JP2013226384A - Method for calculating indicator for determining necessity of jaw surgery in orthodontic treatment, method for determining necessity of jaw surgery in orthodontic treatment, method for calculating indicator for determining disharmony of maxilla and mandible, method for determining disharmony of maxilla and mandible, method for calculating indicators for determining jaw deformity, method for determining jaw deformity, program and computer - Google Patents

Abstract

PROBLEM TO BE SOLVED: To provide a method for calculating indicators for determining the necessity of jaw surgery in orthodontic treatment, the method enabling easy calculation of indicators for determining the necessity of jaw surgery that serve as objective material for a dentist to determine whether a patient requires jaw surgery in orthodontic treatment, and enabling the dentist to easily and quickly perform a more objective and accurate diagnosis by also taking the result of another examination method into account, as appropriate; and a program therefor.SOLUTION: Indicators for determining the necessity of jaw surgery in orthodontic treatment are calculated by calculating P=((S-X)+(Go-X))/(S-A) (except in the case where X=B and X=Me) using the following measurements from a cephalogram of a patient: the distance (S-A) between S and A; the distance (S-X) between S and X(i is an integer between 1 and 4, inclusive, and X=B, X=Pog, X=Gn, and X=Me); and the distance (Go-X) between Go and X(j is an integer between 1 and 4, inclusive, and j=i or j≠i).

Description

  The present invention relates to a method for calculating an index for determining whether or not jaw surgery is required in orthodontic treatment, a method for determining whether or not jaw surgery is necessary in orthodontic treatment, a method for calculating an index for determining incongruity in the upper and lower jaws, a method for determining incompatibility in the upper and lower jaws, a method for determining jaw deformation TECHNICAL FIELD The present invention relates to a method for calculating a symptom determination index, a method for determining a jaw deformity, a method for calculating a maxillary undergrowth / overgrowth determination index, a method for calculating a mandibular undergrowth / overgrowth determination index, their programs, and a computer having these programs. In the present invention, for example, a dentist determines whether or not a patient's jaw bone surgery is necessary for orthodontic treatment, and the dentist or doctor determines the degree of harmony (skeletal pattern) of the upper and lower jaw bones. It is suitable for use in determining whether or not it is a jaw deformity.

  In orthodontic treatment, some patients may need to perform jaw surgery. Conventionally, the necessity of this surgical operation of the jawbone is to take a cephalogram of the patient's cephalogram, and based on this cephalogram, perform a cephalometric analysis centered on angle measurement, Based on the result, a dentist made a judgment (for example, see Non-Patent Document 1).

Satoshi Kameda, “Diagnostic methods in orthodontic practice”, pages 54-71 (Medical Publishing Co., Ltd., issued in June 1978)

  However, since the above-described conventional diagnostic methods often depend on the experience of the dentist, as a result, the dentist tends to vary in the diagnosis results, making it difficult to make an objective diagnosis. For this reason, there was a possibility that appropriate orthodontic treatment could not be performed.

  On the other hand, if it is possible to objectively determine whether the patient's maxilla or mandible is incongruent or jaw deformity based on cephalometric analysis, there is a possibility that effective treatment can be performed based on that. Until now, no method has been found to objectively judge the incongruity of the maxilla and mandible or jaw deformity.

  Therefore, the problem to be solved by the present invention is to provide an index for determining whether or not a jaw bone operation is necessary as an objective material for a dentist to determine whether or not the patient's jaw surgery is necessary in orthodontic treatment of the patient. In orthodontic treatment, which can be easily calculated and enables dentists to make more accurate and accurate diagnosis easily and in a short time by combining the results of other inspection methods as appropriate. It is to provide a method for calculating an index for determining whether or not jaw surgery is necessary and a program therefor.

  Another problem to be solved by the present invention is to provide an index for determining whether or not jaw surgery is necessary as an objective material for a dentist to determine whether or not a patient needs jaw surgery in orthodontic treatment. A method for determining the necessity of jaw bone surgery in orthodontic treatment, which allows dentists to make more accurate and accurate diagnosis easily and in a short time by using the results of other inspection methods as appropriate And providing a program for it.

  Still another problem to be solved by the present invention is to provide an index for determining the inequalities of the maxilla and mandible, which is an objective material for a dentist or doctor to judge anomalies in the mandible and maxilla of the patient in the dental treatment or medical treatment of the patient. Maxillary bone incompatibility that can be easily calculated and allows dentists and doctors to make more accurate and accurate diagnosis easily and in a short time by using the results of other examination methods as appropriate It is to provide a method for calculating a judgment index and a program therefor.

  Still another problem to be solved by the present invention is to provide an index for determining the inequalities of the maxilla and mandible, which is an objective material for a dentist or doctor to judge anomalies in the mandible and maxilla of the patient in the dental treatment or medical treatment of the patient. Using and appropriately combining the results of other examination methods, the dentist and doctor can easily make a more objective and accurate diagnosis in a short time, and a method for determining the maxillary and mandibular incongruity and a program therefor Is to provide.

  Still another problem to be solved by the present invention is to easily calculate a jaw deformity determination index that is an objective material for a dentist or doctor to determine whether a patient has jaw deformity or not. And a method for calculating a jaw deformity determination index that allows a dentist or doctor to easily make a more objective and accurate diagnosis in a short time by combining the results of other examination methods as appropriate. It is to provide a program for this purpose.

  Still another problem to be solved by the present invention is that a dentist or doctor uses a jaw deformity determination index as an objective material for determining whether or not a patient has jaw deformity, and performs other examinations. It is to provide a method for judging jaw deformity and a program therefor that allow dentists and doctors to make more accurate and accurate diagnosis easily and in a short time by appropriately using the results of the method. .

  Still another problem to be solved by the present invention is that a dentist or a doctor or the like is a maxillary undergrowth / overgrowth determination index which is an objective material for determining the presence or degree of maxillary undergrowth or maxillary overgrowth of a patient. The maxillary undergrowth can be easily calculated, and the results of other examination methods can be used in combination, allowing dentists and doctors to make more accurate and accurate diagnosis easily and in a short time. / To provide an overgrowth determination index calculation method and a program therefor.

  Still another problem to be solved by the present invention is that a dentist or doctor or the like is a mandibular undergrowth / overgrowth determination index which is an objective material for judging the presence or absence or degree of mandibular undergrowth or mandible overgrowth of a patient. Mandibular undergrowth that allows dentists and doctors to make more accurate and accurate diagnoses easily and in a short time by easily combining the results of other testing methods / To provide an overgrowth determination index calculation method and a program therefor.

  Still another problem to be solved by the present invention is to provide a computer having the above program.

  The present inventor accidentally measures the distance between specific measurement points in a cephalometric radiogram in the course of conducting intensive research to solve the above-described problems, and uses these distances to calculate a specific calculation formula. It is found that by using the numerical value obtained by calculation based on the dentist, the dentist can objectively and easily determine whether or not the patient's jaw surgery is necessary in the orthodontic treatment of the patient. Actually, the above numerical values were calculated for a large number of patients to confirm their effectiveness. Furthermore, the present inventors have also found that the above numerical values are effective for objectively and easily determining whether or not the patient has a mandibular maxillary bone incompatibility or jaw deformity.

  The present invention has been devised as a result of intensive studies based on the above-mentioned knowledge obtained independently by the present inventors.

That is, in order to solve the above problems, the present invention provides:
The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
Jaw bone in orthodontic treatment that calculates P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me) This is a method for calculating an index for determining the necessity of surgery.

In addition, this invention
The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me)
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate
This is a method for determining whether or not jaw surgery is necessary in orthodontic treatment, in which it is determined whether or not the calculated P or Q is equal to or greater than a predetermined value.

  Here, S, A, B, Go, Pog, Gn, and Me are measurement points obtained by cephalometric radiography. The position of each measurement point is shown in FIG. S is an abbreviation for Sella, and is the center point of the saddle-shaped shadow image of the sphenoid turkey. A is an abbreviation for point A, ANS (the anterior nasal spine, which is the tip of the anterior nasal spine, the tip of the joint bone with the people under the nose) and the maxillary central incisor This is the deepest point on the mid-sagittal plane between the prosthion and the foremost tip of the interdental process. B is an abbreviation for point B, and is the deepest point between Infradentale and Pogonion. Go is an abbreviation for Gonion, and the bisector of the angle between the line connecting the posterior margin plane of the temporomandibular joint and the posterior edge of the mandibular angle and the mandibular plane intersects the mandibular angle. Is a point. Pog is an abbreviation for Pogonion, and is the most protruding point of the mandibular bulge relative to the Frankfurt plane. Gn is an abbreviation for Gnathion, which is the second of the angle between the face plane (N (Nasion, the foremost point of nasal frontal suture) and Pog) and the lower mandibular plane. This is the point where the line intersects with the raised ridge image. Me is an abbreviation for menton, and is the lowest point of the midline cross-sectional image of the chin.

Specifically, P = ((S−X _i ) + (Go−X _j )) / (S−A) is the following expressions (1) to (15).
P = ((S-Pog) + (Go-Me)) / (SA) (1)
P = ((S−Gn) + (Go−Me)) / (SA) (2)
P = ((S-Me) + (Go-Me)) / (SA) (3)
P = ((SB) + (Go-Gn)) / (SA) (4)
P = ((S-Pog) + (Go-Gn)) / (SA) (5)
P = ((S-Gn) + (Go-Gn)) / (SA) (6)
P = ((S-Me) + (Go-Gn)) / (SA) (7)
P = ((SB) + (Go-Pog)) / (SA) (8)
P = ((S-Pog) + (Go-Pog)) / (SA) (9)
P = ((S-Gn) + (Go-Pog)) / (SA) (10)
P = ((S-Me) + (Go-Pog)) / (SA) (11)
P = ((SB) + (Go-B)) / (SA) (12)
P = ((S-Pog) + (Go-B)) / (SA) (13)
P = ((S−Gn) + (Go−B)) / (S−A) (14)
P = ((S-Me) + (Go-B)) / (SA) (15)

The inventor measures distances (S−A), (S−X _i ), and (Go−X _j ) in cephalometric radiograms of a large number of patients, and P = ((S−X _i ) + ( As a result of calculating Go-X _j )) / ( _SA ),
P = ((S−X _i ) + (Go−X _j )) / (S−A) = 2. XYZ
(X, Y and Z are integers from 0 to 9)
I found out that In other words, P of the majority of patients is in the range of 2.000 ≦ P <3.000, and only the decimal part is different. However, for very few patients, P <2.000.

P itself may be used as an index for determining the necessity of jaw surgery, but it is easy to understand when expressed as an integer. For this reason, in the case of 2.000 ≦ P <3.000, typically, after calculating P, after rounding down the fourth decimal place of P, Q = (P− [P] ) × 1000. Since [P] means that the decimal part of P is rounded down, P- [P] means that the decimal part of P is extracted. Q = (P− [P]) × 1000 means that the fractional part thus extracted is multiplied by 1000. in this case,
P- [P] = 2. XYZ- [2. XYZ] = 2. XYZ-2 = 0. XYZ
It becomes. Therefore, Q = (P− [P]) × 1000 = XYZ, which is an integer of 0 to 999. As an example, when P = 2.512, Q = (P− [P]) × 1000 = (2.512− [2.512]) × 1000 = (2.512−2) × 1000 = 0.512 X1000 = 512.

  P- [P] or a numerical value XYZ obtained by multiplying it by 1000 can be considered as a numerical value for evaluating the ratio of the size of the mandible to the maxilla in the profile of the head.

  When the calculated P or Q is equal to or greater than a predetermined value, it is determined that, in principle, surgical correction of the jawbone based on mandibular cutting operation is necessary in orthodontic treatment. can do. If the calculated P or Q is less than the predetermined value or greater than or equal to the predetermined value, but is not significantly different from the predetermined value, a borderline case is assumed. In borderline cases, for example, the distance between S and N (S-N) and Wits analysis (when a perpendicular line is drawn from points A and B to the occlusal plane, A supplementary analysis is added according to the distance Wits). If there is a problem with the distance (S−N), specifically, for example, if the distance is shorter than the average value of (S−N) by 2 × standard deviation (2SD) or more, the result of Wits analysis should be 12 mm or more, for example. For example, it can be determined that surgical indication, in other words, jaw bone surgery is required. In the following, Q or the integer XYZ is referred to as an OPE index (operation index) as necessary.

On the other hand, in the case of P <2.000 (usually 1.000 ≦ P <2.000), typically, after calculating P, after rounding down the fourth decimal place of P, Q = (P − ([P] +1)) × 1000 is calculated. in this case,
P-([P] +1) = 1. XYZ-([1.XYZ] +1) = 1. XYZ-2
It becomes. Therefore, Q = (P − ([P] +1)) × 1000 = (1.XYZ−2) × 1000, which is an integer from −1000 to −1. As an example, if P = 1.912, Q = (P-([P] +1)) × 1000 = (1.912-([1.912] +1)) × 1000 = (1.9912-2) × 1000 = −0.088 × 1000 = −88.

The method for calculating the index for determining the necessity of jaw surgery can be easily executed using a computer having a predetermined program including the above-described calculation formulas for P and Q. This program can be stored in various computer-readable recording media such as a CD-ROM, or can be provided through an electric communication line such as the Internet. The computer as data necessary for the calculation, for example, a distance in the head X-ray standard photo (S-A), and inputs the (S-X _i) and (Go-X _j). Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, A, B, Go, Pog, Gn, and Me are measured from this image data, and the distance (S -A), (S-X _i ), and (Go-X _j ) may be obtained by calculation, and P and Q may be calculated by the above formula using these distances.

  The method for determining whether or not the jawbone surgery is necessary can be easily executed using a computer having a predetermined program including the above-described P and Q calculation formulas or P and Q determination formulas. This program can be stored in various computer-readable recording media such as a CD-ROM, or can be provided through an electric communication line such as the Internet. Data necessary for the calculation can be obtained in the same manner as the above-described method for calculating the index for determining the necessity of jaw surgery.

In the above invention, P = ((S−X _i ) + (Go−X _j )) / (S−A) is calculated and supplemented by the measured value of the distance (S−N) as necessary. Although analysis is performed, it is also effective to reflect the distance (S−N) in the calculation formula of P from the beginning. Specifically, instead of P = ((S−X _i ) + (Go−X _j )) / ( _SA ), for example, P ′ = ((S−X _i ) + (Go−X _j )) / ((SA) + (SN)).

When using P ', if necessary, further round off the decimal place of P'
Q ′ = (P ′ − [P ′]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P ′ <2.000)
Or Q ′ = (P ′ − ([P ′] + 1)) × 1000 ([] is a Gaussian symbol) (where P ′ <1.000)
Calculate Then, it is determined whether or not the jaw bone surgery is necessary by determining whether or not P ′ or Q ′ calculated in this way is greater than or equal to a predetermined value.

The method for calculating the index for determining whether or not the jaw surgery is necessary using P ′ or Q ′ can be easily executed using a computer having a predetermined program including the calculation formulas for P ′ and Q ′. This program can be stored in various computer-readable recording media such as a CD-ROM, or can be provided through an electric communication line such as the Internet. The computer as data necessary for the calculation, for example, a distance in the head X-ray standard photo (S-A), and inputs the (S-N), (S -X i) and (Go-X _j). Alternatively, for example, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, A, N, B, Go, Pog, Gn, and Me are measured from this image data. Distances (S-A), (S-N), (S-X _i ) and (Go-X _j ) are calculated, and P ′ and Q ′ are calculated by the above formula using these distances. You may make it do.

  In addition, the above-described method for determining the necessity of jaw surgery using P ′ and Q ′ can be easily performed using a computer having a predetermined program including the above-described calculation formulas for P ′ and Q ′ or the determination formulas for P ′ and Q ′. Can be executed. This program can be stored in various computer-readable recording media such as a CD-ROM, or can be provided through an electric communication line such as the Internet. Data necessary for the calculation can be obtained in the same manner as the above-described method for calculating the index for determining the necessity of jaw surgery.

In addition, this invention
The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except for the case of X _i = B and X _j = Me) It is a calculation method.

In addition, this invention
The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me)
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate
This is a method for determining the maxilla and mandible incongruity by determining whether or not the calculated P or Q is equal to or greater than a predetermined value.

In addition, this invention
The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (however, excluding the case where X _i = B and X _j = Me) Is the method.

In addition, this invention
The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me)
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate
This is a jaw deformity determination method in which it is determined whether or not the calculated P or Q is equal to or greater than a predetermined value.

  In the invention of the above-described method for calculating the maxillary and mandibular incongruity determination index, the method for determining the maxillary and mandibular incongruity determination method, the method for calculating the jaw deformity determination index, and the method for determining the jaw deformity What has been described in relation to the invention of the method for calculating the index for determining the necessity of jaw surgery in treatment and the method for determining the necessity of jaw surgery in orthodontic treatment are valid.

  Here, the method for calculating the maxillary and mandibular incompatibility index and the method for discriminating the maxilla and mandible are effective in determining maxillary bone incongruity in various treatments in which it is effective to perform treatment according to the maxillary and mandible incongruity. is there. This treatment includes both dental treatment and medical treatment. For example, dental treatment includes various treatments that are effective for treatment according to maxillary and mandibular incongruity. Specifically, in addition to orthodontic treatment, prosthetics such as dentures (dentures) are also included. included.

In addition, this invention
The distance (S-A) between S and A, the distance between Go and A (Go-A), the distance between S and B (S -B), using the distance between Go and B (Go-B) and the distance between Go and Me (Go-Me),
P = ((SB) + (Go−B) + (Go−Me)) / ((S−A) + (Go−A)) This is the calculation method.

In addition, this invention
The distance (S-A) between S and A, the distance between Go and A (Go-A), the distance between S and B (S -B), using the distance between Go and B (Go-B) and the distance between Go and Me (Go-Me),
P = ((S−B) + (Go−B) + (Go−Me)) / ((S−A) + (Go−A))
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P <2.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <1.000)
Calculate
This is a method for determining whether or not jaw surgery is necessary in orthodontic treatment, in which it is determined whether or not the calculated P or Q is equal to or greater than a predetermined value.

In addition, this invention
The distance (S-A) between S and A, the distance between Go and A (Go-A), the distance between S and B (S -B), using the distance between Go and B (Go-B) and the distance between Go and Me (Go-Me),
This is a method for calculating the maxillary and mandibular discord determination index for calculating P = ((SB) + (Go-B) + (Go-Me)) / ((SA) + (Go-A)).

In addition, this invention
The distance (S-A) between S and A, the distance between Go and A (Go-A), the distance between S and B (S -B), using the distance between Go and B (Go-B) and the distance between Go and Me (Go-Me),
P = ((S−B) + (Go−B) + (Go−Me)) / ((S−A) + (Go−A))
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P <2.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <1.000)
Calculate
This is a method for determining the maxilla and mandible incongruity by determining whether or not the calculated P or Q is equal to or greater than a predetermined value.

In addition, this invention
The distance (S-A) between S and A, the distance between Go and A (Go-A), the distance between S and B (S -B), using the distance between Go and B (Go-B) and the distance between Go and Me (Go-Me),
P = ((SB) + (Go−B) + (Go−Me)) / ((S−A) + (Go−A)) is a method for calculating a jaw deformity determination index.

In addition, this invention
The distance (S-A) between S and A, the distance between Go and A (Go-A), the distance between S and B (S -B), using the distance between Go and B (Go-B) and the distance between Go and Me (Go-Me),
P = ((S−B) + (Go−B) + (Go−Me)) / ((S−A) + (Go−A))
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P <2.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <1.000)
Calculate
This is a jaw deformity determination method in which it is determined whether or not the calculated P or Q is equal to or greater than a predetermined value.

P = ((SB) + (Go−B) + (Go−Me)) / ((SA) + (Go−A)) Necessity of jaw surgery in orthodontic treatment described above Judgment index calculation method, Jaw bone surgery necessity determination method in orthodontic treatment, upper and lower jaw bone inconsistency determination index calculation method, upper and lower jaw bone inconsistency determination method, jaw deformity determination index calculation method and jaw deformity determination method In the invention, as long as it is not contrary to the nature, what has been explained in relation to each of the above inventions using the formula of P = ((S−X _i ) + (Go−X _j )) / (S−A) To establish. In addition, the methods of these inventions can be easily executed using a computer having a predetermined program including the above-described P and Q calculation formulas or P and Q determination formulas.

By the way, in the method for determining whether or not the jaw surgery is necessary in orthodontic treatment, the method for determining the incompatibility of the maxilla and mandible and the method for determining jaw deformity, the degree of growth of the maxilla or mandible in order to make a more accurate and objective judgment. It is effective to consider This is because it can be a standard for determining the treatment method or a standard indicating the difficulty of the treatment. Specifically, whether or not you have maxillary prognathism, what pattern if you have maxillary prognathism, whether or not you have mandibular prognathism, and if you have mandibular prognathism It is also effective to check for such patterns. Specifically, maxillary protrusion is
1. Maxillary undergrowth (maxillary retro) + Mandibular undergrowth (maxillary retro)
2. 2. Maxilla normal + mandibular undergrowth Upper jaw overgrowth + lower jaw normal 4. It is classified into maxillary overgrowth + mandibular undergrowth. In addition, mandibular prognathism
1. Upper jaw undergrowth + lower jaw normal 2. 2. Maxilla undergrowth + mandible overgrowth Maxilla normal + mandible overgrowth4. It is classified into maxillary overgrowth + mandibular overgrowth. For example, severe maxillary undergrowth requires maxillary surgery in orthodontic treatment and jaw deformity treatment.

  As a result of diligent research, the present inventor has found an index that is effective for indicating the presence or absence of the above-described undergrowth or overgrowth of the upper jaw or undergrowth or overgrowth of the lower jaw, and has devised the following invention. It came to do.

That is, this invention
The distance between S and N (S−N), the distance between S and A (S−A), and the distance between Go and A (Go) measured by cephalometric radiography of the patient. This is a method for calculating the maxillary undergrowth / overgrowth determination index in which P is calculated by at least one of the following formulas (16) to (18) using a distance selected from the group consisting of -A).
P = ((S−A) + (Go−A)) / (S−N) (16)
P = (SA) / (SN) (17)
P = (S−A) − (S−N) (18)
When calculating P by equation (16), if necessary, further round off the fourth decimal place of P,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate

When calculating P using Equation (17), if necessary, further round off the fourth decimal place of P,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P <2.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <1.000)
Calculate

  In the following, Q or P calculated by Expression (18) is simply referred to as the maxillary retro index as necessary. Here, the lower the Q or the P calculated by the equation (18), the lower the upper jaw, and the higher the upper jaw, the higher the upper jaw.

In addition, this invention
The distance between S and N (S−N), the distance between S and A (S−A), and the distance between S and B (S) measured by cephalometric radiography of the patient -B), using a distance selected from the group consisting of a distance between Go and B (Go-B) and a distance between Go and Me (Go-Me), 23) A method of calculating a mandibular undergrowth / overgrowth determination index which calculates P by at least one of the equations (23).
P = ((S−B) + (Go−B) + (Go−Me)) / ((S−N) + (S−A))
(19)
P = ((S−B) + (Go−B)) / ((S−N) + (S−A)) (20)
P = ((S−B) + (Go−B)) / (S−N) (21)
P = (SB) / (SN) (22)
P = (S−B) − (S−N) (23)

When calculating P by the formula (19), (20) or (22), if necessary, further round off the decimal place of P 4 or less.
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P <2.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <1.000)
Calculate

When calculating P by the equation (21), further calculate P / 2 as necessary, and round down the fourth decimal place.
Q = (P / 2− [P / 2]) × 1000 ([] is a Gaussian symbol) (where 1.000 ≦ P / 2 <2.000)
Or Q = (P / 2 − ([P / 2] +1)) × 1000 ([] is a Gaussian symbol) (where P / 2 <1.000)
Calculate

  In the following, Q or P calculated by Expression (23) is simply referred to as a mandibular retro index as necessary. Here, the lower the Q or the P calculated by the equation (23), the lower the lower jaw tendency, and the higher the lower jaw tendency, the lower jaw overgrowth tendency.

  The ratio of P in formula (21) to P in formula (16), ie, [((S−B) + (Go−B)) / (S−N)] / [((S−A) + (Go− A)) / (S−N)] = ((S−B) + (Go−B)) / ((S−A) + (Go−A)) indicates whether or not the jaw bone surgery is necessary in orthodontic treatment. It can be used as an index, a maxillary maxillary bone discord determination index, or a jaw deformity determination index.

Therefore, this invention is
The distance between S and A (SA), the distance between S and B (SB), and the distance between Go and A (Go) measured by X-ray imaging of the patient's head -A) and the distance between Go and B (Go-B)
P = ((S−B) + (Go−B)) / ((S−A) + (Go−A))
This is a calculation method of an index for determining whether or not jaw surgery is necessary in orthodontic treatment.

In addition, this invention
The distance between S and A (SA), the distance between S and B (SB), and the distance between Go and A (Go) measured by X-ray imaging of the patient's head -A) and the distance between Go and B (Go-B)
P = ((S−B) + (Go−B)) / ((S−A) + (Go−A))
This is a method for calculating the index for determining the discord in the maxilla and mandible.

In addition, this invention
The distance between S and A (SA), the distance between S and B (SB), and the distance between Go and A (Go) measured by X-ray imaging of the patient's head -A) and the distance between Go and B (Go-B)
P = ((S−B) + (Go−B)) / ((S−A) + (Go−A))
This is a method for calculating a jaw deformity determination index.
When calculating P = ((S−B) + (Go−B)) / ((S−A) + (Go−A)), 2P is further calculated as necessary, and the decimal number is calculated. Rounded down to the fourth place
Q = (2P− [2P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ 2P <3.000)
Or Q = (2P − ([2P] +1)) × 1000 ([] is a Gaussian symbol) (where 2P <2.000)
Calculate

Upper jaw undergrowth / overgrowth judgment index calculation method and lower jaw undergrowth / overgrowth judgment index calculation method, or upper jaw undergrowth / overgrowth judgment method and lower jaw underage Jaw surgery required for orthodontic treatment using the formula of growth / overgrowth determination, P = ((SB) + (Go−B)) / ((SA − + (Go−A))) Method for calculating rejection index, method for determining index of inferior and mandibular bone, method for calculating index for determining jaw deformity, or method for determining whether or not jaw surgery is necessary based on the index calculated by using these calculation methods, In the determination method and the jaw deformity determination method, unless there is contrary to the nature thereof, each of the above inventions using the formula P = ((S−X _i ) + (Go−X _j )) / (S−A) The related explanation is valid. In addition, the methods of these inventions can be easily executed using a computer having a predetermined program including the above-described P and Q calculation formulas or P and Q determination formulas.

  According to the present invention, it is possible to easily calculate a jaw bone surgery necessity determination index that is an objective material for a dentist to determine whether or not a patient's jaw bone surgery is necessary in orthodontic treatment of the patient. In addition, by properly using the results of other inspection methods, it becomes possible for a dentist to make a more objective and accurate diagnosis easily and in a short time. Also, simply calculate the maxillary and mandibular incompatibility index, which is an objective material for dentists and doctors to determine the patient's maxilla and mandible inconsistency in dental treatment and medical treatment such as orthodontic treatment of the patient. Thus, by properly using the results of other inspection methods, it is possible for a dentist or doctor to easily perform an accurate diagnosis with higher objectivity and in a short time. In addition, it is possible to easily calculate a jaw deformity determination index that is an objective material for a dentist or doctor to determine whether a patient has jaw deformity or not. By using it together, it becomes possible for a dentist or doctor to easily perform a more accurate and accurate diagnosis in a short time. In addition, it is possible to easily calculate the maxillary undergrowth / overgrowth determination index, which is an objective material for dentists and doctors to judge the presence or degree of maxillary undergrowth or maxillary overgrowth of patients. By appropriately using the results of the inspection method, it is possible for a dentist or doctor to easily perform a more accurate and accurate diagnosis in a short time. In addition, a dentist or doctor can easily calculate a mandibular undergrowth / overgrowth determination index, which is an objective material for judging the presence or degree of mandibular undergrowth or mandible overgrowth. By appropriately using the results of the inspection method, it is possible for a dentist or doctor to easily perform a more accurate and accurate diagnosis in a short time.

It is a basic diagram for demonstrating the measurement point in a head X-ray standard photograph. It is a flowchart which shows the calculation method of the determination index of the necessity of jaw surgery in the orthodontic treatment according to the first embodiment of the present invention. 2 is a transcribing diagram created based on a cephalometric radiogram of patient 1. FIG. It is a transmission figure created based on the cephalometric radiograph after the mandibular cutting operation of the patient 1. FIG. 5 is a transmission diagram created based on a cephalometric radiogram of patient 2. FIG. 5 is a transmission diagram created based on a cephalometric radiogram after a mandibular cutting operation for patient 2; FIG. 4 is a transmission diagram created based on a cephalometric radiogram of patient 3. FIG. 6 is a transmission diagram created based on a cephalometric radiogram of patient 4. FIG. 6 is a transmission diagram created based on a cephalometric radiogram of a patient 5. FIG. 6 is a transmission diagram created based on a cephalometric radiogram of a patient 6. FIG. 5 is a transmission diagram created based on a cephalometric radiogram after a mandibular cutting operation for a patient 6; FIG. 5 is a transmission diagram created based on a cephalometric radiogram of a patient 7. FIG. 6 is a transmission diagram created based on a cephalometric radiogram of a patient 8. FIG. 6 is a transmission diagram created based on a cephalometric radiogram of a patient 9. FIG. 3 is a transmission diagram created based on a cephalometric radiogram of a patient 10. FIG. 3 is a transmission diagram created based on a cephalometric radiogram of a patient 11. FIG. 5 is a transmission diagram created based on a cephalometric radiogram of a patient 12. It is a flowchart which shows the jaw bone surgery necessity judgment method in the orthodontic treatment by the 2nd Embodiment of this invention. It is a flowchart which shows the calculation method of the jaw bone surgery necessity determination parameter | index in the orthodontic treatment by 7th Embodiment of this invention. It is a flowchart which shows the jaw bone surgery necessity judgment method in the orthodontic treatment by 8th Embodiment of this invention. Jaw bone surgery necessity determination index calculation method, jaw bone surgery necessity determination method, maxilla maxillary bone incompatibility determination index calculation method, maxilla maxillary incompatibility determination method, jaw deformity It is a basic diagram which shows the data processor used for implementation of the calculation method of a judgment index, the jaw deformity judgment method, the upper jaw undergrowth / overgrowth judgment index, or the lower jaw undergrowth / overgrowth judgment index.

Hereinafter, modes for carrying out the invention (hereinafter referred to as embodiments) will be described.
<1. First Embodiment>
In the first embodiment, a method of calculating an OPE index as an index for determining the necessity of jaw surgery in orthodontic treatment will be described.

  FIG. 2 shows a flowchart of this calculation method. A program according to this flowchart is created and executed by a computer.

Before performing this calculation, it performs head X-ray imaging of a patient for performing an orthodontic treatment, the distance (S-A) between the S and A, the distance between S and X _i (S-X _i ) and the distance between Go and X _j (Go−X _j ). These distances are measured using, for example, a pen tablet or a digitizer, and S, A, X _i (X ₁ = B, X ₂ = Pog, X ₃ = Gn, X ₄ = X on the cephalometric radiogram) This can be easily performed by inputting coordinate data of measurement points of Me) and Go. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and S, A, X _i (X ₁ = B, X ₂ = Pog, X ₃ = Gn, X ₄ = Me) and The coordinates of Go may be measured, and the distances (SA), (S-X _i ), and (Go-X _j ) may be obtained by calculation from the coordinates thus measured.

As shown in FIG. 2, in step S1, distance measured in the manner described above (S-A), and inputs the (S-X _i) and (Go-X _j).

In step S2, the inputted (S−A), (S−X _i ) and (Go−X _j ) are used to calculate P = ((S−X _i ) + (Go−X _j )) / (S−A). )
Calculate P according to

In step S3, the fourth decimal place or less of P obtained by calculation as described above is rounded down. When 2.000 ≦ P <3.000,
OPE index Q is calculated according to Q = (P− [P]) × 1000, and when P <2.000,
Q = (P − ([P] +1)) × 1000
The OPE index Q is calculated according to

  In step S4, the OPE index Q calculated as described above is output to a display, for example.

When the OPE index Q calculated in this way is a predetermined value (C ₁ ) or more, in principle, it can be diagnosed that a mandibular cutting operation is necessary in orthodontic treatment. Although OPE factor Q is C ₂ or C ₁ less than or C ₁ or more, in the cases of borderline that do not differ significantly from C _1, the distance added supplementary analysis by the (S-N) and Wits analysis. For example, when the distance (S−N) is shorter than the average value by 2SD or more, if the result of Wits analysis is 12 mm or more, it is determined that surgical adaptation, in other words, jaw surgery is necessary. C ₁ and C ₂ can be appropriately determined depending on which of the above formulas (1) to (15) is used. In general, C ₁ is, for example, 430 or more and 680 or less, and C ₂ is, for example, from C ₁ 30 to 100 inclusive is smaller.

When the OPE index Q is less than C _{2 and} 0 or more, it can be determined that the orthodontic treatment does not require surgery on the jawbone.

  A negative OPE index Q also means a significant retro (undergrowth) tendency of the mandible or an overgrowth tendency of the maxilla, and the surgical operation of the jaw bone needs to be considered.

  In general, in addition to the OPE index Q, the dentist finally determines whether or not the jaw bone surgery is necessary by using the results of other examinations such as a conventional cephalometric analysis centering on angle measurement.

[Example 1]
A cephalometric radiograph of patient 1 was taken. Imaging was performed at the central occlusal position or a position corresponding thereto (the same applies to Examples 2 to 12 below). FIG. 3 shows a transmission diagram created based on the cephalometric radiogram.

  From FIG. 3, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 3 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 67.0 mm and Wits = 17.0 mm.

Formula (1): P = (133.0 + 78.0) /78.0=2.7051, OPE index Q = 705
For example, when C ₁ = 585 is set, the OPE index Q is 705. Therefore, it can be determined that the patient 1 has jaw deformity and a mandibular bone cutting operation is necessary in orthodontic treatment. .

Formula (2): P = (134.0 + 78.0) /78.0=2.179, OPE index Q = 717
For example, when C ₁ = 600 is set, since the OPE index Q is 717, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (3): P = (132.0 + 78.0) /78.0=2.923, OPE index Q = 692
For example, when C ₁ = 585 is set, the OPE index Q is 692. Therefore, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (4): P = (123.0 + 81.0) /78.0=2.6153, OPE index Q = 615
For example, when C ₁ = 475 is set, the OPE index Q is 615. Therefore, it can be determined that the patient 1 has jaw deformity and an orthodontic treatment requires a mandibular cutting operation. .

Formula (5): P = (133.0 + 81.0) /78.0=2.7435, OPE index Q = 743
For example, when C ₁ = 630 is set, the OPE index Q is 743, so that it can be determined that the patient 1 has jaw deformity and a mandibular bone cutting operation is necessary in orthodontic treatment. .

Formula (6): P = (134.0 + 81.0) /78.0=2.564, OPE index Q = 756
For example, when C ₁ = 660 is set, since the OPE index Q is 756, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (7): P = (132.0 + 81.0) /78.0=2.307, OPE index Q = 730
For example, when C ₁ = 650 is set, since the OPE index Q is 730, it can be determined that the patient 1 has jaw deformity and a mandibular bone cutting operation is necessary in orthodontic treatment. .

Formula (8): P = (123.0 + 83.0) /78.0=2.410, OPE index Q = 641
For example, when C ₁ = 490 is set, the OPE index Q is 641. Therefore, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (9): P = (133.0 + 83.0) /78.0=2.7292, OPE index Q = 769
For example, when C ₁ = 645 is set, since the OPE index Q is 769, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (10): P = (134.0 + 83.0) /78.0=2.820, OPE index Q = 782
For example, when C ₁ = 675 is set, since the OPE index Q is 782, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (11): P = (132.0 + 83.0) /78.0=2.564, OPE index Q = 756
For example, when C ₁ = 665 is set, the OPE index Q is 756, so that it can be determined that the patient 1 has jaw deformity and mandibular bone cutting operation is necessary in orthodontic treatment. .

Formula (12): P = (123.0 + 78.0) /78.0=2.5769, OPE index Q = 576
For example, when C ₁ = 435 is set, since the OPE index Q is 576, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (13): P = (133.0 + 78.0) /78.0=2.050, OPE index Q = 705
For example, when C ₁ = 575 is set, the OPE index Q is 705. Therefore, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (14): P = (134.0 + 78.0) /78.0=2.179, OPE index Q = 717
For example, when C ₁ = 610 is set, since the OPE index Q is 717, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

Formula (15): P = (132.0 + 78.0) /78.0=2.923, OPE index Q = 692
For example, when C ₁ = 600 is set, the OPE index Q is 692. Therefore, it can be determined that the patient 1 has jaw deformity and a mandibular cutting operation is necessary in orthodontic treatment. .

  Therefore, the necessary cutting operation of the mandible was performed. After the cutting operation, a cephalometric radiogram of patient 1 was taken. FIG. 4 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 4, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 4 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 67.0 mm and Wits = 4.0 mm.

Formula (1): P = (125.0 + 73.0) /78.0=2.5384, OPE index Q = 538
Since OPE index Q is 538 for C ₁ = 585, it can be determined that patient 1 can perform orthodontic treatment as a result of mandibular cutting operation.

Formula (2): P = (127.0 + 73.0) /78.0=2.5641, OPE index Q = 564
Since the OPE index Q is 564 for C ₁ = 600, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (3): P = (125.0 + 73.0) /78.0=2.5384, OPE index Q = 538
Since OPE index Q is 538 for C ₁ = 585, it can be determined that patient 1 can perform orthodontic treatment as a result of mandibular cutting operation.

Formula (4): P = (111.0 + 77.0) /78.0=2.4102, OPE index Q = 410
Since the OPE index Q is 410 for C ₁ = 475, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (5): P = (125.0 + 77.0) /78.0=2.5897, OPE index Q = 589
Since the OPE index Q is 589 for C ₁ = 630, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (6): P = (127.0 + 77.0) /78.0=2.6153, OPE index Q = 615.
Since the OPE index Q is 615 for C ₁ = 660, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (7): P = (125.0 + 77.0) /78.0=2.5897, OPE index Q = 589
Since the OPE index Q is 589 for C ₁ = 650, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (8): P = (111.0 + 79.0) /78.0=2.4358, OPE index Q = 435
Since the OPE index Q is 435 for C ₁ = 490, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (9): P = (125.0 + 79.0) /78.0=2.6153, OPE index Q = 615
Since the OPE index Q is 615 for C ₁ = 645, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (10): P = (127.0 + 79.0) /78.0=2.410, OPE index Q = 641
Since the OPE index Q is 641 for C ₁ = 675, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (11): P = (125.0 + 79.0) /78.0=2.6153, OPE index Q = 615
Since OPE index Q is 615 for C ₁ = 665, it can be determined that patient 1 can perform orthodontic treatment as a result of mandibular cutting operation.

Formula (12): P = (111.0 + 73.0) /78.0=2.589, OPE index Q = 358
Since the OPE index Q is 358 for C ₁ = 435, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (13): P = (125.0 + 73.0) /78.0=2.5384, OPE index Q = 538
Since the OPE index Q is 538 for C ₁ = 575, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (14): P = (127.0 + 73.0) /78.0=2.5641, OPE index Q = 564
Since the OPE index Q is 564 for C ₁ = 610, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (15): P = (125.0 + 73.0) /78.0=2.5384, OPE index Q = 538
Since the OPE index Q is 538 for C ₁ = 600, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 2]
A cephalometric radiograph of patient 2 was taken. FIG. 5 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 5, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 5 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 69.0 mm and Wits = 16.0 mm.

Formula (1): P = (135.0 + 81.0) /83.0=2.604, OPE index Q = 602
For C ₁ = 585, the OPE index Q is 602, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (2): P = (138.0 + 81.0) /83.0=2.6385, OPE index Q = 638
For C ₁ = 600, the OPE index Q is 638, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (3): P = (137.0 + 81.0) /83.0=2.6265, OPE index Q = 626
For C ₁ = 585, the OPE index Q is 626, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cut operation. Judgment can be made.

Formula (4): P = (123.0 + 84.0) /83.0=2.4939, OPE index Q = 493
For C ₁ = 475, the OPE index Q is 493, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cut operation. Judgment can be made.

Formula (5): P = (135.0 + 84.0) /83.0=2.6385, OPE index Q = 638
For C ₁ = 630, the OPE index Q is 638, and Wits is as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (6): P = (138.0 + 84.0) /83.0=2.6746, OPE index Q = 674
For C ₁ = 660, the OPE index Q is 674, and Wits is as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (7): P = (137.0 + 84.0) /83.0=2.6626, OPE index Q = 662
For C ₁ = 650, the OPE index Q is 692 and Wits is also as large as 16.0 mm, so that patient 2 has jaw deformity and mandibular bone cutting is necessary for orthodontic treatment. Judgment can be made.

Formula (8): P = (123.0 + 85.0) /83.0=2.56060, OPE index Q = 506
For C ₁ = 490, the OPE index Q is 506, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (9): P = (135.0 + 85.0) /83.0=2.506, OPE index Q = 650
For C ₁ = 645, the OPE index Q is 650, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (10): P = (138.0 + 85.0) /83.0=2.867, OPE index Q = 686
For C ₁ = 675, the OPE index Q is 686, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (11): P = (137.0 + 85.0) /83.0=2.6746, OPE index Q = 674
For C ₁ = 665, the OPE index Q is 674 and Wits is also as large as 16.0 mm. Therefore, the patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (12): P = (123.0 + 80.0) /83.0=2.4457, OPE index Q = 445
For C ₁ = 435, the OPE index Q is 445, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (13): P = (135.0 + 80.0) /83.0=2.5903, OPE index Q = 590
For C ₁ = 575, since the OPE index Q is 590 and Wits is also as large as 16.0 mm, the patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (14): P = (138.0 + 80.0) /83.0=2.6265, OPE index Q = 626
For C ₁ = 610, the OPE index Q is 626, and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

Formula (15): P = (137.0 + 80.0) /83.0=2.6144, OPE index Q = 614
For C ₁ = 600, the OPE index Q is 614 and Wits is also as large as 16.0 mm. Therefore, patient 2 has jaw deformity, and the orthodontic treatment requires a mandibular cutting operation. Judgment can be made.

  Therefore, the necessary cutting operation of the mandible was performed. After the cutting operation, a cephalometric radiogram of patient 2 was taken. A transmission diagram created based on the cephalometric radiogram is shown in FIG.

  From FIG. 6, distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 6 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 69.0 mm and Wits = 6.0 mm.

Formula (1): P = (132.0 + 80.0) /83.0=2.5542, OPE index Q = 554
Since the OPE index Q is 554 for C ₁ = 585, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (2): P = (134.0 + 80.0) /83.0=2.5783, OPE index Q = 578
Since the OPE index Q is 578 for C ₁ = 600, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (3): P = (133.0 + 80.0) /83.0=2.5662, OPE index Q = 566
Since the OPE index Q is 566 for C ₁ = 585, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (4): P = (116.0 + 85.0) /83.0=2.4216, OPE index Q = 421
Since the OPE index Q is 421 for C ₁ = 475, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (5): P = (132.0 + 85.0) /83.0=2.6144, OPE index Q = 614
Since OPE index Q is 614 for C ₁ = 630, it can be determined that patient 2 can perform orthodontic treatment as a result of mandibular cutting operation.

Formula (6): P = (134.0 + 85.0) /83.0=2.6385, OPE index Q = 638
Since the OPE index Q is 638 for C ₁ = 660, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (7): P = (133.0 + 85.0) /83.0=2.6265, OPE index Q = 626
Since the OPE index Q is 626 for C ₁ = 650, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (8): P = (116.0 + 87.0) /83.0=2.4457, OPE index Q = 445
Since OPE index Q is 445 for C ₁ = 490, it can be determined that patient 2 can perform orthodontic treatment as a result of mandibular cutting operation.

Formula (9): P = (132.0 + 87.0) /83.0=2.6385, OPE index Q = 638
Since the OPE index Q is 638 with respect to C ₁ = 645, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (10): P = (134.0 + 87.0) /83.0=2.6626, OPE index Q = 662
Since the OPE index Q is 662 for C ₁ = 675, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (11): P = (133.0 + 87.0) /83.0=2.506, OPE index Q = 650
Since the OPE index Q is 650 for C ₁ = 665, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (12): P = (116.0 + 80.0) /83.0=2.3614, OPE index Q = 361
Since the OPE index Q is 361 for C ₁ = 435, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (13): P = (132.0 + 80.0) /83.0=2.5542, OPE index Q = 554
Since OPE index Q is 554 for C ₁ = 575, it can be determined that patient 2 can perform orthodontic treatment as a result of mandibular cutting operation.

Formula (14): P = (134.0 + 80.0) /83.0=2.5783, OPE index Q = 578
Since the OPE index Q is 578 for C ₁ = 610, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (15): P = (133.0 + 80.0) /83.0=2.5662, OPE index Q = 566
Since the OPE index Q is 566 for C ₁ = 600, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 3]
A cephalometric radiogram of patient 3 was taken. FIG. 7 shows a transmission diagram created based on the cephalometric radiogram.

  From FIG. 7, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 7 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 67.0 mm and Wits = 7.0 mm.

Formula (1): P = (143.0 + 78.0) /88.0=2.5113, OPE index Q = 511
Although it is a few skeletal class III cases, since OPE index Q is 511 with respect to C ₁ = 585, it is judged that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (2): P = (145.0 + 78.0) /88.0=2.5340, OPE index Q = 534
Although it is a few skeletal class III cases, since OPE index Q is 534 for C ₁ = 600, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (3): P = (143.0 + 78.0) /88.0=2.5113, OPE index Q = 511
Although it is a few skeletal class III cases, since OPE index Q is 511 with respect to C ₁ = 585, it is judged that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (4): P = (126.0 + 83.0) /88.0=2.3750, OPE index Q = 375
Although some skeletal class III cases have an OPE index Q of 375 with respect to C ₁ = 475, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (5): P = (143.0 + 83.0) /88.0=2.5681, OPE index Q = 568
Is a slight skeletal Class III cases, with respect to C ₁ = 630, since OPE factor Q is a 568, the patient 3 is determined that in performing the orthodontic treatment, is to perform the jawbone surgery is not required can do.

Formula (6): P = (145.0 + 83.0) /88.0=2.5909, OPE index Q = 590.
Is a slight skeletal Class III cases, with respect to C ₁ = 660, since OPE factor Q is a 590, the patient 3 is determined that in performing the orthodontic treatment, is to perform the jawbone surgery is not required can do.

Formula (7): P = (143.0 + 83.0) /88.0=2.5681, OPE index Q = 568
Is a slight skeletal Class III cases, with respect to C ₁ = 650, since OPE factor Q is a 568, the patient 3 is determined that in performing the orthodontic treatment, is to perform the jawbone surgery is not required can do.

Formula (8): P = (126.0 + 86.0) /88.0=2.4900, OPE index Q = 409
Although it is a few skeletal class III cases, since the OPE index Q is 409 for C ₁ = 490, it is judged that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (9): P = (143.0 + 86.0) /88.0=2.6022, OPE index Q = 602
Although it is a few skeletal class III cases, the OPE index Q is 602 for C ₁ = 645, so it is judged that patient 3 does not need to perform jaw surgery when performing orthodontic treatment can do.

Formula (10): P = (145.0 + 86.0) /88.0=2.6250, OPE index Q = 625
Although it is a few skeletal class III cases, since OPE index Q is 625 for C ₁ = 675, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (11): P = (143.0 + 86.0) /88.0=2.6022, OPE index Q = 602
Although it is a few skeletal class III cases, since OPE index Q is 602 with respect to C ₁ = 665, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (12): P = (126.0 + 80.0) /88.0=2.409, OPE index Q = 340.
Although it is a few skeletal class III cases, since OPE index Q is 340 for C ₁ = 435, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (13): P = (143.0 + 80.0) /88.0=2.5340, OPE index Q = 534
Although it is a few skeletal class III cases, since OPE index Q is 534 for C ₁ = 575, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

Formula (14): P = (145.0 + 80.0) /88.0=2.5568, OPE index Q = 556
Is a slight skeletal Class III cases, with respect to C ₁ = 610, since OPE factor Q is a 556, the patient 3 is determined that in performing the orthodontic treatment, is to perform the jawbone surgery is not required can do.

Formula (15): P = (143.0 + 80.0) /88.0=2.5340, OPE index Q = 534
Although it is a few skeletal class III cases, since OPE index Q is 534 for C ₁ = 600, it is determined that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

[Example 4]
A cephalometric radiogram of patient 4 was taken. A transmission diagram created based on the cephalometric radiogram is shown in FIG.

  From FIG. 8, distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 8 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 64.0 mm and Wits = 9.0 mm.

Formula (1): P = (137.0 + 77.0) /85.0=2.5176, OPE index Q = 517
Although it is a skeletal class III case, C ₁ = 585, while the OPE index Q is 517. Therefore, it is determined that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (2): P = (138.0 + 77.0) /85.0=2.5294, OPE index Q = 529
Is a skeletal Class III cases, with respect to C ₁ = 600, since OPE factor Q is a 529, the patient 4, when performing the orthodontic treatment, by performing the jawbone surgery be determined to be unnecessary Can do.

Formula (3): P = (135.0 + 77.0) /85.0=2.4944, OPE index Q = 494
Although it is a skeletal class III case, C ₁ = 585, OPE index Q is 494. Therefore, it is judged that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (4): P = (119.0 + 80.0) /85.0=2.411, OPE index Q = 341
Although it is a skeletal class III case, the OPE index Q is 341 for C ₁ = 475, so patient 4 judges that it is unnecessary to perform jaw surgery when performing orthodontic treatment Can do.

Formula (5): P = (137.0 + 80.0) /85.0=2.5529, OPE index Q = 552
Is a skeletal Class III cases, with respect to C ₁ = 630, since OPE factor Q is a 552, the patient 4, when performing the orthodontic treatment, by performing the jawbone surgery be determined to be unnecessary Can do.

Formula (6): P = (138.0 + 80.0) /85.0=2.5647, OPE index Q = 564
Although it is a skeletal class III case, the OPE index Q is 564 for C ₁ = 660. Therefore, it is determined that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (7): P = (135.0 + 80.0) /85.0=2.5294, OPE index Q = 529
Although it is a skeletal class III case, C ₁ = 650, and the OPE index Q is 529. Therefore, it is determined that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (8): P = (119.0 + 82.0) /85.0=2.647, OPE index Q = 364
Although it is a skeletal class III case, the OPE index Q is 364 for C ₁ = 490, so patient 4 judges that it is not necessary to perform jaw surgery when performing orthodontic treatment Can do.

Formula (9): P = (137.0 + 82.0) /85.0=2.5764, OPE index Q = 576
Although it is a skeletal class III case, C ₁ = 645, OPE index Q is 576. Therefore, it is judged that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (10): P = (138.0 + 82.0) /85.0=2.5882, OPE index Q = 588
Although it is a skeletal class III case, C ₁ = 675, and the OPE index Q is 588. Therefore, it is determined that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (11): P = (135.0 + 82.0) /85.0=2.5529, OPE index Q = 552
Is a skeletal Class III cases, with respect to C ₁ = 665, since OPE factor Q is a 552, the patient 4, when performing the orthodontic treatment, by performing the jawbone surgery be determined to be unnecessary Can do.

Formula (12): P = (119.0 + 76.0) /85.0=2.2941, OPE index Q = 294
Although it is a skeletal class III case, the OPE index Q is 294 for C ₁ = 435, so it is judged that patient 4 does not need to perform jaw surgery when performing orthodontic treatment Can do.

Formula (13): P = (137.0 + 76.0) /85.0=2.05058, OPE index Q = 505
Although it is a skeletal class III case, the OPE index Q is 505 for C ₁ = 575. Therefore, it is determined that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (14): P = (138.0 + 76.0) /85.0=2.5176, OPE index Q = 517
Although it is a skeletal class III case, C ₁ = 610, and the OPE index Q is 517. Therefore, it is determined that patient 4 does not need to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (15): P = (135.0 + 76.0) /85.0=2.4823, OPE index Q = 482
Is a skeletal Class III cases, with respect to C ₁ = 600, since OPE factor Q is a 482, the patient 4, when performing the orthodontic treatment, by performing the jawbone surgery be determined to be unnecessary Can do.

[Example 5]
A cephalometric radiogram of patient 5 was taken. FIG. 9 shows a transmission diagram created based on the cephalometric radiogram.

  From FIG. 9, distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 9 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 65.0 mm and Wits = 10.0 mm.

Formula (1): P = (123.0 + 70.0) /75.0=2.5733, OPE index Q = 573
Since C ₁ = 585, the OPE index Q is 573, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (2): P = (124.0 + 70.0) /75.0=2.5866, OPE index Q = 586
For C ₁ = 600, the OPE index Q is 586, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (3): P = (122.0 + 70.0) /75.0=2.5600, OPE index Q = 560
Since C ₁ = 585, the OPE index Q is 560, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (4): P = (109.0 + 76.0) /75.0=2.466, OPE index Q = 466
For C ₁ = 475, the OPE index Q is 466, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (5): P = (123.0 + 76.0) /75.0=2.533, OPE index Q = 653
For C ₁ = 630, the OPE index Q is 653, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (6): P = (124.0 + 76.0) /75.0=2.6666, OPE index Q = 666
Since C ₁ = 660, the OPE index Q is 666, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (7): P = (122.0 + 76.0) /75.0=2.6400, OPE index Q = 640
Since C ₁ = 650, the OPE index Q is 640, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (8): P = (109.0 + 77.0) /75.0=2.4800, OPE index Q = 480
Since the OPE index Q is 480 for C ₁ = 490, this is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (9): P = (123.0 + 77.0) /75.0=2.6666, OPE index Q = 666
Since C ₁ = 645, the OPE index Q is 666, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (10): P = (124.0 + 77.0) /75.0=2.6800, OPE index Q = 680
Since C ₁ = 675, the OPE index Q is 680, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (11): P = (122.0 + 77.0) /75.0=2.533, OPE index Q = 653
Since C ₁ = 665, the OPE index Q is 653, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (12): P = (109.0 + 73.0) /75.0=2.4266, OPE index Q = 426
Since C ₁ = 435, the OPE index Q is 426, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (13): P = (123.0 + 73.0) /75.0=2.6133, OPE index Q = 613
For C ₁ = 575, the OPE index Q is 613, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (14): P = (124.0 + 73.0) /75.0=2.6266, OPE index Q = 626
Since C ₁ = 610, the OPE index Q is 626, which is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

Formula (15): P = (122.0 + 73.0) /75.0=2.6000, OPE index Q = 600
Since the OPE index Q is 600 for C ₁ = 600, this is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but (SN) = 65.0 mm. Therefore, it is judged that it is not necessary to perform jaw surgery when performing orthodontic treatment. Can do.

[Example 6]
A cephalometric radiogram of patient 6 was taken. FIG. 10 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 10, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 10 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 68.0 mm and Wits = 12.0 mm.

Formula (1): P = (141.0 + 80.0) /87.0=2.5402, OPE index Q = 540
Since C ₁ = 585, the OPE index Q is 540, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (2): P = (143.0 + 80.0) /87.0=2.5632, OPE index Q = 563
For C ₁ = 600, the OPE index Q is 563, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (3): P = (142.0 + 80.0) /87.0=2.5517, OPE index Q = 551
Since C ₁ = 585, the OPE index Q is 551, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (4): P = (128.0 + 83.0) /87.0=2.4252, OPE index Q = 425
Since C ₁ = 475, the OPE index Q is 425, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (5): P = (141.0 + 83.0) /87.0=2.5747, OPE index Q = 574
For C ₁ = 630, the OPE index Q is 574, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (6): P = (143.0 + 83.0) /87.0=2.5977, OPE index Q = 597
For C ₁ = 660, the OPE index Q is 597, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (7): P = (142.0 + 83.0) /87.0=2.5862, OPE index Q = 586
For C ₁ = 650, the OPE index Q is 586, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (8): P = (128.0 + 84.0) /87.0=2.4367, OPE index Q = 436
For C ₁ = 490, the OPE index Q is 436, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (9): P = (141.0 + 84.0) /87.0=2.5862, OPE index Q = 586
For C ₁ = 645, the OPE index Q is 586, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (10): P = (143.0 + 84.0) /87.0=2.6091, OPE index Q = 609
Since C ₁ = 675, the OPE index Q is 609, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (11): P = (142.0 + 84.0) /87.0=2.5977, OPE index Q = 597
Since C ₁ = 665, the OPE index Q is 597, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (12): P = (128.0 + 80.0) /87.0=2.3908, OPE index Q = 390
For C ₁ = 435, the OPE index Q is 390, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (13): P = (141.0 + 80.0) /87.0=2.5402, OPE index Q = 540
Since C ₁ = 575, the OPE index Q is 540, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (14): P = (143.0 + 80.0) /87.0=2.5632, OPE index Q = 563
For C ₁ = 610, the OPE index Q is 563, which is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

Formula (15): P = (142.0 + 80.0) /87.0=2.5517, OPE index Q = 551
Since the OPE index Q is 551 for C ₁ = 600, this is a borderline case. Since Wits are 12.0 mm and larger than 10.0 mm and (S−N) = 68.0 mm, this is a skeletal class III case and can be determined to be jaw deformity. It can be determined that a cutting operation is necessary.

  Therefore, the necessary cutting operation of the mandible was performed. After the cutting operation, a cephalometric radiograph of patient 6 was taken. FIG. 11 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 11, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 11 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 68.0 mm and Wits = 5.0 mm.

Formula (1): P = (136.0 + 73.0) /87.0=2.4222, OPE index Q = 402
Since the OPE index Q is 402 for C ₁ = 585, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (2): P = (138.0 + 73.0) /87.0=2.4252, OPE index Q = 425
Since the OPE index Q is 425 for C ₁ = 600, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (3): P = (137.0 + 73.0) /87.0=2.4137, OPE index Q = 413
Since the OPE index Q is 413 for C ₁ = 585, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (4): P = (121.0 + 75.0) /87.0=2.2528, OPE index Q = 252
Since the OPE index Q is 252 for C ₁ = 475, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (5): P = (136.0 + 75.0) /87.0=2.4252, OPE index Q = 425
Since the OPE index Q is 425 for C ₁ = 630, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (6): P = (138.0 + 75.0) /87.0=2.482, OPE index Q = 448
Since the OPE index Q is 448 for C ₁ = 660, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (7): P = (137.0 + 75.0) /87.0=2.4367, OPE index Q = 436
Since the OPE index Q is 436 for C ₁ = 650, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (8): P = (121.0 + 77.0) /87.0=2.758, OPE index Q = 275
Since the OPE index Q is 275 for C ₁ = 490, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (9): P = (136.0 + 77.0) /87.0=2.482, OPE index Q = 448
Since the OPE index Q is 448 for C ₁ = 645, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (10): P = (138.0 + 77.0) /87.0=2.47212, OPE index Q = 471
Since the OPE index Q is 471 for C ₁ = 675, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (11): P = (137.0 + 77.0) /87.0=2.4597, OPE index Q = 459
Since the OPE index Q is 459 for C ₁ = 665, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (12): P = (121.0 + 73.0) /87.0=2.2298, OPE index Q = 229
Since the OPE index Q is 229 for C ₁ = 435, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (13): P = (136.0 + 73.0) /87.0=2.4222, OPE index Q = 402
Since the OPE index Q is 402 for C ₁ = 575, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (14): P = (138.0 + 73.0) /87.0=2.4252, OPE index Q = 425
Since the OPE index Q is 425 for C ₁ = 610, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

Formula (15): P = (137.0 + 73.0) /87.0=2.4137, OPE index Q = 413
Since the OPE index Q is 413 for C ₁ = 600, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 7]
A cephalometric radiogram of patient 7 was taken. FIG. 12 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 12, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 12 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 67.0 mm and Wits = 0 mm.

Formula (1): P = (123.0 + 69.0) /86.0=2.2325, OPE index Q = 232
For C ₁ = 585, the OPE index Q is 232 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (2): P = (124.0 + 69.0) /86.0=2.441, OPE index Q = 244
For C ₁ = 600, the OPE index Q is 244, and there is a tendency to retreat the mandible. However, patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (3): P = (123.0 + 69.0) /86.0=2.2325, OPE index Q = 232
For C ₁ = 585, the OPE index Q is 232 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (4): P = (111.0 + 73.0) /86.0=2.1395, OPE index Q = 139
For C ₁ = 475, the OPE index Q is 139 and there is a tendency to retreat the mandible, but the patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (5): P = (123.0 + 73.0) /86.0=2.2790, OPE index Q = 279
For C ₁ = 630, the OPE index Q is 279, and there is a tendency to retreat the mandible. However, patient 7 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged as adaptation.

Formula (6): P = (124.0 + 73.0) /86.0=2.2906, OPE index Q = 290
For C ₁ = 660, the OPE index Q is 290 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (7): P = (123.0 + 73.0) /86.0=2.2790, OPE index Q = 279
For C ₁ = 650, the OPE index Q is 279, and there is a tendency to retreat the mandible. However, patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (8): P = (111.0 + 74.0) /86.0=2.511, OPE index Q = 151
For C ₁ = 490, the OPE index Q is 151 and there is a tendency to retreat the mandible, but the patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (9): P = (123.0 + 74.0) /86.0=2.2906, OPE index Q = 290
For C ₁ = 645, the OPE index Q is 290 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (10): P = (124.0 + 74.0) /86.0=2.3033, OPE index Q = 302
For C ₁ = 675, the OPE index Q is 302 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (11): P = (123.0 + 74.0) /86.0=2.2906, OPE index Q = 290
For C ₁ = 665, the OPE index Q is 290, and there is a tendency to retreat the mandible, but the patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by tooth extraction treatment It can be judged as adaptation.

Formula (12): P = (111.0 + 73.0) /86.0=2.1395, OPE index Q = 139
For C ₁ = 435, the OPE index Q is 139, and there is a tendency to retreat the mandible. However, patient 7 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged as adaptation.

Formula (13): P = (123.0 + 73.0) /86.0=2.2790, OPE index Q = 279
For C ₁ = 575, the OPE index Q is 279 and there is a tendency to retreat the mandible, but the patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

Formula (14): P = (124.0 + 73.0) /86.0=2.2906, OPE index Q = 290
For C ₁ = 610, the OPE index Q is 290 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by tooth extraction treatment It can be judged as adaptation.

Formula (15): P = (123.0 + 73.0) /86.0=2.2790, OPE index Q = 279
For C ₁ = 600, the OPE index Q is 279, and there is a tendency to retreat the mandible. However, patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

[Example 8]
A cephalometric radiogram of patient 8 was taken. FIG. 13 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 13, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 13 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 68.0 mm and Wits = 11.0 mm.

Formula (1): P = (138.0 + 80.0) /90.0=2.4222, OPE index Q = 422
Since the OPE index Q is 422 for C ₁ = 585, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (2): P = (141.0 + 80.0) /90.0=2.4555, OPE index Q = 455
Since the OPE index Q is 455 for C ₁ = 600, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (3): P = (140.0 + 80.0) /90.0=2.4444, OPE index Q = 444
Since the OPE index Q is 444 for C ₁ = 585, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (4): P = (127.0 + 83.0) /90.0=2.3333, OPE index Q = 333
Since the OPE index Q is 333 for C ₁ = 475, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (5): P = (138.0 + 83.0) /90.0=2.4555, OPE index Q = 455
Since the OPE index Q is 455 for C ₁ = 630, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (6): P = (141.0 + 83.0) /90.0=2.4888, OPE index Q = 488
Since the OPE index Q is 488 for C ₁ = 660, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (7): P = (140.0 + 83.0) /90.0=2.477, OPE index Q = 477
Since the OPE index Q is 477 for C ₁ = 650, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (8): P = (127.0 + 84.0) /90.0=2.3444, OPE index Q = 344
Since the OPE index Q is 344 for C ₁ = 490, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (9): P = (138.0 + 84.0) /90.0=2.4666, OPE index Q = 466
Since the OPE index Q is 466 for C ₁ = 645, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (10): P = (141.0 + 84.0) /90.0=2.5000, OPE index Q = 500
Since the OPE index Q is 500 for C ₁ = 675, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (11): P = (140.0 + 84.0) /90.0=2.4888, OPE index Q = 488
Since the OPE index Q is 488 for C ₁ = 665, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (12): P = (127.0 + 80.0) /90.0=2.3000, OPE index Q = 300
Since the OPE index Q is 300 for C ₁ = 435, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (13): P = (138.0 + 80.0) /90.0=2.4222, OPE index Q = 422
Since the OPE index Q is 422 for C ₁ = 575, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (14): P = (141.0 + 80.0) /90.0=2.4555, OPE index Q = 455
Since the OPE index Q is 455 for C ₁ = 610, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (15): P = (140.0 + 80.0) /90.0=2.4444, OPE index Q = 444
Since the OPE index Q is 444 for C ₁ = 600, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

[Example 9]
A cephalometric radiogram of patient 9 was taken. FIG. 14 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 14, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 14 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 68.0 mm and Wits = 3.0 mm.

Formula (1): P = (116.0 + 73.0) /79.0=2.924, OPE index Q = 392
Since the OPE index Q is 392 for C ₁ = 585, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (2): P = (117.0 + 73.0) /79.0=2.050, OPE index Q = 405
Since the OPE index Q is 405 for C ₁ = 600, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (3): P = (116.0 + 73.0) /79.0=2.924, OPE index Q = 392
Since the OPE index Q is 392 for C ₁ = 585, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (4): P = (105.0 + 76.0) /79.0=2.911, OPE index Q = 291
Since the OPE index Q is 291 for C ₁ = 475, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (5): P = (116.0 + 76.0) /79.0=2.4303, OPE index Q = 430
Since the OPE index Q is 430 for C ₁ = 630, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (6): P = (117.0 + 76.0) /79.0=2.4430, OPE index Q = 443
Since the OPE index Q is 443 for C ₁ = 660, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (7): P = (116.0 + 76.0) /79.0=2.4303, OPE index Q = 430
Since the OPE index Q is 430 for C ₁ = 650, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (8): P = (105.0 + 78.0) /79.0=2.3164, OPE index Q = 316
Since the OPE index Q is 316 for C ₁ = 490, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (9): P = (116.0 + 78.0) /79.0=2.556, OPE index Q = 455
Since the OPE index Q is 455 for C ₁ = 645, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (10): P = (117.0 + 78.0) /79.0=2.6833, OPE index Q = 468
Since the OPE index Q is 468 for C ₁ = 675, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (11): P = (116.0 + 78.0) /79.0=2.556, OPE index Q = 455
Since the OPE index Q is 455 for C ₁ = 665, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (12): P = (105.0 + 74.0) /79.0=2.2658, OPE index Q = 265
Since the OPE index Q is 265 for C ₁ = 435, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (13): P = (116.0 + 74.0) /79.0=2.050, OPE index Q = 405
Since the OPE index Q is 405 for C ₁ = 575, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (14): P = (117.0 + 74.0) /79.0=2.4177, OPE index Q = 417
Since the OPE index Q is 417 for C ₁ = 610, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

Formula (15): P = (116.0 + 74.0) /79.0=2.050, OPE index Q = 405
Since the OPE index Q is 405 for C ₁ = 600, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

[Example 10]
A cephalometric radiogram of patient 10 was taken. FIG. 15 shows a transmission diagram created based on this cephalometric radiogram.

  From FIG. 15, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go- Gn) and (Go-Me) were measured. FIG. 15 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 69.0 mm and Wits = 3.0 mm.

Formula (1): P = (115.0 + 70.0) /81.0=2.2839, OPE index Q = 283
Although it is a non-skeletal case, since the OPE index Q is 283 with respect to C ₁ = 585, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (2): P = (117.0 + 70.0) /81.0=2.3086, OPE index Q = 308
Although it is a non-skeletal case, since the OPE index Q is 308 for C ₁ = 600, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (3): P = (116.0 + 70.0) /81.0=2.2962, OPE index Q = 296
Although it is a non-skeletal case, since the OPE index Q is 296 for C ₁ = 585, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (4): P = (103.0 + 74.0) /81.0=2.1851, OPE index Q = 185
Although it is a non-skeletal case, since the OPE index Q is 185 with respect to C ₁ = 475, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (5): P = (115.0 + 74.0) /81.0=2.3333, OPE index Q = 333
Although it is a non-skeletal case, since the OPE index Q is 333 for C ₁ = 630, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (6): P = (117.0 + 74.0) /81.0=2.3580, OPE index Q = 358
Although it is a non-skeletal case, since the OPE index Q is 358 with respect to C ₁ = 660, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (7): P = (116.0 + 74.0) /81.0=2.456, OPE index Q = 345
Although it is a non-skeletal case, since the OPE index Q is 345 for C ₁ = 650, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (8): P = (103.0 + 75.0) /81.0=2.1975, OPE index Q = 197
Although it is a non-skeletal case, since the OPE index Q is 197 with respect to C ₁ = 490, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment, and is based on non-extraction treatment It can be judged to be an orthodontic treatment indication.

Formula (9): P = (115.0 + 75.0) /81.0=2.456, OPE index Q = 345
Although it is a non-skeletal case, since the OPE index Q is 345 for C ₁ = 645, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (10): P = (117.0 + 75.0) /81.0=2.703, OPE index Q = 370
Although it is a non-skeletal case, since the OPE index Q is 370 for C ₁ = 675, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (11): P = (116.0 + 75.0) /81.0=2.3580, OPE index Q = 358
Although it is a non-skeletal case, since the OPE index Q is 358 for C ₁ = 665, the patient 10 does not need to perform jaw bone surgery when performing orthodontic treatment, and is based on non-extraction treatment It can be judged to be an orthodontic treatment indication.

Formula (12): P = (103.0 + 72.0) /81.0=2.1604, OPE index Q = 160
Although it is a non-skeletal case, since the OPE index Q is 160 for C ₁ = 435, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (13): P = (115.0 + 72.0) /81.0=2.3086, OPE index Q = 308
Although it is a non-skeletal case, since the OPE index Q is 308 for C ₁ = 575, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (14): P = (117.0 + 72.0) /81.0=2.3333, OPE index Q = 333
Although it is a non-skeletal case, since the OPE index Q is 333 with respect to C ₁ = 610, the patient 10 does not need to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

Formula (15): P = (116.0 + 72.0) /81.0=2.3209, OPE index Q = 320
Although it is a non-skeletal case, since the OPE index Q is 320 for C ₁ = 600, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

[Example 11]
A cephalometric radiogram of patient 11 was taken. FIG. 16 shows a transmission diagram created based on the cephalometric radiogram.

  From FIG. 16, distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go- Gn) and (Go-Me) were measured. FIG. 16 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 63.0 mm and Wits = 2.0 mm.

Formula (1): P = (122.0 + 68.0) /81.0=2.456, OPE index Q = 345
For C ₁ = 585, OPE index Q is 345, Wits is 2.0 mm, and this is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (2): P = (123.0 + 68.0) /81.0=2.3580, OPE index Q = 358
For C ₁ = 600, OPE index Q is 358, Wits is 2.0 mm, and it is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (3): P = (122.0 + 68.0) /81.0=2.456, OPE index Q = 345
For C ₁ = 585, OPE index Q is 345, Wits is 2.0 mm, and this is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (4): P = (108.0 + 72.0) /81.0=2.2222, OPE index Q = 222
For C ₁ = 475, the OPE index Q is 222 and Wits is 2.0 mm, which is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (5): P = (122.0 + 72.0) /81.0=2.3950, OPE index Q = 395
For C ₁ = 630, OPE index Q is 395, Wits is 2.0 mm, and this is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (6): P = (123.0 + 72.0) /81.0=2.4074, OPE index Q = 407
For C ₁ = 660, the OPE index Q is 407, Wits is 2.0 mm, and it is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (7): P = (122.0 + 72.0) /81.0=2.3950, OPE index Q = 395
For C ₁ = 650, OPE index Q is 395, Wits is 2.0 mm, and this is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (8): P = (108.0 + 73.0) /81.0=2.2345, OPE index Q = 234
For C ₁ = 490, OPE index Q is 234, Wits is 2.0 mm, which is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (9): P = (122.0 + 73.0) /81.0=2.4074, OPE index Q = 407
For C ₁ = 645, OPE index Q is 407, Wits is 2.0 mm, and this is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (10): P = (123.0 + 73.0) /81.0=2.4197, OPE index Q = 419
For C ₁ = 675, the OPE index Q is 419 and Wits is 2.0 mm, which is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (11): P = (122.0 + 73.0) /81.0=2.4074, OPE index Q = 407
For C ₁ = 665, the OPE index Q is 407 and Wits is 2.0 mm, which is a non-skeletal case, but patient 11 does not need to perform jawbone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (12): P = (108.0 + 69.0) /81.0=2.1851, OPE index Q = 185
For C ₁ = 435, OPE index Q is 185, Wits is 2.0 mm, and it is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (13): P = (122.0 + 69.0) /81.0=2.3580, OPE index Q = 358
For C ₁ = 575, OPE index Q is 358, Wits is 2.0 mm, and it is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (14): P = (123.0 + 69.0) /81.0=2.703, OPE index Q = 370
For C ₁ = 610, OPE index Q is 370, Wits is 2.0 mm, and this is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

Formula (15): P = (122.0 + 69.0) /81.0=2.3580, OPE index Q = 358
For C ₁ = 600, OPE index Q is 358, Wits is 2.0 mm, and it is a non-skeletal case, but patient 11 does not need to perform jaw surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

[Example 12]
A cephalometric radiogram of patient 12 was taken. A transmission diagram created based on the cephalometric radiogram is shown in FIG.

  From FIG. 17, the distances (SA), (SB), (S-Pog), (S-Gn), (S-Me), (Go-B), (Go-Pog), (Go-) Gn) and (Go-Me) were measured. FIG. 17 shows the measured distance. The results of calculating P by the equations (1) to (15) using these data are as follows. Note that (S−N) = 74.0 mm and Wits = 0 mm.

Formula (1): P = (125.0 + 65.0) /91.0=2.0879, OPE index Q = 87
For C ₁ = 585, the OPE index Q is 87. In general, in the case of Q <100, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (2): P = (127.0 + 65.0) /91.0=2.1098, OPE index Q = 109
For C ₁ = 600, the OPE index Q is 109. In general, in the case of Q <120, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (3): P = (126.0 + 65.0) /91.0=2.0989, OPE index Q = 98
For C ₁ = 585, the OPE index Q is 98. In general, in the case of Q <100, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (4): P = (115.0 + 68.0) /91.0=2.0109, OPE index Q = 10
For C ₁ = 475, the OPE index Q is 10. In general, in the case of Q <100, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (5): P = (125.0 + 68.0) /91.0=2.1208, OPE index Q = 120
For C ₁ = 630, the OPE index Q is 120. In general, in the case of Q <130, the need for orthognathic surgery is high when orthodontic treatment is performed, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (6): P = (127.0 + 68.0) /91.0=2.1428, OPE index Q = 142
For C ₁ = 660, the OPE index Q is 142. In general, in the case of Q <160, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (7): P = (126.0 + 68.0) /91.0=2.318, OPE index Q = 131
For C ₁ = 650, the OPE index Q is 131. In general, in the case of Q <150, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (8): P = (115.0 + 70.0) /91.0=2.0329, OPE index Q = 32
For C ₁ = 490, the OPE index Q is 32. In general, in the case of Q <100, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (9): P = (125.0 + 70.0) /91.0=2.1428, OPE index Q = 142
For C ₁ = 645, the OPE index Q is 142. In general, in the case of Q <150, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (10): P = (127.0 + 70.0) /91.0=2.1648, OPE index Q = 164
For C ₁ = 675, the OPE index Q is 164. In general, in the case of Q <180, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (11): P = (126.0 + 70.0) /91.0=2.1538, OPE index Q = 153
For C ₁ = 665, the OPE index Q is 153. In general, in the case of Q <150, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (12): P = (115.0 + 70.0) /91.0=2.0329, OPE index Q = 32
For C ₁ = 435, the OPE index Q is 32. In general, in the case of Q <100, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (13): P = (125.0 + 70.0) /91.0=2.1428, OPE index Q = 142
For C ₁ = 575, the OPE index Q is 142. In general, in the case of Q <160, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (14): P = (127.0 + 70.0) /91.0=2.1648, OPE index Q = 164
For C ₁ = 610, the OPE index Q is 164. In general, in the case of Q <200, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and the patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

Formula (15): P = (126.0 + 70.0) /91.0=2.1538, OPE index Q = 153
For C ₁ = 600, the OPE index Q is 153. In general, in the case of Q <190, it is necessary to perform jaw surgery when performing orthodontic treatment, but this is a case with a strong tendency to retrograde the mandible, and patient 12 performs orthodontic treatment, It can be determined that it is not necessary to perform jaw surgery.

As described above, according to the calculation method of the first jaw bone surgery necessity determination index according to the embodiment, the distance measured by the head X-ray (S-A), (S -X i) and ( Go-X _j ) can be used to calculate the OPE index Q. Based on this OPE index Q, it is possible to accurately determine whether or not the jaw bone surgery is necessary for orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist. Judgment can be made.

<2. Second Embodiment>
In the second embodiment, a method for determining whether or not jaw surgery is necessary in orthodontic treatment will be described.

  FIG. 18 shows a flowchart of the method for determining whether or not the jawbone surgery is necessary. A program according to this flowchart is created and executed by a computer.

Similar to the first embodiment, the distances (SA), (SX- _i ), and (Go- _Xj ) are measured before this jaw bone surgery necessity determination method is executed.

As shown in FIG. 18, in step S11, the measured distance as described above (S-A), and inputs the (S-X _i) and (Go-X _j).

In step S12, P = ((S−X _i ) + (Go−X _j )) / (S−A) from the inputted (S−A), (S−X _i ) and (Go−X _j ). )
Calculate P according to

In step S13, it is determined from P obtained by calculation as described above whether 2.000 ≦ P <3.000 or P <2.000. As a result of the determination, if 2.000 ≦ P <3.000, the fourth decimal place of P is rounded down,
Q = (P− [P]) × 1000
To calculate the OPE index Q, and if P <2.000,
Q = (P − ([P] +1)) × 1000
The OPE index Q is calculated according to

In step S14, it is determined whether or not the OPE index Q calculated in this way is C ₁ or more.

In step S15, when the OPE index Q is C ₁ or more, it is determined that a mandibular cutting operation is necessary in orthodontic treatment.

  In step S16, the determination result that mandibular cutting operation is necessary is output to a display, for example.

When it is determined in step S14 that Q is not C ₁ or more, it is determined in step S17 whether Q is C ₂ or more and less than C ₁ .

If the OPE index Q is greater than or equal to C _{2 and} less than C _1, it is determined in step S18 whether the distance (S−N) is shorter than the average value by 2SD or more and Wits is 12 mm or more. If applicable, it is determined in step S19 that a surgical operation on the jawbone is necessary.

  If it is determined that the jaw bone surgery is necessary, the determination result is output to, for example, a display in step S20.

  If it is determined in step S18 that the distance (S−N) is shorter than the average value by 2SD or more and Wits does not correspond to 12 mm or more, it is determined in step S21 that the jaw bone surgery is unnecessary.

  If it is determined that the jaw bone surgery is unnecessary, the determination result is output to, for example, a display in step S22.

If it is determined in step S17 that Q is not C ₂ or more and less than C ₁ , it is determined in step S23 whether Q is 0 or more and less than C ₂ .

If it is determined that the OPE index Q is 0 or more and less than C _2, it is determined in step S24 that no surgical operation on the jawbone is necessary.

  If it is determined that the jaw bone surgery is unnecessary, the determination result is output to a display, for example, in step S25.

When it is not determined that the OPE index Q is 0 or more and less than C ₂ , the OPE index Q is negative. In this case, in step S26, the dentist determines whether or not the jaw bone surgery is necessary, and in step S27 outputs the diagnosis result to, for example, a display.

According to the jaw bone surgery necessity determination method according to the second embodiment, the distances (SA), (SX- _i ), and (Go- _Xj ) measured by cephalometric radiography are used. Based on the calculated OPE index Q, whether or not the jaw bone surgery is necessary in orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist. Judgment can be made.

<3. Third Embodiment>
In the third embodiment, the maxilla and mandible discord determination index is calculated by the same method as the calculation method of the jaw bone surgery necessity determination index in the orthodontic treatment described in the first embodiment.

  According to the third embodiment, the maxilla and mandible discord determination index can be easily calculated. Based on this index for determining the inequalities of the maxilla and mandible, the maxilla and mandible can be used in dental treatment and medical treatment such as orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Discord can be accurately determined.

<4. Fourth Embodiment>
In the fourth embodiment, the method for determining the upper and lower jaw bones is performed in the same manner as the method for determining whether or not the jaw surgery is necessary in the orthodontic treatment described in the second embodiment.

  According to the fourth embodiment, the dentistry such as orthodontic treatment can be performed in a short time and with a certain objectivity without being influenced by the experience of the dentist or the doctor based on the index for determining the incompatibility of the maxilla and mandible. It is possible to accurately determine maxillary and mandibular incompatibility in medical treatment and medical treatment.

<5. Fifth Embodiment>
In the fifth embodiment, the jaw deformity determination index is calculated by the same method as the calculation method of the jaw bone surgery necessity determination index in the orthodontic treatment described in the first embodiment.

  According to the fifth embodiment, the jaw deformity determination index can be easily calculated. Based on this jaw deformity determination index, it is possible to accurately determine whether or not the subject has jaw deformity in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. it can.

<6. Sixth Embodiment>
In the sixth embodiment, the jaw deformity determination method is implemented by the same method as the method for determining whether or not the jaw bone surgery is necessary in the orthodontic treatment described in the second embodiment.

  According to the sixth embodiment, based on the jaw deformity determination index, whether or not the subject has jaw deformity in a short time and with a certain objectivity without being influenced by the experience of a dentist or a doctor. Can be accurately determined.

<7. Seventh Embodiment>
In the seventh embodiment, a method for calculating an OPE index as an index for determining the necessity of jaw surgery in orthodontic treatment will be described.

  FIG. 19 shows a flowchart of this calculation method. A program according to this flowchart is created and executed by a computer.

  Before performing this calculation, a cephalometric radiograph of the patient undergoing orthodontic treatment is performed and distances (SA), (Go-A), (SB), (Go-B) and (Go) -Me) is measured. These distances can be easily measured by inputting coordinate data of S, A, B, Go, and Me measurement points on a cephalometric radiogram using, for example, a pen tablet or digitizer. it can. Alternatively, image data obtained by cephalometric radiography is taken into a computer, the coordinates of S, A, B, Go and Me are measured from this image data, and the distance (SA) from the coordinates thus measured, (Go-A), (SB), (Go-B), and (Go-Me) may be obtained by calculation.

  As shown in FIG. 19, in step S31, the distances (SA), (Go-A), (SB), (Go-B), and (Go-Me) measured as described above are obtained. input.

In step S32, P = ((SB) + (Go−) from the inputted (SA), (Go−A), (SB), (Go−B) and (Go−Me). B) + (Go-Me)) / ((SA) + (Go-A))
(24)
Calculate P according to

In step S33, the fourth decimal place or less of P obtained by calculation as described above is rounded down. When 1.000 ≦ P <2.000,
Calculate the OPE index Q according to Q = (P− [P]) × 1000, and if P <1.000,
Q = (P − ([P] +1)) × 1000
The OPE index Q is calculated according to

  In step S34, the OPE index Q calculated as described above is output to a display, for example.

When the OPE index Q calculated in this way is C ₃ or more, it can be diagnosed that a mandibular cutting operation is necessary in orthodontic treatment. For borderline cases where the OPE index Q is C ₄ or more and less than C ₃ , supplementary analysis is added by Wits analysis. If the result of Wits analysis is 12 mm or more, it is judged that surgical indication, in other words, jaw bone surgery is necessary. C ₃ and C ₄ can be determined as appropriate.

When the OPE index Q is less than C _{4 and} 0 or more, it can be diagnosed that jaw surgery is unnecessary in orthodontic treatment.

  A negative OPE index Q also means a significant retro tendency of the mandible or an overgrowth tendency of the maxilla, and jaw surgery should be considered.

  In general, in addition to the OPE index Q, the dentist finally determines whether or not the jaw bone surgery is necessary by using the results of other examinations such as a conventional cephalometric analysis centering on angle measurement.

[Example 13]
From FIG. 3 which shows the transmission drawing produced based on the cephalometric radiogram of the patient 1 image | photographed in Example 1, distance (SA), (Go-A), (SB), (Go). -B) and (Go-Me) were measured. As a result, (SA) = 78.0 mm, (Go−A) = 77.0 mm, (SB) = 123.0 mm, (Go−B) = 78.0 mm, (Go−Me) = 78 0.0 mm. When P was calculated using these data, it was (123.0 + 78.0 + 78.0) / (78.0 + 77.0) = 1.8000. Therefore, the OPE index Q is 800.

For example, when C ₃ = 740 is set, since the OPE index Q is 800, the patient 1 can determine that a mandibular cutting operation is necessary in orthodontic treatment.

  Therefore, the necessary cutting operation of the mandible was performed. From FIG. 4 which shows the transmission figure of the head X-ray standard photograph after the mandibular cutting operation of the patient 1 imaged in Example 1, distances (SA), (Go-A), (SB), (Go-B) and (Go-Me) were measured. As a result, (SA) = 78.0 mm, (Go−A) = 79.0 mm, (SB) = 111.0 mm, (Go−B) = 73.0 mm, (Go−Me) = 73 0.0 mm. When P was calculated using these data, it was (111.0 + 73.0 + 73.0) / (78.0 + 79.0) = 1.6369. Therefore, the OPE index Q is 636.

Since the OPE index Q is 636 for C ₃ = 740, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 14]
From FIG. 5, which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2, the distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 83.0 mm, (Go−A) = 78.0 mm, (SB) = 123.0 mm, (Go−B) = 80.0 mm, (Go−Me) = 81 0.0 mm. When P was calculated using these data, it was (123.0 + 80.0 + 81.0) / (83.0 + 78.0) = 1.7639. Therefore, the OPE index Q is 763.

Since the OPE index Q is 763 for C ₃ = 740, it can be determined that the patient 2 needs a mandibular cutting operation.

  Therefore, the necessary cutting operation of the mandible was performed. From FIG. 6 which shows the transillumination created based on the cephalometric radiogram after the mandibular cutting operation of the patient 2, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−A) = 83.0 mm, (Go−A) = 83.0 mm, (S−B) = 116.0 mm, (Go−B) = 80.0 mm, (Go−Me) = 80 0.0 mm. When P was calculated using these data, it was (116.0 + 80.0 + 80.0) / (83.0 + 83.0) = 1.626. Therefore, the OPE index Q is 662.

Since OPE index Q is 662 for C ₃ = 740, it can be determined that patient 2 can perform orthodontic treatment as a result of mandibular cutting operation.

[Example 15]
From FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 88.0 mm, (Go−A) = 85.0 mm, (SB) = 12.6 mm, (Go−B) = 80.0 mm, (Go−Me) = 78 0.0 mm. When P was calculated using these data, it was (126.0 + 80.0 + 78.0) / (88.0 + 85.0) = 1.6416. Therefore, the OPE index Q is 641.

Although it is a few skeletal class III cases, OPE index Q is 641 for C ₃ = 740, so it is judged that patient 3 does not need to perform jaw surgery when performing orthodontic treatment can do.

[Example 16]
From FIG. 8 which shows a transmission diagram created based on a cephalometric radiogram of the patient 4 taken in Example 4, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 85.0 mm, (Go-A) = 78.0 mm, (SB) = 119.0 mm, (Go-B) = 76.0 mm, (Go-Me) = 77 0.0 mm. When P was calculated using these data, it was (119.0 + 76.0 + 77.0) / (85.0 + 78.0) = 1.6687. Therefore, the OPE index Q is 668.

Although it is a skeletal class III case, C ₃ = 740, while the OPE index Q is 668, it is judged that patient 4 does not need to perform jaw surgery when performing orthodontic treatment Can do.

[Example 17]
From FIG. 9, which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 75.0 mm, (Go−A) = 74.0 mm, (SB) = 109.0 mm, (Go−B) = 73.0 mm, (Go−Me) = 70 0.0 mm. When P was calculated using these data, it was (109.0 + 73.0 + 70.0) / (75.0 + 74.0) = 1.6912. Therefore, the OPE index Q is 691.

Since the OPE index Q is 691 for C ₃ = 740, this is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but it is 12 mm or less and (SN) = 65.0 mm, so it is not necessary to perform jaw surgery when performing orthodontic treatment Can be determined.

[Example 18]
From FIG. 10 which shows the transmission drawing created based on the cephalometric radiogram of the patient 6 photographed in Example 6, the distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 87.0 mm, (Go−A) = 79.0 mm, (SB) = 12.8 mm, (Go−B) = 80.0 mm, (Go−Me) = 80 0.0 mm. When P was calculated using these data, it was (128.0 + 80.0 + 80.0) / (87.0 + 79.0) = 1.7349. Therefore, the OPE index Q is 734.

For C ₃ = 740, the OPE index Q is 734, which is a borderline case. Since Wits is 12.0 mm and (S−N) = 68.0 mm, it is a skeletal class III case and can be judged as jaw deformity, and mandibular cutting operation is necessary. It can be judged that there is.

  Therefore, the necessary cutting operation of the mandible was performed. From FIG. 11 which shows the transillumination created based on the cephalometric radiograph after the mandibular cutting operation of the patient 6, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 87.0 mm, (Go−A) = 77.0 mm, (SB) = 121.0 mm, (Go−B) = 73.0 mm, (Go−Me) = 73 0.0 mm. When P was calculated using these data, it was (121.0 + 73.0 + 73.0) / (87.0 + 77.0) = 1.6280. Therefore, the OPE index Q is 628.

Since the OPE index Q is 628 for C ₃ = 740, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 19]
From FIG. 12, which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 86.0 mm, (Go-A) = 86.0 mm, (SB) = 111.0 mm, (Go-B) = 73.0 mm, (Go-Me) = 69 0.0 mm. When P was calculated using these data, it was (111.0 + 73.0 + 69.0) / (86.0 + 86.0) = 1.4709. Therefore, the OPE index Q is 470.

For C ₃ = 740, the OPE index Q is 470 and there is a tendency to retreat the mandible, but patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by tooth extraction treatment It can be judged as adaptation.

[Example 20]
From FIG. 13 which shows the transmission drawing created based on the cephalometric radiogram of the patient 8 taken in Example 8, the distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 90.0 mm, (Go−A) = 79.0 mm, (SB) = 127.0 mm, (Go−B) = 80.0 mm, (Go−Me) = 80 0.0 mm. When P was calculated using these data, it was (127.0 + 80.0 + 80.0) / (90.0 + 79.0) = 1.6982. Therefore, the OPE index Q is 698.

Since the OPE index Q is 698 for C ₃ = 740, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

[Example 21]
From FIG. 14 which shows the transmission figure created based on the cephalometric radiogram of the patient 9 photographed in Example 9, the distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (SA) = 79.0 mm, (Go−A) = 81.0 mm, (SB) = 105.0 mm, (Go−B) = 74.0 mm, (Go−Me) = 73 0.0 mm. When P was calculated using these data, it was (105.0 + 74.0 + 73.0) / (79.0 + 81.0) = 1.575. Therefore, the OPE index Q is 575.

Since the OPE index Q is 575 for C ₃ = 740, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

[Example 22]
From FIG. 15, which shows a transmission diagram created based on a cephalometric radiogram of the patient 10 taken in Example 10, distances (SA), (Go-A), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−A) = 81.0 mm, (Go−A) = 83.0 mm, (S−B) = 103.0 mm, (Go−B) = 72.0 mm, (Go−Me) = 70 0.0 mm. When P was calculated using these data, it was (103.0 + 72.0 + 70.0) / (81.0 + 83.0) = 1.4939. Therefore, the OPE index Q is 493.

Although it is a non-skeletal case, since the OPE index Q is 493 for C ₃ = 740, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

[Example 23]
From FIG. 16 which shows the transmission figure produced based on the head X-ray standard photograph of the patient 11 image | photographed in Example 11, distance (SA), (Go-A), (SB), (Go). -B) and (Go-Me) were measured. As a result, (SA) = 81.0 mm, (Go−A) = 78.0 mm, (SB) = 108.0 mm, (Go−B) = 69.0 mm, (Go−Me) = 68 0.0 mm. When P was calculated using these data, it was (108.0 + 69.0 + 68.0) / (81.0 + 78.0) = 1.5408. Therefore, the OPE index Q is 540.

For C ₃ = 740, OPE index Q is 540, Wits is 2.0 mm, which is a non-skeletal case, but patient 11 does not need to perform jawbone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

[Example 24]
From FIG. 17 which shows the transmission drawing produced based on the cephalometric radiogram of the patient 12 image | photographed in Example 12, distance (SA), (Go-A), (SB), (Go). -B) and (Go-Me) were measured. As a result, (S−A) = 91.0 mm, (Go−A) = 87.0 mm, (SB) = 115.0 mm, (Go−B) = 70.0 mm, (Go−Me) = 65 0.0 mm. When P was calculated using these data, it was (115.0 + 70.0 + 65.0) / (91.0 + 87.0) = 1.4444. Therefore, the OPE index Q is 404.

Since the OPE index Q is 404 for C ₃ = 740, this is a borderline case. The patient 12 is a case with a strong mandibular retro tendency, and it can be determined that it is not necessary to perform jaw bone surgery when performing orthodontic treatment.

  As described above, according to the calculation method of the jaw bone surgery necessity determination index according to the seventh embodiment, the distances (SA), (Go-A), (S) measured by cephalometric radiography. -B), (Go-B) and (Go-Me) can be used to calculate the OPE index Q. Based on this OPE index Q, it is possible to accurately determine whether or not the jaw bone surgery is necessary for orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist. Can be diagnosed.

<8. Eighth Embodiment>
In the eighth embodiment, a method for determining the necessity of jaw surgery in orthodontic treatment will be described.

  FIG. 20 shows a flowchart of the method for determining whether or not jaw surgery is necessary. A program according to this flowchart is created and executed by a computer.

  Similarly to the eighth embodiment, before executing this jaw bone surgery necessity determination method, the distances (SA), (Go-A), (SB), (Go-B), and (Go) -Me) is measured.

  As shown in FIG. 20, in step S41, the distances (SA), (Go-A), (SB), (Go-B), and (Go-Me) measured as described above are calculated. input.

In step S42, P = ((S−B) + (Go−) from the inputted (S−A), (Go−A), (S−B), (Go−B) and (Go−Me)]. B) + (Go-Me)) / ((SA) + (Go-A))
Calculate P according to

In step S43, it is determined from P obtained by calculation as described above whether 1.000 ≦ P <2.000 or P <1.000. As a result of the determination, if 1.000 ≦ P <2.000, the fourth decimal place of P is rounded down,
Q = (P− [P]) × 1000
To calculate the OPE index Q according to:
Q = (P − ([P] +1)) × 1000
The OPE index Q is calculated according to

In step S44, it is determined whether or not the OPE index Q calculated in this way is C ₃ or more.

In step S45, when the OPE index Q is C ₃ or more, it is determined that a mandibular cutting operation is necessary in the orthodontic treatment.

  In step S46, a determination result that mandibular cutting operation is necessary is output to a display, for example.

If it is determined in step S44 that Q is not C ₃ or more, it is determined in step S47 whether Q is C ₄ or more and less than C ₃ .

In step S48, the when OPE factor Q is less than C ₄ or C ₃ are, Wits is equal to or 12mm more. If applicable, it is determined in step S49 that the jawbone surgery is necessary.

  If it is determined that the jaw bone surgery is necessary, the determination result is output to, for example, a display in step S50.

  If it is determined in step S48 that Wits does not correspond to 12 mm or more, it is determined in step S41 that the surgical operation of the jawbone is unnecessary.

  If it is determined that the jaw bone surgery is unnecessary, the determination result is output to, for example, a display in step S52.

If it is determined in step S47 that Q is not C ₄ or more and less than C ₃ , it is determined in step S53 whether Q is 0 or more and less than C ₄ .

If it is determined that the OPE index Q is greater than or equal to 0 and less than C _4, it is determined in step S54 that no surgical operation on the jawbone is necessary.

  If it is determined that the jaw bone surgery is not necessary, the determination result is output to, for example, a display in step S55.

When it is not determined that the OPE index Q is 0 or more and less than C ₄ , the OPE index Q is negative. In this case, in step S56, the dentist determines whether or not the jaw bone surgery is necessary, and outputs the determination result to, for example, a display in step S57.

  According to the jaw bone surgery necessity determination method according to the eighth embodiment, distances (SA), (Go-A), (SB), (Go-B) measured by cephalometric radiography. ) And (Go-Me) based on the OPE index Q, the jaw bone surgery in orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist, etc. It is possible to accurately determine whether or not is necessary.

<9. Ninth Embodiment>
In the ninth embodiment, the maxillary and mandible discord determination index is calculated by the same method as the calculation method for determining the necessity of jaw surgery in the orthodontic treatment described in the seventh embodiment.

  According to the ninth embodiment, the maxilla and mandible discord determination index can be easily calculated. Based on this index for determining the inequalities of the maxilla and mandible, the maxilla and mandible can be used in dental treatment and medical treatment such as orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Discord can be accurately determined.

<10. Tenth Embodiment>
In the tenth embodiment, the method for determining the upper and lower jaw bone inconsistencies is performed by the same method as the method for determining the necessity of jaw surgery in the orthodontic treatment described in the eighth embodiment.

  According to the tenth embodiment, based on the maxillary and mandibular incompatibility determination index, the dental treatment such as orthodontic treatment is performed in a short time and with a certain objectivity without being influenced by the experience of the dentist or the doctor. It is possible to accurately determine maxillary and mandibular incompatibility in medical treatment and medical treatment.

<11. Eleventh Embodiment>
In the eleventh embodiment, the jaw deformity determination index is calculated by the same method as the calculation method of the jaw bone surgery necessity determination index in the orthodontic treatment described in the seventh embodiment.

  According to the eleventh embodiment, the jaw deformity determination index can be easily calculated. Based on this jaw deformity determination index, it is possible to accurately determine whether or not the subject has jaw deformity in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. it can.

<12. Twelfth Embodiment>
In the twelfth embodiment, the jaw deformity determination method is performed by the same method as the method for determining the necessity of jaw surgery in the orthodontic treatment described in the eighth embodiment.

  According to the twelfth embodiment, whether or not the subject has jaw deformity in a short time and with a certain objectivity without being influenced by the experience of the dentist or doctor based on the jaw deformity determination index. Can be accurately determined.

<13. Thirteenth Embodiment>
In the thirteenth embodiment, a method for calculating the maxillary retro index will be described.

  Before performing this calculation, a cephalometric radiograph of the patient is performed and distances (SN), (SA), and (Go-A) are measured. These distances can be easily measured by inputting coordinate data of S, N, A, and Go measurement points on a cephalometric radiogram using, for example, a pen tablet or a digitizer. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, A, and Go are measured from this image data, and the distance (SN), (S -A) and (Go-A) may be obtained by calculation.

  First, in step S61, the distances (SN), (SA), and (Go-A) measured as described above are input.

In step S62, from the inputted (S−N), (S−A) and (Go−A), P = ((S−A) + (Go−A)) / (S−N) (16)
Calculate P according to

In step S63, the fourth decimal place of P obtained by calculation as described above is rounded down. If 2.000 ≦ P <3.000,
Calculate maxillary retro index Q according to Q = (P− [P]) × 1000, and if P <2.000,
Q = (P − ([P] +1)) × 1000
The maxillary retro index Q is calculated according to

  In step S64, the maxillary retro index Q calculated as described above is output to a display, for example.

  The presence or degree of maxillary undergrowth or maxillary overgrowth can be objectively determined by the thus calculated maxillary retro index Q.

[Example 25]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 3 which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1. . As a result, (S−N) = 67.0 mm, (S−A) = 78.0 mm, and (Go−A) = 77.0 mm. When P was calculated using these data, it was (78.0 + 77.0) /67.0=2.3134. Therefore, the maxillary retro index Q is 313.

  From FIG. 4 which shows a transparent view of the cephalometric radiograph after the mandibular cutting operation of the patient 1 taken in Example 1, the distances (SN), (SA), and (Go-A) are shown. Measured. As a result, (S−N) = 67.0 mm, (S−A) = 78.0 mm, and (Go−A) = 79.0 mm. It was (78.0 + 79.0) /67.0=2.432 when P was calculated using these data. Therefore, the maxillary retro index Q is 343.

[Example 26]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 5 which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2. . As a result, (S−N) = 69.0 mm, (S−A) = 83.0 mm, and (Go−A) = 78.0 mm. When P was calculated using these data, it was (83.0 + 78.0) /69.0=2.333. Therefore, the maxillary retro index Q is 333.

  The distances (SN), (SA), and (Go-A) were measured from FIG. 6 which shows a transmission diagram created based on a cephalometric radiograph after mandibular cutting operation of the patient 2. . As a result, (S−N) = 69.0 mm, (S−A) = 83.0 mm, and (Go−A) = 83.0 mm. When P was calculated using these data, it was (83.0 + 83.0) /69.0=2.4057. Therefore, the maxillary retro index Q is 405.

[Example 27]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3. . As a result, (S−N) = 67.0 mm, (S−A) = 88.0 mm, and (Go−A) = 85.0 mm. When P was calculated using these data, it was (88.0 + 85.0) /67.0=2.5820. Therefore, the maxillary retro index Q is 582.

[Example 28]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 8 which shows a transparent drawing created based on the cephalometric radiogram of the patient 4 taken in Example 4. . As a result, (S−N) = 64.0 mm, (S−A) = 85.0 mm, and (Go−A) = 78.0 mm. When P was calculated using these data, it was (85.0 + 78.0) /64.0=2.5468. Therefore, the maxillary retro index Q is 546.

[Example 29]
The distances (SN), (S-A), and (Go-A) were measured from FIG. 9 showing a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5. . As a result, (S−N) = 65.0 mm, (S−A) = 75.0 mm, and (Go−A) = 74.0 mm. When P was calculated using these data, it was (75.0 + 74.0) /65.0=2.2923. Therefore, the maxillary retro index Q is 292.

[Example 30]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 10, which shows a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6. . As a result, (S−N) = 68.0 mm, (S−A) = 87.0 mm, and (Go−A) = 79.0 mm. When P was calculated using these data, it was (87.0 + 79.0) /68.0=2.4411. Therefore, the maxillary retro index Q is 441.

  The distances (SN), (SA), and (Go-A) were measured from FIG. 11 showing a transmission diagram created based on the cephalometric radiograph after mandibular cutting operation of the patient 6. . As a result, (S−N) = 68.0 mm, (S−A) = 87.0 mm, and (Go−A) = 77.0 mm. When P was calculated using these data, it was (87.0 + 77.0) /68.0=2.4117. Therefore, the maxillary retro index Q is 411.

[Example 31]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 12, which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7. . As a result, (S−N) = 67.0 mm, (S−A) = 86.0 mm, and (Go−A) = 86.0 mm. When P was calculated using these data, it was (86.0 + 86.0) /67.0=2.5671. Therefore, the maxillary retro index Q is 567.

[Example 32]
The distances (SN), (S-A), and (Go-A) were measured from FIG. 13 showing a transmission diagram created based on the cephalometric radiogram of the patient 8 taken in Example 8. . As a result, (S−N) = 68.0 mm, (S−A) = 90.0 mm, and (Go−A) = 79.0 mm. When P was calculated using these data, it was (90.0 + 79.0) /68.0=2.4852. Therefore, the maxillary retro index Q is 485.

[Example 33]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 14 which shows a transmission diagram created based on the cephalometric radiogram of the patient 9 taken in Example 9. . As a result, (S−N) = 68.0 mm, (S−A) = 79.0 mm, and (Go−A) = 81.0 mm. When P was calculated using these data, it was (79.0 + 81.0) /68.0=2.529. Therefore, the maxillary retro index Q is 352.

[Example 34]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 15 which shows a transmission diagram created based on a cephalometric radiogram of the patient 10 taken in Example 10. . As a result, (S−N) = 69.0 mm, (S−A) = 81.0 mm, and (Go−A) = 83.0 mm. When P was calculated using these data, it was (81.0 + 83.0) /69.0=2.768. Therefore, the maxillary retro index Q is 376.

[Example 35]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 16 which shows a transmission diagram created based on the cephalometric radiogram of the patient 11 taken in Example 11. . As a result, (S−N) = 63.0 mm, (S−A) = 81.0 mm, and (Go−A) = 78.0 mm. When P was calculated using these data, it was (81.0 + 78.0) /63.0=2.5238. Therefore, the maxillary retro index Q is 523.

[Example 36]
The distances (S-N), (S-A), and (Go-A) were measured from FIG. 17 which shows a transmission diagram created based on the cephalometric radiogram of the patient 12 taken in Example 12. . As a result, (S−N) = 74.0 mm, (S−A) = 91.0 mm, and (Go−A) = 87.0 mm. When P was calculated using these data, it was (91.0 + 87.0) /74.0=2.4054. Therefore, the maxillary retro index Q is 405.

  As described above, according to the method for calculating the maxillary retro index according to the thirteenth embodiment, the distances (SN), (SA), and (Go-A) measured by cephalometric radiography. Can be used to calculate the maxillary retro index Q. Based on the maxillary retro index Q, the presence or degree of maxillary undergrowth or maxillary overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<14. Fourteenth Embodiment>
In the fourteenth embodiment, a method for calculating the maxillary retro index will be described.

  Before performing this calculation, a cephalometric radiograph of the patient is performed and the distances (SN) and (SA) are measured. The measurement of these distances can be easily performed by inputting coordinate data of S, N, and A measurement points on a cephalometric radiogram using, for example, a pen tablet or a digitizer. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, and A are measured from the image data, and the distances (SN) and (SA) are measured from the coordinates thus measured. ) May be obtained by calculation.

  First, in step S71, the distances (SN) and (SA) measured as described above are input.

In step S72, from the input (S−N) and (S−A), P = (S−A) / (S−N) (17)
Calculate P according to

In step S73, the fourth decimal place of P obtained by calculation as described above is rounded down. When 1.000 ≦ P <2.000,
Calculate maxillary retro index Q according to Q = (P− [P]) × 1000, and if P <1.000,
Q = (P − ([P] +1)) × 1000
The maxillary retro index Q is calculated according to

  In step S74, the maxillary retro index Q calculated as described above is output to a display, for example.

  The presence or degree of maxillary undergrowth or maxillary overgrowth can be objectively determined by the thus calculated maxillary retro index Q.

[Example 37]
The distances (S−N) and (S−A) were measured from FIG. 3 which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1. As a result, (S−N) = 67.0 mm and (S−A) = 78.0 mm. It was 78.0 / 67.0 = 1.1641 when P was calculated using these data. Therefore, the maxillary retro index Q is 164.

  The distances (S-N) and (S-A) were measured from FIG. 4 which shows a transparent view of the cephalometric radiograph after the mandibular cutting operation of the patient 1 photographed in Example 1. As a result, (S−N) = 67.0 mm and (S−A) = 78.0 mm. It was 78.0 / 67.0 = 1.1641 when P was calculated using these data. Therefore, the maxillary retro index Q is 164.

[Example 38]
The distances (S-N) and (S-A) were measured from FIG. 5 which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2. As a result, (S−N) = 69.0 mm and (S−A) = 83.0 mm. When P was calculated using these data, it was 83.0 / 69.0 = 1.2028. Therefore, the maxillary retro index Q is 202.

  The distances (S-N) and (S-A) were measured from FIG. 6 which shows a transparent drawing created based on the cephalometric radiogram after the mandibular cutting operation of the patient 2. As a result, (S−N) = 69.0 mm and (S−A) = 83.0 mm. When P was calculated using these data, it was 83.0 / 69.0 = 1.2028. Therefore, the maxillary retro index Q is 202.

[Example 39]
The distances (S-N) and (S-A) were measured from FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3. As a result, (S−N) = 67.0 mm and (S−A) = 88.0 mm. When P was calculated using these data, it was 88.0 / 67.0 = 1.3134. Therefore, the maxillary retro index Q is 313.

[Example 40]
The distances (S-N) and (S-A) were measured from FIG. 8 which shows a transparent drawing created based on the cephalometric radiogram of the patient 4 taken in Example 4. As a result, (S−N) = 64.0 mm and (S−A) = 85.0 mm. It was 85.0 / 64.0 = 1.3281 when P was calculated using these data. Therefore, the maxillary retro index Q is 328.

[Example 41]
The distances (S−N) and (S−A) were measured from FIG. 9, which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5. As a result, (S−N) = 65.0 mm and (S−A) = 75.0 mm. When P was calculated using these data, it was 75.0 / 65.0 = 1.1538. Therefore, the maxillary retro index Q is 153.

[Example 42]
The distances (S-N) and (S-A) were measured from FIG. 10, which shows a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6. As a result, (S−N) = 68.0 mm and (S−A) = 87.0 mm. When P was calculated using these data, it was 87.0 / 68.0 = 1.294. Therefore, the maxillary retro index Q is 279.

  The distances (S-N) and (S-A) were measured from FIG. 11 which shows a transmission diagram created based on a cephalometric radiogram after the mandibular cutting operation of the patient 6. As a result, (S−N) = 68.0 mm and (S−A) = 87.0 mm. When P was calculated using these data, it was 87.0 / 68.0 = 1.294. Therefore, the maxillary retro index Q is 279.

[Example 43]
The distances (S−N) and (S−A) were measured from FIG. 12 which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7. As a result, (S−N) = 67.0 mm and (S−A) = 86.0 mm. When P was calculated using these data, it was 86.0 / 67.0 = 1.2835. Therefore, the maxillary retro index Q is 283.

[Example 44]
The distances (S−N) and (S−A) were measured from FIG. 13 which shows a transmission diagram created based on the cephalometric radiogram of the patient 8 taken in Example 8. As a result, (S−N) = 68.0 mm and (S−A) = 90.0 mm. When P was calculated using these data, it was 90.0 / 68.0 = 1.3235. Therefore, the maxillary retro index Q is 323.

[Example 45]
The distances (S-N) and (S-A) were measured from FIG. 14 which shows a transparent drawing created based on the cephalometric radiogram of the patient 9 taken in Example 9. As a result, (S−N) = 68.0 mm and (S−A) = 79.0 mm. When P was calculated using these data, it was 79.0 / 68.0 = 1.1617. Therefore, the maxillary retro index Q is 161.

[Example 46]
The distances (S−N) and (S−A) were measured from FIG. 15 which shows a transmission diagram created based on the cephalometric radiogram of the patient 10 taken in Example 10. As a result, (S−N) = 69.0 mm and (S−A) = 81.0 mm. When P was calculated using these data, it was 81.0 / 69.0 = 1.1739. Therefore, the maxillary retro index Q is 173.

[Example 47]
The distances (S−N) and (S−A) were measured from FIG. 16 which shows a transmission diagram created based on the cephalometric radiogram of the patient 11 taken in Example 11. As a result, (S−N) = 63.0 mm and (S−A) = 81.0 mm. When P was calculated using these data, it was 81.0 / 63.0 = 1.2857. Therefore, the maxillary retro index Q is 285.

[Example 48]
The distances (S−N) and (S−A) were measured from FIG. 17, which shows a transparent drawing created based on the cephalometric radiogram of the patient 12 taken in Example 12. As a result, (S−N) = 74.0 mm and (S−A) = 91.0 mm. When P was calculated using these data, it was 91.0 / 74.0 = 1.297. Therefore, the maxillary retro index Q is 229.

  As described above, according to the method for calculating the maxillary retro index according to the fourteenth embodiment, the maxillary retro index using the distances (SN) and (SA) measured by cephalometric radiography. Q can be calculated. Based on the maxillary retro index Q, the presence or degree of maxillary undergrowth or maxillary overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<15. Fifteenth Embodiment>
In the fifteenth embodiment, a method for calculating the maxillary retro index will be described.

  Before performing this calculation, a cephalometric radiograph of the patient is performed and the distances (SN) and (SA) are measured. The measurement of these distances can be easily performed by inputting coordinate data of S, N, and A measurement points on a cephalometric radiogram using, for example, a pen tablet or a digitizer. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, and A are measured from the image data, and the distances (SN) and (SA) are measured from the coordinates thus measured. ) May be obtained by calculation.

  First, in step S81, the distances (SN) and (SA) measured as described above are input.

In step S82, from the input (S−N) and (S−A), P = (S−A) − (S−N) (18)
Calculate P according to

  In step S83, the maxillary retro index P calculated as described above is output to a display, for example.

  The presence or degree of maxillary retro can be objectively determined by the maxillary retro index P thus calculated.

[Example 49]
The distances (S−N) and (S−A) were measured from FIG. 3 which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1. As a result, (S−N) = 67.0 mm and (S−A) = 78.0 mm. When P was calculated using these data, it was 78.0-67.0 = 11 mm. Therefore, the maxillary retro index P is 11 mm.

  The distances (S-N) and (S-A) were measured from FIG. 4 which shows a transparent view of the cephalometric radiograph after the mandibular cutting operation of the patient 1 photographed in Example 1. As a result, (S−N) = 67.0 mm and (S−A) = 78.0 mm. When P was calculated using these data, it was 78.0-67.0 = 11 mm. Therefore, the maxillary retro index P is 11 mm.

[Example 50]
The distances (S-N) and (S-A) were measured from FIG. 5 which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2. As a result, (S−N) = 69.0 mm and (S−A) = 83.0 mm. When P was calculated using these data, it was 83.0-69.0 = 14 mm. Therefore, the maxillary retro index P is 14 mm.

  The distances (S-N) and (S-A) were measured from FIG. 6 which shows a transparent drawing created based on the cephalometric radiogram after the mandibular cutting operation of the patient 2. As a result, (S−N) = 69.0 mm and (S−A) = 83.0 mm. When P was calculated using these data, it was 83.0-69.0 = 14 mm. Therefore, the maxillary retro index P is 14 mm.

[Example 51]
The distances (S-N) and (S-A) were measured from FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3. As a result, (S−N) = 67.0 mm and (S−A) = 88.0 mm. When P was calculated using these data, it was 88.0-67.0 = 21 mm. Therefore, the maxillary retro index P is 21 mm.

[Example 52]
The distances (S-N) and (S-A) were measured from FIG. 8 which shows a transparent drawing created based on the cephalometric radiogram of the patient 4 taken in Example 4. As a result, (S−N) = 64.0 mm and (S−A) = 85.0 mm. When P was calculated using these data, it was 85.0-64.0 = 21 mm. Therefore, the maxillary retro index P is 21 mm.

[Example 53]
The distances (S−N) and (S−A) were measured from FIG. 9, which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5. As a result, (S−N) = 65.0 mm and (S−A) = 75.0 mm. When P was calculated using these data, it was 75.0-65.0 = 10 mm. Therefore, the maxillary retro index P is 10 mm.

[Example 54]
The distances (S-N) and (S-A) were measured from FIG. 10, which shows a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6. As a result, (S−N) = 68.0 mm and (S−A) = 87.0 mm. When P was calculated using these data, it was 87.0-68.0 = 19 mm. Therefore, the maxillary retro index P is 19 mm.

  The distances (S-N) and (S-A) were measured from FIG. 11 which shows a transmission diagram created based on a cephalometric radiogram after the mandibular cutting operation of the patient 6. As a result, (S−N) = 68.0 mm and (S−A) = 87.0 mm. When P was calculated using these data, it was 87.0-68.0 = 19 mm. Therefore, the maxillary retro index P is 19 mm.

[Example 55]
The distances (S−N) and (S−A) were measured from FIG. 12 which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7. As a result, (S−N) = 67.0 mm and (S−A) = 86.0 mm. When P was calculated using these data, it was 86.0-67.0 = 19 mm. Therefore, the maxillary retro index P is 19 mm.

[Example 56]
The distances (S−N) and (S−A) were measured from FIG. 13 which shows a transmission diagram created based on the cephalometric radiogram of the patient 8 taken in Example 8. As a result, (S−N) = 68.0 mm and (S−A) = 90.0 mm. When P was calculated using these data, it was 90.0-68.0 = 22 mm. Therefore, the maxillary retro index P is 22 mm.

[Example 57]
The distances (S-N) and (S-A) were measured from FIG. 14 which shows a transparent drawing created based on the cephalometric radiogram of the patient 9 taken in Example 9. As a result, (S−N) = 68.0 mm and (S−A) = 79.0 mm. When P was calculated using these data, it was 79.0-68.0 = 11 mm. Therefore, the maxillary retro index P is 11 mm.

[Example 58]
The distances (S−N) and (S−A) were measured from FIG. 15 which shows a transmission diagram created based on the cephalometric radiogram of the patient 10 taken in Example 10. As a result, (S−N) = 69.0 mm and (S−A) = 81.0 mm. When P was calculated using these data, it was 81.0-69.0 = 12 mm. Therefore, the maxillary retro index P is 12 mm.

[Example 59]
The distances (S−N) and (S−A) were measured from FIG. 16 which shows a transmission diagram created based on the cephalometric radiogram of the patient 11 taken in Example 11. As a result, (S−N) = 63.0 mm and (S−A) = 81.0 mm. When P was calculated using these data, it was 81.0-63.0 = 18 mm. Therefore, the maxillary retro index P is 18 mm.

[Example 60]
The distances (S−N) and (S−A) were measured from FIG. 17, which shows a transparent drawing created based on the cephalometric radiogram of the patient 12 taken in Example 12. As a result, (S−N) = 74.0 mm and (S−A) = 91.0 mm. When P was calculated using these data, it was 91.0-74.0 = 17 mm. Therefore, the maxillary retro index P is 17 mm.

  As described above, according to the method for calculating the maxillary retro index according to the fifteenth embodiment, the maxillary retro index using the distances (SN) and (SA) measured by cephalometric radiography. P can be calculated. Based on the maxillary retro index P, the presence or degree of maxillary undergrowth or maxillary overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<16. Sixteenth Embodiment>
In the sixteenth embodiment, a method for calculating the mandibular retro index will be described.

  Before performing this calculation, a cephalometric radiograph of the patient is performed and the distances (SN), (SA), (SB), (Go-B), and (Go-Me) are measured. . Measurement of these distances is easily performed by inputting coordinate data of S, N, A, B, Go, and Me measurement points on a cephalometric radiogram using, for example, a pen tablet or digitizer. be able to. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, A, B, Go and Me are measured from this image data, and the distance (SN) is measured from the coordinates thus measured. ), (SA), (SB), (Go-B), and (Go-Me) may be obtained by calculation.

  First, in step S91, the distances (SN), (SA), (SB), (Go-B), and (Go-Me) measured as described above are input.

In step S92, P = ((S−B) + (Go−) from the inputted (S−N), (S−A), (S−B), (Go−B) and (Go−Me). B) + (Go−Me)) / ((S−N) + (S−A))
(19)
Calculate P according to

In step S93, the fourth decimal place of P obtained by calculation as described above is rounded down. When 1.000 ≦ P <2.000,
Calculate mandibular retro index Q according to Q = (P− [P]) × 1000, and if P <1.000,
Q = (P − ([P] +1)) × 1000
The mandibular retro index Q is calculated according to

  In step S94, the lower jaw retro index Q calculated as described above is output to, for example, a display.

  The presence / absence or extent of mandibular undergrowth or mandibular overgrowth can be objectively determined by the mandibular retro index Q thus calculated.

[Example 61]
From FIG. 3 which shows the transmission figure produced based on the cephalometric radiogram of the patient 1 image | photographed in Example 1, distance (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 67.0 mm, (S−A) = 78.0 mm, (SB) = 123 mm, (Go−B) = 78.0 mm, (Go−Me) = 78.0 mm Met. When P was calculated using these data, it was (123.0 + 78.0 + 78.0) / (67.0 + 78.0) = 1.9241. Therefore, the mandibular retro index Q is 924.

  From FIG. 4 which shows the transmission figure of the head X-ray standard photograph after the mandibular cutting operation of the patient 1 imaged in Example 1, the distances (SN), (SA), (SB), (Go-B) and (Go-Me) were measured. As a result, (S−N) = 67.0 mm, (SA) = 78.0 mm, (SB) = 111 mm, (Go−B) = 73.0 mm, (Go−Me) = 73.0 mm Met. When P was calculated using these data, it was (111.0 + 73.0 + 73.0) / (67.0 + 78.0) = 1.7724. Therefore, the mandibular retro index Q is 772.

[Example 62]
From FIG. 5, which shows a transmission diagram created based on a cephalometric radiogram of patient 2 taken in Example 2, distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 69.0 mm, (S−A) = 83.0 mm, (S−B) = 123 mm, (Go−B) = 80.0 mm, (Go−Me) = 81.0 mm Met. When P was calculated using these data, it was (123.0 + 80.0 + 81.0) / (69.0 + 83.0) = 1.8684. Therefore, the mandibular retro index Q is 868.

  From FIG. 6 which shows the transmission figure created based on the cephalometric radiograph after the mandibular cutting operation of the patient 2, distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 69.0 mm, (S−A) = 83.0 mm, (S−B) = 116 mm, (Go−B) = 80.0 mm, (Go−Me) = 80.0 mm Met. When P was calculated using these data, it was (116.0 + 80.0 + 80.0) / (69.0 + 83.0) = 1.8157. Therefore, the mandibular retro index Q is 815.

[Example 63]
From FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 67.0 mm, (S−A) = 88.0 mm, (SB) = 126.0 mm, (Go−B) = 80.0 mm, (Go−Me) = 78 0.0 mm. When P was calculated using these data, it was (126.0 + 80.0 + 78.0) / (67.0 + 88.0) = 1.8322. Therefore, the mandibular retro index Q is 832.

[Example 64]
From FIG. 8 which shows a transmission diagram created based on the cephalometric radiograph of the patient 4 taken in Example 4, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 64.0 mm, (S−A) = 85.0 mm, (S−B) = 119.0 mm, (Go−B) = 76.0 mm, (Go−Me) = 77 0.0 mm. When P was calculated using these data, it was (119.0 + 76.0 + 77.0) / (64.0 + 85.0) = 1.8255. Therefore, the mandibular retro index Q is 825.

[Example 65]
From FIG. 9, which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 65.0 mm, (S−A) = 75.0 mm, (S−B) = 109.0 mm, (Go−B) = 73.0 mm, (Go−Me) = 70 0.0 mm. When P was calculated using these data, it was (109.0 + 73.0 + 70.0) / (65.0 + 75.0) = 1.8000. Therefore, the mandibular retro index Q is 800.

[Example 66]
From FIG. 10 which shows the transmission drawing created based on the cephalometric radiogram of the patient 6 photographed in Example 6, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 68.0 mm, (S−A) = 87.0 mm, (SB) = 128.0 mm, (Go−B) = 80.0 mm, (Go−Me) = 80 0.0 mm. When P was calculated using these data, it was (128.0 + 80.0 + 80.0) / (68.0 + 87.0) = 1.8580. Therefore, the mandibular retro index Q is 858.

  From FIG. 11 which shows the transillumination created based on the cephalometric radiogram after the mandibular cutting operation of the patient 6, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 68.0 mm, (S−A) = 87.0 mm, (S−B) = 121.0 mm, (Go−B) = 73.0 mm, (Go−Me) = 73 0.0 mm. When P was calculated using these data, it was (121.0 + 73.0 + 73.0) / (68.0 + 87.0) = 1.7225. Therefore, the mandibular retro index Q is 722.

[Example 67]
From FIG. 12, which shows a transmission diagram created based on a cephalometric radiogram of the patient 7 taken in Example 7, distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 67.0 mm, (S−A) = 86.0 mm, (S−B) = 111.0 mm, (Go−B) = 73.0 mm, (Go−Me) = 69 0.0 mm. It was (111.0 + 73.0 + 69.0) / (67.0 + 86.0) = 1.6535 when P was calculated using these data. Therefore, the mandibular retro index Q is 653.

[Example 68]
From FIG. 13 which shows the transmission drawing created based on the cephalometric radiogram of the patient 8 taken in Example 8, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 68.0 mm, (S−A) = 90.0 mm, (S−B) = 127.0 mm, (Go−B) = 80.0 mm, (Go−Me) = 80 0.0 mm. When P was calculated using these data, it was (127.0 + 80.0 + 80.0) / (68.0 + 90.0) = 1.8164. Therefore, the mandibular retro index Q is 816.

[Example 69]
From FIG. 14 which shows the transmission figure created based on the cephalometric radiogram of the patient 9 photographed in Example 9, the distances (SN), (SA), (SB), (Go) -B) and (Go-Me) were measured. As a result, (S−N) = 68.0 mm, (S−A) = 79.0 mm, (S−B) = 105.0 mm, (Go−B) = 74.0 mm, (Go−Me) = 73 0.0 mm. When P was calculated using these data, it was (105.0 + 74.0 + 73.0) / (68.0 + 79.0) = 1.7142. Therefore, the mandibular retro index Q is 714.

[Example 70]
From FIG. 15, which shows a transmission diagram created based on a cephalometric radiogram of the patient 10 taken in Example 10, the distances (SN), (SA), (SB), (Go) are shown. -B) and (Go-Me) were measured. As a result, (S−N) = 69.0 mm, (S−A) = 81.0 mm, (S−B) = 103.0 mm, (Go−B) = 72.0 mm, (Go−Me) = 70 0.0 mm. When P was calculated using these data, it was (103.0 + 72.0 + 70.0) / (69.0 + 81.0) = 1.6333. Therefore, the mandibular retro index Q is 633.

[Example 71]
From FIG. 16 which shows the transmission figure created based on the head X-ray standard photograph of the patient 11 image | photographed in Example 11, distance (SN), (SA), (SB), (Go). -B) and (Go-Me) were measured. As a result, (S−N) = 63.0 mm, (S−A) = 81.0 mm, (S−B) = 108.0 mm, (Go−B) = 69.0 mm, (Go−Me) = 68 0.0 mm. When P was calculated using these data, it was (108.0 + 69.0 + 68.0) / (63.0 + 81.0) = 1.7033. Therefore, the mandibular retro index Q is 701.

[Example 72]
From FIG. 17 which shows the transmission drawing produced based on the head X-ray standard photograph of the patient 12 image | photographed in Example 12, distance (SN), (SA), (SB), (Go). -B) and (Go-Me) were measured. As a result, (S−N) = 74.0 mm, (S−A) = 91.0 mm, (S−B) = 115.0 mm, (Go−B) = 70.0 mm, (Go−Me) = 65 0.0 mm. When P was calculated using these data, it was (115.0 + 70.0 + 65.0) / (74.0 + 91.0) = 1.5151. Therefore, the mandibular retro index Q is 515.

  As described above, according to the mandibular retro index calculation method according to the sixteenth embodiment, the distances (SN), (SA), and (SB) measured by cephalometric radiography. , (Go-B) and (Go-Me) can be used to calculate the mandibular retro index Q. Based on this mandibular retro index Q, the presence or absence or degree of mandibular undergrowth or mandibular overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<17. Seventeenth Embodiment>
In the seventeenth embodiment, a method for calculating the mandibular retro index will be described.

  Before performing this calculation, a cephalometric radiograph of the patient is performed, and the distances (SN), (SA), (SB), and (Go-B) are measured. These distances can be easily measured by inputting coordinate data of S, N, A, B, and Go measurement points on a cephalometric radiogram using a pen tablet or digitizer, for example. it can. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, A, B, and Go are measured from the image data, and the distance (S−N) from the coordinates thus measured, (SA), (SB), and (Go-B) may be obtained by calculation.

  First, in step S101, the distances (SN), (SA), (SB), and (Go-B) measured as described above are input.

In step S102, from the input (S−N), (S−A), (S−B) and (Go−B), P = ((S−B) + (Go−B)) / (( S−N) + (S−A))
(20)
Calculate P according to

In step S103, the fourth decimal place of P obtained by calculation as described above is rounded down. When 1.000 ≦ P <2.000,
Calculate mandibular retro index Q according to Q = (P− [P]) × 1000, and if P <1.000,
Q = (P − ([P] +1)) × 1000
The mandibular retro index Q is calculated according to

  In step S104, the lower jaw retro index Q calculated as described above is output to, for example, a display.

  The presence / absence or extent of mandibular undergrowth or mandibular overgrowth can be objectively determined by the mandibular retro index Q thus calculated.

[Example 73]
From FIG. 3, which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1, distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 67.0 mm, (S−A) = 78.0 mm, (SB) = 123 mm, and (Go−B) = 78.0 mm. It was (123.0 + 78.0) / (67.0 + 78.0) = 1.3862 when P was calculated using these data. Therefore, the mandibular retro index Q is 386.

  From FIG. 4 which shows a transillumination of a cephalometric radiograph after the mandibular cutting operation of the patient 1 taken in Example 1, distances (SN), (SA), (SB) and (Go-B) was measured. As a result, (S−N) = 67.0 mm, (S−A) = 78.0 mm, (SB) = 111 mm, and (Go−B) = 73.0 mm. When P was calculated using these data, it was (111.0 + 73.0) / (67.0 + 78.0) = 1.2689. Therefore, the mandibular retro index Q is 268.

[Example 74]
From FIG. 5, which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2, the distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 69.0 mm, (S−A) = 83.0 mm, (S−B) = 123 mm, and (Go−B) = 80.0 mm. When P was calculated using these data, it was (123.0 + 80.0) / (69.0 + 83.0) = 1.3355. Therefore, the mandibular retro index Q is 335.

  From FIG. 6 which shows the transillumination created based on the cephalometric radiograph after the mandibular cutting operation of the patient 2, the distances (SN), (SA), (SB) and (Go) are shown. -B) was measured. As a result, (S−N) = 69.0 mm, (S−A) = 83.0 mm, (S−B) = 116 mm, and (Go−B) = 80.0 mm. When P was calculated using these data, it was (116.0 + 80.0) / (69.0 + 83.0) = 1.2894. Therefore, the mandibular retro index Q is 289.

[Example 75]
From FIG. 7, which shows a transmission diagram created based on a cephalometric radiogram of the patient 3 taken in Example 3, the distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 67.0 mm, (S−A) = 88.0 mm, (SB) = 126.0 mm, and (Go−B) = 80.0 mm. When P was calculated using these data, it was (126.0 + 80.0) / (67.0 + 88.0) = 1.3290. Therefore, the mandibular retro index Q is 329.

[Example 76]
From FIG. 8, which shows a transmission diagram created based on the cephalometric radiogram of the patient 4 taken in Example 4, the distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 64.0 mm, (S−A) = 85.0 mm, (S−B) = 119.0 mm, and (Go−B) = 76.0 mm. When P was calculated using these data, it was (119.0 + 76.0) / (64.0 + 85.0) = 1.3087. Therefore, the mandibular retro index Q is 308.

[Example 77]
From FIG. 9, which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5, the distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 65.0 mm, (S−A) = 75.0 mm, (S−B) = 109.0 mm, and (Go−B) = 73.0 mm. When P was calculated using these data, it was (109.0 + 73.0) / (65.0 + 75.0) = 1.3000. Therefore, the mandibular retro index Q is 300.

[Example 78]
From FIG. 10, which shows a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6, the distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 68.0 mm, (S−A) = 87.0 mm, (SB) = 12.8 mm, and (Go−B) = 80.0 mm. When P was calculated using these data, it was (128.0 + 80.0) / (68.0 + 87.0) = 1.419. Therefore, the mandibular retro index Q is 341.

  From FIG. 11, which shows a transmission diagram created based on a cephalometric radiograph after mandibular cutting operation of the patient 6, distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 68.0 mm, (S−A) = 87.0 mm, (SB) = 121.0 mm, and (Go−B) = 73.0 mm. When P was calculated using these data, it was (121.0 + 73.0) / (68.0 + 87.0) = 1.2516. Therefore, the mandibular retro index Q is 251.

[Example 79]
From FIG. 12, which shows a transmission diagram created based on a cephalometric radiogram of the patient 7 taken in Example 7, distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 67.0 mm, (S−A) = 86.0 mm, (S−B) = 111.0 mm, and (Go−B) = 73.0 mm. It was (111.0 + 73.0) / (67.0 + 86.0) = 1.026 when P was calculated using these data. Therefore, the mandibular retro index Q is 202.

[Example 80]
From FIG. 13 which shows a transmission diagram created based on a cephalometric radiogram of the patient 8 taken in Example 8, distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 68.0 mm, (S−A) = 90.0 mm, (S−B) = 127.0 mm, and (Go−B) = 80.0 mm. When P was calculated using these data, it was (127.0 + 80.0) / (68.0 + 90.0) = 1.3101. Therefore, the mandibular retro index Q is 310.

[Example 81]
From FIG. 14 which shows a transmission diagram created based on a cephalometric radiogram of the patient 9 taken in Example 9, distances (SN), (SA), (SB) and (Go) are shown. -B) was measured. As a result, (S−N) = 68.0 mm, (S−A) = 79.0 mm, (SB) = 105.0 mm, and (Go−B) = 74.0 mm. When P was calculated using these data, it was (105.0 + 74.0) / (68.0 + 79.0) = 1.2176. Therefore, the mandibular retro index Q is 217.

[Example 82]
From FIG. 15 which shows a transmission diagram created based on a cephalometric radiogram of the patient 10 taken in Example 10, the distances (SN), (SA), (SB), and (Go) are shown. -B) was measured. As a result, (S−N) = 69.0 mm, (S−A) = 81.0 mm, (S−B) = 103.0 mm, and (Go−B) = 72.0 mm. When P was calculated using these data, it was (103.0 + 72.0) / (69.0 + 81.0) = 1.1666. Therefore, the mandibular retro index Q is 166.

[Example 83]
From FIG. 16 which shows the transmission drawing produced based on the head X-ray standard photograph of the patient 11 image | photographed in Example 11, distance (SN), (SA), (SB), and (Go). -B) was measured. As a result, (S−N) = 63.0 mm, (S−A) = 81.0 mm, (S−B) = 108.0 mm, and (Go−B) = 69.0 mm. When P was calculated using these data, it was (108.0 + 69.0) / (63.0 + 81.0) = 1.2291. Therefore, the mandibular retro index Q is 229.

[Example 84]
From FIG. 17 which shows the transmission drawing produced based on the head X-ray standard photograph of the patient 12 image | photographed in Example 12, distance (SN), (SA), (SB), and (Go). -B) was measured. As a result, (S−N) = 74.0 mm, (S−A) = 91.0 mm, (S−B) = 115.0 mm, and (Go−B) = 70.0 mm. When P was calculated using these data, it was (115.0 + 70.0) / (74.0 + 91.0) = 1.1212. Therefore, the mandibular retro index Q is 121.

  As described above, according to the method for calculating the mandibular retro index according to the seventeenth embodiment, the distances (SN), (SA), (SB) measured by cephalometric radiography. And (Go-B) can be used to calculate the mandibular retro index Q. Based on this mandibular retro index Q, the presence or absence or degree of mandibular undergrowth or mandibular overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<18. Eighteenth Embodiment>
In the eighteenth embodiment, a method for calculating the mandibular retro index will be described.

  Before performing this calculation, a cephalometric radiograph of the patient is performed and the distances (SN), (SB), and (Go-B) are measured. These distances can be easily measured by inputting coordinate data of S, N, B, and Go measurement points on a cephalometric radiogram using a pen tablet or a digitizer, for example. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, B, and Go are measured from this image data, and the distance (S−N), (S -B) and (Go-B) may be obtained by calculation.

  First, in step S111, the distances (SN), (SB), and (Go-B) measured as described above are input.

In step S112, from the input (S−N), (S−B) and (Go−B), P = ((S−B) + (Go−B)) / (S−N) (21)
Calculate P according to

In step S113, P / 2 is calculated using P obtained by calculation as described above, and the fourth decimal place is rounded down. When 1.000 ≦ P / 2 <2.000,
Mandible retro index Q is calculated according to Q = (P / 2− [P / 2]) × 1000, and when P / 2 <1.000,
Q = (P / 2 − ([P / 2] +1)) × 1000
The mandibular retro index Q is calculated according to

  In step S114, the lower jaw retro index Q calculated as described above is output to, for example, a display.

  The presence / absence or extent of mandibular undergrowth or mandibular overgrowth can be objectively determined by the mandibular retro index Q thus calculated.

[Example 85]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 3, which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1. . As a result, (S−N) = 67.0 mm, (S−B) = 123 mm, and (Go−B) = 78.0 mm. Using these data, P / 2 was calculated to be [(123.0 + 78.0) /67.0] /2=1.5000. Therefore, the mandibular retro index Q is 500.

  From FIG. 4 which shows a transillumination of a cephalometric radiograph after the mandibular cutting operation of the patient 1 taken in Example 1, the distances (SN), (SB), and (Go-B) are shown. Measured. As a result, (S−N) = 67.0 mm, (S−B) = 111 mm, and (Go−B) = 73.0 mm. Using these data, P / 2 was calculated to be [(111.0 + 73.0) /67.0] /2=1.3731. Therefore, the mandibular retro index Q is 373.

[Example 86]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 5, which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2. . As a result, (S−N) = 69.0 mm, (S−B) = 123 mm, and (Go−B) = 80.0 mm. Using these data, P / 2 was calculated to be [(123.0 + 80.0) /69.0] /2=1.4710. Therefore, the mandibular retro index Q is 471.

  The distances (SN), (SB), and (Go-B) were measured from FIG. 6 which shows a transparent drawing created based on the cephalometric radiograph after mandibular cutting operation of the patient 2. . As a result, (S−N) = 69.0 mm, (S−B) = 116 mm, and (Go−B) = 80.0 mm. Using these data, P / 2 was calculated to be [(116.0 + 80.0) /69.0] /2=1.4202. Therefore, the mandibular retro index Q is 420.

[Example 87]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 7 showing a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3. . As a result, (S−N) = 67.0 mm, (S−B) = 126.0 mm, and (Go−B) = 80.0 mm. Using these data, P / 2 was calculated to be [(126.0 + 80.0) /67.0] /2=1.5373. Therefore, the mandibular retro index Q is 537.

[Example 88]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 8, which shows a transmission diagram created based on the cephalometric radiogram of the patient 4 taken in Example 4. . As a result, (S−N) = 64.0 mm, (S−B) = 119.0 mm, and (Go−B) = 76.0 mm. Using these data, P / 2 was calculated to be [(119.0 + 76.0) /64.0] /2=1.5234. Therefore, the mandibular retro index Q is 523.

[Example 89]
The distances (SN), (SB), and (Go-B) were measured from FIG. 9 showing a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5. . As a result, (S−N) = 65.0 mm, (S−B) = 109.0 mm, and (Go−B) = 73.0 mm. Using these data, P / 2 was calculated to be [(109.0 + 73.0) /65.0] /2=1.4000. Therefore, the mandibular retro index Q is 400.

[Example 90]
The distances (S-N), (S-B), and (Go-B) were measured from FIG. 10 which shows a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6. . As a result, (S−N) = 68.0 mm, (S−B) = 128.0 mm, and (Go−B) = 80.0 mm. Using these data, P / 2 was calculated to be [(128.0 + 80.0) /68.0] /2=1.5294. Therefore, the mandibular retro index Q is 529.

  The distances (SN), (SB), and (Go-B) were measured from FIG. 11 which shows a transparent drawing created based on a cephalometric radiograph after mandibular cutting operation of the patient 6. . As a result, (S−N) = 68.0 mm, (S−B) = 121.0 mm, and (Go−B) = 73.0 mm. Using these data, P / 2 was calculated to be [(121.0 + 73.0) /68.0] /2=1.4264. Therefore, the mandibular retro index Q is 426.

[Example 91]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 12, which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7. . As a result, (S−N) = 67.0 mm, (S−B) = 111.0 mm, and (Go−B) = 73.0 mm. Using these data, P / 2 was calculated to be [(111.0 + 73.0) /67.0] /2=1.3731. Therefore, the mandibular retro index Q is 373.

[Example 92]
The distances (SN), (SB), and (Go-B) were measured from FIG. 13 showing a transmission diagram created based on the cephalometric radiogram of the patient 8 taken in Example 8. . As a result, (S−N) = 68.0 mm, (S−B) = 127.0 mm, and (Go−B) = 80.0 mm. Using these data, P / 2 was calculated to be [(127.0 + 80.0) /68.0] /2=1.5220. Therefore, the mandibular retro index Q is 522.

[Example 93]
The distances (SN), (SB), and (Go-B) were measured from FIG. 14 showing a transmission diagram created based on the cephalometric radiogram of the patient 9 taken in Example 9. . As a result, (S−N) = 68.0 mm, (S−B) = 105.0 mm, and (Go−B) = 74.0 mm. Using these data, P / 2 was calculated to be [(105.0 + 74.0) /68.0] /2=1.3161. Therefore, the mandibular retro index Q is 316.

[Example 94]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 15, which shows a transmission diagram created based on the cephalometric radiogram of the patient 10 taken in Example 10. . As a result, (S−N) = 69.0 mm, (S−B) = 103.0 mm, and (Go−B) = 72.0 mm. Using these data, P / 2 was calculated to be [(103.0 + 72.0) /69.0] /2=1.2681. Therefore, the mandibular retro index Q is 268.

[Example 95]
The distances (SN), (SB), and (Go-B) were measured from FIG. 16 showing a transmission diagram created based on the cephalometric radiogram of the patient 11 taken in Example 11. . As a result, (S−N) = 63.0 mm, (S−B) = 108.0 mm, and (Go−B) = 69.0 mm. Using these data, P / 2 was calculated to be [(108.0 + 69.0) /63.0] /2=1.4047. Therefore, the mandibular retro index Q is 404.

[Example 96]
The distances (S−N), (S−B), and (Go−B) were measured from FIG. 17, which shows a transmission diagram created based on the cephalometric radiogram of the patient 12 taken in Example 12. . As a result, (S−N) = 74.0 mm, (S−B) = 115.0 mm, and (Go−B) = 70.0 mm. Using these data, P / 2 was calculated to be [(115.0 + 70.0) /74.0] /2=1.500. Therefore, the mandibular retro index Q is 250.

  As described above, according to the method for calculating the mandibular retro index according to the eighteenth embodiment, the distances (SN), (SB), and (Go-B) measured by cephalometric radiography. Can be used to calculate the mandibular retro index Q. Based on the mandibular retro index Q, the presence or absence of the mandibular retro can be accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor.

<19. Nineteenth Embodiment>
In the nineteenth embodiment, a method for calculating the mandibular retro index will be described.

  Prior to this calculation, the patient's cephalometric radiograph is taken and the distances (SN) and (SB) are measured. Measurement of these distances can be easily performed by inputting coordinate data of S, N, and B measurement points on a cephalometric radiogram using a pen tablet or a digitizer, for example. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, and B are measured from the image data, and the distances (SN) and (SB) are measured from the coordinates thus measured. ) May be obtained by calculation.

  First, in step S121, the distances (SN) and (SB) measured as described above are input.

In step S122, from the input (S−N) and (S−B), P = (S−B) / (S−N) (22)
Calculate P according to

In step S123, the fourth decimal place of P obtained by calculation as described above is rounded down. When 1.000 ≦ P <2.000,
Calculate mandibular retro index Q according to Q = (P− [P]) × 1000, and if P <1.000,
Q = (P − ([P] +1)) × 1000
The mandibular retro index Q is calculated according to

  In step S124, the lower jaw retro index Q calculated as described above is output to a display, for example.

  The presence / absence or extent of mandibular undergrowth or mandibular overgrowth can be objectively determined by the mandibular retro index Q thus calculated.

[Example 97]
The distances (S−N) and (S−B) were measured from FIG. 3 which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1. As a result, (S−N) = 67.0 mm and (S−B) = 123 mm. When P was calculated using these data, it was 123.0 / 67.0 = 1.8358. Therefore, the mandibular retro index Q is 835.

  The distances (S−N) and (S−B) were measured from FIG. 4, which shows a transparent view of the cephalometric radiograph after the mandibular cutting operation of the patient 1 taken in Example 1. As a result, (S−N) = 67.0 mm and (S−B) = 111 mm. When P was calculated using these data, it was 111.0 / 67.0 = 1.6567. Therefore, the mandibular retro index Q is 656.

[Example 98]
The distances (S-N) and (S-B) were measured from FIG. 5 which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2. As a result, (S−N) = 69.0 mm and (S−B) = 123 mm. When P was calculated using these data, it was 123.0 / 69.0 = 1.826. Therefore, the mandibular retro index Q is 782.

  The distances (S-N) and (S-B) were measured from FIG. 6 which shows a transparent drawing created based on the cephalometric radiogram after the mandibular cutting operation of the patient 2. As a result, (S−N) = 69.0 mm and (S−B) = 116 mm. It was 116.0 / 69.0 = 1.6811 when P was calculated using these data. Therefore, the mandibular retro index Q is 681.

Example 99
The distances (S-N) and (S-B) were measured from FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3. As a result, (S−N) = 67.0 mm and (S−B) = 12.6 mm. When P was calculated using these data, it was 126.0 / 67.0 = 1.8805. Therefore, the mandibular retro index Q is 880.

[Example 100]
The distances (S-N) and (S-B) were measured from FIG. 8 which shows a transmission diagram created based on the cephalometric radiogram of the patient 4 taken in Example 4. As a result, (S−N) = 64.0 mm and (S−B) = 119.0 mm. When P was calculated using these data, it was 119.0 / 64.0 = 1.8593. Therefore, the mandibular retro index Q is 859.

[Example 101]
The distances (S−N) and (S−B) were measured from FIG. 9 which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5. As a result, (S−N) = 65.0 mm and (S−B) = 109.0 mm. When P was calculated using these data, it was 109.0 / 65.0 = 1.6769. Therefore, the mandibular retro index Q is 676.

[Example 102]
The distances (S−N) and (S−B) were measured from FIG. 10 showing a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6. As a result, (S−N) = 68.0 mm and (S−B) = 12.0 mm. When P was calculated using these data, it was 128.0 / 68.0 = 1.8823. Therefore, the mandibular retro index Q is 882.

  The distances (S−N) and (S−B) were measured from FIG. 11, which shows a transparent drawing created based on a cephalometric radiogram after the mandibular cutting operation of the patient 6. As a result, (S−N) = 68.0 mm and (S−B) = 121.0 mm. When P was calculated using these data, it was 121.0 / 68.0 = 1.794. Therefore, the mandibular retro index Q is 779.

[Example 103]
The distances (S−N) and (S−B) were measured from FIG. 12 which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7. As a result, (S−N) = 67.0 mm and (S−B) = 111.0 mm. When P was calculated using these data, it was 111.0 / 67.0 = 1.6567. Therefore, the mandibular retro index Q is 656.

[Example 104]
The distances (S−N) and (S−B) were measured from FIG. 13 which shows a transmission diagram created based on the cephalometric radiogram of the patient 8 taken in Example 8. As a result, (S−N) = 68.0 mm and (S−B) = 127.0 mm. When P was calculated using these data, it was 127.0 / 68.0 = 1.8676. Therefore, the mandibular retro index Q is 867.

[Example 105]
The distances (S−N) and (S−B) were measured from FIG. 14, which shows a transmission diagram created based on the cephalometric radiogram of the patient 9 taken in Example 9. As a result, (S−N) = 68.0 mm and (S−B) = 105.0 mm. When P was calculated using these data, it was 105.0 / 68.0 = 1.5441. Therefore, the mandibular retro index Q is 544.

[Example 106]
The distances (S−N) and (S−B) were measured from FIG. 15 which shows a transmission diagram created based on the cephalometric radiogram of the patient 10 taken in Example 10. As a result, (S−N) = 69.0 mm and (S−B) = 103.0 mm. When P was calculated using these data, it was 103.0 / 69.0 = 1.4927. Therefore, the mandibular retro index Q is 492.

[Example 107]
The distances (S−N) and (S−B) were measured from FIG. 16 which shows a transmission diagram created based on the cephalometric radiogram of the patient 11 taken in Example 11. As a result, (S−N) = 63.0 mm and (S−B) = 108.0 mm. When P was calculated using these data, it was 108.0 / 63.0 = 1.7142. Therefore, the mandibular retro index Q is 714.

[Example 108]
The distances (S−N) and (S−B) were measured from FIG. 17, which shows a transmission diagram created based on the cephalometric radiogram of the patient 12 taken in Example 12. As a result, (S−N) = 74.0 mm and (S−B) = 115.0 mm. When P was calculated using these data, it was 115.0 / 74.0 = 1.5540. Therefore, the mandibular retro index Q is 554.

  As described above, according to the method for calculating the mandibular retro index according to the nineteenth embodiment, the mandibular retro index using the distances (SN) and (SB) measured by cephalometric radiography. Q can be calculated. Based on this mandibular retro index Q, the presence or absence or degree of mandibular undergrowth or mandibular overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<20. 20th Embodiment>
In the twentieth embodiment, a method for calculating the mandibular retro index will be described.

  Prior to this calculation, the patient's cephalometric radiograph is taken and the distances (SN) and (SB) are measured. Measurement of these distances can be easily performed by inputting coordinate data of S, N, and B measurement points on a cephalometric radiogram using a pen tablet or a digitizer, for example. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, N, and B are measured from the image data, and the distances (SN) and (SB) are measured from the coordinates thus measured. ) May be obtained by calculation.

  First, in step S131, the distances (SN) and (SB) measured as described above are input.

In step S132, from the input (S−N) and (S−B), P = (S−B) − (S−N) (23)
Calculate P according to

  In step S133, the lower jaw retro index P calculated as described above is output to, for example, a display.

  The presence or degree of lower jaw undergrowth or lower jaw overgrowth can be objectively determined by the lower jaw retro index P thus calculated.

[Example 109]
The distances (S−N) and (S−B) were measured from FIG. 3 which shows a transmission diagram created based on the cephalometric radiogram of the patient 1 taken in Example 1. As a result, (S−N) = 67.0 mm and (S−B) = 123 mm. When P was calculated using these data, it was 123.0-67.0 = 56 mm. Therefore, the mandibular retro index P is 56 mm.

  The distances (S−N) and (S−B) were measured from FIG. 4, which shows a transparent view of the cephalometric radiograph after the mandibular cutting operation of the patient 1 taken in Example 1. As a result, (S−N) = 67.0 mm and (S−B) = 111 mm. When P was calculated using these data, it was 111.0-67.0 = 44 mm. Therefore, the mandibular retro index P is 44 mm.

[Example 110]
The distances (S-N) and (S-B) were measured from FIG. 5 which shows a transmission diagram created based on the cephalometric radiogram of the patient 2 taken in Example 2. As a result, (S−N) = 69.0 mm and (S−B) = 123 mm. When P was calculated using these data, it was 123.0-69.0 = 54 mm. Therefore, the mandibular retro index P is 54 mm.

  The distances (S-N) and (S-B) were measured from FIG. 6 which shows a transparent drawing created based on the cephalometric radiogram after the mandibular cutting operation of the patient 2. As a result, (S−N) = 69.0 mm and (S−B) = 116 mm. When P was calculated using these data, it was 116.0-69.0 = 47 mm. Therefore, the mandibular retro index P is 47 mm.

[Example 111]
The distances (S-N) and (S-B) were measured from FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3. As a result, (S−N) = 67.0 mm and (S−B) = 12.6 mm. When P was calculated using these data, it was 126.0-67.0 = 59 mm. Therefore, the mandibular retro index P is 59 mm.

[Example 112]
The distances (S-N) and (S-B) were measured from FIG. 8 which shows a transmission diagram created based on the cephalometric radiogram of the patient 4 taken in Example 4. As a result, (S−N) = 64.0 mm and (S−B) = 119.0 mm. When P was calculated using these data, it was 119.0-64.0 = 55 mm. Therefore, the mandibular retro index P is 55 mm.

[Example 113]
The distances (S−N) and (S−B) were measured from FIG. 9 which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5. As a result, (S−N) = 65.0 mm and (S−B) = 109.0 mm. When P was calculated using these data, it was 109.0-65.0 = 44 mm. Therefore, the mandibular retro index P is 44 mm.

[Example 114]
The distances (S−N) and (S−B) were measured from FIG. 10 showing a transmission diagram created based on the cephalometric radiogram of the patient 6 taken in Example 6. As a result, (S−N) = 68.0 mm and (S−B) = 12.0 mm. When P was calculated using these data, it was 128.0-68.0 = 60 mm. Therefore, the mandibular retro index P is 60 mm.

  The distances (S−N) and (S−B) were measured from FIG. 11, which shows a transparent drawing created based on a cephalometric radiogram after the mandibular cutting operation of the patient 6. As a result, (S−N) = 68.0 mm and (S−B) = 121.0 mm. When P was calculated using these data, it was 121.0-68.0 = 53 mm. Therefore, the mandibular retro index P is 53 mm.

[Example 115]
The distances (S−N) and (S−B) were measured from FIG. 12 which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7. As a result, (S−N) = 67.0 mm and (S−B) = 111.0 mm. When P was calculated using these data, it was 111.0-67.0 = 44 mm. Therefore, the mandibular retro index P is 44 mm.

[Example 116]
The distances (S−N) and (S−B) were measured from FIG. 13 which shows a transmission diagram created based on the cephalometric radiogram of the patient 8 taken in Example 8. As a result, (S−N) = 68.0 mm and (S−B) = 127.0 mm. When P was calculated using these data, it was 127.0-68.0 = 59 mm. Therefore, the mandibular retro index P is 59 mm.

[Example 117]
The distances (S−N) and (S−B) were measured from FIG. 14, which shows a transmission diagram created based on the cephalometric radiogram of the patient 9 taken in Example 9. As a result, (S−N) = 68.0 mm and (S−B) = 105.0 mm. When P was calculated using these data, it was 105.0-68.0 = 37 mm. Therefore, the mandibular retro index P is 37 mm.

[Example 118]
The distances (S−N) and (S−B) were measured from FIG. 15 which shows a transmission diagram created based on the cephalometric radiogram of the patient 10 taken in Example 10. As a result, (S−N) = 69.0 mm and (S−B) = 103.0 mm. When P was calculated using these data, it was 103.0-69.0 = 34 mm. Therefore, the mandibular retro index P is 34 mm.

[Example 119]
The distances (S−N) and (S−B) were measured from FIG. 16 which shows a transmission diagram created based on the cephalometric radiogram of the patient 11 taken in Example 11. As a result, (S−N) = 63.0 mm and (S−B) = 108.0 mm. When P was calculated using these data, it was 108.0-63.0 = 45 mm. Therefore, the mandibular retro index P is 45 mm.

[Example 120]
The distances (S−N) and (S−B) were measured from FIG. 17, which shows a transmission diagram created based on the cephalometric radiogram of the patient 12 taken in Example 12. As a result, (S−N) = 74.0 mm and (S−B) = 115.0 mm. When P was calculated using these data, it was 115.0-74.0 = 41 mm. Therefore, the mandibular retro index P is 41 mm.

  As described above, according to the method for calculating the mandibular retro index according to the twentieth embodiment, the mandibular retro index using the distances (SN) and (SB) measured by cephalometric radiography. P can be calculated. Based on the mandibular retro index P, the presence or absence or degree of mandibular undergrowth or mandibular overgrowth is accurately diagnosed in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Can do.

<21. Twenty-first embodiment>
In the twenty-first embodiment, a method of calculating a jaw bone surgery necessity determination index in orthodontic treatment will be described.

  Before performing this calculation, a cephalometric radiograph of a patient performing orthodontic treatment is performed, and distances (SA), (Go-A), (SB), and (Go-B) are measured. . These distances can be easily measured by inputting coordinate data of S, A, B, and Go measurement points on a cephalometric radiogram using a pen tablet or a digitizer, for example. Alternatively, image data obtained by cephalometric radiography is taken into a computer, and the coordinates of S, A, B, and Go are measured from this image data, and the distance (SA), (Go) from the coordinates thus measured. -A), (SB) and (Go-B) may be obtained by calculation.

  First, in step S141, the distances (SA), (Go-A), (SB), and (Go-B) measured as described above are input.

In step S142, P = ((S−B) + (Go−B)) / (() from the inputted (S−A), (Go−A), (S−B) and (Go−B). S−A) + (Go−A))
Calculate P according to

In step S143, 2P is calculated using P obtained by calculation as described above, and the fourth decimal place is rounded down. When 2.000 ≦ P <3.000,
OPE index Q is calculated according to Q = (P− [P]) × 1000, and when P <2.000,
Q = (P − ([P] +1)) × 1000
The OPE index Q is calculated according to

  In step S144, the OPE index Q calculated as described above is output to a display, for example.

When the OPE index Q calculated in this way is C ₅ or more, it can be diagnosed that a mandibular cutting operation is necessary in orthodontic treatment. For borderline cases where the OPE index Q is C ₆ or more and less than C ₅ , supplementary analysis is added by Wits analysis. If the result of Wits analysis is 12 mm or more, it is judged that surgical indication, in other words, jaw bone surgery is necessary. C ₅ and C ₆ can be determined as appropriate.

When the OPE index Q is less than C _{6 and} 0 or more, it can be diagnosed that jaw surgery is unnecessary in orthodontic treatment.

  A negative OPE index Q also means a significant retro tendency of the mandible or an overgrowth tendency of the maxilla, and jaw surgery should be considered.

  In general, in addition to the OPE index Q, the dentist finally determines whether or not the jaw bone surgery is necessary by using the results of other examinations such as a conventional cephalometric analysis centering on angle measurement.

[Example 121]
From FIG. 3, which shows a transmission diagram created based on a cephalometric radiogram of patient 1 taken in Example 1, distances (SA), (Go-A), (SB), and (Go) are shown. -B) was measured. As a result, (SA) = 78.0 mm, (Go−A) = 77.0 mm, (SB) = 123.0 mm, and (Go−B) = 78.0 mm. When 2P was calculated using these data, it was 2 × [(123.0 + 78.0) / (78.0 + 77.0)] = 2.5935. Therefore, the OPE index Q is 593.

For example, when C ₅ = 470 is set, the OPE index Q is 593, so that the patient 1 can determine that a mandibular cutting operation is necessary in orthodontic treatment.

  Therefore, the necessary cutting operation of the mandible was performed. From FIG. 4 which shows a transillumination of a cephalometric radiograph after the mandibular cutting operation of the patient 1 taken in Example 1, distances (SA), (Go-A), (SB) and (Go-B) was measured. As a result, (SA) = 78.0 mm, (Go−A) = 79.0 mm, (SB) = 111.0 mm, and (Go−B) = 73.0 mm. When 2P was calculated using these data, it was 2 × [(111.0 + 73.0) / (78.0 + 79.0)] = 2.3439. Therefore, the OPE index Q is 343.

Since the OPE index Q is 343 for C ₅ = 470, it can be determined that the patient 1 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 122]
From FIG. 5, which shows a transmission diagram created based on a cephalometric radiogram of the patient 2 taken in Example 2, the distances (SA), (Go-A), (SB), and (Go) are shown. -B) was measured. As a result, (SA) = 83.0 mm, (Go−A) = 78.0 mm, (SB) = 123.0 mm, and (Go−B) = 80.0 mm. When 2P was calculated using these data, it was 2 × [(123.0 + 80.0) / (83.0 + 78.0)] = 2.5217. Therefore, the OPE index Q is 521.

Since the OPE index Q is 521 for C ₅ = 470, it can be determined that the patient 2 needs a mandibular cutting operation.

  Therefore, the necessary cutting operation of the mandible was performed. From FIG. 6 which shows the transillumination created based on the cephalometric radiogram after the mandibular cutting operation of the patient 2, distances (SA), (Go-A), (SB) and (Go) are shown. -B) was measured. As a result, (S−A) = 83.0 mm, (Go−A) = 83.0 mm, (S−B) = 116.0 mm, and (Go−B) = 80.0 mm. When 2P was calculated using these data, it was 2 × [(116.0 + 80.0) / (83.0 + 83.0)] = 2.3614. Therefore, the OPE index Q is 361.

Since the OPE index Q is 361 for C ₅ = 470, it can be determined that the patient 2 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 123]
From FIG. 7 which shows a transmission diagram created based on the cephalometric radiogram of the patient 3 taken in Example 3, the distances (SA), (Go-A), (SB) and (Go) are shown. -B) was measured. As a result, (SA) = 88.0 mm, (Go-A) = 85.0 mm, (SB) = 16.0 mm, and (Go−B) = 80.0 mm. When 2P was calculated using these data, it was 2 × [(126.0 + 80.0) / (88.0 + 85.0)] = 2.3815. Therefore, the OPE index Q is 381.

Although it is a few skeletal class III cases, the CPE = Q is 381 for C ₅ = 470. Therefore, it is judged that patient 3 does not need to perform jaw surgery when performing orthodontic treatment. can do.

[Example 124]
From FIG. 8 which shows a transmission diagram created based on the cephalometric radiogram of the patient 4 taken in Example 4, the distances (SA), (Go-A), (SB) and (Go) are shown. -B) was measured. As a result, (SA) = 85.0 mm, (Go−A) = 78.0 mm, (SB) = 119.0 mm, and (Go−B) = 76.0 mm. When 2P was calculated using these data, it was 2 × [(119.0 + 76.0) / (85.0 + 78.0)] = 2.3926. Therefore, the OPE index Q is 392.

Although it is a skeletal class III case, the OPE index Q is 392 for C ₅ = 470, so patient 4 judges that it is not necessary to perform jaw surgery for orthodontic treatment Can do.

[Example 125]
From FIG. 9, which shows a transmission diagram created based on the cephalometric radiogram of the patient 5 taken in Example 5, the distances (SA), (Go-A), (SB), and (Go) are shown. -B) was measured. As a result, (SA) = 75.0 mm, (Go−A) = 74.0 mm, (SB) = 109.0 mm, and (Go−B) = 73.0 mm. When 2P was calculated using these data, it was 2 × [(109.0 + 73.0) / (75.0 + 74.0)] = 2.4429. Therefore, the OPE index Q is 442.

Since the OPE index Q is 442 for C ₅ = 470, this is a borderline case. Wits is 10.0 mm, which is a very skeletal case, but it is 12 mm or less and (SN) = 65.0 mm, so it is not necessary to perform jaw surgery when performing orthodontic treatment Can be determined.

[Example 126]
From FIG. 10 which shows the transillumination created based on the cephalometric radiogram of the patient 6 taken in Example 6, the distances (SA), (Go-A), (SB) and (Go) are shown. -B) was measured. As a result, (SA) = 87.0 mm, (Go−A) = 79.0 mm, (SB) = 12.8 mm, and (Go−B) = 80.0 mm. When 2P was calculated using these data, it was 2 × [(128.0 + 80.0) / (87.0 + 79.0)] = 2.060. Therefore, the OPE index Q is 506.

Since the OPE index Q is 506 for C ₅ = 470, this is a borderline case. Since Wits is 12.0 mm and (S−N) = 68.0 mm, it is a skeletal class III case and can be judged as jaw deformity, and mandibular cutting operation is necessary. It can be judged that there is.

Therefore, the necessary cutting operation of the mandible was performed. From FIG. 11, which shows a transillumination created based on a cephalometric radiograph after mandibular cutting operation of the patient 6, distances (SA), (Go-A), (SB), and (Go) are shown. -B) was measured. As a result, (SA) = 87.0 mm, (Go−A) = 77.0 mm, (SB) = 121.0 mm, and (Go−B) = 73.0 mm. When 2P was calculated using these data, it was 2 × [(121.0 + 73.0) / (87.0 + 77.0)] = 2.3658. Therefore, the OPE index Q is 365.
Since the OPE index Q is 365 for C ₃ = 470, it can be determined that the patient 6 can perform orthodontic treatment as a result of the mandibular cutting operation.

[Example 127]
From FIG. 12, which shows a transmission diagram created based on the cephalometric radiogram of the patient 7 taken in Example 7, the distances (SA), (Go-A), (SB), and (Go) are shown. -B) was measured. As a result, (SA) = 86.0 mm, (Go−A) = 86.0 mm, (SB) = 111.0 mm, and (Go−B) = 73.0 mm. When 2P was calculated using these data, it was 2 × [(111.0 + 73.0) / (86.0 + 86.0)] = 2.1395. Therefore, the OPE index Q is 139.

For C ₅ = 470, the OPE index Q is 139 and there is a tendency to retreat the mandible, but the patient 7 does not need to perform jaw surgery when performing orthodontic treatment, and orthodontic treatment by extraction treatment It can be judged as adaptation.

[Example 128]
From FIG. 13 which shows the transmission figure produced based on the head X-ray standard photograph of the patient 8 image | photographed in Example 8, distance (SA), (Go-A), (SB), and (Go). -B) was measured. As a result, (S−A) = 90.0 mm, (Go−A) = 79.0 mm, (S−B) = 127.0 mm, and (Go−B) = 80.0 mm. When 2P was calculated using these data, it was 2 × [(127.0 + 80.0) / (90.0 + 79.0)] = 2.4497. Therefore, the OPE index Q is 449.

Since the OPE index Q is 449 for C ₃ = 470, it can be determined that the patient 8 does not need to perform jaw surgery when performing orthodontic treatment.

[Example 129]
From FIG. 14 which shows a transmission diagram created based on the cephalometric radiogram of the patient 9 taken in Example 9, the distances (SA), (Go-A), (SB) and (Go) are shown. -B) was measured. As a result, (S−A) = 79.0 mm, (Go−A) = 81.0 mm, (SB) = 105.0 mm, and (Go−B) = 74.0 mm. When 2P was calculated using these data, it was 2 × [(105.0 + 74.0) / (79.0 + 81.0)] = 2.2375. Therefore, the OPE index Q is 237.

Since the OPE index Q is 237 for C ₃ = 470, it can be determined that the patient 9 does not need to perform jaw surgery when performing orthodontic treatment.

[Example 130]
From FIG. 15, which shows a transmission diagram created based on a cephalometric radiogram of the patient 10 taken in Example 10, distances (SA), (Go-A), (SB), and (Go) are shown. -B) was measured. As a result, (S−A) = 81.0 mm, (Go−A) = 83.0 mm, (S−B) = 103.0 mm, and (Go−B) = 72.0 mm. When 2P was calculated using these data, it was 2 × [(103.0 + 72.0) / (81.0 + 83.0)] = 2.3411. Therefore, the OPE index Q is 134.

Although it is a non-skeletal case, since the OPE index Q is 134 for C ₃ = 470, it is not necessary for the patient 10 to perform jaw surgery when performing orthodontic treatment. It can be judged to be an orthodontic treatment indication.

[Example 131]
From FIG. 16 which shows the transmission figure produced based on the head X-ray standard photograph of the patient 11 image | photographed in Example 11, distance (SA), (Go-A), (SB), and (Go). -B) was measured. As a result, (SA) = 81.0 mm, (Go−A) = 78.0 mm, (SB) = 108.0 mm, and (Go−B) = 69.0 mm. When 2P was calculated using these data, it was 2 × [(108.0 + 69.0) / (81.0 + 78.0)] = 2.2264. Therefore, the OPE index Q is 226.

For C ₅ = 470, OPE index Q is 226, Wits is 2.0 mm, which is a non-skeletal case, but patient 11 does not need to perform jaw bone surgery when performing orthodontic treatment Therefore, it can be determined that the orthodontic treatment is applied by non-extraction treatment.

[Example 132]
From FIG. 17 which shows the transmission figure produced based on the cephalometric radiogram of the patient 12 image | photographed in Example 12, distance (SA), (Go-A), (SB), and (Go). -B) was measured. As a result, (SA) = 91.0 mm, (Go−A) = 87.0 mm, (SB) = 115.0 mm, and (Go−B) = 70.0 mm. When 2P was calculated using these data, it was 2 × [(115.0 + 70.0) / (91.0 + 87.0)] = 2.0786. Therefore, the OPE index Q is 78.

Since the OPE index Q is 78 for C ₅ = 470, it can be determined that the patient 12 does not need to perform jaw surgery when performing orthodontic treatment.

  As described above, according to the calculation method of the jaw bone surgery necessity determination index according to the twenty-first embodiment, the distances (SA), (Go-A), (S) measured by cephalometric radiography. -B) and (Go-B) can be used to calculate the OPE index Q. Based on this OPE index Q, it is possible to accurately determine whether or not the jaw bone surgery is necessary for orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist. Can be diagnosed.

<22. Twenty-second embodiment>
In the twenty-second embodiment, orthodontic treatment is performed in the same manner as in the second embodiment using the method for calculating the index of necessity of jaw surgery in orthodontic treatment described in the twenty-first embodiment. The method for determining the necessity of jaw surgery is implemented.

  According to the twenty-second embodiment, whether or not jaw surgery is necessary in orthodontic treatment is performed in a short time and with a certain objectivity, regardless of the experience of the dentist, based on the index for determining whether or not jaw surgery is necessary. Can be accurately determined.

<23. Twenty-third embodiment>
In the twenty-third embodiment, the maxilla and mandible discord determination index is calculated by the same method as the calculation method of the jaw bone surgery necessity determination index in the orthodontic treatment described in the twenty-first embodiment.

  According to the twenty-third embodiment, the maxilla and mandible discord determination index can be easily calculated. Based on this index for determining the inequalities of the maxilla and mandible, the maxilla and mandible can be used in dental treatment and medical treatment such as orthodontic treatment in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. Discord can be accurately determined.

<24. Twenty-fourth embodiment>
In the twenty-fourth embodiment, the method for determining the maxilla and mandible incongruity is performed in the same manner as in the fourth embodiment, using the method for calculating the discord in the maxilla and mandible described in the twenty-third embodiment. .

  According to the twenty-fourth embodiment, on the basis of the maxillary and mandible discord judgment index, the dental treatment such as orthodontic treatment is performed in a short time and with a certain objectivity without being influenced by the experience of the dentist or the doctor. It is possible to accurately determine maxillary and mandibular incompatibility in medical treatment and medical treatment.

<25. 25th Embodiment>
In the twenty-fifth embodiment, the jaw deformity determination index is calculated by the same method as the calculation method of the jaw bone surgery necessity determination index in the orthodontic treatment described in the twenty-first embodiment.

  According to the twenty-fifth embodiment, the jaw deformity determination index can be easily calculated. Based on this jaw deformity determination index, it is possible to accurately determine whether or not the subject has jaw deformity in a short time and with a certain objectivity, regardless of the experience of the dentist or doctor. it can.

<26. Twenty-sixth embodiment>
In the twenty-sixth embodiment, using the method for calculating a jaw deformity determination index described in the twenty-fifth embodiment, the method for determining a jaw deformity is performed in the same manner as in the sixth embodiment.

  According to the twenty-sixth embodiment, based on the jaw deformity determination index, whether or not the subject has jaw deformity in a short time and with a certain objectivity, regardless of the experience of a dentist or a doctor. Can be accurately determined.

  Here, the calculation method of the jaw bone surgery necessity determination index, the jaw bone surgery necessity judgment method, the upper and lower jaw bone incompatibility judgment index calculation method, the upper and lower jaw bone incompatibility judgment method, and jaw deformity according to the first to twenty-sixth embodiments A data processing apparatus used for carrying out a calculation method of a judgment index, a jaw deformity judgment method, a maxillary undergrowth / overgrowth judgment index, or a mandibular undergrowth / overgrowth judgment index will be described.

  FIG. 21 shows an example of the data processing apparatus 10. As shown in FIG. 21, the data processing device 10 includes an auxiliary storage device 11, a memory 12, a CPU (Central Processing Unit) 13 as a processing unit, an input unit 14, an output unit 15, and an input / output interface 16.

  The auxiliary storage device 11 stores various kinds of information, and includes, for example, a hard disk, a ROM (Read Only Memory), and the like. The auxiliary storage device 11 stores a program 111, a compiler 112, and an execution module 113.

  The program 111 is a program (source program) in which processing on the flowchart shown in FIG. 2, FIG. 18, FIG. 19 or FIG. 20 is described. The compiler 112 compiles and links the program 111. The execution module 113 is a module compiled and linked by the compiler 112.

  The memory 12 is temporary storage means for storing various types of information, and is configured by, for example, a RAM (Random Access Memory). The CPU 13 performs various arithmetic processes such as addition, subtraction, multiplication, and division, and plays a role of executing the execution module 13 through the memory 12 and the input / output interface 16. The input unit 14 is an input device for inputting various execution commands and the like. The output unit 15 is an output device that outputs various execution results. The input / output interface 16 mediates input / output between each component of the data processing apparatus 10.

  Next, the operation of the data processing apparatus 10 configured as described above will be described. First, a compile command input from the input unit 14 by the operator is stored in the memory 12 via the input / output interface 16. In the memory 12, the program 111 of the auxiliary storage device 11 is compiled and linked by the compiler 112, and an execution module 113 that is a machine language code is generated.

  Next, when an execution command is input from the input unit 14 by the operator, the CPU 13 loads the execution module 113 into the memory 12. When the execution module 113 is loaded into the memory 12, the CPU 13 sequentially calls each process on the flowchart shown in FIG. 2, 18, 19, or 20 from the memory 12 to the CPU 13, and executes each process. The execution result is stored in the memory 12. The execution result stored in the memory 12 is output by the CPU 13 to the output unit 15 via the input / output interface 16.

  For example, when the processing on the flowchart shown in FIG. 2 is executed to calculate the OPE index, the following is performed. First, the execution module 113 for realizing step S1 of the input process is called from the memory 12 to the CPU 13. In step S <b> 1, data (distance (SA), (SB) and (Go-Me)) input from the input unit 14 by the operator is loaded into the memory 12. When the input process of step S1 is completed, an execution module 113 for realizing step S2 of the calculation process is called from the memory 12 to the CPU 13. In step S2, P is calculated from the input data. When the calculation process of step S2 ends, the execution module 113 for realizing step S3 is called from the memory 12 to the CPU 13. In step S3, an OPE index is calculated according to the size of P. When the calculation process in step S3 ends, the execution module 113 for realizing step S4 is called from the memory 12 to the CPU 13. In step S4, the value of P is output to the output unit 15 as a calculation result.

  The case where the processing on the flowchart shown in FIG. 18, FIG. 19, or FIG. 20 is executed is the same as described above.

  Although the embodiments and examples of the present invention have been specifically described above, the present invention is not limited to the above-described embodiments and examples, and various modifications based on the technical idea of the present invention. Is possible.

  For example, the numerical values, flowcharts, and the like given in the above-described embodiments and examples are merely examples, and different numerical values, flowcharts, and the like may be used as necessary.

Incidentally, P = in the case of _{((S-X i) +} (Go-X j)) / (S-A) in the X _i = B and _{X j = Me, P = (} (S-X i) + ( Go-X _j )) / (SA) (except for the case of X _i = B and X _j = Me).

Further, for example, P = ((S−X _i ) + (Go−X _j )) / (S−A), P = ((S−B) + (Go−B) + (Go−Me)) / ((S−A) + (Go−A)) or other mathematically equivalent expressions that can obtain numerical indices equivalent to the expressions (16) to (24) may be used. For example, multiplying each term of the denominator numerator on the right side of these P formulas by adding an arbitrary coefficient, adding another term, adding or subtracting a constant, or adding or subtracting a constant to the right side Good. Specifically, for example, P = (b (S−X _i ) + c (Go−X _j ) instead of P = ((S−X _i ) + (Go−X _j )) / ( _SA ). )) / A (SA) + d (where a, b, c and d are real numbers).

  DESCRIPTION OF SYMBOLS 10 ... Data processing apparatus, 11 ... Auxiliary storage device, 12 ... Memory, 13 ... CPU, 14 ... Input part, 15 ... Output part, 16 ... Input / output interface, 111 ... Program, 112 ... Compiler, 113 ... Execution module

Claims (9)

The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
Jaw bone in orthodontic treatment that calculates P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me) How to calculate the index for determining the necessity of surgery. Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
The method for calculating an index for determining whether or not jaw surgery is necessary in orthodontic treatment according to claim 1. The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me)
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate
A method for determining whether or not jaw surgery is necessary in orthodontic treatment, wherein it is determined whether or not the calculated P or Q is equal to or greater than a predetermined value. The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except for the case of X _i = B and X _j = Me) Method of calculation. The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me)
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or
Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate
A method for determining the maxilla and mandible inconsistency by determining whether or not the calculated P or Q is equal to or greater than a predetermined value. The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (however, excluding the case where X _i = B and X _j = Me) Method. The distance between S and A (SA), S and X _i (i is an integer between 1 and 4, X ₁ = B, X ₂ = Pog, measured by X-ray imaging of the patient's head , X ₃ = Gn, the distance (S-X _i) and Go and X _j (j between X ₄ = Me) with 1 to 4 integer, j = i or j ≠ i) between the Using the distance (Go-X _j )
P = ((S−X _i ) + (Go−X _j )) / (S−A) (except when X _i = B and X _j = Me)
Or
Furthermore, round down the decimal place to the fourth decimal place,
Q = (P− [P]) × 1000 ([] is a Gaussian symbol) (however, 2.000 ≦ P <3.000)
Or Q = (P − ([P] +1)) × 1000 ([] is a Gaussian symbol) (where P <2.000)
Calculate
A method for determining jaw deformity, wherein it is determined whether or not the calculated P or Q is equal to or greater than a predetermined value.   The method for calculating the need for jaw surgery in orthodontic treatment according to claim 1 or 2, the method for judging the need for jaw surgery in orthodontic treatment, and the inequalities of the maxilla and mandible according to claim 4. 7. A computer for calculating at least one of a method for calculating a judgment index, a method for judging incongruity of maxilla and mandible according to claim 5, a method for calculating a jaw deformity judgment index according to claim 6, and a method for judging jaw deformity according to claim 7. A program to make it run.   A computer comprising at least one of the programs according to claim 8.

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