JPS6172148A - Building structure - Google Patents

Building structure

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Publication number
JPS6172148A
JPS6172148A JP19338884A JP19338884A JPS6172148A JP S6172148 A JPS6172148 A JP S6172148A JP 19338884 A JP19338884 A JP 19338884A JP 19338884 A JP19338884 A JP 19338884A JP S6172148 A JPS6172148 A JP S6172148A
Authority
JP
Japan
Prior art keywords
point
regular hexahedron
unit
division
points
Prior art date
Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
Pending
Application number
JP19338884A
Other languages
Japanese (ja)
Inventor
寺田 秀夫
Current Assignee (The listed assignees may be inaccurate. Google has not performed a legal analysis and makes no representation or warranty as to the accuracy of the list.)
ITASU KK
Original Assignee
ITASU KK
Priority date (The priority date is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the date listed.)
Filing date
Publication date
Application filed by ITASU KK filed Critical ITASU KK
Priority to JP19338884A priority Critical patent/JPS6172148A/en
Publication of JPS6172148A publication Critical patent/JPS6172148A/en
Pending legal-status Critical Current

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Abstract

(57)【要約】本公報は電子出願前の出願データであるた
め要約のデータは記録されません。
(57) [Summary] This bulletin contains application data before electronic filing, so abstract data is not recorded.

Description

【発明の詳細な説明】 〔産業上の利用分野〕 本発明は建築構造体に関し、詳しくは、正六面体を構成
する一面の正方形の上に成立するドームを縦・横任怠に
連接して得られる建築構造体に関する 〔従来の技術〕 ドーム構造体 空間まで任意の大きさの空間を覆うことができ、ドーム
の単位構成面が三角形をなすドーム構造体に関して述べ
ると、ドームの構成面となる三角形状の1ユニツトの大
きさを人間の持てる大きさまで分割すれば、その三角形
状の1ユニツトを順次連接することによって誰にでも安
定した構造体を構築することができる。
[Detailed Description of the Invention] [Field of Industrial Application] The present invention relates to an architectural structure, and more specifically, the present invention relates to an architectural structure that is obtained by vertically and horizontally connecting domes formed on one square of a regular hexahedron. [Prior art] Regarding a dome structure that can cover a space of any size up to the dome structure space, and whose unit constituent faces are triangular, there is a dome structure in which the unit constituent faces of the dome are triangular. If the size of one unit of the shape is divided to a size that a human can hold, anyone can construct a stable structure by sequentially connecting the triangular units.

〔発明か解決しようとする問題点〕[Problem that the invention attempts to solve]

しかしながら一般的にドーム状構造体は半球状或いは球
状に近似するので、その垂直投影面積が太き(なればな
る程、必然的にその高さも高くなり、その構築時の危険
性も増大するとともに、起重機等の設備も必要になり、
アマチュアが垂直投影面積の大きなドームを構築するに
際して極めて大きな障壁となる。
However, since dome-shaped structures are generally hemispherical or spherical, their vertical projected area is larger (the larger they are, the higher their height will inevitably be, and the dangers associated with their construction will also increase). , equipment such as a hoist is also required,
This poses an extremely large barrier for amateurs to construct domes with large vertical projected areas.

〔問題点を解決するための手段及びその作用〕本発明は
このような現状に鑑みてなされたものであり、アマチュ
アでも例えば物置・温室・仮設建築物等任意の大きさの
空間を覆うことのできるドーム状の建築構造体を提供す
ることを目的とする。
[Means for solving the problems and their effects] The present invention was made in view of the current situation, and even amateurs can use it to cover spaces of arbitrary size, such as storerooms, greenhouses, temporary buildings, etc. The purpose is to provide a dome-shaped architectural structure that can be constructed.

要約すれば、本発明の建築構造体は、正六面体の外接味
を前記正六面体を構成する一面の正六面体の4辺を弦と
する円弧によって分離して得られる、前記正六面体の外
接味の一部を、前記正六面体を構成する前記一面の正方
形の重心を通る垂線が前記正六面体の外接味と交叉する
点と、前記正六面体を構成する前記一面の正方形の各頂
点とを結ぶ線分を弦とする円弧によって4つの中部分に
第1の分割をし、第1の分割をなされた前記正六面体の
外接味の一部を囲む3つの円弧を各々3分割し、その各
分割点を結ぶ線分を弦とする円弧によって前記第1の分
割をなされた前記中部分を更に各々9つの小部分に第2
の分割をし、第2の分割をなされた前記小部分の頂点を
連結する単位個体を相互に連接して得られるドーム状構
造体を単位ユニットとして、上記単位ユニットのドーム
状構造体を前後左右に連接することによって任意の大き
さの空間を覆うことができるようになされている。
In summary, the architectural structure of the present invention has a circumscribed taste of a regular hexahedron obtained by separating the circumscribed taste of the regular hexahedron by an arc whose chord is the four sides of one regular hexahedron constituting the regular hexahedron. A line segment connecting a point where a perpendicular line passing through the center of gravity of the one-sided square constituting the regular hexahedron intersects the circumscription of the regular hexahedron and each vertex of the one-sided square constituting the regular hexahedron. A first division is made into four middle parts by a circular arc whose chord is , and each of the three circular arcs surrounding a part of the circumscribed area of the regular hexahedron that has been made the first division is divided into three parts, and each division point is The middle part, which has been divided into the first part by a circular arc whose chord is the connecting line segment, is further divided into nine small parts.
The dome-shaped structure obtained by dividing the unit parts into each other and connecting the vertices of the second divided small parts to each other is taken as a unit unit, and the dome-shaped structure of the above unit unit is divided into the front, back, left, and right directions. It is designed to cover a space of any size by connecting it to.

〔発明の実施例] 以下図面を参照して本発明の1実施例を詳細に説明する
[Embodiment of the Invention] An embodiment of the present invention will be described in detail below with reference to the drawings.

先ず、第1図は本発明の1実施例となる単位ユニットの
ドーム状の構造体の基本構造を示す平面図、第2図は上
記単位ユニットのドーム状の構造体の基本構造を示す正
面図、第3図は上記単位ユニットのドーム状の構造体の
基本構造を示す斜視図である。
First, FIG. 1 is a plan view showing the basic structure of a dome-shaped structure of a unit according to an embodiment of the present invention, and FIG. 2 is a front view showing the basic structure of the dome-shaped structure of the unit. , FIG. 3 is a perspective view showing the basic structure of the dome-shaped structure of the unit.

本発明の構造体の単位ユニットは、正六面体の外接味を
前記正六面体を構成する一面の正方形の4辺を弦とする
円弧によって分離して得られる、前記正六面体の外接味
の一部の上に成立する。
The unit of the structure of the present invention is a part of the circumscribed flavor of the regular hexahedron obtained by separating the circumscribed flavor of the regular hexahedron by an arc whose chord is the four sides of a square on one side constituting the regular hexahedron. established above.

具体的には本発明の構造体のベースとなる正六面体10
は図面においては一点鎖線で示されており、正六面体1
0は唯一の外接味20を持つ。
Specifically, the regular hexahedron 10 that is the base of the structure of the present invention
is shown by a dashed line in the drawing, and is a regular hexahedron 1
0 has only one circumscribed flavor 20.

そして正六面体10の一面をなす正方形10aの各頂点
を各々点P2・点P3・点P4・点P5と定義し、点P
2・点P3を結ぶ線分を弦とする円弧(本明!I書にお
いて円弧という場合はその円弧は前記外接味20の一部
をなし、正六面体10の重心をその中心とする。)と、
点P3 ・点P4を結ぶ線分を弦とする円弧と、点P4
・点P5を結ぶ線分を弦とする円弧と、点P5・点P2
を結ぶ線分を弦とする円弧とによって前記の外接味20
の1/6の部分を概念的に分離する。
Then, each vertex of the square 10a forming one side of the regular hexahedron 10 is defined as point P2, point P3, point P4, and point P5, and the point P
2. A circular arc whose chord is the line segment connecting the point P3 (in the case of a circular arc in this book I, the circular arc forms a part of the circumscribed element 20 and has the center of gravity of the regular hexahedron 10 as its center). ,
A circular arc whose chord is the line segment connecting point P3 and point P4, and point P4
・A circular arc whose chord is the line segment connecting point P5, and points P5 and P2
The above circumscription 20 is obtained by the arc whose chord is the line segment connecting
conceptually separate 1/6 of the

次ぎに、第2図に示すように、この正六面体lOを構成
する一つの正方形10aの重心Gを通過する垂線が前記
正六面体10の外接味20と交叉する点を点P、と定義
し、上記のようにして分離された外接味20の1/6の
部分を、点P1と点P2を通過する円弧と、点P1と点
P3を通過する円弧と、点PI と点P4を通過する円
弧と、点Plと点P5を通過する円弧とによって4つの
中部分に第1の分割する。
Next, as shown in FIG. 2, the point where a perpendicular line passing through the center of gravity G of one square 10a constituting this regular hexahedron 10 intersects the circumscribed line 20 of the regular hexahedron 10 is defined as a point P, The 1/6 portion of the circumscribed taste 20 separated as described above is divided into an arc passing through points P1 and P2, an arc passing through points P1 and P3, and an arc passing through points PI and P4. and a circular arc passing through point Pl and point P5.

次ぎに、点P1と点P2を通過する円弧を点P6及び点
P7で3分割し、点P、と点P3を通過する円弧を点2
日及び点P9で3分割し、点PIと点P4を通過する円
弧を点PIO及び点Puで3分割し、点P、と点P5を
通過する円弧を点PI2及び点pegで3分割する。
Next, the arc passing through points P1 and P2 is divided into three by points P6 and P7, and the arc passing through points P and P3 is divided into three parts.
The arc passing through points PI and P4 is divided into three by points PIO and Pu, and the arc passing through points P and P5 is divided into three by points PI2 and peg.

又、点P2と点P3を通過する円弧を点P14及び点P
ISで3分割し、点P3と点P4を通過する円弧を点P
 +6及び点PI7で3分割し、点P4と点P5を通過
する円弧を点p te及び点P tQで3分割し、点P
5と点P、を通過する円弧を点P20及び点P21で3
分割する。
Also, the arc passing through point P2 and point P3 is defined as point P14 and point P.
Divided into three by IS, the arc passing through points P3 and P4 is set to point P.
+6 and point PI7, the arc passing through points P4 and P5 is divided into three by points p te and points P tQ, and point P
The arc passing through 5 and point P is 3 at points P20 and P21.
To divide.

次に、第4図Aに示すように、点P6と点P20を結ぶ
円弧と、点P12と点P21を結ぶ円弧と、点PDと点
P7を結ぶ円弧は各々3点で相互に交叉する。そしてこ
の3点の交叉点を第4図Bに拡大して示すように点P 
22 a・点P22b・点P 22 Cと定義し、点P
22a’点P22b・点P22cとによって形成される
三角形(第4図Bに斜線で示す三角形)の重心G、と外
接床20の中心Pを結ぶ直線が前記外接床20と交叉す
る点を点P22と定義する。尚、第4図Bでは外接床の
一部を点P 22 a・点P22b・点P 22 cと
によって形成される三角形から浮き上がらせて示してい
るが、実際にはその各頂点となる点P 22 a・点P
 22 b・点P 22 Cが各々一致することはいう
までもない。
Next, as shown in FIG. 4A, the arc connecting points P6 and P20, the arc connecting points P12 and P21, and the arc connecting points PD and P7 intersect each other at three points. As shown in Fig. 4B, the intersection point of these three points is a point P.
22 a, point P22b, point P 22 C, and point P
22a' The point where the straight line connecting the center of gravity G of the triangle formed by points P22b and P22c (triangle indicated by diagonal lines in FIG. 4B) and the center P of the circumscribed floor 20 intersects the circumscribed floor 20 is called the point P22. It is defined as In addition, in FIG. 4B, a part of the circumscribed floor is shown raised from the triangle formed by points P 22 a, points P 22 b, and points P 22 c, but in reality, each of the points P 22 22 a・Point P
It goes without saying that the points 22b and 22c coincide with each other.

以下同様にして点P8と点P 14を結ぶ円弧と、点P
6と点PISを結ぶ円弧と、点P7と点P9を結ぶ円弧
との交叉点を頂点として形成される三角形の重心と外接
床20の中心Pを通る直線が前記外接床20と交叉する
点を点P23と定義し、点P、。と点PI6を結ぶ円弧
と、点Pθと点P +7を結ぶ円弧と、点P9と点pH
を結ぶ円弧との交叉点を頂点として形成される三角形の
重心と前記外接床20の中心Pを通る直線が前記外接床
20と交叉する点を点P 24と定義し、点P12と点
P18を結ぶ円弧と、点PIOと点PI9を結ぶ円弧と
、点pttと点Pl!を結ぶ円弧との交叉点を頂点とし
て形成される三角形の重心と外接床20の中心Pを通る
直線が前記外接床20と交叉する点を点P25と定義す
る。
Similarly, a circular arc connecting points P8 and P14 and a point P
The point where a straight line passing through the center P of the circumscribed floor 20 and the center of gravity of a triangle formed with the vertex at the intersection of the circular arc connecting 6 and the point PIS and the circular arc connecting the points P7 and P9 intersects the circumscribed floor 20. Point P23 is defined as point P,. an arc connecting point PI6, an arc connecting point Pθ and point P+7, and point P9 and point pH
The point where a straight line passing through the center P of the circumscribed floor 20 and the centroid of the triangle formed with the apex at the point of intersection with the circular arc connecting the two intersects the circumscribed floor 20 is defined as a point P24, and the point P12 and the point P18 are defined as a point P24. The connecting arc, the arc connecting points PIO and PI9, and the points PTT and Pl! A point P25 is defined as a point where a straight line passing through the center P of the circumscribed floor 20 and the center P of the triangle formed with the intersection point with the circular arc connecting the apexes intersects the circumscribed floor 20 as a point P25.

このようにして外接味20上に点P1から点P25迄の
点を決定し、相互に隣接する点間を剛体で連結すると第
1の分割をされた4つの中部分が各々9つの小部分に第
2の分割をなされて、ドーム状の構造体が構成される。
In this way, by determining the points from point P1 to point P25 on the circumscribed element 20 and connecting the mutually adjacent points with a rigid body, the four middle parts that were first divided are each divided into nine small parts. A second division is made to form a dome-shaped structure.

そして、この構造体は前記第2の分割をなされた三角形
状の小部分を連結した構造となるので、力学数に極めて
強固なものとなり、しかも各点間の距離が決定されれば
誰が構築しても常に同一の構造体を得ることができる。
Since this structure is a structure in which the triangular parts obtained by the second division are connected, it is extremely robust against mechanical numbers, and can be constructed by anyone once the distance between each point is determined. You can always get the same structure no matter what.

そこで、本実施例では例えば第2の分割をなされた各小
部分、即ち、点P1 ・点P6 ・点P12で形成され
る三角板状の単位個体を4枚、点P6 ・点P、2・点
P22で形成される三角板状の単位個体を4枚、点P6
・点P7・点P22で形成される三角板状の単位個体を
4枚、点P1゜・点P13・点P4・2・で形成される
三角板状の単位個体を4枚、点P7・点P2・点P21
で形成される三角板状の単位個体を4枚、点P7・点P
21・点P22で形成される三角板状の単位個体を4枚
、点P22・点P21・点P20で形成される三角板状
の単位個体を4枚、点P22・点P20・点P13で形
成される三角板状の単位個体を4枚、点PIK・点P2
0・点P5で形成される三角板状の単位個体を4枚を1
組としたキットを指定通りに連結することにより単位ユ
ニ・7トのドーム構造体を構築できるようにしている。
Therefore, in this embodiment, for example, each of the second divided small parts, that is, four triangular plate-shaped unit bodies formed by point P1, point P6, and point P12, is divided into four triangular plate-shaped unit bodies, which are formed by point P6, point P, and point 2. Four triangular plate-shaped unit individuals formed at P22, point P6
・Four triangular plate-shaped unit individuals formed by point P7 and point P22, four triangular plate-shaped unit individuals formed by point P1°, point P13, point P4, 2, point P7, point P2, Point P21
Four triangular plate-shaped unit individuals formed by, point P7 and point P
21. 4 triangular plate-shaped unit individuals formed by point P22, 4 triangular plate-shaped unit individuals formed by point P22, point P21, and point P20, and 4 triangular plate-shaped unit individuals formed by point P22, point P20, and point P13. 4 triangular plate-shaped unit individuals, point PIK, point P2
0. 4 triangular plate-shaped unit individuals formed by point P5 are 1
By connecting the assembled kits as specified, a dome structure of 7 units can be constructed.

例えば、点PL  ・点P6 ・点P12で形成される
三角板状の単位個体と点P6・点P12・点P22で形
成される三角板状の単位個体の断面を第5図に示すと、
本実施例では点P、・点P6 ・点PI3間に形成され
る三角板状の単位個体30と点P6・点P12・点P2
2間に形成される三角板状の単位個体40の外周に各々
一定の幅の立曲げ部31・41を形成し、立曲げ部31
・41に各々少なくとも2箇所以上のボルト穴32・4
2を穿孔し、ボルト穴32・42をポル)50及びすy
 ) 51で締結すれば、三角板状の単位個体30と三
角板状の単位個体40とが画一的に連結される。そして
全ての三角板状の単位個体を同様にして指示通りに連結
すれば、誰でも確実に単位ユニットのドーム構造体を構
築することが可能になる。
For example, FIG. 5 shows the cross sections of a triangular plate-shaped unit formed by points PL, P6, and P12, and a triangular plate-shaped unit formed by points P6, P12, and P22.
In this embodiment, the triangular plate-shaped unit individual 30 formed between the points P, ・Point P6, and Point PI3, and the points P6, P12, and P2
Vertical bent portions 31 and 41 each having a constant width are formed on the outer periphery of the triangular plate-shaped unit body 40 formed between the vertical bent portions 31 and 2.
・At least two bolt holes 32 and 4 in each of 41
2 and bolt holes 32 and 42) 50 and sy
) 51, the triangular plate-shaped unit individual 30 and the triangular plate-shaped unit individual 40 are uniformly connected. By connecting all the triangular plate-shaped units in the same manner and following the instructions, anyone can reliably construct a unit dome structure.

そして、本実施例において特徴的な点は、上記の如くし
て構築される単位ユニットのドーム状の構造体が、正六
面体10の外接法20を前記正六面体を構成する一つの
正方形10aの各辺を弦とする円弧で分離した外接法2
0の一部の上に成立し、且つ、正方形10aの各辺を弦
とする円弧を各々3分割しているという点である。従っ
て、本実施例によって構築される単位ユニットのドーム
状の構造体は、点P14と点PI5を結ぶ線分が点P1
8と点P19を結ぶ線分と平行になり、点P16と点P
、?を結ぶ線分が点P20と点P2□を結ぶ線分と平行
になるとともに、点P L4と点P15を通る直線及び
点pieと点PI9を通る直線が、点P16と点P L
7を通る直線及び点P20と点P21を通る直線と各々
直交するので、第6図及び第7図に示すように単位ユニ
ットのドーム状の構造体を縦・横任意数連接させれば、
任意の大きさの空間を覆うことができる。
The characteristic point of this embodiment is that the dome-shaped structure of the unit constructed as described above has a circumscription 20 of the regular hexahedron 10, which corresponds to each of the squares 10a constituting the regular hexahedron. Circumscription method 2 separated by an arc whose sides are chords
The point is that an arc that is established on a part of 0 and whose chord is each side of the square 10a is divided into three parts. Therefore, in the dome-shaped structure of the unit constructed according to this embodiment, the line segment connecting the point P14 and the point PI5 is the point P1.
It is parallel to the line segment connecting 8 and point P19, and the point P16 and point P
,? The line segment connecting the points P20 and P2□ becomes parallel to the line segment connecting the points P20 and P2
7 and the straight line passing through points P20 and P21, respectively, so if an arbitrary number of unit dome-shaped structures are connected vertically and horizontally as shown in FIGS. 6 and 7,
Can cover any size space.

尚、第6図は上記のようにして単位ユニットのドーム状
の構造体を縦に3個、横に5個連接した状態を示す平面
図であり、第7図はその正面図である。そして単位ユニ
ットのドーム状構造体間の空隙(第6図及び第7図中に
斜線で示す星型の部分)には同一形状の充填部材を取り
付ければ、任意の広さの空間を覆うことができ、又、そ
の四辺を構造壁又は柱で持ち上げれば任意の高さの構築
物を得ることができる。
Incidentally, FIG. 6 is a plan view showing a state in which three dome-shaped structures of unit units are connected vertically and five horizontally as described above, and FIG. 7 is a front view thereof. If a filling member of the same shape is attached to the gap between the dome-shaped structures of the unit units (the star-shaped portion indicated by diagonal lines in Figures 6 and 7), it is possible to cover a space of any size. Moreover, by lifting the four sides with structural walls or columns, a structure of any height can be obtained.

又、単位ユニットのドーム状の構造体を縦横に連接する
場合は上記の第5図において例示したように単位ユニッ
トのドーム状構造体の構成要素となる三角板状の単位個
体の周囲の立曲げ部分を前記と同様にボルトナツトその
他の締結手段で締結すればよい。
In addition, when the dome-shaped structures of the unit units are connected vertically and horizontally, as illustrated in Fig. 5 above, the vertically bent portions around the triangular plate-shaped unit bodies, which are the constituent elements of the dome-shaped structure of the unit units, are connected vertically and horizontally. may be fastened with bolts and nuts or other fastening means in the same manner as described above.

又、上記では1組の三角板状の単位個体を連接して単位
ユニットのドーム状構造体を構築する例を示したが、外
接法20上の隣接する2点(例えば第1図における点P
1と点Ps)を結ぶ棒状僻を単位制体止して、ジヨイン
ト金具で順次連接するようにしてもよい。尚、その場合
は棒状の単位個体間の空間面はアクリル板等によって被
覆されることはいうまでもない。
Furthermore, in the above example, a set of triangular plate-shaped unit bodies is connected to construct a dome-shaped structure of unit units.
1 and point Ps) may be fixed as a unit and sequentially connected using joint fittings. In this case, it goes without saying that the space between the rod-shaped units is covered with an acrylic plate or the like.

更に、上記では例えば点P1と点P2とを結ぶ線分を弦
とする円弧を3等分するようにした例を示したが、点P
1と点P2とを結ぶ弦を3等分してもよい。
Furthermore, in the above example, the arc whose chord is the line segment connecting points P1 and P2 is divided into three equal parts.
The string connecting point P2 and point P2 may be divided into three equal parts.

又、上記では単位ユニットのドーム状の構造体の大きさ
は特に限定せずに説明したが(尚、この大きさを限定す
ることは本発明の本質的な要求ではない。)アマチtア
が個人的に組み立てることを想定した場合は例えば点P
1と点P6間の距離は通常は数10cm乃至1m数10
cmになるであろう。
In addition, although the size of the dome-shaped structure of the unit unit is not particularly limited in the above description (note that limiting this size is not an essential requirement of the present invention), If you are assuming that you will assemble it personally, for example, point P
The distance between 1 and point P6 is usually several tens of cm to 1 m.
It will be cm.

〔発明の効果〕〔Effect of the invention〕

以上説明したように、本発明によれは、予め組み合わさ
れた三角板や棒状体等の単位個体を指示通りに連接すれ
ば、誰でも確実に単位ユニットのドーム状の構造体を構
築することができるとともに、上記のようにして構築さ
れた単位ユニットのドーム状構造体を縦横に任意数連接
することによって任意大きさの空間を覆うことも可能に
なる。
As explained above, according to the present invention, anyone can reliably construct a dome-shaped structure of unitary units by connecting unitary units such as triangular plates and rod-shaped bodies assembled in advance as instructed. At the same time, it is also possible to cover a space of any size by connecting any number of unit dome-shaped structures constructed as described above vertically and horizontally.

更に、本発明によれば平地で単位ユニットのドーム状構
造体構築した後に、これを縦横に連接することによって
任免の大きさの空間を覆うことができるので、たとえ垂
直投影面積の大きな空間を覆う場合であっても、構築に
際しての危険性は増大せず、又、起重機等の大型設備も
不要になる。
Furthermore, according to the present invention, by constructing a unit dome-shaped structure on a flat ground and then connecting it vertically and horizontally, it is possible to cover a space as large as the size of an appointment, so even if a space with a large vertical projected area is covered. Even in the case of construction, the danger during construction does not increase, and large equipment such as a hoist becomes unnecessary.

更に、本発明によって得られるドーム状の構造体は、そ
れが単位ユニットの構造体であれ、単位ユニットの構造
体を連接した構造体であれ、その内法が概ね方形になる
ので、家具やその他の設備を収納するあ際しても、従来
の設備をそのまま流用することが可能になる。
Furthermore, the dome-shaped structure obtained by the present invention, whether it is a structure of unit units or a structure of connected unit structures, has an approximately rectangular inner dimension, so it can be used for furniture or other objects. Even when storing equipment, it is possible to use the existing equipment as is.

【図面の簡単な説明】[Brief explanation of the drawing]

第1図は本発明の1実施例となる単位ユニ・7トのドー
ム状構造体の基本構造を示す平面図、第2図は上記単位
ユニットのドーム状構造体の基本構造を示す正面図、第
3図は上記単位ユニットのドーム状構造体の基本構造を
示す斜視図、第4図A第4図Bは点P22の位置を示す
説明図、第5図は三角板の連接方法の1例を示す断面図
、第6図は単位ユニットのドーム状構造体を連接した状
態の平面図、第7図は単位ユニットのドーム状構造体を
連接した状態の正面図。 10・・・正六面体    10a・・・正方形20・
・・外接法 P、〜P25・・・外接床上の定義された点30・40
・・・三角板  31・41・・・立曲げ部32・42
・・・ボルト穴 50・・・ボルト51・・・ナツト
FIG. 1 is a plan view showing the basic structure of a dome-like structure of unit 7 which is an embodiment of the present invention, FIG. 2 is a front view showing the basic structure of the dome-like structure of the above-mentioned unit, FIG. 3 is a perspective view showing the basic structure of the dome-shaped structure of the unit, FIG. 4A and FIG. 4B are explanatory diagrams showing the position of point P22, and FIG. 5 is an example of a method of connecting triangular plates. FIG. 6 is a plan view of the dome-like structures of the unit units connected together, and FIG. 7 is a front view of the dome-like structures of the unit units connected together. 10...Regular hexahedron 10a...Square 20.
... Circumscribed method P, ~ P25 ... Defined points 30 and 40 on the circumscribed floor
... Triangular plate 31, 41 ... Vertical bent part 32, 42
...Bolt hole 50...Bolt 51...Nut

Claims (2)

【特許請求の範囲】[Claims] (1)、正六面体の外接球を前記正六面体を構成する一
面の正方形の4辺を弦とする円弧によつて分離して得ら
れる、前記正六面体の外接球の一部を、前記正六面体を
構成する前記一面の正方形の重心を通る垂線が前記正六
面体の外接球と交叉する点と、前記正六面体を構成する
前記一面の正方形の各頂点とを結ぶ線分を弦とする円弧
によつて4つの中部分に第1の分割をし、 第1の分割をなされた前記正六面体の外接球の一部を囲
む3つの円弧を各々3分割し、その各分割点を結ぶ線分
を弦とする円弧によつて前記第1の分割をなされた前記
中部分を更に各々9つの小部分に第2の分割をし、 第2の分割をなされた前記小部分の頂点を連結する単位
個体を相互に連接してドーム構造を得るようにした建築
構造体。
(1), a part of the circumscribed sphere of the regular hexahedron obtained by separating the circumscribed sphere of the regular hexahedron by an arc whose chord is the four sides of the square on one side constituting the regular hexahedron, An arc whose chord is a line segment connecting the point where a perpendicular passing through the center of gravity of the one-sided square constituting the square intersects the circumscribed sphere of the regular hexahedron and each vertex of the one-sided square constituting the regular hexahedron. Divide the first division into four middle parts, divide each of the three arcs surrounding a part of the circumscribed sphere of the regular hexahedron into three parts, and draw the line segment connecting each division point into three parts. The middle part, which has been divided into the first division by a circular arc, is further divided into a second division into nine small parts, and a unit individual is formed by connecting the vertices of the second division into nine small parts. An architectural structure that is interconnected to form a dome structure.
(2)、正六面体の外接球を前記正六面体を構成する一
面の正方形の4辺を弦とする円弧によつて分離して得ら
れる、前記正六面体の外接球の一部を、前記正六面体を
構成する前記一面の正方形の重心を通る垂線が前記正六
面体の外接球と交叉する点と、前記正六面体を構成する
前記一面の正方形の各頂点とを結ぶ線分を弦とする円弧
によつて4つの中部分に第1の分割をし、 第1の分割をなされた前記正六面体の外接球の一部を囲
む3つの円弧を各々3分割し、その各分割点を結ぶ線分
を弦とする円弧によつて前記第1の分割をなされた前記
中部分を更に各々9つの小部分に第2の分割をし、 第2の分割をなされた前記小部分の頂点を連結する単位
個体を相互に連接して得られる1単位のドーム構造体を
、 前記正六面体を構成する前記一面の正方形の隣接する頂
点を結ぶ線分を弦とする円弧を3分割した中央部で連接
するようにした建築構造体。
(2), a part of the circumscribed sphere of the regular hexahedron obtained by separating the circumscribed sphere of the regular hexahedron by an arc whose chord is the four sides of the square on one side constituting the regular hexahedron, An arc whose chord is a line segment connecting the point where a perpendicular passing through the center of gravity of the one-sided square constituting the square intersects the circumscribed sphere of the regular hexahedron and each vertex of the one-sided square constituting the regular hexahedron. Divide the first division into four middle parts, divide each of the three arcs surrounding a part of the circumscribed sphere of the regular hexahedron into three parts, and draw the line segment connecting each division point into three parts. The middle part, which has been divided into the first division by a circular arc, is further divided into a second division into nine small parts, and a unit individual is formed by connecting the vertices of the second division into nine small parts. One unit of dome structure obtained by connecting each other is connected at the center of a circular arc whose chord is a line segment connecting adjacent vertices of the squares on one side constituting the regular hexahedron. architectural structure.
JP19338884A 1984-09-14 1984-09-14 Building structure Pending JPS6172148A (en)

Priority Applications (1)

Application Number Priority Date Filing Date Title
JP19338884A JPS6172148A (en) 1984-09-14 1984-09-14 Building structure

Applications Claiming Priority (1)

Application Number Priority Date Filing Date Title
JP19338884A JPS6172148A (en) 1984-09-14 1984-09-14 Building structure

Publications (1)

Publication Number Publication Date
JPS6172148A true JPS6172148A (en) 1986-04-14

Family

ID=16307103

Family Applications (1)

Application Number Title Priority Date Filing Date
JP19338884A Pending JPS6172148A (en) 1984-09-14 1984-09-14 Building structure

Country Status (1)

Country Link
JP (1) JPS6172148A (en)

Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
JPS525766A (en) * 1975-07-02 1977-01-17 Fujisawa Pharmaceut Co Ltd Process for preparation of 1-h-indazole acetate derivatives
JPS57187450A (en) * 1981-04-30 1982-11-18 Toringaari Mario Three-dimensional structural element
JPS598848U (en) * 1982-07-08 1984-01-20 日産自動車株式会社 Automobile rear lamp lighting confirmation device

Patent Citations (3)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
JPS525766A (en) * 1975-07-02 1977-01-17 Fujisawa Pharmaceut Co Ltd Process for preparation of 1-h-indazole acetate derivatives
JPS57187450A (en) * 1981-04-30 1982-11-18 Toringaari Mario Three-dimensional structural element
JPS598848U (en) * 1982-07-08 1984-01-20 日産自動車株式会社 Automobile rear lamp lighting confirmation device

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