CN103911320B - Multi cell culture biomass culture method - Google Patents

Multi cell culture biomass culture method Download PDF

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CN103911320B
CN103911320B CN 201410090816 CN201410090816A CN103911320B CN 103911320 B CN103911320 B CN 103911320B CN 201410090816 CN201410090816 CN 201410090816 CN 201410090816 A CN201410090816 A CN 201410090816A CN 103911320 B CN103911320 B CN 103911320B
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load
production
cell culture
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许建刚
谢全森
王停军
冯卫东
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广东美瑞科海洋生物科技有限公司
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本发明公开了一种生物质多培养池培养方法,其包括以下步骤:(1)对单个培养池活性物质的工业化培养过程分解为几个基本工序;(2)分析基本工序中每个工序所消耗的生产基地资源;(3)负荷分析;(4)确定单个培养池在一个生产周期中每天的各基本工序负荷消耗;(5)根据生产目标确定需要培养池的数量,通过负荷累计确定最佳方案。 The present invention discloses a multi-culture cell culture biomass, comprising the steps of: (1) industrial culture cell culture process for a single active substance into several basic procedure; (2) Analysis of each step of the basic process production base resource consumption; (3) load analysis; (4) determining a single culture tank of each basic process load daily consumed in a production cycle; (5) determines that the number of cell culture according to the production objectives, the cumulative determined most by load good plan. 本发明的多培养池生产的方法可以实现高效率、科学可靠的运行含有多个开放式的微生物生物质培养池的生产系统,使得生产系统的产能最大化。 Multi cell culture produced according to the present invention can achieve high efficiency, reliable operation SCIENCES comprising culturing a plurality of open-cell microbial biomass material production system, the production system so that the yield can be maximized.

Description

生物质多培养池培养方法 Multi cell culture biomass culture method

技术领域 FIELD

[0001] 本发明涉及藻类生产技术领域。 [0001] The present invention relates to a technical field of production of algae.

背景技术 Background technique

[0002] 微生物生物质为微藻和细菌的微生物混合群,所述混合群是微藻、硅藻、酵母、真菌、原生生物、小型浮游生物和细菌的絮凝物。 [0002] The microbial biomass of microalgae and microorganisms in a mixed population of bacteria, said mixed population is a microalga, diatoms, yeasts, fungi, protists, bacteria and plankton small flocs. 微藻在水产养殖中用作软体动物类、甲壳动物类和某些鱼类的饲料,并且用于水产养殖食物链中使用的浮游动物的饲料。 Microalgae as molluscs, crustaceans and certain fish feed in aquaculture, and zooplankton for feed of the food chain for use in aquaculture. 微藻在对虾养殖中起到了关键作用。 Microalgae played a key role in shrimp farming. 含微藻的微生物生物质絮团在干燥后可作为甲壳动物的饲料添加剂,但主要的困难是产量稳定、价格低廉的产品。 Microalgae containing microbial biomass flocs after drying can be used as feed additives crustacean, but the main difficulty is that production of stable, low-cost products.

[0003] 微藻、螺旋藻、硅藻等微生物的生产工艺一般是使用合适的碳源、营养原料在一定的容器内经过一定时间及条件下进行繁殖生长,其中容器有开发式、封闭式。 [0003] microorganisms microalgae, Spirulina, diatoms and other production processes generally use a suitable carbon source, growth and reproduction nutritional feedstock within a certain predetermined time elapsed and the vessel conditions, wherein the container has developed, closed. 从工业化规模化生产来看,微生物生物质的培养需要大量的水体、增氧、曝气等条件,而稳定、低成本的生产是目前微生物生产的主要障碍。 From the industrial-scale production point of view, the microorganisms are cultured biomass requires a lot of water, oxygen, aeration and other conditions, and stable, low-cost production is a major obstacle to microbial production.

[0004] 目前微藻的培养技术主要侧重于养料投放的用量、培养的环境控制,产品的质量和产出。 [0004] microalgae culture techniques focus primarily on the amount of nutrients delivered, control of the culture environment, the quality and yield. 随着技术的发展,上述技术也日趋完善,在工业化生产需求逐步提高的背景下,成熟、高效的工业化操作技术日趋成为短板。 As technology advances, the above techniques are maturing, demand in the industrial production gradually increase the background, mature, efficient operation of industrial technology has become a short board. 从工业化规模化角度看,微生物生物质培养涉及到培养容器、注水、投放原料、搅拌增氧曝气的工艺、质量控制规范、物料收取、排水等,尤其是在多培养池连续生产的情况下,这些技术的解决是规模化产出的关键。 From the perspective of industrial scale, microbial culture raw material relates to the culture vessel, water, raw material delivery, oxygen aeration stirring process, quality control standards, the material charge, drainage, particularly in the case of a multi-tank continuous production culture to solve these techniques is the key to large-scale output. 就现有技术进展来说,为了保证产品质量,一些微藻的技术,如中国专利CN102863115A所公开的技术,一定程度上牺牲了产能的发挥。 On the progress of the prior art, in order to ensure product quality, some of microalgae technology, such as Chinese patent CN102863115A disclosed technology, to some extent, at the expense of play production capacity.

[0005] 发明专利(CN102016001A)提到了微生物生物质的生产方法可以在室外水箱或水池分批或半连续方式操作,但并未公开工业化生产的可行性方法。 [0005] Patent (CN102016001A) mentioned method for producing a microbial biomass may be operated batchwise or semi-continuous tank or outside the tank, but does not disclose the feasibility of industrial production methods. 在发明专利(CN102016001A)涉及的微生物生物质培养,微藻领域所涉及的微藻产品的生产有一个共同特点,都是使用不同种类配比的养料、不同种类的碳源在培养容器内(封闭式的有光合反应器、发酵罐,开放式的养殖池)搅拌充气使之充分生长,然后进行采收、干燥。 In the production Patent (CN102016001A) culturing microbial biomass invention relates to a material, the area covered microalgae microalgal products have a common characteristic, are using different proportions of nutrients types, different types of carbon in the culture vessel (closed photosynthetically type reactor, a fermentor, pond open) so that the inflator stirred sufficiently grown, harvested and then dried. 当培养容器为一个或通常的2~4个时产品的生产过程很容易通过人工或自动化设备实现。 When the culture or a container is generally 2 to 4 during the production process is easily achieved by manual or automated equipment. 然而当考虑工业化规模化生产,考虑增加培养容器至1 〇~40个时,会出现很多新的困难。 However, when considering industrial-scale production, to consider increasing the culture container 1 billion to 40, many new difficulties arise. 当培养容器数量众多时,累计起来的碳源、养料投放、设备、电力消耗等会成为一个很大的数字。 When a large number of culture container, add up the carbon, nutrient delivery, equipment, power consumption will become a very large number. 这会产生一个对于各项物资、设备、人员的管理问题。 This results in a for the materials, equipment, personnel management issues.

[0006] 当培养容器数量增加时,他们所能达到的总的最高产品就需要作科学的测算。 [0006] When the culture to increase the number of containers, they can achieve the highest total of the product is required to make estimates science. 最简单的计算方法,设培养容器有n个,一定时间tn内的当个培养容器产量为PJt,整个生产时间T内的总产量P。 The simplest method of calculation, the culture container is provided with n, as a production culture vessel within a certain time tn is PJT, throughout the total production time T P.

Figure CN103911320BD00031

[0008]但这种计算方式无疑是错误的,只是将总产量作了最理想化的考虑,实际生产必须考虑一个生产系统各项投入要素的最大供应能力,比如未作科学规划时某一个生产时间点会有多个培养容器需要同时投放碳源,另一个时间节点会同时需要更大的电力供应以确保设备运转,当整个工厂的碳源投放能力、电力供应能力小于时间点的需求量时,生产就会不可实现,就必须通过减少和延后培养池生产的方法来作调整,进而整个生产系统的产能下降,导致单位产品的人力、物力、财力的消耗升高,进而导致成本上升。 When a certain production [0008] However, this calculation is undoubtedly wrong, but made the best of the total consideration, the actual production must take into account the maximum supply capacity of a production system input factors, such as non-scientific planning time point there needs to serve a plurality of culture containers at the same time the carbon source, the other node also require more time to ensure power supply to operate the device, the ability to serve as a carbon source for the entire plant is less than the power supply capacity demand time points production will not be achieved, it must be adjusted by means of reducing production and delayed training pool, thereby producing the whole production system can be decreased, resulting in human, material and financial resources consumption per unit of product increases, leading to rising costs.

Figure CN103911320BD00041

[0010] 式中: [0010] wherein:

[0011] ?8^13^(3^(1分别为关键限制性生产要素&、要素13、要素(3、要素(1。 [0011]? 8 ^ 13 ^ (3 ^ (1 were limiting factors of production & critical, element 13, element (3, element (1.

[0012] 当培养容器为开放式养殖池时,不可避免的受台风等恶劣天气影响,就需要对正在生产的培养池和已计划生产的培养池作调整,但哪怕就是一个培养池的生产计划调整, 对总的生产系统来说涉及到的物资、电力、人力等因素就会有调整,更何况有多个培养池进行计划调整。 [0012] When the culture vessel bad weather is an open pond, inevitably affected by the typhoon, etc., you need to make adjustments to the training pool training pool being produced and planned production, but even if it is a cell culture production plan adjustment, total production system relates to the materials, power, labor and other factors will have to adjust, not to mention there are more plans to adjust the training pool. 如何确保调整后的生产尽量减少产能损失,如何在无恶劣天气时提高产能,成为了一个极难作科学回答的问题。 How to adjust production to ensure the capacity to minimize losses, how to increase productivity in the absence of bad weather, the problem has become extremely difficult to make a scientific answer.

[0013] 只有当多培养池生产的技术和管理方法获得突破,现有的工业化目标才有实现的可能。 [0013] possible only when the multi-culture techniques and management methods of producing breakthrough pool, existing only to achieve the goal of industrialization. 产量进一步扩大,规模化低成本的生产微生物生物质产品才能最终解决此类产品质优但价高的难题,才能让饲料行业成功应用优质低价的微生物产品。 To further expand the production scale low-cost production of microbial biomass products to the final settlement of such high quality products, but the problem of high prices, the feed industry to make successful application of microbiological quality low-priced products.

发明内容 SUMMARY

[0014] 为了解决上述问题,本发明提供了一种运行多个微生物生物质培养池生产的方法。 [0014] In order to solve the above problems, the present invention provides a method of operating a plurality of cell culture microbial biomass production.

[0015] 为了实现上述发明目的,本发明采用了以下技术方案:一种生物质多培养池培养方法,其特征在于包括以下步骤: [0015] In order to achieve the above object, the present invention employs the following technical solution: A cell culture biomass multiple culture method, comprising the steps of:

[0016] (1)工艺分解 [0016] (1) Decomposition Process

[0017]针对待培养生物质对单个培养池活性物质的工业化培养过程分解为几个基本工序; [0017] For culture biomass to be industrialized culture process a single cell culture active substance is decomposed into several basic steps;

[0018] (2)工序分析 [0018] (2) Step Analysis

[0019] 分析所述几个基本工序中每个工序所消耗的生产基地资源,包括电力投入、人员投入、供水需求、排水需求、物料投放需求; [0019] Analysis of the production of several basic resource base of each process step consumed, including a power input, staff input, demand for water, drainage requirements, to serve the needs of the material;

[0020] (3)负荷分析 [0020] (3) Load Analysis

[0021] 列出各工序对生产基地资源的负荷数据,根据基地的投资规模、软硬件条件、管理能力列出基本负荷与极限负荷; [0021] List load data base in each step of production resources listed according to base load and load limit investment base, hardware and software conditions, management;

[0022] (4)确定单个培养池在一个生产周期中每天的各基本工序负荷消耗; [0022] (4) determining a single cell culture step of each load substantially consumed per day in a production cycle;

[0023] (5)根据生产目标确定需要培养池的数量,通过负荷累计确定最佳方案; [0023] (5) determine the number of pools according to the need to develop production targets, the cumulative load is determined by the best solution;

[0024] (5.1)根据生产目标,确定需要n个相同的培养池,第N+1号培养池比N号培养池晚投料t天,同一个培养池前后两个生产周期相隔时间为AT天,t为0,1,2,3,,,沽的非负整数,AT为0,l,2,3,,,,j的非负整数,且N+l<n; [0024] (5.1) according to the production objectives, determines that n identical culture cell, the N + 1 cultured cell culture than the number N cell Night feeding t days, the culture two cycle apart longitudinal pool time same as AT days , t ,,, 0,1,2,3 put the non-negative integer, the AT is 0, l, 2,3 ,,,, nonnegative integer j, and N + l <n;

[0025] (5 • 2)依次计算当t=0,1,2,3,,,,k时,AT=0,1,2,3,,,,j时,的非负整数对生产周期的每天内从1号培养池到n号培养池的各项基本工序负荷消耗进行累计,得到每天内n个培养池各项基本工序的总负荷累计值; When [0025] (5 • 2) are sequentially calculated when t = 0,1,2,3 ,,,, k, AT = 0,1,2,3 ,,,, j, nonnegative integer production cycle the basic step in the cell culture every day from No. 1 to No. n consumption load cell culture accumulates, the basic procedure to obtain the total load of the cell culture integrated value of n within a day;

[0026] (5 • 3)比较t=0,1,2,3,,,,k及AT=0,1,2,3,,,,j时,步骤5 • 2所得到的各组总负荷累计值,确定最佳的方案。 [0026] (5 • 3) Comparison t = 0,1,2,3 ,,,, k and AT = 0,1,2,3 ,,,, j, the step 5 • each group was obtained 2 load accumulated value, to determine the best solution.

[0027] 具体来说,所述生物质为微藻和细菌的微生物混合群,所述混合群是微藻、硅藻、 酵母、真菌、原生生物、小型浮游生物和细菌的絮凝物。 [0027] Specifically, the microalgal biomass mixed population of bacteria and microorganisms, the mixed population is a microalga, diatoms, yeasts, fungi, protists, bacteria and plankton small flocs.

[0028]具体来说,所述生物质来源于根据公布号为CN102016001A的中国发明专利申请所记载方法而获得的微生物生物质。 [0028] Specifically, the raw material derived from a microbial biomass according to the Publication No. CN102016001A Chinese invention patent application describes a method obtained.

[0029]进一步地,所述生物质多培养池培养方法,包括以下步骤: [0029] Further, the multi-culture cell culture biomass, comprising the steps of:

[0030] (1)工艺分解; [0030] (1) decomposition process;

[0031] 针对待培养生物质对单个培养池活性物质的工业化培养过程包括以下几个基本工序:注水、初次投养料、初次培养、二次投养料、投碳源、培养、排水、抽取物料,每个工序列出对应的英文描述及字母标识,分解后的工艺可以使用字母标识来完整描述生产流程; [0032] (2)工序分析; [0031] For industrial be cultured biomass culture process for a single cell culture active material includes the following basic steps: injection, the initial investment and nutrients, primary culture, secondary nutrients cast, cast carbon source, culture, drain, extraction materials, each step is described and listed in the corresponding English letter designation after the decomposition process can be fully described using the letter designations production process; [0032] (2) analysis of step;

[0033] (3)负荷分析; [0033] (3) Analysis of the load;

[0034]列出各工序对生产基地资源的负荷数据,根据基地的投资规模、软硬件条件、管理能力列出基本负荷与极限负荷; [0034] List load data base in each step of production resources listed according to base load and load limit investment base, hardware and software conditions, management;

[0035] (4)确定单个培养池在一个生产周期中每天的各基本工序负荷消耗; [0035] (4) determining a single cell culture step of each load substantially consumed per day in a production cycle;

[0036] (5)根据生产目标确定需要培养池的数量,通过负荷累计确定最佳方案; [0036] (5) determine the number of pools according to the need to develop production targets, the cumulative load is determined by the best solution;

[0037] (5.1)根据生产目标,确定需要n个相同的培养池,第N+1个培养池比N号培养池晚投料t天,t为0,1,2,3,,,,k的非负整数,且N+l < n, [0037] (5.1) according to the production objectives, determines that n identical cell culture, the culture of the N + 1 cell culture inserts number later than N days feeding t, t is 0,1,2,3 ,,,, k the non-negative integer, and N + l <n,

[0038] (5.2)依次计算当t=0,1,2,3,,,,k时,对生产周期的每天内从1号培养池到n号培养池的各项基本工序负荷消耗进行累计,得到每天内n个培养池各项基本工序的总负荷累计值; When [0038] (5.2) followed by calculation when t = 0,1,2,3 ,,,, k, the production cycle to consume the basic step number n load cell culture in cell culture 1 day from accumulating give the n-th day, the cell culture process is substantially integrated value of the total load;

[0039] (5.3)比较丨=0,1,2,3,,,沽时,步骤5.2所得到的各组总负荷累计值,根据以下原则确定最佳的方案: [0039] (5.3) Comparative Shu = 0,1,2,3,, when put, the total load of each group obtained in step 5.2 accumulated value, to determine the best solution based on the following principles:

[0040] A.-个生产周期内各项基本工序的负荷波动平缓; The [0040] A.- production cycle step of the basic load fluctuation gentle;

[0041] B. -个生产周期内各项基本工序的负荷没有超出极限负荷; [0041] B. - Load the basic step in the production cycle of the load limit is not exceeded;

[0042] C.注水工序有部分用水可以直接使用排水工序中排出的水,因此注水量和排水量可以部分对冲,对冲率为30%~〈50%,对冲率=可对冲排水量/总进水量X 100%; [0042] C. water for injection step part may be used directly in the water discharged from the drainage step, water injection and thus displacement may be partially hedge hedge 30% to <50%, of a hedge = hedge against displacement / total amount of water X 100%;

[0043] D.人员投入的工作时间和物料投放均需要考虑满足在上限值和下限值范围之内。 [0043] D. personnel into work time and material release are to be considered to meet within the upper limit and lower limit range.

[0044] 进一步地,所述步骤4还包括根据各基本工序负荷消耗绘制负荷曲线,用于反映整个生产基地运行的各种负荷的高低。 [0044] Further, the step 4 further comprises a consumption load curves plotted according to each of the basic process load, for various loads reflect the level of the entire production run of bases.

[0045] 优选地,所述培养池为方形或长方形培养池,优选的长宽比为1:1~1.3:1,培养池水深:0.5~3.0米,培养水体体积为4000~30000立方米。 [0045] Preferably, the culture cell culture inserts is square or rectangular, preferably an aspect ratio of 1: 1 to 1.3: 1, culture water depth: 0.5 to 3.0 meters, the culture volume of water of 4000 to 30,000 cubic meters.

[0046] 本发明的多培养池生产的方法可以实现高效率、科学可靠的运行含有多个开放式的微生物生物质培养池的生产系统,目的是确保各项生产要素的合理规划,使得生产系统的产能最大化。 [0046] The method of producing a multi-cultured cell of the present invention can achieve high efficiency, reliable operation comprising a plurality of scientific open microbial biomass cell culture production system, in order to ensure a rational planning of production elements, such that the production system maximize capacity. 作为工业化生产,一个生产基地所能提供的电力、水力、人工、原料投放、产品加工等能力有限。 Limited as industrial production, a production base can provide the ability to electricity, water, labor, raw materials delivery, product processing. 本发明可以实现产能最大化与基地有限生产能力之间的协调关系,使生产充分体现在基地现有能力的最大产能。 The present invention may be implemented to coordinate the relationship between the base and maximize the limited production capacity and production, the production capacity of the largest fully reflected in the base of existing capacity. 本发明为超大规模培养池这一新的微生物生物质生产基础解决了工业化生产主要问题。 The present invention is a super-large-scale cultivation of this new pool of microbial biomass production base materials for industrial production to solve the main problem. 证明了开放式室外超大规模培养池能够进行工业化、高产量生产微生物生物质的可行性。 Demonstrate an open outdoor pool ultra large-scale cultivation can be industrialized, high-volume production feasibility microbial biomass. 降低了设厂选址的难度,降低了固定资产投入。 Reduces the difficulty of siting factories, reduced investment in fixed assets. 微生物生物质培养所需的水源、养料、碳源投放实现了机械化、自动化、管道运输,工业化实现程度高,节省了大量的人力设备投入。 Microbial biomass training required for water, nutrients, carbon source put in to achieve a high mechanization and automation, pipeline transportation, to achieve the degree of industrialization, saving a lot of manpower and equipment investment. 解决了工业化生产的多培养池连续生产问题,使得拥有10~30个超大规模培养池的工厂的产能可以最大化。 To solve the industrial production of continuous multi-cultured cell production problems that have produced 10 to 30 ultra-large-scale cultivation of the plant cell can be maximized. 降低了运行成本、显著提高了产量, 实现了真正意义上的工业化、规模化。 Reducing operating costs and significantly improve productivity, achieve industrialization, large-scale in the true sense.

[0047]本发明虽然是以公布号为CN102016001A的中国发明专利申请所记载方法而获得的微生物生物质的培养为例,但其总体思想同样适用于微生物领域的工业化培养。 [0047] Although the present invention is based on Patent Application Publication No. CN102016001A the method described in Chinese invention, the microbial biomass obtained by culture of an example, but the general idea is equally applicable to the industrial field of microbial culture.

附图说明 BRIEF DESCRIPTION

[0048]图1是本发明的原理图。 [0048] FIG. 1 is a schematic view of the invention.

[0049] 图2是养料输送管道连接示意图,其中1为养料溶解罐。 [0049] FIG 2 is a connection diagram nutrient delivery conduit, wherein 1 is a dissolution tank nutrients.

[0050] 图3是碳源输送管道连接示意图,其中2为碳源溶解罐。 [0050] FIG. 3 is a schematic view of a carbon source is connected delivery conduit, wherein the dissolving tank 2 as the carbon source.

[0051 ]图4是物料收取输送管道连接示意图,其中3为半成品储存罐。 [0051] FIG. 4 is a schematic view of the connection pipeline charged material, wherein the semi-finished product 3 is a storage tank.

[0052]图5是当N+1号培养池比N号培养池晚投料一天时的负荷累计图表。 [0052] FIG. 5 is N + 1 when cultured cell culture load pool feed one day later than the total number graph N.

[0053]图6为实施例1规划方案表格。 [0053] FIG. 6 is a plan Table 1 Example embodiment.

[0054]图7为实施例1的负荷曲线图。 [0054] FIG. 7 is a graph showing an example of a load 1 embodiment.

[0055]图8为实施例2规划方案表格。 [0055] Example 2 FIG. 8 is a plan tables embodiment.

[0056]图9为实施例2的负荷曲线图。 [0056] FIG. 9 is a load curve of the embodiment of FIG. 2 embodiment.

具体实施方式 detailed description

[0057]本发明是以发明专利(CN102016001A)中所涉及的产物微生物生物质作为培养对象。 [0057] The present invention is based on the microbial biomass product Patent (CN102016001A) involved in the invention as a culture object.

[0058] 本发明采用多个培养池共同对微生物质进行培养。 [0058] The present invention employs a plurality of common cell culture of microbial biomass is cultured. 作为优选,所述培养池为方形或长方形培养池,优选的长宽比为1:1~1.3:1。 Advantageously, the culture cell culture inserts is square or rectangular, preferably an aspect ratio of 1: 1 to 1.3: 1. 培养池水深:0.5~3.0米,1~2.5米,1.5~ 2.0米。 Culture water depth: 0.5 to 3.0 m, 2.5 m ~ 1, 1.5 to 2.0 meters. 培养水体体积:4000~30000立方米。 Water culture volume: 4000 - 30000 m3. 培养池要求:池底及池壁使用水泥进行硬化,池底可为水泥底面、HDPE膜或PP膜底面。 Cell culture requirements: the bottom and the wall hardened cement, the cement may be the bottom surface of the bottom, HDPE or PP film bottom surface of the film.

[0059] 作为优选,所述多个培养池共同使用供电设备、管道,集中投放养料碳源。 [0059] Advantageously, the plurality of power supply apparatus commonly used cell culture, pipes, carbon source nutrients serve concentrated. 使用管道将所有培养池连接,共三套管道连接系统。 All cultures using the pipe connection pools, three common pipe joining system.

[0060] 本发明的多培养池培养方法包括以下步骤: [0060] Multi-culture cell culture method of the present invention comprises the steps of:

[0061] (1)工艺分解; [0061] (1) decomposition process;

[0062] 工艺分解是指对单个培养池活性物质的工业化培养过程分解为几个基本工序,工艺分解的原则为:各项生产要素的最佳化利用;各项生产要素分解后的可重复性,可以进行标准化操作;分解后的工艺能发挥生产要素的能力;能满足工艺改进、特殊要求。 [0062] The decomposition process of industrialization culture process refers to a single cell culture active substance into several basic step, the process is decomposed principles: optimum utilization of the factors of production; various factors of production after decomposition repeatability , the operation can be standardized; decomposition process can play the factors of production capacity; improved process to meet special requirements.

[0063]依据以上原则,本发明将单个培养池活性物质的工业化培养过程分解为以下几个基本工序:注水、初次投养料、初次培养、二次投养料、投碳源、二次培养、排水、抽物料。 Industrial culture processes [0063] Based on the above principles, the present invention is a single cell culture active substance is decomposed into the following basic steps: injection, the initial investment and nutrients, primary culture, secondary nutrients cast, cast carbon source, secondary culture, drainage , pumping materials. 每个工序列出对应的英文描述及字母标识。 Each step is described and listed in the corresponding English letter designation. 分解后的工艺可以使用字母标识来完整描述生产流程。 After the decomposition process may use letter designations to complete the production process is described. 具体如下表1 The following table 1

[0064]表1 [0064] TABLE 1

Figure CN103911320BD00071

[0066] 单个培养池典型的生产周期工艺描述可以使用字母标识描述为下表2。 [0066] A typical single cell culture process cycle described letter designations may be used as described in Table 2. (以天为单位) (In days)

[0067] 表2 [0067] TABLE 2

Figure CN103911320BD00072

[0069] (2)工序分析; [0069] (2) Analysis of step;

[0070] 工序分析是指分析步骤1中的几个基本工序,每个工序所消耗的基地资源。 [0070] Step analysis refers to several basic resource base analysis step is step 1, each step consumed. 活性物质培养过程所需的生产基地资源包括:电力投入、人员投入、供水需求、排水需求、物料投放需求、产品收取。 Production base of active material resources required training process includes: power input, staff input, demand for water, drainage requirements, material delivery requirements, product fee.

[0071 ]这些需求的特点为:可进行操作标准化、规范化;基地的支持能力有限,不能无限扩大;可以不断改进,不断提高效率、降低消耗。 [0071] characteristics of these needs is: can operate standardization; limited base of support capabilities, can not be unlimited expand; can continue to improve, continue to improve efficiency and reduce consumption.

[0072] 工业化培养需要的资源及其分析如下表3。 [0072] and their resource requirements industrialized cultures as follows in Table 3.

[0073] 表3 [0073] TABLE 3

Figure CN103911320BD00073

[0075] [0075]

Figure CN103911320BD00081

[0076] (3)负荷分析; [0076] (3) Analysis of the load;

[0077]所述负荷分析是研究一个已知生产基地的各项资源所能承受的生产负荷,列出的负荷数据与即将计划的生产规划的总负荷作对比,通过检查调整为切实可行的生产规划。 [0077] The load analysis is the study of a known resource base of production can bear the production load, load data listed in the total load of the upcoming program of production planning for comparison by checking adjusted to practical production planning. [0078]根据生产基地的投资规模、软硬件条件、管理能力列出基本负荷与极限负荷。 [0078] According to the investment scale production base, hardware and software conditions, the ability to manage lists basic load and load limit. 见下表4。 Table 4 below. 工序的负荷分析见表5。 Table 5 Load step analysis.

Figure CN103911320BD00082

Figure CN103911320BD00091

[0084] (4)确定单个培养池在一个生产周期中每天的各工序负荷消耗; [0084] (4) determining a single cell culture in each step a load consumption per day production cycle;

[0085] 根据表5中的工序负荷分析列出的数据制定单个培养池在一个生产周期中每天的各工序负荷数据表,见下表6。 [0085] The development of a single cell culture in each step a load data tables per day production cycle, the step load the data in Table 6 below in Table 5 the analysis are listed.

[0086] 表6 [0086] TABLE 6

Figure CN103911320BD00092

[0088] (5)根据生产目标确定需要培养池的数量,通过负荷累计确定最佳方案。 [0088] (5) determine the number of pools according to the need to develop production target cumulative best determined by the load.

[0089] 根据生产目标确定需要多少培养池,然后进行规划。 [0089] How much training pool is determined according to the needs of production goals, then plan accordingly. 例如,依据生产目标确定需要20个培养池,每个培养池大小相同,所需用料及培养周期等也完全相同。 For example, according to the production needs determined target 20 culture pools, each pool of the same size culture, the culture period required materials and the like are also the same. 由于在培养周期内的每一天的消耗是不同的,因此如果20个培养池为同时投料培养时,能量消耗为一个培养池某一天能耗的20倍,这无疑是低效率、高耗能的做法。 Since the consumption per day and the culture period is different, so if the culture tank 20 simultaneously feeding culture, the energy consumption of a culture tank 20 times a day energy consumption, this is inefficient, high energy consumption practice. 因此,考虑不同的培养池错开投料时间。 Therefore, considering the different culture pool stagger feeding time. N+1号培养池比N号培养池晚投料t天,t可以是1,2,3,,,,等自然数。 N + 1 cell culture cell culture feed later than N number day t, t may be a natural number 1, 2, ,,,,.

[0090] 当t=l时,即N+1号培养池比N号培养池晚投料1天,计算20个培养池每天所需的电力负荷、工人数量、养料一用量、养料二用量、碳源用量、注水量及排水量。 [0090] When t = l, i.e., N + 1, cultured cell feed one day than the number N culture pool night, calculates a power load 20 culture pools required per day, number of workers, nutrients an amount of nutrients two amounts, carbon The amount of the source, water injection and displacement. 从而计算每天内20个培养池各项消耗的总负荷累计值。 Thereby calculating the 20 day cell culture and the consumption of the integrated value of the total load. 统计计算培养池负荷数据,即电力每日总负荷、工人工时每日总负荷、养料每日总投入、碳源每日总投入、抽排水每日处理量。 Statistical data calculation load cell culture, i.e. a daily total power load, the total daily work load of the workers, the total daily nutrient inputs, the total daily into carbon, the amount of daily treatment drainage pump.

[0091]又,当t=2时,即N+1号培养池比N号培养池晚投料2天,计算20个培养池每天所需的电力负荷、工人数量、养料一用量、养料二用量、碳源用量、注水量及排水量。 [0091] and, when t = 2, i.e., N + 1, cultured cell culture than the number N cell Night feeding two days, computing power load 20 culture pools required per day, number of workers, nutrients an amount of nutrients two dosage , the amount of carbon, water injection and displacement. 从而计算每天内20个培养池各项消耗的总负荷累计值。 Thereby calculating the 20 day cell culture and the consumption of the integrated value of the total load. 可参照图2所示。 Referring to Figure 2 can be. 图中,横坐标为日期,纵坐标为培养池编号。 Diagram, the abscissa is the date, cell culture ordinate numbers.

[0092]同理,计算t=3或以上时,每天内20个培养池各项消耗的总负荷累计值。 When [0092] Similarly, the calculated t = 3 or more, the total load of the cell culture day 20 the consumption accumulated value.

[0093]另外,由于全年的生产日期约为300天,每个培养池在完成一个生产周期后可以准备进入下一个生产周期。 [0093] Further, since the production date is about 300 days of the year, each cell culture after completion of a production cycle may be ready for the next production cycle. 同一培养池前后2个生产周期之间的相隔时间为AT,AT可以是1, 2,3,,,,等自然数。 Culturing the same cell before and after the separated time between two cycles of production AT, AT can be 1, 2, 3 ,,,, natural number. AT的时间同样是需要考虑在内的。 AT the same time it needs to be considered, including.

[0094] 比较t=l、t=2、t=3……以及AT=1、AT=2、AT=3,,,,的各种组合时每天内20个培养池各项消耗的总负荷累计值,确定最佳的方案。 [0094] Comparative t = l, t = 2, t = 3 ...... total load and AT = 1, AT = 2, when various combinations of 3 ,,,, = consumption within a day of the culture tank 20 AT cumulative value, determine the best solution.

[0095] 还可以进一步绘制负荷曲线,用于反映整个生产基地运行的各种负荷的高低,直观观察和比较各个负荷的高低程度。 [0095] The load curve can be drawn further, for various loads with the level of reflection of the level of the entire production run base, visual observation and comparison of the individual load.

[0096] 在确定最佳方案时,考虑以下原则: [0096] In determining the best solution, consider the following guidelines:

[0097] 1.判断各项消耗是否波动平缓。 [0097] 1 determines whether the consumption smooth movements.

[0098] 2.看各项消耗是否超出极限负荷。 [0098] 2. To see if the consumption exceeds the limit load.

[0099] 3.由于每天都有注水量和排水量,而注水工序在某些情况下可以直接使用从培养池排出的水,因此注水量和排水量可以部分抵冲,从而大大减小水的用量。 [0099] 3. Since both injection and displacement of water per day, and in some cases water step can be directly discharged from the culture pond water, so water injection and may be partially offset the displacement, thereby greatly reducing the amount of water. 对冲率为30%~〈 50%,(对冲率=可对冲排水量/总进水量X 100%。 Hedge 30% to <50%, (available hedge hedge displacement rate = / total amount of water X 100%.

[0100] 4.需要工人的工作时间和养料养料一、养料二、碳源均需要考虑满足在上限值和下限值范围之内,否则造成资源的浪费。 [0100] 4. The need for workers to work a time and nourishment nourishment, nourishment Second, the carbon source to meet all needs to be considered within the upper and lower limits, otherwise a waste of resources.

[0101] 综合各项因素,比较后确定最佳的t值、AT值。 [0101] Integrated various factors, comparison to determine the optimum values ​​of t, AT value.

[0102] 实施例1 [0102] Example 1

[0103] 工艺分解 [0103] Decomposition Process

[0104] 本例共设置有30个培养池,以3 X 10的方式排列。 [0104] The present embodiment is provided with a total of 30 culture pools, as to arrangement of 3 X 10.

[0105] 单个培养池活性物质的工业化培养过程可以分解为以下几个工序:注水、初次投料、初次培养、二次投养料、投碳源、培养、排水、抽物料。 [0105] a single cell culture active substance industrial culture processes can be decomposed into the following steps: injection, the initial feed, primary culture, secondary nutrients cast, cast carbon source, culture, drainage and pumping the material.

[0106] 生产周期工艺使用字母标识如表2所示。 [0106] process using a production cycle letter designations shown in Table 2. (以天为单位) (In days)

[0107] 表2 [0107] TABLE 2

Figure CN103911320BD00101

[0109] 工序分析 [0109] Step Analysis

[0110]分析工序消耗生产基地资源的主要需求。 [0110] analysis of the main production base of the consumption needs of process resources. 活性物质培养过程所需的需求包括:电力投入、人员投入、供水需求、排水需求、物料投放需求。 Required for the active substance culture process needs include: power input, staff input, demand for water, drainage requirements, material delivery requirements. 负荷分析 Load analysis

[0112] 3 X 10规划的生产基地的负荷数据见下表7。 [0112] Load data base 3 X 10 production planning Table 7 below.

[0113] 表7 [0113] TABLE 7

Figure CN103911320BD00111

[0115] 以培养池面积为6000平米,注水量10000立方米,8台增氧设备,2台搅拌设备计算。 [0115] In cell culture area of ​​6,000 square meters, 10,000 cubic meters of water injection, eight oxygen equipment, computing device 2 with stirring. 工序的负荷数据见下表8。 Step 8 payload data in the table below.

[0116] 表8 [0116] TABLE 8

Figure CN103911320BD00112

[0118]以中国广东地区气温较高的月份确定生产时间,从3月1日开始,12月25日结束,共300天。 [01] determined at a higher temperature in January China Guangdong region production time, beginning from March 1, ending December 25, a total of 300 days.

[0119]培养池养殖顺序从1#池开始依次至30#池。 [0119] culture ponds and pools in order from # 1 to 30 # sequentially pool. 以Excel表格作为工具与表达形式。 In Excel spreadsheets as tools and forms of expression. 示意图以日期/序号为横坐标,以培养池编号作为纵坐标。 Schematic date / number as the abscissa, in order to cultivate cell number as ordinate. 工作区用于规划各个培养池的周期。 Planning work area for each training cycle pool. 编制的30个池的计划。 Establishment of 30 pool plan. 制定的计划方式为:开始培养每个培养池每隔3天开始进行,从1# 培养池至30#池,期间,第44天1#培养池生产结束,8天后仍以每隔3天的频率开始第二次1# ~30#培养池的生产。 Plan developed for the way: each culture began training pool every three days to start from 1 # to 30 # pool training pool, during the first 44 days # 1 cell culture production end, still 8 days every 3 days frequency # 30 started producing a second culture cell # 1 ~.

[0120]根据初步制定的规划,计算每个日程的主要负荷数据。 [0120] According to the preliminary plan developed to calculate the main load data for each schedule. 统计计算进入规划的培养池负荷数据,即电力每日总负荷、工人工时每日总负荷、养料每日总投入、碳源每日总投入、 抽排水每日处理量。 Statistical data is calculated into the culture tank load planning, that is, the total daily power load, the total daily load of workers working hours, daily nourishment total investment, the total daily carbon investment, drainage pumping daily handling capacity. 如图6所示。 As shown in Figure 6.

[0121]将统计后的各项负荷制作成曲线图,用于反映整个生产基地运行的各个要素的负荷能力的高低,直观观察和比较各个负荷的高低程度。 [0121] The load after the statistics made into a graph, a height, visually observed and compared with the level of reflection of the respective load throughout the production run base load capacity of the various elements. 如图7所示。 As shown in FIG.

[0122] 通过负荷曲线参考下表9分析判断所制定的规划是否科学合理,是否具有可操作性,是否可以进行分工安排,是否可实现。 [0122] By reference to the load curve analysis to determine whether the table 9 developed by scientific and rational planning, whether operational, whether the division may be arranged, if achievable.

[0123] 表9 [0123] Table 9

[0124] [0124]

Figure CN103911320BD00121

[0125] 从负荷对照表及负荷曲线图综合分析判断,此生产规划的平均负荷与最高负荷都没有超出基地的基本负荷与极限负荷,说明此生产方式不会对管理造成压力,减少了混乱出错的风险。 [0125] from a comprehensive analysis of the load table and graphs to determine the load, average load this production planning with maximum load and base load did not exceed the base limit load, indicating that this production will not put pressure on management to reduce the confusion error risks of.

[0126] 各项负荷是逐步平缓提高并稳定,没有空闲与满负荷运行的较大反差。 [0126] gently and gradually increase the load is stable and there is no greater contrast between idle and full load operation.

[0127]制定的规划的负荷能力低于基本负荷,有一定调整空间,有进一步广能提尚的空间。 Load capacity [0127] Whereas plans is lower than the base load, there is some room for adjustment, there is still further Guangneng mention of space.

[0128] 日程编制 [0128] the preparation of the agenda

[0129] 在规划完成后即得出在生产周期内的总产量,根据负荷数据表以一个月为单位分别制定,电力、人力、养料采购库存、碳源采购库存、抽排水等的计划。 [0129] results in the total production cycle after the plan is completed in order to develop each month as a unit based on load data tables, electricity plans, human resources, procurement inventory nutrients, carbon stocks of purchases, such as pumping and drainage. 生产的目标即以完成计划为重点。 Production target that is to complete the plan as the focus.

[0130] 实施例2 [0130] Example 2

[0131] 本例中的培养池设置有30个,以3X10的方式排列。 [0131] cell culture in the present embodiment is provided with 30, arranged in a manner 3X10.

[0132] 工艺分解 [0132] Decomposition Process

[0133] 单个培养池活性物质的工业化培养过程可以分解为以下几个工序:注水、初次投料、初次培养、二次投养料、投碳源、培养、排水、抽物料。 [0133] The single cell culture active substance industrial culture processes can be decomposed into the following steps: injection, the initial feed, primary culture, secondary nutrients cast, cast carbon source, culture, drainage and pumping the material.

[0134] 工序分析 [0134] Step Analysis

[0135] 分析工序消耗生产基地资源的主要需求。 [0135] analysis of the main production base of the consumption needs of process resources. 活性物质培养过程所需的需求包括:电力投入、人员投入、供水需求、排水需求、物料投放需求、产品收取。 Required for the active substance culture process needs include: power input, staff input, demand for water, drainage requirements, material delivery requirements, product fee.

[0136] 负荷分析 [0136] Load Analysis

[0137] 3 X 10规划的生产基地的负荷数据见下表10。 [0137] Base Load data production plan table below 3 X 10 10.

[0138] 表1〇 [0138] Table 1〇

Figure CN103911320BD00131

[0140] 以培养池面积为6000平米,注水量10000立方米,8台增氧设备,2台搅拌设备计算。 [0140] In cell culture area of ​​6,000 square meters, 10,000 cubic meters of water injection, eight oxygen equipment, computing device 2 with stirring. 工序的负荷数据见下表11。 Step 11 loads data in the table below.

[0141] 表11 [0141] Table 11

Figure CN103911320BD00132

[0143] 根据工序负荷分析列出的数据制定典型生产工艺及其负荷数据表。 [0143] Typical production processes and the development of load data table according to the data listed load analysis step.

[0144] 以中国广东地区气温较高的月份确定规划时间,从3月1日开始,12月25日结束,共300天。 [0144] at a high temperature in January China Guangdong region to determine the planning period, beginning from March 1, ending December 25, a total of 300 days.

[0145] 规划的培养池养殖顺序从1 #池开始依次至30#池。 Culture ponds sequence [0145] Programming the cell # 1 to 30 # sequentially pool.

[0146] 以Excel表格作为工具与表达形式。 [0146] As an Excel spreadsheet tools and forms of expression. 不意图以日期/序号为横坐标,以培养池编号作为纵坐标。 Not intended to date / number as the abscissa, in order to cultivate cell number as ordinate. 工作区用于规划各个培养池的周期。 Planning work area for each training cycle pool.

[0147] 编制的30个池的计划初稿见图8所示。 [0147] The preparation of cell 30 shown in Figure 8. Program Preliminary.

[0148] 制定的计划方式为:开始培养每个培养池每隔2天开始进行,从1#培养池至30#池, 期间,第44天1#培养池生产结束,2天后仍以每隔2天的频率开始第二次1#~30#培养池的生产。 [0148] plans to develop ways to: Start each training pool training starts every two days, from 1 to 30 # # culture pond pool, during the first 44 days # 1 end of the incubation cell production, still every 2 days 2 days start the second frequency # 1 ~ # 30 produced cell culture.

[0149] 根据初步制定的规划,计算每个日程的主要负荷数据。 [0149] According to the preliminary plan developed to calculate the main load data for each schedule. 统计计算进入规划的培养池负荷数据,即电力每日总负荷、工人工时每日总负荷、养料每日总投入、碳源每日总投入、 抽排水每日处理量。 Statistical data is calculated into the culture tank load planning, that is, the total daily power load, the total daily load of workers working hours, daily nourishment total investment, the total daily carbon investment, drainage pumping daily handling capacity. 以表格形式表不。 Table is not in tabular form.

[0150]将统计后的各项负荷制作成曲线图,用于反映整个基地运行的各个要素的负荷能力的高低,直观观察和比较各个负荷的高低程度。 [0150] The load after the statistics made into a graph, the level of load capacity for each base element to reflect the entire operation, and comparison with the level of visual observation of the individual load. 如图9所示。 9 shown in FIG.

[0151]通过负荷曲线分析判断所制定的规划是否科学合理,是否具有可操作性,是否可以进行分工安排,是否可实现。 [0151] By the load curve analysis to determine whether the development of scientific and rational planning, whether operational, whether the division of labor arrangements, whether realized.

[0152] 从负荷对照表12及负荷曲线图图9综合分析判断,此生产规划的平均负荷与最高负荷都没有超出基地的基本负荷与极限负荷,说明此生产方式不会对管理造成压力,减少了混乱出错的风险。 [0152] From a comprehensive analysis of the load table 12 and the load curve of FIG. 9 is determined, this average load of maximum load and production planning are not substantially exceed the limit load and base load, this description will not cause pressure on the production management, reducing confusion risk of error.

[0153] 表12 [0153] Table 12

Figure CN103911320BD00141

[0155] 各项负荷是逐步平缓提高并稳定,没有空闲与满负荷运行的较大反差。 [0155] gently and gradually increase the load is stable and there is no greater contrast between idle and full load operation.

[0156] 此规划的另一个优点是当某一个培养池需要注水时会有另一个培养池需要排水, 两者正好可以对冲。 Another advantage of [0156] Programming of this is that when a need for a culture pool water drainage needs to be another cell culture, just two hedge. 进而可以节约用水。 Further water can be saved.

[0157] 在各项负荷没有超过生产基地基本负荷的情况下,培养池规划的生产周期密度有所提尚,提尚了各项生广负荷,说明计划切实可彳丁,可以完成并实施。 [0157] In the load does not exceed the basic production base load conditions, the production cycle training pool planning density has mentioned yet, still put a wide load the raw, realistic plan can be explained Ding left foot, can be completed and implemented.

[0158] 日程编制 [0158] the preparation of the agenda

[0159] 在规划完成后即得出在生产周期内的总产量,根据负荷数据表以一个月为单位分别制定,电力、人力、养料采购库存、碳源采购库存、抽排水等的计划。 [0159] results in the total production cycle after the plan is completed in order to develop each month as a unit based on load data tables, electricity plans, human resources, procurement inventory nutrients, carbon stocks of purchases, such as pumping and drainage. 生产的目标即以完成计划为重点。 Production target that is to complete the plan as the focus.

Claims (4)

  1. 1. 一种生物质多培养池培养方法,其特征在于包括以下步骤: (1) 工艺分解针对待培养生物质对单个培养池活性物质的工业化培养过程分解为几个基本工序:注水、初次投养料、初次培养、二次投养料、投碳源、培养、排水、抽取物料,每个工序列出对应的英文描述及字母标识,分解后的工艺使用字母标识来完整描述生产流程; (2) 工序分析分析所述几个基本工序中每个工序所消耗的生产基地资源,包括电力投入、人员投入、 供水需求、排水需求、物料投放需求; (3) 负荷分析列出各工序对生产基地资源的负荷数据,根据基地的投资规模、软硬件条件、管理能力列出基本负荷与极限负荷; (4) 确定单个培养池在一个生产周期中每天的各基本工序负荷消耗; (5) 根据生产目标确定需要培养池的数量,通过负荷累计确定最佳方案; (5.1) 根据生产目标,确定 A cell culture biomass multiple culture method, comprising the steps of: (1) for the decomposition process to be industrialized culture biomass cultivation process single cell culture active substance is decomposed into a few basic steps: injection, the initial investment nutrients, primary culture, secondary nutrients cast, cast carbon source, culture, drain, extraction materials, each step is described and listed in the corresponding English letter identification process using the decomposed letter designations to a complete description of the production process; (2) analysis of resource production step of the base of each process step several substantially consumed, including a power input, staff input, demand for water, drainage requirements, to serve the needs of the material; (3) analysis of the load of each process are listed in the resource base production loading data, are listed in accordance with the basic load and load limit investment base, hardware and software conditions, management; (4) determining a single cell culture step of each load substantially consumed in one day production cycle; (5) the production objectives determining the number of pools need to develop, the cumulative load is determined by the best solution; (5.1) according to the production objectives, it is determined 需要η个相同的培养池,第N+1号培养池比N号培养池晚投料t 天,同一个培养池前后两个生产周期相隔时间为AT天,t为0,1,2,3,,,沽的非负整数,八丁为〇,l,2,3,,,,j的非负整数,且N+l<n; (5.2) 依次计算当七=0,1,2,3,,,汰时,六1 = 0,1,2,3,,,,」时,的非负整数对生产周期的每天内从1号培养池到η号培养池的各项基本工序负荷消耗进行累计,得到每天内η个培养池各项基本工序的总负荷累计值; (5.3) 比较t = 0,1,2,3,,,,k及Δ Τ = 0,1,2,3,,,,j时,步骤5.2所得到的各组总负荷累计值,按以下原则确定最佳的方案: A. -个生产周期内各项基本工序的负荷波动平缓; B. -个生产周期内各项基本工序的负荷没有超出极限负荷; C. 注水工序有部分用水直接使用排水工序中排出的水,因此注水量和排水量部分对冲,对冲率为30 %~< 50 %, Requires η identical cell culture, the N + 1 cell culture cell culture days later than t feed number N, the same production cycle two spaced apart longitudinal culture time was pool AT days, t is 0, 1, Put ,, nonnegative integer, T is the eight billion, l, 2,3 ,,,, nonnegative integer j, and N + l <n; (5.2) followed by calculation when seven = 0,1,2,3, ,, while eliminating, 0,1,2,3 ,,,, = 1 when six "non-negative integer in the daily production cycle from cell culture No. 1 to No. η cell culture load the basic step for consumption total, per day to give the η fundamental step a cultured cell integrated value of the total load; (5.3) Comparative t = 0,1,2,3 ,,,, k and Δ Τ = 0,1,2,3 ,, ,, j, the total load of each group obtained in step 5.2 accumulated value, to determine the best solution according to the following principles: A. - the basic load fluctuations in the production process of a gentle cycle; B. - within each production cycle load items does not exceed the substantially limit load step; C. direct injection step some water drainage water discharging step, water injection and the displacement portions so hedge hedge 30% to <50%, 冲率=对冲排水量/总进水量X 100 % ; D. 人员投入的工作时间和物料投放均需要考虑满足在上限值和下限值范围之内。 = Displacement rate hedge red / total amount of water X 100%; D. staff input work time and material needs to be considered to satisfy delivery in both the upper and lower limits of the range.
  2. 2. 根据权利要求1所述的生物质多培养池培养方法,其特征在于:所述生物质为微藻和细菌的微生物混合群。 2. The biomass according to claim more than one culture cell culture method, wherein: the biomass of microalgae and microorganisms in a mixed population of bacteria.
  3. 3. 根据权利要求1所述的生物质多培养池培养方法,其特征在于:步骤4还包括根据各基本工序负荷消耗绘制负荷曲线,用于反映整个生产基地运行的各种负荷的高低。 3. The biomass according to claim more than one culture cell culture method, wherein: the step 4 further comprises a consumption load curves plotted according to each of the basic process load, for various loads reflect the level of the entire production run of bases.
  4. 4. 根据权利要求1所述的生物质多培养池培养方法,其特征在于:所述培养池为方形或长方形培养池,长宽比为1:1~1.3:1,培养池水深:0.5~3.0米,培养水体体积为4000~ 30000立方米。 4. The biomass according to more than one cell culture method as claimed in claim culture, wherein: the cell culture is a culture square or rectangular pools, an aspect ratio of 1: 1 to 1.3: 1, culture water depth: 0.5 3.0 m, the culture volume of water of 4000 to 30,000 cubic meters.
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Citations (2)

* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101689045A (en) * 2007-05-14 2010-03-31 搭篷技术公司 Nonlinear model predictive control of a biofuel fermentation process
CN102016001A (en) * 2008-04-30 2011-04-13 联邦科学和工业研究组织 Microbial biomass, feed product/ingredient and processes for production thereof

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* Cited by examiner, † Cited by third party
Publication number Priority date Publication date Assignee Title
CN101689045A (en) * 2007-05-14 2010-03-31 搭篷技术公司 Nonlinear model predictive control of a biofuel fermentation process
CN102016001A (en) * 2008-04-30 2011-04-13 联邦科学和工业研究组织 Microbial biomass, feed product/ingredient and processes for production thereof

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