WO2020220347A1 - Amplifier and amplification device - Google Patents

Amplifier and amplification device Download PDF

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Publication number
WO2020220347A1
WO2020220347A1 PCT/CN2019/085371 CN2019085371W WO2020220347A1 WO 2020220347 A1 WO2020220347 A1 WO 2020220347A1 CN 2019085371 W CN2019085371 W CN 2019085371W WO 2020220347 A1 WO2020220347 A1 WO 2020220347A1
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WIPO (PCT)
Prior art keywords
transistor
coupled
differential amplifier
circuit
resistor
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Application number
PCT/CN2019/085371
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French (fr)
Chinese (zh)
Inventor
王国瑞
杨帆
力争
王晨
张福泉
李红云
Original Assignee
华为技术有限公司
Priority date (The priority date is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the date listed.)
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Application filed by 华为技术有限公司 filed Critical 华为技术有限公司
Priority to CN201980091191.8A priority Critical patent/CN113396537B/en
Priority to PCT/CN2019/085371 priority patent/WO2020220347A1/en
Publication of WO2020220347A1 publication Critical patent/WO2020220347A1/en

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    • HELECTRICITY
    • H03ELECTRONIC CIRCUITRY
    • H03FAMPLIFIERS
    • H03F1/00Details of amplifiers with only discharge tubes, only semiconductor devices or only unspecified devices as amplifying elements
    • H03F1/02Modifications of amplifiers to raise the efficiency, e.g. gliding Class A stages, use of an auxiliary oscillation
    • HELECTRICITY
    • H03ELECTRONIC CIRCUITRY
    • H03FAMPLIFIERS
    • H03F3/00Amplifiers with only discharge tubes or only semiconductor devices as amplifying elements
    • H03F3/45Differential amplifiers

Definitions

  • This application relates to the field of communication technology, and in particular to an amplifier and an amplifier device.
  • the radio frequency front end amplifier must take into account the gain, noise, linearity, and power consumption indicators.
  • the schematic diagram of the structure of the amplifier of the radio frequency front end may be as shown in FIG. 1.
  • the signal input from the positive input terminal (Vip) is amplified by multiple metal-oxide semiconductor (MOS) tubes connected in parallel, and then transmitted to the negative output terminal (Von) after passing through a parallel resonant load; negative
  • the signal input from the input terminal (Vin) is amplified by multiple parallel MOS transistors, and then transmitted to the positive output terminal (Vop) after passing through the parallel resonant load (ie, the resistance R, the capacitor C, and the inductance L in Figure 1) to achieve the pairing Amplification of differential input signals. That is to say, in this amplifier, multiple MOS tubes connected in parallel are used to realize the amplification function.
  • the intrinsic non-linear characteristics of the active transistors (such as MOS transistors) in the amplifier can be used to position the active transistors at the bias point of the n-th order (such as the third order) with the least non-linearity.
  • the MOS tube is set at the bias point with the smallest n-th order nonlinearity by adjusting the gate-source bias voltage Vgs.
  • the gate-source bias voltage Vgs can be determined by the feedback circuit shown in FIG. 2, and the output of the feedback circuit can be used as the gate-source bias voltage to be applied to the Vgs terminal in FIG. 1. It can be deduced from the voltage value of each node and the current value of each branch in FIG. 2 that using the output of FIG. 2 as the gate-source bias voltage can make the third-order nonlinearity of the amplifier shown in FIG. 1 be zero.
  • the feedback circuit shown in Figure 2 includes active transistors, current sources, operational amplifiers and other electronic devices.
  • the display circuit drives active transistors, it is affected by the process, temperature, model accuracy of these electronic devices, etc., which will cause the output of the circuit shown in Figure 2 to fluctuate greatly (that is, cause the Vgs to fluctuate greatly), and then cause the circuit shown in Figure 1.
  • the gain of the amplifier fluctuates greatly with the process, temperature, and model accuracy of the electronic device in Figure 2. Therefore, adopting the scheme of improving linearity shown in Fig. 2, the consistency of mass production of amplifier gain and power consumption is poor, and the product yield rate is low.
  • the embodiments of the present application provide an amplifier and an amplifying device, which are used to improve the linearity of the amplifier while reducing fluctuations in the gain and power consumption of the amplifier.
  • an embodiment of the present application provides an amplifier, the amplifier includes: at least one first gain circuit for amplifying a first signal; each first gain circuit includes a first transistor and a second transistor; The channel is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; at least one second gain circuit is used to amplify the second signal; each second gain circuit includes a third transistor and a fourth transistor; The channel of the three transistors is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal and the second signal constitute a differential signal; wherein, the gate bias voltage of the first transistor and the third transistor is The first voltage, the gate bias voltage of the second transistor and the fourth transistor are the second voltage.
  • the channels of the first transistor and the third transistor are in a strong inversion state, the first signal and the second signal can be amplified by the first transistor and the third transistor respectively.
  • the channels of the four transistors are in a weak inversion state, so the output signal of the first transistor and the output signal of the third transistor can be non-linearly compensated by the second transistor and the fourth transistor respectively, thereby improving the linearity of the amplifier.
  • the channels of the second transistor and the fourth transistor are in a weak inversion state, the gain is small, and the power consumption is small. Therefore, in the amplifier provided in the first aspect, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifier, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
  • the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor.
  • the signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
  • the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, the drain of the first transistor is coupled to the load of the amplifier; the source of the second transistor is coupled to ground , The drain of the second transistor is coupled to the load of the amplifier; the gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifier; the fourth transistor The source of the transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifier.
  • an embodiment of the present application provides an amplifier, which includes: at least one first gain circuit, each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state , The channel of the second transistor is in a weak inversion state; at least one second gain circuit, each second gain circuit includes a third transistor and a fourth transistor; the channel of the third transistor is in a strong inversion state, the fourth transistor The channel is in a weak inversion state; where the first signal and the second signal constitute a differential signal; the gate bias voltage of the first transistor and the third transistor is the first voltage, and the gates of the second transistor and the fourth transistor The bias voltage is the second voltage.
  • the channels of the first transistor and the third transistor are in a strong inversion state, the first signal and the second signal can be amplified by the first transistor and the third transistor respectively.
  • the channels of the four transistors are in a weak inversion state, so the output signal of the first transistor and the output signal of the third transistor can be non-linearly compensated by the second transistor and the fourth transistor respectively, thereby improving the linearity of the amplifier.
  • the channels of the second transistor and the fourth transistor are in a weak inversion state, the gain is small, and the power consumption is small. Therefore, in the amplifier provided by the second aspect, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifier, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
  • the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor.
  • the signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
  • the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, the drain of the first transistor is coupled to the load of the amplifier; the source of the second transistor is coupled to ground , The drain of the second transistor is coupled to the load of the amplifier; the gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifier; the fourth transistor The source of the transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifier.
  • an embodiment of the present application provides an amplifying device, which includes an amplifier and a closed-loop feedback circuit.
  • the amplifier includes at least one first gain circuit for amplifying the first signal and at least one second gain circuit for amplifying the second signal.
  • Each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; each second gain circuit includes a third transistor and The fourth transistor; the channel of the third transistor is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal and the second signal constitute a differential signal; wherein the gates of the first transistor and the third transistor The pole bias voltage is the first voltage generated by the first current source, and the gate bias voltages of the second transistor and the fourth transistor are the second voltage; the closed loop feedback circuit is used to generate the second voltage.
  • the channels of the first transistor and the third transistor are in a strong inversion state, the first signal and the second signal can be amplified by the first transistor and the third transistor respectively; because the second transistor and the second transistor The channels of the four transistors are in a weak inversion state, so the output signal of the first transistor and the output signal of the third transistor can be non-linearly compensated by the second transistor and the fourth transistor respectively, thereby improving the linearity of the amplifier.
  • the gain fluctuation and power consumption fluctuation of the first transistor and the third transistor are also small.
  • the second transistor and the fourth transistor are biased through the closed-loop feedback circuit, although the bias provided by the closed-loop feedback circuit will cause fluctuations in gain and power consumption, the channels of the second and fourth transistors are in a weak inversion state.
  • the gain is small and the power consumption is small, so even if gain fluctuations and power consumption fluctuations occur, the value of the fluctuations will hardly have a large impact on the first gain circuit and the second gain circuit. Therefore, in the amplifying device provided by the third aspect, the gain fluctuation and power consumption fluctuation of the first gain circuit and the second gain circuit are small.
  • the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for offsetting the nonlinearity, and only contribute a very low proportion of the power consumption and power consumption. Gain. Therefore, in the amplifying device provided by the third aspect, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
  • the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor.
  • the signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
  • the closed-loop feedback circuit includes a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, and a fourth differential amplifier circuit; among them, the first differential amplifier circuit and the third differential amplifier circuit
  • the DC bias is generated by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit.
  • the gain coefficient of the third differential amplifier circuit may be 1/m of the gain coefficient of the first differential amplifier circuit, and the AC input voltage of the third differential amplifier circuit may be m times the AC input voltage of the first differential amplifier circuit, m>1;
  • the gain coefficient of the fourth differential amplifier circuit can be 1/m of the gain coefficient of the second differential amplifier circuit, and the AC input voltage of the fourth differential amplifier circuit can be m times the AC input voltage of the second differential amplifier circuit .
  • the first differential amplifier circuit and the second differential amplifier circuit can be constructed as a differential amplifier circuit with a small input signal and a large gain coefficient
  • the third differential amplifier circuit and the fourth differential amplifier circuit can be constructed as a large input signal, small Differential amplifier circuit with gain coefficient
  • the closed-loop feedback circuit further includes: an error amplifier for combining the output signal of the first differential amplifier circuit and the second differential amplifier circuit, and the third differential amplifier circuit and the fourth differential amplifier circuit. The error of the output signal after the circuit is compared, and the second voltage is output.
  • the output signal of the differential amplifier circuit with small input signal and large gain coefficient can be compared with the output signal of the differential amplifier circuit with large input signal and small gain coefficient.
  • the non-linear compensation transistor can compensate the non-linearity of the transistor that it compensates. Therefore, the gate bias voltage that meets the design requirements can be obtained through the above solution.
  • the closed loop feedback circuit further includes: a first transimpedance amplifier, the positive output terminal of the first differential amplifier circuit, and the positive output terminal of the second differential amplifier circuit are coupled to the negative input terminal of the first transimpedance amplifier , The negative output terminal of the first differential amplifier circuit and the negative output terminal of the second differential amplifier circuit are coupled to the positive input terminal of the first transimpedance amplifier; the second transimpedance amplifier, the positive output terminal of the third differential amplifier circuit and the fourth The positive output terminal of the differential amplifier circuit is coupled to the negative input terminal of the second transimpedance amplifier, and the negative output terminal of the third differential amplifier circuit and the negative output terminal of the fourth differential amplifier circuit are coupled to the positive input terminal of the second transimpedance amplifier;
  • the amplification factor of the second transimpedance amplifier is the same as the amplification factor of the first transimpedance amplifier; by mistake, the positive output terminal of the first transimpedance amplifier and the positive output terminal of the second transimpedance amplifier are coupled to the negative input terminal of the error amplifier,
  • the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is provided by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit. Therefore, the second differential amplifier circuit can perform nonlinear compensation on the first differential amplifier circuit, and the fourth differential amplifier circuit can perform nonlinear compensation on the third differential amplifier circuit.
  • the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit found through feedback can be used as the DC bias of the second transistor and the fourth transistor in the amplifier, so that the second transistor can perform the output signal of the first transistor. Non-linear compensation, and enables the fourth transistor to perform non-linear compensation on the output signal of the third transistor.
  • the first differential amplifier circuit includes at least one fifth transistor and at least one sixth transistor, the gate of the fifth transistor is coupled to the positive input terminal of the first differential amplifier circuit, and the gate of the sixth transistor is coupled to the first differential amplifier.
  • the negative input terminal of the circuit is coupled, the number of the fifth transistor is obtained by reducing the number of the first transistor in the amplifying device by the first ratio, and the number of the sixth transistor is obtained by reducing the number of the third transistor in the amplifying device by the first ratio
  • the second differential amplifier circuit includes at least one seventh transistor and at least one eighth transistor. The gate of the seventh transistor is coupled to the positive input terminal of the second differential amplifier circuit, and the gate of the eighth transistor is coupled to the second differential amplifier.
  • the negative input terminal of the circuit is coupled, the number of the seventh transistor is obtained by reducing the number of the second transistor in the amplifying device by the first ratio, and the number of the eighth transistor is obtained by reducing the number of the fourth transistor in the amplifying device by the first ratio
  • the third differential amplifier circuit includes at least one ninth transistor and at least one tenth transistor.
  • the gate of the ninth transistor is coupled to the positive input terminal of the third differential amplifier circuit, and the gate of the tenth transistor is coupled to the third differential amplifier.
  • the negative input terminal of the circuit is coupled.
  • the number of the ninth transistor is obtained by reducing the number of the first transistor in the amplifying device by the second ratio, and the number of the tenth transistor is obtained by reducing the number of the third transistor in the amplifying device by the second ratio.
  • the fourth differential amplifier circuit includes at least one eleventh transistor and at least one twelfth transistor, the gate of the eleventh transistor is coupled to the positive input of the fourth differential amplifier circuit, and the gate of the twelfth transistor is coupled to The negative input of the fourth differential amplifier circuit is coupled, the number of the eleventh transistor is obtained by reducing the number of the second transistor in the amplifying device by the second ratio, and the number of the twelfth transistor is obtained by reducing the number of the fourth transistor in the amplifying device The quantity is obtained after the second scale is reduced.
  • the first differential amplifying circuit, the second differential amplifying circuit, the third differential amplifying circuit, and the fourth differential amplifying circuit are all formed by reducing the number of transistors in the amplifying device to a certain extent, which can reduce the power of the closed-loop feedback circuit. Therefore, the power consumption of the amplifier is mainly used to amplify the input signal, and only a small power consumption is used to determine the gate bias voltage of the second transistor and the fourth transistor to compensate for the nonlinearity of the output signal.
  • the closed-loop feedback circuit may further include: a second current source for providing a DC bias for the first differential amplifier circuit and the third differential amplifier circuit; a buffer for the second differential amplifier circuit and the fourth differential amplifier circuit Provides a DC bias, the input of the buffer is coupled to the output of the closed loop feedback circuit; the first resistor, the second resistor, the third resistor, and the fourth resistor are connected in series in sequence; the first resistor is coupled to the first power supply and the fourth resistor Coupled to ground, the second resistor and the third resistor are coupled to the second current source; the resistance ratio of the first resistance to the second resistance is m-1, and the resistance ratio of the fourth resistance to the third resistance is m-1 , The second resistor and the third resistor have the same resistance; where the connection between the first resistor and the first power supply is coupled to the positive input end of the third differential amplifier circuit, and the coupling ground end of the fourth resistor is coupled to the third differential amplifier circuit The connection of the first resistor and the second resistor is coupled to the positive input of
  • the AC input and DC bias can be provided for the four differential amplifier circuits through the second current source, the buffer and the multiple resistors.
  • the buffer can save and output the output voltage of the closed-loop feedback circuit, so that the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is a stable voltage value, and will not fluctuate with current changes.
  • the second current source can be obtained by mirror biasing of the first current source.
  • the second current source may include a first current source, an N-type MOS tube (i.e. NMOS) and a P-type MOS tube (i.e. PMOS).
  • the first current source is output after passing through NMOS and PMOS in turn, as the first differential amplifier circuit and The DC bias of the third differential amplifier circuit.
  • the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, the drain of the first transistor is coupled to the load of the amplifying device; the source of the second transistor is coupled Ground, the drain of the second transistor is coupled to the load of the amplifying device; the gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifying device; The source of the fourth transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifying device.
  • FIG. 1 is a schematic diagram of the structure of an amplifier provided in the prior art
  • Fig. 2 is a schematic structural diagram of a feedback circuit provided in the prior art
  • FIG. 3 is a schematic structural diagram of an amplifier provided by an embodiment of the application.
  • FIG. 4 is a schematic structural diagram of another amplifier provided by an embodiment of the application.
  • FIG. 5 is a schematic structural diagram of an amplification device provided by an embodiment of the application.
  • FIG. 6 is a schematic structural diagram of a series resistor provided by an embodiment of the application.
  • FIG. 7 is a schematic structural diagram of another series resistor provided by an embodiment of the application.
  • FIG. 8 is a schematic structural diagram of a closed-loop feedback circuit provided by an embodiment of the application.
  • FIG. 9 is a schematic structural diagram of another closed-loop feedback circuit provided by an embodiment of the application.
  • FIG. 10 is a schematic diagram of a variation curve of the total gain of an amplifier provided by an embodiment of the application.
  • RF front-end amplifiers need to take into account multiple indicators such as gain, noise, linearity, and power consumption.
  • the prior art usually uses the feedback circuit shown in FIG. 2 to provide bias for the active transistors in the amplifier shown in FIG. 1.
  • the feedback circuit shown in Figure 2 can improve the linearity of the amplifier, it will cause the amplifier's gain to fluctuate greatly, that is, it is difficult to balance the amplifier's gain, power consumption, and linearity indicators.
  • the embodiments of the present application provide an amplifier and an amplifying device, which are used to improve the linearity of the amplifier while reducing fluctuations in the gain and power consumption of the amplifier.
  • the amplifier 300 includes at least one first gain circuit 301 for amplifying a first signal and at least one second gain circuit 302 for amplifying a second signal.
  • Each first gain circuit 301 includes a first transistor 301a and a second transistor 301b; the channel of the first transistor 301a is in a strong inversion state, and the channel of the second transistor 301b is in a weak inversion state.
  • each second gain circuit 302 includes a third transistor 302a and a fourth transistor 302b; the channel of the third transistor 302a is in a strong inversion state, and the channel of the fourth transistor 302b is in a weak inversion state.
  • the first signal and the second signal constitute a differential signal
  • the gate bias voltages of the first transistor 301a and the third transistor 302a are the first voltage
  • the gate bias voltages of the second transistor 301b and the fourth transistor 302b are the first voltage. Two voltage.
  • the specific meaning of the strong inversion state can be: the gate-source voltage VGS of the transistor is much larger than the threshold voltage VT of the transistor, an inversion layer (channel) is formed under the gate oxide film, and the transistor drain -There is current activity between the sources. This state is called a strong inversion state.
  • the specific meaning of the weak inversion state can be: the gate-source voltage VGS of the transistor is less than the threshold voltage VT of the transistor and the drain still has a small current activity. This state is called the weak inversion state.
  • the first transistor 301a can be used to amplify the first signal and the second transistor 301b can be used for nonlinear compensation of the output signal of the first transistor 301a; since the channel of the third transistor 302a is in a strong inversion state and the channel of the fourth transistor 302b is in a weak inversion state, the third transistor 302a can be used for Amplifying the second signal, the fourth transistor 302b can be used to perform nonlinear compensation on the output signal of the third transistor 302a.
  • the first signal and the second signal can be amplified by the first transistor 301a and the third transistor 302a respectively, and the first transistor can be amplified by the second transistor 301b and the fourth transistor 302b respectively.
  • the output signal of 301a and the output signal of the third transistor 302a perform nonlinear compensation to improve the linearity of the amplifier 300.
  • the channels of the second transistor 301b and the fourth transistor 302b are in a weak inversion state, and their gain is small and the power consumption is small. Therefore, the gain and power consumption of the amplifier 300 are mainly determined by the first transistor 301a and the third transistor 302a; the second transistor 301b and the fourth transistor 302b are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifier 300, the linearity of the amplifier 300 can be improved through the second transistor 301b and the fourth transistor 302b, and the gain fluctuation and power consumption fluctuation of the amplifier 300 can be reduced.
  • the specific connection mode of the first transistor 301a, the second transistor 301b, the third transistor 302a and the fourth transistor 302b may be: the gate of the first transistor 301a is used to receive the first signal, The source of the transistor 301a is coupled to ground, the drain of the first transistor 301a is coupled to the load of the amplifier 300; the source of the second transistor 301b is coupled to ground, and the drain of the second transistor 301b is coupled to the load of the amplifier 300; the third transistor 302a The gate of the third transistor 302a is used to receive the second signal, the source of the third transistor 302a is coupled to ground, the drain of the third transistor 302a is coupled to the load of the amplifier 300; the source of the fourth transistor 302b is coupled to ground, and the drain of the fourth transistor 302b The pole is coupled to the load of the amplifier 300.
  • the source of the first transistor 301a is coupled to ground, which may mean that the first transistor 301a is directly grounded, or the first transistor 301a is grounded through an inductor, a capacitor, or other devices.
  • the meaning of coupling to ground is the same, which will not be explained in detail later.
  • the transistor adopts a CMOS process as an example for illustration. In practical applications, the transistor can also use other processes. When the transistor adopts other processes, the names of the various ports of the transistor will be different, but the functions are basically the same.
  • the transistor is a bipolar junction transistor (BJT)
  • the base in BJT is equivalent to the gate in CMOS
  • the collector in BJT is equivalent to the drain in CMOS
  • the emitter in BJT The pole is equivalent to the source in CMOS. Therefore, the amplifier based on the CMOS tube in this application can be equivalent to the amplifier based on the BJT.
  • the embodiments of the present application take the transistors using the CMOS process as an example for illustration, and the specific implementation methods when using other processes are not described in detail.
  • the transistors adopt the method of gate input signal and source coupling grounding.
  • the transistor can also adopt the method of source input signal and gate coupling grounding. This is not specifically limited.
  • a possible schematic diagram of the structure of the amplifier 300 may be as shown in FIG. 4.
  • the transistor whose gate is coupled to the positive input terminal Vip can be regarded as the first transistor 301a, and the transistor whose gate is coupled to the negative input terminal Vin can be regarded as the third transistor 302a, and the first transistor
  • the transistor connected to 301a and biased by Vgs_Aux can be regarded as the second transistor 301b, and the transistor connected to the third transistor 302a and biased by Vgs_Aux can be regarded as the fourth transistor 302b.
  • the RLC network forms an equivalent parallel resonant load, Vop is the positive output terminal, and Von is the negative output terminal.
  • the first transistor 301a and the third transistor 302a respectively amplify the differential signal output from the positive input terminal and the negative input terminal, which can be collectively referred to as the "main pipe”; the second transistor 301b pair and the fourth transistor 302b respectively affect the first transistor 301a and the second transistor 302b.
  • the output signal of the three transistors 302a performs nonlinear compensation, which can be collectively referred to as an "auxiliary compensation tube".
  • the interconnected "main pipe” and "auxiliary compensation pipe” can be called a "Gm unit".
  • the amplifying device 500 includes an amplifier 501 and a closed loop feedback circuit 502.
  • the amplifier 501 includes at least one first gain circuit for amplifying the first signal and at least one second gain circuit for amplifying the second signal.
  • each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; each second gain circuit includes a third Transistor and fourth transistor; the channel of the third transistor is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal and the second signal constitute a differential signal; the gates of the first transistor and the third transistor
  • the pole bias voltage is the first voltage generated by the first current source, and the gate bias voltages of the second transistor and the fourth transistor are the second voltage; the closed loop feedback circuit is used to generate the second voltage.
  • the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor.
  • the signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
  • the specific implementation of the amplifier 501 can be referred to the related description in the amplifier 300 shown in FIG. 3, which will not be repeated here.
  • the first signal and the second signal can be amplified by the first transistor and the third transistor, respectively. Since the first transistor and the third transistor are biased by the first current source, it is difficult to ensure that the first transistor and the third transistor can be set at the bias point with the smallest n-th order nonlinearity.
  • the second transistor and the fourth transistor can be used to perform nonlinear compensation on the output signal of the first transistor and the output signal of the third transistor, so that the linearity of the amplifying device 500 can be improved.
  • the first transistor and the third transistor are biased by the first current source.
  • This bias mode can be regarded as a fixed bias, and its bias voltage fluctuation is small, so the gain fluctuations of the first transistor and the third transistor are combined.
  • the power consumption fluctuation is also small.
  • the second transistor and the fourth transistor are biased by the closed-loop feedback circuit 502 although the bias provided by the closed-loop feedback circuit 502 will cause fluctuations in gain and power consumption, the second and fourth transistors are used for nonlinear compensation.
  • the transistor has a small gain and low power consumption. Therefore, even if gain fluctuations and power consumption fluctuations occur, the value of the fluctuations will hardly have a large impact on the first gain circuit and the second gain circuit. Therefore, in the amplifying device 500, the gain fluctuation and power consumption fluctuation of the first gain circuit and the second gain circuit are small.
  • the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifying device 500, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
  • the specific connection mode of the first transistor, the second transistor, the third transistor, and the fourth transistor may be: the gate of the first transistor is used to receive the first signal, and the source of the first transistor Coupled to ground, the drain of the first transistor is coupled to the load of the amplifying device 500; the source of the second transistor is coupled to ground, and the drain of the second transistor is coupled to the load of the amplifying device 500; the gate of the third transistor is used to receive the first For two signals, the source of the third transistor is coupled to the ground, the drain of the third transistor is coupled to the load of the amplifying device 500; the source of the fourth transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifying device 500.
  • the amplifying device 500 may further include a parallel resonant load, and the parallel resonant load may be regarded as an equivalent load of the amplifying device 300.
  • the input terminal of the parallel resonant load is respectively coupled with the output terminal of the first gain circuit and the output terminal of the second gain circuit.
  • the parallel resonant load can be an output matching network, or a device such as a balun.
  • the closed-loop feedback circuit 302 may include: a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, and a fourth differential amplifier circuit, a first transimpedance amplifier, a second transimpedance amplifier, and error amplification.
  • the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is provided by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit.
  • the gain coefficient of the third differential amplifier circuit is 1/m of the gain coefficient of the first differential amplifier circuit, and the AC input voltage of the third differential amplifier circuit is m times the AC input voltage of the first differential amplifier circuit, m> 1;
  • the gain coefficient of the fourth differential amplifier circuit is 1/m of the gain coefficient of the second differential amplifier circuit, and the AC input voltage of the fourth differential amplifier circuit is m times the AC input voltage of the second differential amplifier circuit.
  • the first differential amplifier circuit and the second differential amplifier circuit can be constructed as a differential amplifier circuit with a small input signal and a large gain coefficient
  • the third differential amplifier circuit and the fourth differential amplifier circuit can be constructed as a large Input signal, differential amplifier circuit with small gain coefficient.
  • the closed loop feedback circuit 502 may also include an error amplifier.
  • the error amplifier is used to compare errors between the combined output signal of the first differential amplifier circuit and the second differential amplifier circuit and the combined output signal of the third differential amplifier circuit and the fourth differential amplifier circuit, and output the second voltage.
  • the error amplifier can compare the output signal of a differential amplifier circuit with a small input signal and a large gain coefficient with the output signal of a differential amplifier circuit with a large input signal and small gain coefficient. When the two output signals are approximately the same, it is used
  • the non-linear compensation transistor can compensate for the non-linearity of the transistor it compensates, so the gate bias voltage that meets the design requirements can be obtained through the above solution.
  • the closed-loop feedback circuit 502 may also include a first transimpedance amplifier and a second transimpedance amplifier.
  • the positive output terminal of the first differential amplifier circuit and the positive output terminal of the second differential amplifier circuit are coupled to the negative input terminal of the first transimpedance amplifier, the negative output terminal of the first differential amplifier circuit and the negative output terminal of the second differential amplifier circuit
  • the output terminal is coupled to the positive input terminal of the first transimpedance amplifier;
  • the positive output terminal of the third differential amplifier circuit and the positive output terminal of the fourth differential amplifier circuit are coupled to the negative input terminal of the second transimpedance amplifier, and the third differential amplifier circuit
  • the negative output terminal of and the negative output terminal of the fourth differential amplifier circuit are coupled to the positive input terminal of the second transimpedance amplifier; the gain coefficient of the second transimpedance amplifier is the same as that of the first transimpedance amplifier.
  • the positive output terminal of the first transimpedance amplifier and the positive output terminal of the second transimpedance amplifier are coupled to the negative input terminal of the error amplifier, and the negative output terminal of the first transimpedance amplifier and the negative output terminal of the second transimpedance amplifier are coupled to the error
  • the positive input terminal of the amplifier; the output terminal of the error amplifier is used as the output terminal of the closed loop feedback circuit 502.
  • the closed-loop feedback circuit 502 may include a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, a fourth differential amplifier circuit, a first transimpedance amplifier, and a second transimpedance amplifier. Amplifier and error amplifier.
  • the gain factor of the first differential amplifier circuit is A
  • the AC input voltage of the positive input terminal of the first differential amplifier circuit is a1
  • the AC input voltage of the negative input terminal of the first differential amplifier circuit is a2
  • the gain factor of the second differential amplifier circuit Is B the AC input voltage of the positive input terminal of the second differential amplifier circuit is b1
  • the AC input voltage of the negative input terminal of the second differential amplifier circuit is b1.
  • the AC input voltage of the third differential amplifier circuit is m*a1 and m*a2, and the gain coefficient is A*1/m
  • the AC input voltage of the fourth differential amplifier circuit is m*b1 and m*b2, and the gain coefficient is B*1/m.
  • the input of its positive input terminal is a1*A+b1*B
  • the input of its negative input terminal is a2*A+b2* B
  • the linearity of the first differential amplifier circuit, the second differential amplifier circuit, the third differential amplifier circuit, and the fourth differential amplifier circuit is relatively high.
  • the output of the first transimpedance amplifier and the second transimpedance amplifier should be the same.
  • the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is provided by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit . Therefore, the second differential amplifier circuit can perform nonlinear compensation on the first differential amplifier circuit, and the fourth differential amplifier circuit can perform nonlinear compensation on the third differential amplifier circuit.
  • the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit found by feedback can be used as the DC bias of the second transistor and the fourth transistor in the amplifying device 500, so that the second transistor can output to the first transistor The signal performs nonlinear compensation, and the fourth transistor can perform nonlinear compensation on the output signal of the third transistor.
  • the first differential amplifier circuit may include at least one fifth transistor and at least one sixth transistor, the gate of the fifth transistor is coupled to the positive input terminal of the first differential amplifier circuit, and the gate of the sixth transistor is connected to the first The negative input terminal of the differential amplifier circuit is coupled, the number of the fifth transistor is obtained by reducing the number of the first transistor in the amplifying device 500 by a first ratio, and the number of the sixth transistor is obtained by reducing the number of the third transistor in the amplifying device 500 to Obtained after the first scale is reduced.
  • the second differential amplifier circuit may include at least one seventh transistor and at least one eighth transistor, the gate of the seventh transistor is coupled to the positive input terminal of the second differential amplifier circuit, and the gate of the eighth transistor is connected to the second differential amplifier circuit.
  • the negative input terminal is coupled, the number of the seventh transistor is obtained by reducing the number of the second transistor in the amplifying device 500 by the first ratio, and the number of the eighth transistor is obtained by reducing the number of the fourth transistor in the amplifying device 500 by the first ratio After getting.
  • the third differential amplifier circuit may include at least one ninth transistor and at least one tenth transistor.
  • the gate of the ninth transistor is coupled to the positive input terminal of the third differential amplifier circuit, and the gate of the tenth transistor is connected to the third differential amplifier circuit.
  • the negative input is coupled, the number of the ninth transistor is obtained by reducing the number of the first transistor in the amplifying device 500 by the second ratio, and the number of the tenth transistor is obtained by reducing the number of the third transistor in the amplifying device 500 by the second ratio After getting.
  • the first ratio is m times the second ratio.
  • the fourth differential amplifier circuit may include at least one eleventh transistor and at least one twelfth transistor, the gate of the eleventh transistor is coupled to the positive input terminal of the fourth differential amplifier circuit, and the gate of the twelfth transistor is coupled to the fourth
  • the negative input terminal of the differential amplifier circuit is coupled, the number of the eleventh transistor is obtained by reducing the number of the second transistor in the amplifying device 500 by the second ratio, and the number of the twelfth transistor is obtained by reducing the number of the fourth transistor in the amplifying device 500 The quantity is obtained after the second scale is reduced.
  • both the first differential amplifier circuit and the third differential amplifier circuit can be formed by removing the second transistor and the fourth transistor in the amplifier 501, and reducing the number of the first transistor and the third transistor.
  • Both a differential amplifying circuit and a third differential amplifying circuit can be used to simulate the working state of the transistor used to amplify the input signal in the amplifier 501, the difference is only that the gain coefficients of the first differential amplifying circuit and the second differential amplifying circuit are different;
  • Both the second differential amplifier circuit and the fourth differential amplifier circuit can be formed by removing the first transistor and the third transistor in the amplifier 501 and reducing the number of the second transistor and the fourth transistor to a certain extent.
  • the second differential amplifier circuit Both the fourth differential amplifier circuit and the fourth differential amplifier circuit can be used to simulate the working state of the transistor used for nonlinear compensation in the amplifier 501.
  • the power consumption of the closed-loop feedback circuit 502 can be reduced, so that the power consumption of the amplifier device 500 is mainly used for amplifying the input signal, and only a smaller
  • the power consumption determines the bias of the second transistor and the fourth transistor to compensate for the non-linearity of the output signal.
  • the fifth transistor and the first transistor may have the same specifications, the sixth transistor and the third transistor may have the same specifications; the seventh transistor and the second transistor may have the same specifications, and the eighth transistor and the fourth transistor may have the same specifications;
  • the ninth transistor and the first transistor may have the same specifications, the tenth transistor and the third transistor may have the same specifications; the eleventh transistor and the second transistor may have the same specifications, and the twelfth transistor and the fourth transistor may have the same specifications.
  • the closed-loop feedback circuit 502 may also include: a second current source for providing a DC bias for the first differential amplifier circuit and the third differential amplifier circuit; a buffer for the second differential amplifier circuit and the fourth differential amplifier circuit The circuit provides a DC bias, the input of the buffer is coupled with the output of the closed loop feedback circuit 502; the first resistor, the second resistor, the third resistor, and the fourth resistor are connected in series; the fifth resistor and the sixth resistor are connected in series , The seventh resistor and the eighth resistor.
  • the second current source can be obtained by mirror biasing of the first current source.
  • the buffer can store and output the output voltage of the closed-loop feedback circuit 502, so that the DC bias of the second differential amplifying circuit and the fourth differential amplifying circuit is a stable voltage value, and will not fluctuate with current changes.
  • the specific connection manner of the first resistor to the fourth resistor in series may be: the first resistor is coupled to the first power source, the fourth resistor is coupled to the ground, and the second resistor and the third resistor are coupled to the second current source;
  • the resistance ratio of the resistance to the second resistance is m-1
  • the resistance ratio of the fourth resistance to the third resistance is m-1
  • the resistances of the second resistance and the third resistance are the same; where the first resistance is equal to
  • the connection of the first power supply is coupled with the positive input terminal of the third differential amplifier circuit, and the coupling ground terminal of the fourth resistor is coupled with the negative input terminal of the third differential amplifier circuit;
  • the connection between the first resistor and the second resistor is coupled with the first
  • the positive input terminal of the differential amplifier circuit is coupled
  • the connection of the third resistor and the fourth resistor is coupled with the negative input terminal of the first differential amplifier circuit.
  • the first power source may be an alternating current source.
  • the specific connection manner of the fifth resistor to the eighth resistor in series may be: the fifth resistor is coupled to the second power source, the eighth resistor is coupled to the ground, and the sixth resistor and the seventh resistor are coupled to the output terminal of the buffer;
  • the resistance ratio of the fifth resistor to the sixth resistor is m-1
  • the resistance ratio of the eighth resistor to the seventh resistor is m-1
  • the resistance values of the sixth resistor and the seventh resistor are the same; among them, the fifth resistor
  • the connection with the second power supply is coupled with the positive input end of the fourth differential amplifier circuit, the coupling ground end of the eighth resistor is coupled with the negative input end of the fourth differential amplifier circuit;
  • the connection between the fifth resistor and the sixth resistor is coupled with the first
  • the positive input ends of the two differential amplifier circuits are coupled, and the junction of the seventh resistor and the eighth resistor is coupled with the negative input end of the second differential amplifier circuit.
  • the second power source may be an alternating current source.
  • the AC input and DC bias can be provided for the four differential amplifier circuits through the second current source, the buffer and the multiple resistors.
  • the first resistor, the second resistor, the third resistor, and the fourth resistor connected in series in sequence and the output of each node therein may be as shown in FIG. 6. It can be seen from FIG. 6 that the DC bias of the first differential amplifier circuit and the third differential amplifier circuit are both provided by the second current source. Since the resistance ratio of the first resistance to the second resistance is m-1, the resistance ratio of the fourth resistance to the third resistance is m-1, and the resistances of the second resistance and the third resistance are the same, then, The input of the positive input terminal of the three differential amplifier circuit is m times the input of the positive input terminal of the first differential amplifier circuit, and the input of the negative input terminal of the third differential amplifier circuit is m times the input of the negative input terminal of the first differential amplifier circuit.
  • the AC input voltage of the third differential amplifier circuit is m times the AC input voltage of the first differential amplifier circuit, the first differential amplifier circuit and the third differential amplifier circuit
  • the DC bias is provided by the second current source.
  • the fifth resistor, the sixth resistor, the seventh resistor, and the eighth resistor connected in series in sequence and the output of each node therein may be as shown in FIG. 7.
  • the input terminal of the buffer is coupled with the output terminal of the closed loop feedback circuit, so the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit 502.
  • the resistance ratio of the fifth resistor to the sixth resistor is m-1
  • the resistance ratio of the eighth resistor to the seventh resistor is m-1
  • the resistance values of the sixth and seventh resistors are the same
  • the input of the positive input terminal of the four differential amplifier circuit is m times the input of the positive input terminal of the second differential amplifier circuit
  • the input of the negative input terminal of the fourth differential amplifier circuit is m times the input of the negative input terminal of the second differential amplifier circuit. Therefore, through the four resistors in series as shown in Figure 7, it is possible to realize that "the AC input voltage of the fourth differential amplifier circuit is m times the AC input voltage of the second differential amplifier circuit, the second differential amplifier circuit and the fourth differential amplifier circuit
  • the DC bias is the output voltage of the closed-loop feedback circuit".
  • the closed loop feedback circuit 502 includes a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, a fourth differential amplifier circuit, a first transimpedance amplifier, a second transimpedance amplifier, an error amplifier, and a second Two current sources, buffers, and series resistors (first resistor, second resistor, third resistor, and fourth resistor connected in series, and fifth resistor, sixth resistor, seventh resistor, and eighth resistor connected in series).
  • the closed-loop feedback circuit 502 shown in FIG. 8 can be used to provide a bias for the second transistor and the fourth transistor in the amplifying device 500 shown in FIG. 5, so that the second transistor performs nonlinear compensation on the first transistor and the fourth transistor Perform nonlinear compensation on the third transistor.
  • the closed loop feedback circuit shown in FIG. 9 can be used to provide Vgs_Aux (equivalent to the bias voltage of the second transistor and the fourth transistor) for the amplifier. That is, the closed loop feedback circuit shown in FIG. 9 is connected to the Vgs_Aux terminal in FIG. 4.
  • the amplifier shown in FIG. 4 and the closed loop feedback circuit shown in FIG. 9 can form an amplifying device, which can be regarded as a specific example of the amplifying device 500 shown in FIG. 5.
  • the Aux Gm in the lower half is equivalent to the removal of the "main pipe” in Figure 4 and the "auxiliary compensation pipe” is formed after the number is reduced according to the ratio of 1/n.
  • n may be 100.
  • the Gm unit in FIG. 9 can be obtained by duplicating the "main pipe” and the "auxiliary compensation pipe” in the Gm unit in FIG. 4, respectively, with sizes 1/n and 4/n.
  • the common mode of the main pipe (Main Gm) is biased by the conventional mirror image
  • the common mode of the auxiliary compensation pipe (Aux Gm) is biased by the voltage of the closed loop feedback circuit (ie, Vgs_aux).
  • differential signals of different sizes can be applied to the Gm cell in the upper half and the Gm cell in the lower half.
  • the ratio of the gain coefficient of the upper half of the Gm unit to the lower half of the Gm unit is 4:1, then the ratio of the input signal of the upper half of the Gm unit to the lower half of the Gm unit can be 1:4 .
  • the two differential output currents are converted into voltages through transimpedance amplifiers of opposite proportions.
  • the two differential voltages are amplified by an error amplifier (EA) and used to control the state of the "auxiliary compensation tube" in Figure 4 to form a closed loop negative feedback.
  • EA error amplifier
  • the function of closed-loop negative feedback is to make the small signal path (in the upper part of Figure 9, the input signal is 1x, called the small signal path) and the large signal path (in the lower half of Figure 9, the input signal is 4x, called the small signal path)
  • the output of the large signal path is the same, and the output of the upper and lower parts is equal to achieve the so-called "linear”.
  • the output "Vgs_Aux" voltage found by the closed-loop feedback circuit just enables the "auxiliary compensation tube” to compensate for the non-linear fluctuations of the "main pipe” and realize the "adaptive" closed-loop adjustment.
  • the amplifying device 500 since the channels of the first transistor 301a and the third transistor 302a are in a strong inversion state, the first transistor 301a and the third transistor 302a can be used to realize the Amplification of the signal and the second signal; since the channels of the second transistor 301b and the fourth transistor 302b are in a weak inversion state, the output signal and the second transistor of the first transistor 301a can be transmitted through the second transistor 301b and the fourth transistor 302b, respectively The output signal of the three-transistor 302a performs nonlinear compensation to improve the linearity of the amplifier 501.
  • this bias mode can be regarded as a fixed bias, and its bias voltage fluctuation is small, so the gain fluctuation and power of the first transistor and the third transistor The consumption fluctuation is also small.
  • the second transistor and the fourth transistor are biased through the closed-loop feedback circuit 502 although the bias provided by the closed-loop feedback circuit 502 will cause fluctuations in gain and power consumption, the channels of the second and fourth transistors are in weak inversion. In the state, the gain is small and the power consumption is small. Therefore, even if gain fluctuations and power consumption fluctuations occur, the value of the fluctuations will hardly have a large impact on the first gain circuit and the second gain circuit. Therefore, in the amplifying device 500, the gain fluctuation and power consumption fluctuation of the first gain circuit and the second gain circuit are small.
  • the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of the power. Consumption and gain. Therefore, in the amplifying device 500, the linearity of the amplifier 501 can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier 501 can be reduced.
  • the total gain of the amplifier, the gain of the main pipe (ie the first transistor and the third transistor) and the auxiliary compensation tube (ie the second transistor and the fourth transistor) gain vary with the input signal
  • the changes can be shown in Figure 10. It can be seen from Figure 10 that the overall gain of the amplifier has better linearity.
  • the auxiliary compensation tube can compensate the main pipe nonlinearly, so that the total gain of the amplifier is stable with the input signal.
  • the amplifying device 500 provided by the embodiment of the present application can reduce the gain and power consumption fluctuation of the amplifier.
  • the total gain of the amplifier and the input referred 3rd-order intercept point (IIP3) can be changed as follows: Shown in Table 1 and Table 2. Among them, before compensation refers to a situation where the amplifier does not include an auxiliary compensation tube and the main pipe is biased by a current source; after compensation refers to a situation where the amplifying device provided in the embodiment of the present application is used.
  • the amplifier 300 and the amplifier 500 provided in the embodiments of the present application can be applied to a variety of terminal devices, for example, can be applied to mobile phones, tablets, virtual reality (virtual reality). , VR) terminal, augmented reality (augmented reality, AR) terminal and other terminal equipment.
  • VR virtual reality
  • AR augmented reality

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Abstract

Disclosed are an amplifier and an amplification device, which are used for reducing the gain and power consumption fluctuation of an amplifier while improving the linearity of the amplifier. The amplifier comprises: at least one first gain circuit for amplifying a first signal, each first gain circuit comprising a first transistor and a second transistor, wherein a channel of the first transistor is in a strong inversion state, and a channel of the second transistor is in a weak inversion state; and at least one second gain circuit for amplifying a second signal, each second gain circuit comprising a third transistor and a fourth transistor, wherein a channel of the third transistor is in a strong inversion state, and a channel of the fourth transistor is in a weak inversion state. The first signal and the second signal constitute a differential signal. A gate electrode bias voltage of the first transistor and the third transistor is a first voltage, and a gate electrode bias voltage of the second transistor and the fourth transistor is a second voltage.

Description

一种放大器及放大装置Amplifier and amplifying device 技术领域Technical field
本申请涉及通信技术领域,尤其涉及一种放大器及放大装置。This application relates to the field of communication technology, and in particular to an amplifier and an amplifier device.
背景技术Background technique
随着宽带无线通信的发展,对射频前端中的放大器的性能指标要求越来越严格,射频前端放大器必须兼顾增益、噪声、线性度及功耗等指标。With the development of broadband wireless communication, the performance index requirements of the amplifier in the radio frequency front end are becoming more and more stringent. The radio frequency front end amplifier must take into account the gain, noise, linearity, and power consumption indicators.
现有技术中,射频前端的放大器的结构示意图可以如图1所示。在图1中,正输入端(Vip)输入的信号经多个并联的金属氧化物半导体(metal-oxide semiconductor,MOS)管放大,然后经过并联谐振负载后传输至负输出端(Von);负输入端(Vin)输入的信号经多个并联的MOS管放大,然后经过并联谐振负载(即图1中的电阻R、电容C和电感L)后传输至正输出端(Vop),从而实现对差分输入信号的放大。也就是说,在该放大器中,通过多个并联的MOS管实现放大功能。In the prior art, the schematic diagram of the structure of the amplifier of the radio frequency front end may be as shown in FIG. 1. In Figure 1, the signal input from the positive input terminal (Vip) is amplified by multiple metal-oxide semiconductor (MOS) tubes connected in parallel, and then transmitted to the negative output terminal (Von) after passing through a parallel resonant load; negative The signal input from the input terminal (Vin) is amplified by multiple parallel MOS transistors, and then transmitted to the positive output terminal (Vop) after passing through the parallel resonant load (ie, the resistance R, the capacitor C, and the inductance L in Figure 1) to achieve the pairing Amplification of differential input signals. That is to say, in this amplifier, multiple MOS tubes connected in parallel are used to realize the amplification function.
通常,为了提高放大器的线性度,可以利用放大器中有源晶体管(例如MOS管)的本征非线性特性,将有源晶体管置位在n阶(比如三阶)非线性最小的偏置点。对于图1所示的放大器来说,即通过调整栅源偏置电压Vgs将MOS管置位在n阶非线性最小的偏置点。具体实现时,栅源偏置电压Vgs可通过图2所示的反馈电路确定,该反馈电路的输出可以作为栅源偏置电压施加在图1中的Vgs端。通过图2中各节点电压值以及各支路的电流值可以推导出:将图2的输出作为栅源偏置电压可以使得图1所示放大器的三阶非线性为0。Generally, in order to improve the linearity of the amplifier, the intrinsic non-linear characteristics of the active transistors (such as MOS transistors) in the amplifier can be used to position the active transistors at the bias point of the n-th order (such as the third order) with the least non-linearity. For the amplifier shown in Figure 1, the MOS tube is set at the bias point with the smallest n-th order nonlinearity by adjusting the gate-source bias voltage Vgs. In specific implementation, the gate-source bias voltage Vgs can be determined by the feedback circuit shown in FIG. 2, and the output of the feedback circuit can be used as the gate-source bias voltage to be applied to the Vgs terminal in FIG. 1. It can be deduced from the voltage value of each node and the current value of each branch in FIG. 2 that using the output of FIG. 2 as the gate-source bias voltage can make the third-order nonlinearity of the amplifier shown in FIG. 1 be zero.
但是,采用图2所示方式提高放大器的线性度,会存在如下问题:由于图2所示的反馈电路中包括有源晶体管、电流源、运算放大器等多种电子器件,因而在通过图2所示电路驱动有源晶体管时,受这些电子器件的工艺、温度、模型精度等的影响,会导致图2所示电路的输出波动较大(即导致Vgs波动较大),进而导致图1所示的放大器的增益随图2中电子器件的工艺、温度、模型精度等波动较大。因此,采用图2所示的提高线性度的方案,放大器的增益和功耗的量产一致性较差,产品良率较低。However, using the method shown in Figure 2 to improve the linearity of the amplifier will have the following problems: Since the feedback circuit shown in Figure 2 includes active transistors, current sources, operational amplifiers and other electronic devices, When the display circuit drives active transistors, it is affected by the process, temperature, model accuracy of these electronic devices, etc., which will cause the output of the circuit shown in Figure 2 to fluctuate greatly (that is, cause the Vgs to fluctuate greatly), and then cause the circuit shown in Figure 1. The gain of the amplifier fluctuates greatly with the process, temperature, and model accuracy of the electronic device in Figure 2. Therefore, adopting the scheme of improving linearity shown in Fig. 2, the consistency of mass production of amplifier gain and power consumption is poor, and the product yield rate is low.
综上,亟需一种提高放大器的线性度的方案,用以在提高放大器线性度的同时,减小放大器的增益和功耗波动。In summary, there is an urgent need for a solution to improve the linearity of the amplifier, so as to reduce the gain and power consumption fluctuation of the amplifier while improving the linearity of the amplifier.
发明内容Summary of the invention
本申请实施例提供一种放大器及放大装置,用以在提高放大器的线性度的同时,减小放大器的增益和功耗波动。The embodiments of the present application provide an amplifier and an amplifying device, which are used to improve the linearity of the amplifier while reducing fluctuations in the gain and power consumption of the amplifier.
第一方面,本申请实施例提供一种放大器,该放大器包括:至少一个第一增益电路,用于放大第一信号;每个第一增益电路包括第一晶体管和第二晶体管;第一晶体管的沟道处于强反型状态,第二晶体管的沟道处于弱反型状态;至少一个第二增益电路,用于放大第二信号;每个第二增益电路包括第三晶体管和第四晶体管;第三晶体管的沟道处于强反型状态,第四晶体管的沟道处于弱反型状态;第一信号和第二信号构成差分信号;其中,第一晶体管和第三晶体管的栅极偏置电压为第一电压,第二晶体管和第四晶体管的栅极偏 置电压为第二电压。In a first aspect, an embodiment of the present application provides an amplifier, the amplifier includes: at least one first gain circuit for amplifying a first signal; each first gain circuit includes a first transistor and a second transistor; The channel is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; at least one second gain circuit is used to amplify the second signal; each second gain circuit includes a third transistor and a fourth transistor; The channel of the three transistors is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal and the second signal constitute a differential signal; wherein, the gate bias voltage of the first transistor and the third transistor is The first voltage, the gate bias voltage of the second transistor and the fourth transistor are the second voltage.
采用上述方案,由于第一晶体管和第三晶体管的沟道处于强反型状态,因而可以分别通过第一晶体管和第三晶体管实现对第一信号和第二信号的放大,由于第二晶体管和第四晶体管的沟道处于弱反型状态,因而可以分别通过第二晶体管和第四晶体管对第一晶体管的输出信号和第三晶体管的输出信号进行非线性补偿,提高放大器的线性度。With the above solution, since the channels of the first transistor and the third transistor are in a strong inversion state, the first signal and the second signal can be amplified by the first transistor and the third transistor respectively. The channels of the four transistors are in a weak inversion state, so the output signal of the first transistor and the output signal of the third transistor can be non-linearly compensated by the second transistor and the fourth transistor respectively, thereby improving the linearity of the amplifier.
此外,在第一方面提供的放大器中,第二晶体管和第四晶体管的沟道处于弱反型状态,其增益较小、产生的功耗也较小。因此,第一方面提供的放大器中,增益和功耗主要由第一晶体管和第三晶体管决定;第二晶体管和第四晶体管负责抵消非线性,只贡献很低比例的功耗和增益。因而在该放大器中,可以通过第二晶体管和第四晶体管提高放大器的线性度的同时,减小放大器的增益波动和功耗波动。In addition, in the amplifier provided in the first aspect, the channels of the second transistor and the fourth transistor are in a weak inversion state, the gain is small, and the power consumption is small. Therefore, in the amplifier provided in the first aspect, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifier, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
具体地,由于第一晶体管的沟道处于强反型状态、第二晶体管的沟道处于弱反型状态,因而第一晶体管可用于放大第一信号、第二晶体管可用于对第一晶体管的输出信号进行非线性补偿;由于第三晶体管的沟道处于强反型状态、第四晶体管的沟道处于弱反型状态,因而第三晶体管可用于放大第二信号,第四晶体管可用于对第三晶体管的输出信号进行非线性补偿。Specifically, since the channel of the first transistor is in a strong inversion state and the channel of the second transistor is in a weak inversion state, the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor. The signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
在一种可能的设计中,第一晶体管的栅极用于接收第一信号,第一晶体管的源极耦合接地,第一晶体管的漏极与放大器的负载耦合;第二晶体管的源极耦合接地,第二晶体管的漏极与放大器的负载耦合;第三晶体管的栅极用于接收第二信号,第三晶体管的源极耦合接地,第三晶体管的漏极与放大器的负载耦合;第四晶体管的源极耦合接地,第四晶体管的漏极与放大器的负载耦合。In a possible design, the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, the drain of the first transistor is coupled to the load of the amplifier; the source of the second transistor is coupled to ground , The drain of the second transistor is coupled to the load of the amplifier; the gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifier; the fourth transistor The source of the transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifier.
第二方面,本申请实施例提供一种放大器,该放大器包括:至少一个第一增益电路,每个第一增益电路包括第一晶体管和第二晶体管;第一晶体管的沟道处于强反型状态,第二晶体管的沟道处于弱反型状态;至少一个第二增益电路,每个第二增益电路包括第三晶体管和第四晶体管;第三晶体管的沟道处于强反型状态,第四晶体管的沟道处于弱反型状态;其中,第一信号和第二信号构成差分信号;第一晶体管和第三晶体管的栅极偏置电压为第一电压,第二晶体管和第四晶体管的栅极偏置电压为第二电压。In a second aspect, an embodiment of the present application provides an amplifier, which includes: at least one first gain circuit, each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state , The channel of the second transistor is in a weak inversion state; at least one second gain circuit, each second gain circuit includes a third transistor and a fourth transistor; the channel of the third transistor is in a strong inversion state, the fourth transistor The channel is in a weak inversion state; where the first signal and the second signal constitute a differential signal; the gate bias voltage of the first transistor and the third transistor is the first voltage, and the gates of the second transistor and the fourth transistor The bias voltage is the second voltage.
采用上述方案,由于第一晶体管和第三晶体管的沟道处于强反型状态,因而可以分别通过第一晶体管和第三晶体管实现对第一信号和第二信号的放大,由于第二晶体管和第四晶体管的沟道处于弱反型状态,因而可以分别通过第二晶体管和第四晶体管对第一晶体管的输出信号和第三晶体管的输出信号进行非线性补偿,提高放大器的线性度。With the above solution, since the channels of the first transistor and the third transistor are in a strong inversion state, the first signal and the second signal can be amplified by the first transistor and the third transistor respectively. The channels of the four transistors are in a weak inversion state, so the output signal of the first transistor and the output signal of the third transistor can be non-linearly compensated by the second transistor and the fourth transistor respectively, thereby improving the linearity of the amplifier.
此外,在第二方面提供的放大器中,第二晶体管和第四晶体管的沟道处于弱反型状态,其增益较小、产生的功耗也较小。因此,第二方面提供的放大器中,增益和功耗主要由第一晶体管和第三晶体管决定;第二晶体管和第四晶体管负责抵消非线性,只贡献很低比例的功耗和增益。因而在该放大器中,可以通过第二晶体管和第四晶体管提高放大器的线性度的同时,减小放大器的增益波动和功耗波动。In addition, in the amplifier provided by the second aspect, the channels of the second transistor and the fourth transistor are in a weak inversion state, the gain is small, and the power consumption is small. Therefore, in the amplifier provided by the second aspect, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifier, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
具体地,由于第一晶体管的沟道处于强反型状态、第二晶体管的沟道处于弱反型状态,因而第一晶体管可用于放大第一信号,第二晶体管可用于对第一晶体管的输出信号进行非线性补偿;由于第三晶体管的沟道处于强反型状态、第四晶体管的沟道处于弱反型状态,因而第三晶体管可用于放大第二信号,第四晶体管可用于对第三晶体管的输出信号进行非线性补偿。Specifically, since the channel of the first transistor is in a strong inversion state and the channel of the second transistor is in a weak inversion state, the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor. The signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
在一种可能的设计中,第一晶体管的栅极用于接收第一信号,第一晶体管的源极耦合接地,第一晶体管的漏极与放大器的负载耦合;第二晶体管的源极耦合接地,第二晶体管的漏极与放大器的负载耦合;第三晶体管的栅极用于接收第二信号,第三晶体管的源极耦合接地,第三晶体管的漏极与放大器的负载耦合;第四晶体管的源极耦合接地,第四晶体管的漏极与放大器的负载耦合。In a possible design, the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, the drain of the first transistor is coupled to the load of the amplifier; the source of the second transistor is coupled to ground , The drain of the second transistor is coupled to the load of the amplifier; the gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifier; the fourth transistor The source of the transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifier.
第三方面,本申请实施例提供一种放大装置,该放大装置包括放大器和闭环反馈电路。其中,该放大器包括用于放大第一信号的至少一个第一增益电路和用于放大第二信号的至少一个第二增益电路。每个第一增益电路包括第一晶体管和第二晶体管;第一晶体管的沟道处于强反型状态,第二晶体管的沟道处于弱反型状态;每个第二增益电路包括第三晶体管和第四晶体管;第三晶体管的沟道处于强反型状态,第四晶体管的沟道处于弱反型状态;第一信号和第二信号构成差分信号;其中,第一晶体管和第三晶体管的栅极偏置电压为通过第一电流源产生的第一电压,第二晶体管和第四晶体管的栅极偏置电压为第二电压;闭环反馈电路,用于产生第二电压。In a third aspect, an embodiment of the present application provides an amplifying device, which includes an amplifier and a closed-loop feedback circuit. Wherein, the amplifier includes at least one first gain circuit for amplifying the first signal and at least one second gain circuit for amplifying the second signal. Each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; each second gain circuit includes a third transistor and The fourth transistor; the channel of the third transistor is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal and the second signal constitute a differential signal; wherein the gates of the first transistor and the third transistor The pole bias voltage is the first voltage generated by the first current source, and the gate bias voltages of the second transistor and the fourth transistor are the second voltage; the closed loop feedback circuit is used to generate the second voltage.
采用上述方案,由于第一晶体管和第三晶体管的沟道处于强反型状态,因而可以分别通过第一晶体管和第三晶体管实现对第一信号和第二信号的放大;由于第二晶体管和第四晶体管的沟道处于弱反型状态,因而可以分别通过第二晶体管和第四晶体管对第一晶体管的输出信号和第三晶体管的输出信号进行非线性补偿,提高放大器的线性度。With the above solution, since the channels of the first transistor and the third transistor are in a strong inversion state, the first signal and the second signal can be amplified by the first transistor and the third transistor respectively; because the second transistor and the second transistor The channels of the four transistors are in a weak inversion state, so the output signal of the first transistor and the output signal of the third transistor can be non-linearly compensated by the second transistor and the fourth transistor respectively, thereby improving the linearity of the amplifier.
此外,由于第一晶体管和第三晶体管由第一电流源提供偏置,因而第一晶体管和第三晶体管的增益波动和功耗波动也较小。第二晶体管和第四晶体管通过闭环反馈电路提供偏置时,虽然通过闭环反馈电路提供偏置会导致增益波动和功耗波动,但是第二晶体管和第四晶体管的沟道处于弱反型状态,其增益较小、产生的功耗也较小,因而即使出现增益波动和功耗波动,其波动的数值对第一增益电路和第二增益电路也难以产生较大影响。因此,在第三方面提供的放大装置中,第一增益电路和第二增益电路的增益波动和功耗波动较小。In addition, since the first transistor and the third transistor are biased by the first current source, the gain fluctuation and power consumption fluctuation of the first transistor and the third transistor are also small. When the second transistor and the fourth transistor are biased through the closed-loop feedback circuit, although the bias provided by the closed-loop feedback circuit will cause fluctuations in gain and power consumption, the channels of the second and fourth transistors are in a weak inversion state. The gain is small and the power consumption is small, so even if gain fluctuations and power consumption fluctuations occur, the value of the fluctuations will hardly have a large impact on the first gain circuit and the second gain circuit. Therefore, in the amplifying device provided by the third aspect, the gain fluctuation and power consumption fluctuation of the first gain circuit and the second gain circuit are small.
综上所述,第三方面提供的放大装置中,增益和功耗主要由第一晶体管和第三晶体管决定;第二晶体管和第四晶体管负责抵消非线性,只贡献很低比例的功耗和增益。因而在第三方面提供的放大装置中,可以通过第二晶体管和第四晶体管提高放大器的线性度的同时,减小放大器的增益波动和功耗波动。To sum up, in the amplifying device provided by the third aspect, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for offsetting the nonlinearity, and only contribute a very low proportion of the power consumption and power consumption. Gain. Therefore, in the amplifying device provided by the third aspect, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
具体地,由于第一晶体管的沟道处于强反型状态、第二晶体管的沟道处于弱反型状态,因而第一晶体管可用于放大第一信号,第二晶体管可用于对第一晶体管的输出信号进行非线性补偿;由于第三晶体管的沟道处于强反型状态、第四晶体管的沟道处于弱反型状态,因而第三晶体管可用于放大第二信号,第四晶体管可用于对第三晶体管的输出信号进行非线性补偿。Specifically, since the channel of the first transistor is in a strong inversion state and the channel of the second transistor is in a weak inversion state, the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor. The signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
在一种可能的设计中,闭环反馈电路包括第一差分放大电路、第二差分放大电路、第三差分放大电路和第四差分放大电路;其中,第一差分放大电路和第三差分放大电路的直流偏置由第二电流源产生;第二差分放大电路和第四差分放大电路的直流偏置为闭环反馈电路的输出电压。In a possible design, the closed-loop feedback circuit includes a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, and a fourth differential amplifier circuit; among them, the first differential amplifier circuit and the third differential amplifier circuit The DC bias is generated by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit.
进一步地,第三差分放大电路的增益系数可以为第一差分放大电路的增益系数的1/m,第三差分放大电路的交流输入电压可以为第一差分放大电路的交流输入电压的m倍,m>1;第四差分放大电路的增益系数可以为第二差分放大电路的增益系数的1/m,第四差分放大电路的交流输入电压可以为第二差分放大电路的交流输入电压的m倍。Further, the gain coefficient of the third differential amplifier circuit may be 1/m of the gain coefficient of the first differential amplifier circuit, and the AC input voltage of the third differential amplifier circuit may be m times the AC input voltage of the first differential amplifier circuit, m>1; the gain coefficient of the fourth differential amplifier circuit can be 1/m of the gain coefficient of the second differential amplifier circuit, and the AC input voltage of the fourth differential amplifier circuit can be m times the AC input voltage of the second differential amplifier circuit .
采用上述方案,可以将第一差分放大电路和第二差分放大电路构造成小输入信号、大增益系数的差分放大电路,将第三差分放大电路和第四差分放大电路构造成大输入信号、小增益系数的差分放大电路。With the above solution, the first differential amplifier circuit and the second differential amplifier circuit can be constructed as a differential amplifier circuit with a small input signal and a large gain coefficient, and the third differential amplifier circuit and the fourth differential amplifier circuit can be constructed as a large input signal, small Differential amplifier circuit with gain coefficient.
在一种可能的设计中,闭环反馈电路还包括:误差放大器,用于对第一差分放大电路和第二差分放大电路合路后的输出信号以及第三差分放大电路和第四差分放大电路合路后的输出信号的误差进行比较,输出第二电压。In a possible design, the closed-loop feedback circuit further includes: an error amplifier for combining the output signal of the first differential amplifier circuit and the second differential amplifier circuit, and the third differential amplifier circuit and the fourth differential amplifier circuit. The error of the output signal after the circuit is compared, and the second voltage is output.
采用上述方案,可以对小输入信号、大增益系数的差分放大电路的输出信号和大输入信号、小增益系数的差分放大电路的输出信号进行比较,在两个输出信号近似相同的情况下,用于非线性补偿的晶体管可以对其补偿的晶体管的非线性进行补偿,因而通过上述方案可以得到符合设计要求的栅极偏置电压。Using the above solution, the output signal of the differential amplifier circuit with small input signal and large gain coefficient can be compared with the output signal of the differential amplifier circuit with large input signal and small gain coefficient. When the two output signals are approximately the same, use The non-linear compensation transistor can compensate the non-linearity of the transistor that it compensates. Therefore, the gate bias voltage that meets the design requirements can be obtained through the above solution.
在一种可能的设计中,闭环反馈电路还包括:第一跨阻放大器,第一差分放大电路的正输出端以及第二差分放大电路的正输出端耦合至第一跨阻放大器的负输入端,第一差分放大电路的负输出端以及第二差分放大电路的负输出端耦合至第一跨阻放大器的正输入端;第二跨阻放大器,第三差分放大电路的正输出端以及第四差分放大电路的正输出端耦合至第二跨阻放大器的负输入端,第三差分放大电路的负输出端以及第四差分放大电路的负输出端耦合至第二跨阻放大器的正输入端;第二跨阻放大器的放大倍数与第一跨阻放大器的放大倍数相同;误其中,第一跨阻放大器的正输出端和第二跨阻放大器的正输出端耦合至误差放大器的负输入端,第一跨阻放大器的负输出端和第二跨阻放大器的负输出端耦合至误差放大器的正输入端。In a possible design, the closed loop feedback circuit further includes: a first transimpedance amplifier, the positive output terminal of the first differential amplifier circuit, and the positive output terminal of the second differential amplifier circuit are coupled to the negative input terminal of the first transimpedance amplifier , The negative output terminal of the first differential amplifier circuit and the negative output terminal of the second differential amplifier circuit are coupled to the positive input terminal of the first transimpedance amplifier; the second transimpedance amplifier, the positive output terminal of the third differential amplifier circuit and the fourth The positive output terminal of the differential amplifier circuit is coupled to the negative input terminal of the second transimpedance amplifier, and the negative output terminal of the third differential amplifier circuit and the negative output terminal of the fourth differential amplifier circuit are coupled to the positive input terminal of the second transimpedance amplifier; The amplification factor of the second transimpedance amplifier is the same as the amplification factor of the first transimpedance amplifier; by mistake, the positive output terminal of the first transimpedance amplifier and the positive output terminal of the second transimpedance amplifier are coupled to the negative input terminal of the error amplifier, The negative output terminal of the first transimpedance amplifier and the negative output terminal of the second transimpedance amplifier are coupled to the positive input terminal of the error amplifier.
采用上述方案,第一差分放大电路和第三差分放大电路的直流偏置由第二电流源提供;第二差分放大电路和第四差分放大电路的直流偏置为闭环反馈电路的输出电压。因而第二差分放大电路可以对第一差分放大电路进行非线性补偿,第四差分放大电路可以对第三差分放大电路进行非线性补偿。通过反馈方式找到的第二差分放大电路和第四差分放大电路的直流偏置,可以作为放大器中第二晶体管和第四晶体管的直流偏置,使得第二晶体管可以对第一晶体管的输出信号进行非线性补偿,并使得第四晶体管可以对第三晶体管的输出信号进行非线性补偿。With the above solution, the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is provided by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit. Therefore, the second differential amplifier circuit can perform nonlinear compensation on the first differential amplifier circuit, and the fourth differential amplifier circuit can perform nonlinear compensation on the third differential amplifier circuit. The DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit found through feedback can be used as the DC bias of the second transistor and the fourth transistor in the amplifier, so that the second transistor can perform the output signal of the first transistor. Non-linear compensation, and enables the fourth transistor to perform non-linear compensation on the output signal of the third transistor.
进一步地,第一差分放大电路包括至少一个第五晶体管以及至少一个第六晶体管,第五晶体管的栅极与第一差分放大电路的正输入端耦合,第六晶体管的栅极与第一差分放大电路的负输入端耦合,第五晶体管的数量通过将放大装置中第一晶体管的数量以第一比例缩小后得到,第六晶体管的数量通过将放大装置中第三晶体管的数以第一比例缩小后得到;第二差分放大电路包括至少一个第七晶体管以及至少一个第八晶体管,第七晶体管的栅极与第二差分放大电路的正输入端耦合,第八晶体管的栅极与第二差分放大电路的负输入端耦合,第七晶体管的数量通过将放大装置中第二晶体管的数量以第一比例缩小后得到,第八晶体管的数量通过将放大装置中第四晶体管的数量以第一比例缩小后得到;第三差分放大电路包括至少一个第九晶体管以及至少一个第十晶体管,第九晶体管的栅极与第三差分放大电路的正输入端耦合,第十晶体管的栅极与第三差分放大电路的负输入端耦合,第九晶体管的数量通过将放大装置中第一晶体管的数量以第二比例缩小后得到,第十晶体管的数量通过将放大装置中第三晶体管的数量以第二比例缩小后得到;第四差分放大电路包括至少一个第十一晶体管以及至少一个第十二晶体管,第十一晶体管的栅极与第四差分放大电路的正输入端耦合,第十二晶体管的栅极与第四差分放大电路的负输入端耦合,第十一 晶体管的数量通过将放大装置中第二晶体管的数量以第二比例缩小后得到,第十二晶体管的数量通过将放大装置中第四晶体管的数量以第二比例缩小后得到。Further, the first differential amplifier circuit includes at least one fifth transistor and at least one sixth transistor, the gate of the fifth transistor is coupled to the positive input terminal of the first differential amplifier circuit, and the gate of the sixth transistor is coupled to the first differential amplifier. The negative input terminal of the circuit is coupled, the number of the fifth transistor is obtained by reducing the number of the first transistor in the amplifying device by the first ratio, and the number of the sixth transistor is obtained by reducing the number of the third transistor in the amplifying device by the first ratio The second differential amplifier circuit includes at least one seventh transistor and at least one eighth transistor. The gate of the seventh transistor is coupled to the positive input terminal of the second differential amplifier circuit, and the gate of the eighth transistor is coupled to the second differential amplifier. The negative input terminal of the circuit is coupled, the number of the seventh transistor is obtained by reducing the number of the second transistor in the amplifying device by the first ratio, and the number of the eighth transistor is obtained by reducing the number of the fourth transistor in the amplifying device by the first ratio The third differential amplifier circuit includes at least one ninth transistor and at least one tenth transistor. The gate of the ninth transistor is coupled to the positive input terminal of the third differential amplifier circuit, and the gate of the tenth transistor is coupled to the third differential amplifier. The negative input terminal of the circuit is coupled. The number of the ninth transistor is obtained by reducing the number of the first transistor in the amplifying device by the second ratio, and the number of the tenth transistor is obtained by reducing the number of the third transistor in the amplifying device by the second ratio. After obtaining; the fourth differential amplifier circuit includes at least one eleventh transistor and at least one twelfth transistor, the gate of the eleventh transistor is coupled to the positive input of the fourth differential amplifier circuit, and the gate of the twelfth transistor is coupled to The negative input of the fourth differential amplifier circuit is coupled, the number of the eleventh transistor is obtained by reducing the number of the second transistor in the amplifying device by the second ratio, and the number of the twelfth transistor is obtained by reducing the number of the fourth transistor in the amplifying device The quantity is obtained after the second scale is reduced.
采用上述方案,第一差分放大电路、第二差分放大电路、第三差分放大电路和第四差分放大电路均通过将放大装置中的晶体管的数量做一定缩减后形成,可以降低闭环反馈电路的功耗,从而使得放大器的功耗主要用于放大输入信号,仅用较小的功耗确定第二晶体管和第四晶体管的栅极偏置电压,来补偿输出信号的非线性。With the above solution, the first differential amplifying circuit, the second differential amplifying circuit, the third differential amplifying circuit, and the fourth differential amplifying circuit are all formed by reducing the number of transistors in the amplifying device to a certain extent, which can reduce the power of the closed-loop feedback circuit. Therefore, the power consumption of the amplifier is mainly used to amplify the input signal, and only a small power consumption is used to determine the gate bias voltage of the second transistor and the fourth transistor to compensate for the nonlinearity of the output signal.
此外,闭环反馈电路还可包括:第二电流源,用于为第一差分放大电路和第三差分放大电路提供直流偏置;缓冲器,用于为第二差分放大电路和第四差分放大电路提供直流偏置,缓冲器的输入端与闭环反馈电路的输出端耦合;依次串联的第一电阻、第二电阻、第三电阻和第四电阻;第一电阻耦合至第一电源,第四电阻耦合接地,第二电阻和第三电阻与第二电流源耦合;第一电阻与第二电阻的阻值之比为m-1,第四电阻与第三电阻的阻值之比为m-1,第二电阻与第三电阻的阻值相同;其中,第一电阻与第一电源的连接处与第三差分放大电路的正输入端耦合,第四电阻的耦合接地端与第三差分放大电路的负输入端耦合;第一电阻与第二电阻的连接处与第一差分放大电路的正输入端耦合,第三电阻和第四电阻的连接处与第一差分放大电路的负输入端耦合;依次串联的第五电阻、第六电阻、第七电阻和第八电阻;第五电阻耦合至第二电源,第八电阻耦合接地,第六电阻和第七电阻与缓冲器的输出端耦合;第五电阻与第六电阻的阻值之比为m-1,第八电阻与第七电阻的阻值之比为m-1,第六电阻与第七电阻的阻值相同;其中,第五电阻与第二电源的连接处与第四差分放大电路的正输入端耦合,第八电阻的耦合接地端与第四差分放大电路的负输入端耦合;第五电阻与第六电阻的连接处与第二差分放大电路的正输入端耦合,第七电阻和第八电阻的连接处与第二差分放大电路的负输入端耦合。In addition, the closed-loop feedback circuit may further include: a second current source for providing a DC bias for the first differential amplifier circuit and the third differential amplifier circuit; a buffer for the second differential amplifier circuit and the fourth differential amplifier circuit Provides a DC bias, the input of the buffer is coupled to the output of the closed loop feedback circuit; the first resistor, the second resistor, the third resistor, and the fourth resistor are connected in series in sequence; the first resistor is coupled to the first power supply and the fourth resistor Coupled to ground, the second resistor and the third resistor are coupled to the second current source; the resistance ratio of the first resistance to the second resistance is m-1, and the resistance ratio of the fourth resistance to the third resistance is m-1 , The second resistor and the third resistor have the same resistance; where the connection between the first resistor and the first power supply is coupled to the positive input end of the third differential amplifier circuit, and the coupling ground end of the fourth resistor is coupled to the third differential amplifier circuit The connection of the first resistor and the second resistor is coupled to the positive input of the first differential amplifier circuit, and the connection of the third resistor and the fourth resistor is coupled to the negative input of the first differential amplifier circuit; The fifth resistor, the sixth resistor, the seventh resistor, and the eighth resistor are connected in series in sequence; the fifth resistor is coupled to the second power source, the eighth resistor is coupled to the ground, and the sixth resistor and the seventh resistor are coupled to the output terminal of the buffer; The resistance ratio of the fifth resistor to the sixth resistor is m-1, the resistance ratio of the eighth resistor to the seventh resistor is m-1, and the resistance of the sixth resistor and the seventh resistor are the same; among them, the fifth resistor The connection with the second power supply is coupled with the positive input end of the fourth differential amplifier circuit, the coupling ground end of the eighth resistor is coupled with the negative input end of the fourth differential amplifier circuit; the connection between the fifth resistor and the sixth resistor is coupled with the first The positive input ends of the two differential amplifier circuits are coupled, and the junction of the seventh resistor and the eighth resistor is coupled with the negative input end of the second differential amplifier circuit.
采用上述实现方案,可以通过第二电流源、缓冲器和多个电阻为四个差分放大电路提供交流输入和直流偏置。缓冲器可以保存闭环反馈电路的输出电压并输出,使得第二差分放大电路和第四差分放大电路的直流偏置为一个稳定的电压值,不会随电流变化而发生波动。By adopting the above implementation scheme, the AC input and DC bias can be provided for the four differential amplifier circuits through the second current source, the buffer and the multiple resistors. The buffer can save and output the output voltage of the closed-loop feedback circuit, so that the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is a stable voltage value, and will not fluctuate with current changes.
其中,第二电流源可以由第一电流源镜像偏置后得到。例如,第二电流源可以包括第一电流源、N型MOS管(即NMOS)和P型MOS管(即PMOS),第一电流源依次经过NMOS和PMOS后输出,作为第一差分放大电路和第三差分放大电路的直流偏置。Wherein, the second current source can be obtained by mirror biasing of the first current source. For example, the second current source may include a first current source, an N-type MOS tube (i.e. NMOS) and a P-type MOS tube (i.e. PMOS). The first current source is output after passing through NMOS and PMOS in turn, as the first differential amplifier circuit and The DC bias of the third differential amplifier circuit.
在一种可能的设计中,第一晶体管的栅极用于接收第一信号,第一晶体管的源极耦合接地,第一晶体管的漏极与放大装置的负载耦合;第二晶体管的源极耦合接地,第二晶体管的漏极与放大装置的负载耦合;第三晶体管的栅极用于接收第二信号,第三晶体管的源极耦合接地,第三晶体管的漏极与放大装置的负载耦合;第四晶体管的源极耦合接地,第四晶体管的漏极与放大装置的负载耦合。In a possible design, the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, the drain of the first transistor is coupled to the load of the amplifying device; the source of the second transistor is coupled Ground, the drain of the second transistor is coupled to the load of the amplifying device; the gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifying device; The source of the fourth transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifying device.
采用上述方案,提供了一种第一晶体管、第二晶体管、第三晶体管和第四晶体管的一种具体连接方式。With the above solution, a specific connection manner of the first transistor, the second transistor, the third transistor and the fourth transistor is provided.
附图说明Description of the drawings
图1为现有技术提供的一种放大器的结构示意图;FIG. 1 is a schematic diagram of the structure of an amplifier provided in the prior art;
图2为现有技术提供的一种反馈电路的结构示意图;Fig. 2 is a schematic structural diagram of a feedback circuit provided in the prior art;
图3为本申请实施例提供的一种放大器的结构示意图;3 is a schematic structural diagram of an amplifier provided by an embodiment of the application;
图4为本申请实施例提供的另一种放大器的结构示意图;FIG. 4 is a schematic structural diagram of another amplifier provided by an embodiment of the application;
图5为本申请实施例提供的一种放大装置的结构示意图;FIG. 5 is a schematic structural diagram of an amplification device provided by an embodiment of the application;
图6为本申请实施例提供的一种串联电阻的结构示意图;FIG. 6 is a schematic structural diagram of a series resistor provided by an embodiment of the application;
图7为本申请实施例提供的另一种串联电阻的结构示意图;FIG. 7 is a schematic structural diagram of another series resistor provided by an embodiment of the application;
图8为本申请实施例提供的一种闭环反馈电路的结构示意图;8 is a schematic structural diagram of a closed-loop feedback circuit provided by an embodiment of the application;
图9为本申请实施例提供的另一种闭环反馈电路的结构示意图;9 is a schematic structural diagram of another closed-loop feedback circuit provided by an embodiment of the application;
图10为本申请实施例提供的一种放大器总增益的变化曲线示意图。FIG. 10 is a schematic diagram of a variation curve of the total gain of an amplifier provided by an embodiment of the application.
具体实施方式Detailed ways
如背景技术中所述,随着宽带无线通信的发展,射频前端放大器需兼顾增益、噪声、线性度及功耗等多个指标。As described in the background art, with the development of broadband wireless communications, RF front-end amplifiers need to take into account multiple indicators such as gain, noise, linearity, and power consumption.
为了提高放大器的线性度,现有技术通常采用图2所示的反馈电路为图1所示的放大器中的有源晶体管提供偏置。虽然采用图2所示的反馈电路可以提高放大器的线性度,但是会导致放大器的增益波动较大,即难以兼顾放大器的增益、功耗和线性度指标。In order to improve the linearity of the amplifier, the prior art usually uses the feedback circuit shown in FIG. 2 to provide bias for the active transistors in the amplifier shown in FIG. 1. Although the feedback circuit shown in Figure 2 can improve the linearity of the amplifier, it will cause the amplifier's gain to fluctuate greatly, that is, it is difficult to balance the amplifier's gain, power consumption, and linearity indicators.
本申请实施例提供一种放大器及放大装置,用以在提高放大器的线性度的同时,减小放大器的增益和功耗波动。The embodiments of the present application provide an amplifier and an amplifying device, which are used to improve the linearity of the amplifier while reducing fluctuations in the gain and power consumption of the amplifier.
下面将结合附图对本申请实施例作进一步地详细描述。The embodiments of the present application will be described in further detail below in conjunction with the accompanying drawings.
需要说明的是,本申请实施例中,多个是指两个或两个以上。另外,需要理解的是,在本申请的描述中,“第一”、“第二”等词汇,仅用于区分描述的目的,而不能理解为指示或暗示相对重要性,也不能理解为指示或暗示顺序。本申请中所提到的“耦合”,是指电学连接,具体可以包括直接连接或者间接连接两种方式。It should be noted that in the embodiments of the present application, multiple refers to two or more. In addition, it should be understood that in the description of this application, words such as “first” and “second” are only used for the purpose of distinguishing description, and cannot be understood as indicating or implying relative importance, nor can it be understood as indicating Or imply the order. The "coupling" mentioned in this application refers to electrical connection, which specifically may include direct connection or indirect connection.
参见图3,为本申请实施例提供的一种放大器300。该放大器300包括用于放大第一信号的至少一个第一增益电路301以及用于放大第二信号的至少一个第二增益电路302。每个第一增益电路301包括第一晶体管301a和第二晶体管301b;第一晶体管301a的沟道处于强反型(strong inversion)状态,第二晶体管301b的沟道处于弱反型(weak inversion)状态;每个第二增益电路302包括第三晶体管302a和第四晶体管302b;第三晶体管302a的沟道处于强反型状态,第四晶体管302b的沟道处于弱反型状态。其中,第一信号和第二信号构成差分信号,第一晶体管301a和第三晶体管302a的栅极偏置电压为第一电压,第二晶体管301b和第四晶体管302b的栅极偏置电压为第二电压。Referring to FIG. 3, an amplifier 300 provided in an embodiment of this application. The amplifier 300 includes at least one first gain circuit 301 for amplifying a first signal and at least one second gain circuit 302 for amplifying a second signal. Each first gain circuit 301 includes a first transistor 301a and a second transistor 301b; the channel of the first transistor 301a is in a strong inversion state, and the channel of the second transistor 301b is in a weak inversion state. State; each second gain circuit 302 includes a third transistor 302a and a fourth transistor 302b; the channel of the third transistor 302a is in a strong inversion state, and the channel of the fourth transistor 302b is in a weak inversion state. Among them, the first signal and the second signal constitute a differential signal, the gate bias voltages of the first transistor 301a and the third transistor 302a are the first voltage, and the gate bias voltages of the second transistor 301b and the fourth transistor 302b are the first voltage. Two voltage.
其中,强反型状态的具体含义可以是:晶体管的栅极—源极间电压VGS比晶体管的阈值电压VT大很多,在栅氧化膜下方构成反型层(沟道),在晶体管的漏极-源极间有电流活动,这种状态称为强反型状态。弱反型状态的具体含义可以是:晶体管的栅极—源极间电压VGS小于晶体管的阈值电压VT且漏极仍有微小的电流活动,这种状态称为弱反型状态。Among them, the specific meaning of the strong inversion state can be: the gate-source voltage VGS of the transistor is much larger than the threshold voltage VT of the transistor, an inversion layer (channel) is formed under the gate oxide film, and the transistor drain -There is current activity between the sources. This state is called a strong inversion state. The specific meaning of the weak inversion state can be: the gate-source voltage VGS of the transistor is less than the threshold voltage VT of the transistor and the drain still has a small current activity. This state is called the weak inversion state.
具体地,在放大器300中,由于第一晶体管301a的沟道处于强反型状态,第二晶体管301b的沟道处于弱反型状态,因而第一晶体管301a可用于放大第一信号,第二晶体管301b可用于对第一晶体管301a的输出信号进行非线性补偿;由于第三晶体管302a的沟道处于强反型状态、第四晶体管302b的沟道处于弱反型状态,因而第三晶体管302a可用于放大第二信号,第四晶体管302b可用于对第三晶体管302a的输出信号进行非线性补偿。Specifically, in the amplifier 300, since the channel of the first transistor 301a is in a strong inversion state and the channel of the second transistor 301b is in a weak inversion state, the first transistor 301a can be used to amplify the first signal and the second transistor 301b can be used for nonlinear compensation of the output signal of the first transistor 301a; since the channel of the third transistor 302a is in a strong inversion state and the channel of the fourth transistor 302b is in a weak inversion state, the third transistor 302a can be used for Amplifying the second signal, the fourth transistor 302b can be used to perform nonlinear compensation on the output signal of the third transistor 302a.
在图3所示的放大器300中,可以分别通过第一晶体管301a和第三晶体管302a实现对第一信号和第二信号的放大,并分别通过第二晶体管301b和第四晶体管302b对第一晶体管301a的输出信号和第三晶体管302a的输出信号进行非线性补偿,提高放大器300的线性度。In the amplifier 300 shown in FIG. 3, the first signal and the second signal can be amplified by the first transistor 301a and the third transistor 302a respectively, and the first transistor can be amplified by the second transistor 301b and the fourth transistor 302b respectively. The output signal of 301a and the output signal of the third transistor 302a perform nonlinear compensation to improve the linearity of the amplifier 300.
此外,在放大器300中,第二晶体管301b和第四晶体管302b的沟道处于弱反型状态,,其增益较小、产生的功耗也较小。因此,放大器300的增益和功耗主要由第一晶体管301a和第三晶体管302a决定;第二晶体管301b和第四晶体管302b负责抵消非线性,只贡献很低比例的功耗和增益。因而在放大器300中,可以通过第二晶体管301b和第四晶体管302b提高放大器300的线性度的同时,减小放大器300的增益波动和功耗波动。In addition, in the amplifier 300, the channels of the second transistor 301b and the fourth transistor 302b are in a weak inversion state, and their gain is small and the power consumption is small. Therefore, the gain and power consumption of the amplifier 300 are mainly determined by the first transistor 301a and the third transistor 302a; the second transistor 301b and the fourth transistor 302b are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifier 300, the linearity of the amplifier 300 can be improved through the second transistor 301b and the fourth transistor 302b, and the gain fluctuation and power consumption fluctuation of the amplifier 300 can be reduced.
具体实现时,放大器300中,第一晶体管301a、第二晶体管301b、第三晶体管302a和第四晶体管302b的具体连接方式可以是:第一晶体管301a的栅极用于接收第一信号,第一晶体管301a的源极耦合接地,第一晶体管301a的漏极与放大器300的负载耦合;第二晶体管301b的源极耦合接地,第二晶体管301b的漏极与放大器300的负载耦合;第三晶体管302a的栅极用于接收第二信号,第三晶体管302a的源极耦合接地,第三晶体管302a的漏极与放大器300的负载耦合;第四晶体管302b的源极耦合接地,第四晶体管302b的漏极与放大器300的负载耦合。In specific implementation, in the amplifier 300, the specific connection mode of the first transistor 301a, the second transistor 301b, the third transistor 302a and the fourth transistor 302b may be: the gate of the first transistor 301a is used to receive the first signal, The source of the transistor 301a is coupled to ground, the drain of the first transistor 301a is coupled to the load of the amplifier 300; the source of the second transistor 301b is coupled to ground, and the drain of the second transistor 301b is coupled to the load of the amplifier 300; the third transistor 302a The gate of the third transistor 302a is used to receive the second signal, the source of the third transistor 302a is coupled to ground, the drain of the third transistor 302a is coupled to the load of the amplifier 300; the source of the fourth transistor 302b is coupled to ground, and the drain of the fourth transistor 302b The pole is coupled to the load of the amplifier 300.
其中,第一晶体管301a的源极耦合接地,其含义可以是:第一晶体管301a直接接地,或者第一晶体管301a通过电感、电容等器件接地。此外,在本申请实施例的其他示例中,耦合接地的含义相同,后续将不再详细解释。Wherein, the source of the first transistor 301a is coupled to ground, which may mean that the first transistor 301a is directly grounded, or the first transistor 301a is grounded through an inductor, a capacitor, or other devices. In addition, in other examples of the embodiments of the present application, the meaning of coupling to ground is the same, which will not be explained in detail later.
需要说明的是,在本申请实施例的描述中,均以晶体管采用CMOS工艺为例进行示意。实际应用中,晶体管还可以采用其他工艺。当晶体管采用其他工艺时,晶体管的各个端口的名称会有所不同,但功能基本一致。示例性地,晶体管为双极结型晶体管(bipolar junction transistor,BJT)时,BJT中的基极相当于CMOS中的栅极;BJT中的集电极相当于CMOS中的漏极;BJT中的发射极相当于CMOS中的源极。因此,本申请中基于CMOS管实现的放大器,可以与基于BJT实现的放大器等同。It should be noted that in the description of the embodiments of the present application, the transistor adopts a CMOS process as an example for illustration. In practical applications, the transistor can also use other processes. When the transistor adopts other processes, the names of the various ports of the transistor will be different, but the functions are basically the same. Exemplarily, when the transistor is a bipolar junction transistor (BJT), the base in BJT is equivalent to the gate in CMOS; the collector in BJT is equivalent to the drain in CMOS; the emitter in BJT The pole is equivalent to the source in CMOS. Therefore, the amplifier based on the CMOS tube in this application can be equivalent to the amplifier based on the BJT.
由于晶体管采用其他工艺时的实现方式与原理与采用CMOS工艺时类似,因此本申请实施例中均以晶体管采用CMOS工艺为例进行示意,不再对采用其他工艺时的具体实现方式做详细介绍。Since the implementation methods and principles of the transistors using other processes are similar to those of the CMOS process, the embodiments of the present application take the transistors using the CMOS process as an example for illustration, and the specific implementation methods when using other processes are not described in detail.
此外,在本申请的各示例中,晶体管均采用栅极输入信号、源极耦合接地的方式,实际应用中,晶体管也可以采用源极输入信号、栅极耦合接地的方式,本申请实施例对此不做具体限定。In addition, in each example of this application, the transistors adopt the method of gate input signal and source coupling grounding. In practical applications, the transistor can also adopt the method of source input signal and gate coupling grounding. This is not specifically limited.
示例性地,当放大器300中的各个晶体管采用上述连接方式、且放大器300中包含并联谐振负载时,放大器300的一种可能的结构示意图可以如图4所示。Exemplarily, when each transistor in the amplifier 300 adopts the above-mentioned connection mode and the amplifier 300 includes a parallel resonant load, a possible schematic diagram of the structure of the amplifier 300 may be as shown in FIG. 4.
在图4所示的放大器300中,栅极与正输入端Vip耦合的晶体管可以视为第一晶体管301a,栅极与负输入端Vin耦合的晶体管可以视为第三晶体管302a,与第一晶体管301a连接的、由Vgs_Aux提供偏置的晶体管可以视为第二晶体管301b,与第三晶体管302a连接的、由Vgs_Aux提供偏置的晶体管可以视为第四晶体管302b。RLC网络组成等效后的并联谐振负载,Vop为正输出端,Von为负输出端。第一晶体管301a和第三晶体管302a分别对正输入端和负输入端输出的差分信号进行放大,可以统称为“主管”;第二晶体管301b对和第四晶体管302b分别对第一晶体管301a和第三晶体管302a的输出信号进行非 线性补偿,可以统称为“辅助补偿管”。互连的“主管”和“辅助补偿管”可以称为一个“Gm单元”。In the amplifier 300 shown in FIG. 4, the transistor whose gate is coupled to the positive input terminal Vip can be regarded as the first transistor 301a, and the transistor whose gate is coupled to the negative input terminal Vin can be regarded as the third transistor 302a, and the first transistor The transistor connected to 301a and biased by Vgs_Aux can be regarded as the second transistor 301b, and the transistor connected to the third transistor 302a and biased by Vgs_Aux can be regarded as the fourth transistor 302b. The RLC network forms an equivalent parallel resonant load, Vop is the positive output terminal, and Von is the negative output terminal. The first transistor 301a and the third transistor 302a respectively amplify the differential signal output from the positive input terminal and the negative input terminal, which can be collectively referred to as the "main pipe"; the second transistor 301b pair and the fourth transistor 302b respectively affect the first transistor 301a and the second transistor 302b. The output signal of the three transistors 302a performs nonlinear compensation, which can be collectively referred to as an "auxiliary compensation tube". The interconnected "main pipe" and "auxiliary compensation pipe" can be called a "Gm unit".
基于同一发明构思,本申请实施例还提供一种放大装置。参见图5,放大装置500中包括放大器501和闭环反馈电路502。其中,放大器501包括用于放大第一信号的至少一个第一增益电路和用于放大第二信号的至少一个第二增益电路。Based on the same inventive concept, an embodiment of the present application also provides an amplifying device. Referring to FIG. 5, the amplifying device 500 includes an amplifier 501 and a closed loop feedback circuit 502. The amplifier 501 includes at least one first gain circuit for amplifying the first signal and at least one second gain circuit for amplifying the second signal.
其中,每个第一增益电路包括第一晶体管和第二晶体管;第一晶体管的沟道处于强反型状态,第二晶体管的沟道处于弱反型状态;每个第二增益电路包括第三晶体管和第四晶体管;第三晶体管的沟道处于强反型状态,第四晶体管的沟道处于弱反型状态;第一信号和第二信号构成差分信号;第一晶体管和第三晶体管的栅极偏置电压为通过第一电流源产生的第一电压,第二晶体管和第四晶体管的栅极偏置电压为第二电压;闭环反馈电路,用于产生第二电压。Wherein, each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; each second gain circuit includes a third Transistor and fourth transistor; the channel of the third transistor is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal and the second signal constitute a differential signal; the gates of the first transistor and the third transistor The pole bias voltage is the first voltage generated by the first current source, and the gate bias voltages of the second transistor and the fourth transistor are the second voltage; the closed loop feedback circuit is used to generate the second voltage.
具体地,由于第一晶体管的沟道处于强反型状态、第二晶体管的沟道处于弱反型状态,因而第一晶体管可用于放大第一信号,第二晶体管可用于对第一晶体管的输出信号进行非线性补偿;由于第三晶体管的沟道处于强反型状态、第四晶体管的沟道处于弱反型状态,因而第三晶体管可用于放大第二信号,第四晶体管可用于对第三晶体管的输出信号进行非线性补偿。Specifically, since the channel of the first transistor is in a strong inversion state and the channel of the second transistor is in a weak inversion state, the first transistor can be used to amplify the first signal, and the second transistor can be used to output the first transistor. The signal is nonlinearly compensated; since the channel of the third transistor is in a strong inversion state and the channel of the fourth transistor is in a weak inversion state, the third transistor can be used to amplify the second signal, and the fourth transistor can be used to The output signal of the transistor performs nonlinear compensation.
在放大装置500中,放大器501的具体实现方式可以参见图3所示的放大器300中的相关描述,此处不再赘述。In the amplifying device 500, the specific implementation of the amplifier 501 can be referred to the related description in the amplifier 300 shown in FIG. 3, which will not be repeated here.
在图5所示的放大装置500中,可以分别通过第一晶体管和第三晶体管实现对第一信号和第二信号的放大。由于第一晶体管和第三晶体管通过第一电流源提供偏置,因而难以保证第一晶体管和第三晶体管能置位在n阶非线性最小的偏置点。本申请实施例中,可分别通过第二晶体管和第四晶体管对第一晶体管的输出信号和第三晶体管的输出信号进行非线性补偿,因而可以提高放大装置500的线性度。In the amplifying device 500 shown in FIG. 5, the first signal and the second signal can be amplified by the first transistor and the third transistor, respectively. Since the first transistor and the third transistor are biased by the first current source, it is difficult to ensure that the first transistor and the third transistor can be set at the bias point with the smallest n-th order nonlinearity. In the embodiment of the present application, the second transistor and the fourth transistor can be used to perform nonlinear compensation on the output signal of the first transistor and the output signal of the third transistor, so that the linearity of the amplifying device 500 can be improved.
此外,第一晶体管和第三晶体管由第一电流源提供偏置,这种偏置方式可以视为固定偏置,其偏置电压波动较小,因而第一晶体管和第三晶体管的增益波动和功耗波动也较小。第二晶体管和第四晶体管通过闭环反馈电路502提供偏置时,虽然通过闭环反馈电路502提供偏置会导致增益波动和功耗波动,但是第二晶体管和第四晶体管是用于进行非线性补偿的晶体管,其增益较小、产生的功耗也较小,因而即使出现增益波动和功耗波动,其波动的数值对第一增益电路和第二增益电路也难以产生较大影响。因此,放大装置500中,第一增益电路和第二增益电路的增益波动和功耗波动较小。In addition, the first transistor and the third transistor are biased by the first current source. This bias mode can be regarded as a fixed bias, and its bias voltage fluctuation is small, so the gain fluctuations of the first transistor and the third transistor are combined. The power consumption fluctuation is also small. When the second transistor and the fourth transistor are biased by the closed-loop feedback circuit 502, although the bias provided by the closed-loop feedback circuit 502 will cause fluctuations in gain and power consumption, the second and fourth transistors are used for nonlinear compensation. The transistor has a small gain and low power consumption. Therefore, even if gain fluctuations and power consumption fluctuations occur, the value of the fluctuations will hardly have a large impact on the first gain circuit and the second gain circuit. Therefore, in the amplifying device 500, the gain fluctuation and power consumption fluctuation of the first gain circuit and the second gain circuit are small.
综上所述,放大装置500中,增益和功耗主要由第一晶体管和第三晶体管决定;第二晶体管和第四晶体管负责抵消非线性,只贡献很低比例的功耗和增益。因而在放大装置500中,可以通过第二晶体管和第四晶体管提高放大器的线性度的同时,减小放大器的增益波动和功耗波动。To sum up, in the amplifying device 500, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of power consumption and gain. Therefore, in the amplifying device 500, the linearity of the amplifier can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier can be reduced.
具体实现时,放大装置500中,第一晶体管、第二晶体管、第三晶体管和第四晶体管的具体连接方式可以是:第一晶体管的栅极用于接收第一信号,第一晶体管的源极耦合接地,第一晶体管的漏极与放大装置500的负载耦合;第二晶体管的源极耦合接地,第二晶体管的漏极与放大装置500的负载耦合;第三晶体管的栅极用于接收第二信号,第三晶体管的源极耦合接地,第三晶体管的漏极与放大装置500的负载耦合;第四晶体管的源极耦 合接地,第四晶体管的漏极与放大装置500的负载耦合。In specific implementation, in the amplifying device 500, the specific connection mode of the first transistor, the second transistor, the third transistor, and the fourth transistor may be: the gate of the first transistor is used to receive the first signal, and the source of the first transistor Coupled to ground, the drain of the first transistor is coupled to the load of the amplifying device 500; the source of the second transistor is coupled to ground, and the drain of the second transistor is coupled to the load of the amplifying device 500; the gate of the third transistor is used to receive the first For two signals, the source of the third transistor is coupled to the ground, the drain of the third transistor is coupled to the load of the amplifying device 500; the source of the fourth transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifying device 500.
在一种可能的实现方式中,放大装置500中还可包括并联谐振负载,并联谐振负载可以视为放大装置300的等效负载。并联谐振负载的输入端分别与第一增益电路的输出端以及第二增益电路的输出端耦合。In a possible implementation manner, the amplifying device 500 may further include a parallel resonant load, and the parallel resonant load may be regarded as an equivalent load of the amplifying device 300. The input terminal of the parallel resonant load is respectively coupled with the output terminal of the first gain circuit and the output terminal of the second gain circuit.
其中,并联谐振负载可以为输出匹配网络,或者巴伦(balun)等器件。Among them, the parallel resonant load can be an output matching network, or a device such as a balun.
具体实现时,闭环反馈电路302可以包括:第一差分放大电路、第二差分放大电路、第三差分放大电路和第四差分放大电路、第一跨阻放大器、第二跨阻放大器和误差放大。其中,第一差分放大电路和第三差分放大电路的直流偏置由第二电流源提供;第二差分放大电路和第四差分放大电路的直流偏置为闭环反馈电路的输出电压。In specific implementation, the closed-loop feedback circuit 302 may include: a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, and a fourth differential amplifier circuit, a first transimpedance amplifier, a second transimpedance amplifier, and error amplification. Wherein, the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is provided by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit.
进一步地,第三差分放大电路的增益系数为第一差分放大电路的增益系数的1/m,第三差分放大电路的交流输入电压为第一差分放大电路的交流输入电压的m倍,m>1;第四差分放大电路的增益系数为第二差分放大电路的增益系数的1/m,第四差分放大电路的交流输入电压为第二差分放大电路的交流输入电压的m倍。Further, the gain coefficient of the third differential amplifier circuit is 1/m of the gain coefficient of the first differential amplifier circuit, and the AC input voltage of the third differential amplifier circuit is m times the AC input voltage of the first differential amplifier circuit, m> 1; The gain coefficient of the fourth differential amplifier circuit is 1/m of the gain coefficient of the second differential amplifier circuit, and the AC input voltage of the fourth differential amplifier circuit is m times the AC input voltage of the second differential amplifier circuit.
不难看出,采用上述方案,可以将第一差分放大电路和第二差分放大电路构造成小输入信号、大增益系数的差分放大电路,将第三差分放大电路和第四差分放大电路构造成大输入信号、小增益系数的差分放大电路。It is not difficult to see that with the above solution, the first differential amplifier circuit and the second differential amplifier circuit can be constructed as a differential amplifier circuit with a small input signal and a large gain coefficient, and the third differential amplifier circuit and the fourth differential amplifier circuit can be constructed as a large Input signal, differential amplifier circuit with small gain coefficient.
此外,闭环反馈电路502还可以包括误差放大器。误差放大器用于对第一差分放大电路和第二差分放大电路合路后的输出信号以及第三差分放大电路和第四差分放大电路合路后的输出信号的误差进行比较,输出第二电压。In addition, the closed loop feedback circuit 502 may also include an error amplifier. The error amplifier is used to compare errors between the combined output signal of the first differential amplifier circuit and the second differential amplifier circuit and the combined output signal of the third differential amplifier circuit and the fourth differential amplifier circuit, and output the second voltage.
通过误差放大器可以对小输入信号、大增益系数的差分放大电路的输出信号和大输入信号、小增益系数的差分放大电路的输出信号进行比较,在两个输出信号近似相同的情况下,用于非线性补偿的晶体管可以对其补偿的晶体管的非线性进行补偿,因而通过上述方案可以得到符合设计要求的栅极偏置电压。The error amplifier can compare the output signal of a differential amplifier circuit with a small input signal and a large gain coefficient with the output signal of a differential amplifier circuit with a large input signal and small gain coefficient. When the two output signals are approximately the same, it is used The non-linear compensation transistor can compensate for the non-linearity of the transistor it compensates, so the gate bias voltage that meets the design requirements can be obtained through the above solution.
进一步地,闭环反馈电路502还可以包括第一跨阻放大器和第二跨阻放大器。其中,第一差分放大电路的正输出端以及第二差分放大电路的正输出端耦合至第一跨阻放大器的负输入端,第一差分放大电路的负输出端以及第二差分放大电路的负输出端耦合至第一跨阻放大器的正输入端;第三差分放大电路的正输出端以及第四差分放大电路的正输出端耦合至第二跨阻放大器的负输入端,第三差分放大电路的负输出端以及第四差分放大电路的负输出端耦合至第二跨阻放大器的正输入端;第二跨阻放大器的增益系数与第一跨阻放大器的增益系数相同。第一跨阻放大器的正输出端和第二跨阻放大器的正输出端耦合至误差放大器的负输入端,第一跨阻放大器的负输出端和第二跨阻放大器的负输出端耦合至误差放大器的正输入端;误差放大器的输出端作为闭环反馈电路502的输出端。Further, the closed-loop feedback circuit 502 may also include a first transimpedance amplifier and a second transimpedance amplifier. Wherein, the positive output terminal of the first differential amplifier circuit and the positive output terminal of the second differential amplifier circuit are coupled to the negative input terminal of the first transimpedance amplifier, the negative output terminal of the first differential amplifier circuit and the negative output terminal of the second differential amplifier circuit The output terminal is coupled to the positive input terminal of the first transimpedance amplifier; the positive output terminal of the third differential amplifier circuit and the positive output terminal of the fourth differential amplifier circuit are coupled to the negative input terminal of the second transimpedance amplifier, and the third differential amplifier circuit The negative output terminal of and the negative output terminal of the fourth differential amplifier circuit are coupled to the positive input terminal of the second transimpedance amplifier; the gain coefficient of the second transimpedance amplifier is the same as that of the first transimpedance amplifier. The positive output terminal of the first transimpedance amplifier and the positive output terminal of the second transimpedance amplifier are coupled to the negative input terminal of the error amplifier, and the negative output terminal of the first transimpedance amplifier and the negative output terminal of the second transimpedance amplifier are coupled to the error The positive input terminal of the amplifier; the output terminal of the error amplifier is used as the output terminal of the closed loop feedback circuit 502.
那么,在一种可能的示例中,闭环反馈电路502可以包括第一差分放大电路、第二差分放大电路、第三差分放大电路、第四差分放大电路、第一跨阻放大器、第二跨阻放大器和误差放大器。Then, in a possible example, the closed-loop feedback circuit 502 may include a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, a fourth differential amplifier circuit, a first transimpedance amplifier, and a second transimpedance amplifier. Amplifier and error amplifier.
假设第一差分放大电路的增益系数为A,第一差分放大电路的正输入端的交流输入电压为a1,第一差分放大电路的负输入端的交流输入电压为a2;第二差分放大电路的增益系数为B,第二差分放大电路的正输入端的交流输入电压为b1,第二差分放大电路的负输入端的交流输入电压为b1。那么,第三差分放大电路的交流输入电压为m*a1和m*a2,增益系数为A*1/m;第四差分放大电路的交流输入电压为m*b1和m*b2,增益系数为B*1/m。 那么,对于与第一差分放大电路和第二差分放大电路耦合的第一跨阻放大器,其正输入端的输入为a1*A+b1*B,其负输入端的输入为为a2*A+b2*B;对于与第三差分放大电路和第四差分放大电路耦合的第二跨阻放大器,其正输入端的输入为m*a1*A*1/m+m*b1*B*1/m=a1*A+b1*B,其负输入端的输入为m*a2*A*1/m+m*b2*B*1/m=a2*A+b2*B。由于第一跨阻放大器和第二跨阻放大器的增益系数相同,因而在第一差分放大电路、第二差分放大电路、第三差分放大电路和第四差分放大电路的线性度较高的情况下,第一跨阻放大器和第二跨阻放大器的输出应相同。Assuming that the gain factor of the first differential amplifier circuit is A, the AC input voltage of the positive input terminal of the first differential amplifier circuit is a1, and the AC input voltage of the negative input terminal of the first differential amplifier circuit is a2; the gain factor of the second differential amplifier circuit Is B, the AC input voltage of the positive input terminal of the second differential amplifier circuit is b1, and the AC input voltage of the negative input terminal of the second differential amplifier circuit is b1. Then, the AC input voltage of the third differential amplifier circuit is m*a1 and m*a2, and the gain coefficient is A*1/m; the AC input voltage of the fourth differential amplifier circuit is m*b1 and m*b2, and the gain coefficient is B*1/m. Then, for the first transimpedance amplifier coupled with the first differential amplifier circuit and the second differential amplifier circuit, the input of its positive input terminal is a1*A+b1*B, and the input of its negative input terminal is a2*A+b2* B; For the second transimpedance amplifier coupled with the third differential amplifier circuit and the fourth differential amplifier circuit, the input of the positive input terminal is m*a1*A*1/m+m*b1*B*1/m=a1 *A+b1*B, the input of its negative input terminal is m*a2*A*1/m+m*b2*B*1/m=a2*A+b2*B. Since the gain coefficients of the first transimpedance amplifier and the second transimpedance amplifier are the same, the linearity of the first differential amplifier circuit, the second differential amplifier circuit, the third differential amplifier circuit, and the fourth differential amplifier circuit is relatively high. , The output of the first transimpedance amplifier and the second transimpedance amplifier should be the same.
在上述实现方式中,第一差分放大电路和第三差分放大电路的直流偏置由第二电流源提供;第二差分放大电路和第四差分放大电路的直流偏置为闭环反馈电路的输出电压。因而第二差分放大电路可以对第一差分放大电路进行非线性补偿,第四差分放大电路可以对第三差分放大电路进行非线性补偿。通过反馈方式找到的第二差分放大电路和第四差分放大电路的直流偏置,可以作为放大装置500中第二晶体管和第四晶体管的直流偏置,使得第二晶体管可以对第一晶体管的输出信号进行非线性补偿,并使得第四晶体管可以对第三晶体管的输出信号进行非线性补偿。In the above implementation, the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is provided by the second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit . Therefore, the second differential amplifier circuit can perform nonlinear compensation on the first differential amplifier circuit, and the fourth differential amplifier circuit can perform nonlinear compensation on the third differential amplifier circuit. The DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit found by feedback can be used as the DC bias of the second transistor and the fourth transistor in the amplifying device 500, so that the second transistor can output to the first transistor The signal performs nonlinear compensation, and the fourth transistor can perform nonlinear compensation on the output signal of the third transistor.
具体实现时,第一差分放大电路可以包括至少一个第五晶体管以及至少一个第六晶体管,第五晶体管的栅极与第一差分放大电路的正输入端耦合,第六晶体管的栅极与第一差分放大电路的负输入端耦合,第五晶体管的数量通过将放大装置500中第一晶体管的数量以第一比例缩小后得到,第六晶体管的数量通过将放大装置500中第三晶体管的数量以第一比例缩小后得到。In specific implementation, the first differential amplifier circuit may include at least one fifth transistor and at least one sixth transistor, the gate of the fifth transistor is coupled to the positive input terminal of the first differential amplifier circuit, and the gate of the sixth transistor is connected to the first The negative input terminal of the differential amplifier circuit is coupled, the number of the fifth transistor is obtained by reducing the number of the first transistor in the amplifying device 500 by a first ratio, and the number of the sixth transistor is obtained by reducing the number of the third transistor in the amplifying device 500 to Obtained after the first scale is reduced.
第二差分放大电路可以包括至少一个第七晶体管以及至少一个第八晶体管,第七晶体管的栅极与第二差分放大电路的正输入端耦合,第八晶体管的栅极与第二差分放大电路的负输入端耦合,第七晶体管的数量通过将放大装置500中第二晶体管的数量以第一比例缩小后得到,第八晶体管的数量通过将放大装置500中第四晶体管的数量以第一比例缩小后得到。The second differential amplifier circuit may include at least one seventh transistor and at least one eighth transistor, the gate of the seventh transistor is coupled to the positive input terminal of the second differential amplifier circuit, and the gate of the eighth transistor is connected to the second differential amplifier circuit. The negative input terminal is coupled, the number of the seventh transistor is obtained by reducing the number of the second transistor in the amplifying device 500 by the first ratio, and the number of the eighth transistor is obtained by reducing the number of the fourth transistor in the amplifying device 500 by the first ratio After getting.
第三差分放大电路可以包括至少一个第九晶体管以及至少一个第十晶体管,第九晶体管的栅极与第三差分放大电路的正输入端耦合,第十晶体管的栅极与第三差分放大电路的负输入端耦合,第九晶体管的数量通过将放大装置500中第一晶体管的数量以第二比例缩小后得到,第十晶体管的数量通过将放大装置500中第三晶体管的数量以第二比例缩小后得到。第一比例为第二比例的m倍。The third differential amplifier circuit may include at least one ninth transistor and at least one tenth transistor. The gate of the ninth transistor is coupled to the positive input terminal of the third differential amplifier circuit, and the gate of the tenth transistor is connected to the third differential amplifier circuit. The negative input is coupled, the number of the ninth transistor is obtained by reducing the number of the first transistor in the amplifying device 500 by the second ratio, and the number of the tenth transistor is obtained by reducing the number of the third transistor in the amplifying device 500 by the second ratio After getting. The first ratio is m times the second ratio.
第四差分放大电路可以包括至少一个第十一晶体管以及至少一个第十二晶体管,第十一晶体管的栅极与第四差分放大电路的正输入端耦合,第十二晶体管的栅极与第四差分放大电路的负输入端耦合,第十一晶体管的数量通过将放大装置500中第二晶体管的数量以第二比例缩小后得到,第十二晶体管的数量通过将放大装置500中第四晶体管的数量以第二比例缩小后得到。The fourth differential amplifier circuit may include at least one eleventh transistor and at least one twelfth transistor, the gate of the eleventh transistor is coupled to the positive input terminal of the fourth differential amplifier circuit, and the gate of the twelfth transistor is coupled to the fourth The negative input terminal of the differential amplifier circuit is coupled, the number of the eleventh transistor is obtained by reducing the number of the second transistor in the amplifying device 500 by the second ratio, and the number of the twelfth transistor is obtained by reducing the number of the fourth transistor in the amplifying device 500 The quantity is obtained after the second scale is reduced.
也就是说,第一差分放大电路和第三差分放大电路均可以通过将放大器501中的第二晶体管和第四晶体管去掉,并将第一晶体管和第三晶体管的数量做一定缩减后形成,第一差分放大电路和第三差分放大电路均可以用于模拟放大器501中用于对输入信号进行放大的晶体管的工作状态,区别仅在于第一差分放大电路和第二差分放大电路的增益系数不同;第二差分放大电路和第四差分放大电路均可以通过将放大器501中的第一晶体管和第三晶体管去掉,并将第二晶体管和第四晶体管的数量做一定缩减后形成,第二差分放大电路和 第四差分放大电路均可以用于模拟放大器501中用于进行非线性补偿的晶体管的工作状态。In other words, both the first differential amplifier circuit and the third differential amplifier circuit can be formed by removing the second transistor and the fourth transistor in the amplifier 501, and reducing the number of the first transistor and the third transistor. Both a differential amplifying circuit and a third differential amplifying circuit can be used to simulate the working state of the transistor used to amplify the input signal in the amplifier 501, the difference is only that the gain coefficients of the first differential amplifying circuit and the second differential amplifying circuit are different; Both the second differential amplifier circuit and the fourth differential amplifier circuit can be formed by removing the first transistor and the third transistor in the amplifier 501 and reducing the number of the second transistor and the fourth transistor to a certain extent. The second differential amplifier circuit Both the fourth differential amplifier circuit and the fourth differential amplifier circuit can be used to simulate the working state of the transistor used for nonlinear compensation in the amplifier 501.
通过将放大器501中的晶体管的数量做一定缩减后形成四个差分放大电路,可以降低闭环反馈电路502的功耗,从而使得放大装置500的功耗主要用于放大输入信号,仅用较小的功耗确定第二晶体管和第四晶体管的偏置,来补偿输出信号的非线性。By reducing the number of transistors in the amplifier 501 to a certain extent to form four differential amplifier circuits, the power consumption of the closed-loop feedback circuit 502 can be reduced, so that the power consumption of the amplifier device 500 is mainly used for amplifying the input signal, and only a smaller The power consumption determines the bias of the second transistor and the fourth transistor to compensate for the non-linearity of the output signal.
其中,第五晶体管与第一晶体管可以具有相同规格,第六晶体管与第三晶体管可以具有相同规格;第七晶体管与第二晶体管可以具有相同规格,第八晶体管与第四晶体管可以具有相同规格;第九晶体管与第一晶体管可以具有相同规格,第十晶体管与第三晶体管可以具有相同规格;第十一晶体管与第二晶体管可以具有相同规格,第十二晶体管与第四晶体管可以具有相同规格。The fifth transistor and the first transistor may have the same specifications, the sixth transistor and the third transistor may have the same specifications; the seventh transistor and the second transistor may have the same specifications, and the eighth transistor and the fourth transistor may have the same specifications; The ninth transistor and the first transistor may have the same specifications, the tenth transistor and the third transistor may have the same specifications; the eleventh transistor and the second transistor may have the same specifications, and the twelfth transistor and the fourth transistor may have the same specifications.
此外,闭环反馈电路502还可以包括:第二电流源,用于为第一差分放大电路和第三差分放大电路提供直流偏置;缓冲器,用于为第二差分放大电路和第四差分放大电路提供直流偏置,缓冲器的输入端与闭环反馈电路502的输出端耦合;依次串联的第一电阻、第二电阻、第三电阻和第四电阻;依次串联的第五电阻、第六电阻、第七电阻和第八电阻。In addition, the closed-loop feedback circuit 502 may also include: a second current source for providing a DC bias for the first differential amplifier circuit and the third differential amplifier circuit; a buffer for the second differential amplifier circuit and the fourth differential amplifier circuit The circuit provides a DC bias, the input of the buffer is coupled with the output of the closed loop feedback circuit 502; the first resistor, the second resistor, the third resistor, and the fourth resistor are connected in series; the fifth resistor and the sixth resistor are connected in series , The seventh resistor and the eighth resistor.
其中,第二电流源可以由第一电流源镜像偏置后得到。缓冲器可以保存闭环反馈电路502的输出电压并输出,使得第二差分放大电路和第四差分放大电路的直流偏置为一个稳定的电压值,不会随电流变化而发生波动。Wherein, the second current source can be obtained by mirror biasing of the first current source. The buffer can store and output the output voltage of the closed-loop feedback circuit 502, so that the DC bias of the second differential amplifying circuit and the fourth differential amplifying circuit is a stable voltage value, and will not fluctuate with current changes.
具体地,串联的第一电阻~第四电阻的具体连接方式可以是:第一电阻耦合至第一电源,第四电阻耦合接地,第二电阻和第三电阻与第二电流源耦合;第一电阻与第二电阻的阻值之比为m-1,第四电阻与第三电阻的阻值之比为m-1,第二电阻和第三电阻的阻值相同;其中,第一电阻与第一电源的连接处与第三差分放大电路的正输入端耦合,第四电阻的耦合接地端与第三差分放大电路的负输入端耦合;第一电阻与第二电阻的连接处与第一差分放大电路的正输入端耦合,第三电阻和第四电阻的连接处与第一差分放大电路的负输入端耦合。其中,第一电源可以是交流电流源。Specifically, the specific connection manner of the first resistor to the fourth resistor in series may be: the first resistor is coupled to the first power source, the fourth resistor is coupled to the ground, and the second resistor and the third resistor are coupled to the second current source; The resistance ratio of the resistance to the second resistance is m-1, the resistance ratio of the fourth resistance to the third resistance is m-1, and the resistances of the second resistance and the third resistance are the same; where the first resistance is equal to The connection of the first power supply is coupled with the positive input terminal of the third differential amplifier circuit, and the coupling ground terminal of the fourth resistor is coupled with the negative input terminal of the third differential amplifier circuit; the connection between the first resistor and the second resistor is coupled with the first The positive input terminal of the differential amplifier circuit is coupled, and the connection of the third resistor and the fourth resistor is coupled with the negative input terminal of the first differential amplifier circuit. Wherein, the first power source may be an alternating current source.
具体地,串联的第五电阻~第八电阻的具体连接方式可以是:第五电阻耦合至第二电源,第八电阻耦合接地,第六电阻和第七电阻与缓冲器的输出端耦合;第五电阻与第六电阻的阻值之比为m-1,第八电阻与第七电阻的阻值之比为m-1,第六电阻和第七电阻的阻值相同;其中,第五电阻与第二电源的连接处与第四差分放大电路的正输入端耦合,第八电阻的耦合接地端与第四差分放大电路的负输入端耦合;第五电阻与第六电阻的连接处与第二差分放大电路的正输入端耦合,第七电阻和第八电阻的连接处与第二差分放大电路的负输入端耦合。其中,第二电源可以是交流电流源。Specifically, the specific connection manner of the fifth resistor to the eighth resistor in series may be: the fifth resistor is coupled to the second power source, the eighth resistor is coupled to the ground, and the sixth resistor and the seventh resistor are coupled to the output terminal of the buffer; The resistance ratio of the fifth resistor to the sixth resistor is m-1, the resistance ratio of the eighth resistor to the seventh resistor is m-1, and the resistance values of the sixth resistor and the seventh resistor are the same; among them, the fifth resistor The connection with the second power supply is coupled with the positive input end of the fourth differential amplifier circuit, the coupling ground end of the eighth resistor is coupled with the negative input end of the fourth differential amplifier circuit; the connection between the fifth resistor and the sixth resistor is coupled with the first The positive input ends of the two differential amplifier circuits are coupled, and the junction of the seventh resistor and the eighth resistor is coupled with the negative input end of the second differential amplifier circuit. Wherein, the second power source may be an alternating current source.
采用上述实现方案,可以通过第二电流源、缓冲器和多个电阻为四个差分放大电路提供交流输入和直流偏置。By adopting the above implementation scheme, the AC input and DC bias can be provided for the four differential amplifier circuits through the second current source, the buffer and the multiple resistors.
示例性地,依次串联的第一电阻、第二电阻、第三电阻和第四电阻及其中各个节点的输出可以如图6所示。由图6可以看出,第一差分放大电路和第三差分放大电路的直流偏置均由第二电流源提供。由于第一电阻与第二电阻的阻值之比为m-1、第四电阻与第三电阻的阻值之比为m-1、第二电阻和第三电阻的阻值相同,那么,第三差分放大电路的正输入端的输入为第一差分放大电路的正输入端的输入的m倍,第三差分放大电路的负输入端的输入为第一差分放大电路的负输入端的输入的m倍。因而通过图6所示依次串联的四个电阻,可以实现“第三差分放大电路的交流输入电压为第一差分放大电路的交流输入电压的m倍、第一差分放大电路和第三差分放大电路的直流偏置由第二电流源提供”。Exemplarily, the first resistor, the second resistor, the third resistor, and the fourth resistor connected in series in sequence and the output of each node therein may be as shown in FIG. 6. It can be seen from FIG. 6 that the DC bias of the first differential amplifier circuit and the third differential amplifier circuit are both provided by the second current source. Since the resistance ratio of the first resistance to the second resistance is m-1, the resistance ratio of the fourth resistance to the third resistance is m-1, and the resistances of the second resistance and the third resistance are the same, then, The input of the positive input terminal of the three differential amplifier circuit is m times the input of the positive input terminal of the first differential amplifier circuit, and the input of the negative input terminal of the third differential amplifier circuit is m times the input of the negative input terminal of the first differential amplifier circuit. Therefore, through the four resistors in series as shown in Figure 6, it is possible to realize that "the AC input voltage of the third differential amplifier circuit is m times the AC input voltage of the first differential amplifier circuit, the first differential amplifier circuit and the third differential amplifier circuit The DC bias is provided by the second current source".
示例性地,依次串联的第五电阻、第六电阻、第七电阻和第八电阻及其中各个节点的输出可以如图7所示。在图7中,缓冲器的输入端与闭环反馈电路的输出端耦合,因而第二差分放大电路和第四差分放大电路的直流偏置为闭环反馈电路502的输出电压。由于第五电阻与第六电阻的阻值之比为m-1、第八电阻与第七电阻的阻值之比为m-1、第六电阻和第七电阻的阻值相同,那么,第四差分放大电路的正输入端的输入为第二差分放大电路的正输入端的输入的m倍,第四差分放大电路的负输入端的输入为第二差分放大电路的负输入端的输入的m倍。因而通过图7所示依次串联的四个电阻,可以实现“第四差分放大电路的交流输入电压为第二差分放大电路的交流输入电压的m倍、第二差分放大电路和第四差分放大电路的直流偏置为闭环反馈电路的输出电压”。Exemplarily, the fifth resistor, the sixth resistor, the seventh resistor, and the eighth resistor connected in series in sequence and the output of each node therein may be as shown in FIG. 7. In FIG. 7, the input terminal of the buffer is coupled with the output terminal of the closed loop feedback circuit, so the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the output voltage of the closed loop feedback circuit 502. Since the resistance ratio of the fifth resistor to the sixth resistor is m-1, the resistance ratio of the eighth resistor to the seventh resistor is m-1, and the resistance values of the sixth and seventh resistors are the same, then, The input of the positive input terminal of the four differential amplifier circuit is m times the input of the positive input terminal of the second differential amplifier circuit, and the input of the negative input terminal of the fourth differential amplifier circuit is m times the input of the negative input terminal of the second differential amplifier circuit. Therefore, through the four resistors in series as shown in Figure 7, it is possible to realize that "the AC input voltage of the fourth differential amplifier circuit is m times the AC input voltage of the second differential amplifier circuit, the second differential amplifier circuit and the fourth differential amplifier circuit The DC bias is the output voltage of the closed-loop feedback circuit".
结合以上对闭环反馈电路502的介绍,闭环反馈电路502的一种可能的结构示意图可以如图8所示。在图8中,闭环反馈电路502包括第一差分放大电路、第二差分放大电路、第三差分放大电路、第四差分放大电路、第一跨阻放大器、第二跨阻放大器、误差放大器、第二电流源、缓冲器、以及串联电阻(串联的第一电阻、第二电阻、第三电阻、第四电阻,以及串联的第五电阻、第六电阻、第七电阻、第八电阻)。采用图8所示的闭环反馈电路502,可以为图5所示的放大装置500中的第二晶体管和第四晶体管提供偏置,使得第二晶体管对第一晶体管进行非线性补偿、第四晶体管对第三晶体管进行非线性补偿。In combination with the above introduction to the closed-loop feedback circuit 502, a possible structural schematic diagram of the closed-loop feedback circuit 502 may be shown in FIG. 8. In FIG. 8, the closed loop feedback circuit 502 includes a first differential amplifier circuit, a second differential amplifier circuit, a third differential amplifier circuit, a fourth differential amplifier circuit, a first transimpedance amplifier, a second transimpedance amplifier, an error amplifier, and a second Two current sources, buffers, and series resistors (first resistor, second resistor, third resistor, and fourth resistor connected in series, and fifth resistor, sixth resistor, seventh resistor, and eighth resistor connected in series). The closed-loop feedback circuit 502 shown in FIG. 8 can be used to provide a bias for the second transistor and the fourth transistor in the amplifying device 500 shown in FIG. 5, so that the second transistor performs nonlinear compensation on the first transistor and the fourth transistor Perform nonlinear compensation on the third transistor.
示例性地,针对图4所示的放大器,可以采用图9所示的闭环反馈电路为该放大器提供Vgs_Aux(相当于第二晶体管和第四晶体管的偏置电压)。即图9所示的闭环反馈电路与图4中的Vgs_Aux端连接。图4所示的放大器和图9所示的闭环反馈电路可以组成一个放大装置,该放大装置可以视为图5所示的放大装置500的一个具体示例。Exemplarily, for the amplifier shown in FIG. 4, the closed loop feedback circuit shown in FIG. 9 can be used to provide Vgs_Aux (equivalent to the bias voltage of the second transistor and the fourth transistor) for the amplifier. That is, the closed loop feedback circuit shown in FIG. 9 is connected to the Vgs_Aux terminal in FIG. 4. The amplifier shown in FIG. 4 and the closed loop feedback circuit shown in FIG. 9 can form an amplifying device, which can be regarded as a specific example of the amplifying device 500 shown in FIG. 5.
图9中,上半部分(用4x标示)中的Main Gm相当于将图4中的“辅助补偿管”去掉、“主管”按照4/n比例缩小数量后形成,上半部分中的Aux Gm相当于将图4中的“主管”去掉、“辅助补偿管”按照4/n比例缩小数量后形成;下半部分(用1x标示)中的Main Gm相当于将图4中的“辅助补偿管”去掉、“主管”按照1/n比例缩小数量后形成,下半部分中的Aux Gm相当于将图4中的“主管”去掉、“辅助补偿管”按照1/n比例缩小数量后形成。示例性地,n可以为100。也就是说,图9中的Gm单元可以通过将图4中的Gm单元中的“主管”和“辅助补偿管”分别复制尺寸为1/n和4/n的两份得到。其中主管(Main Gm)的共模由常规镜像偏置,辅助补偿管(Aux Gm)的共模由闭环反馈电路的电压(即Vgs_aux)进行偏置。In Figure 9, the Main Gm in the upper part (marked with 4x) is equivalent to removing the "auxiliary compensation tube" in Figure 4, and the "main pipe" is formed by reducing the number according to the ratio of 4/n, and the Aux Gm in the upper half It is equivalent to removing the "main pipe" in Figure 4 and the "auxiliary compensation pipe" is formed by reducing the number according to the ratio of 4/n; Main Gm in the lower half (marked by 1x) is equivalent to removing the "auxiliary compensation pipe" in Figure 4 "Remove," the "main pipe" is formed after the number is reduced according to the ratio of 1/n. The Aux Gm in the lower half is equivalent to the removal of the "main pipe" in Figure 4 and the "auxiliary compensation pipe" is formed after the number is reduced according to the ratio of 1/n. Illustratively, n may be 100. In other words, the Gm unit in FIG. 9 can be obtained by duplicating the "main pipe" and the "auxiliary compensation pipe" in the Gm unit in FIG. 4, respectively, with sizes 1/n and 4/n. The common mode of the main pipe (Main Gm) is biased by the conventional mirror image, and the common mode of the auxiliary compensation pipe (Aux Gm) is biased by the voltage of the closed loop feedback circuit (ie, Vgs_aux).
通过图9中的缓冲器和电流源,可以对上半部分的Gm单元和下半部分的Gm单元施加大小不同的差分信号。例如,上半部分的Gm单元和下半部分的Gm单元的增益系数之比为4:1,那么,上半部分的Gm单元和下半部分的Gm单元的输入信号之比可以为1:4。然后,通过成相反比例的跨阻放大器,将两路差分输出电流转化为电压。两个差分电压经误差放大器(error amplifier,EA)放大,用于控制图4中“辅助补偿管”的状态,形成闭环负反馈。Through the buffer and current source in FIG. 9, differential signals of different sizes can be applied to the Gm cell in the upper half and the Gm cell in the lower half. For example, the ratio of the gain coefficient of the upper half of the Gm unit to the lower half of the Gm unit is 4:1, then the ratio of the input signal of the upper half of the Gm unit to the lower half of the Gm unit can be 1:4 . Then, the two differential output currents are converted into voltages through transimpedance amplifiers of opposite proportions. The two differential voltages are amplified by an error amplifier (EA) and used to control the state of the "auxiliary compensation tube" in Figure 4 to form a closed loop negative feedback.
其中,闭环负反馈的作用是使小信号通路(图9中上半部分,输入信号为1x,称为小信号通路)和大信号通路(图9中下半部分,输入信号为4x,称为大信号通路)的输出相同,上下部分的输出相等即实现了所谓“线性”。这时闭环反馈电路找到的输出“Vgs_Aux”电压,恰好使“辅助补偿管”能补平“主管”的非线性波动,实现了“自适应”闭环调节。Among them, the function of closed-loop negative feedback is to make the small signal path (in the upper part of Figure 9, the input signal is 1x, called the small signal path) and the large signal path (in the lower half of Figure 9, the input signal is 4x, called the small signal path) The output of the large signal path is the same, and the output of the upper and lower parts is equal to achieve the so-called "linear". At this time, the output "Vgs_Aux" voltage found by the closed-loop feedback circuit just enables the "auxiliary compensation tube" to compensate for the non-linear fluctuations of the "main pipe" and realize the "adaptive" closed-loop adjustment.
综上,采用本申请实施例提供的放大装置500,由于第一晶体管301a和第三晶体管302a 的沟道处于强反型状态,因而可以分别通过第一晶体管301a和第三晶体管302a实现对第一信号和第二信号的放大;由于第二晶体管301b和第四晶体管302b的沟道处于弱反型状态,因而可以分别通过第二晶体管301b和第四晶体管302b对第一晶体管301a的输出信号和第三晶体管302a的输出信号进行非线性补偿,提高放大器501的线性度。In summary, with the amplifying device 500 provided by the embodiment of the present application, since the channels of the first transistor 301a and the third transistor 302a are in a strong inversion state, the first transistor 301a and the third transistor 302a can be used to realize the Amplification of the signal and the second signal; since the channels of the second transistor 301b and the fourth transistor 302b are in a weak inversion state, the output signal and the second transistor of the first transistor 301a can be transmitted through the second transistor 301b and the fourth transistor 302b, respectively The output signal of the three-transistor 302a performs nonlinear compensation to improve the linearity of the amplifier 501.
由于第一晶体管和第三晶体管由第一电流源提供偏置,这种偏置方式可以视为固定偏置,其偏置电压波动较小,因而第一晶体管和第三晶体管的增益波动和功耗波动也较小。第二晶体管和第四晶体管通过闭环反馈电路502提供偏置时,虽然通过闭环反馈电路502提供偏置会导致增益波动和功耗波动,但是第二晶体管和第四晶体管的沟道处于弱反型状态,其增益较小、产生的功耗也较小,因而即使出现增益波动和功耗波动,其波动的数值对第一增益电路和第二增益电路也难以产生较大影响。因此,放大装置500中,第一增益电路和第二增益电路的增益波动和功耗波动较小。Since the first transistor and the third transistor are biased by the first current source, this bias mode can be regarded as a fixed bias, and its bias voltage fluctuation is small, so the gain fluctuation and power of the first transistor and the third transistor The consumption fluctuation is also small. When the second transistor and the fourth transistor are biased through the closed-loop feedback circuit 502, although the bias provided by the closed-loop feedback circuit 502 will cause fluctuations in gain and power consumption, the channels of the second and fourth transistors are in weak inversion. In the state, the gain is small and the power consumption is small. Therefore, even if gain fluctuations and power consumption fluctuations occur, the value of the fluctuations will hardly have a large impact on the first gain circuit and the second gain circuit. Therefore, in the amplifying device 500, the gain fluctuation and power consumption fluctuation of the first gain circuit and the second gain circuit are small.
综上所述,本申请实施例提供的放大装置500中,增益和功耗主要由第一晶体管和第三晶体管决定;第二晶体管和第四晶体管负责抵消非线性,只贡献很低比例的功耗和增益。因而在放大装置500中,可以通过第二晶体管和第四晶体管提高放大器501的线性度的同时,减小放大器501的增益波动和功耗波动。In summary, in the amplifying device 500 provided by the embodiment of the present application, the gain and power consumption are mainly determined by the first transistor and the third transistor; the second transistor and the fourth transistor are responsible for canceling the nonlinearity, and only contribute a very low proportion of the power. Consumption and gain. Therefore, in the amplifying device 500, the linearity of the amplifier 501 can be improved by the second transistor and the fourth transistor, and the gain fluctuation and power consumption fluctuation of the amplifier 501 can be reduced.
示例性地,采用本申请实施例提供的放大装置500,放大器总增益、主管(即第一晶体管和第三晶体管)增益和辅助补偿管(即第二晶体管和第四晶体管)增益随输入信号的变化可以如图10所示。从图10可以看出,放大器总增益的线性度较好。当输入信号发生变化时,辅助补偿管可以对主管进行非线性补偿,使得放大器总增益随输入信号稳定。Exemplarily, using the amplifying device 500 provided by the embodiment of the present application, the total gain of the amplifier, the gain of the main pipe (ie the first transistor and the third transistor) and the auxiliary compensation tube (ie the second transistor and the fourth transistor) gain vary with the input signal The changes can be shown in Figure 10. It can be seen from Figure 10 that the overall gain of the amplifier has better linearity. When the input signal changes, the auxiliary compensation tube can compensate the main pipe nonlinearly, so that the total gain of the amplifier is stable with the input signal.
特别地,若辅助补偿管的增益由于闭环反馈电路中各器件的工艺、温度、模型精度等发生波动时(例如波动50%),由于主管的增益远大于辅助补偿管的增益,因而辅助补偿管的增益波动不会对放大器总增益产生较大影响,因而与现有技术提供的方案相比,采用本申请实施例提供的放大装置500,可以减小放大器的增益和功耗波动。In particular, if the gain of the auxiliary compensation tube fluctuates due to the process, temperature, and model accuracy of each device in the closed-loop feedback circuit (for example, 50% fluctuation), since the gain of the main tube is much greater than the gain of the auxiliary compensation tube, the auxiliary compensation tube The gain fluctuation will not have a great impact on the overall gain of the amplifier. Therefore, compared with the solution provided in the prior art, the amplifying device 500 provided by the embodiment of the present application can reduce the gain and power consumption fluctuation of the amplifier.
此外,在不同温度和工艺下,采用辅助补偿管进行补偿前以及采用辅助补偿管进行补偿后,放大器总增益和输入3阶交截点(input referred 3rd-order interception point,IIP3)变化可以分别如表1和表2所示。其中,补偿前是指放大器中不包含辅助补偿管,且主管采用电流源偏置的情形;补偿后是指采用本申请实施例提供的放大装置的情形。In addition, under different temperatures and processes, before the auxiliary compensation tube is used for compensation and after the auxiliary compensation tube is used for compensation, the total gain of the amplifier and the input referred 3rd-order intercept point (IIP3) can be changed as follows: Shown in Table 1 and Table 2. Among them, before compensation refers to a situation where the amplifier does not include an auxiliary compensation tube and the main pipe is biased by a current source; after compensation refers to a situation where the amplifying device provided in the embodiment of the present application is used.
表1Table 1
Gm(增益)Gm (gain) 不补偿(Gm)No compensation (Gm) 补偿后(Gm)After compensation (Gm)
tt 55tt 55 10.610.6 11.111.1
ss-40ss-40 11.611.6 11.911.9
ss 125ss 125 9.49.4 1010
ff-40ff-40 12.412.4 12.712.7
ff 125ff 125 1010 10.610.6
表2Table 2
IIP3IIP3 不补偿(dBm)No compensation (dBm) 补偿后(dBm)After compensation (dBm)
tt 55tt 55 10.210.2 16.716.7
ss-40ss-40 10.310.3 17.317.3
ss 125ss 125 11.311.3 17.917.9
ff-40ff-40 10.110.1 16.216.2
ff 125ff 125 11.211.2 16.616.6
在表1和表2中,“tt”、“ss”、“ff”表示不同工艺角,其后的数字代表温度。从表1中可以看出,在不同的工艺和温度下,补偿后的放大器总增益的波动得以减小(补偿前增益波动为9.4~12.4,补偿后增益波动为10~12.7);从表2中可以看出,在不同的工艺和温度下,对放大器进行补偿后,IIP3均明显提高,即放大器的线性度得到了提升。In Table 1 and Table 2, "tt", "ss", and "ff" represent different process angles, and the following numbers represent temperature. It can be seen from Table 1 that under different processes and temperatures, the fluctuation of the total gain of the compensated amplifier can be reduced (the gain fluctuation before compensation is 9.4~12.4, and the gain fluctuation after compensation is 10~12.7); from Table 2 It can be seen that, after the amplifier is compensated under different processes and temperatures, IIP3 is significantly improved, that is, the linearity of the amplifier is improved.
此外,需要说明的是,本申请实施例提供的放大器300和放大装置500可以应用于多种终端设备中,例如,可以应用于手机(mobile phone)、平板电脑(pad)、虚拟现实(virtual reality,VR)终端、增强现实(augmented reality,AR)终端等终端设备中。In addition, it should be noted that the amplifier 300 and the amplifier 500 provided in the embodiments of the present application can be applied to a variety of terminal devices, for example, can be applied to mobile phones, tablets, virtual reality (virtual reality). , VR) terminal, augmented reality (augmented reality, AR) terminal and other terminal equipment.
显然,本领域的技术人员可以对本申请实施例进行各种改动和变型而不脱离本申请实施例的范围。这样,倘若本申请实施例的这些修改和变型属于本申请权利要求及其等同技术的范围之内,则本申请也意图包含这些改动和变型在内。Obviously, those skilled in the art can make various changes and modifications to the embodiments of the present application without departing from the scope of the embodiments of the present application. In this way, if these modifications and variations of the embodiments of this application fall within the scope of the claims of this application and their equivalent technologies, this application is also intended to include these modifications and variations.

Claims (13)

  1. 一种放大器,其特征在于,包括:An amplifier, characterized in that it comprises:
    至少一个第一增益电路,用于放大第一信号;每个第一增益电路包括第一晶体管和第二晶体管;所述第一晶体管的沟道处于强反型状态,所述第二晶体管的沟道处于弱反型状态;At least one first gain circuit is used to amplify the first signal; each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state, and the channel of the second transistor Tao is in a weakly inverse state;
    至少一个第二增益电路,用于放大第二信号;每个第二增益电路包括第三晶体管和第四晶体管;所述第三晶体管的沟道处于强反型状态,所述第四晶体管的沟道处于弱反型状态;所述第一信号和所述第二信号构成差分信号;At least one second gain circuit is used to amplify the second signal; each second gain circuit includes a third transistor and a fourth transistor; the channel of the third transistor is in a strong inversion state, and the channel of the fourth transistor The track is in a weak inversion state; the first signal and the second signal constitute a differential signal;
    其中,所述第一晶体管和所述第三晶体管的栅极偏置电压为第一电压,所述第二晶体管和所述第四晶体管的栅极偏置电压为第二电压。Wherein, the gate bias voltages of the first transistor and the third transistor are the first voltage, and the gate bias voltages of the second transistor and the fourth transistor are the second voltage.
  2. 如权利要求1所述的放大器,其特征在于,所述第一晶体管用于放大第一信号,所述第二晶体管用于对所述第一晶体管的输出信号进行非线性补偿;所述第三晶体管用于放大第二信号,所述第四晶体管用于对所述第三晶体管的输出信号进行非线性补偿。The amplifier according to claim 1, wherein the first transistor is used to amplify a first signal, and the second transistor is used to perform nonlinear compensation on the output signal of the first transistor; The transistor is used to amplify the second signal, and the fourth transistor is used to perform nonlinear compensation on the output signal of the third transistor.
  3. 如权利要求1或2所述的放大器,其特征在于,所述第一晶体管的栅极用于接收所述第一信号,所述第一晶体管的源极耦合接地,所述第一晶体管的漏极与所述放大器的负载耦合;The amplifier of claim 1 or 2, wherein the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, and the drain of the first transistor is Pole is coupled to the load of the amplifier;
    所述第二晶体管的源极耦合接地,所述第二晶体管的漏极与所述放大器的负载耦合;The source of the second transistor is coupled to ground, and the drain of the second transistor is coupled to the load of the amplifier;
    所述第三晶体管的栅极用于接收所述第二信号,所述第三晶体管的源极耦合接地,所述第三晶体管的漏极与所述放大器的负载耦合;The gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifier;
    所述第四晶体管的源极耦合接地,所述第四晶体管的漏极与所述放大器的负载耦合。The source of the fourth transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifier.
  4. 一种放大装置,其特征在于,包括放大器和闭环反馈电路;所述放大器包括用于放大第一信号的至少一个第一增益电路和用于放大第二信号的至少一个第二增益电路;An amplifying device, characterized in that it comprises an amplifier and a closed-loop feedback circuit; the amplifier comprises at least one first gain circuit for amplifying a first signal and at least one second gain circuit for amplifying a second signal;
    其中,每个第一增益电路包括第一晶体管和第二晶体管;所述第一晶体管的沟道处于强反型状态,所述第二晶体管的沟道处于弱反型状态;至少一个第二增益电路,每个第二增益电路包括第三晶体管和第四晶体管;所述第三晶体管的沟道处于强反型状态,所述第四晶体管的沟道处于弱反型状态;所述第一信号和所述第二信号构成差分信号;其中,所述第一晶体管和所述第三晶体管的栅极偏置电压为通过第一电流源产生的第一电压,所述第二晶体管和所述第四晶体管的栅极偏置电压为第二电压;Wherein, each first gain circuit includes a first transistor and a second transistor; the channel of the first transistor is in a strong inversion state, and the channel of the second transistor is in a weak inversion state; at least one second gain Each second gain circuit includes a third transistor and a fourth transistor; the channel of the third transistor is in a strong inversion state, and the channel of the fourth transistor is in a weak inversion state; the first signal And the second signal constitute a differential signal; wherein the gate bias voltage of the first transistor and the third transistor is a first voltage generated by a first current source, and the second transistor and the first transistor The gate bias voltage of the four transistors is the second voltage;
    所述闭环反馈电路,用于产生所述第二电压。The closed loop feedback circuit is used to generate the second voltage.
  5. 如权利要求4所述的放大装置,其特征在于,所述第一晶体管用于放大第一信号,所述第二晶体管用于对所述第一晶体管的输出信号进行非线性补偿;所述第三晶体管用于放大第二信号,所述第四晶体管用于对所述第三晶体管的输出信号进行非线性补偿。5. The amplifying device according to claim 4, wherein the first transistor is used to amplify a first signal, and the second transistor is used to perform nonlinear compensation on the output signal of the first transistor; The three transistors are used to amplify the second signal, and the fourth transistor is used to perform nonlinear compensation on the output signal of the third transistor.
  6. 如权利要求4或5所述的放大装置,其特征在于,所述闭环反馈电路包括第一差分放大电路、第二差分放大电路、第三差分放大电路和第四差分放大电路;The amplifying device according to claim 4 or 5, wherein the closed-loop feedback circuit comprises a first differential amplifying circuit, a second differential amplifying circuit, a third differential amplifying circuit, and a fourth differential amplifying circuit;
    其中,所述第一差分放大电路和所述第三差分放大电路的直流偏置由第二电流源产生;所述第二差分放大电路和所述第四差分放大电路的直流偏置为所述闭环反馈电路的输出电压。Wherein, the DC bias of the first differential amplifier circuit and the third differential amplifier circuit is generated by a second current source; the DC bias of the second differential amplifier circuit and the fourth differential amplifier circuit is the The output voltage of the closed loop feedback circuit.
  7. 如权利要求6所述的放大装置,其特征在于,所述第三差分放大电路的增益系数为所述第一差分放大电路的增益系数的1/m,所述第三差分放大电路的交流输入电压为所述第一差分放大电路的交流输入电压的m倍,m>1;The amplifying device according to claim 6, wherein the gain coefficient of the third differential amplifying circuit is 1/m of the gain coefficient of the first differential amplifying circuit, and the AC input of the third differential amplifying circuit The voltage is m times the AC input voltage of the first differential amplifier circuit, m>1;
    所述第四差分放大电路的增益系数为所述第二差分放大电路的增益系数的1/m,所述第四差分放大电路的交流输入电压为所述第二差分放大电路的交流输入电压的m倍。The gain coefficient of the fourth differential amplifying circuit is 1/m of the gain coefficient of the second differential amplifying circuit, and the AC input voltage of the fourth differential amplifying circuit is a ratio of the AC input voltage of the second differential amplifying circuit m times.
  8. 如权利要求6或7所述的放大装置,其特征在于,所述闭环反馈电路还包括:8. The amplifying device according to claim 6 or 7, wherein the closed loop feedback circuit further comprises:
    误差放大器,用于对所述第一差分放大电路和所述第二差分放大电路合路后的输出信号以及所述第三差分放大电路和所述第四差分放大电路合路后的输出信号的误差进行比较,输出所述第二电压。Error amplifier, used to combine the output signal of the first differential amplifier circuit and the second differential amplifier circuit and the output signal of the third differential amplifier circuit and the fourth differential amplifier circuit. The errors are compared, and the second voltage is output.
  9. 如权利要求8所述的放大装置,其特征在于,所述闭环反馈电路还包括:8. The amplifying device of claim 8, wherein the closed-loop feedback circuit further comprises:
    第一跨阻放大器,所述第一差分放大电路的正输出端以及所述第二差分放大电路的正输出端耦合至所述第一跨阻放大器的负输入端,所述第一差分放大电路的负输出端以及所述第二差分放大电路的负输出端耦合至所述第一跨阻放大器的正输入端;A first transimpedance amplifier, the positive output terminal of the first differential amplifier circuit and the positive output terminal of the second differential amplifier circuit are coupled to the negative input terminal of the first transimpedance amplifier, the first differential amplifier circuit The negative output terminal of the second differential amplifier circuit and the negative output terminal of the second differential amplifier circuit are coupled to the positive input terminal of the first transimpedance amplifier;
    第二跨阻放大器,所述第三差分放大电路的正输出端以及所述第四差分放大电路的正输出端耦合至所述第二跨阻放大器的负输入端,所述第三差分放大电路的负输出端以及所述第四差分放大电路的负输出端耦合至所述第二跨阻放大器的正输入端;所述第二跨阻放大器的放大倍数与所述第一跨阻放大器的放大倍数相同;The second transimpedance amplifier, the positive output terminal of the third differential amplifier circuit and the positive output terminal of the fourth differential amplifier circuit are coupled to the negative input terminal of the second transimpedance amplifier, and the third differential amplifier circuit The negative output terminal of the fourth differential amplifier circuit and the negative output terminal of the fourth differential amplifier circuit are coupled to the positive input terminal of the second transimpedance amplifier; the amplification factor of the second transimpedance amplifier and the amplification of the first transimpedance amplifier Same multiples;
    其中,所述第一跨阻放大器的正输出端和所述第二跨阻放大器的正输出端耦合至所述误差放大器的负输入端,所述第一跨阻放大器的负输出端和所述第二跨阻放大器的负输出端耦合至所述误差放大器的正输入端。Wherein, the positive output terminal of the first transimpedance amplifier and the positive output terminal of the second transimpedance amplifier are coupled to the negative input terminal of the error amplifier, and the negative output terminal of the first transimpedance amplifier and the The negative output terminal of the second transimpedance amplifier is coupled to the positive input terminal of the error amplifier.
  10. 如权利要求7~9任一项所述的放大装置,其特征在于,所述第一差分放大电路包括至少一个第五晶体管以及至少一个第六晶体管,所述第五晶体管的栅极与所述第一差分放大电路的正输入端耦合,所述第六晶体管的栅极与所述第一差分放大电路的负输入端耦合,所述第五晶体管的数量通过将所述放大装置中第一晶体管的数量以第一比例缩小后得到,所述第六晶体管的数量通过将所述放大装置中第三晶体管的数量以所述第一比例缩小后得到;The amplifying device according to any one of claims 7-9, wherein the first differential amplifying circuit includes at least one fifth transistor and at least one sixth transistor, and the gate of the fifth transistor is connected to the The positive input terminal of the first differential amplifier circuit is coupled, the gate of the sixth transistor is coupled with the negative input terminal of the first differential amplifier circuit, and the number of the fifth transistor is determined by the first transistor in the amplifier device. The number of the sixth transistors is reduced by a first ratio, and the number of the sixth transistors is obtained by reducing the number of third transistors in the amplifying device by the first ratio;
    所述第二差分放大电路包括至少一个第七晶体管以及至少一个第八晶体管,所述第七晶体管的栅极与所述第二差分放大电路的正输入端耦合,所述第八晶体管的栅极与所述第二差分放大电路的负输入端耦合,所述第七晶体管的数量通过将所述放大装置中第二晶体管的数量以所述第一比例缩小后得到,所述第八晶体管的数量通过将所述放大装置中第四晶体管的数量以所述第一比例缩小后得到;The second differential amplifier circuit includes at least one seventh transistor and at least one eighth transistor, the gate of the seventh transistor is coupled to the positive input terminal of the second differential amplifier circuit, and the gate of the eighth transistor Coupled with the negative input terminal of the second differential amplifier circuit, the number of the seventh transistor is obtained by reducing the number of the second transistor in the amplifying device by the first ratio, the number of the eighth transistor Obtained by reducing the number of fourth transistors in the amplifying device by the first ratio;
    所述第三差分放大电路包括至少一个第九晶体管以及至少一个第十晶体管,所述第九晶体管的栅极与所述第三差分放大电路的正输入端耦合,所述第十晶体管的栅极与所述第 三差分放大电路的负输入端耦合,所述第九晶体管的数量通过将所述放大装置中第一晶体管的数量以第二比例缩小后得到,所述第十晶体管的数量通过将所述放大装置中第三晶体管的数量以所述第二比例缩小后得到;所述第一比例为所述第二比例的m倍;The third differential amplifier circuit includes at least one ninth transistor and at least one tenth transistor, the gate of the ninth transistor is coupled to the positive input terminal of the third differential amplifier circuit, and the gate of the tenth transistor Is coupled to the negative input terminal of the third differential amplifier circuit, the number of the ninth transistor is obtained by reducing the number of the first transistor in the amplifying device by a second ratio, and the number of the tenth transistor is obtained by reducing The number of third transistors in the amplifying device is obtained after being reduced by the second ratio; the first ratio is m times the second ratio;
    所述第四差分放大电路包括至少一个第十一晶体管以及至少一个第十二晶体管,所述第十一晶体管的栅极与所述第四差分放大电路的正输入端耦合,所述第十二晶体管的栅极与所述第四差分放大电路的负输入端耦合,所述第十一晶体管的数量通过将所述放大装置中第二晶体管的数量以所述第二比例缩小后得到,所述第十二晶体管的数量通过将所述放大装置中第四晶体管的数量以所述第二比例缩小后得到。The fourth differential amplifier circuit includes at least one eleventh transistor and at least one twelfth transistor. The gate of the eleventh transistor is coupled to the positive input terminal of the fourth differential amplifier circuit. The gate of the transistor is coupled to the negative input terminal of the fourth differential amplifier circuit, and the number of the eleventh transistor is obtained by reducing the number of the second transistor in the amplifying device by the second ratio. The number of the twelfth transistor is obtained by reducing the number of the fourth transistor in the amplifying device by the second ratio.
  11. 如权利要求7~10任一项所述的放大装置,其特征在于,所述闭环反馈电路还包括:The amplifying device according to any one of claims 7 to 10, wherein the closed-loop feedback circuit further comprises:
    所述第二电流源,用于为所述第一差分放大电路和所述第三差分放大电路提供直流偏置;The second current source is used to provide a DC bias for the first differential amplifier circuit and the third differential amplifier circuit;
    缓冲器,用于为所述第二差分放大电路和所述第四差分放大电路提供直流偏置,所述缓冲器的输入端与所述闭环反馈电路的输出端耦合;A buffer for providing a DC bias for the second differential amplifying circuit and the fourth differential amplifying circuit, the input end of the buffer is coupled with the output end of the closed loop feedback circuit;
    依次串联的第一电阻、第二电阻、第三电阻和第四电阻;所述第一电阻耦合至第一电源,所述第四电阻耦合接地,所述第二电阻和所述第三电阻与所述第二电流源耦合;所述第一电阻与所述第二电阻的阻值之比为m-1,所述第四电阻与所述第三电阻的阻值之比为m-1,所述第二电阻与所述第三电阻的阻值相同;其中,所述第一电阻与所述第一电源的连接处与所述第三差分放大电路的正输入端耦合,所述第四电阻的耦合接地端与所述第三差分放大电路的负输入端耦合;所述第一电阻与所述第二电阻的连接处与所述第一差分放大电路的正输入端耦合,所述第三电阻和所述第四电阻的连接处与所述第一差分放大电路的负输入端耦合;The first resistor, the second resistor, the third resistor, and the fourth resistor are connected in series; the first resistor is coupled to the first power source, the fourth resistor is coupled to the ground, and the second resistor and the third resistor are connected to the The second current source is coupled; the resistance ratio of the first resistor to the second resistance is m-1, and the resistance ratio of the fourth resistance to the third resistance is m-1, The second resistor and the third resistor have the same resistance value; wherein the connection between the first resistor and the first power source is coupled to the positive input terminal of the third differential amplifier circuit, and the fourth The coupling ground end of the resistor is coupled to the negative input end of the third differential amplifier circuit; the connection between the first resistor and the second resistor is coupled to the positive input end of the first differential amplifier circuit, and the first The junction of the three resistors and the fourth resistor is coupled with the negative input terminal of the first differential amplifier circuit;
    依次串联的第五电阻、第六电阻、第七电阻和第八电阻;所述第五电阻耦合至第二电源,所述第八电阻耦合接地,所述第六电阻和所述第七电阻与所述缓冲器的输出端耦合;所述第五电阻与所述第六电阻的阻值之比为m-1,所述第八电阻与所述第七电阻的阻值之比为m-1,所述第六电阻与所述第七电阻的阻值相同;其中,所述第五电阻与所述第二电源的连接处与所述第四差分放大电路的正输入端耦合,所述第八电阻的耦合接地端与所述第四差分放大电路的负输入端耦合;所述第五电阻与所述第六电阻的连接处与所述第二差分放大电路的正输入端耦合,所述第七电阻和所述第八电阻的连接处与所述第二差分放大电路的负输入端耦合。The fifth resistor, the sixth resistor, the seventh resistor, and the eighth resistor are connected in series; the fifth resistor is coupled to the second power source, the eighth resistor is coupled to the ground, and the sixth resistor and the seventh resistor are connected to the The output terminal of the buffer is coupled; the resistance ratio of the fifth resistor to the sixth resistor is m-1, and the resistance ratio of the eighth resistor to the seventh resistor is m-1 , The sixth resistor has the same resistance value as the seventh resistor; wherein the connection between the fifth resistor and the second power source is coupled to the positive input terminal of the fourth differential amplifier circuit, and the first The coupling ground end of the eight resistor is coupled to the negative input end of the fourth differential amplifier circuit; the connection of the fifth resistor and the sixth resistor is coupled to the positive input end of the second differential amplifier circuit, the The junction of the seventh resistor and the eighth resistor is coupled with the negative input terminal of the second differential amplifier circuit.
  12. 如权要求3~11任一项所述的放大装置,其特征在于,所述第二电流源由所述第一电流源镜像偏置后得到。The amplifying device according to any one of claims 3 to 11, wherein the second current source is obtained after being mirror-biased by the first current source.
  13. 如权利要求1~12任一项所述的放大装置,其特征在于,所述第一晶体管的栅极用于接收所述第一信号,所述第一晶体管的源极耦合接地,所述第一晶体管的漏极与所述放大装置的负载耦合;The amplifying device according to any one of claims 1 to 12, wherein the gate of the first transistor is used to receive the first signal, the source of the first transistor is coupled to ground, and the The drain of a transistor is coupled to the load of the amplifying device;
    所述第二晶体管的源极耦合接地,所述第二晶体管的漏极与所述放大装置的负载耦合;The source of the second transistor is coupled to ground, and the drain of the second transistor is coupled to the load of the amplifying device;
    所述第三晶体管的栅极用于接收所述第二信号,所述第三晶体管的源极耦合接地,所 述第三晶体管的漏极与所述放大装置的负载耦合;The gate of the third transistor is used to receive the second signal, the source of the third transistor is coupled to ground, and the drain of the third transistor is coupled to the load of the amplifying device;
    所述第四晶体管的源极耦合接地,所述第四晶体管的漏极与所述放大装置的负载耦合。The source of the fourth transistor is coupled to ground, and the drain of the fourth transistor is coupled to the load of the amplifying device.
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