

205 EPG服务器响应页面请求; 205 EPG server responds to the page request;

206客户端向EPG服务器发起页面返回请求; 206 client initiates the page request to return to the EPG server;

207 EPG月良务器乂人堆4戋中弹出4戋顶元素;208 EPG月艮务器#»据弹出栈顶元素构建一个目标页面的i青求; 207 EPG service is good qe Rendui May 4 constricted constricted pop top element 4; 208 EPG month that works to filter # »pop stack data elements to build a green target page i demand;

209 EPG月良务器将目标页面的i青求发给客户端进行重定向。 209 EPG month good business page i will target youth seeking to redirect to the client.

以上所述<又为本发明的优选实施例而已,并不用于限制本发明,对于本领域的技术人员来说,本发明可以有各种更改和变化。 The above <further preferred embodiment of the present invention, but not intended to limit the invention to those skilled in the art, the present invention may have various changes and variations. 凡在本发明的精神和原则之内,所作的任何修改、等同替换、改进等,均应包含在本发明的保护范围之内。 Any modification within the spirit and principle of the present invention, made, equivalent substitutions, improvements, etc., should be included within the scope of the present invention.

Claims (10)

1. 一种用于电子节目单导航的页面返回方法,其特征在于,包括以下步骤: 步骤S102,设置用于存储页面参数的堆栈; 步骤S104,访问电子节目单导航的首页时,所述首页的参数被压入所述堆栈; 步骤S106,当访问当前页面上的链接时,进入所述链接对应的页面后,所进入的页面的参数被压入所述堆栈; 步骤S108,当在当前页面选择了返回操作时,首先将当前所述堆栈的栈顶元素弹出,然后返回弹出栈顶元素以后剩下的栈顶元素,根据所返回的栈顶元素生成返回页面的链接,进入所返回的页面,返回至步骤S106。 An electronic program guide pages for return to the navigation method comprising the following steps: step S102, the page is provided for storing the parameter stack; step S104, when access to the electronic program navigation single home, the home parameters are pressed into the stack; after step S106, when the access link on the current page, enter the page corresponding to the link, parameters entered into said page stack is pressed; step S108, when the current page when the return operation is selected, said first current stack pop the top element, the top element and then returns the remaining elements after pop stack, the top element in accordance with the returned generate a return linked pages, enter the page returned returns to step S106.
2. 根据权利要求1所述的页面返回方法,其特征在于,通过机顶盒来i方问所述电子节目单导航的首页、当前页面上的链接、以及通过机顶盒在当前页面选择返回操作。 According to claim 1, wherein the page return, characterized in that the set-top box to ask the party i home electronic program navigation link on the current page, and by selecting the set top box page in the current return operation.
3. 根据权利要求1所述的页面返回方法,其特征在于,所述首页的参数是栈底元素,当所述堆栈中只存在所述首页的参数时, 出栈操作只包括返回所述首页的参数。 According to claim 1, wherein the page return, characterized in that said parameter is the bottom of the stack home element when the home parameter exists only in the stack, the stack includes only the operation returns to the home parameters.
4. 根据权利要求1所述的页面返回方法,其特征在于,在步骤S106中,当所进入的页面的参数将净皮压入所述堆栈时,判断所进入的页面的参数是否已经在所述堆栈中存在,如果存在, 则将存在位置之上的所有元素弹出,再将所进入的页面的参数压入所述堆栈。 The page of the method returns to claim 1, wherein, in the step S106, when the parameter entered net page stack pressed into the skin, the page parameter determines whether enters the the stack is present, if present, will be all the elements present above the eject position, and then enters the parameter page is pressed into the stack.
5. 根椐权利要求1所述的页面返回方法,其特征在于,所述电子节目单导航的页面之间的链接是树形结构。 1, page 5. As noted in the claim returned, characterized in that the link between the electronic program navigation page is a tree structure.
6. 根据权利要求1所述的页面返回方法,其特征在于,在页面上设置返回标签,用于进行返回4喿作的选择。 According to claim 1, wherein the page return, characterized in that a return to the label on the page, go back and select for 4 Qiao made.
7. 才艮据权利要求1所述的页面返回方法,其特征在于,在步骤S108中,进入所返回的页面后,所进入的页面的参lt不净皮压入所述堆栈。 7. Gen only the page data return method of claim 1, wherein, in the step S108, enter the page returned, the page reference lt enters the skin is not a net pressed into the stack.
8. 根椐权利要求7所述的页面返回方法,其特征在于,通过设置返回标识,来区分进入链4妾的页面还是进入返回的页面,如果是进入链4妾的页面,则执行入栈才喿作,如果是进入返回的页面, 则不纟丸行入栈:操作。 8. The page noted in the claim 7 to return, characterized in that, by providing the return identifier to differentiate into the chain of 4 or concubine pages into the page returned if the chain 4 entering concubine page stack is performed Qiao was made, if it is returned into the page, not Si stack pill line: operation.
9. 根据权利要求1至8中任一项所述的页面返回方法,其特征在于,所述页面参^:包括页面访问路径。 9. The method according Back page 1 to 8 according to any one of the preceding claims, wherein the reference page ^: page includes access path.
10. 根据权利要求1至8中任一项所述的页面返回方法,其特征在于,通过页面Tag元素来触发入栈才喿作和出栈操作。 10. The method returns a page according to claim 8, characterized in that, triggered by the push element was Tag page for Qiao and pop operations.
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